The false option about a real image is that It appears behind the mirror. Last option.
What is a real image?Rays merely appear to diverge in a virtual image, whereas they actually converge in a real image. Only when the item is placed farther away from the mirror/lens than the focal point and this real picture is reversed can concave mirrors and converging lenses produce genuine images.
Using a converging lens or a concave mirror, actual images can be captured. The positioning of the object affects the size of the actual image.
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131 53i is an artificially made radioactive isotope of iodine, produced during the operation of nuclear power plants and the detonation of nuclear bombs. exposure to high concentrations of 131 53i represents a serious risk for human health. however, small doses of this radioactive isotope are put to good use in medical studies. 131 53i is widely used in treating thyroid cancer and in diagnosis of abnormal liver and kidney function.
Part A
What is emitted when the radioactive nucleus of 131 53I decays to form the stable isotope of xenon 131 54Xe?
part B
What is the energy Q released when 131 53Idecays and 131 54Xe is formed? The atomic mass of 131 53I is 130.906118 u and the atomic mass of 131 54Xe is 130.90508 u.
Part C
The newly formed xenon nucleus is left in an excited state. Thus, when it decays to a state of lower energy a gamma ray is emitted. If the wavelength of the emitted gamma ray is 3.44×10−12 m , what is the decrease in mass, ΔmXe, of the xenon nucleus as a result of this decay?
A . The emitted particle is β⁻.
The radiactive isotope ¹³¹ I ₅₃ decays into ¹³⁵Xe₅₄ by emitting a beta particle and an information .
¹³¹ I ₅₃ --> ¹³⁵Xe₅₄+ β⁻ +v + Q
Therefore, The emitted particle is β⁻.
B .the energy Q released when 131 53I decays and 131 54 Xe is formed is 0.966MeV
Q= Δmc²
= (130.906118u - 130.90508u - 0.32*10⁻⁴u)(931.5MeV/c²)
= 0.966MeV
C . the decrease in mass, ΔmXe, of the xenon nucleus is 3.87*10⁻⁴ u.
= hc/λ
= [tex]\frac{(6.625*10^{-34} )(3*10^{8} m/s)}{3.44*10^{-12} }[/tex]
= 0.3605 MeVj
Δm = (0.3065)MeV([tex]\frac{1u}{931.5Mev/c^{2} }[/tex])
= 3.87*10⁻⁴ .
Mass is a quantitative measure of inertia in physics and a fundamental property of all matter. In effect, it is the resistance that an object offers to changes in velocity or position when a force is applied. The greater the mass of an object, the smaller the change caused by an applied force.
Mass can be experimentally defined as the inertia of a body, a measure of its resistance to acceleration (change in velocity) when a net force is applied. An object's mass also determines the strength of its attraction to other bodies. size. A 2kg cast iron weight used for scales. The decrease in mass, ΔmXe, of the xenon nucleus is 3.87*10⁻⁴ u
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A ramp is 10 m high and 20 m long. What is the IMA of the ramp?
The IMA of the ramp is 2.
How do you calculate a mechanical advantage?The force amplified by utilising a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the necessary output force amplification, the gadget trades off input forces against movement. The law of the lever serves as a paradigm for this. Mechanisms are machine parts made to control forces and motion in this way. An ideal transmission system does not increase or decrease power. Consequently, the ideal machine is devoid of a power source, frictionless, and built from inflexible materials that do not flex or wear. Efficiency factors that account for deviations from the ideal are used to express how well a real system performs in comparison to the ideal.The length of the effort arm of a lever divided by the length of the resistance arm represents the optimal mechanical advantage. The IMA is typically calculated as the resistance force (Fr) divided by the effort force (Fe). IMA is also equal to the product of the load's travel distance (dr) and the distance over which the effort is applied (de).Given data :
L = 20 mH = 10 mBy using the formula,
MA = L / H
= 20 / 10
= 2
IMA = 2
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If the speed of every atom in a monatomic ideal gas were doubled, by what factor would the Kelvin temperature of the gas be multiplied?
a) 4
b)2
c)1
d) 1/2
e) 1/4
If the given speed of any atom in a monatomic state of an ideal gas were doubled, then by using four factor we would multiplied the Kelvin present temperature of the gas. Option (a) is correct.
We recollect a monatomic best fueloline having debris of mass m that don't engage and whose middle of mass stays at rest. For a monatomic best fueloline (which include helium, neon, or argon), the most effective contribution to the strength comes from translational kinetic strength. The common translational kinetic strength of a unmarried atom relies upon most effective at the fueloline temperature and is given through the equation: Kavg = 3/2 kt.
These are helium, neon, argon, krypton, xenon, and radon. Noble gases have a complete outer valence shell making them as an alternative non-reactive species. Many gases which include nitrogen, oxygen, hydrogen, noble gases, a few heavier gases like carbon dioxide and combinations which include air, may be dealt with as best gases inside affordable tolerances over a significant parameter variety round widespread temperature and pressure.
We know that,
K.E = (1/2) m*[tex]V^{2}[/tex]
If we doubled the speed then 2*2=4 times its affect the temperature.
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what happens when light passes from air into water? does it slow down; when light travels from glass to air; when light travels from air to glass the ray of light bends; when light travels from air to glass what happens to the speed; when light travels from air to water does wavelength change; what happens when light travels from air to water; light refraction; what happens to a light ray when it travels from water into air?
When light passes from air into water, it slows down and bend towards the normal.
When light travels from glass to air its speed increases and bend away from the normal.
When light travels from air to glass, speed decreases.
When light travels from air to water wavelength increase as refractive index of air is less than the water.
When light travels from water into air, its speed increases and it bend away from the normal.
Refraction is defined as the bending of light at the surface of two media when it changes medium of propagation.
When light passes from an optically rarer medium to optically denser medium. its speed decreases and it bend towards the normal. When light passes from the denser medium to a rarer medium, its speed increases and it bends away from the normal.
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in the instant of fig. 11-41, two particles move in an xy plane. particle p1 has mass 6.5 kg and speed v1 2.2 m/s, and it is at dis- tance d1 1.5 m from point o. particle p2 has mass 3.1 kg and speed v2 3.6 m/s, and it is at distance d2 2.8 m from point o. what are the (a) magnitude and (b) direction of the
The magnitude and direction of net angular momentum of particles is [tex]52.7kg.m^2/s[/tex] out of the page.
Given,
particle 1:-
Mass ,m1 = 6.5 kg
speed , v1 = 2.2 m/s
distance from point O, d1 = 1.5 m
Particle 2:-
Mass ,m2 = 3.1 kg
speed, v2 = 3.6 m/s
distance from point O, d2 = 2.8 m
Angular momentum can be determined by formula,
p=mvd
angular momentum of particle-1, [tex]\rho_1=6.5*2.2*1.5=21.45 kg.m^2/s[/tex]
angular momentum of particle-2, [tex]\rho_2=3.1*3.6*2.8=31.248 kg.m^2/s[/tex]
Then, the net angular momentum is
[tex]\rho=\rho_1+\rho_2=21.45+31.248=52.69kg.m^2/s[/tex]
The direction of angular momentum of particle is always perpendicular to the motion of particle, as the particles are moving on xy-plane then the their direction will be perpendicular to xy-plane i.e. z-plane, it means out of the page.
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Your question is incomplete, here is the complete question.
In the instant shown in the diagram, two particles move in an xy-plane. Particle P1 has mass 6.5 kg and speed v1 = 2.2 m/s, and it is at distance d1 = 1.5 m from point O. Particle P2 has mass 3.1 kg and speed v2 = 3.6 m/s, and it is at distance d2 = 2.8 m from point O. What is the magnitude and direction of net angular momentum of the two particles about O?
A) 52.7 kg · m2/s out of the page B) 52.7 kg · m2/s into the page C) 21.5 kg · m2/s into the page D) 9.8 kg · m2/s into the page E) 9.8 kg · m2/s out of the page
an electron in a cathode-ray tube is accelerated through a potential difference of 10 kv, then passes through the d
The field strength that will deflect the electrons is 2.93*10^-3 T or 2.93mT.
Calculation:
from figure
sin(o) =d/r
r =d/sin(o) =1.6/sin8 =11.5 cm
from conservation of energy
qV =(1/2)mv^2
[tex](1.6*10^-19)(10*10^3)=(1/2)(9.11*10^-31)*v^2[/tex]
[tex]v=5.93*10^7 m/s[/tex]
and
r = mv/qB
= [tex]B =mv/qr =(9.11*10^-31)*(5.93*10^7)/(1.6*10^-19)(11.5*10^-2)[/tex]
B = 2.93*10^-3 T or 2.93mT.
An electron is a subatomic particle with a negative elementary charge. Electrons belong to the first generation of the leptonic particle family and are generally considered elementary particles because they have no known composition or substructure. In the standard model of particle physics.
Electrons are the smallest particles that make up an atom and have a negative charge. In neutral atoms, the number of protons and electrons is the same, and are considered elementary or elementary particles. electrons belong to a group of elementary particles called leptons.
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temperatures rise, which results in melting of sea ice. the loss of sea ice exposes dark-colored ocean which is a better absorber of heat. as the darker ocean water absorbs more heat, temperatures rise further. the rising temperature melts even more sea ice, exposing even more darker-colored ocean, and so the cycle continues as one change is reinforced by the other.
Within the summer, the ice will soften due to hotter temperatures and longer exposure to the sun. for the duration of the summertime, whilst sea ice will attain its thinnest through mid-September, the place blanketed through ice is about 1/2 the scale of the wintry weather maximum.
Better ocean temperatures cause melted glaciers, bleached coral reefs, and worsened hurricanes. increasing ocean temperatures may have strongly bad results for our economies and great lifestyles. Oceans put off massive portions of carbon dioxide from the environment through natural strategies.
We already see consequences scientists expected, inclusive of the lack of sea ice, melting glaciers and ice sheets, sea degree upward thrust, and greater severe warmth waves. Scientists predict worldwide temperature will increase from human-made greenhouse gases will maintain. intense climate damage may even grow and accentuate.
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Which of the following statement is true of ATP? A. ATP stands for adenosine triphosphate
B. ATP consists of one adenosine atom and three phosphate atoms
C. ATP consists of one adPOenosine atom and two phosphate atoms
D. The breakdown of ATP provides the energy needed to fuel muscle contraction
The one that is accurate is that when the phosphate is broken down into ADP, ATP releases energy.
Does ATP save its energy in glucose form?The energy that cells need is produced through the breakdown of glucose. More energy cannot be stored by ATP molecules than is released by the cells. In actuality, ATP doesn't retain as much energy as a glucose molecule. See the equation in the question; roughly 38 ATP molecules are produced for every glucose molecule.
How does ATP store energy?The cell stores extra energy by reattaching a free phosphate molecule to ADP, converting it back into ATP. This extra energy can come from the breakdown of food that has been ingested or, in the case of plants, energy produced during photosynthesis.
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Figure shows a closed loop of wire that consists of a pair of equal semicircles, of radius 3.7 cm, lying in mutually perpendicular planes.The loop was formed by folding a flat circular loop along a diameter until the two halves became perpendicular to each other. A uniform magnetic field B of magnitude 76 mT is directed perpendicular to the fold diameter and makes equal angles (of 45°) with the planes of the semicircles. The magnetic field is reduced to zero at a uniform rate during a time interval of 4.5 ms. During this interval, what are the (a) magnitude and (b) direction (clockwise or counterclockwise when viewed along the direction of B) of the emf induced in the loop?
(a) Magnitude of the average emf induced in the loop is 0.20 mV.
(b) direction is perpendicular to the field.
Average emf induced in the circular loop is given by;-
The magnitude of average emf induced in the loop is calculated as follows are;
emf = NA(B₁ - B₂)/t
by using the formula of the induced emf we calculate the average emf.
A = area of the loop
N =number of turns
B1 = initial magnetic field
B2 = final magnetic field
t=time
A = πr² = π(0.37)²
= 5.027 x 10⁻³ m²
emf = (1)(5.027 x 10⁻³)(0.45 - 0.37)/7.6
emf = 2.01 x 10⁻⁴ V
emf = 0.201 mV
Therefore, magnitude of the average emf is induced in the loop = 0.20 mV.
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A proton accelerates from rest in a uniform electric field of 640 N/C. At some later time, its speed is 1.20 x 10% m/s (nonrelativistic, because v is much less than the speed of light).
(a) Find the acceleration of the proton.
(b) How long does it take the proton to reach this speed?
(c) How far has it moved in this time?
(d) What is its kinetic energy at this time?
a) The acceleration of the proton is 6.4×10¹⁰ m/s².
b) Time taken is 1.875×10⁻⁵ second .
c) It moved in this time is 11.25 meter.
d) its kinetic energy is 1.15×10⁻¹⁵ Joule.
What is electric field?The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
uniform electric field: E = 640 N/C.
its speed is: v= 1.20 x 10⁶ m/s
a) the acceleration of the proton = qE/m
= (1.6×10⁻¹⁹×641)/(1.6×10⁻²⁷) m/s²
= 6.4×10¹⁰ m/s²
b) Time taken = (1.20 x 10⁶ / 6.4×10¹⁰)second = 1.875×10⁻⁵ second .
c) it moved in this time = ( 1.20 x 10⁶×1.875×10⁻⁵ )/2 meter = 11.25 meter.
d) its kinetic energy = mv²/2 = (1.6×10⁻²⁷)(1.20 x 10⁶)²/2 joule = 1.15×10⁻¹⁵ Joule.
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Cardiopulmonary resuscitation is a procedure used to deliver oxygenated blood to the brain when the heart is no longer beating.
Responses
False
False
True
Answer: True
Explanation:
Cardiopulmonary resuscitation (CPR) is a medical procedure involving repeated compression of a patient's chest in an attempt to restore the blood circulation and breathing of a person who has suffered cardiac arrest.
in today's demonstration, a nonmoving ball placed at the top of the ramp is an example of question 5 options: chemical energy gravitational potential energy elastic potential energy kinetic energy
Gravitational Potential Energy is demonstrated by a stationary ball put at the top of a ramp. The energy that a body has or acquires is known as gravitational potential energy.
because when something is in a gravitational field, it changes position. It is, to put it simply, energy that results from gravitational force or gravity. Taken two pencils is the most typical illustration. If one pencil is set down on a table and the other is raised above it, the pencil raised will have more gravitational potential energy than the pencil set down on the table. The equation U = mgh is used to compute it. The mass, m, is expressed in kilograms.
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what causes a bullet or projectile to travel down the barrel of a firearm and exit at the muzzle?; what is one thing that almost always happens when a cartridge is fired; what can affect the performance of a cartridge; firing mechanism of a gun; how is a single-shot different from a repeating firearm; which type of action operates automatically each time you pull the trigger; shot pellets and a bullet are examples of which basic component; what happens when you pull the trigger on a gun
When gunpowder explodes, a gaseous byproduct is produced that expands quickly. The cartridge is propelled through the barrel by the projectile due to this gas expanding.
An object which is in motion in the air with no other force beyond gravity influencing it is a projectile. A projectile is an object that is launched into the air with only downward gravity force acting on it and maintains speed due to its own inertia. A projectile is a body that is launched into space or the air. The trajectory of a projectile is defined as its curved path of travel. The free fall motion of any item in a horizontal path with constant velocity is Projectile Motion.
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In a period of 1.00 s, 5.00×1023 nitrogen molecules strike a wall with an area of 8.00cm2. Assume the molecules move with a speed of 300 m/s and strike the wall head-on in elastic collisions. What is the pressure exerted on the wall? Note: The mass of one N2 molecule is 4.65×10−26kg.
A wall with an area of 8 cm² is struck by 5.00 x 10²³ nitrogen molecules over the course of 1 s. Assume that the molecules are moving at a speed of 300 m/s and colliding with the wall in an elastic manner. The pressure acting on the wall is 17.43 kPa.
Mass in motion is a definition of momentum. Mass and velocity are multiplied to determine momentum. That is, p = mv where p,m, and v denotes momentum, mass, and velocity.
Given the change in the time period, Δt is 1 second, the number of nitrogen molecules is 5.00×10²³ molecules, the change in velocity Δv is 300 m/s, and the area is 8×10⁻⁴ m².
The momentum of one molecule is given as 2mΔv. Then, the momentum of N molecules is 2NmΔv.
The force exerted on the wall by nitrogen molecule is written as,
[tex]\begin{aligned}\text{Force F}&=\frac{\Delta\text {momentum}}{\Delta t}\\&=\frac{2Nm\Delta v}{\Delta t}\end{aligned}[/tex]
Then, the pressure exerted by nitrogen molecule on the wall is,
[tex]\begin{aligned}P&=\frac{F}{A}\\&=\frac{2Nm\Delta v}{\Delta t\times A}\\&=\frac{2\times 5\times10^{23}\times4.65\times10^{-26}\times300}{8\times 10^{-4}\times 1.00}\\&=\mathrm{17.43\;kPa}\end{aligned}[/tex]
Therefore, the required answer is 17.43 kPa.
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an atomic spectrum contains a line with a wavelength centered at 402 nm . careful measurements show the line is really spread out between 401 and 403 nm . estimate the lifetime of the excited state that produced this line.
The lifetime of the excited state that produced this line is 416.66sec if a wavelength ranges from 401nm and 403nm.
For solving this problem we use Rydberg equation whose formula is given by
v=[(1 / λ₁) -1 / λ₂)]×(h×c)
where v is the frequency of the photon,
λ is the wavelength of the photon
h is plank's constant
and c is the speed of light in vacuum
Since we are given λ₁ ,λ₂ as 401nm and 403nm respectively.Also we know that value of h is 6.6ˣ10⁻³⁴(J-sec)/m and c=3ˣ10⁸m/sec
So,putting all values on above formula,we get
=>v=[(1/401)-(1/403)]ˣ(6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)
=>v=[(403-401) ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] / (401 ˣ 403)ˣ(1/10⁻²⁷)
=>v= [[2 ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] ₓ(1/10⁻²⁷)] ˣ (1 / 401 ˣ 403)
=>v=(39.6 ˣ 10) / 161603
=>v = 396/161603
=>v = 0.0024/sec
We know time period is reverse of frequency, so lifetime span is
=>t=1/v
=>t=1/ (0.0024/sec)
=>t=416.66sec
Hence, lifetime of the excited state is 416.66sec.
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The gravitational force between two bodies varies inversely as the square of the distance between them. If the force between two bodies is 18 N when the distance between them is 10 km, find the fource between the bodies when the distance between them is 7.5 km.
The statement states that the force between both the bodies at a distance of 7.5 km equals F = 32 N.
What is gravitational force?This force that earth applies to a body is referred to as gravitational force. Its down motion of water in the river, the downwards motion if water in a stream, or an upwards motion of a ball being thrown are examples of motion brought on by gravitational influence.
Briefing:F = k/d² where k is the inverse variation's constant.
18 N = k / (10 km)²
18 N = k / 100 km²
k = (18 N) (100 km²)
k = 1800 (N)(km²)
F = ?
d = 7.5 km
k = 1800 (N) (km²)
F = 1800 (N)(km²) / (7.5 km)²
F = 1800 (N) (km²) / (55.25 km²)
F = 32 N
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Use Eq. (9.20) to calculate the moment of inertia of a uniform, solid disk with mass M and radius R for an axis per- pendicular to the plane of the disk and passing through its center
Circular disc's moment of inertia around axis passing through mass and parallel to disc Icm=MR22
Explain about the moment of inertia?The phrase "moment of inertia" in physics refers to the precise calculation of a body's inertia with respect to rotation, or the resistance a body exhibits when a torque is applied to alter its rate of rotation around an axis (turning force).
It is a broad (additive) property: the moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.
Moment of inertia is the propensity of an object to continue rotating at a constant speed or in a condition of rest. More torque is needed to shift this state the higher the moment of inertia.
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Light of wavelength 550 nm illuminates a double slit, and the interference pattern is observed on a screen behind the slit. The third maximum is measured to be 2.8 cm from the central maximum. The slits are then illuminated with light of wavelength 440 nm.
How far is the fourth maximum from the central maximum?
The fourth maximum is measured to be 2.97 cm from the central maximum when slits are illuminated with light of wavelength 440 nm.
The interference or bending of waves passing through an aperture around the corner of an obstacle or into the geometric shadow area of the obstacle/aperture is defined as diffraction. Secondary sources of propagating waves are diffractive objects or apertures. It is the process by which a ray or other wave system expands as it passes through a narrow aperture or edge. It is usually the result of interference between the generated waveforms.
Given,
[tex]\lambda = 550 nm=550*10^{-9}n[/tex]
[tex]y_3 = 2.8 cm = 2.8 * 10^{-2} m[/tex]
The third maximum from the central maximum can be determined by
[tex]y_3 = \frac{3D \lambda}{d}\\\\2.8*10^{-2}=\frac{3*550*10^{-9}D}{d}\\\\\frac{2.8*10^{-2}}{3*550*10^{-9}}=\frac{D}{d}\\\\0.0169*10^6=\frac{D}{d}[/tex]
Now, the fourth maximum from the central maximum can be determined by,
Now, [tex]\lamda = 440 nm =440 *10^{-91} m[/tex]
[tex]y_4 = \frac{4D \lambda }{d}\\\\y_4=4*0.0169*10^6*440*10^{-9}\\\\y_4=29.744*10^{-3}m=2.97 cm[/tex]
Thus, the fourth maximum is measured to be 2.97 cm from the central maximum
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which of the following is not one of the credit categories for points in leed certification? energy and atmosphere
Construction and demolition waste management planning is not a credit in the LEED v4.1 BD C MR category.
We are confident that the rating system achieves those objectives because this version of LEED is the result of countless hours of work by our volunteers and staff.
The world's standard for measuring the efficiency of green building design, construction, and operation is called LEED. With more than 93,000 projects registered and certified globally and more than 19 billion square feet of space, different LEED versions have steadily advanced the global green building market over the past 18 years.
Regions and markets develop at different rates, and we want to be sure we can meet the needs of every member of the green building community. LEED v4.1 is the culmination of a number of improvements that will raise the bar for our standards, promote leadership, and make our platform more accessible, user-friendly, and most importantly, collaborative than ever.
The platform for LEED v4.1 will be the most open and transparent one yet.
The question is incomplete. the complete question is 'a) construction and demolition waste management planning b) building life cycle impact reduction c) construction and demolition waste management d) building product disclosure and optimization - sourcing of raw materials'
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a student used a tuning fork of frequency 512 hz and observed that the speed of sound was 343 m/s. calculate the wavelength of this sound wave (in m). (enter your answer with 2 significant figures.)
The wavelength of the sound wave (2 sig. figs.) will be 0.67m
What is wavelength?The wavelength is a property of a wave that tells the distance between identical points between two successive waves. The distance between one crest (or trough) of one wave and the next is the wavelength of the wave.
The wavelength of light determines its color, and the wavelength of sound determines the pitch.
Wavelength is indicated using the Greek letter lambda (λ).
λ = v/f
where v = speed or velocity of the wave
f = frequency of the wave.
λ = v/f
given v = 343m/s
f = 512 hz
λ = 343/512
λ = 0.669m
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An air-filled parallel-plate capacitor has plates of area 2.60 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 17.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? рC c) What is the magnitude of the uniform electric field between the plates? N/C
a) The value of its capacitance is 0.90 pF
b) The charge on the capacitor is 15.3 pC
c) The magnitude of the uniform electric field between the plates is 6.8 N/C.
given that :
are of the parallel plate capacitor = 2.60 cm²
distance d = 2.5 mm
potential = 17 V
a) The value of its capacitance is :
C = Eo A / d
= ( 8.85 × 10⁻¹² C² / N . m ) ( 2.60 × 10⁻⁴ m²) / 2.50 × 10⁻³
= 0.90 × 10⁻¹² F
= 0.90 pF
b) The charge on the capacitor is :
q = CVo
q = 0.90 × 10⁻¹² F × 17 V
q = 15.3 × 10⁻¹² C
q = 15.3 pC
c) The magnitude of the uniform electric field between the plates is :
E = Vo / d
E = 17 / 2.50 × 10⁻³
E = 6.8 N/C
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A 0.46-kg mass suspended from a spring undergoes simple harmonic oscillations with a period of 1.6 s.
How much mass, in kilograms, must be added to the object to change the period to 1.8 s?
please write each step. thank you
0.12kg of mass, must be added to the object to change the period to 1.8 s.
What is the period?
The period is the amount of time needed for a simple pendulum to swing back and forth (backwards). Seconds (s) are the SI unit of time. A simple pendulum completes one cycle when it swings back and forth.
What is mass?
The amount of matter in a particle or object is represented by its mass, a dimensionless quantity. In the International System, the kilogram serves as the primary unit of mass.
Calculations:
Given
mass suspended from string M = 0.46kg
Oscillating time T = 1.6sec
To find (M') Mass added to change oscillating time to T' = 1.8sec
we know that:
T = 2π/ω
ω = √ (K/M)
T = 2π √ (K/M)
T = 2π × √ (M/K)
1.6 = 2 × 3.14 × √ (0.46) /K
1.6/6.28 = √ (0.46) /K
0.254 = √ (0.46) /K
Sq. In both sides
(0.254) ² = {√ (0.46) /K}²
0.645 = 0.46 /K
K= 7.13N/m
Now, for time T'
T' = 2π × √ (M'/K)
1.8 = 2 × 3.14 × √(M' /7.13)
1.8/6.28 = √(M' /7.13)
0.286 = √(M' /7.13)
Sq. In both sides
(0.286)²= √(M' /7.13)²
0.0817 = M' /7.13
M'= 0.0817 × 7.13
M' = 0.58kg
To find the added mass
=M' - M
=(0.58 - 0.46) kg
= 0.12kg.
Hence, 0.12kg of mass, must be added to the object to change the time period to 1.8 s.
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Consider a pendulum swinging. Which type(s) of energy is/are associated with the pendulum in the following instances: i. the moment at which it completes one cycle, just before it begins to fall back towards the other end, ii. the moment that it is in the middle between the two ends, iii. just before it reaches the end of one cycle (just before instant i.).
i. potential, ii. kinetic, iii. potential and kinetic
In the following situations, the type(s) the energy is/are related to the pendulum: potential kinetic potential,kinetic
When someone is kinetic, what does that mean?When an organism moves as a result of a stimulation like light, this is known as kinesis. Being able to use one's own internal kinesis power is what it means to be kinetic. Kinetics have such a supernatural ability, just like Telekinetics, Psychokinetics, and those who have Extra Sensory Perception.
What is it that makes kinetic energy move?Kinetic energy is the energy that any item has with a result of motion. An item can only be accelerated through the application of a force. Applying force requires effort on our part. Following completion of the work, energy is transmitted to the object, which then moves at the a new, consistent rate.
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A spring has an unstretched length of 10 cm. It exerts a restoring force F when stretched to a length of 11 cm.
a. For what length of the spring is its restoring force 3F?
b. At what compressed length is the restoring force 2F
a) The length for 3F force is : 13 cm
b) The length for 2F force is : 8 cm
The required length and compressed length of the spring at the given force values are 13 cm and 8 cm respectively.
Explanation:
F = ke
k = spring constant ;
e = extension;
e = (Final length - Initial length)
Initial length, l = 10
Final length = L1 = 11
F = k(11 - 10)
F = k;
Length for a restoring force of 3F ;
3F = k(Final length - Initial length)
k = F
3F = F(L1 - 10)
3F = - 10F + F(L1)
F(L1) = 3F + 10F
F(L1) = 13F
L1 = 13
Hence, required length ls 13 cm
B.)
Let compressed length = c
2F = F(initial length - compressed length)
2F = F(10 - c)
2F = 10F - F(c)
F(c) = 10F - 2F
F(c) = 8F
c = 8F / F
c = 8 cm
Therefore, the required compressed length ls 8 cm
Spring:
A spring is an elastic body that stores mechanical energy. Coil springs are often used in daily life, but there are many different types of springs. Modern quills are usually made of spring steel, but non-metallic items like bows are also quills.
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The brakes of a 1000kg car exert 3000N. How long will it take the car to come to a stop from a velocity of 30meter per second and how far will the car travel during this time?
If the car is traveling at 30 meters per second, it will take 10 seconds to halt. A 1,000 kilogram car's brakes produce 3000 N of force.
Which is greater, velocity or speed?In contrast to speed, velocity represents the direction and speed of an object's motion since it follows a path. As a result, velocity is a vector, whereas speed is a scalar.
What distinguishes speed from acceleration?The rate at which a displacement varies is measured by its velocity. Accelerated speed changes are experienced. Its velocity is an vector quantity since it is composed of two parts. Acceleration is also a vector quantity since it is simply the rate about which velocity varies.
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A piano tuner stretches a steel piano wire with a tension of 1070N . The wire is 0.400m long and has a mass of 4.00g .
A) What is the frequency of its fundamental mode of vibration?
B) What is the number of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to 1.00
The frequency of its fundamental mode of vibration is 409Hz and the number of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to 1.00x10^4 is 24
Given tension of a steel piano wire (T) = 1070N
Length of wire L = 0.400m
Mass of piano wire M = 4g
We know linear density = mass/length = 4x10-3/0.400 = 0.01 kg/m
fundamental frequency f = 1/2L√T/µ
f = 1/2x0.4x√1070/0.01 = 409Hz
number of loops is n
n = f'/f = 1x10^4/409 = 24.5 = 24
Hence the frequency of its fundamental mode of vibration is 409Hz and the number of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to 1.00x10^4Hz is 25.
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a brick lies perilously close to the edge of the flat roof of a building. the roof edge is 50 ft above street level, and the brick has 740.0 j of potential energy with respect to street level.a. Someone edges the brick off the roof, and it begins to fall. What is the brick’s kinetic energy when it is 35 ft above street level?b. What is the brick’s kinetic energy the instant before it hits the street surface?
(a) The brick’s kinetic energy when it is 35 ft above street level is 221.7 J
(b) The brick’s kinetic energy the instant before it hits the street surface is 740 J.
What is the brick’s kinetic energy?The brick’s kinetic energy when it is 35 ft above street level is calculated by applying the principle of conservation of energy as follows.
P.E = mgh
where;
m is the mass of the brickg is acceleration due to gravityh is the height of the brick above the ground = 50 ft = 15.24 mm = P.E / gh
m = (740) / (9.8 x 15.24)
m = 4.95 kg
The brick’s kinetic energy when it is 35 ft above street level is calculated as follows;
K.E = ΔP.E
K.E = mg(Δh)
K.E = mg(50 ft - 35 ft)
K.E = mg(15 ft)
where;
15 ft = 4.57 m
K.E = 4.95 x 9.8 x 4.57
K.E = 221.7 J
Based on the law of conservation of energy, the brick’s kinetic energy the instant before it hits the street surface will be equal to the initial potential energy of the brick which is equal to 740 J.
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If the mass of a satellite is doubled while the radius of its orbit remains constant, the speed of the satellite is a increased by a factor of 2 b. reduced by a factor of 2. c. 8 reduced by a factor of 8. d. increased by a factor of 8. e. not changed.
If the mass of the satellite is doubled and the radius of orbit is remains same then the speed of the satellite is constant.
The speed at which a body orbits the system's center, which is typically a planet or a natural satellite, is known as its orbital speed. Typically, this system is centred on a large body. The earth orbits the sun at a speed of 108,000 kilometres per hour.
Through the provided formula, it is linking the mass of a specific planet to the gravitational constant and radius. The "universal gravitational constant," G, is a constant that appears in the orbital speed formula. It is worth 6.673 10 11 Nm2 kg2. The radius of the Earth is 6.38 x 106 metres.
we know that the orbital speed is
Vo = sqrt(G*M/R)
wher M is mass of the Earth not the mass of the satellite
and R is radius of the orbit
so the speed will be same not changed
Hence, the correct option is e.
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you are heading toward an island in a speedboat and you see your friend standing on the shore, at the base of a cliff. you sound the boat's horn to alert your friend of your arrival. the sound from the boat hits the cliff behind your friend and returns to you as an echo. part description answer save status a. if the horn has a rest frequency of f0, what frequency does your friend hear? lower than f0 equal to f0 higher than f0 click here to check your answer 6.25 pts.100%
The frequency heard is greater than frequency [tex]f_{0}[/tex].
This happens because of doppler's effect.
When the source and observer are moving relative to each other, the frequency observed by the observer (fa) is different from the actual frequency produced by the source (f0)Here, when the source of waves is moving towards the observer they will have an upward shift in frequency. As for the observers from whom the source is receding, there will be a downward shift in frequency.However, it should be noted that the effect does not occur as a result of the actual change in the frequency of the wave source. The main reason that we experience the Doppler effect is that as the wave source moves toward the observer, each new wave crest that is formed from the source is emitted from a location that is closer to the observer.Therefore, as the source moves closer and closer the waves will now take less time to reach the observer or the time between the arrivals of new wave crests is reduced. This further causes an increase in frequency.To know more about sound visit:
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(a) In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, -2.0 m, 2.0 m) due to force F1 with components F1x = 5.0 N and F1y = F1z = 0?(b) In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, -3.0 m, 2.0 m) due to force F2 with components F2x = 0, F2y = 3.0 N, and F2z = 5.0 N?
The torque about the origin is [tex]$2.0 \mathrm{Nm} \hat{i}-8.0 \mathrm{Nm} \hat{j}-12.0 \mathrm{Nm} \hat{k}$[/tex].
What is torque?
Torque[tex]$\vec{T}$[/tex] is the cross product between force [tex]$\vec{F}$[/tex] and vector position [tex]$\vec{r}$[/tex] respect a fixed point (in our case the origin):
[tex]\vec{\tau}=\vec{r} \times \vec{F}$$[/tex]
There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:
[tex]$\vec{r} \times \vec{F}=-\left[\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ F 1_x & F 1_y & F 1_z \\ r_x & r_y & r_z\end{array}\right]$[/tex]
[tex]\begin{aligned}& \vec{r} \times \vec{F}=-\left(\left(F 1_y r_z-F 1_z r_y\right) \hat{i}-\left(F 1_x r_z-F 1_z r_x\right) \hat{j}+\left(F 1_x r_y-F 1_y r_x\right) \hat{k}\right) \\& \vec{r} \times \vec{F}=-((0(2.0 m)-0(-3.0 m)) \hat{i}-((4.0 N)(2.0 m)-(0)(0)) \hat{j}+((4.0 N)(-3.0 m)- \\& 0(0) \hat{k}) \\& \vec{r} \times \vec{F}=-2.0 N m \hat{i}+8.0 N m \hat{j}+12.0 N m \hat{k}=\vec{\tau}\end{aligned}[/tex]
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