Option c is correct. Transition metals typically have low melting points. A collection of elements known as transition metals, or the d-block, are found in the middle of the periodic table.
Because of their strong metallic bonding and partially full d-orbitals, transition metals are noted for having high melting and boiling temperatures. Due to the splitting of the d-orbitals into two energy levels, the molecule acquires its distinctive hue by absorption of light.
Their other distinguishing characteristics, including as their capacity to exist in various oxidation states and their capacity to form complex ions, are similarly influenced by these partially filled d-orbitals.
The unpaired electrons in the d-orbitals of transition metal complexes frequently give rise to magnetic characteristics. Due to the d-orbital electrons' ability to absorb light in the visible spectrum, they frequently have colored compounds as well.
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Complete question
Which one of the following is not true about transition metals?
a. they frequently have more than one common oxidation state.
b. their compounds frequently exhibit magnetic properties.
c. they typically have low melting points.
d. their compounds are frequently colored.
e. they are found in the d-block of the periodic table.
For the buffer made from hno2 and nano2, write the balanced chemical reaction that will occur if you add naoh to that buffer.
The balanced chemical reaction that will occur if you add NaOH to a buffer made from HNO2 and NaNO2 is:
HNO2 + NaOH → NaNO2 + H2O
In this reaction, the NaOH will react with the HNO2 present in the buffer to form NaNO2 and water.
This reaction will result in the consumption of some of the HNO2 present in the buffer, which will cause a shift in the pH of the buffer solution.
However, since the buffer contains both the weak acid HNO2 and its conjugate base NaNO2, the buffer capacity will still be maintained, and the pH of the solution will remain relatively stable.
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are elements in groups in 1 and 2 metals? Hydrogen? How about lacthanides and actinides?
Are elements in Groups 1 and 2 metals, and what about hydrogen, lanthanides, and actinides?
Elements in Groups 1 and 2 are indeed metals. They are known as alkali metals (Group 1) and alkaline earth metals (Group 2). However, hydrogen is an exception. Although it is in Group 1, hydrogen is a non-metal due to its unique properties and electron configuration.
Lanthanides and actinides are also metals. They are part of the inner transition metals and are located in the f-block of the periodic table. Lanthanides consist of elements with atomic numbers 57-71, while actinides consist of elements with atomic numbers 89-103. Both groups are known for their metallic properties and reactive nature.
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Is it Ca₂C or CaC₂ which is calcium carbide? I am confused because Ca₂C is logical because of the balance of charges, but CaC₂ is what it shows on websites which is illogical because then it becomes a -6 charge. Thank you in advance if you have an answer! :D
Calcium carbide is actually CaC₂, not Ca₂C. While it may seem logical that the formula should be Ca₂C to balance the charges, the correct formula is CaC₂.
In CaC₂, the calcium ion (Ca²⁺) has a +2 charge, and the carbide ion (C₂²⁻) has a -2 charge. Therefore, the overall compound is neutral.
The reason why it's not Ca₂C is because that compound doesn't exist. If we try to form Ca₂C, we would need two calcium ions (2 x Ca²⁺ = +4 charge) to balance the charge of the carbide ion (C²⁻ = -2 charge), which would result in a net charge of +2. Therefore, Ca₂C cannot form as a stable compound.
I hope that clears up your confusion!
A line-angle structure has a line terminus, five vertices, and an OH, with an O atom double-bonded to the fifth (from left to right) vertex, and a CH3 group attached to the fourth vertex.
Spell out the IUPAC name of the compound.
The IUPAC name of the compound with line-angle structure has a line terminus, five vertices is 3-methylpentan-1,4-diol.
Based on the description, the line-angle structure of the compound can be represented as follows:
CH3
|
H -- C -- H
|
H -- C -- H
|
H -- C -- O -- H
| ||
H -- C -- C ||
| ||
H H
The compound has six carbon atoms, and the OH group is attached to the third carbon atom. The CH3 group is attached to the second carbon atom.
"pentan" indicates a five-carbon chain
"-1,4-diol" indicates that there are two hydroxyl (-OH) groups, located on the first and fourth carbon atoms, respectively
"3-methyl" indicates that there is a methyl (CH3) group attached to the third carbon atom
To provide a more complete IUPAC name of the compound, we need to specify the configuration of the hydroxyl (-OH) groups, as they are chiral centers.
The line-angle structure given does not indicate the stereochemistry, so we cannot determine the exact configuration of the -OH groups. We will assume that the compound has a pair of enantiomers due to the presence of chiral centers.
If the -OH groups are both in the R configuration, then the name of the compound would be (3R,4R)-3-methylpentane-1,4-diol.
If the -OH groups are both in the S configuration, then the name of the compound would be (3S,4S)-3-methylpentane-1,4-diol.
If the -OH groups have opposite configurations, then the compound would be a pair of enantiomers, and the name would be (3R,4S)-3-methylpentane-1,4-diol and (3S,4R)-3-methylpentane-1,4-diol, respectively.
Therefore, the complete IUPAC name of the compound depends on the stereochemistry of the -OH groups, which is not specified in the given line-angle structure.
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What is the hybridization of the central atom in AlBr3?Hybridization = What are the approximate bond angles in this substance?Bond angles = °
The hybridization of the central atom (Al) in AlBr3 is sp2.
As for the approximate bond angles the central atom with a bond angle of approximately 120°.
When aluminum (Al) is bonded to three bromine (Br) atoms in AlBr3, it forms three equivalent Al-Br bonds. To form these bonds, aluminum uses its three valence electrons to make three covalent bonds with three bromine atoms.
The bonding in AlBr3 involves overlapping of hybrid orbitals of aluminum and p-orbitals of three bromine atoms.
In AlBr3, the 3s orbital and two of the 3p orbitals of aluminum hybridize to form three sp2 hybrid orbitals. The hybridization process involves the mixing of one 3s orbital and two 3p orbitals of aluminum to form three sp2 hybrid orbitals.
The remaining 3p orbital of aluminum remains unhybridized and can form a pi-bond with one of the Br atoms.
The three sp2 hybrid orbitals of aluminum arrange themselves in a trigonal planar configuration around the central atom, with bond angles of approximately 120°.
Each of these hybrid orbitals contains a single electron and overlaps with one of the three 2p orbitals of the bromine atoms to form the Al-Br covalent bond.
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T/F: Chemical reactions with free energy changes close to zero are at equilibrium and regulated by concentration of products and reactants.
The given statement "Chemical reactions with free energy changes close to zero are at equilibrium and regulated by concentration of products and reactants." is true. Chemical reactions with free energy changes close to zero are at equilibrium, meaning the forward and reverse reactions occur at equal rates.
At this point, the concentration of products and reactants are constant and regulated by the equilibrium constant, which is determined by the temperature and the stoichiometry of the reaction. Any changes in the concentrations of reactants or products will shift the equilibrium towards the side with lower concentration, until a new equilibrium is established.
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3
5 points
Students mixed two liquids in a beaker and listed their observations.
Observations
Liquid 1 was colorless
Liquid 2 was colorless.
The mixture of liquids 1 and 2 formed a colorless solution.
Small, solid particles formed and fell to the bottom of the beaker.
Based on these observations, which statement contains the best evidence that a chemical reaction occurred?
There is a change in shape.
The two liquids form a new substance.
The two liquids mix into a solution.
There is a change in volume.
The statement that contains the best evidence that the chemical reaction occurred is The two liquids form a new substance.
The chemical change will occur from the chemical reaction, and the physical change occurs is when the matter will changes forms and not the chemical identity. In the physical change, there will be no new substance will formed. The physical change is the type of the change which is reversible change.
The chemical change is the reaction that accompanied by the one or the more new substance. The chemical changes is the change that are irreversible change that is the original substance cannot be formed.
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Please answer the full thing I will mark brianliest <3
1. Balance the following equation and use calculations for average atomic masses to show that both sides of the equation have equal masses. This style of problem was covered in Live Lesson. Show your work. (4 pts)
Mg(OH)2(aq) + HCl(aq) MgCl2(s) + H2O(l)
2. Use Avogadro’s number to determine the number of particles found in 20.0 g of NaCl. Show your work. (3 pts)
3. In a thermite reaction, aluminum powder undergoes a redox reaction with rust. If 55.0 g of aluminum reacts completely, what mass of iron is formed? Start by balancing the equation. Show your work. (3 pts)
Al + Fe2O3 Fe + Al2O3
Answer:
That is the correct explaination for your question
A 100g sample to water at 25. 3 degrees celsius was placed in a calorimeter. 45. 0g of lead shots (at 100 degrees celsius) was added to the calorimeter and the final temperature of the mixture was 34. 4 degrees celsius. What is the specific heat of lead?
The specific heat of lead for 100g sample to water at 25. 3 degrees Celsius was placed in a calorimeter is 0.131 J/g°C.
To solve for the specific heat of lead, we can use the formula:
q = mcΔT
Where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.
We can first calculate the heat absorbed by the water:
q_water = m_water × c_water × ΔT_water
= 100g × 4.18 J/g°C × (34.4°C - 25.3°C)
= 3784 J
We can then calculate the heat released by the lead:
q_lead = m_lead × c_lead × ΔT_lead
= 45g × c_lead × (100°C - 34.4°C)
= 1962g × c_lead
Since the heat lost by the lead is equal to the heat gained by the water, we can set these two equations equal to each other:
q_lead = q_water
1962g × c_lead = 3784 J
Solving for c_lead, we get:
c_lead = 3784 J / (1962g × (100°C - 34.4°C))
= 0.131 J/g°C
Therefore, the specific heat of lead is 0.131 J/g°C.
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2. Use Avogadro's number to determine the number of particles found in 20.0 g of NaCl. Show your
work. (3 pts)
Answer:
That is the correct explaination for the question
What are the signs of δsuniv, δssurr, and δssys, respectively, for water freezing at −10°c?
If the absolute value of ΔSsys is less than ΔSsurr, then ΔSuniv will be positive, indicating a spontaneous process. If the absolute value of ΔSsys is greater than ΔSsurr, then ΔSuniv will be negative, indicating a non-spontaneous process.
1. ΔSsys (Change in entropy of the system): When water freezes, it transitions from a more disordered state (liquid) to a more ordered state (solid). Therefore, the entropy of the system decreases, and the sign of ΔSsys is negative.
2. ΔSsurr (Change in entropy of the surroundings): When water freezes, it releases heat into the surroundings, increasing the entropy of the surroundings. Therefore, the sign of ΔSsurr is positive.
3. ΔSuniv (Change in entropy of the universe): The change in entropy of the universe is the sum of the changes in entropy of the system and the surroundings (ΔSuniv = ΔSsys + ΔSsurr). In this case, since ΔSsys is negative and ΔSsurr is positive, the sign of ΔSuniv depends on the magnitudes of ΔSsys and ΔSsurr.
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List all elements in periodic table.
# of protons
# of neutrons
# of electrons
# of valence electrons
Solid,gas, liquid
Atomic symbol
Ion charge
Answer ASAP pls
The chemical elements are arranged in rows and columns on what is known as the periodic table, or periodic table of the (chemical) elements.
Thus, It is frequently used in physics, chemistry, and other sciences and is frequently regarded as a symbol of chemistry.
It is a visual representation of the periodic law, which claims that the atomic numbers of chemical elements have a roughly periodic relationship with their attributes.
The table is divided into four blocks that are about rectangular in shape. The table's columns are referred to as groups and its rows are known as periods.
Thus, The chemical elements are arranged in rows and columns on what is known as the periodic table, or periodic table of the (chemical) elements.
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what Name functional groups that usually act as acids. Name the functional groups that usually act as bases
The functional groups that usually act as acids include carboxylic acids, phenols, and sulfonic acids. The functional groups that usually act as bases include amines and amidines. Here's a brief explanation:
1. Carboxylic acids (R-COOH) have a weak acidic behavior due to the presence of the acidic carboxyl group (-COOH). They can donate a proton (H+) to a base, forming a carboxylate ion (R-COO-).
2. Phenols (Ar-OH) are aromatic compounds with a hydroxyl group (-OH) attached to a benzene ring. They have acidic properties because the oxygen can donate a proton (H+) to a base, forming a phenoxide ion (Ar-O-).
3. Sulfonic acids (R-SO3H) contain a sulfonic acid group (-SO3H), which can donate a proton (H+) to a base, forming a sulfonate ion (R-SO3-).
1. Amines (R-NH2, R2-NH, or R3-N) have a basic behavior due to the presence of the lone pair of electrons on the nitrogen atom. They can accept a proton (H+) from an acid, forming an ammonium ion (R-NH3+, R2-NH2+, or R3-NH+).
2. Amidines (R-C(=NR')-NR2") are compounds with a nitrogen atom connected to a carbonyl group and another nitrogen with two substituents. The nitrogen with the substituents can accept a proton (H+) from an acid, forming a protonated amidine.
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Which reaction occurs at the cathode of a galvanic cell that has the following: an aluminum electrode in an electrolyte with aluminum ions and a zing electrode in an electrolyte with zinc ions? The reduction potential for the
reduction of A13+ = -1.68 V. The reduction potential for the reduction of Zn2+
-0.76 V.
O A. Zn2+ (ag) + 28
-> Zn(s)
O B. Al(s) - Al$+(34) + 3e
O C. Zn(s) -> Zn2+ (ag) + 2€
O D. AlS*(a9) + 36 -> Al(s)
The reaction that occurs at the cathode of the illustrated galvanic cell is Zn(s) -> Zn2+ (aq) + 2e-. Option C
What is reduction potential?The reaction that occurs at the cathode of a typical galvanic cell depends on the relative reduction potentials of the two half-reactions involved.
In this case, the reduction potential for the reduction of Al3+ (-1.68 V) is more negative than the reduction potential for the reduction of Zn2+ (-0.76 V). This means that the reduction of Al3+ requires more energy than the reduction of Zn2+.
Since the cathode is the site of reduction, the half-reaction with the more positive reduction potential (i.e., the reduction of Zn2+) will occur at the cathode.
Therefore, the correct answer is Zn(s) -> Zn2+ (aq) + 2e-.
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Using the Brønsted-Lowry theory, which compounds from the following list are bases? Select all that apply. CH 3
COOCH 2
HCOOH CHOO −
HNO 3
The Brønsted-Lowry bases from the given compounds are COOCH[tex]^{2}[/tex] and CHOO.
According to the Brønsted-Lowry theory, a base is a substance that can accept a proton ([tex]H^{+}[/tex]). Let's analyze each compound to see if it can act as a base:
CH[tex]_{3}[/tex]: This compound cannot accept a proton, as there is no available lone pair of electrons.
COOCH[tex]^{2}[/tex]: This compound contains an oxygen atom with a lone pair of electrons on the COO- group. It can accept a proton, making it a Brønsted-Lowry base.
HCOOH (formic acid): This compound is an acid, not a base, because it can donate a proton from its COOH group.
CHOO-: This compound contains an oxygen atom with a lone pair of electrons on the O- group. It can accept a proton, making it a Brønsted-Lowry base.
HNO[tex]_{3}[/tex] (nitric acid): This compound is an acid, not a base, because it can donate a proton from its OH group.
To summarize, the Brønsted-Lowry bases in the given list are COOCH[tex]^{2}[/tex] and CHOO-.
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Answer the following question: Ethanol, C2H5OH, is considered clean fuel because it burns in oxygen to produce carbon dioxide and water with few trace pollutants. If 500.0 g of H2O are produced during the combustion of ethanol, how many grams of ethanol were present at the beginning of the reaction? When answering this question include the following:
Have both the unbalanced and balanced chemical equations.
Explain how to find the molar mass of the compounds.
Explain how the balanced chemical equation is used to find the ratio of moles (hint: step 3 in the video).
The numerical answer and the correct units.
424.9 grams of ethanol were present at the beginning of the reaction.
What is molar mass?One mole of a material weighs one molar mass. The standard unit of measurement is grams per mole (g/mol). The atomic weights of the atoms in a molecule or the formula weight of a compound are added up to determine the molar mass.
How do you determine it?For ethanol combustion, the imbalanced chemical equation is:
C₂H₅OH + O₂ =CO₂ + H₂O.
The number of atoms of each element must be equal on both sides of the equation for the equation to be balanced:
C₂H₅OH + 3O₂ = CO₂ + 3H₂O
This equation demonstrates the reaction between one molecule of ethanol and three molecules of oxygen, which results in the production of two molecules of carbon dioxide and three molecules of water.
We must sum the atomic masses of the constituent elements in the compound, multiplied by the number of atoms in each element, to determine the molar mass of ethanol. 2 x 12.01 g/mol of carbon, 6 x 1.01 g/mol of hydrogen, and 16.00 g/mol of oxygen make up the molar mass of C₂H₅OH= 46.07 g/mol.
According to the chemical equation, 3 moles of water are created for every 1 mole of ethanol that interacts. As a result, we can use the following formula to determine how many moles of ethanol were involved in the reaction:
moles of water = moles of ethanol / 3.
We must first determine the quantity of water created in moles. We may do this by dividing the created mass of water by its molar mass:
500.0 g / 18.02 g/mol = 27.7 mol of water is equal to one mole of water. Molar mass of water is equal to the mass of water.
The quantity of ethanol that reacted may then be calculated:
Water moles divided by three equals 27.7 mol divided by three equals 9.23 mol of ethanol.
Using the molar mass of ethanol, we can finally determine the mass of ethanol that reacted:
9.23 moles of ethanol times 46.07 grams per mole of ethanol is 424.9 grams of ethanol in terms of mass.
So, at the start of the reaction, there was around 424.9 g of ethanol.
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Please answer and explain this!!!!
ASAP!!!
Answer:
D. CH=CH
Explanation:
A ground glass joint should be greased before use. Apply____(options: a large glob, a complete coating, a thin line) of grease to____(options: the outer part, both parts, the inner part) of the joint. Then, (options: wipe the joint with a cloth, run a stick around the joint, connect and turn the joint) to distribute the grease. You____(options: should, should not) be able to see the grease in a properly greased joint.
The proper way to grease a ground glass joint is to apply a thin line of grease to the inner part of the joint and then connect and turn the joint to distribute the grease, ensuring that the grease is visible in the properly greased joint.
What is the proper way to grease a ground glass joint?A ground glass joint is commonly used in laboratory glassware to connect two pieces of glassware, such as a flask and a condenser, creating an airtight and leak-proof seal.
To ensure that the joint functions properly, it is essential to grease it before use.
The proper way to grease a ground glass joint is to first apply a thin line of high-vacuum grease or silicone grease to the inner part of the joint, making sure that it is evenly spread.
Then, connect the two pieces of glassware and turn the joint several times to distribute the grease evenly. Finally, inspect the joint to ensure that the grease is visible, indicating that the joint has been properly greased.
This simple procedure helps to prevent leaks and ensures accurate and precise laboratory experiments.
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A DNA backbone is composed of what 2 things? How is it read? Are the two strands antiparallel?
A DNA backbone is composed of sugar (deoxyribose) and phosphate molecules that alternate to form a sugar-phosphate backbone. The sequence of nitrogenous bases (adenine, thymine, cytosine, and guanine) is then attached to this backbone.
A sugar-phosphate-sugar chain forms the "backbone" of DNA. Nitrogenous bases are faced inside. Within a polynucleotide chain, the two nucleotides linked together by a bond, which is called a phosphodiester bond. In nucleotide, phosphoric acid and pentose sugar( deoxyribose) are bonded with phosphoester bond. And pentose sugar and nitrogenous bases are bonded with the N-Glycosidic bond. The two strands of DNA are held together by Hydrogen bonds, which present between nitrogenous bases of the opposing strand.
DNA is read by separating the two strands of the double helix and matching complementary base pairs: adenine with thymine and cytosine with guanine. The two strands of DNA are indeed antiparallel, meaning they run in opposite directions with one strand running from 5' to 3' and the other running from 3' to 5'.
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when 0.10 mol of a weak acid ha was diluted to one liter, experiment showed the acid to be 1% dissociated. what is the acid dissociation constant
The acid dissociation constant (Ka) for the weak acid HA is 0.000111.
To find the acid dissociation constant (Ka) of the weak acid HA, given that 0.10 mol of HA was diluted to one liter and found to be 1% dissociated, follow these steps:
1. Calculate the initial concentration of HA: 0.10 mol / 1 L = 0.10 M
2. Determine the dissociated amount of HA: 1% of 0.10 M = 0.01 M
3. Set up the equilibrium expression: Ka = [H+][A-] / [HA]
4. Write the equilibrium concentrations:
- [H+] = [A-] = 0.01 M (dissociated amount)
- [HA] = 0.10 M - 0.01 M = 0.09 M (initial concentration minus dissociated amount)
5. Substitute the concentrations into the Ka expression:
Ka = (0.01 M)(0.01 M) / (0.09 M)
6. Calculate Ka: Ka = 0.000111
The acid dissociation constant (Ka) for the weak acid HA is 0.000111.
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what is the nucleophile involved in the formation of the bromohydrin product?
a THF b bromide anion с succinimide d wateR
The nucleophile involved in the formation of the bromohydrin product is water.
Bromohydrin is a molecule that contains both a bromine atom and a hydroxyl (-OH) group on adjacent carbon atoms. The formation of a bromohydrin typically involves the addition of bromine to an alkene in the presence of water. The water molecule acts as a nucleophile, attacking one of the carbons in the alkene double bond and forming a cyclic intermediate.
The bromine atom then adds to the other carbon of the alkene, creating a molecule with a bromine atom and a hydroxyl group on adjacent carbons. This reaction is an example of an electrophilic addition, as the electrophile (bromine) is added to the alkene, and the nucleophile (water) attacks the electrophilic carbon.
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How many atoms of hydrogen are in 1 mole of water (H2O)?
Answer:
There are 2 atoms of hydrogen in 1 molecule of water (H2O).
To find the number of atoms of hydrogen in 1 mole of water, we need to multiply the number of hydrogen atoms per molecule by Avogadro's number, which is approximately 6.02 x 10^23.
So, 1 mole of water contains:
2 atoms of hydrogen per molecule x Avogadro's number
= 2 x 6.02 x 10^23
= 1.204 x 10^24 atoms of hydrogen.
Please select the following statement that is NOT true about diazonium salts. a. Aryldiazonium salts are used in the synthesis of commercially available dyes through coupling reactions between activated aromatic compounds. b.Alkyldiazonium salts are likely to decompose and give a variety of products because N2 is far more stable than R-N2, where R is an alkyl group. c.Aryldiazonium salts are moderately stable in water at 0 °C because the System of the aromatic ring stabilizes the п system of the N2+, the diazonium ion. d. Diazotization and coupling reactions must be performed at least 1 suppress the hydrolysis of the diazonium salt.
The statement that is NOT true about diazonium salts is d. Diazotization and coupling reactions must be performed at least 1 suppress the hydrolysis of the diazonium salt.
Diazonium salts are compounds that contain a positive charged nitrogen atom (N⁺) and are commonly used as intermediates in organic synthesis. They are formed through a reaction called diazotization, which involves the conversion of a primary aromatic amine to its corresponding diazonium salt by treating it with nitrous acid.
Aryldiazonium salts (where R is an aryl group) are used in the synthesis of commercially available dyes through coupling reactions between activated aromatic compounds. On the other hand, alkyldiazonium salts (where R is an alkyl group) are unstable and likely to decompose, giving a variety of products because N2 is far more stable than R-N2.
Aryldiazonium salts are moderately stable in water at 0 °C because the system of the aromatic ring stabilizes the pi system of the N2+, the diazonium ion. However, diazonium salts are generally unstable in water and can undergo hydrolysis to produce the corresponding phenol or amine. Therefore, diazotization and coupling reactions must be performed in a dry, organic solvent to suppress the hydrolysis of the diazonium salt.
Therefore, option d is NOT true as it states that diazotization and coupling reactions must be performed to suppress the hydrolysis of the diazonium salt, while in reality, these reactions are performed in dry, organic solvents to avoid hydrolysis.
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This diagram shows a model of an atom. The subatomic particles are labeled.
Model of an Atom
Particles x and y are found in the nucleus and have a positive charge.
Particles x and y are found in the electron cloud and have a negative charge.
Particle z is found in the electron cloud and has a negative charge.
Particle Z is the electron cloud and have a negative charge.
What are the subatomic particles?The electron is found in the orbits of the atom and the electrons are the particles that ahve been marked Z. They have a negative charge and control the chemical activity of the element.
While electrons are present in the orbitals surrounding the nucleus of an atom, protons and neutrons are both found in the atom's nucleus. While the number of electrons in an atom defines its chemical behavior, the number of protons in an atom determines the element it represents.
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define non bonded strain (or van der waals repulsion). In what conformation is this most commonly seen?
Non-bonded strain, also known as van der Waals repulsion, refers to the repulsive forces between two atoms or molecules that are in close proximity but not bonded together. This phenomenon is most commonly seen in the eclipsed conformation of molecules.
Non-bonded strain, also known as van der Waals repulsion, refers to the repulsive forces that occur between non-bonded atoms when they are brought too close to each other. This strain arises due to the overlapping of electron clouds, causing an increase in electron-electron repulsion. This phenomenon is most commonly seen in the eclipsed conformation of molecules. In the eclipsed conformation, atoms are arranged in such a way that they directly overlap one another along the line of sight, leading to increased van der Waals repulsion and higher potential energy. This makes eclipsed conformations less stable compared to their staggered counterparts.
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35 Points and Brainliest!!!
What parts of the electromagnetic spectrum are most commonly analyzed by spectrometers? (please answer with at minimum 2 full sentences. )
Spectrometers are commonly used to analyze the visible, ultraviolet, and infrared regions of the electromagnetic spectrum, depending on the application and the specific properties of the sample being studied.
Numerous types of electromagnetic radiation may be studied using spectrometers. The visible, ultraviolet, and infrared parts of the electromagnetic spectrum, however, are the ones that are most frequently studied.
Because they are within the energy ranges of molecular and atomic transitions, these regions are of great relevance because they may be used to distinguish between various kinds of chemical compounds. These areas are also useful in a wide range of disciplines, including astronomy, biology, and materials science, among others.
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what is the maximum volume of oxygen that can be produced when 150. ml of co2 is passed over 0.500 g of ko2?
The maximum volume of the oxygen which can be produced when the 150. ml of CO₂ is passed over the 0.500 g of the KO₂ is 118 mL.
The chemical equation is :
4KO₂ + 2CO₂ ----> 2K₂CO₃ + 3O₂
The mass of the KO₂ = 0.500 g
The number of moles of KO₂ = mass / molar mass
The molar mass of KO₂ = 71 g/mol
The number of moles of KO₂ = 0.500 / 71
The number of moles of KO₂ = 0.0070 mol
1 mole of the substance = 22.4 L
The volume of the 150 mL = 0.150 L
The volume of oxygen = (3/4) × 0.0070 × 22400
The volume of oxygen = 118 mL.
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a particulate representation from before and after the reaction is shown below. the contents of the container before the reaction are represented in the box on the left, and the contents of the container after the reaction are shown in the box on the right. a student claims that n2 is the limiting reactant. do you agree or disagree?
Yes I agree that N₂ is the limiting reagent.
Generally, limiting reagent is defined as a substance that does not allow a chemical reaction to take place completely. Basically, if in a chemical reaction limiting reagent is involved , then the atoms/molecules/ions of the other reactant with which it (limiting reagent ) combines will remain free or will remain unreacted.
Yes, I absolutely agree that N₂ is a limiting reactant because you can clearly see that in the right box that after the reaction N₂ gets completely consumed ( not left over ) and is not present in excess. So, N₂ is limiting reactant.
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Hello! If you don’t mind can you answer this question please.
Celium sulfate is a substance that is more soluble at lower temperatures than at higher temperatures.
How to interpret the graph given?The graph provided shows the solubility of different substances at different temperatures; in this graph, the temperature is represented on the horizontal axis, while the solubility is represented on the vertical axis. Most of the substances show a positive pending, which means as temperature increases solubility also increases. This does not occur with celium sulfate as solubility decreases with temperature.
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Alpha carbons are _________ (acidic/basic), meaning they want to ____________ (accept/donate) electrons by __________ (accepting/donating) protons. This results in a _______ (carbocation/carbanion).
Alpha carbons are acidic, meaning they want to accept electrons by donating protons. This results in a carbanion.
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