Which ordered pairs represent points on the graph of this equation? Select all that apply.
–5/6x=y+1/6
(-5,4)
(-7,5)
(0,2)
(6,7)
(-5,-6)
(1,-1)

Answer:41.5

Step-by-step explanation:

By arranging the data from smallest to largest, like this:

40, 41, 42, 45, we can take the average of the two middle values divided by 2 to find the median. This is done with an equation like this:

(41+42)/2

Which comes out to be 41.5.

The solution is, : Factor out the greatest common factor, then solving the equation 4(2x – 1) + 8 = 4x + 24, we get, x=5.

Here, we have,

given that,

4(2x – 1) + 8 = 4x + 24.

Factor out a 4 from each side

4{ 2x-1 +2} = 4(x+6)

Cancel the 4 on each side

2x-1+2 = x+6

Combine like terms

2x+1 = x+6

Subtract x from each side

2x+1-x = x+6-x

x+1 = 6

Subtract 1 from each side

x+1-1 = 6-1

x = 5

Factor out the greatest common factor, then solving the equation 4(2x – 1) + 8 = 4x + 24, we get, x=5.

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complete question:

Solve the equation 4(2x – 1) + 8 = 4x + 24. Factor out the greatest common factor, then

solve.

The dimensions of the box that minimize the amount of material used are a base side length of 25 cm and a height of 25 cm.

Let x be the side length of the square base and h be the height of the box. Since the box has a square base, the volume of the box is V = x²h. We want to minimize the amount of material used, which is given by the surface area of the box, A = x² + 4xh.

Using the volume constraint, we can solve for h in terms of x: h = V / x² = 62,500 / x². Substituting this into the expression for A, we get A = x² + 4x(62,500 / x²) = x² + 250,000 / x.

To minimize A, we take its derivative with respect to x and set it equal to zero: dA/dx = 2x - 250,000 / x² = 0. Solving for x, we get x = 25 cm. Substituting this back into the expression for h, we get h = 25 cm.

Therefore, base side length is 25 cm and height is 25 cm.

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Answer: 204cm²

Step-by-step explanation:

I assume you are trying to work out the area of the shaded section as you have not provided a question?

1. To get the area of the whole rectangle we do length x width.

12 x 20 = 240.

2. To get the area of the triangle we do base x height, ÷ 2.

9 x 8 = 72

72 ÷ 2 = 36

3. Then to get the area of the shaded section we do the area of the rectangle - the area of the triangle

240 - 36 = 204

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The ordered pair that could be another vertex of the square is (2, 6).

The other vertices of the square must be located either 3 units to the right or 3 units to the left of (5, 3), and either 3 units above or 3 units below (5, 3).

(4, 9) is not 3 units away horizontally or vertically from (5, 3), so it cannot be another vertex of the square.

(6, 3) is 3 units to the right of (5, 3), but it is not 3 units above or below (5, 3), so it cannot be another vertex of the square.

(1, 0) is too far away from (5, 3) to be another vertex of the square.

(2, 6) is 3 units to the left of (5, 3) and 3 units above (5, 3), so it could be another vertex of the square.

Therefore, the ordered pair that could be another vertex of the square is (2, 6).

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(a) The algorithm fails when the initial choices of w and h are not of full rank.

(b) The entries of h and w may not always be non-negative, but the algorithm aims for non-negative matrix factorisation.

(c) The algorithm is used to compute a nonnegative matrix factorisation of A = [6 8] using iterative updates of w and h.

(a) An example of a situation where the algorithm would fail is when the initial choices of w and h are not of full rank. In this case, the iterative computation of h and w would not converge to the rank r factorisation of matrix A.

(b) If the algorithm does not fail and the iterative computation of h and w converges to the rank r factorisation of matrix A, then the entries of h and w may not always be non-negative. However, the algorithm is designed to find a non-negative matrix factorisation, so it is expected that the entries of h and w will be non-negative in most cases.

(c) Using the given algorithm, we can compute the rank r nonnegative matrix factorisation of matrix A as follows:

- Set w to be a 2x1 matrix of random non-negative values, and h to be a 1x2 matrix of random non-negative values, both of full rank.
- Compute h = h .* (w' * A) ./ (w' * w * h) and w = w .* (A * h') ./ (w * h * h'), where .* denotes element-wise multiplication, and ' denotes matrix transpose.
- Repeat step 2 until convergence is achieved, or a maximum number of iterations is reached.

Using this algorithm, we can compute the nonnegative matrix factorisation of matrix A as:

w = [0.1829; 0.9119]
h = [3.6953 4.9237]

where w and h are non-negative matrices of rank 1 that satisfy A = w * h.

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The area of triangle RST is 27 square units.

Option A is the correct answer.

We have,

To find the area of the triangle RST, we can use the formula:

Area = 1/2 x base x height

where the base is the distance between any two of the vertices, and the height is the perpendicular distance from the third vertex to the line containing the base.

Let's take RS as the base.

The distance between R and S is 2 + 7 = 9 units.

To find the height, we need to determine the equation of the line containing the base RS, and then find the distance from vertex T to this line.

The slope of the line RS is:

(y2 - y1)/(x2 - x1) = (-7 - 2) / (-9-(-9)) = -9/0,

which is undefined.

This means that the line is vertical and has the equation x = -9.

The perpendicular distance from T to the line x = -9 is simply the horizontal distance between T and the point (-9,-7), which is 6 units.

Therefore,

The area of triangle RST is:

Area = 1/2 x base x height = 1/2 x 9 x 6 = 27 square units.

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The sample standard deviation is approximately 15.29 miles.

Using the formula for sample standard deviation:

Find the mean of the data:

mean = (11 + 6 + 36 + 16 + 5 + 40) / 6 = 114 / 6 = 19

Subtract the mean from each data point, square the result, and sum the squares:

[tex](11 - 19)^2 + (6 - 19)^2 + (36 - 19)^2 + (16 - 19)^2 + (5 - 19)^2 + (40 - 19)^2\\= (-8)^2 + (-13)^2 + 17^2 + (-3)^2 + (-14)^2 + 21^264 + 169 + 289 + 9 + 196 + 441\\= 1168[/tex]

Divide the sum of squares by (n-1), where n is the sample size:

[tex]s^2 = 1168 / (6-1) = 233.6[/tex]

Take the square root of [tex]s^2[/tex] to find the sample standard deviation:

s = sqrt(233.6) ≈ 15.29

Therefore, the sample standard deviation is approximately 15.29 miles.

The deviation is a metric used in statistics and mathematics to determine how different a variable's observed value and predicted value are from one another. The deviation is the distance from the centre point, to put it simply.

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The x-coordinates changed awhile the y-coordinates stayed the same

A reflection over the y-axis is a transformation in mathematics which entails 'flipping' a shape or object across the y-axis, the vertical axis of a Cartesian coordinate plane.

All points on the flipped shape or object will be reflected with respect to the y-axis; points initially residing to the right of the y-axis now appear to the left, whereas points that were originally to the left have been shifted to the correct side of the y-axis.

The points that marked the intersection of the y-axis with the graph remain identical, as they are equidistant from each end.

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The solution and value of x include the following: B. x = 3.

In order to evaluate and solve this equation, we would have to apply the PEMDAS rule, where mathematical operations within the parenthesis (grouping symbols) are first of all evaluated, followed by exponent, and then multiplication or division from the left side of the equation to the right. Lastly, the mathematical operations of addition or subtraction would be performed from left to right.

Based on the information provided, we have the following mathematical equation:

2x + 4 = 10.

By subtracting 4 from both sides of the equation, we have the following:

2x + 4 - 4 = 10 - 4

2x = 6

x = 6/2

x = 3.

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Complete Question:

Solve 2x + 4 = 10.

OA. x = 5

OB. x=3

OC. x = -3

OD. x = 7

Answer: 9:51

Step-by-step explanation:

The steady-state equilibrium level of labor in the decentralised market economy is the same as the centralised allocation of labor that is optimally chosen by the representative household.

To find the steady-state equilibrium level of labor, we need to set the time derivative of labor to zero in equation (11.18):

dK/dt = 0 = RK + W(1 - * ) - C - 8*K

Solving for * , we get:

W*(1 - * ) = C + (R - 8)*K

Dividing both sides by W and rearranging, we get:

1 - * = (C/W) + [(R/W) - (8/W)]*K

Now, we substitute the expression for consumption from equation (11.17):

C = e-pt[In(Ct) + Bln(1 - * )]dt

Taking the derivative of the above equation with respect to * , we get:

dC/d* = -B*e-pt/(1 - * )

Substituting this expression for C in the equation for * , we get:

1 - * = [e-pt/W]*[-B/(1 - * ) + (R/W) - (8/W)]*K

Multiplying both sides by (1 - * ) and rearranging, we get:

(1 + B/W)* * = 1 + (R/W) - (8/W)

Simplifying, we get:

= [1/(1 + B/W)]*[1 + (R/W) - (8/W)]

Substituting the expression for a from equation (11.16), we get:

= 1/[1 + B/(1 - a)]*[1 + (R/W) - (8/W)]

Simplifying further, we get:

= 1/[1 + B/(1 - a)]*[1 - a + a(R/W) - a(8/W)]

= [1 - a + a(R/W) - a(8/W)]/[1 + B - Ba]

Substituting the values of a, R, and W from equations (10.25), (10.24), and (11.6), respectively, we get:

= 1/[1 + B/(1 + p)]*[1 - (1 + p) + (1 + p)(d + n)/w - (1 + p)(1 - d - n)/w]

Simplifying further, we get:

= 1/[1 + B/(1 + p)]*[p/(1 + p) + (d + n - (1 - d - n)(1 + p))/(1 + p)]

= 1/[1 + B/(1 + p)]*[p/(1 + p) + (2d + n - 1 - np)/(1 + p)]

= [p + (2d + n - 1 - np)*[1 + p/(B + 1)]]/[1 + p(B + 1)/(B + 1)]

Simplifying the above expression, we get:

= [p + (2d + n - 1 - np)*(B + 2)/(B + 1)]/[Bp/(B + 1) + p + 1]

This is the same expression as equation (10.26) in the centralised economy of the Ramsey model. Therefore, the steady-state equilibrium level of labor in the decentralised market economy is the same as the centralised allocation of labor that is optimally chosen by the representative household.

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Answer: 84

Step-by-step explanation:

Sorry if this is wrong.

Answer:

(x+10)² + (y+5)² = 125

Step-by-step explanation:

We are given that a circle has a center (-10,-5), and passes through the point (-5,5).

We want to write the equation of this circle in the standard equation. The standard equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

As we are already given the center point, we can substitute its values into the equation.

Reminder: the equation uses negative values, and we have negative numbers.

(x--10)² + (y--5)² = r²

This can be simplified to:

(x+10)² + (y+5)² = r²

Now, we need to find r².

As the point passes through (-5,5), we can use its values to solve for r².

Substitute -5 as x and 5 as y.

(-5+10)² + (5+5)² = r²

(5)² + (10)² = r²

25 + 100 = r²

125=r²

The radius is 125

Substitute 125 as r².

(x+10)² + (y+5)² = 125

Answer:

65%

Step-by-step explanation:

ITS CORRECT

a)  The bias does not approach zero as A approaches infinity, e^-X is not asymptotically unbiased.

b)  if Y₁ is the best unbiased estimator of P(X=0), we need to compare its MSE with the MSE of any other unbiased estimator.

c) in terms of MSE, Y₁ is better than e^-X with n = 10 and λ = 1.

(a) To check if e^-X is an unbiased estimator of P(X=0), we need to calculate its expected value and check if it is equal to P(X=0).

The moment generating function of Poi(A) is M(t) = exp(A(e^t -1)), and the moment generating function of -X is M(-t) = exp(A(1 - e^t)).

Using the moment generating function of -X, we can calculate the expected value of e^-X as follows:

E(e^-X) = E(exp(-X log(e))) = M(-log(e)) = exp(A(1 - e^-1))

Now, we need to check if E(e^-X) = P(X=0). Since P(X=0) = exp(-A), we can see that the estimator e^-X is biased. The bias is given by B(e^-X) = E(e^-X) - P(X=0) = exp(A(1-e^-1)) - exp(-A).

To check if the bias is asymptotically unbiased, we need to take the limit as A approaches infinity.

lim(A → ∞) B(e^-X) = lim(A → ∞) exp(A(1-e^-1)) - exp(-A) = ∞

Since the bias does not approach zero as A approaches infinity, e^-X is not asymptotically unbiased.

To check if e^-X is the best unbiased estimator of P(X=0), we need to compare its mean squared error (MSE) with the MSE of any other unbiased estimator.

(b) Y₁ is an unbiased estimator of P(X=0) if P(Y₁ = 1) = P(X=0) and P(Y₁ = 0) = 1 - P(X=0). Since Y₁ Ber(P(X=0)), we have

P(Y₁ = 1) = P(X=0) and P(Y₁ = 0) = 1 - P(X=0), which means that Y₁ is an unbiased estimator of P(X=0).

The bias of Y₁ is zero, so it is unbiased and there is no need to check if it is asymptotically unbiased. To check if Y₁ is the best unbiased estimator of P(X=0), we need to compare its MSE with the MSE of any other unbiased estimator.

(c) Using the fact that E(Xi) = λ and Var(Xi) = λ, we can calculate the MSE of e^-X and Y₁ as follows:

MSE(e^-X) = E((e^-X - P(X=0))^2) = Var(e^-X) + B(e^-X)^2 = exp(A(e^-1 - 2)) + (exp(A(1-e^-1)) - exp(-A))^2 - exp(-2A)

MSE(Y₁) = E((Y₁ - P(X=0))^2) = Var(Y₁) = P(X=0)(1-P(X=0)) = exp(-λ)(1-exp(-λ))

Substituting n = 10 and λ = 1, we get:

MSE(e^-X) ≈ 0.1381 + (exp(9)(1-e^-9))^2 - exp(-2) ≈ 1.3869

MSE(Y₁) ≈ exp(-1)(1-exp(-1)) ≈ 0.3935

Therefore, in terms of MSE, Y₁ is better than e^-X with n = 10 and λ = 1.

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Answer:

-2,2 + (2)-4 =?

Step-by-step explanation:

if you add y+-3r that would actually be the correct answer

Answer:

Choice C  y = -3x - 4

Step-by-step explanation:

slope is negative (line slants down), so you can toss out answer D.

y-intercept is -4 (where the line crosses the y axis), so you can toss out answers  A and B.

That leaves C as the right answer.

Just to prove that the slope = -3, calculate it:

y = (-4-2) / (0--2) = -6/2 = -3

It would take 2.083 hours to cover 1100 miles.

We have,

Speed= 528 mph

Distance = 1100 miles

Using speed = Distance/ time

So, Time = Distance/ speed

Time = 1100 / 528

Time = 2.083 hour

Thus, the time taken 2.083 hour.

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Answer:

The z-score is calculated as follows:

z = (x - μ) / σ

where x is the value of interest, μ is the mean, and σ is the standard deviation.

Plugging in the values given, we get:

z = (86 - 62) / 12 = 2

Therefore, the z-score for a value of 86 is 2.

The answer is (C) 2.

Step-by-step explanation:

The number of liters it would take to cover 120 km is 8 liters.

Looking at the graph that shows the liters consumed per kilometer, or rather the number of kilometers per liter, we see that each liter enables to car to go for 15 km.

This means that if we should want to go 120 km, the number of liters needed would be:

= Distance to cover / Kilometers per liter

Distance to cover = 120 km

Kilometers per liter = 15 km

The liters needed are:

= 120 / 15

= 8 liters

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The 90% confidence interval for the population mean is (-9.05, 15.05).

To construct a confidence interval for a population mean with a known standard deviation when the sample size is less than 30, we use the formula:

CI = x ± z*(σ/√n)

where x is the sample mean, σ is the population standard deviation, n is the sample size, z is the z-score associated with the desired confidence level, and CI is the confidence interval.

Given the information provided, we have:

x = 3

σ = 26

n = 15

The desired confidence level is 90%, which corresponds to a z-score of 1.645 (from the standard normal distribution table)

Substituting these values into the formula, we get:

CI = 3 ± 1.645*(26/√15)

CI = 3 ± 12.05

Therefore, the 90% confidence interval for the population mean is (-9.05, 15.05).

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the answer to your math question is x=-7

Hi! To find the level of marketing expenditure that will maximize sales and the maximum sales value, we can follow these steps:

1. The relationship between marketing expenditure (x) and sales (y) is given by the formula: y = 9x - 0.20x^2 + 8.
2. To maximize sales, we need to find the maximum point of this quadratic function, which can be done by finding the vertex.
3. The vertex formula for a quadratic function is: x = -b / (2a), where a and b are coefficients in the equation (in this case, a = -0.20 and b = 9).
4. Calculate x (marketing expenditure) for the vertex: x = -9 / (2 * -0.20) = -9 / -0.40 = 22.50.
5. Round the marketing expenditure to 2 decimal places: 22.50.
6. Plug the marketing expenditure value (x) back into the sales formula to find the maximum sales value (y): y = 9(22.50) - 0.20(22.50)^2 + 8.
7. Calculate y: y = 202.50 - 0.20(506.25) + 8 = 202.50 - 101.25 + 8 = 109.25.
8. Round the maximum sales value to 2 decimal places: 109.25.

So, the level of marketing expenditure that will maximize sales is $22.50, and the maximum sales value is $109.25.

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A graph that shows the line y = –3/4 x + 1 is: A. The graph with the X-coordinate marks -4, -2, 0, 2, and 4. The Y-coordinate mark -4, -2, 0, 2, and 4. There is line which intersects y-axis at (0, 1) and x-axis at (3, -3).

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical expression:

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (3 - 0)/(-3 - 1)

Slope (m) = -3/4

At data point (0, 1) and a slope of -3/4, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 1 = -3/4(x - 0)  

y = -3x/4 + 1

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Complete Question;

Which graph shows the line y = –3/4 x + 1?

Step-by-step explanation:

Area of base ( 1/2 *  L1  *  L2 )     *  height = volume

            1/2 ( 7)(8)     *   5 =  140 in^3

The value of the equation 5- c  for c = 3 will be  2.

Since the solution of an equation refers usually to the values of the variables involved in that equation which if substituted in place of that variable would give a true mathematical statement.

We need to find the solutions does the equation 5 - c for c = 3;

Now solving for c;

5-c

for c = 3

5 - 3 = 2

Therefore, the value is 2.

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If Charlotte will take out the garbage for 15 weeks,  Charlotte will earn 327.67 dollars on the 15th week.

To find how much Charlotte will earn on the 15th week, we can use the formula for the sum of a geometric series:

Sₙ = a(1 - rⁿ) / (1 - r)

where Sₙ is the sum of the first n terms of the series, a is the first term, r is the common ratio, and n is the number of terms.

In this case, a = 1 cent, r = 2 (since each week Charlotte earns twice as much as she did the week before), and n = 15. Substituting these values into the formula gives:

S₁₅ = 1(1 - 2¹⁵) / (1 - 2)

S₁₅ = (1 - 32768) / (-1)

S₁₅ = 32767 cents

Therefore, Charlotte will earn 327.67 dollars on the 15th week.

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