Which polygon does not belong with the others?

Which Polygon Does Not Belong With The Others?

Answers

Answer 1
The second one. The octagon.

This is because all of the other choices are equal sided, which makes them a regular polygon.

Related Questions

Find the value of y.
answer choices
A. 118
B. 32.5
C. 65
D. 130

Answers

The value of 'y' is 32. 5 degrees . Option B

How to determine the value

It is important to note that If two chords intersect inside a circle,

The measure of the angle formed is half the sum of the measure of the arcs intercepted by the angle and its vertical angle

From the diagram, it is shown that the both the chords at 'y' and the angle '65' intersect in the circle

We then have that;

[tex]y = 65[/tex] × [tex]\frac{1}{2}[/tex]

[tex]y = 65[/tex] × [tex]0. 5[/tex]

y = 32. 5 degrees

We can see that the value of 'y' in the given figure is 32. 5 degrees which is half the angle at the vertex of the intersecting chords.

Thus, the value of 'y' is 32. 5 degrees . Option B

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Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0

Answers

If you do in fact mean [tex]f(1)=f(6)=0[/tex] (as opposed to one of these being the derivative of [tex]f[/tex] at some point), then integrating twice gives

[tex]f''(x) = -\dfrac1{x^2}[/tex]

[tex]f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1[/tex]

[tex]f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2[/tex]

From the initial conditions, we find

[tex]f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0[/tex]

[tex]f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)[/tex]

Eliminating [tex]C_2[/tex], we get

[tex](C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))[/tex]

[tex]-5C_1 = \ln(6)[/tex]

[tex]C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)[/tex]

Then

[tex]\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}[/tex]

Evaluate each expression if A=2
B=-3. C=-1. D=4


2d-a/b

Answers

Answer:

2 × 4 - 2 / -3

8-2/-3

6/-3

-2

find the area of a triangular shaped land having the length of three sides 20,34 M and 42 respectively in metre square Anna and ropani​

Answers

Step-by-step explanation:

if I understand you correctly, then the 3 sides are

a = 20 m

b = 34 m

c = 42 m

under this assumption the best is to use Heron's Formula to get the area :

s = (a + b + c)/2

area = sqrt(s(s - a)(s - b)(s - c))

in our case

s = (20 + 34 + 42)/2 = 96/2 = 48

area = sqrt(48(48-20)(48-34)(48-42)) =

= sqrt(48×28×14×6) = sqrt(112,896) =

= 336 m²

Answer:

sorry i didnt know this D: <3

Step-by-step explanation:

ONE HUNDRED LOTTERY TICKETS ARE SOLD FOR $5.00 EACH. ONE PRIZE OF $300
WILL BE AWARDED. STEVE PURCHASES ONE TICKET. FIND HIS EXPECTATION.

Answers

1/100 tickets = 1% chance = 0.01
$5 spent on 1 ticket

0.01(300) - 5
3-5
-$2

Rachel is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove to get to the safe zone at 242424 meters per second. After 444 seconds of driving, she was 707070 meters away from the safe zone.
Let yyy represent the distance (in meters) from the safe zone after xxx seconds.
Complete the equation for the relationship between the distance and number of seconds.

Answers

The distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone. This can be obtained by converting the conditions to equations.

Find the equation for the relationship between the distance and number of seconds:

A linear function containing one dependent and one independent variable.

It can be represented using the equation,

y = mx + c

where m is the slope

It is given in the question that,

Rachel is a stunt driver and one time during a gig where she escaped from a building about to explode she drove to get to the safe zone at 24 meters per second.

After 4 seconds of driving, she was 70 meters away from the safe zone.

Let, D(t) be the distance to the safe zone (measured in meters) and t be the  time (measured in seconds)

After 4 seconds of driving, she was 70 meters away from the safe zone.

⇒ This means that at t = 4 seconds, D(4) = 70 meters

Rachel's rate is the slope of the function D(t). Since the distance is decreasing when the time is increasing, the slope must be negative

m = - 24

y = mx + c

⇒ D(t) = (-24)t + c

Put t = 4,

D(4) = (-24)4 + c

70 = -96 + c ⇒ c = 166

D(t) = 166 - 24t

Hence the distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone.

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Given the following function, find f(-5), f(0), and f(3).
f(x) = x^2+5

Answers

Answer:

f(-5) = 30

f(0) = 5

f(3) = 14

Step-by-step explanation:

=> f(x) = x²+5

for , f(-5) = (-5)² +5

=> 25 +5

=> 30

for , f(0) = (0)² +5

=> 5

for , f(3) = (3)² + 5

=> 9 + 5

=> 14

can you answer this question

Answers

Based on the given entries that Jonathan Shaw owes and owns, the Balance Sheet can be drawn below.

What is Jonathan Shaw's balance sheet?

The assets will go to the right side of the sheet and the liabilities and equity will go to the left.

                                            Jon's Shop of Gifts Balance Sheet

Assets                                                                                          Liabilities

Cash                                    $2,556           Bank loan                    $19,000

Accounts Receivable:         $450             Accounts Payable -           $900

R. Gregory                                                 Ceramic supply

Accounts Receivable:         $1,860          Accounts Payable -           $2,900

R. Gregory                                                 Jose's Art Co.

Supplies                               $1,000         Total liabilities                 $22,800

Furniture                              $10,300       Equity

Equipment                           $20,000       Jonathan Shaw capital  $51,166

Automobiles                       $37,800         Total equity                   $51,166

Total assets                       $73,966        Total liabilities and          $73,966

                                                                  equity

The equity can be found as:

= Assets - liabilities

= 73,966 - 22,800

= $51,166

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please help me im begging you help me i beg u :(

Answers

A. 3.14159…

A rational number either terminates (stops) or repeats. Since 3.14159… will go on forever without ending or repeating a pattern, it is not rational.

ill give brainliest


Directions: Factor the following trinomials containing negative numbers. Follow the rules for operations with signed numbers to identify the correct binomial factors.

1. x2 + 6x - 7

2. x2 - 5x + 6

3. x2 - 6x - 7

4. x2 + 5x - 6

5. x2 + x - 12

6. x2 - 2x - 8

7. x2 - 4x - 5

8. x2 + 2x - 3

9. x2 - 16

10. x2 - x - 12

11. x2 -9x + 18

12. x2 -5x - 14

13. x2 - 7x + 10

14. x2 -11x + 24

15. x2 - x - 30

Answers

The aim of factorization to obtain the common factors that are present in the expression.

What are factors?

When we factorize an expression, the aim is to obtain the common factors that are present in the expression.

Now we have trinomials numbered 1 - 15. Trinomial is an expression that is made up of three terms. Quadratic expressions are mostly found to appear as trinomial

The binomial factors that are associated with each are shown in the factorized expressions below. The binomials contain two terms in each bracket.

Given the trinomials, the correct binomial factors are;

(x−1)(x+7) (x−2)(x−3)(x+1)(x−7) (x−1)(x+6)(x−3)(x+4)(x+2)(x−4)(x+1)(x−5)(x−1)(x+3) (x+4)(x−4)(x+3)(x−4)(x−3)(x−6)(x+2)(x−7)(x−2)(x−5) (x−3)(x−8) (x+5)(x−6)

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find derivative of y= sin x sin 3x​

Answers

The derivative of y= sin x sin 3x​ is [tex]$=3 \cos x-3 \cos 3 x$[/tex]

What is a derivative?Futures contracts, options contracts, and credit default swaps are typical types of derivatives. Beyond this, a sizable number of derivative contracts satisfy the requirements of a wide range of counterparties.

To find the derivative of y= sin x sin 3x​:

[tex]$y=3 \sin (x)-\sin (3 x)$[/tex]

[tex]$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$[/tex]

[tex]$y^{\prime}=3(\cos x-\cos 3 x)$[/tex]

[tex]\frac{dx}{dy} =3 cosx - 3 cos x[/tex]

Differentiate [tex]sin 3x[/tex] using the chain rule

Given [tex]y=f^{'} (g(x))*g^{'}[/tex]←chain rule

y=[tex]y=3 sin x-sin 3x[/tex]

[tex]\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)[/tex]

[tex]=3cosx-3cos3x[/tex]

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The controller of MingWare Ceramics Inc. wishes to prepare a cost of goods sold budget for September. The controller assembled the following information for constructing the cost of goods sold budget: Direct materials: Enamel Paint Porcelain Total Total direct materials purchases budgeted for September $35,870 $7,530 $139,890 $183,290 Estimated inventory, September 1 1,730 4,150 6,920 12,800 Desired inventory, September 30 2,980 2,710 7,150 12,840 Direct labor cost: Kiln Department Decorating Department Total Total direct labor cost budgeted for September $51,550 $149,500 $201,050 Finished goods inventories: Dish Bowl Figurine Total Estimated inventory, September 1 $5,810 $3,310 $2,730 $11,850 Desired inventory, September 30 3,720 4,590 4,360 12,670 Work in process inventories: Estimated inventory, September 1 $3,540 Desired inventory, September 30 1,980 Budgeted factory overhead costs for September: Indirect factory wages $80,400 Depreciation of plant and equipment 10,550 Power and light 5,110 Indirect materials 3,390 Total 99,450 Use the preceding information to prepare a cost of goods sold budget for September. For those boxes in which you must enter subtracted or negative numbers use a minus sign. MingWare Ceramics Inc. Cost of Goods Sold Budget For the Month Ending September 30 Finished goods inventory, September 1 $Finished goods inventory, September 1 Direct labor $Direct labor Direct materials: $- Select - - Select - $- Select - - Select - $- Select - Direct labor fill in the blank 15 - Select - - Select - $- Select - Work in process inventory, September 30 fill in the blank 22 - Select - $- Select - - Select - $- Select - 4,100

Answers

The preparation of the Cost of Goods Sold Budget for MingWare Ceramics Inc. in September is as follows:

Cost of Goods Sold Budget:

Beginning inventory of finished goods $11,850

Cost of goods manufactured                485,310

Ending inventory of finished goods      (12,670)

Cost of Goods Sold                          $484,490

What is the cost of goods sold budget?

The cost of goods sold budget sums the costs of the beginning inventory of finished goods with the cost of goods manufactured and subtracts the ending inventory of finished goods.

The cost of goods sold budget is based on the cost of goods manufactured budget.

Data and Calculations:

Direct materials:                            Enamel        Paint     Porcelain      Total    

Total direct materials purchases

budgeted for September            $35,870    $7,530    $139,890  $183,290

Estimated inventory, September 1   1,730        4,150          6,920      12,800 Desired inventory, September 30 (2,980)      (2,710)         (7,150)    (12,840)

Materials used in production                                                          $183,250

Direct labor cost:           Kiln Department    Decorating Department   Total

Total direct labor cost

 budgeted for September    $51,550                   $149,500        $201,050

Finished goods inventories:             Dish       Bowl     Figurine             Total

Estimated inventory, September 1  $5,810   $3,310     $2,730        $11,850

Desired inventory, September 30    3,720    4,590       4,360         12,670

Cost of goods manufactured budget:

Work in process inventories:

 Estimated inventory, September 1      $3,540

Direct materials used in production $183,250

Direct labor costs                              $201,050

Total factory overhead costs             $99,450

 Desired inventory, September 30       (1,980)

Cost of goods manufactured           $485,310

Budgeted factory overhead costs for September:

Indirect factory wages $80,400

Depreciation of plant and equipment 10,550

Power and light 5,110

Indirect materials 3,390

Total 99,450

Thus, to prepare the cost of goods sold, as above, MingWare Ceramics, requires to determine the cost of goods manufactured for September.

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It takes Natalie's mother 20 minutes to drive to work. She works 6 miles away.
If she drives the same speed to pick up Natalie at a friend's house that is 14 miles
away, about how long will the drive take?
A 8.7 minutes
B 2.4 minutes
C 45.7 minutes
D 705 minutes

Answers

Answer:

B. 45.7

Step-by-step explanation:

20/6=3.33

3.33*14=46.62

46.62 is closest to 45.7

Therefore, 45.7 is the best answer.

A cylinder has radius of 4 inches and height 10inches.There’s a small cylinder inside the previous cylinder of radius of 2 inches with the same height and same centre.What is total surface area?

Answers

The surface area of the cylinder is 48π inches².

How to find the Surface area of a cylinder?

Surface area of a cylinder = 2πr(r + h)

where

r = radiush = height

Therefore,

Surface area of the smaller cylinder = 2 × π × 2(2 + 10)

Surface area of the smaller cylinder = 4π(12)

Surface area of the smaller cylinder = 48π

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27. Identify the domain of the set (6,2), (-1,-5), (4,4), (9, 2) and tell if the relation is a function.
O {-1, 4, 6, 9); not a function
O {-5, 2, 4}; a function
O {-1,4,6,9}; a function
O {-5, 2, 4); not a function

Answers

Answer:

the third one

Step-by-step explanation:

it is function that contain four domain

DIRE NEED OF HELP, pleaseee help
(not a lot of points sorry)

Answers

Answer:

C. Subtract 4 from both sides.

Step-by-step explanation:

You need the equation in the form x² + ax + b = 0 to then either try factoring or use the quadratic formula.

In order to achieve that, you need to first:

Subtract 4 from both sides.

Underwood Company is preparing its annual profit plan. As part of its analysis of the profitability of individual products, the controller estimates the amount of manufacturing overhead that should be assigned to each of the two product lines from the information given below. Wall Mirrors Specialty Windows Total units produced 30 30 Total number of material moves 7 18 Direct labor hours per unit 145 145 Budgeted material-handling costs are $30,000. The material-handling cost per wall mirror under activity-based costing is:

Answers

The material-handling cost per wall mirror under activity-based costing is $280

What is activity-based costing?

Activity-based costing involves absorbing overheads based on cost drivers which directly impact the incurrence of the overhead, in this case, material moves determine the amount of material-handling costs to be incurred, hence, material-handing overheads would be absorbed into the two products based on material moves, which is the appropriate cost driver.

There 25 materials move in both divisions (i.e. 7+18=25)

Material-handling cost per material move=Budgeted material-handling costs /total material moves

Budgeted material-handling costs =$30,000

Material-handling cost per material move=$30,000/25

Material-handling cost per material move=$1,200

Total material-handing costs for wall mirror=number of material moves for wall mirror*Material-handling cost per material move

Total material-handing costs for wall mirror=7*$120

Total material-handing costs for wall mirror=$8,400

material-handling cost per wall mirror=Total material-handing costs for wall mirror/number of wall mirrors

material-handling cost per wall mirror=$8,400/30

material-handling cost per wall mirror=$280

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which expression gives the value of QR?
a. 67 sin 80 degrees over sin 52 degrees
b. 67 sin 52 degrees over sin 80 degrees
c. 51 tan 52 degrees
d. 51 sin 80 degrees over cos 52 degrees

Answers

Answer:

B

Step-by-step explanation:

using the Sine Rule in Δ QRS

[tex]\frac{QR}{sinS}[/tex] = [tex]\frac{RS}{sinQ}[/tex] ( substitute values )

[tex]\frac{QR}{sin52}[/tex] = [tex]\frac{67}{sin80}[/tex] ( cross- multiply )

QR × sin80° = 67 × sin52° ( divide both sides by sin80° )

QR = [tex]\frac{67sin52}{sin80}[/tex]

Manufacturers of tires report that car tires should be able to last an average of 50,000 miles. A new tire company produces a different type of tread and tests 100 randomly selected tires. This sample of 100 tires lasted an average of 51,500 miles. Assuming the new type of tread does not improve the mileage of the tire, 200 sample means were simulated and displayed on the dotplot.



Using the dotplot and the sample mean mileage, is there convincing evidence that the new type of tread improves the mileage of the tire?

Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
Yes, because a mean mileage of 51,500 or less occurred 186 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
No, because a mean mileage of 51,500 or less occurred 186 out of 200 times, the mean mileage is not statistically significant. There is not convincing evidence the new type of tire tread improves mileage of the tire.
No, because a mean mileage of 51,500 or more occurred 14 out of 200 times, the mean mileage is not statistically significant. There is not convincing evidence the new type of tire tread improves mileage of the tire.

Answers

There is convincing evidence the new type of tire tread improves mileage of the tire.

How to interpret the mean mileage?

The given parameter is:

Average = 50000 miles

New average = 51500 miles

The dot plot is added as an attachment

From the dot plot, we can see that the mean value of 51500 or more occurred 14 times out of the 200 samples

So, the conclusion is that: (a) Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.

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i need help with these 2

Answers

Answer:

Step-by-step explanation: Hey for the second one I got y = -3/4x -0.5 I'm not sure if its correct though sorry if not
ill try my best to explain my solution though
1. From the parallel equation (3x + 4y = 12) all we need to do is find the slope

So the easiest way to do so is to put the said equation in y-intercept form

y=mx +b
m= slope

b= y intercept

so 1. 3x + 4y = 12

=

4y = 12-3x

divide that by 4 to get only y

y=3-3/4x

-3/4 is our slope

y=-3/4x+b

than we have a point -2, -2

if we put -2 for y

-2=-3/4x+b

and then we put our -2 for x
-2 = -3/4 * -2 + b

=

-2  = -1.5 +b
b=-0.5

Answer : y=-3/4x-0.5

Two trains leave towns 664 miles apart at the same time and travel toward each other. One train travels 16 mih faster than the other. If they meet in 4 hours, what is the rate of each train?

Answers

Answer:

I think that I am right.  One train is traveling at 75 mph and the other train is traveling at 91 mph

Step-by-step explanation:

(Subtracting rational coefficients-Mixed numbers)

Simplify by combining like terms:

1/3k - 8 3/4k

[?] ?
_k
?

Answers

Answer:

-8 5/12

Step-by-step explanation:

A line with slope
-1/3
passes through the point (-4, 4).
Find the coordinates of another point on the line.

Answers

Answer:

(0, 8/3) = y-intercept

Step-by-step explanation:

I chose to find the y-intercept since it is easy to find with the given information.

The equation for a line is y = mx + b

To find the y-intercept, we must plug in the info we have and solve for b:

4 = -1/3 (-4) + b

4 = -4/3 + b

8/3 = b

To find a point on the line, you also could have added -1 to 4 and 3 to -4 since slope means rise/run or change in y/change in x:

(y - 1) / (x + 3) = (4 - 1) / (-4 + 3) = (3, -1) (flip since it's the y and x coordinate) = (-1, 3)

(3x+1)^2-2(3x+1)(3x+5)^2+(3x+5)^2 ​

Answers

Answer:

soln,

write the question

=9x^2+1-6x-2×9x^2+25+9x^2+25

=9x^2+1-6x-18x^2+25+9x^2+25

=9x^2-18x^2+9x^2+1+25+25-6x

=51-6x

if(3x+1)^2 mean that (3x+1)has power of 2 and u don't have to use the formula this is the answer

Step-by-step explanation:

it's just BODMAS method

Hey guys I need some help with #11 so if anyone could help that would be great THANK YOU!!

Answers

the answer is (0,-7) !

how you get it:

a=4 , b=0
x=-0/2x4
x=0
f(x)=4x^2-7, x=0
f(0)=-7
(0,-7)

On Wednesday, the temperature changes -3

each hour for 10 hours. If the temperature was 12

to begin with on Wednesday, what was the temperature after the 10 hours.

Answers

Answer:

-24 would be the temperature

Answer:

-24 BECAUSE I did all the math.

a population of bobcats increase by 5% per year if the population is currently 40 in how many years will the population reach 80 round your answer to the nearest tenth. The population will reach 80 in about _____years​

Answers

[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & 80\\ P=\textit{initial amount}\dotfill &40\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years \end{cases} \\\\\\ 80=40(1 + 0.05)^{t}\implies \cfrac{80}{40}=1.05^t\implies 2=1.05^t\implies \log(2)=\log(1.05^t) \\\\\\ \log(2)=t\log(1.05)\implies \cfrac{\log(2)}{\log(1.05)}=t\implies 14.2\approx t[/tex]

There are three novels on Sam's reading table: Light, Zami, and Money.
. On his next trip, he can choose to take some, none, or all of these novels. In the braces below, list all the possible sets of novels that Sam can take.
Write each set in your list in roster form. If there is more than one set in your list, separate them with commas. If you need the empty set in your list, use the symbol Ø.

Answers

The subsets of the set of novels is given as follows:

{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.

How to find the subsets of a set?

Suppose we have a set with cardinality n, that is, with n elements. This set will have 2^n subsets, which are all the possible combinations with the elements of the set, including the empty set.

In this problem, the novels are given as follows:

Light, Zami, and Money.

Hence the possible subsets are given as follows:

{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.

With is the list that is asked for this problem, which are the subsets of the set of novels.

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Based on the family the graph below belongs to, which equation could represent the graph?

Answers

Considering the asymptotes of the function, the equation that represents the graph is:

[tex]y = \frac{1}{x + 2} + 3[/tex]

What are the asymptotes of a function f(x)?

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

This function, from the graph, has a vertical asymptote at x = -2, hence the denominator is given by:[tex]y = \frac{1}{x + 2} + 3[/tex]

x + 2, as x + 2 = 0 -> x = -2.

The horizontal asymptote is of y = 3, hence:

[tex]\lim_{x \rightarrow \infty} f(x) = 3[/tex]

Which means that the function is described by the following rule:

[tex]y = \frac{1}{x + 2} + 3[/tex]

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Ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table given below. General Knowledge Math Science Acel Barek Carlin Acton Bay Acton Anael Max Anael Max Kai Kai Carl Anael Dario Dario Carlin Barek Let G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. Find G n M and G u S .

Answers

The computation shows that:

G n M = Anael and Max

G u S = Acel, Action, Anael, Max, Carl, Dario, Catlin, Kai, and Barek.

How to illustrate the information?

From the information, ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table.

The subjects include general Knowledge Math Science.

Therefore, G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. The intersection is illustrated above.

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