The sets of compounds that would form buffers in aqueous solution are HF and NaF, as well as HCOOH and HCOONa Option 3 & 4.
To form a buffer in aqueous solution, we need a combination of a weak acid and its conjugate base or a weak base and its conjugate acid. Based on this criteria, the set of compounds that would form a buffer in aqueous solution is HF and NaF, as well as HCOOH and HCOONa.
HF (hydrofluoric acid) is a weak acid, and NaF (sodium fluoride) is its conjugate base.
When HF and NaF are mixed in aqueous solution, they can act as a buffer because the HF can donate a proton (H+) to maintain the solution's acidity, while the F- ion from NaF can accept a proton to maintain the solution's basicity. This combination allows for the buffering of changes in pH.
Similarly, HCOOH (formic acid) is a weak acid, and HCOONa (sodium formate) is its conjugate base. When HCOOH and HCOONa are mixed in aqueous solution, they can also act as a buffer. HCOOH can donate a proton to maintain acidity, and the HCOO- ion from HCOONa can accept a proton to maintain basicity, thereby resisting changes in pH.
The other compounds mentioned (NaF and KF, HBr and NaBr, HF and KC Option 3 & 4 are correct.
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Product 1 would require a metal sheet of 0.250 m2, a glass sheet of 0.120 m2 and 3 units of electrical components. Product 2 would require a metal sheet of 0.150 m2, a glass sheet of 0.050 m2 and 2 units of electrical components. The weekly available resources are 90 m2 of metal sheets, 30 m2 of glass sheets and 800 units of electrical parts. Each unit of Product 1 would bring a unit profit of BD 2.200 and each unit of Product 2 would bring a profit of BD 1.400.
Based on the available resources and profit per unit, producing 266 units of Product 1 would result in the highest total profit of BD 585.20.
To determine the maximum number of units of each product that can be produced given the available resources, we need to compare the resource requirements of the products with the available resources.
Let's calculate the resource requirements for each product:
Product 1:
- Metal sheet: 0.250 m2 per unit
- Glass sheet: 0.120 m2 per unit
- Electrical components: 3 units per unit
Product 2:
- Metal sheet: 0.150 m2 per unit
- Glass sheet: 0.050 m2 per unit
- Electrical components: 2 units per unit
Now let's compare the resource requirements with the available resources:
Metal sheets:
- Product 1 requires 0.250 m2 per unit, so the maximum number of units that can be produced using available metal sheets is 90 m2 / 0.250 m2 = 360 units.
- Product 2 requires 0.150 m2 per unit, so the maximum number of units that can be produced using available metal sheets is 90 m2 / 0.150 m2 = 600 units.
Glass sheets:
- Product 1 requires 0.120 m2 per unit, so the maximum number of units that can be produced using available glass sheets is 30 m2 / 0.120 m2 = 250 units.
- Product 2 requires 0.050 m2 per unit, so the maximum number of units that can be produced using available glass sheets is 30 m2 / 0.050 m2 = 600 units.
Electrical components:
- Product 1 requires 3 units per unit, so the maximum number of units that can be produced using available electrical components is 800 units / 3 units = 266 units.
- Product 2 requires 2 units per unit, so the maximum number of units that can be produced using available electrical components is 800 units / 2 units = 400 units.
Now let's determine the maximum number of units that can be produced for each product based on the limiting resource:
Metal sheets: The maximum number of units that can be produced is 360 units (for Product 1) since it requires a larger area of metal sheets.
Glass sheets: The maximum number of units that can be produced is 250 units (for Product 1) since it requires a larger area of glass sheets.
Electrical components: The maximum number of units that can be produced is 266 units (for Product 1) since it requires a larger number of electrical components.
Since the limiting resource for all three resources is reached with Product 1, the maximum number of units that can be produced for Product 1 is 266 units. As for Product 2, it can be produced up to a maximum of 250 units.
Now let's calculate the profit for each product:
Profit per unit for Product 1: BD 2.200
Profit per unit for Product 2: BD 1.400
Total profit for Product 1: 266 units × BD 2.200 = BD 585.20
Total profit for Product 2: 250 units × BD 1.400 = BD 350.00
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value of standard atmospheric pressure
Answer:
value of standard atmospheric pressure is atmosphere
How does an ionic bond differ from a covalent bond?
Answer:
Ionic bonds transfer electrons and covalent bonds share electrons.
Explanation:
Ionic bonds tend to transfer electrons completely. Take NaCl for example.
Cl has 7 valence electrons.
Na has 1 valence electron.
To stabilize themselves, either with a full 8 shells or full outer shell, Cl wants 1 electron and Na wants to lose 1 electron. So when NaCl forms, Na donates its electron to Cl.
In a covalent bond, the electrons are shared. Water can be used as an example. The electrons in water usually are around the oxygen, but sometimes it is around the hydrogens.
HELP QUICK!! Match the term with the definition. (4 points)
1. Solid
2. Liquid
3. Gas
4. Plasma
a. assumes the shape of the part of the container from the bottom up
b. charged particles that do not have a definite shape or volume
c. has a fixed volume and shape
d. takes the shape and volume of an entire container
Answer:
1. c.
2. d.
3. b.
4. a.
Explanation:
2. d
1. c
3. a
4. b
I am not sure since I don't know what plasma is
A 0.520 g sample of an unknown nonelectrolyte compound is dissolved in 4.62 g of lauric acid (Kf = 3.90 .C/m).
The freezing point depression is determine to be 4.20 C. What is the molar mass of the compound?
Using the given mass of the compound (0.520 g) and the calculated moles, we can determine the molar mass of the compound.
To find the molar mass of the compound, we can use the formula:
ΔT = Kf * m
where ΔT is the freezing point depression, Kf is the cryoscopic constant (in this case, 3.90 °C/m), and m is the molality of the solution.
First, we need to calculate the molality (m) of the solution:
m = moles of solute / mass of solvent (in kg)
The mass of the solvent (lauric acid) is given as 4.62 g. Since the unknown compound is a solute, we need to convert its mass to moles:
moles = mass / molar mass
Given that the mass of the unknown compound is 0.520 g, we can now calculate the moles of the compound.
Next, we convert the mass of the solvent to kg by dividing by 1000:
mass of solvent (lauric acid) = 4.62 g / 1000 = 0.00462 kg
Now we can calculate the molality:
m = moles of solute / mass of solvent = (moles of the compound) / (mass of solvent)
Finally, we can use the freezing point depression formula to find the molar mass of the compound:
ΔT = Kf * m
Substituting the given values:
4.20 °C = 3.90 °C/m * m
Now solve for m:
m = (4.20 °C) / (3.90 °C/m)
Once we have the molality, we can calculate the moles of the compound:
moles = molality * mass of solvent (in kg)
Finally, we calculate the molar mass:
molar mass = mass of solute / moles of solute
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if 8.2 ml of 0.055 m naoh is required to titrate a 5.5 ml sample of potassium bitartrate, what is the concentration of hc4h4o6-
The concentration of HC4H4O6- in the given solution is 0.1 M The given reaction is as follows:HC4H4O6- + NaOH → NaKC4H4O6 + H2OIn the given are , the volume of Na OH used in the titration is 8.2 mL and the concentration is 0.055 M.
The volume of HC4H4O6- taken for titration is 5.5 mL.To find the concentration of HC4H4O6-, we need to find the number of moles of NaOH used in the reaction. Moles of NaOH = Molarity x Volume = 0.055 x 8.2/1000 = 0.000451 molFrom the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of HC4H4O6-.Thus, the number of moles of HC4H4O6- present in 5.5 mL = 0.000451 mol
The volume of the solution taken is 5.5 mL = 5.5/1000 = 0.0055 LThe concentration of HC4H4O6- is given by:C = (n/V) = 0.000451/0.0055 = 0.0818 M = 0.1 M find the concentration of HC4H4O6-, we first need to find the number of moles of NaOH used in the reaction. We can do this by multiplying the volume of NaOH used (in liters) with its molarity.The balanced equation tells us that 1 mole of NaOH reacts with 1 mole of HC4H4O6-. Therefore, the number of moles of HC4H4O6- present in the solution is equal to the number of moles of NaOH used in the reaction.We can then use the formula to find the concentration of HC4H4O6-, which is given by the number of moles divided by the volume of the solution taken. In this case, we are given the volume of the solution taken to be 5.5 mL, which we convert to liters before using it in the formula.
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Enter the net ionic equation for the reaction that occurs when aqueous hydrobromic acid and aqueous barium sulfide are mixed.
Answer:
Explanation:
Refer the image
which of the following statements about catalysts are true? select all.group of answer choicescatalysts lower the overall activation energy of a reaction.a catalyst does not particpate in a chemical reaction.catalysts are formed early in a reaction and consumed later in the reaction.catalysts change the delta h of a reaction.catalysts are present before and after a chemical reaction.a catalyst can convert an exothermic reaction into an endothermic reaction.catalysts make reactions go faster in both directions.
Catalysts are known to lower the overall activation energy of a reaction and does not participate in the chemical reaction. They are not used up during the reaction, and as such, can be used in successive reactions. Catalysts are present before and after a chemical reaction, and they can change the rate at which a reaction takes place.
Furthermore, catalysts can convert an exothermic reaction into an endothermic reaction, making the reaction go faster in both directions. Catalysts can be defined as substances that can alter the rate of a chemical reaction. They can do this by lowering the overall activation energy of a reaction, making it easier for a reaction to occur. However, catalysts do not participate in the chemical reaction; instead, they only help to speed it up by providing an alternative reaction pathway.The energy required to break the bond in a chemical reaction is known as the activation energy. Catalysts reduce the activation energy, thereby allowing the reaction to take place more quickly. Once the reaction has taken place, the catalyst remains unchanged, and it can be used in successive reactions. Catalysts are present before and after a chemical reaction, and they can change the rate at which a reaction takes place.Catalysts can also convert an exothermic reaction into an endothermic reaction, making the reaction go faster in both directions. For example, enzymes are biological catalysts that convert an exothermic reaction into an endothermic reaction.
In conclusion, catalysts are substances that can alter the rate of a chemical reaction by lowering the activation energy. Catalysts are present before and after a chemical reaction and can convert an exothermic reaction into an endothermic reaction, making the reaction go faster in both directions. Catalysts do not participate in the chemical reaction and are not used up during the reaction, allowing them to be used in successive reactions.
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Express the following in
scientific notation.
0.0094x10^2
9.4x10^?
what is the missing exponent?
Answer:
-1
Explanation:
since 0.0094×10^2 = 100*0.0094 = 0.94 = 9.4*10^-1.
10^-1 = 0.1
0.1 * 9.4 = 0.94
[tex]9.4\times10^?[/tex] can be expressed as [tex]9.4 \times 10^{-1[/tex] in scientific notation. Therefore the missing exponent is -1.
To express [tex]0.0094\times10^2[/tex] in scientific notation, we move the decimal point two places to the right, resulting in 9.4. The exponent remains the same, so the scientific notation is [tex]9.4\times10^2[/tex].
To determine the missing exponent for [tex]9.4\times10^?[/tex] we count the number of decimal places needed to shift the decimal point to the right of the first nonzero digit, which in this case is 9.4. In this case, we need to move the decimal point one place to the left to obtain 9.4. Therefore, the missing exponent is -1.
So, [tex]9.4\times10^?[/tex] can be expressed as [tex]9.4\times10^{-1[/tex] in scientific notation.
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A stock solution of potassium permanganate (KMnO4) was prepared by dissolving 13.0g KMnO4 with DI H2O in a 100.00-mL volumetric flask and diluting to the calibration mark. Determine the molarity of the solution
Molarity of KMnO4 solution = Number of moles of KMnO4 / Volume of solution = (13.0 g / 158.03 g/mol) / 0.1000 L
The molarity of a potassium permanganate (KMnO4) solution can be calculated by dividing the number of moles of KMnO4 by the volume of the solution in liters. To find the number of moles, we divide the mass of KMnO4 by its molar mass. In this case, the mass of KMnO4 is given as 13.0 g, and the molar mass of KMnO4 is approximately 158.03 g/mol. The volume of the solution is 100.00 mL, which needs to be converted to liters by dividing by 1000. By substituting these values into the formula, we can determine the molarity of the potassium permanganate solution.
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, the solute is potassium permanganate (KMnO4), and the volume of the solution is 100.00 mL.
To calculate the molarity, we need to find the number of moles of KMnO4. This can be done by dividing the mass of KMnO4 by its molar mass. The molar mass of KMnO4 is approximately 158.03 g/mol.
Number of moles of KMnO4 = Mass of KMnO4 / Molar mass of KMnO4
= 13.0 g / 158.03 g/mol
Next, we need to convert the volume of the solution from milliliters to liters. This can be done by dividing the volume by 1000.
Volume of solution = 100.00 mL / 1000
= 0.1000 L
Now we can calculate the molarity of the solution by dividing the number of moles of KMnO4 by the volume of the solution in liters.
Molarity of KMnO4 solution = Number of moles of KMnO4 / Volume of solution
= (13.0 g / 158.03 g/mol) / 0.1000 L
By evaluating this expression, we can determine the molarity of the potassium permanganate solution.
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At what temperature
does water boil
Answer:
I feel like it will boil at 100 and up
Explanation:
What is the answer? True or false? Please answer, thank you!
what is the [h3o ] of a 0.791 m solution of calcium hydroxide?
The concentration of H3O+ ions in a 0.791 m solution of calcium hydroxide is extremely low or close to zero due to the limited solubility and limited dissociation of calcium hydroxide in water.
To determine the concentration of H3O+ ions in a solution of calcium hydroxide (Ca(OH)2), we need to consider the dissociation of water and the subsequent reaction with the hydroxide ions.
Calcium hydroxide is a strong base that dissociates in water to form calcium ions (Ca2+) and hydroxide ions (OH-):
Ca(OH)2(s) → Ca2+(aq) + 2OH-(aq)
Water (H2O) also undergoes autoionization, producing hydronium ions (H3O+) and hydroxide ions:
2H2O(l) ⇌ H3O+(aq) + OH-(aq)
In this case, the concentration of OH- ions is determined by the solubility of calcium hydroxide in water. However, calcium hydroxide is only sparingly soluble in water, so it undergoes limited dissociation.
Given that we have a 0.791 m solution of calcium hydroxide, we can assume that the concentration of OH- ions will be relatively low compared to the initial concentration of Ca(OH)2.
To find the concentration of H3O+ ions, we can use the fact that in a neutral solution, the concentration of H3O+ ions is equal to the concentration of OH- ions:
[H3O+] = [OH-]
Since calcium hydroxide is a strong base, it will react with water to produce OH- ions. However, the extent of dissociation is relatively low. Therefore, the concentration of OH- ions is negligible compared to the concentration of Ca(OH)2, and consequently, the concentration of H3O+ ions will also be negligible.
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A 1.638 Gram pure sample of a compound containing only carbon hydrogen and oxygen was burned in excess oxygen gas 3.117 g of carbon dioxide and 1.911 g of water were produced find the empirical formula of the compound
Answer:
C2H6O
Explanation:
First, find the masses of C, H, and O. I used ratios.
3.117g CO2 x 1 mol CO2/44.01g CO2 x 1 mol C/1 mol CO2 x 12.01g C/1 mol C = 0.850606 g C
1.911g H2O x 1 mol H2O/18.016g H2O x 2 mol H2O/1 mol H2O x 1.008g H/1 mol H = 0.213842 g H
To find the mass of oxygen, just add the masses of C and H together and subtract that from the total mass of the sample.
1.638 - (0.850606 + 0.213842) = 0.57355 g O
Second, find the moles of C, H, and O.
0.850606g C x 1 mol C/12.01g C = 0.070825 mol C
0.213842g H x 1 mol H/1.008g H = 0.212145 mol H
0.57355 g O x 1 mol O/16g O = 0.035847 mol O
Finally, divide the number of moles of each element by the smallest value of moles calculated. In this case, the smallest value is 0.035847.
0.070825/0.035847 = 2
0.212145/0.035847 = 6
0.035847/0.035847 = 1
The empirical formula represents the chemical with the ratio of the simplest whole numbers. The empirical formula of the 1.638-gram compound is C₂H₆O.
What is the empirical formula?The representation of the chemical compound with the chemical symbols and the coefficients as the whole number are called empirical formulas.
The molecular formula for the sample is, CxHyOz
Given,
Mass of carbon dioxide = 3.117 gm
Mass of water = 1.911 gm
Mass of pure sample = 1.638 gram
The moles of carbon (x) are calculated as,
Moles = mass ÷ molar mass
= 3.117 ÷ 44.01
= 0.0708248
Moles of hydrogen (y) are calculated as,
Moles = 1.9911 ÷ 18.015
= 0.106078 moles
In water there are 2 hydrogen atoms so, 0.212156 moles
Mass of CxHyOz is used to calculate moles of oxygen as,
0.0708248 × 12.0107 + 0.212156 × 1.00784 + z × 15.999 = 1.638
1.0644747 + 15.999 z = 1.638
15.999 z = 0.5735253
z = 0.0358475
So, x = 0.0708248, y = 0.212156 and z = 0.0358475
These values are divided by the least number of moles to give the ratio as,
0.070825 ÷ 0.035847 = 2
0.212145 ÷ 0.035847 = 6
0.035847 ÷ 0.035847 = 1
Therefore, the empirical formula for the compound is C₂H₆O.
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A nuclear particle that has about the same mass as a proton, but with no electrical charge, is called a(n)
a. nuclide. c. electron.
b. neutron. d. isotope.
Answer:
neutron?
Explanation:
a fluoride ion (F1-) has the same number of electrons as which of the following?
Answer : The correct option is, (d) [tex]Mg^{+2}[/tex]
Explanation :
First we have to determine the number of electrons present in [tex]F^{-1}[/tex] ion.
Atomic number of fluorine (F) = 9
As we know that,
Atomic number = Number of electrons (for neutral atom)
Number of electrons in [tex]F^{-1}[/tex] ion = 9 + 1 = 10
Now we have to determine the number of electrons present in given option ions.
For [tex]B^{-3}[/tex] ion:
Atomic number of boron (B) = 5
Number of electrons in [tex]B^{-3}[/tex] ion = 5 + 3 = 8
For [tex]N^{+1}[/tex] ion:
Atomic number of nitrogen (N) = 7
Number of electrons in [tex]N^{+1}[/tex] ion = 7 - 1 = 6
For [tex]Na^{-1}[/tex] ion:
Atomic number of sodium (Na) = 11
Number of electrons in [tex]Na^{-1}[/tex] ion = 11 + 1 = 12
For [tex]Mg^{+2}[/tex] ion:
Atomic number of magnesium (Mg) = 12
Number of electrons in [tex]Mg^{+2}[/tex] ion = 12 - 2 = 10
For [tex]Ne^{-1}[/tex] ion:
Atomic number of neon (Ne) = 10
Number of electrons in [tex]Ne^{-1}[/tex] ion = 10 + 1 = 11
From this we conclude that magnesium ion, [tex]Mg^{+2}[/tex] has the same number of electrons as a fluoride ion, [tex]F^{-1}[/tex].
Hence, the correct option is, (d) [tex]Mg^{+2}[/tex]
The radius of an atom is dependent upon which 2 things? (Two answers)
A.) the number of electrons that it contains
B.) the number of neutrons that it contains
C.) the magnitude of attraction from its nucleus
D.) the distance between the electrons and its nucleus
Answer:
The correct options are;
C. The magnitude of attraction from its nucleus
D. The distance between the electrons and its nucleus
Explanation:
The atomic radius reduces, within a given period, as we move from left to right, the number of protons increases alongside the number of electrons and the while the quantum shell to which the extra electrons are added to is the same. Therefore, the radius of the atom is dependent on the magnitude of the attraction from the nucleus
Similarly, as we progress to the next period, with an extra quantum shell, the atomic radius is seen to increase.
Therefore, the atomic radius is determined by the distance between the electrons and its nucleus.
Water is one of the end products of acrobic respiration. What is the source of the oxygen atom used in formation of the water? the molecular oxygen (O2) you breathe the glucose (C6H1206) you eat carbon dioxide (CO2) pyruvate (C3H3O3-)
The source of the oxygen atom used in the formation of water during aerobic respiration is the molecular oxygen (O2) that you breathe.
During aerobic respiration, glucose (C6H12O6) is oxidized in the presence of oxygen to produce energy, carbon dioxide (CO2), and water (H2O). The oxygen atoms used in the formation of water come from the molecular oxygen (O2) that is taken in during breathing.
In the process of aerobic respiration, glucose is broken down in multiple steps, including glycolysis, the Krebs cycle, and the electron transport chain. During the electron transport chain, oxygen acts as the final electron acceptor. It accepts electrons and protons, which combine to form water.
Therefore, the oxygen atoms used to form water in aerobic respiration come from the molecular oxygen (O2) that is breathed in during respiration.
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Diiodine pentaoxide is used in respirators to remove carbon monoxide from air:
I2O5(s) + 5CO(g) -----> I2(s) + 5CO2(g)
(a) What mass of carbon monoxide could be removed from air
by a respirator that contains 50.0 g of diiodine pentaoxide?
(b) What mass of I2 would remain in the respirator?
A respirator containing 50.0 g of diiodine pentaoxide can remove approximately 20.95 g of carbon monoxide from the air, leaving approximately 190.08 g of diiodine ([tex]I_2[/tex]) remaining.
We use stoichiometry and the given balanced equation:
[tex]I_2O_5(s) + 5CO(g)[/tex]→[tex]I_2(s) + 5CO_2(g)[/tex]
(a) The mass of carbon monoxide (CO) that can be removed, we need to determine the stoichiometric ratio between diiodine pentaoxide[tex](I_2O_5)[/tex] and CO. From the balanced equation, we can see that 1 mole of [tex](I_2O_5)[/tex] reacts with 5 moles of CO.
We calculate the number of moles of [tex](I_2O_5)[/tex]:
Number of moles = mass / molar mass
Molar mass of [tex](I_2O_5)[/tex] = 2(I) + 5(O) = 2(126.9 g/mol) + 5(16.0 g/mol) = 333.8 g/mol
Number of moles of [tex](I_2O_5)[/tex] = 50.0 g / 333.8 g/mol ≈ 0.15 mol
Since the stoichiometric ratio is 1:5 between [tex](I_2O_5)[/tex] and CO, the number of moles of CO that can be removed is:
Number of moles of CO = 0.15 mol × 5 = 0.75 mol
The mass of CO, we multiply the number of moles by its molar mass:
Mass of CO = number of moles × molar mass
Molar mass of CO = 12.0 g/mol + 16.0 g/mol = 28.0 g/mol
Mass of CO = 0.75 mol × 28.0 g/mol ≈ 21.0 g
Therefore, approximately 21.0 grams of carbon monoxide could be removed from the air by a respirator containing 50.0 grams of diiodine pentaoxide.
(b) To find the mass of [tex]I_2[/tex] remaining in the respirator, we use the stoichiometric ratio of 1 mole of [tex](I_2O_5)[/tex] to 1 mole of[tex]I_2[/tex]
Number of moles of [tex]I_2[/tex] remaining = 0.15 mol
To calculate the mass of [tex]I_2[/tex], we multiply the number of moles by its molar mass:
Mass of [tex]I_2[/tex] = number of moles × molar mass
Molar mass of [tex]I_2[/tex] = 2(I) = 2(126.9 g/mol) = 253.8 g/mol
Mass of [tex]I_2[/tex] = 0.15 mol × 253.8 g/mol ≈ 38.1 g
Therefore, approximately 38.1 grams of [tex]I_2[/tex] would remain in the respirator.
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Which phrase best describes a scientists?
Answer:
They are helpers of the world who find out about the natural world and try to explain what they have observed.
Explanation:
The
energy of wind helps a windmill to
generate power.
Help me pls.
The wind blows onto the windmill, the blades of the windmill move so the wind's kinetic energy rotates it and turns it into mechanical energy.
what atoms are present In the molecule KNO3 and how many are there of each ?
Answer:
one potassium, one nitrogen and three oxygen
Explanation:
potassium is K, nitrogen is N and oxygen is O
is iron nails strongly heated a physical/chemical change
Answer: A chemical change, because the result is rust, and rust completely differs from iron.
what is a key characteristic of a molecular solid? what is a key characteristic of a molecular solid? it consists of atoms held together by extended arrays of covalent bonds. it consists of neutral, covalently bound molecules held together by intermolecular attractive forces. it exhibits a face-centered cubic lattice structure. it exhibits a diamond structure. it consists of a host element and dopant.
Answer: A molecular solid is a type of solid in which molecules are held together by van der Waals forces rather than by ionic or covalent bonds.
Explanation:
The dipole forces are weaker than ionic or covalent bonds. The relatively weak intermolecular forces cause molecular solids to have relatively low melting points, typically less than 300 degrees Celsius.
Molecular solids tend to dissolve in organic solvents. Most molecular solids are relatively soft electrical insulators with low density.
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How much force would it take to throw a 0.5 kg basketball at an acceleration of 20 m/s??
Answer:
The answer is 10 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
Force = mass × accelerationFrom the question
mass = 0.5 kg
acceleration = 20 m/s²
We have
Force = 0.5 × 20
We have the final answer as
10 NHope this helps you
Answer:
[tex]\boxed {\tt 10 \ Newtons}[/tex]
Explanation:
Force can be found by multiplying the mass by the acceleration.
[tex]F=m*a[/tex]
The mass of the basketball is 0.5 kilograms.
The acceleration is 20 meters per second squared.
[tex]m= 0.5 \ kg \\a= 20 \ m/s^2[/tex]
Substitute the values into the formula.
[tex]F= 0.5 \ kg * 20 \ m/s^2[/tex]
Multiply.
[tex]F= 10 \ kg*m/s^2[/tex]
A kilogram meter per second squared is equal to a Newton.
Therefore, 10 kilogram meters per second squared is equal to 10 Newtons.
[tex]F= 10 \ N[/tex]
10 Newtons of force would be required.
After the plastic strip is run through the fingers, would the fingers have a positive charge, negative charge, or no charge?
please answer for brain list before 12
:40
Answer:
You become negatively charged
When forming positive ions transition metals comply gain electrons??
Answer:
elements on the left-hand side of the periodic table such as sodium and magnesium prefer to lose electrons to form a cation because this requires less energy to obtain a stable octet, and vice-versa for the right-hand side of the periodic table e.g. fluorine. However, using this reasoning I am not sure why all transition metals tend to lose electrons rather than gain them.
A 3.458 g sample of KHP, a monoprotic acid, requires 45.71 mL of a KOH solution to reach the endpoint. What is the concentration of the KOH solution? The molar mass of KHP is 204.22 g/mol. x 10! M KOH Enter your answer in scientific notation.
The concentration of the KOH solution is 0.100 M. To calculate the concentration of the KOH solution, we can use the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Given:
Mass of KHP (potassium hydrogen phthalate) = 3.458 g
Molar mass of KHP = 204.22 g/mol
Volume of KOH solution = 45.71 mL = 0.04571 L
First, we need to calculate the moles of KHP:
moles of KHP = (mass of KHP) / (molar mass of KHP)
moles of KHP = 3.458 g / 204.22 g/mol ≈ 0.01693 mol
Next, we can calculate the concentration of the KOH solution:
Molarity of KOH solution = (moles of KOH) / (volume of solution)
Molarity of KOH solution = 0.01693 mol / 0.04571 L ≈ 0.370 M
Converting the concentration to scientific notation, we have:
Molarity of KOH solution ≈ 3.70 x 10^-1 M
Therefore, the concentration of the KOH solution is approximately 0.100 M.
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quick!!
Which best describes the purpose of bar graphs?
O They show changes over a period of time.
O They compare quantities for particular categories.
O They show the relationship among parts of a whole
O They compare ranges as continuous data.
Answer:
A I think....
Explanation:
The pH of a water is measured to be 7.5. The concentration of bicarbonate was measured to be 1.3E^-3 M. Assume system closed to atmosphere. Find: What are the concentrations of carbonate, carbonic acid, and C_T (Total inorganic C)?
The concentrations of carbonate, carbonic acid, and C_T (Total inorganic C) can be approximated as follows: [CO3^2-] ≈ 0 M, [H2CO3] ≈ 0 M, [C_T] = [HCO3-] + [CO3^2-] + [H2CO3] ≈ [HCO3-] ≈ 1.3 x 10^(-3) M.
To find the concentrations of carbonate, carbonic acid, and C_T (Total inorganic C), we need to consider the equilibrium reactions involving bicarbonate (HCO3-) and carbonate (CO3^2-) ions.
In a system closed to the atmosphere, bicarbonate ions (HCO3-) can undergo the following reactions to form carbonate ions (CO3^2-) and carbonic acid (H2CO3):
Dissociation of bicarbonate:
HCO3- + H2O ⇌ H2CO3 + OH-
Dissociation of carbonic acid:
H2CO3 ⇌ H+ + HCO3-
Formation of carbonate:
HCO3- ⇌ CO3^2- + H+
Given that the pH of water is measured to be 7.5, which indicates a slightly basic solution, we can assume that the concentration of hydroxide ions (OH-) is negligible compared to the concentration of H+ ions. Therefore, the first reaction can be ignored.
Since the pH is 7.5, the concentration of H+ ions can be calculated using the formula:
[H+] = 10^(-pH)
[H+] = 10^(-7.5) = 3.162 x 10^(-8) M
Using the equilibrium constant expression for the second reaction, we can relate the concentrations of H2CO3, H+, and HCO3-:
Ka = [H+][HCO3-] / [H2CO3]
Assuming the concentration of H2CO3 is initially zero, we can approximate it by assuming that most of the H2CO3 dissociates to form H+ and HCO3-. Therefore, we can write:
Ka = [H+][HCO3-] / [H2CO3] ≈ [H+][HCO3-] / 0
Simplifying the equation, we have:
[HCO3-] ≈ [H+]
Thus, the concentration of bicarbonate ions is approximately equal to the concentration of H+ ions:
[HCO3-] ≈ 3.162 x 10^(-8) M
Since the concentration of bicarbonate ions is given as 1.3 x 10^(-3) M, we can conclude that the concentration of carbonate ions is negligible in this system, as the majority of the bicarbonate ions exist in the HCO3- form.
Therefore, the concentrations of carbonate, carbonic acid, and C_T (Total inorganic C) can be approximated as follows:
[CO3^2-] ≈ 0 M
[H2CO3] ≈ 0 M
[C_T] = [HCO3-] + [CO3^2-] + [H2CO3] ≈ [HCO3-] ≈ 1.3 x 10^(-3) M
In summary, in a system closed to the atmosphere with a measured pH of 7.5 and a bicarbonate concentration of 1.3 x 10^(-3) M, the concentrations of carbonate and carbonic acid are considered negligible, and the concentration of C_T (Total inorganic C) is approximately equal to the concentration of bicarbonate ions.
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