Which state of matter is being described below? it cannot be squashed easily, spreads out slowly, is of medium density

From the addition of 1 equivalent of HBr to 1,3-butadiene, 3-bromo-1-butene is obtained as a product.

What is moles?

Moles are defined as the smallest base unit that is equivalent to [tex]6.02214 X 10^{23}[/tex] units.

Moles are chemical entities, which are used to measure the mass or molecular mass of the compound, molecule, or atom. The moles are, for example can be explained as equal to the mass of the atom. For example, there is one mole in 12 grams of carboncarbon.

Thus the kinetic product formed is 3-bromo-1-butene.

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Using the gas laws, the volume of nitrogen produced is 6.6 L.

We know that the product of a reaction is obtained from the balanced reaction equation. The reactants combine together to yield the products hence we have; N2 + 3H2 ----> 2NH3

We know that 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies 25500 L

x = 1 mole * 25500 L/ 22.4 L

x = 1138.4 moles

If 3 mole of hydrogen reacts with 1 mole of nitrogen

1138.4 moles  reacts with 1138.4 moles * 1 mole/ 3 moles = 379.5 moles

Mass of nitrogen = 379.5 moles * 28 g/mol = 10626 g

Now 3 moles of hydrogen produces 44.8 L of NH3

1138.4 moles  produces 1138.4 moles * 44.8 L/ 3 moles = 17000 L

Now;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1 * 17000 * 848/5.5 * 273

V2 =9601 L

2) 2NH4NNO3(s) ---> 4H2O(g) + 2N2(g) + O2(g)

Number of moles = 12g/ 80 g/mol = 0.15 moles

Now;

2 moles of NH4NNO3 produced 2 moles of nitrogen hence 0.15 moles of N2 was produced.

1 mole of N2 occupies 22.4 L

0.15 moles of N2 occupies 0.15 moles  *  22.4 L/1 mole = 3.36 L

P1 = 760 torr

V1 = 3.36 L

T1 = 273 K

P2 = 745 torr

T2 = 527 degrees or 800 K

V2 = ?

V2 =  P1V1T2/P2T1

V2 =  760 *  3.36 * 527/745 * 273

V2 = 6.6 L

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Ester is the major product formed in the reaction involving an acid anhydride dissolved in alcohol.

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When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M

The reaction of neutralization of HNO₃ with NaOH is

HNO₃ + NaOH → H₂O + NaNo₃

When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -

With the mole and volumes, we can find molarity as follows:

            Moles of NaOH = moles HNO₃

            ⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH

            =0.014 mol HNO₃

Molarity: -

              [tex]\frac{(Mole of HNO₃)}{(volume of HNO₃)}= \frac{0.014}{0.34}[/tex]

               = 0.041 M

Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.

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Answer:

Section 2 will decrease.

Explanation:

A catalyst is a substance that increases the rate of the chemical reaction without taking part in the overall reaction. Catalysts speed up a reaction by lowering the activation energy needed for a reaction to take place. The activation energy is the minimum energy necessary for a reaction to take place. As such, when a catalyst is added, the activation energy (or the potential energy) needed to start the reaction decreases. This shows itself in the graph by decreasing the "hump" in Section 2.

It should be noted that Sections 1 and 3 will remain the same. This is because the energy of the reactants and products does not change regardless of a catalyst being present.

Mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current is 19.55 g

Given, I=8.70A, t=33.5min=33.5*60=2010 sec, m of Ag = 19600g M=107.87 g/mol

From  faradays law we can write q=I*t= 8.70*2010=17487 C.

moles of Ag =17487/ 19600=0.1812 moles

Ag deposited = 0.1812*107.87 = 19.55 g

Having the atomic number 47 and the Latin word argentum, which means "bright" or "white," silver is a chemical element. Its symbol is Ag. The highest electrical, thermal, and reflectivity of any metal are displayed by this transition metal, which is soft, white, and lustrous. The metal can be found in the Earth's crust in three different forms: as an alloy with other metals like gold and in minerals like argentite and chlorargyrite. It can also be found in its pure, free elemental form, also known as "native silver." During the refining of copper, gold, lead, and zinc, the majority of silver is created as a byproduct. As a valuable metal, silver has long been treasured.

What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 326 g 3. 07 g 0. 102 g

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Considering the definition of molar volume and density,the density of copper at 25°C is 8.96 [tex]\frac{g}{cm^{3} }[/tex].

Molar volume is an intensive property that indicates how much space one mole of a certain substance or compound occupies. In other words, the molar volume is the space occupied by one mole of a substance.

The expression to calculate the molar volume is:

Vm= V÷ n

where:

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

The relationship between molar volume and density is reflected in the following expression, where the molar volume is calculated by dividing the molar mass (M) by the mass density (ρ):

Vm= M÷ρ

In this case, you know:

Replacing in the relationship between molar volume and density:

7.09 [tex]\frac{cm^{3} }{mol}[/tex]= 63.5 [tex]\frac{g}{mol}[/tex]÷ρ

Solving:

7.09 [tex]\frac{cm^{3} }{mol}[/tex]×ρ= 63.5 [tex]\frac{g}{mol}[/tex]

ρ= 63.5 [tex]\frac{g}{mol}[/tex]÷7.09 [tex]\frac{cm^{3} }{mol}[/tex]

ρ= 8.96 [tex]\frac{g}{cm^{3} }[/tex]

Finally, the density of copper at 25°C is 8.96 [tex]\frac{g}{cm^{3} }[/tex].

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It will occupy 18 L volume when the pressure is changed to 0. 5 atm and the temperature remain constant.

Calculation,

According to Boyle law, the pressure of a given quantity of gas varies inversely with its volume at constant temperature.

[tex]P_{1} V _{1} = k[/tex]    .....(i)

[tex]P_{2} V _{2} = k[/tex]    (ii)

Combining equation (i) and (ii). we get,

[tex]P_{1} V _{1} = P_{2} V _{2}[/tex]

3 atm× 3L=  [tex]V _{2}[/tex]× 0.5atm

[tex]V _{2}[/tex]  =   3 atm× 3L/0.5atm = 18 L

Boyle law used during respiration or breathing.

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The name for aqueous [tex]H_{2} CO_{3}[/tex] is carbonic acid.

So, option C is correct one.

Binary hydrogen compounds with non metals may form H+ (proton) and an anion dissolved in water. The acidic solutions are named as if they were molecular acids , using the usual name for the compound itself , replacing hydrogen with hydro- and suffix -ide with ic. The word acid is then use.

The inorganic acid is an acid drive from one or more inorganic compounds. All inorganic acids form hydrogen ions and the conjugate base ions when dissolved in water.

Example: carbonic acid ( [tex]H_{2} CO_{3}[/tex] )

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There are 2  peaks are in the proton spin decoupled 13C NMR spectrum of 1,3,5-trinitrobenzene .

The 13C NMR spectrum give the peak which is directly about the carbon skeleton not just the proton attached to it  . The number of signals tell us how many different carbons or set of equivalent carbons . The splitting of a signal tells us how many hydrogens  are attached to each carbon.

In 1,3,5-trinitrobenzene molecule , there are 2  peaks are in the proton spin decoupled 13C NMR spectrum three carbon give one signal and another three carbon give another one signal .

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The piece of plastic has   1.256× 10¹³  protons  more than  that of electrons.

A proton is a subatomic particle with a defined mass of 1 and a charge of +1 (positive charge). The symbol for the proton is either p or p+.

An electron is a subatomic particle that has a negative electric charge and that actively orbits the nucleus of the atom .

To calculate ,

given ,

magnitude of charge , q=+2μC=+2×10⁻⁶

Since, protons carry positive charge. Then, we know that standard number of proton in 1 Coulomb of charge is,

1C=6.28×10¹⁸ protons

Number of protons in 1 microcoulomb charge is,

=6.28×10¹⁸×10⁻⁶

=6.28×10¹²

Then for the net charge of q, the number of protons is given as,

np= q×6.28×10¹²

np= 2×6.28×10¹²

np=1.256×10¹³ protons

Thus, the piece of plastic has 1.256×10¹³   more protons than electrons.

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Percent ionization = 3.17%

We utilize the supplied acid equilibrium constant (Ka) to calculate the percentage of the acid that is ionized. It is the ratio of the acid and dissociated ion equilibrium concentrations. The HF acid would dissociate in the manner described below:

HF = H+ + F-

The following is how the acid equilibrium constant might be written:

Ka = [H+][F-] / [HF] = 3.5 x 10-4

We utilize the ICE table to determine the equilibrium concentrations.

        HF             H+              F-

I      0.337           0                 0

C      -x              +x               +x

---------------------------------------------

E    0.337-x        x                   x

3.5 x 10-4 = [H+][F-] / [HF]

3.5 x 10-4 = [x][x] / [0.337-x]

Solving for x,

x = 0.01069 = [H+] = [F-]

percent ionization = 0.01069 / 0.337 x 100  = 3.17%

percent ionization = 3.17%

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The potential of the hydrogen in water gives the pH of the acidity and basicity of the solution. The pH of the solution is 9.06. Thus, option iii is correct.

The pH of a substance is given by the subtraction of the pOH from 14 which is the range of the pH scale.

The dissociation reaction for ammonia is given as,

NH₃ (aq) + H₂O (l)  ⇄  NH₄⁺ (aq) + OH⁻ (aq)

Here, the concentration of ammonia is [NH₃] - x, ammonium ion is [NH₄⁺] + x, and hydroxide ion is x.

The molar concentration of ammonia is,

M = (0.12 M × 0.2 L) ÷ 0.45 L = 0.053 M

The molar concentration of ammonium ion is,

M = (0.15 M × 0.25 L) ÷ 0.45 L = 0.083 M

From the base dissociation constant and previous concentration from the reaction, the value of x or hydroxide ion is calculated as,

Kb = [NH₄⁺][OH⁻] ÷ [NH₃]

1.8 × 10⁻⁵ (0.053 - x) - (0.083 + x) × x = 0

x = [OH⁻] = 1.15 x 10⁻⁵

The pH from the hydroxide ion is calculated as,

pOH = - log [OH⁻]

= - log (1.15 x 10⁻⁵)

= 4.94

Further,

pH = 14 - pOH

= 14 - 4.94

= 9.06

Therefore, option iii. 9.06 is the pH of the solution.

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The energy required to melt 20 g of water (ice) starting at 0° C is 6680 J.

Heat is a form of energy that is possessed by a system by virtue of its temperature. Its unit is Joule.

Enthalpy is the amount of the heat content of a system.

It is the amount of heat required to increase the temperature of a system by 1° C. It is an extensive property. Its unit is J/°C

Heat Capacity is given by

[tex]c= \frac{q}{\Delta T}[/tex]

where q = heat required

[tex]\Delta T[/tex] = change in temperature

Enthalpy of Fusion is the enthalpy change when 1 mole of a solid substance changes into its liquid state at its melting point.

Here, water in solid form (ice) melts into liquid form at 0°C

[tex]H_{2} O (s) \rightarrow H_{2} O(l) \\\Delta H_{fus } =334Jg^-^1[/tex]

We know,

[tex]\Delta H = \frac{m}{q}\\[/tex]

where m =  given mass

q = heat required

[tex]q = \Delta H \times m[/tex]

q = 334 [tex]Jg^-^1[/tex] x 20 g

    = 6680 J

Thus, the heat required to melt 20 g of water at 0°C is 6680 J

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Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.

Molecular weight of C4H10 is = 58.1 grams

Moles of butane = given mass/ molar mass

= 2/58.1

= 0.0344 mol

Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:

0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules

of butane

Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:

so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.

Thus the no. of carbon atom is 8.28×10^22.

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Answer: nutrient

Explanation:

In an ecosystem like where a farmer  stopped maintaining a field that was once used to grow crops. Over time, the field eventually became a forest. These changes best illustrate the process of nutrient recycling.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Ethers have a much lower boiling point than their isomeric alcohols because ether have not hydrogen bond that why ethers have lower boiling point .

Ethers will not have a hydrogen atom attached to the oxygen atom as alcohols do. Because ether molecules can not form intermolecular hydrogen bonds, their boiling points are much shorter than those of alcohol with such a comparable mass.

Owing to the combination of intermolecular H-bonding in alcohols though not in ethers, alcohols possess higher boiling temperatures than isomeric ethers.

Therefore, ethers have a much lower boiling point than their isomeric alcohols because ether have not hydrogen bond that why ethers have lower boiling point .

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The pressure of the gas is obtained as 48 atm.

Now we know that;

Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles

Number of moles of H2 =  56.0 grams/2 g/mol = 28 moles

Total number of moles present = 3 moles + 28 moles = 31 moles

Using;

PV =nRT

P = total pressure

V = total volume

n = total number of moles

R = gas constant

T = temperature

P = nRT/V

P = 31 * 0.082 * 286/15

P = 48 atm

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3.74×[tex]10^{21}[/tex]

3.74 ×[tex]10^{21}[/tex] molecules of propane were in the erlenmeyer flask.

number of moles of propane can be calculated as moles of propane.

mass of propane =  0.274 g

molar mass of propane = 44.1

So this gives us the value of 6.21×[tex]10^{-3}[/tex] moles of propane

No one mole of propane As a 6.0-2 × [tex]10^{23}[/tex]

so, 6.21 ×[tex]10^{-3}[/tex] × 6. 022 × 10^23

= 3.74 ×[tex]10^{21}[/tex]

Therefore, molecules of propane were in the erlenmeyer flask is found to be 3.74 ×[tex]10^{21}[/tex]

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Answer:

Explanation:

Take a look at the balanced chemical equation for this synthesis reaction

N

2(g]

+

3

H

2(g]

→

2

NH

3(g]

Notice that you have a

1

:

3

mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have

2

moles of nitrogen taking part in the reaction, you will need

2

moles N

2

⋅

3

moles H

2

1

mole N

2

=

6 moles H

2

The pH is 13.31.

The smaller the pH value the more acidic, the larger the pH value the more basic.

The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution.

Molarity of NaOH = 0.40 M

Volume of NaOH = 10.0 mL

Molarity of HCL = 0.50 M

Volume of HCL = 20.0 ml

[tex][OH^-] = (M_2V_2 -M_1V_1)/(V_1+V_2)\\[/tex]

         [tex]= (0.50*20.0 - 0.40*10.0) / (20+10)[/tex]

         [tex]= (10 -4)/ 30\\[/tex]

         [tex]= 6/30[/tex]

         [tex]=0.2[/tex]

[tex]pOH = - log (OH ^-)[/tex]

[tex]pOH = - log (0.2)\\[/tex]

[tex]pOH = - ( - 0.698)[/tex]

[tex]pOH = 0.69[/tex]

[tex]pH + pOH = 14[/tex]

[tex]pH = 14 -0.69[/tex]

[tex]pH = 13.31[/tex]

Therefore, the pH after 10.0 mL of 0.40 M NaOH is 13.31.

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The pH at 25°c of a 0. 0077 m solution of a weak base with a kb of 6. 2 × 10−9 is 8.8.

The base dissociation constant is termed as Kb. Throughout a base split into ts constituent ions in water is determined by its base dissociation constant.

Kb = [B+] [OH-]/[BOH]

Now, let the concentration of [B+] = [OH-] = x

Given,

Kb = 6. 2 × 10^-9

6. 2 × 10^-9 = x^2/(0.0077-x)

x = 6.909 × 10^(-6)

[B+] = [OH-] = 6.909 × 10^(-6)

As we know that,

pOH = -log [OH-]

pOH = -log( 6.909 × 10^(-6))

pOH = 5.2

As we also know that,

pOH + pH = 14

pH = 14 - pOH

pH = 14 - 5.2

pH = 8.8

Thus we calculated that the pH of the solution is 8.8.

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Molecular formula of a compound whose molecular mass is 60.00 g/mol and has an empirical formula of C₂H₈N₂.

We know the empirical formula and thus the molar mass of the empirical formula, we simply need to find out how many of these fit into the molar mass of the molecular formula.

In this problem, we have an empirical formula of CH₄N

so the molar mass is 12 + 4 + 14 = 30 g/mol.

Molecular formula mass/Empirical formula mass=60 g/mol/30 g/mol=2

The molecular formula is TWICE that of the empirical formula.

Molecular formula = 2XCH₄N = C₂H₈N₂

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Answer:

C2H8N2

Explanation:

edge 2023

Answer:

1. Carbon is very special because it can form so many compounds

2. Many carbon-based compounds are not attracted to water and so in general do not dissolve in water. As a result, water alone cannot be used to remove grease or oil from a surface, nor will water dissolve our skin, because all of these things are carbon compounds.

3. Carbon can also link together in long chains or rings, carbon to carbon to carbon to carbon and so on.

Explanation:

Point defects are possible for al2o3 as an impurity in mgo. then 2 Al3+ must be added to form 1 Mg2+  must be added to form each of these defects

Point defects are zero-dimensional lattice defects, meaning they lack lattice structure in any dimension. Impurity atoms in a pure metal, vacancies, and self-interstitials are examples of common point defects.

Point defects are zero-dimensional lattice defects, which means they lack any kind of lattice structure. Point defects include, but are not limited to, atoms of impurity in a pure metal, vacancies, and self-interstitials.

The term "point defect" refers to the flaw or imperfection that results from the placement of a point-like constituent particle, such as an atom, an ion, or a molecule, in a crystalline structure.

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Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen . Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen

0.5

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The type of reaction that is represented by these diagrams (attached) are given as:  "condensation polymerization" (Option D)

Any type of polymer in polymer science that undergoes a condensation reaction during the polymerization process is referred to as a condensation polymer (i.e. a little molecules, methanol or water is derived as a metabolite).

The provided reaction is an example of condensation polymerization because it involves the combination of two monomers, which produces a big polymer and water as a byproduct.

Condensation polymers make significant contributions to the packaging, insulation, and textile sectors as far as real-world application of same is concerned.

Also examples of times that are condensation polymers and that have silicon rather than carbon as part of their molecular or structural make up are;

In conclusion, it is to be noted that The type of reaction that is represented by these diagrams (attached) are given as:  "condensation polymerization"

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Answer:

condensation polymerization

Explanation:

The enthalpy of reaction (ΔH) of the above chemical reaction is equal to -143 kJ/mol.

A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

Next, we would write the properly balanced chemical equation for this chemical reaction:

                                    3/2O₂ -----> 2/2O₃

Therefore, the enthalpy of reaction (ΔH) of the above chemical reaction is half the enthalpy of reaction (ΔH) of the initial chemical reaction:

Enthalpy of reaction (ΔH) = ½ × -286 kJ/mol

Enthalpy of reaction (ΔH) = -143 kJ/mol.

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Answer:

This is the answer

Explanation:

charges passed = current x time = 10 x 3 x 60

= 1800 C

mole of charge = 1800 / 96500

= .01865 moles

Au+3 contains 3 positive charges

3 mole of charge will deposit 1 mole of Au .01865 moles will deposit .01865 / 3 mole

= 6.2167 x 10-3 moles.

The pH of a  a 0. 10 m solution of NaCN at 25°C is 11.15

Calculation

The reaction in the solution is given below

                   [tex]CN^{-} + H_{2} O[/tex] → HCN + [tex]OH^{-}[/tex]

initial                    0.1

change           ( -x)                (+x)

equilibrium     (  0.1 - x )         x

Kb = [HCN] [[tex]CN^{-}[/tex] ]/[[tex]CN^{-}[/tex] ]

Kb × Ka = Kw = 1.0 × [tex]10^{-14}[/tex]

Kb =  1.0 × [tex]10^{-14}[/tex] / 4.9  × [tex]10^{-10}[/tex] =  [HCN] [[tex]CN^{-}[/tex] ]/[[tex]CN^{-}[/tex] ] = [tex]x^{2}[/tex]/ (  0.1 - x )

Kb =  2.04× [tex]10^{-5}[/tex] = [tex]x^{2}[/tex]/ (  0.1 - x )

Since , [NaCN] /Kb > 100 , we can simplify the above equation to

=  2.04× [tex]10^{-5}[/tex] = [tex]x^{2}[/tex]/ (  0.1 )

x = 1.43 × [tex]10^{-3}[/tex] M = [HCN] = [ [tex]OH^{-}[/tex]]

Then pOH = 2.84

pH + pOH = 14

pH = 14- pOH = 14 - 2.84 = 11.15

Therefore , the pH is 11.15

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