Statement b and d are inconsistent with Dalton's atomic theory.
Dalton's atomic theory, as originally stated, includes the following postulates:
All matter is made up of tiny, indivisible particles called atoms.
All atoms of a given element are identical in mass and properties.
Compounds are formed when atoms of different elements combine in fixed ratios.
Chemical reactions involve the rearrangement of atoms; no atoms are created, destroyed or changed into atoms of another element.
Statement b contradicts postulate 3 by suggesting that a water molecule is formed from 1.5 hydrogen atoms and 1 oxygen atom. However, in Dalton's theory, atoms combine in whole-number ratios to form compounds.
Statement d contradicts postulate 4 by suggesting that the formation of a compound involves the destruction of one or more atoms. However, in Dalton's theory, atoms are neither created nor destroyed in chemical reactions. Instead, they are rearranged to form new compounds.
Statement a and c are consistent with Dalton's atomic theory as all atoms of a given element are identical in mass and properties and compounds are formed when atoms of different elements combine in fixed ratios.
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Nan is upset because she has not lost enough weight to buy the new swimsuit that she had wanted, so she imagines herself on the beach having fun with her friends in her current swimsuit. Nan is using mental images to
Group of answer choices
When the accompanying stimuli are not present, we can alter and reactivate internal representations through mental imagery. This procedure results in the phenomenon known as "seeing with the mind's eye" when it comes to visual mental images. Thus, option B is correct.
What is the use of mental images?Mental imagery is mostly used to simulate potential future events and "relive" previous experiences. According to this viewpoint, imagery ought to be investigated in a variety of cognitive tasks as well as on its own.
Although it is widely used to enhance physical performance, mental imagery can also benefit tasks that need both cognitive and emotional functioning, such as managing emotions and stress or public speaking.
Therefore, change her feelings. Studies have demonstrated that imaging can promote relaxation in the body and mind. Manage depression, stress, and anxiety are other benefits. Help lessen the agony
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The given question is incomplete. The complete question is given below:
Nan is upset because she has not lost enough weight to buy the new swimsuit that she had wanted, so she imagines herself on the beach having fun with her friends in her current swimsuit. Nan is using mental images to
a.
Prepare for some action.
b.
Change her feelings.
c.
Make a decision.
d.
Aid memory.
What is the mass of a car possessing 15,000 kg*m/s of momentum going a speed of 35 m/s?
A.525000 kg
B.428.6 kg
C.14965 kg
D.0.0023 kg
Answer: B is correct
Explanation: The mass of the car can be calculated using the equation: mass = momentum / velocity Therefore, the mass of the car is: mass = 15,000 kg*m/s / 35 m/s mass = 428.6 kg
What is electric resistance? Describe differet factors which affect electr resistance.
Answer:
That is, electrical resistance–is a force that counteracts the flow of current. In this way, it serves as an indicator of how difficult it is for current to flow. Resistance values are expressed in ohms (Ω). Or electrical Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.
There are four factors that affect the resistance of a wire ( electrical resistant metal ) :
Resistance is proportional to length. If you take a wire of different lengths and give each a particular potential difference across its ends. The longer the wire the less volts each centimeter of it will get. This means that the 'electric slope' that makes the electrons move gets less steep as the wire gets longer, and the average drift velocity of electrons decreases. The correct term for this 'electric slope' is the potential gradient. A smaller potential gradient (less volts per metre) means current decreases with increased length and resistance increases.
Resistance is inversely proportional to cross-sectional-area. The bigger the cross sectional area of the wire the greater the number of electrons that experience the 'electric slope' from the potential difference. As the length of the wire does not change each cm still gets the same number of volts across it - the potential gradient does not change and so the average drift velocity of individual electrons does not change. Although they do not move any faster there are more of them moving so the total charge movement in a given time is greater and current flow increases. This means resistance decreases. This does not give rise to a straight line graph as cross sectional area is inversely proportional to resistance not directly proportional to it
Resistance depends on the material the wire is made of. The more tightly an atom holds on to its outermost electrons the harder it will be to make a current flow. The electronic configuration of an atom determines how willing the atom will be to allow an electron to leave and wander through the lattice. If a shell is almost full the atom is reluctant to let its electrons wander and the material it is in is an insulator. If the outermost shell (or sub-shell with transition metals) is less than half full then the atom is willing to let those electrons wander and the material is a conductor.
Resistance increases with the temperature of the wire. The hotter wire has a larger resistance because of increased vibration of the atomic lattice. When a material gets hotter the atoms in the lattice vibrate more. This makes it difficult for the electrons to move without interaction with an atom and increases resistance. The relationship between resistance and temperature is not a simple one.
Have a wonderful day! :-)
Students are conducting an experiment. One student has kept 3 books and another student 6 books. They are using a ramp with same size and dimensions. They are measuring the distance travelled by the car. What they are trying to find out? Will you be able to predict the outcome and give conclusion for that experiment?
A student conducts an experiment to find the speed of a toy car that has been released from various heights on a ramp as it reaches the bottom of the ramp.
What are the outcomes of the experiment?The student may need to obtain more height measurements in order to confirm the accuracy of his experiment and thereby enhance it. By averaging all the heights, it is now possible to determine the height's accuracy.
The results show the speed of a toy car from different heights measurements and can be improved by doing different trials.
Therefore, students try to find out the speed of a toy car from different heights.
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A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west.. After they collide, the two interlock and move together. What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)*
A. 11.25 m/s west
B. 11.25 m/s east
C. 32.6 m/s east
D. 32.6 m/s west
The final velocity of the truck after collision, given that the car and the truck interlock and move together is 11.25 m/s west (Option A)
How do I determine the final velocity of the truck?The final velocity of the truck after the collision can be obtained as illustrated below:
Mass of car (m₁) = 1500 KgInitial velocity of car (u₁) = 20 m/sMass of truck (m₂) = 2500 KgInitial velocity of truck (u₂) = 11 m/sEast = Positvie directionWest = Negative directionFinal velocity (v) = ?Momentum before = momentum after
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(1500 × 20) - (2500 × 30) = v(1500 + 2500)
30000 - 75000 = v × 4000
-45000 = v × 4000
Divide both sides by 4000
v = -45000 / 4000
v = -11.25 m/s
Recall => West is negative
v = 11.25 m/s west
Thus, the final velocity is 11.25 m/s west (Option A)
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Which factors affect the gravitational force between two objects?
distance and velocity
O mass and distance
mass and weight
O acceleration and weight
Answer:
mass and distance
Explanation:
I could explain it but I don't know how to word it xd
Answer:
My best guess is:
B) mass and distance
This is because gravity is affected by the size of objects and the distance between objects.
Explanation:
Hope it helps! =D
What things would be difficult or impossible if you were born deaf? One teacher of the deaf said that being deaf is analogous to being in a soundproof booth while a person outside is trying to teach you Japanese. Actually, she said, you (as a hearing person) have the easier job because you know what you are expected to do, and you can hear yourself speaking. The deaf child does not and cannot.
Answer:
you would have difficulty hearing on a daily basis, as mentioned in the example, but you would also have trouble getting jobs, you would have fewer educational opportunities, and also a lack of awareness of your everyday surroundings.
Explanation:
A car moving with an initial velocity of 25 m/s north has a constant acceleration of 5.5 m/s2 south. After 10 seconds its velocity will be
Answer:
80 m/s
Explanation:
v = v₀ + at
v = 25 m/s + (5.5 m/s²)(10 s) = 80 m/s
Which is matched correctly with its unit of measure?
luminous flux - lumens
illuminance - malus
illuminance - lumens
luminous flux - lux
Correctly matched with its unit of measure is : luminous flux - lumens
What is luminous flux?Luminous flux is also called luminous power. It is is the measure of perceived power of light and it differs from the measure of total power of light emitted, called 'radiant flux'.
In photometry, measure of the perceived power of light is known as luminous flux . It differs from radiant flux, measure of the total power of electromagnetic radiation, in that luminous flux is adjusted to reflect varying sensitivity of human eye to different wavelengths of light.
Lumen is the standard unit of luminous flux and luminous flux is the measure of perceived power of light by human eye and we measure luminous flux in lumens.
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Using the internet to help answer this question...Does a Komodo Dragon reproduce sexually or asexually
Komodo's dragons reproduce through both sexual reproduction and a form of asexual reproduction called parthenogenesis.
What is parthenogenesis?A zygote lacking gametes forms during parthenogenesis. Invertebrates and lower plants frequently exhibit it.
As it turns out, the Komodo dragon is capable of both sexual and asexual reproduction, depending on the circumstances. The majority of zoos keep female dragons alone and apart from the males.
Therefore, both sexual reproduction and parthenogenesis, a type of asexual reproduction, are used by Komodo dragons to breed.
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Consider a ball on a circular track. The ball is slowly coming to a stop which takes 15.0 seconds. At the start, the ball was moving around with 9.13 rad/s. Calculate the angular deceleration if the ball traveled across 90 radians.
The answer should be -0.42 rad/s2
I don't know how to solve it
The angular deceleration of the ball is -0.42 rad/s².
What is angular acceleration?Angular acceleration is a measure of the rate of change of angular velocity of an object rotating about an axis. When an object rotates, its angular velocity (ω) can change as a result of various factors, such as the application of an external torque or the redistribution of mass in the object.
We can use the formula for angular acceleration:
α = (ωf - ωi) / t
where
α is the angular acceleration
ωi is the initial angular velocity
ωf is the final angular velocity (which is zero in this case since the ball comes to a stop)
t is the time it takes for the ball to come to a stop
To find the initial and final angular positions, we can use the formula:
θf - θi = ωi * t + (1/2) * α * t²
where
θi is the initial angular position (0 in this case)
θf is the final angular position (90 radians in this case)
Substtuting the given values, we have:
θf - θi = ωi * t + (1/2) * α * t²
90 - 0 = (9.13 rad/s) * 15 s + (1/2) * α * (15 s)²
Simplifying and solving for α, we get:
α = -0.42 rad/s²
Therefore, the angular deceleration of the ball is -0.42 rad/s².
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One pipe can fill a tank in 3 hours, and another pipe can fill the tank in 6 hours. How long will it take to fill the tank if both pipes are used at the same time?
It will take both pipes working together 2 hours to fill the tank. As in general, when two pipes or machines are working together to complete a task, their combined rate is the sum of their individual rates.
Let's assume that the tank has a volume of 1 unit (you can use any unit you prefer).
The first pipe can fill the tank in 3 hours, which means it can fill 1/3 of the tank in one hour. Similarly, the second pipe can fill the tank in 6 hours, which means it can fill 1/6 of the tank in one hour.
If both pipes are used at the same time, the rate at which they fill the tank is the sum of their individual rates. So, the combined rate at which they fill the tank is:
1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2
This means that both pipes together can fill half of the tank in one hour. To fill the entire tank, we need to multiply this rate by the time it takes to fill the tank, which we'll call "t":
1/2 * t = 1
Solving for "t", we get:
t = 2 hours
Therefore, it will take both pipes working together 2 hours to fill the tank.
This same concept can be applied to many different types of problems involving pipes, machines, or workers working together to complete a task. The key is to find the individual rates of each pipe or machine and add them together to get the combined rate. Then, you can use the combined rate to find the time it takes to complete the task.
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A soccer ball is kicked with a speed of 15.6 m/s
at an angle of 52.5 ∘
above the horizontal.
If the ball lands at the same level from which it was kicked, for what amount of time was it in the air?
According to the question the soccer ball was in the air for a total of 2.26 seconds.
What is air?Air is a mixture of gases made up of nitrogen (78%), oxygen (21%), and other trace gases like argon and carbon dioxide (1%). This mixture of gases makes up a unseen fluid we call air. It is all around us, surrounding us and filling the space between us and the Earth.
The time that the soccer ball was in the air can be determined using the kinematic equations of motion. First, we need to calculate the initial vertical and horizontal velocity components of the ball when it is kicked. The vertical velocity component is given by Vy = V*sin(angle) = 15.6 m/s * sin(52.5°) = 11.2 m/s.
The horizontal velocity component is given by Vx = V*cos(angle) = 15.6 m/s * cos(52.5°) = 9.2 m/s.
Now we can solve for time using the equation t = (2*Vy)/g, where Vy is the vertical velocity component and g is the acceleration due to gravity (9.8 m/s2). Thus, t = (2*11.2 m/s)/9.8 m/s2 = 2.26 s.
Therefore, the soccer ball was in the air for a total of 2.26 seconds.
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A child operating a radio-controlled model car on a dock accidentally steers it off the edge. The car’s displacement 1.0s after leaving the dock has a magnitude of 6.5 m. What is the cars speed at the instant it drives off the edge of the dock?
The speed is 6.5 m/s.
What is speed?Speed is a scalar quantity that represents the rate at which an object is moving. It is defined as the distance traveled by an object in a certain amount of time. The formula for speed is:
speed = distance ÷ time
where distance is the total distance traveled by the object and time is the duration of the journey. The unit of speed is usually meters per second (m/s) or kilometers per hour (km/h).
In this case, we would take the speed and the velocity to be the same;
Speed/Velocity = Displacement/Time
= 6.5 m/ 1.0 s
= 6.5 m/s
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According to dalton's law of partial pressures, the pressure of oxygen in dry air would be.
The pressure of oxygen in dry air at standard atmospheric pressure is approximately 22.3 kilopascals.
What is Dalton's law of partial pressure?The overall pressure of a gas mixture is equal to the sum of the partial pressures of each gas in the mixture, according to Dalton's law of partial pressures.
With a few other gases present in trace levels, nitrogen and oxygen make up roughly 78% and 21% of the atmosphere, respectively, in dry air.
As a result, using Dalton's law, the pressure of oxygen in dry air can be computed as follows:
Total pressure of dry air equals the pressure of nitrogen, oxygen, and any additional gases.
Total pressure of dry air = pressure of nitrogen + pressure of oxygen
Pressure of oxygen = Total pressure of dry air - pressure of nitrogen
= 101.3 kPa - 79 kPa
= 22.3 kPa
Thus, this is the pressure of oxygen in dry air.
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The mass of Jupiter is 1/1047 of the Sun's mass (that's 0.000955). We want to confirm this using Newton's version of Kepler's Third Law, following the examples in Lecture 7. We'll use the approximate data for two different moons of Jupiter to see how close the results are. Pick the closest answer in each case: (a) Ganymede is the third moon from the inside. It has an orbital period around Jupiter of approximately 0.0194 Earth years. Its semimajor axis is 0.0071 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data → [Select ] 0.000951 (b) Europa is the second moon from the inside. It has an ork 0.000989 approximately 0.0096 Earth years. Its semimajor axis is 0.0045 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data? [Select] Hint: See also example 3.4 in the textbook.
These come closest to the mass of Jupiter as (a) 0.000951; (b) 0.000955.
what is Kepler's law?Kepler's laws describe the motion of planets in their orbits around the sun.
This question involves using Newton's version of Kepler's Third Law to calculate the mass of Jupiter. Kepler's Third Law states that the square of the period of revolution of a planet/moon around a central object is proportional to the cube of the semimajor axis of the orbit. Newton's version of the law introduces the masses of the two objects in the equation, allowing us to solve for the mass of the central object (in this case, Jupiter) if we know the period and semimajor axis of a moon's orbit around it.
For part (a), we are given the period and semimajor axis of Ganymede's orbit and asked to select the closest answer for the mass of Jupiter when using this data. By plugging the values into Newton's version of Kepler's Third Law and solving for Jupiter's mass, we get an answer of 0.000951 solar masses.
For part (b), we are given the period and semimajor axis of Europa's orbit and asked to select the closest answer for the mass of Jupiter when using this data. Again, by plugging the values into the equation and solving for Jupiter's mass, we get an answer of 0.000989 solar masses.
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Find the moment of inertia for the following objects:
A. A uniform disc of mass M and radius R rotating about its axis. Replace the sum in 3.31 by the appropriate integral and do the integral in polar coordinates.
B. A uniform solid sphere rotating about a diameter. Replace the sum in 3.31 by the appropriate integral and do the integral in spherical coordinates.
The moment of inertia of a uniform disc of mass M and radius R rotating about its axis is [tex](1/2) MR^2[/tex].
The moment of inertia of a uniform solid sphere of mass M and radius R rotating about a diameter is [tex](8/5) MR^2[/tex].
The moment of inertia of a uniform disc of mass M and radius R rotating about its axis can be found by integrating the moment of inertia of small elements of mass dm located at a distance r from the axis of rotation.
Using polar coordinates, we can write dm = (M/πR^2)rdrdθ, where r ranges from 0 to R and θ ranges from 0 to 2π.
The moment of inertia of each element is given by dI = dm r^2. Therefore, we have:
I = ∫dI
= ∫[tex]r^2 dm[/tex]
= ∫₀²π ∫₀ᴿ (M/πR^2)r³drdθ
= (M/πR^2) ∫₀²π [∫₀ᴿ r³dr] dθ
= (M/πR^2) ∫₀²π [(1/4)R^4] dθ
= (M/πR^2) (1/4)R^4 (2π)
= [tex](1/2) MR^2[/tex]
The moment of inertia of a uniform solid sphere of mass M and radius R rotating about a diameter can be found by integrating the moment of inertia of small elements of mass dm located at a distance r from the diameter. Using spherical coordinates, we can write dm = (M/4πR^3)r^2sinθdrdθdφ, where r ranges from 0 to R, θ ranges from 0 to π, and φ ranges from 0 to 2π. The moment of inertia of each element is given by dI = dm r^2sin^2θ. Therefore, we have:
I = ∫dI = ∫r^2sin^2θ dm = ∫₀²π ∫₀ᴾ ∫₀ᴿ (M/4πR^3)r^4sin^3θdrdθdφ
= (M/4πR^3) ∫₀²π ∫₀ᴾ [∫₀ᴿ r^4sin^3θdr] dθdφ
= (M/4πR^3) ∫₀²π ∫₀ᴾ [(2/5)R^5sin^3θ] dθdφ
= (2/5) MR^2 ∫₀²π [∫₀ᴾ sin^3θ dθ] dφ
= (2/5) MR^2 ∫₀²π [(-cosθ + (3/2)cos^3θ/3)|₀ᴾ] dφ
= (8/15) MR^2 ∫₀²π dφ
= (8/15) MR^2 (2π)
= (8/5) MR^2
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What is the average distance from Sun in AU of an object with a planetary object with orbital period of 325 years?
Answer: So, the average distance from the Sun of a planetary object with an orbital period of 325 years is approximately 40.0 AU.
Explanation:
The average distance from the Sun (in astronomical units) of a planetary object with an orbital period of 325 years can be estimated using Kepler's Third Law of Planetary Motion. This law states that the square of the orbital period (T) of a planet is proportional to the cube of its average distance from the Sun (r):
T^2 = k * r^3
where k is a constant. We can rearrange this equation to solve for r:
r = (T^2 / k)^(1/3)
The value of k depends on the units used for T and r, so it is important to make sure that the units are consistent. If T is in years and r is in astronomical units (AU), then k has a value of approximately 4π^2.
Using this formula, we can estimate the average distance from the Sun of a planetary object with an orbital period of 325 years:
r = (325^2 / (4 * π^2))^(1/3)
r ≈ 40.0 AU
So, the average distance from the Sun of a planetary object with an orbital period of 325 years is approximately 40.0 AU.
A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. What is the average velocity of the deer during this time?
Answerbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Explanation:
A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. Therefore, 60m/s is the average velocity of the deer during this time.
What is average velocity?Motion may be defined using physical quantity concepts such as speed, velocity, duration, displacement, as well as acceleration. Sir Isaac Newton provided the correct explanation of motion.
All of these quantities are explained in terms of a single quantity, time. In this section, we will look at average velocity, its mathematical representation, and its graphical depiction.
average velocity = 520 m+ 380 m / 15=60m/s
Therefore, 60m/s is the average velocity of the deer during this time.
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The
The leader of a bicycle race is traveling with a constant velocity of +11.1 m/s and is 9.60 m ahead of the second-place
second-place cyclist has a velocity of +9.80 m/s and an acceleration of +1.20 m/s². How much time elapses before he catches the
leader?
Answer:
We can use the following kinematic equation to solve the problem:
Δx = v1(t) + (1/2)a2t²
where Δx is the initial separation between the two cyclists, v1 is the velocity of the leader, a2 is the acceleration of the second-place cyclist, and t is the time taken for the second-place cyclist to catch up with the leader.
Substituting the given values, we get:
9.60 m = (11.1 m/s)t + (1/2)(1.20 m/s²)t²
Simplifying and rearranging the equation, we get a quadratic equation in t:
0.6t² + 11.1t - 9.60 = 0
We can solve for t using the quadratic formula:
t = [-11.1 ± √(11.1² - 4(0.6)(-9.60))] / (2(0.6))t = [-11.1 ± 12.7] / 1.2
t = 0.91 s or t = -18.43 s
Since time cannot be negative, we can discard the negative solution. Therefore, the time taken for the second-place cyclist to catch up with the leader is:
t = 0.91 s
Hence, it will take 0.91 s for the second-place cyclist to catch up with the leader.
Explanation:
If two bowling balls were to collide head on stick to one another, with some loss in kinetic energy, the collision would be considered a(n) ___________ collision.*
A. Cushy
B.Perfectly Inelastic
C.Reversable
D.Elastic
Answer: D
Explanation:An inelastic collision is one in which objects stick together after impact, and kinetic energy is not conserved. This lack of conservation means that the forces between colliding objects may convert kinetic energy to other forms of energy, such as potential energy or thermal energy.
A wagon is push on a frictionless surface with a force of 10 Newtons. The acceleration of the wagon is measure to be 10/m/s/s. The same wagon is then pushed on a frictionless surface with a force of 20 Newtons. What is the new acceleration of the wagon? Explain why you chose your answer.
The new acceleration of the wagon is 20 m/s.
According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Thus, the acceleration of the wagon pushed with a force of 10 Newtons can be calculated using the formula:a = F/m
Where,
a is the acceleration,
F is the net force, and
m is the mass of the wagon.
Given that the force is 10 Newtons and the acceleration is 10 m/s/s, we can solve for the mass of the wagon, which is:m = F/a = 10 N / 10 m/s = 1 kg
Now, if the same wagon is pushed with a force of 20 Newtons, the new acceleration can be calculated using the same formula:a' = F'/m
Where,
a' is the new acceleration,
F' is the new net force, and
m is the mass of the wagon.
Substituting the values, we get:
a' = 20 N / 1 kg = 20 m/s/s
Therefore, the new acceleration of the wagon is 20 m/s/s when it is pushed with a force of 20 Newtons on a frictionless surface.
This result shows that the acceleration of the wagon is directly proportional to the net force acting on it, as predicted by Newton's Second Law.
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how to solve velocity ratio
In the 2nd lab you were studying water squirting out from a hole in a cylinder filled with water into a tub. Just as a falling ball converts potential energy to kinetic energy, water pressure pushed water out of the hole by converting potential energy per unit volume (density x g x height) to kinetic energy per unit volume (density x velocity^2/2). Assume you have a 20 cm head of water above the hole and that the hole is 40 cm above ground.
How will the water reach by the time it touches the ground (in cm)?
Sandra who is a Level 200 student of SoE and also a snowboarder starts from rest at the top of a double black diamond hill. As she rides down the slope, GPS coordinates are used to determine her displacement as a function of time: x=0.5t3 + 6t2 +3t where x is in metres and t is in seconds. where x and t are expressed in feet and seconds, respectively. a) Determine the position of the boarder when t = 4 s b) Determine the velocity of the boarder when t = 4s c) Determine the acceleration of the boarder when t = 4s 2021/22
Explanation:
a) To determine the position of the snowboarder when t = 4 seconds, we can substitute t = 4 into the equation x = 0.5t^3 + 6t^2 + 3t:
x = 0.5 * 4^3 + 6 * 4^2 + 3 * 4
x = 64 + 96 + 12
x = 172
So when t = 4 seconds, the snowboarder's position is 172 meters.
b) To determine the velocity of the snowboarder when t = 4 seconds, we'll need to find the first derivative of the displacement function x = 0.5t^3 + 6t^2 + 3t with respect to time:
dx/dt = 3 * 0.5 * t^2 + 2 * 6 * t + 3
Next, we can substitute t = 4 into this expression to find the velocity when t = 4 seconds:
dx/dt = 3 * 0.5 * 4^2 + 2 * 6 * 4 + 3
dx/dt = 72 + 48 + 3
dx/dt = 123
So the velocity of the snowboarder when t = 4 seconds is 123 meters per second.
c) To determine the acceleration of the snowboarder when t = 4 seconds, we'll need to find the second derivative of the displacement function x = 0.5t^3 + 6t^2 + 3t with respect to time:
d^2x/dt^2 = 6 * 0.5 * t + 2 * 6
Next, we can substitute t = 4 into this expression to find the acceleration when t = 4 seconds:
d^2x/dt^2 = 6 * 0.5 * 4 + 2 * 6
d^2x/dt^2 = 24 + 12
d^2x/dt^2 = 36
So the acceleration of the snowboarder when t = 4 seconds is 36 meters per second squared.
Calculate the total work done on a mass m as it moves from position x1 = 0 m to x2 = 40 m
F1 = 5 N F2 = 6 N angle between them 50 degree
F3 = 2 N F4 = 2 N Angle Between them 20 Degree
The total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.
What is Work Done?
Work is a physical quantity that describes the amount of energy transferred when a force acts on an object and causes it to move. When a force acts on an object and causes it to move in the direction of the force, work is said to be done on the object. Mathematically, work is defined as the dot product of force and displacement:
Work = Force x Displacement x cos(theta)
To calculate the total work done on the mass as it moves from position x1 to x2, we need to find the net work done by all the forces on the mass. The net work done by a force is given by the formula:
W = F * d * cos(theta)
where W is the work done, F is the force, d is the displacement of the mass, and theta is the angle between the force and the displacement.
First, we can calculate the work done by each force separately and then add them up to find the total work done.
Work done by F1:
W1 = F1 * (x2 - x1) * cos(0) = 5 N * 40 m * cos(0) = 200 J
Work done by F2:
W2 = F2 * (x2 - x1) * cos(50°) = 6 N * 40 m * cos(50°) ≈ 165.41 J
Work done by F3:
W3 = F3 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J
Work done by F4:
W4 = F4 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J
The total work done on the mass is the sum of the work done by each force:
W_total = W1 + W2 + W3 + W4 ≈ 515.17 J
Therefore, the total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.
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You are asked to figure out the size of an air bladder (a balloon that inflate and deflate to change the buoyancy of a profiling float) a profiling float should have to be able to profile from 1000m to the surface should be (at least). To figure it out, you look at profiles of density from the region where you will be deploying the float (see attached figure) and compute the maximum difference in density (=1000+sigma_theta) between 1000m and the surface.
Your float is a perfect cylinder with 20cm in diameter and 1.5m in length. Figure out its volume, Figure out the mass it should have, without inflating the bladder, to match the largest density observed at 1000m, so it can be neutrally buoyant at that depth (neither sinking or floating).
Finally, given the above, how big should the air bladder be (in minimum and in ml=cm^3) to that when inflated the float will be buoyant at the surface for all conditions observed at that region?
The minimum size of the air bladder [tex](in ml=cm^3)[/tex] should be[tex]2*σθ * 706.5 cm^3[/tex] to make sure that when inflated, the float will be buoyant at the surface for all conditions observed at that region.
What is air bladder?An air bladder is a sac-like organ that is filled with air and is found in certain aquatic animals, such as fish, amphibians, and certain invertebrates. It is used for buoyancy control, allowing the animal to adjust its position in the water column.
Volume of perfect cylinder =[tex]πr^2h[/tex]
[tex]= 3.14 * (10cm/2)^2 * 1.5m= 706.5 cm^3[/tex]
Mass of the float at 1000m = Density at 1000m * Volume of the float
[tex]= (1000+σθ)* 706.5 cm^3= (1000+σθ) * 706.5 g[/tex]
Air bladder size (minimum) = Mass of the float at 1000m - Mass of the float at surface
[tex]= (1000+σθ) * 706.5 g - (1000-σθ) * 706.5 g= 2*σθ * 706.5 g= 2*σθ * 706.5 cm^3[/tex]
Therefore, the minimum size of the air bladder (in ml=cm^3) should be [tex]2*σθ * 706.5 cm^3[/tex] to make sure that when inflated, the float will be buoyant at the surface for all conditions observed at that region.
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A blue marble of mass 0.350 kg traveling at 2.60 m/s to the left collides with a red marble of mass 0.350 kg that is initially at rest. After the collision, the blue marble is at rest. What is the new velocity of the red marble that is now moving in the same direction?
A.2.60 m/s to the left
B.0.350 m/s to the right
C.5.20 m/s to the left
D.0.91 m/s to the left
Answer:
[tex]2.60\; {\rm m\cdot s^{-1}}[/tex] to the left.
Explanation:
When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum of that object would be [tex]p = m\, v[/tex]. Note that since velocity is a vector quantity (has a direction) while mass is a scalar, the direction of momentum would be the same as that of velocity.
Before the collision:
Momentum of the blue marble: [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})[/tex] to the left.Momentum of the red marble would be [tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex] since velocity was [tex]0\; {\rm m\cdot s^{-1}}[/tex].Immediately after the collision:
Momentum of the blue marble would be [tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex].The momentum of the red marble needs to be found.Momentum is conserved immediately before and after the collision. In other words, the total momentum immediately after the collision would be the same as that immediately before the collision.
In this example, total momentum was [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})[/tex] to the left immediately before the collision. Hence, the total momentum immediately after the collision would also be [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})\![/tex] to the left.
Subtract the momentum of the blue marble ([tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex]) from the total momentum to find the momentum of the red marble:
[tex]\begin{aligned}& (0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) - 0\; {\rm kg\cdot m\cdot s^{-1}} \\ =\; & (0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) && (\text{to the left}) \end{aligned}[/tex].
Divide momentum by mass to find velocity:
[tex]\begin{aligned} v &= \frac{p}{m} \\ &= \frac{(0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) }{0.350\; {\rm kg}}&& \genfrac{}{}{0em}{}{(\text{to the left})}{} \\ &= 2.60\; {\rm m\cdot s^{-1}} && (\text{to the left})\end{aligned}[/tex].
Therefore, the velocity of the red marble would be [tex]2.60\; {\rm m\cdot s^{-1}}[/tex] to the left immediately after the collision.
Forensic Entomology
Forensic Entomology
The study of the life cycle of insects that feed on the flesh to the dead, to establish time of death and occasionally identify chemicals present in a person's body at the time of death.
Time since death
Arrive a few hours after a death and are active through decomposition process. They feed on larvae and other insects rather than the corpse itself.
Larvae that feed on human excrement and remains, and are found late in the decomposition process.
Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death
What is meant by Forensic Entomology?The scientific study of the colonization of dead body by arthropods is called forensic entomology .
Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles
Time since death : postmortem Interval.
Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.
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Compared to the audible range for the average human ear, infrasonic waves have a
A. Lower frequency & longer wavelength
B. Higher frequency & shorter wavelength
C. Lower frequency & shorter wavelength
D. Higher frequency & longer wavelength
The Lower frequency & longer wavelength is the correct option (a).
What is frequency ?
The frequency is expressed in Hertz. A sound wave's frequency is determined by how many vibrations it produces ( f ). Another way to think of frequency is as the quantity of waves that pass a specific spot in a second.
What is wavelength ?
The distance between identical points (adjacent crests) in adjacent cycles determines how far a waveform signal has travelled in space or over a wire. In wireless systems, this length is often expressed in metres (m), centimetres (cm), or millimetres (mm).
Therefore, The Lower frequency & longer wavelength is the correct option (a).
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