Which table represents a linear function that has a slope of 5 and a y-intercept of 20?

Answer:

i don't understand the question

Answer:

the answer is D

Answer:

D. - 5n - 6

Step-by-step explanation:

- 4 ( n + 1 ) - ( n + 2 )

= - 4n - 4 - n - 2

= - 4n - n - 4 - 2

= - 5n - 6

Answer:

See Explanation

Step-by-step explanation:

(For Diagram please find in attachment)

Since DE∥BC

∴ By Basic Proportionality Theorem,

AD/DB  = AE/EC

​ Since it is Given, AD=DB

∴ AE/EC  =1

∴ AE=EC  (Proved)

Answer:

3x-14=180

3x=194

x= 64 2/3

4(x-9)=180

4x-36=180

4x=216

x=54

Hope This Helps!!!

Step-by-step explanation:

(3x-14)°=180°

3x-14=180

3x=180+14

3x=194

x=64.6

[4(x-9)]°=180°

4x-36=180

4x=180+36

4x=216

x=54

Answer:

b . is the answer

Step-by-step explanation:

ha ahhgahga

Answer:

Solution given:

Let there be a point P(x, y) equidistant from

A(-3, 2) and B(0,4),

so PA = PB,

[tex]\sqrt{(x+3)²+(y-2)²}=\sqrt{(x-0)²+(y-4)²}[/tex]

squaring both side

[tex](\sqrt{(x+3)²+(y-2)²})^{2}=(\sqrt{(x-0)²+(y-4)²})²[/tex]

x²+6x+9+y²-4y+4=x²+y²-8y+16

x²+6x+y²-4y-x²-y²+8y=16-4-9

6x-4y+8y=3

6x-4y=3 is a required locus

Actually:

A locus is a curve or other figure formed by all the points satisfying a particular equation of the relation between coordinates, or by a point, line, or surface moving according to mathematically defined conditions.

Answer:

Relation

Explanation:

The definition of a relation is just a set of ordered pairs.

A function is a relation in which each domain element is paired with exactly one range element.  

It can't be a function because if it is a vertical line, then the x-value is the same for the whole line.

I hope that helps a bit

12.

[tex]we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{26 + 22 + 32 + 28 + 35 + x}{6} = 30 \\ = > \frac{143 + x}{6} = 30 \\ = > 143 + x = 30 \times 6 \\ = > 143 + x = 180 \\ = > x = 180 - 143 \\ = > x = 37 \\ [/tex]

This is the answer.

Hope it helps!!

Answer:

For the first equation we have:

A*x = b

solving for x, we get:

x = b/A

If it always has a solution, then we can not have A = 0, because that causes an undefined operation.

so for example, if we have A = 1 and b = 2

x = b/A = 2/1

For the other case,

A*y = 0

dividing both sides by A

y = 0/A = 0

y = 0

Here we have only one possible solution, the trivial one, y = 0.

And the dependence on A disappears (because the quotient between zero and a number different than zero is always zero)

Answer:

5 3/5

Step-by-step explanation:

3 1/2 * 1 3/5

Change to  improper fractions

(2*3+1)/2  * (5*1+3)/5

7/2 * 8/5

56/10

Change back to a mixed number

50/10 +6/10

5 +3/5

5 3/5

Answer:

AL= 6.63

Step-by-step explanation:

C = 2[tex]\pi r[/tex]

C = 2[tex]\pi 10[/tex]

C = 20[tex]\pi[/tex]

[tex]AL = \frac{38}{360} 20\pi[/tex]

AL= 6.63

The length of the arc travelled by the car is 6.63 feet.

The distance along the part of circumference of any circle or any curve (arc) is called arc length of a circle.

Arc length = θ×[tex]\frac{\pi }{180}[/tex]× r

where,

θ is central angle of arc

r is the radius of circle

The diameter of a circle is any straight line segment that passes through the center of the circle and whose end points lie on the circumference of the circle.

diameter = 2× radius

According to the given question

we have

θ = 38 degrees

diameter = 20ft

⇒ radius = [tex]\frac{20}{2}[/tex]

⇒ radius = 10

Therefore,

the arc length the car traveled = 38×[tex]\frac{\pi }{180}[/tex]× 10

= 38×[tex]\frac{3.14}{180}[/tex]×10

=[tex]\frac{1193.2}{180}[/tex]

=6.63 feet

Hence, the arc length the car travelled is 6.63feet.

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Answer:

9th is 44 mark me as brainlist

Answer:

Question 9 is perimeter

Answer:

Step-by-step explanation:

z = (k*x*y) / w²

Where,

k = constant of proportionality

z = 72 when x = 80, y = 30 and w = 5

z = (k*x*y) / w²

72 = (k * 80 * 30) / 5²

72 = 2400k / 25

Cross product

72 * 25 = 2400k

1800 = 2,400k

k = 2,400/1800

k = 24/18

= 4/3

k = 1 1/3

k = 1.33

find z when x = 20, y = 60 and w=9

z = (k*x*y) / w²

z = (1.33 * 20 * 60) / 9²

z = (1596) / 81

Cross product

81z = 1596

z = 1596/81

z = 19.703703703703

Approximately,

z = 19.7

Answer:

[tex]j = - 0.45[/tex]

Step-by-step explanation:

Combine like terms and apply the rules of algebra.

[tex]2.25 - 11j - 7.75 + 1.5j = 0.5j - 1[/tex]

[tex] - 5.5 - 9.5j = 0.5j - 1[/tex]

[tex] - 9.5j = 0.5j + 4.5[/tex]

[tex] - 10 j= 4.5[/tex]

[tex]j = - 0.45[/tex]

Answer: j = -0.45

Step-by-step explanation:

Step 1: Combine like terms

2.25 - 11j - 7.75 + 1.5j = 0.5j - 1

-5.5 - 9.5j = 0.5j - 1

Step 2: isolate your variable

-5.5 - 9.5j = 0.5j - 1

Subtract 0.5j from both sides

-5.5 - 10j = -1

Add 5.5 to both sides

-10j = 4.5

Divide both sides by -10

j = -0.45

Answer:

Step-by-step explanation:

[tex]Quotient \ of \ 10 \ and \ x = 10 \div x[/tex]

Step-by-step explanation:

12/3.75 = 3.2 a gallon

Answer:

Step-by-step explanation:

a)   profits = 30,000 + (30,000 * .05 * years)

P(y) = 30,000 + 1500y

b)  P(15) =  30,000 + 1500*(15)

P(15) = 52,500

Hello,

First, you must understand that

(f-g)(x) means f(x)-g(x) it is the difference of two functions :

f(x)=2x+4 and g(x)=3x-7

f(5)=2*5+4=10+4=14

g(5)=3*5-7=15-7=8

So, (f-g)(5)= f(5)-g(5)=14-8=6

Answer A: none of the choices are correct.

An other way to do it:

(f-g)(x)=f(x)-g(x)=2x+4-(3x-7)= 2x-3x+4+7=-x+11

if x= 5 then (f-g)(5)=-5+11=6

Answer:

102471 sq .in the land answer Teri ma ki bosra

Answer:

=256 pi

Step-by-step explanation:

The surface area of a sphere is

SA = 4pi r^2

SA = 4 pi (8)^2

     = 4 * pi *64

     =256 pi

Answer:

The quantity of natural numbers between [tex]a^{2}[/tex] and [tex]c^{2}[/tex] is [tex]2\cdot (a + b) + 1[/tex].

Step-by-step explanation:

If [tex]a^{2}[/tex], [tex]b^{2}[/tex] and [tex]c^{2}[/tex] are consecutive perfect squares, then both [tex]a[/tex], [tex]b[/tex] and [tex]c[/tex] are natural numbers and we have the following quantities of natural numbers:

Between [tex]b^{2}[/tex] and [tex]c^{2}[/tex]:

[tex]c^{2} = (b+1)^{2}[/tex]

[tex]c^{2} = b^{2}+2\cdot b + 1[/tex]

[tex]c^{2}-b^{2} = 2\cdot b + 1[/tex]

And the quantity of natural numbers between [tex]b^{2}[/tex] and [tex]c^{2}[/tex] is:

[tex]c^{2}-b^{2}-1 = 2\cdot b[/tex]

Between [tex]a^{2}[/tex] and [tex]b^{2}[/tex]:

[tex]b^{2} = (a + 1)^{2}[/tex]

[tex]b^{2} = a^{2} +2\cdot a + 1[/tex]

[tex]b^{2}-a^{2} = 2\cdot a + 1[/tex]

And the quantity of natural numbers between [tex]a^{2}[/tex] and [tex]b^{2}[/tex] is:

[tex]b^{2}-a^{2}-1 = 2\cdot a[/tex]

And the quantity of natural numbers between [tex]a^{2}[/tex] and [tex]c^{2}[/tex] is:

[tex]Diff = 2\cdot a + 2\cdot b + 1[/tex]

Please observe that the component +1 represents the natural number [tex]b^{2}[/tex]

Answer:

x ≈ 52.1°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{KL}{LM}[/tex] = [tex]\frac{36}{28}[/tex] , then

x = [tex]tan^{-1}[/tex] ([tex]\frac{36}{28}[/tex] ) ≈ 52.1° () to the nearest tenth )

Answer:

[tex]{ \bf{f(x) = {x}^{3} + {ax}^{2} - 1 }} \\ { \tt{f( - 1) : {( - 1)}^{3} + a {( - 1)}^{2} - 1 = 0}} \\ { \tt{f( - 1) : a - 2 = 0}} \\ a = 2[/tex]

The polynomial function [tex]$x^3 + ax^2 -1[/tex] will have -1 as a root at the value of

a = 2.

A polynomial function exists as a function that applies only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

Given: A root exists at a value of x such that the polynomial exists equivalent to zero.

Let, the polynomial equation be [tex]$x^3 + ax^2 -1[/tex]

then [tex]$\mathbf{f}(\mathbf{x})=\mathbf{x}^{3}+a \mathbf{x}^{2}-\mathbf{1}$[/tex]

Put, x = -1, then we get

[tex]$\mathbf{f}(-1)=(-1)^{3}+\mathrm{a}(-1)^{2}-1=0$[/tex]

f(-1) = a - 2 = 0

a = 2

Therefore, the value of a = 2.

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[tex] {\bold{\red{\huge{\mathbb{QUESTION}}}}} [/tex]

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

[tex]\bold{ \red{\star{\blue{GIVEN }}}}[/tex]

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

[tex]\bold{\blue{\star{\red{TO \: \: FIND}}}}[/tex]

Average cost of 7 articles

[tex] \bold{ \green{ \star{ \orange{FORMULA \: USED}}}}[/tex]

[tex] \red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}[/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

[tex]Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k[/tex]

Answer:

this as a equation looks like this

-1/2x+1+x=11

1/2x=10

x=20

Hope This Helps!!!

20 dollars were originally in the box

Two or more expressions with an Equal sign is called as Equation.

Given,

In an office there was a small cash box.

One day ann took half of the money plus$1 more

Then dan took half of the remaining money plus$1 more

Stan then took the remaining $11

-1/2x+1+x=11

Subtract 1/2x from both sides

1/2x=10

Multiply 2 on both sides

x=20

Hence, 20 dollars were originally in the box

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Answer:

Answer:

[tex]\left(sin\theta -cos\:a\right)\left(cos\:a+sin\theta \right)[/tex]

(sin(θ)-cos(a))(cos(a)+sin(0))

[tex]\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}\left(a-b\right)\left(a+b\right)=a^2-b^2[/tex]

a=sin(θ),b=cos(a)

= sin²(θ)-cos²(a)

-------------------------------

hope it helps...

have a great day!!

Answer:

y - 2 = 36(x - 4)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 36 and (a, b ) = (4, 2 ) , then

y - 2 = 36(x - 4) ← equation of line

[tex]\displaystyle\bf h(x)=-4x-7\Longrightarrow h(3)=-4\cdot3-7=-19\\\\Answer:\boxed{ h(3)=-19}[/tex]

Answer:

-19

Step-by-step explanation:

heyya, so if x = 3 you just replace the x in the calculation to 3:

-4 *3 -7

= -12 -7

= -19

Answer:

48 days

Step-by-step explanation:

Swim = every 6 days

Run = every 4 days

Cycles = every 16 days

Find the lowest common multiple of 6, 4 and 16

6 = 6, 12, 18, 24, 30, 36, 42, and 48

4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

16 = 16, 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

The LCM of 6, 4 and 16 is 48

Therefore,

If she did all 3 activities today, she will do all 3 activities again in the next 48 days

Answer:

[tex]2y^2-7y+6=0[/tex]

Step-by-step explanation:

We are given that [tex]\alpha[/tex] and [tex]\beta[/tex] are the zeroes of the polynomial [tex]6y^2-7y+2[/tex]

[tex]y^2-\frac{7}{6}y+\frac{1}{3}[/tex]

We have to find a quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex].

General quadratic equation

[tex]x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes[/tex]

We get

[tex]\alpha+\beta=\frac{7}{6}[/tex]

[tex]\alpha \beta=\frac{1}{3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3[/tex]

Substitute the values

[tex]y^2-(7/2)y+3=0[/tex]

[tex]2y^2-7y+6=0[/tex]

Hence, the quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex] is given by

[tex]2y^2-7y+6=0[/tex]