Which two statements about these figures are true?
Figures 1 and 3 are not congruent because figure 1 cannot be mapped onto figure 3 using a
sequence of rigid transformations.
All four figures are congruent because each figure can be mapped onto any other figure using a
sequence of rigid transformations.
Figures 1 and 4 are not congruent because figure 1 cannot be mapped onto figure 4 using a
sequence of rigid transformations.
Figures 2 and 4 are congruent because figure 2 can be mapped onto figure 4 using a sequence of
rigid transformations.
Figures 1 and 2 are not congruent because figure 1 cannot be mapped onto figure 2 using a
sequence of rigid transformations.

The real yeild is 0.65%.

The Estimated 10-year Treasury bond yield is 3.65%.

The 10-year Treasury bond yield can be estimated using the 5-year Treasury bond yield and the expected inflation rate of 3%.

This is done by calculating the real yield, which is the difference between the nominal yield and the expected inflation rate.

The 10-year Treasury bond yield can be estimated by adding the real yield of the 5-year Treasury bond to the expected inflation rate of 3%.

Real yield = Nominal yield - Expected inflation rate

Real yield (5-year Treasury bond) = 3.65% - 3% = 0.65%

Estimated 10-year Treasury bond yield = 0.65% + 3% = 3.65%

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The result is the 95% confidence interval for µ.

The Metropolis-Hasting (M-H) algorithm is a Markov Chain Monte Carlo (MCMC) method used to sample from a probability distribution. In this case, we want to sample from the posterior distribution of µ, given the recorded data and the prior distribution. The M-H algorithm works by proposing a new value for µ, calculating the acceptance probability, and then deciding whether to accept or reject the proposed value. Here are the steps to construct the M-H algorithm:

Start with an initial value for µ, denoted as µ0.
Propose a new value for µ, denoted as µp, from the proposal distribution q(µ| µo) : N(θ: mean = µp, std = 2).
Calculate the acceptance probability, denoted as α, using the likelihood function L(µ) and the prior distribution p(µ):
α = min{1, [L(µp)/L(µ0)]*[p(µp)/p(µ0)]*[q(µ0| µp)/q(µp| µ0)]}
Generate a random number u from the uniform distribution U(0,1).
If u ≤ α, accept the proposed value and set µ0 = µp. Otherwise, reject the proposed value and keep µ0 unchanged.
Repeat steps 2 to 5 for a specified number of MCMC draws (15000 in this case), and discard the first 1500 draws as the burn-in phase.
Calculate the 95% confidence interval for µ using the remaining 13500 draws.

The 95% confidence interval for µ can be calculated by finding the 2.5th and 97.5th percentiles of the posterior distribution of µ. This can be done by sorting the 13500 draws of µ in ascending order and finding the values that correspond to these percentiles. The result is the 95% confidence interval for µ.

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The real zeros of the given polynomial P(x) = x³ - 9x² + 20x - 12 are 3 and 2. The real zeros of the given polynomial P(x) = x³ - 9x² + 20x - 12 can be found by factoring the polynomial and setting each factor equal to zero.

Step 1: Factor the polynomial
P(x) = x³ - 9x² + 20x - 12
= (x - 3)(x - 2)(x - 2)

Step 2: Set each factor equal to zero and solve for x
x - 3 = 0 => x = 3
x - 2 = 0 => x = 2
x - 2 = 0 => x = 2

Step 3: The real zeros of the polynomial are the values of x that make each factor equal to zero.
So, the real zeros of the polynomial are x = 3 and x = 2.

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This |x - 32| <= 2 means that the tire pressure can be anywhere between 30 psi and 34 psi.

In order for Ms. Sartain's car to have optimal gas mileage, the tire pressure should remain within 2 psi of 32 psi at all times. This can be modeled with an absolute value inequality.

The absolute value inequality that models this situation is |x - 32| <= 2. This inequality states that the difference between the tire pressure, x, and the optimal pressure, 32, should be less than or equal to 2.

In other words, the tire pressure can be 2 psi above or below the optimal pressure of 32 psi and still be within the acceptable range. This means that the tire pressure can be anywhere between 30 psi and 34 psi.

So the correct answer is |x - 32| <= 2.

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The exponential function is y = 5*(∛2)^x and the value after 10 days is 50.4

Here we can see an exponential function of the form y = a*b^x

First, notice that it passes through (0, 5), then:

5 = a*b^0 = a

5 = a

So we got the initial value, so we can write the equaton like:

y = 5*b^x

And now we need to find the value of b.

We also can see that it passes through (3, 10), then:

10 = 5*b^3

10/5 = b^3

2 = b^3

∛2 = b

So the function is:

y = 5*(∛2)^x

b) The value after 10 days is what wet when we evaluate the function above in x = 10, then we will get:

y = 5*(∛2)^10  = 50.4

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The solutions to the given trigonometric equation on the interval [0,2π) are θ = 2π/3 and θ = 4π/3. These values can also be expressed in decimal form as θ = 2.09 and θ = 4.19, rounded to two decimal places

To solve the given trigonometric equation on the interval [0,2π), we need to use the quadratic formula.

First, let us rewrite the equation in terms of x:
2x^2 + 5x + 2 = 0

Next, we can apply the quadratic formula:
x = (-b ± √(b^2 - 4ac))/(2a)

Plugging in the values from the equation:
x = (-(5) ± √((5)^2 - 4(2)(2)))/(2(2))

Simplifying:
x = (-5 ± √(25 - 16))/4
x = (-5 ± √9)/4
x = (-5 ± 3)/4

This gives us two possible values for x:
x = (-5 + 3)/4 = -2/4 = -0.5
x = (-5 - 3)/4 = -8/4 = -2

Now we need to convert these values back to θ by using the inverse cosine function:
θ = cos^-1(-0.5)
θ = cos^-1(-2)

The first value, θ = cos^-1(-0.5), gives us two solutions on the interval [0,2π):
θ = 2π/3 and θ = 4π/3

The second value, θ = cos^-1(-2), does not give us any solutions on the interval [0,2π) because the cosine function only takes on values between -1 and 1.

Therefore, the solutions to the given trigonometric equation on the interval [0,2π) are θ = 2π/3 and θ = 4π/3. These values can also be expressed in decimal form as θ = 2.09 and θ = 4.19, rounded to two decimal places.

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Note that the correct theorem or definition that justifies the given statement for the diagram is the definition of Right angle postulate.

The postulate indicates that if two lines intersect and make the two adjacent angles equal to each other, then each of the equal angle is a right angle. Also, the two lines that intersect this way is said to be perpendicular to each other.

Since the ∠MRS ≅ ∠MRO, we can state that the correct theorem or definition that justifies the given statement for the diagram is the definition of Right angle postulate.

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Answer:

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The value of p(3) is p(3)=12.

Here, we have,

Synthetic division :

It is a shorthand method of dividing polynomials for the special case of dividing by a linear factor whose leading coefficient is 1.

The given function is,

p(z)=8z⁴-17z³-20z²-4z+15                  

We have to find  p(3)  

Substitute z= 3 in above function.

p(3)=8×3⁴-17×3³-20×3²-4×3+15                

     =12      

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Answer:

24inches ²

Step-by-step explanation:

Scale of length is 20ft : 4inches = 5ft : 1inch

Scale of width will be 5ft: 1inch = 30ft: 6inches

Area of scale =length x width

Area = 4inches x 6inces

Using Poisson distribution, the probability of each scenario is attached below.

(a) The probability of receiving 0 complaints in a 3-day period is given by the Poisson distribution:

P(X=0) = (λ^x * e^(-λ)) / x!

where λ is the expected number of complaints per day, and x is the number of complaints in the time period of interest.

In this case, λ = 1.1 complaints per day, and x = 0 complaints in 3 days.

P(X=0) = (1.1^0 * e^(-1.1 * 3)) / 0! = 0.037

So the probability of receiving 0 complaints in a 3-day period is 3.7%.

(b) The probability of receiving 1 complaint in a 3-day period is:

P(X=1) = (1.1^1 * e^(-1.1 * 3)) / 1! = 0.041

So the probability of receiving 1 complaint in a 3-day period is 4.1%.

(c) The probability of receiving 2 complaints in a 3-day period is:

P(X=2) = (1.1^2 * e^(-1.1 * 3)) / 2! = 0.022

So the probability of receiving 2 complaints in a 3-day period is 2.2%.

(d) The probability of receiving 3 complaints in a 3-day period is:

P(X=3) = (1.1^3 * e^(-1.1 * 3)) / 3! = 0.008

So the probability of receiving 3 complaints in a 3-day period is 0.8%.

(e) The probability of receiving 4 complaints in a 3-day period is:

P(X=4) = (1.1^4 * e^(-1.1 * 3)) / 4! = 0.0022

So the probability of receiving 4 complaints in a 3-day period is 0.22%.

(f) The probability of receiving less than or equal to 4 complaints in a 3-day period is:

P(X ≤ 4) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) = 0.1102

So the probability of receiving less than or equal to 4 complaints in a 3-day period is 11.02%.

(g) The probability of receiving more than 4 complaints in a 3-day period is:

P(X > 4) = 1 - P(X ≤ 4) = 1 - 0.1102 = 0.8898

So the probability of receiving more than 4 complaints in a 3-day period is 88.98%.

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The dimensions that would produce the maximum enclosed area are 350ft x 350ft, which will cut off 3 equal size rectangle regions in the yard.

To understand why this is the case, let's consider the problem step-by-step. If Alex wants to cut off three equal size rectangle regions in the yard, he will need to divide the lawn into four equal size rectangles. Let's call the dimensions of two of these rectangles "x" and "y".

To maximize the enclosed area, we want to maximize the area of the lawn that is left over after the three rectangles are cut out. This area can be represented by the equation A = (350-x)(350-y). We know that the total length of the piping is 1400 ft, so the perimeter of the enclosed area (the sum of all four sides) is 1400 ft. This means that 2x + 2y + 1400 = 1400, or 2x + 2y = 0.

Solving for y, we get y = -x + 700. Substituting this equation into the area equation, we get A = (350-x)(350-(-x+700)), which simplifies to A = x(350-x). To find the maximum area, we can take the derivative of this equation with respect to x, set it equal to 0, and solve for x. Doing this, we find that x = 175, which means that y = 525 - x = 350. Therefore, the dimensions that would produce the maximum enclosed area are 350ft x 350ft.

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The domain of the correspondence is {-3, -2.5, 0, 4} and the range is {3, 9, -10}. This correspondence is not a function because it is not a one-to-one correspondence; for example, both -3 and 4 are mapped to the same value of 3.

The question is asking for the domain, range, and whether the correspondence is a function for the given set of ordered pairs: {(-3,3), (-2.5), (0,9), (4,-10)}.

The domain of a correspondence is the set of all possible input values. In this case, the domain is the set of x-values from the ordered pairs: {-3, -2.5, 0, 4}.

The range of a correspondence is the set of all possible output values. In this case, the range is the set of y-values from the ordered pairs: {3, -5, 9, -10}.

A correspondence is a function if each input (x-value) is associated with only one output (y-value). To determine if the given correspondence is a function, we need to check if any x-value is repeated with a different y-value.

In this case, there are no repeated x-values, so each x-value is associated with only one y-value. Therefore, the correspondence is a function.

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 The solution to the system of equations is (x, y) = (-5/3, -4/3).

What is system of linear equations?

A system of linear equations is a set of two or more equations with two or more variables that are to be solved simultaneously. Each equation in the system is linear, meaning it can be written in the form of ax + by + cz + ... = d, where a, b, c, and d are constants and x, y, z, and other variables are unknowns.

The goal of solving a system of linear equations is to find the values of the variables that satisfy all of the equations in the system. The solution of a system of linear equations is a set of values for the variables that make all of the equations true.

There are different methods to solve systems of linear equations, such as substitution method, elimination method, and matrix method. These methods involve manipulating the equations in the system to isolate one variable, substitute its value into another equation, and eventually find the values of all the variables.

Systems of linear equations are used in many areas of mathematics, science, engineering, and economics to model real-world situations and solve practical problems.

To solve the system of equations:

x + y = -3 (Equation 1)

y = 2x + 2 (Equation 2)

We can substitute Equation 2 into Equation 1 for y and solve for x:

x + (2x + 2) = -3

3x + 2 = -3

3x = -5

x = -5/3

Now that we know x, we can substitute it into either Equation 1 or Equation 2 to find y. Let's use Equation 2:

y = 2x + 2

y = 2(-5/3) + 2

y = -10/3 + 6/3

y = -4/3

Therefore, the solution to the system of equations is (x, y) = (-5/3, -4/3).

Comparing this solution to the answer choices, we see that option (b) is the correct answer:

(a) 5/3, 4/3

(b) -5/3, -4/3 <--- Correct answer

(c) -3/5, -3/4

(d) 3/4, 3/5

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solve for t to get t = 4

1. To find the derivative of f(x) = (3 – 2x^3)^3 we can apply the power rule, the chain rule, and the product rule. The power rule states that the derivative of f(x) = x^n is f'(x) = nx^n-1. The chain rule states that the derivative of f(x) = g(h(x)) is f'(x) = g'(h(x))*h'(x). The product rule states that the derivative of f(x) = uv is f'(x) = u'v + uv'. In this case, we can rewrite f(x) as f(x) = (h(x))^3 where h(x) = 3 - 2x^3. We then apply the chain rule to get f'(x) = 3(3 - 2x^3)^2(-6x^2). Similarly, we can find the derivative of f(t) = 100(6-t)/t+3. We can rewrite f(t) as f(t) = u(t)v(t) where u(t) = 100 and v(t) = (6-t)/t+3. Applying the product rule, we get f'(t) = 100(-1/(t+3)^2) + (6-t)(-1/(t+3)^2).

2. To find other information about a function, we can use the derivative we just found. For example, if we want to find the maximum or minimum values of a function, we can set the derivative equal to 0 and solve for the x or t values. In the case of f(x), we can set 3(3 - 2x^3)^2(-6x^2) = 0 and solve for x to get x = (sqrt(3/2))^(1/3). Similarly, for f(t) we can set 100(-1/(t+3)^2) + (6-t)(-1/(t+3)^2) = 0 and solve for t to get t = 4. We can also use derivatives to find the equation of a tangent line to a function at any given point. In this case, we would use the derivative we found in order to calculate the slope of the tangent line at any given point and then use point-slope form to find the equation of the line.

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Based on the information provided, it can be concluded that Manuel measured the height.

The height of a triangle ( a shape with three sides, three angles, and three vertices) can be defined as the distance between the vertex and the opposite. The vertex refers to the highest point of the triangle, which is usually at the top. In the case of the triangle presented, the height is five and this was correctly obtained by Manuel when he measured the distance from the vertex to its base.

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Answer:If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations. the intersection points (-3,3) Since the system is infinite it means there is 1 line on the graph-

Step-by-step explanation:

a. 39 work sampling observations. b. By selecting a random time and a random employee to observe. c. The 95% confidence interval for the population standard is approximately 83.56 +/- (2 * 22.83), or 37.9 to 129.2 hours per hundred beak adjustments.

a. To determine the number of work sampling observations necessary to achieve a 95% confidence level with a margin of error of +10%, we need to use the following formula:

n = (Z^2 * p * (1-p)) / E^2

Where:

n = sample size

Z = Z-score for the desired confidence level (1.96 for 95% confidence level)

p = proportion of beak adjustments estimated from preliminary investigation (0.3)

E = margin of error (0.1)

Plugging in the values:

n = (1.96^2 * 0.3 * 0.7) / 0.1^2

n = 38.15

Rounding up, we need at least 39 work sampling observations.

b. The random observations should be made by selecting a random time of day, and then selecting a random employee to observe. This should be repeated until the required number of observations has been made. This method ensures that all employees have an equal chance of being observed and that the observations are not biased towards certain times or individuals.

c. To determine the standard in hours per hundred beak adjustments, we need to use the following formula:

Standard = (Total time worked / Total number of beak adjustments) * 100

For the six employees summarized in the table:

Granny:

Standard = (82 / 164) * 100

Standard = 50 hours per hundred beak adjustments

Tweety:

Standard = (80 / 161) * 100

Standard = 49.69 hours per hundred beak adjustments

Item:

Standard = (200 / 185) * 100

Standard = 108.11 hours per hundred beak adjustments

Total:

Standard = (82 + 80 + 200 + 121 + 161 + 185) / (164 + 161 + 185) * 100

Standard = 83.56 hours per hundred beak adjustments

The calculated error is the difference between the estimated standard and the true population standard. Since we do not have the population data, we cannot calculate the error. However, we can calculate the variability in the sample data using the following formula:

Standard Error = Standard Deviation / √(n)

Where:

Standard Deviation = √((Σ(x - x-bar)^2) / (n - 1))

n = sample size

Using the data provided in the table, we can calculate the standard deviation and standard error as follows:

Standard Deviation = √(((82-73.5)^2 + (80-73.5)^2 + (200-119)^2 + (121-82.5)^2 + (161-119)^2 + (185-82.5)^2) / (6-1))

Standard Deviation = 55.88

Standard Error = 55.88 / √(6)

Standard Error = 22.83

This means that there is a 95% chance that the true population standard falls within + or - 2 standard errors of the estimated sample standard. Therefore, the 95% confidence interval for the population standard is approximately 83.56 + or - (2 * 22.83), or 37.9 to 129.2 hours per hundred beak adjustments.

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The complete question goes thus:

ACME Corp has hired Daffy Duck to conduct a work sampling project to establish standards. 25 employees are part of the operations under scrutiny. The operations include scenery making, coloring, animation, joke writing, duck beak adjustment, and carrot sourcing. A preliminary investigation resulted in the estimate that 30 percent of the time of the group was spent adjusting duck beaks (this is equal to 17,614 beak adjustments). a. How many work sampling observations would be necessary to conduct if a 95 percent confidence that the observed data were within a +10 percent of the population data? b. Describe how the random observations should be made and justify why (Assume that all random observations need to be conducted over a three-week period or 15 working days). c. The Following table illustrates summary data gathered from 6 out of the 25 employees. From this data, determine a standard in hours per hundred beak adjustments. What is the calculated error? Granny 82 164 Tweety 80 Item Total hours worked Total observations (all elements) Observations involving cataloguing Average rating Operators Speedy Taz Glez 78 76 200 121 Foghorn Leghorn 68 Yosemite Sam 81 161 185 144 51 57 29 42 47 55 78 95 120 85 95 99

1. 9 months 2) $163.06, because it is the remaining balance after paying off the principal and interest accrued for that month. 3) $348.16, because it is the balance remaining on the lower interest card after paying off the higher interest card and making the monthly payment for that month. 4) 9 months 5) $168.79, because it is the difference between the total amount paid to each card when paying off the higher interest card first versus paying off the lower interest card first.

Interest is the fee paid for the use of borrowed money, usually expressed as a percentage of the borrowed amount.

Therefore, 1. 9 months 2) $163.06, because it is the remaining balance after paying off the principal and interest accrued for that month. 3) $348.16, because it is the balance remaining on the lower interest card after paying off the higher interest card and making the monthly payment for that month. 4) 9 months 5) $168.79, because it is the difference between the total amount paid to each card when paying off the higher interest card first versus paying off the lower interest card first.

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15 + 2x = Price

The price of a medium-sized pizza at Desminos Pizza's online menu is $15 plus $2 per topping. The equation for this is 15 + 2x = Price, where x represents the number of toppings.

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The equation can be written as: x + 24° = 90°.

The measure of the unknown angle is 66°.

An algebraic equation is an equation that is made up of variables and constants, along with algebraic operations like addition, subtraction, square root, etc.

Let the measure of the unknown angle be x.

Since the angle in the corner measures 90° and one piece of the tile will have a measure of 24°. We can write the equation as:

x + 24° = 90°

The measure of the unknown angle can be determined as follow:

​x + 24° = 90°

x = 90° - 24°

x = 66°

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By answering the above question, we may state that As a result, the equation mass of all krill is about 11,485 times more than the mass of all blue whales.

A mathematical equation is a process that links two statements and indicates equality using the equals sign (=). A formal statement that proves the equality of two calculations is known as an equation in algebra. For instance, the equal sign separates the numbers 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula may be used to understand the link between the two phrases that are inscribed on opposite sides of a letter. Frequently, the logo and indeed the particular software are identical. like in 2x - 4 = 2, for example.

Given that there are several species with a wide range in population numbers, it is challenging to identify which animal is the least numerous. The vaquita porpoise, Javan rhinoceros, and Amur leopards are some of the rarest animals, albeit they all exist in the wild. The number of ants on Earth is believed to be 10 quadrillion, which is around 10,000,000,000,000,000 times greater than the population of any of the rarest species.

The estimated mass of all krill on Earth is around 379 million tonnes, whereas the estimated mass of all blue whales is approximately 33,000 tonnes. As a result, the mass of all krill is about 11,485 times more than the mass of all blue whales.

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Answer:

8290

Step-by-step explanation:

Explanation is on the pic

The roommate is wrong. The scaled desk should be 1 1/3 inches high, as per Olaf's initial scaling of 1 inch representing 30 inches of actual length in the room. The other dimensions of the scaled desk would be 12 inches long and 6 2/3 inches wide.

When Olaf decided to let 1 inch represent 30 inches of actual length in the room, he created a scale factor of 1:30. This means that for every inch in the scale model, there are 30 inches in the actual room. Using this scale factor, the scaled desk height should be 40/30 = 4/3 inches. Therefore, the roommate's suggestion of 10 inches high is incorrect.

To find the other dimensions of the scaled desk, we need to apply the same scale factor of 1:30. The scaled length would be 36/30 = 12 inches, and the scaled width would be 20/30 = 2/3 inches. However, it's easier to work with whole numbers, so we can multiply both dimensions by 10 to get 120 inches long and 6 2/3 inches wide, which is equivalent to 12 inches long and 2/3 inches wide in the scaled model.

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Answer: A) -4.2, B) -3.8 C) -9/2 (-4.5)

Step-by-step explanation: Think of a number line, you have 0-10, and -10-0, as you keep going down the number like, the numbers become less and less, just like how -4.2 is less than -3.5, because it is further to the left of the number line, meaning it is less than. Hope this helps!

To solve the equation, we need to get rid of the fractions by multiplying both sides of the equation by the least common denominator (LCD), which is (b^(2)-9). This will give us:
(8)(b^(2)-9)/(b^(2)-9)-(1)(b^(2)-9)/(b+3)=(1)(b^(2)-9)/(b^(2)-9)
Simplifying the equation gives us:
8-(b^(2)-9)/(b+3)=1
Next, we will isolate the variable term by subtracting 8 from both sides of the equation:
-(b^(2)-9)/(b+3)=-7
Now, we will multiply both sides of the equation by (b+3) to get rid of the fraction:
-(b^(2)-9)=-7(b+3)
Expanding the equation gives us:
-b^(2)+9=-7b-21
Rearranging the equation gives us:
b^(2)-7b-30=0
Factoring the equation gives us:
(b-10)(b+3)=0
Setting each factor equal to zero gives us the possible solutions:
b-10=0 or b+3=0
Solving for b gives us the possible solutions:
b=10 or b=-3
However, we need to check for extraneous solutions by plugging the possible solutions back into the original equation. Plugging in b=10 gives us a true statement, but plugging in b=-3 gives us an undefined expression. Therefore, the only solution is b=10.
Answer: b=10

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U is a subspace of R3.  A basis for U is  {(1, -2, 3)}  and dim(U) = 1.

a) To show that U is a subspace of R3, we must verify the three conditions:

1. U is non-empty, since the vector (0,0,0) ∈ U, since 0 + 2(0) - 3(0) = 0.
2. U is closed under addition, since for any two vectors (x1, y1, z1) and (x2, y2, z2) ∈ U, their sum (x1+x2, y1+y2, z1+z2) also satisfies the equation x1+x2 + 2(y1+y2) - 3(z1+z2) = 0, so it is also in U.
3. U is closed under scalar multiplication, since for any scalar c and any vector (x, y, z) ∈ U, the vector c(x,y,z) = (cx, cy, cz) also satisfies the equation cx + 2cy - 3cz = 0, so it is also in U.

Therefore, U is a subspace of R3.

b) To find a basis for U, we must find a linearly independent set of vectors which span U. One such set is the vector (1, -2, 3), since it satisfies the equation x + 2y - 3z = 0. Therefore, {(1, -2, 3)} is a basis for U.

c) The dimension of U is the number of vectors in its basis, which is 1. Therefore, dim(U) = 1.

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The 12th term of the geometric sequence 9, - 18, 36, is 18,432.

In Mathematics, the nth term of a geometric sequence can be calculated by using this mathematical expression:

aₙ = a₁rⁿ⁻¹

Where:

Next, we would determine the common ratio as follows;

Common ratio, r = a₂/a₁

Common ratio, r = -18/9

Common ratio, r = -2

For the 12th term, we have:

a₁₂ = 9(2)¹²⁻¹

a₁₂ = 18,432.

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Answer:

38

Step-by-step explanation:

Interquartile Range

IQR = Q3 - Q1

Quartiles are the values that divide a list of numbers into quarters:

301, 301, 304, 309, 311, 328, 330, 341, 342, 343, 345

Hence,

Quartiles:

Q1 --> 304

Q2 --> 328

Q3 --> 342

And since, IQR = Q3 - Q1

Then,

342 - 304 = 38

As a result, the interquartile range for the data set is 38.

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The proof that ∠B ≅ ∠C is:

D is the midpoint of of BC - Given...................(1)
Thus
BD = DC ................................................................(2)

∠EDC ≅ ∠FDB  - Given......................................(3)

DE ⊥ AB - Given...................................................(4)
DF ⊥ AC - Given ..................................................(5)
∠AED = ∠DEB = 90° - perpendicular bisector theorem  ....(6)

∠AFD = ∠DFC = 90° - perpendicular bisector theorem ....(7)
∠EAF = ∠EDF = 90° - Properties of the angles of a Quadrilateral

Since ∠EDC ≅ ∠FDB, as in   (3) above, and

Both comprise of ∠EDF,

thus,
(∠EDC - ∠EDF) ≅ (∠FDB - ∠EDF)

Since

∠EDB = (∠FDB - ∠EDF); and

∠FDC = (∠EDC - ∠EDF)

Thus,

∠EDB ≅ ∠FDC

thus,
∠EDB = ∠FDC = 45° (Sum of Angles on a Straight line) that is
∠EDB =  ∠FDC = (180° -∠EDF)/2

Since  ∠EDF = 90°
∠EDB =  ∠FDC = (180° -90°)/2

∠EDB =  ∠FDC = 90/2
∠EDB =  ∠FDC = 45°

Since
∠DEB = 90° (5); and

∠DFC = 90° (7)
ΔBED ≅ ΔDFC

Thus, by Sum of Angles in a Triangle,
∠B ≅ ∠C.

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