When the molecules shown are vaporized, the speed of molecule A will be greatest because of its relatively small size.
What affects the speed of a molecule?When a molecule is vaporized, its size can affect its speed in a couple of ways. The speed of a molecule is related to its kinetic energy, which is influenced by factors such as temperature and mass.
When comparing two molecules that have been vaporized at the same temperature, the smaller molecule will tend to have a higher speed than the larger molecule.
Learn more about the speed of a molecule at: https://brainly.com/question/29605566
#SPJ1
59.6 ml of air is at 20.5 °C. What is its volume at 73.9 °C?
The volume of air at 73.9 °C would be approximately 70.91 ml.
To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure and amount of gas are kept constant.
Let's assume that the pressure and amount of air remain constant.
Given:
Initial volume (V1) = 59.6 ml
Initial temperature (T1) = 20.5 °C = 20.5 + 273.15 K = 293.65 K
Final temperature (T2) = 73.9 °C = 73.9 + 273.15 K = 347.05 K
Using Charles's Law, we can set up the following proportion:
V1 / T1 = V2 / T2
Plugging in the values, we have:
59.6 ml / 293.65 K = V2 / 347.05 K
To solve for V2 (the final volume), we can rearrange the equation:
V2 = (59.6 ml * 347.05 K) / 293.65 K
V2 = 70.91 ml
Therefore, the volume of air at 73.9 °C would be approximately 70.91 ml.
for more questions on volume
https://brainly.com/question/29796637
#SPJ8
-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:
6.02 x [tex]10^{20[/tex] formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.
Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.
Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:
(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))
The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:
(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol
Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.
Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.
For more such questions on MgCl₂ visit:
https://brainly.com/question/26311875
#SPJ8