While investigating the relationship between voltage, current, and resistance, students connected different batteries to different circuits
and recorded measurements of battery voltage and current flowing through the battery. They then produced the model shown below.


Based on the data provided in the graphical model, what claim can be made about the resistance of the circuit?

A._The resistance of the circuits increased as battery voltage increased.

B._ The resistance of the circuits decreased as a battery voltage increased.

C._ The resistance of the circuits remained constant as the battery voltage increased.

D._ The resistance of the circuits could have either increased or decreased as the battery voltage increased.

any procedure where velocity fluctuates

Any procedure where the velocity varies is referred to as acceleration. There are only two methods to accelerate because velocity is both a speed and a direction: changing your speed or changing your direction.

An object has positive acceleration if it is accelerating and travelling in the right direction. Positive acceleration was demonstrated in the first example by the speeding car. The acceleration is in the same direction as the car's motion because it is moving forward and speeding up.

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At any any procedure where velocity fluctuates.

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Answer:

V = √ ( 6.65² + 9.87² ) ≈ √ 141.64 = 11.90 mph

The answer of this is "Its surface composition"

Mars is the fourth planet from the Sun and the next planet beyond Earth. It is, on average, more than 142 million miles from the Sun.

Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth. Sometimes the wind blows the red dust into a dust storm. Tiny dust storms can look like tornados, and large ones can be seen from Earth. Mars’ large storms sometimes cover the entire planet.

Mars has about one-third the gravity of Earth. A rock dropped on Mars would fall more slowly than a rock falls on Earth. A person who weighs 100 pounds on Earth would only weigh about 38 pounds on Mars because of the reduced gravity.

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3.813m far will child b have moved when he collide with child a.

We know that,

[tex]x_{cm}[/tex]=[tex]\frac{m_{a} x_{a} +m_{b} x_{b} }{m_{a}+x_{b} }[/tex]

[tex]x_{cm}[/tex]=26(0)+49(11)/26+49=7.187

A=From a is 7.187m

B=we forces know that, the internal can't change the motion of CM. SO they will meet Collide at their C.M.

B has to move the distance from B→C.M. So they will meet Collide at their C.M B will forces.

11-7.187 = 3.863

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The motor is an excellent invention for Allison to use as a model for her device.

People use both interchangeably, but the difference is that motors run on electricity and engines run on combustion. The engine converts various forms of fuels into mechanical force, while the motor transforms electrical energy into mechanical energy.

They operate using principles of electromagnetism, which shows that a force is applied when an electric current is present in a magnetic field. This force creates a torque on a loop of wire present in the magnetic field, which causes the motor to spin and perform useful work.

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If a 2.5 kg mass is attached to a spring with k = 53 N/m, the spring will stretch to 61 cm.

Missing data from the problem:

A spring with spring constant (k) 53 N/m is hang vertically.

Original length of the spring = 15 cm = 0.15 m

A mass of 2.5 kg is attached to the end of the spring.

According to the Hooke's Law:

F = - kx

Where:

F = force applied on the spring

x = spring displacement

From the problem, the only force is the weight of the mass:

F = w = m . g  (g = 9.8 m/s²)

F = 2.5 . 9.8 = 24.5 N

Substitute k = 53 N/m,

24.5 = 53 . x

x = 24.5/53 = 0.46 m = 46 cm

Therefore the final length of the spring = 15 + 46 = 61 cm

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The value of the final angular velocity = 0.44 rev/s

Let Initial angular momentum = [tex]L_{i}[/tex]

Let Final angular momentum = [tex]L_{f}[/tex]

Here, mass of merry go round = [tex]m_{m}[/tex] = 120 kg

radius= r = 1.8 m

initial angular velocity = [tex]w_{i} = 1.2 \pi[/tex]rad/s

mass of the child = [tex]m_{c}[/tex] = 21kg

By law of conservation of angular momentum,

[tex]L_{i}=L_{f}\\\\I_{m}w_{i}=I_{m+c} w_{f}\\\\w _{f} =\frac{I_{m}w_{i}}{I_{m+c}}[/tex]

Here, substitute  [tex]I = \frac{mr^{2} }{2}[/tex]

[tex]w _{f} =\frac{I_{m}w_{i}}{I_{m+c}}\\\\w _{f} =\frac{\frac{m_{m}{r _{m}}^{2}}{2} w_{i}}{\frac{m_{m}{r _{m}}^{2}}{2}+{m_{c}r_{c}}^{2} }\\\\w _{f}= \frac{\frac{120(1.8)^{2} }{2} *1.2\pi}{\frac{120(1.8)^{2} }{2} +21(1.8)^{2}}\\\\w _{f} = 2.8 rad/s[/tex]

The value of the final angular velocity = 2.8 rad/s

                                                                =2.8/2 π

                                                                = 0.44rev/s

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The maximum velocity of the tennis ball when it cross the net in order to still land in the court is 26.7 m/s

The trajectory of the tennis ball follow a projectile motion. When it cross the net, it can be considered it is at its maximum height.

At this position, the component of the velocity is only in x direction.

Vertical direction:

h = 1/2 . g t²

Where:

h = maximum height

g = acceleration due to gravity = 9.8 m/s²

t = time to land

Substitute h = 1 m

t² = 2/g = 0.204

t = 0.45 seconds

Horizontal direction:

x = v . t

12 = v . 0.45

v = 12 / 0.45 = 26.7 m/s

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Answer: The mechanical advantage of the crowbar  9

Answer:

9

Explanation:

50N-load

450N-effort

m.a=load÷effort

450÷50=9

The distance of the travel covered within 5 hours with a speed of 120km/hr is the product of time and this speed and it is 600 km.

Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.

Velocity = distance/time.

Hence, as the time taken for the travel increases velocity will decreases. The time given here is 5 hours and the speed of the vehicle is 120 km/hr. Hence, the distance can be calculated as follows:

Distance = time  × speed

               = 5 hr × 120 km/hr

               =  600 km.

Hence, if you drive at a speed of 120 km/hr for 5 hours you will cover a distance of 600 km.

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(a) The ball will not pass over the wall

(b) The velocity is  21.45m/s

It is the amount of change in velocity per unit time. The velocity change can be calculated using the formula: velocity change = final velocity - initial velocity. This is the time when: The rate of change in velocity is expressed in

Given

A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall.

We have to determine

a) Will the ball pass over the wall?

b) If not, where will it hit the wall and with what velocity?

From the given information

Initial velocity v =20m/s

Initial velocity along x direction vx = vcos300

= 20 cos300

= 20 x 0.866

= 17.32m/s

Initial velocity along y direction vy = v sin300

= 20 sin300

= 20 x 0.5

= 10m/s

Displacement along +ve x = 40m

Time required to travel t = x/vx

= 40/17.32

= 2.31seconds

At this time displacement of the ball along the y direction

Sy = vyt – 1/2gdt2

= 10x2.31 – ½ x 9.81 x (2.31)2

= 23.10 – 26.17

= - 3.07m

Since displacement is in a negative value, it will hit the wall and will not pass over the wall

The ball will hit at d distance from the ground

H = (10 – 3.07)

= 6.93m

Final velocity along +ve y = v’y = vy –gt

= 10 – 9.81 x 2.31

= 10 – 22.66

=-12.66m/s

velocity along +ve x = v’y = vx

= 17.32m/s

So-net velocity of the ball v’= √((v^' x)^2+(v^' y)^2 )

= √(〖(17.32)〗^2+〖(-12.66)〗^2 )

= 21.45m/s

Therefore

(a) The ball will not pass over the wall

(b) The velocity is  21.45m/s

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The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J

Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.

Elastic potential energy = Kinetic energy

Kinetic energy = 110 J

Elastic potential energy = 1 / 2 k x²

Kinetic energy = 1 / 2 m v²

k = Spring constant

x = Displacement

m = Mass

v = Velocity

If friction is ignored,

1 / 2 k x² = 1 / 2 m v²

v / x = √ ( k / m )

Therefore, the maximum elastic potential energy store of the ball is 110 J

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Answer:

c is answer

Explanation:

Humans allow only organisms with favorable traits to reproduce. Is this true of natural selection, artificial selection or both? Competition for resources determines reproductive success.

The final velocity of the orange will be equal to 21.27 m/s.

The equations of motion have established the relationship between the acceleration, velocity, time, and displacement (s) of a moving object.

The equations of motions can be mathematically expressed as:

[tex]v = u +at\\S=ut +\frac{1}{2}at^2\\ v^2-u^2=2aS[/tex]

Given, the velocity of the orange was at rest initially, therefore, u = 0

The time taken by the orange to fall, t = 2.17 s

The acceleration of orange due to gravity, g = 9.8 m/s²

From the first equation of motion, we can find the final velocity after 2.17 s:

v = u +gt

v = 0 + (9.8) × 2.17

v = 21.27 m/s

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The stress that spreads over the soles of the feet by the body is 18000 N/m².

The compressive stress exerted on a body is given by the force applied to the body divided by the area,

So, we can write,

Stress = force/area

In this case, the force will be equal to the weight of the body.

F = Mg

M is the mass of the person,

g is the acceleration due to gravity.

F = 72×10

F = 720N

The area of the soles is given to be 200 cm²

Converting into meter square,

Area = 0.02 m²

As there are two soles,

Area = 0.04

Putting values to find stress,

Stress = 720/0.04

Stress = 18000N/m²

So, the stress on the soles is 18000 N/m².

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Answer:

3

Explanation:

m.a=load÷effort

thus 150N÷50N=3

The magnitude of the resultant with respect to one of the vectors is [tex]10 \sqrt{3} \mathrm{~N}[/tex].

The resultant of two force is given by [tex]$F=\sqrt{A^2+B^2+2 A B \cos \theta}$[/tex] where, [tex]$A \& B$[/tex] are two vectors & [tex]$\theta$[/tex] is the angle between them.

Magnitude or resultant is [tex]$\sqrt{2 \times 10^2+2 \times 100 \cos 60^{\circ}}=10 \sqrt{3} \mathrm{~N}$[/tex].

A force is an influence in physics that can modify the velocity of an object. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. A force is not something that an object 'has in it.' Another object applies a force to another. The concept of a force is not limited to living or nonliving things.

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The relationship between the generator and the energy input is the fact that the generator uses mechanic energy as input to produce electricity.

An electrical generator device is any instrument capable of generating electrical activity using any source of energy as a source for such purpose, such as the movement (motion of mechanical energy) of a turbine.

Therefore, with this data, we can see that an electricity generator device is a given instrument used to generate electricity by exploiting the mechanical energy generated through a particular process.

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An x-ray cassette is kept in a device called a "bucky" that resembles a drawer. It can be installed either on the wall or underneath the exam table.

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The velocity of the 2.0 kg mass just before it hits the rocks when it is dropped from a height of 16 m above the surface of the rocks will be 17.738 m/s in downward direction

given

u = 0

m= mass = 2 kg

height = 16 m

v = ?

using kinematics equation

-s = ut - 1/2* g * [tex]t^{2}[/tex]

t = [tex]\sqrt{2s/g}[/tex]

time = [tex]\sqrt{(2*16) / 9.8}[/tex]

       = [tex]\sqrt{3.27}[/tex]

       = 1.81 seconds

v = u - gt

v = -g t = -9.8 * 1.81 = -17.738 m/s

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The net force on the toy is 0 Newton.

The mass of the toy is 2 kg.

The force F₁ is the tension applied by one of the siblings on the toy is 8N.

Let us assume that the force applied by the other sibling is F₂, which is produced by the acceleration is 4m/s².

We know,

Force = Mass x acceleration

Putting values,

F₂ = 2 x 4

F₂ = 8N.

As we know that the forces are in opposite directions because the toy is being pulled by both the siblings in their respective directions which are opposite to each other.

Hence, the net force F is given by,

F = F₁ - F₂

F = 8-8

F 0N.

Hence, there is no net force on the toy.

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The wave's frequency is 0.35 Hz, and its velocity is 0.9857 m/s. Wave speed is the amount of space a wave covers in a certain length of time, such as how many meters it covers in a second.

Despite the fact that technically, velocity implies both direction and speed wave velocity is most often used to describe speed. Wave intensity has no bearing on a wave's velocity, which is determined by the product of the its wavelength and frequency.

A stationary point is traversed by waves at a specific frequency over a specified period of time. The following equation demonstrates the connections between the three variables: Wavelength × Wave Frequency = Speed. This equation uses the units of meters for wavelength and hertz (Hz) for frequency, or the number many waves per second.

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The third snowman will be placed at a distance of 2.1m from the 15.0 kg mass such that the net gravitational force on it by the other two is zero .

Mass of the snowman 1 = M1 = 15 kg

Mass of the snowman 2 = M2 = 20 kg

Distance between both the masses = r = 4 m

Gravitational force is the force that attracts any two objects of mass.

where G is the gravitational force constant,

M1 and M2 are the masses of the two different bodies respectively,

r is the distance between the masses.

F = [tex]\frac{GM1M2}{r^{2} }[/tex]

Let the mass M3 be the mass which lies between the masses such that the net gravitational force on it by the other two is zero.

F = [tex]\frac{GM1M3}{(r-d)^{2} }[/tex]  = [tex]\frac{GM2M3}{(d)^{2} }[/tex]

here 'd' is the distance at which the mass M3 will be placed such that the net gravitational force on it by the other two is zero.

[tex]\frac{GM1M3}{(r-d)^{2} }[/tex]  = [tex]\frac{GM2M3}{(d)^{2} }[/tex]

[tex]\frac{M1}{(r-d)^{2} }[/tex]  = [tex]\frac{M2}{(d)^{2} }[/tex]

[tex]\frac{15}{(4-d)^{2} }[/tex]  = [tex]\frac{20}{(d)^{2} }[/tex]

3[tex]d^{2}[/tex] = 4[tex](4-d)^{2}[/tex]

3[tex]d^{2}[/tex] = 4 (16 + [tex]d^{2}[/tex] - 2*4*d)

3[tex]d^{2}[/tex] = 64 + 4[tex]d^{2}[/tex] - 32d

[tex]d^{2}[/tex] - 32d + 64 = 0

On solving the above quadratic equation we get the values of d as;

d1 = 29.

d2 = 2.1

Since the d is the distance between the two masses therefore it must be less than 4 m, therefore d2 will be considered as the value of d.

Hence the mass M3 should be placed at a distance of 2.1 m away from the mass M1 to get zero as the net gravitational force

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The secondary coil of the transformer is 21 turns.

We need to know about transformers to solve this problem. The transformer is a device that changes the output voltage by using different turns on its coil. The ratio of output voltage and input voltage should follow this equation

Vo / Vi = Ns / Np

where Vo is output voltage, Vi is input voltage, Ns is secondary turns and Np is primary turns.

From the question above, the given parameters are

Vi = 80 V

Vo = 9.8 V

Np = 170 turns

By using the equation, we can calculate the secondary turns

Vo / Vi = Ns / Np

80 / 9.8 = 170 / Ns

Ns = 170 . 9.8 / 80

Ns = 20.825

Thus we can round the secondary turns to 21.

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The dielectric constant of the wax is 2.

The dielectric constant of wax is the ratio of the capacitance of a capacitor that has wax between its plates to its capacitance when there is no wax between its plates.

This can be calculated by first finding the total capacitance of the capacitor with wax in between it:

C = 2 * pf * (0.5cm)^2

= 1.5 pf

Then, we can calculate the change in capacitance:

C' = C - C

= 2 pf * (0.5cm)^2 - 1.5 pf

= 0.5 pf

Finally, we divide 1/0.5 to find C'/C = 2, so we conclude that the dielectric constant for wax is 2, or twice as large as air's dielectric constant of 1!

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The vertical acceleration of the ball at its highest altitude is 0 m/s.

It is possible for an item to have both zero acceleration and non-zero velocity because acceleration is the change in velocity. Since there is no change in velocity while an object is moving at a constant speed, it experiences no acceleration.

The bullet reaches its highest point when its vertical velocity is zero. The vertical portion of the velocity vector will now point downward. The projectile's horizontal range, which is determined by the object's beginning velocity, is referred to as the projectile's range.

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Two nucleotides on the same strand form a Phosphodiester bond while two complimentary bases on opposite strands form Hydrogen bonds. An a-t base pairing forms 2 such bonds.

In DNA double helix, the individual constituents are called nucleotides. These nucleotides are composed of bases which are linked together though covalent linkage also known as a phosphodiester bond.

Two individual strands in DNA are formed by the combination of phosphodiester linkages.

In general, with in a DNA nucleotides, hydrogen bonds are present which join the complementary pairs of bases. For example, two hydrogen bonds are present between thymine and adenine while three hydrogen bonds are present between cytosine and guanine.

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Answer:

B

Explanation: You (with the ball in your hand)would move in the direction of the ball's initial motion. Momentum!

Answer: You would move backward.

Explanation: You would push back because you would move in the direction of the ball's initial motion.  The ball's initial motion is to come toward you, so you would most likely move backward.

Let me know if this is right! :)

The potential energy at the maximum height is 0.000196 J, the total mechanical energy at the maximum height is 0.000196 J, the potential energy at a height of 0 m is 0 J, the total mechanical energy at a height of 0 m is 0.0001936 J, the kinetic energy at a height of 0 m is 0.0001936 J and the velocity at a height of 0 m (before it lands) is 0.44 m/s.

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