Why are some Hydro flow rolling pins HFO refrigerants classified as a a2l

Answers

Answer 1

Hydro flow rolling pins HFO refrigerants classified as a A2L because they contain a fluorine.

Some Hydro Fluoro Olefin (HFO) refrigerants are classified as A2L according to the ASHRAE (American Society of Heating, Refrigerating, and Air-Conditioning Engineers) classification system for refrigerants. The "A" in A2L stands for "lower toxicity," and the "2" indicates "lower flammability."

The classification of refrigerants is based on their potential toxicity and flammability. A2L refrigerants are considered to have lower toxicity and lower flammability compared to other types of refrigerants. They have specific thermodynamic properties that make them suitable for use in refrigeration and air conditioning systems.

Fluorine makes HFO refrigerants less flammable than  hydrochlorofluorocarbons (HCFCs) and hydrofluorocarbons (HFCs). which are highly flammable.  A2L refrigerants have lower global warming potential (GWP) and ozone depletion potential (ODP), which makes them a more sustainable choice for certain applications.

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Answer 2
Final answer:

Hydro flow rolling pins HFO refrigerants are a type of refrigerant used in air conditioning systems. The 'a2L' is a safety classification from ASHRAE that indicates these refrigerants are mildly flammable but have lower flammability. Such classifications are used for safety considerations.

Explanation:

The Hydro flow rolling pins HFO refrigerants are designed for use in refrigeration and air conditioning systems. An HFO refrigerant is a hydrofluorolefin refrigerant; they are a new class of refrigerants that have a very low planet-warming potential.

The designation a2L is actually a safety classification set by ASHRAE (American Society of Heating, Refrigerating and Air-Conditioning Engineers) and it means that these refrigerants are mildly flammable but exhibit lower flammability. The '2' indicates that the refrigerant has low flammability and the 'L' means it has a lower burning velocity. These classifications inform technicians and engineers about the safety considerations they need to be aware of when handling and working with these substances.

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Related Questions

You may have noticed that all the elements in the first column of the periodic table, the alkali metals, have a 1 charge when they combine with negative ions. Another group of positive ions are the alkaline earth metals located in the second column of the periodic table. What charge is typical for ions of the alkaline earth metals?

Answers

Answer:

The charge that is typical for ions of the alkaline earth metals is +2

Explanation:

Group 1 elements (alkali metals such as Li, Na, K...) all have one valence electron that they donate when forming ionic bonds. This will cause them to have a charge of +1.T he alkaline earth metals (Ca, Mg) have two valence electrons they donate which means their charge when forming ions is +2. The members of the aluminum family lose three electrons giving them a charge of +3.

What volume in milliliters of a 1.00 M solution of sodium hydroxide is required to
make 125 mL of a 0.0600 M solution?
7.50 mL
12.5 mL
16.7 mL
208 mL

Answers

16.7 mL of a 1.00 M solution of sodium hydroxide is required to make 125 mL of a 0.0600 M solution.

Determine the mass of 2.62 mol of iron(III) sulfate.

Answers

The molar mass of 2.62 mol of iron(III) sulfate is 1050.8 g.

Thus, the molar mass of iron(III) sulfate can be calculated by summing the atomic masses of its constituent atoms. The molar mass of a compound is the sum of the atomic masses of all the atoms present in a chemical formula of the compound which is then multiplied by the number of atoms of each element in the formula.

In iron(III) sulfate, the atomic mass of iron will be 111.70 g/mol. The atomic masses of Sulphur and oxygen will be 96.18 g/mol and 192.0 g/mol, respectively. Adding atomic masses of its constituent atoms will be 400.88 g/mol. Therefore, the molar mass of 2.62 mol of iron(III) sulfate is 1050.8 g.

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Balance the following reaction by typing in the correct coefficients in front of each reactant and product.
H3PO4(s) -
-->
H₂(g) +
P(s) +
O₂(g)

Answers

2 H3PO4(s) —> 3 H2 + 2 P + 4 O2

A reaction vessel contains an equilibrium mixture of SO2, O₂, and SO3. The reaction proceeds such that:

2SO₂(g) + O₂(g) <—>2SO3 (g)

The partial pressures at equilibrium are:
PS0₂ = 0.002318 atm
PO2 = 0.002930 atm
PS03 = 0.0166 atm

Calculate alp for the reaction

Answers

The Kp of the reaction is seen to be  1.75 * 10^4

What is the equilibrium constant?

A high Kp value indicates that the equilibrium is in favor of the products, whereas a low Kp value suggests that the equilibrium is in favor of the reactants.

The relative concentrations of reactants and products at equilibrium are shown  by the equilibrium constant.

We know that;

Kp = pSO3^2/pO2 . pSO2^2

Kp =(0.0166)^2/ 0.002930  (0.002318)^2

Kp = 2.8 * 10^-4/1.6 * 10^-8

Kp = 1.75 * 10^4

The Kp of the reaction is gotten as 1.75 * 10^4.

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The symbol that indicates a substance dissolve in water is

Answers

The symbol that indicates a substance dissolve in water is (aq).

What is the symbol?

The word "(aq)" stands for aqueous and denotes a material that dissolves in water.

Aqueous solutions are created when substances dissolve in water and are uniformly dispersed throughout the liquid. "(aq)" is added to the end of a substance's chemical formula in a chemical equation to denote that the material is in an aqueous state.

We often see this in several chemical reactions and the symbols shows that the solute was dissolved in water.

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Calculate volume of 0.3 mole of hydrogen chloride

Answers

6.72L is the volume occupied by 0.3 mole of hydrogen chloride. A measurement of three-dimensional space is volume.

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic foot and litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.

Volume = 0.3×22.4

            =6.72L

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In the following reaction, what quantity in moles of CH₃OH are required to give off 6106 kJ of heat?
2 CH₃OH (l) + 3 O₂ (g) → 2 CO₂ (g) + 4 H₂O(g) ∆H° = -1280. kJ

Answers

To generate 6106 kJ of heat, 9.5 moles of CH₃OH are required.

The given reaction releases -1280 kJ of heat. We need to find how many moles of CH₃OH are required to release 6106 kJ of heat.

From the given balanced equation, we know that 2 moles of CH₃OH releases 1280 kJ of heat.

Therefore, 1 mole of CH₃OH will release 1280 kJ / 2 = 640 kJ of heat.

To release 6106 kJ of heat, we can use the following proportion:

2 moles CH₃OH / 1280 kJ = x moles CH₃OH / 6106 kJ

Solving for x, we get:

x = (2 moles CH₃OH x 6106 kJ) / 1280 kJ = 9.5 moles CH₃OH

Therefore, 9.5 moles of CH₃OH are required to release 6106 kJ of heat.

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We've figured out what part of the salt causes the flame to change color, so now let's measure the wavelengths created with four metals.

Use the ruler under the "tools" icon in the upper right of the video player to measure the wavelengths of light released by each compound.

Answers

Around 450 nm is the wavelength of the spectral line for potassium chloride. The distance among identical spots between two succeeding waves is known as the wavelength.

The distance among identical spots between two succeeding waves is known as the wavelength, which is a feature of waves. The wavelength of a wave is the distance across one wave's peak (or trough) and the next. In mathematics, the Greek symbol lambda () is used to denote wavelength. The colour of light is determined by its wavelength, and the pitch of sound is determined by its wavelength. Around 450 nm is the wavelength of the spectral line for potassium chloride.

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We would like to find RDS using Tapel slope. Provide Tafel slope when we assume each step is RDS, alpha a=0.5 * Target Reaction : Cu oxidation [mV]

Mechanism1 Cu-> Cu2+ +2e-
Mechanism2 Cu-> Cu+ +e-
Cu+->Cu2+ +e-​

Answers

The Tafel slope for Mechanism 2 is the sum of the slopes of both steps, presuming that each step in Mechanism 2 is RCS::

b2 = b2_1 + b2_2 = 0.1184 + 0.1184 = 0.2368 V

How to solve

To identify the rate-controlling step (RCS) utilizing the Tafel slope, we initially need to calculate the Tafel slope for each suggested mechanism when the electron transfer coefficient (alpha, α) equals 0.5.

The target reaction involves Cu oxidation.

Mechanism 1:

Cu -> Cu²⁺ + 2e⁻

Mechanism 2:

Cu -> Cu⁺ + e⁻

Cu⁺ -> Cu²⁺ + e⁻

The Tafel slope (b) can be computed with the following formula:

b = (2.303 * R * T) / (α * n * F)

Where:

R signifies the gas constant (8.314 J/mol K)

T represents the temperature in Kelvin (let's assume 298 K, standard room temperature)

α denotes the electron transfer coefficient (0.5)

n is the number of electrons exchanged in the RCS

F is the Faraday constant (96,485 C/mol)

For Mechanism 1, n = 2 (since 2 electrons are exchanged in the rate-controlling step):

b1 = (2.303 * 8.314 * 298) / (0.5 * 2 * 96,485) = 0.0592 V

For Mechanism 2, we must examine both steps. Let's initially evaluate the Tafel slope for each step.

Step 1 (n = 1):

b2_1 = (2.303 * 8.314 * 298) / (0.5 * 1 * 96,485) = 0.1184 V

Step 2 (n = 1):

b2_2 = (2.303 * 8.314 * 298) / (0.5 * 1 * 96,485) = 0.1184 V

The Tafel slope for Mechanism 2 is the sum of the slopes of both steps, presuming that each step in Mechanism 2 is RCS::

b2 = b2_1 + b2_2 = 0.1184 + 0.1184 = 0.2368 V

Having obtained the Tafel slopes for both mechanisms, we can now compare them to the experimental Tafel slope to ascertain which mechanism is more likely the RCS.

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Magnesium (Mg) has nine electrons. Which of the following shows the correct electron configuration for an atom of Mg? 1, 8

Answers

The correct electron configuration for an atom of Magnesium (Mg) is 2, 7.

What is electron configuration?

The distribution of electrons among an atom's or ion's energy levels and sublevels is referred to as electron configuration. It outlines how electrons are grouped in numerous shells and subshells surrounding an atom's nucleus.

The electron configuration is frequently expressed in shell and subshell notation, such as 1s², 2s², 2p⁶, 3s², 3p², where the numbers represent the energy level or shell and the letters s, p, d, and f represent the sublevels or orbitals inside each shell.

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A student used a video camera to record another student dropping a marble through water in a graduated cylinder. The students watched the video in slow motion and made the observations shown below. During which part or parts of the marble’s fall did the marble experience unbalanced forces?

Answers

Parts B and C of the marble's fall did the marble experience unbalanced forces. Option 4 is correct.

A force is a push or pull (interaction) which changes the momentum of an object, either stationary or in motion when unopposed. All objects experience different forces depending on their environment. When immersed in fluids, unbalanced forces of one upward moving force tends to cancel the gravity force moving downward on a sinking object causing deceleration to a constant sinking speed.

This upward moving force is called as Buoyant force. This is where at part A, the object will experiences a balanced force of gravity which accelerates due to the absence of an opposing force acting upwards on the object. At part B, the speed of the sinking object decreases due to an unbalanced force that cancels the acceleration by the buoyant force. Once the sinking object’s acceleration is cancelled, its sinking speed turns constant at part C.

Hence, 4. is the correct option.

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--The given question is incomplete, the complete question is

"A student used a video camera to record another student dropping a marble through water in a graduated cylinder. The students watched the video in slow motion and made the observations shown below. During which part or parts of the marble's fall did the marble experience unbalanced forces? (1) Part A only (2) Parts A and B only (3) Part C only (4) Parts B and C only."--

NEED HELP FIGURING HOW MANY MOL!! PLEASE QUICK!!THANK YOU SO MUCH

Answers

The number of moles of the gas by the ideal gas law is 0.18 moles.

What is the ideal gas law?

The behavior of an ideal gas, a hypothetical gas made up of randomly moving particles with little volume and no intermolecular interactions, is described by the ideal gas law.

Although intermolecular interactions and non-zero particle volume prevent gases from always behaving in an ideal manner, the ideal gas law is nevertheless a good approximation for many gases under some circumstances.

We know that;

PV = nRT

We have ;

P = 1.2 atm

V = 3.4 L

T = 10 + 273 = 283 K

n = ?

n = PV/RT

n = 1.2 * 3.4/0.082 * 283

n =4.08 /23.2

n = 0.18 moles

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1. Calculate the number of grams of Al in 371 g of Al2O3.
2. Urea [(NH2)2 CO] is used for fertilizer and many other things. Calculate the mass of N, C, O, and H atoms in 1.68 x 10^4 g of urea.​

Answers

For the following calculations:

371 g of Al₂O₃ contains 196.53 g of Al.

Urea contains 7847.55 g N, 3362.69 g C, 152.18 g H, and 4472.57 g O.

How to calculate contents?

1. To calculate the number of grams of Al in 371 g of Al₂O₃, calculate the molar mass of Al₂O₃ and then use stoichiometry to find the mass of Al.

Molar mass of Al₂O₃ = (2 x atomic mass of Al) + (3 x atomic mass of O)

= (2 x 26.98 g/mol) + (3 x 16.00 g/mol)

= 101.96 g/mol

Using stoichiometry to find the mass of Al:

1 mol Al₂O₃ contains 2 mol Al

So, 101.96 g Al₂O₃ contains (2 x 26.98) = 53.96 g Al

Therefore, 371 g of Al₂O₃ contains (53.96/101.96 x 371) = 196.53 g of Al.

2. To calculate the mass of N, C, O, and H atoms in 1.68 x 10⁴ g of urea:

Molar mass of urea = (2 x atomic mass of N) + (1 x atomic mass of C) + (3 x atomic mass of H) + (1 x atomic mass of O)

= (2 x 14.01 g/mol) + (1 x 12.01 g/mol) + (3 x 1.01 g/mol) + (1 x 16.00 g/mol)

= 60.06 g/mol

Using stoichiometry to find the mass of each element:

1 mol urea contains 2 mol N, 1 mol C, 3 mol H, and 1 mol O

So, 60.06 g urea contains 2 x (14.01 g N) = 28.02 g N,

1 x (12.01 g C) = 12.01 g C,

3 x (1.01 g H) = 3.03 g H, and

1 x (16.00 g O) = 16.00 g O.

Therefore, 1.68 x 10⁴ g of urea contains:

(28.02/60.06 x 1.68 x 10⁴) = 7847.55 g N,

(12.01/60.06 x 1.68 x 10⁴) = 3362.69 g C,

(3.03/60.06 x 1.68 x 10^4) = 152.18 g H, and

(16.00/60.06 x 1.68 x 10⁴) = 4472.57 g O.

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How much energy is released when 73 grams of water cools from 72 degrees Celsius to
30 degrees Celsius?

Answers

The amount of energy released when 73 grams of water cools from 72°C to 30°C can be calculated using the following equation:

q = m × c × ΔT

where q is the amount of energy released, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The specific heat capacity of water is 4.18 J/g°C.

The change in temperature is:

ΔT = 72°C - 30°C = 42°C

Substituting these values into the equation gives:

q = (73 g) × (4.18 J/g°C) × (42°C)

q = 13,633.32 J

Therefore, the amount of energy released when 73 grams of water cools from 72°C to 30°C is 13,633.32 J.

Can u mark my answer as the Brainlyest if it work Ty

Please help asp and don 't just put random answers please

Answers

The value of Tan P as fraction simplest form is 15 / 29

How do determine the value of tan P?

The following data were obtained from the question:

Angle θ = POpposite = 15Adjacent = 29Tan P =?

Tan θ ratio is express as:

Tan θ = Opposite / Adjacent

Inputting the various parameters obtained from the question, we can obtain Tan P as shown below:

Tan P = Opposite / Adjacent

Tan P = 15 / 29

Thus, from the above calculation, we can conclude that the value of tan P in it's lowest fraction is 15 / 29

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The empirical formula of caffeine is C4H5N2O. If the molar mass of caffeine is 194.19 g/mol, what is the molecular formula of caffeine?

Answers

The molecular formula of caffeine is  C₈H₁₀N₄O₂

To find the molecular formula of caffeine, we need to determine the ratio of the empirical formula to the actual molecular formula. The empirical formula gives us the smallest whole-number ratio of atoms in a compound, while the molecular formula gives us the actual number of atoms of each element in a molecule.

First, we need to calculate the empirical formula mass of caffeine:

Empirical formula mass = (4 x atomic mass of carbon) + (5 x atomic mass of hydrogen) + (2 x atomic mass of nitrogen) + (1 x atomic mass of oxygen)

Empirical formula mass = (4 x 12.01 g/mol)+ (5 x 1.01 g/mol) + (2 x 14.01 g/mol) + (1 x 16.00 g/mol)

Empirical formula mass = 96.09 g/mol

Next, we can calculate the ratio of the molar mass of caffeine to the empirical formula mass:

Ratio = Molecular mass / Empirical formula mass

Ratio = 194.19 g/mol / 96.09 g/mol

Ratio = 2.02

This ratio tells us that the molecular formula of caffeine is approximate twice the size of the empirical formula. To find the molecular formula, we can multiply the subscripts in the empirical formula by the ratio:

C₄H₅N₂O × 2 = C₈H₁₀N₄O₂

Therefore, the molecular formula of caffeine is C₈H₁₀N₄O₂.

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3. If I have 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container?​

Answers

Answer:

The pressure would be 1.65 atmospheres.

(25 pts) Explain in depth the relationship between LIMITING reactant and THEORETICAL yield

Answers

Answer: I got you fam

Explanation:

A limiting reactant is a reactant in a chemical reaction that limits the amount of product created.

So for example if there are elements X and Y reacting to create product XY, once say element X runs out, the reaction stops, even though there is still more of the reactant Y. So there is 0 g of element X remaining, and maybe 2 g left of element Y. X is the limiting reactant since it limits the amount of product made.

Theoretical yield is the maximum amount of product that could be made in an experiment. This occurs if a reaction is 100% effective (and experimentally, this doesn't usually happen, which is why it is called theoretical).

What is the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound? (Na2CO3 = 106)​

Answers

Answer:

To calculate the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound , you can use the formula:

Amount (in moles) = Mass of substance / Molecular mass

The molecular mass of sodium trioxocarbonate (IV) (Na2CO3) is 106 g/mol, as given in the question. Substituting the values in the formula, we get:

Amount (in moles) = 5.3 g / 106 g/mol = 0.05 mol

Therefore, the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound is 0.05 mol.

Note that the given molecular mass of Na2CO3 must be used to obtain the correct answe12 .

Explanation:

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Reaction Ai Sodium Bicarbonate and Hydrochloric Acid
Experimental Data
(a) Mass of evaporating dish
watch glass
(b) Mass of evaporating dish watch glass sodium bicarbonate
(c) Mass of sodium bicarbonate used
(d) Mass of evaporating dish watch glass sodium chloride
(e) Mass of sodium chloride collected (experimental yield)
.
Mole Ration and Reaction Story
.
.
Data Analysis
1) Use your data to determine the experimental mole-to-mole ratio between sodium bicarbonate and sodium chloride
Show your work for each
NaHCOS
Convert the mass of sodium bicarbonate used to moles
100.69
1
mole
9
Convert the mass of sodium chloride collected in moder
Nac
2g
104.2
3.bg
mole
g
Divide both of your results from the preceding two steps by the lower mole value to determine the simplest mole-to-
mole ratio between sodium bicarbonate and sodium chloride.

Answers

The reaction between sodium carbonate and hydrochloric acid

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O

How to solve

For reaction A

Mass of sodium bicarbonate used = (Mas of evaporating dish + watch glas + sodium bicarbonate) - (Mas of evaporating dish + watch glas)

= 46.582 - 46.263

= 0.319 g

Mass of sodium chloride = (mas of evaporating dish + watch glas + sodium chloride) - (Mas of evaporating dish + watch glas)

= 46.473 - 46.263

= 0.210 g

Moles of sodium bicarbonate (NaHCO3) used = mas/molecular weight

= (0.319 g) / (84 g/mol)

= 0.00380 mol

Moles of sodium chloride (NaCl) used = mas/molecular weight

= (0.210 g) / (58.44 g/mol)

= 0.00359 mol

Mol ratio of NaHCO3 : NaCl = 0.00380 : 0.00359

Divide by 0.00359

Simple mol ratio

NaHCO3 : NaCl = 1.06 : 1

After rounding

Mol ratio of NaHCO3 : NaCl = 1 : 1

Moles of NaHCO3 = moles of NaCl = 0.00359 mol

Theoretical yield of NaCl = moles x molecular weight

= 0.00359 mol x 58.44 g/mol

= 0.210 g

the percent yield of sodium chloride

= actual yield x 100 / theoretical yield

= 0.210*100/0.210

= 100%

the reaction between sodium bicarbonate and hydrochloric acid

NaHCO3 + HCl = NaCl + CO2 + H2O

For reaction B

Mass of sodium carbonate used = (Mas of evaporating dish + watch glas + sodium carbonate) - (Mas of evaporating dish + watch glas)

= 51.677 - 51.368

= 0.309 g

Mass of sodium chloride = (mas of evaporating dish + watch glas + sodium chloride) - (Mas of evaporating dish + watch glas)

= 51.671 - 51.368

= 0.303 g

Moles of sodium carbonate (Na2CO3) used = mas/molecular weight

= (0.309 g) / (106 g/mol)

= 0.00292 mol

Moles of sodium chloride (NaCl) used = mas/molecular weight

= (0.303 g) / (58.44 g/mol)

= 0.00518 mol

Mol ratio of

Na2CO3 : NaCl = 0.00292 : 0.00518

Divide by 0.00292

Simple mol ratio

Na2CO3 : NaCl = 1 : 1.78

After rounding

Mol ratio of Na2CO3 : NaCl = 1 : 2

Moles of NaCl = 2 x moles of Na2CO3

= 2 x 0.00292 = 0.00584 mol

Theoretical yield of NaCl = moles x molecular weight

= 0.00584 mol x 58.44 g/mol

= 0.341 g

the percent yield of sodium chloride

= actual yield x 100 / theoretical yield

= 0.303*100/0.341

= 88.86%

the reaction between sodium carbonate and hydrochloric acid

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O

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Determine the total pressure of a gas mixture that contains O

Answers

To determine the total pressure of a gas mixture that contains oxygen (O2), you need to know the partial pressure of the oxygen gas and the partial pressures of the other gases in the mixture. The total pressure of a gas mixture is equal to the sum of the partial pressures of all the gases in the mixture. This is known as Dalton’s Law of Partial Pressures. Can you provide more information about the gas mixture, such as the partial pressures or mole fractions of the gases in the mixture?

MARK ME BRAINLEIST

Which of the following solutions can function as a buffer

Answers

All of the solutions can function as a buffer and the correct option is option 4.

A buffer solution is a water solvent-based solution which consists of a mixture containing a weak acid and the conjugate base of the weak acid or a weak base and the conjugate acid of the weak base.

They resist a change in pH upon dilution or upon the addition of small amounts of acid/alkali to them.

All of these solutions are combinations of weak acid or base with its salt and thus can function as a buffer.

Thus, the ideal selection is option 4.

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Which compound represents fe+3 o-2

Answers

Answer:

The compound that represents Fe+3 O-2 is Fe2O3 (iron oxide or rust)

Assuming that the mass defect originates solely from the interactions of protons and neutrons in the nucleu, estimate the nuclear binding energy of Li given yhe following data.observee atomic mass (a.m.u) of Li is 7.01600u
1u=1.66054×10^-27kg
Electron rest mass= 9.10939×10^-31kg
Proton rest mass=1.67262×10^-27kg
Neutron rest mass=1.67493×10^-27kg
C=2.998×10^8

Answers

The mass lost in the formation of a nucleus is converted into energy in accordance with the Einstein's mass energy relationship and released, thereby tending to impart stability to the nucleus.

An input of the same amount of energy referred to as the binding energy would be required to decompose the nucleus into its component nucleons. So the energy released from the nucleons during the formation of a nucleus is called the binding energy.

No: of protons in 'Li' = 3

No: of neutrons in 'Li' = 4

Total mass of nucleons = 3(1.67262×10⁻²⁷) + 4 (1.67493×10⁻²⁷) = 1.171 × 10⁻²⁶ kg

Mass defect = 1.171 × 10⁻²⁶ - 1.165 × 10⁻⁻²⁶ = 6 × 10⁻²⁹

Binding energy = Δmc² = 6 × 10⁻²⁹ × (2.998×10⁸)² = 5.392 × 10⁻¹² J

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Trimethylamine is a weak base. A 0.150 M solution of trimethylamine has a pH of 11.5.
What is Kb for trimethylamine?

Answers

Kb for trimethylamine is 1.0 × 10^-2.5.

We can use the relationship between Kb and Ka for a conjugate acid-base pair:

Kb × Ka = Kw

The pKa is related to the pH :

pKa + pKb = 14.00

pKb = 14.00 - pKa

We can calculate the pKa using the relationship:

pH = pKa + log([base]/[acid])

Therefore, [base] = [acid], and we can simplify equation to:

pH = pKa + log(1)

Therefore, the pKa of trimethylammonium ion is 11.5.

Now :

Kb × Ka = Kw

Kb = Kw ÷ Ka

Since we know that Kw = [tex]1.0 * 10^{-14[/tex]and Ka =[tex]10^{-11.5[/tex] (from the pKa value we calculated earlier), we can substitute these values to get:

[tex]Kb = (1.0 * 10^{-14}) / (10^{-11.5}) = 1.0 * 10^{-2.5[/tex]

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Choose the best term or phrase to fill in the blanks in the sentences below. Not all answer choices will be used. Question 10 options: (2) The probability that these parents will have an offspring affected with sickle cell anemia is ______ percent. (3) The probability that their offspring would also be a carrier like them is ______ percent (1) The image shows the cross between two parents who are carriers for sickle cell anemia, a recessive genetic disorder that affects the red blood cells in humans. Both parents are considered to be ______________.

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The image shows the cross between two parents who are carriers for sickle cell anemia, a recessive genetic disorder that affects the red blood cells in humans. Both parents are considered to be carrier.

The scientific study of inheritance and genes is covered in this page, along with details on the structure of DNA, chromosomes, gene variants, and the evolution of living beings and their genomes.

(1) The image shows the cross between two parents who are carriers for sickle cell anemia, a recessive genetic disorder that affects the red blood cells in humans. Both parents are considered to be carrier. (2) The probability that these parents will have an offspring affected with sickle cell anemia is 50 percent.  (3) The probability that their offspring would also be a carrier like them is 50 percent.

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b) 2.38 gm of a metal on treatment with nitric acid and sub sequent ignition gave 3.022 gm of the oxide. Specific heat of the metal is 0.055, calculate the extra atomic weight.

Answers

The extra atomic weight in a metal on treatment with nitric acid is 100.361 g/mol.

How to calculate extra weight?

The first step is to calculate the mass of oxygen in the oxide formed:

Mass of oxygen = Mass of oxide - Mass of metal

Mass of oxygen = 3.022 g - 2.38 g

Mass of oxygen = 0.642 g

Use the specific heat of the metal to determine its identity:

specific heat = 6.4 / atomic weight

Solving for atomic weight:

atomic weight = 6.4 / specific heat

atomic weight = 6.4 / 0.055

atomic weight = 116.36 g/mol

The atomic weight to calculate the extra atomic weight:

extra atomic weight = atomic weight - atomic weight of oxygen

extra atomic weight = 116.36 g/mol - 15.999 g/mol

extra atomic weight = 100.361 g/mol

Therefore, the extra atomic weight is 100.361 g/mol.

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a) If the chemical formula for iron (III) chloride is FeCl 3 , what is the chemical formula for iron (III) nitrate?b) If the chemical formula for lead (II) oxide is PbO, what is the chemical formula for lead (II) sulfate?c) If the chemical formula for silver chloride is AgCl, what is the chemical formula for silver nitrate?

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a) The chemical formula for iron (III) nitrate is Fe(NO₃)₃. b) The chemical formula for lead (II) sulfate is PbSO₄. c) The chemical formula for silver nitrate is AgNO₃.

In chemical nomenclature, the Roman numeral in the name of the compound indicates the oxidation state of the metal ion. To determine the chemical formula of a compound, it is important to balance the charge of the ions in the compound. In the case of iron (III) nitrate, the iron ion has a +3 charge and the nitrate ion has a -1 charge, so it takes three nitrate ions to balance the charge of the iron ion.

In the case of lead (II) sulfate, the lead ion has a +2 charge and the sulfate ion has a -2 charge, so it takes one lead ion and one sulfate ion to balance the charges. Similarly, in the case of silver nitrate, the silver ion has a +1 charge and the nitrate ion has a -1 charge, so it takes one of each to balance the charges.

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NEED HELP TO FIGURE HOW MANY ATM!!?? PLEASE HELP QUICKLY THANK YOU

Answers

Answer: 0.358 atm

Explanation:

This is from Gas Laws in Chemistry. Pretty simple.

You've been given V = 5.5 L, n = 2 mol, and T = 12

It is also given that R = 0.0821 for atm.

Plugging in, you get the equation: 5.5P = 2 x 12 x 0.0821

Solving for P, you get about: 0.358 atm.

Thats the pressure!

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