Answer:
Step-by-step explanation:
Because its an internationally accepted method.
help meeeeeeeeeeeeeeeeeeeeeeeeee
When c=0 It's 75 when x= 0 It's 75 when x= 100 It's 100 when x= 200 its 125 when x= 300 its 150
Step-by-step explanation:
For A, The printer would be 75 dollars and each newspaper printed is .25 cents
Answer:
c
Step-by-step explanation:
What is the value of 0.5+0.3( the 3 is repeating)? Write the answer as a fraction in the lowest terms 
we have the following:
[tex]0.5+0.\hat{3}[/tex]therefore:
[tex]\begin{gathered} 0.5+0.\hat{3}=0.8\hat{3} \\ 08\hat{3}=\frac{5}{6} \end{gathered}[/tex]therefore, the answer is 5/6
I need help solving this practice problem from my prep guide
ANSWER
[tex]\lim _{n\to\infty}\text{ }(\frac{3n^5^{}}{6n^6+1})\text{ = 0}[/tex]EXPLANATION
Step 1: Given that:
[tex]\sum ^{\infty}_{n\mathop=1}(\frac{3n^5^{}}{6n^6+1})[/tex]Step 2: Expand the limit
[tex]\begin{gathered} \lim _{n\to\infty}(\frac{3n^5^{}}{6n^6+1})\text{ } \\ \text{ = }\lim _{n\to\infty}\frac{n^5}{n^5}(\frac{3^{}}{6n^{}+\frac{1}{n^5}}) \\ \text{ = }\lim _{n\to\infty}(\frac{3^{}}{6n^{}+\frac{1}{n^5}}) \\ =\text{ }\lim _{n\to\infty}(\frac{3^{}}{6(\infty)^{}+\frac{1}{(\infty)^5}}) \\ \text{ = }\lim _{n\to\infty}(\frac{3^{}}{6(\infty)^{}+\frac{1}{\infty}}) \\ \text{ = }\lim _{n\to\infty}(\frac{3^{}}{6(\infty)^{}+0^{}}) \\ \text{ = }\lim _{n\to\infty}(\frac{3^{}}{6(\infty)^{}^{}})\text{ = 0} \\ \end{gathered}[/tex]Hence,
[tex]\lim _{n\to\infty}(\frac{3n^5}{6n^6+1})\text{ = 0}[/tex]I need help with 1&2 they are one whole question
1. From the graph we see that the x-intercept occurs at the points: (3,0) and (-4,0).
Therefore, the factored form of the equation is given by:
[tex]\begin{gathered} x=3 \\ x-3=3-3 \\ x-3=0 \end{gathered}[/tex]or
[tex]\begin{gathered} x=-4 \\ x+4=-4+4 \\ x+4=0 \end{gathered}[/tex]So, the factored form is:
[tex](x-3)(x+4)[/tex]Answer: B. (x - 3)(x + 4)
Plllllz help
A candy company sells peanut brittle and almond bark. The information for both types of candy is shown.
graph labeled Peanut Brittle with x axis labeled weight in ounces and y axis labeled cost in dollars with a line from point 0 comma 0 going through 10 comma 10
Determine how much more one candy costs per ounce than the other candy.
Almond bark costs $0.38 more per ounce than peanut brittle.
Peanut brittle costs $0.38 more per ounce than almond bark.
Almond bark costs $0.60 more per ounce than peanut brittle.
Peanut brittle costs $0.60 more per ounce than almond bark.
Answer:
THE ANSWER IS C.
I also took the test.
what digit is in the
We want to do the following operation:
[tex]\frac{1}{27}+\frac{7}{15}[/tex]To add fractions, we need to put both denominators in the same value. We need to find the LCM between 27 and 15. Factorizing those numbers in prime numbers, we have:
[tex]\begin{gathered} 15=5\times3 \\ 27=3\times3\times3 \end{gathered}[/tex]The LCM is the result of multiplying all those prime factors the most times they occur. Since 3 appears on both factorizations, we'll use only the most occuring 3(in this case, 3 times).
[tex]LCM(15,27)=3\times3\times3\times5=135[/tex]Now, we need to rewrite those fractions with the new denominator. To do that we just need to multiply both the numerator and the denominator by the same factor. To find those factors we just need to find the ratio between the denominator and 135.
[tex]\begin{gathered} \frac{135}{27}=5 \\ \frac{135}{15}=9 \end{gathered}[/tex]Now, converting those fractions to this denominator:
[tex]\begin{gathered} \frac{1}{27}=\frac{1\cdot5}{27\cdot5}=\frac{5}{135} \\ \frac{7}{15}=\frac{7\cdot9}{15\cdot9}=\frac{63}{135} \end{gathered}[/tex]Now, to finally do the addition, we just add the numerators.
[tex]\frac{1}{27}+\frac{7}{15}=\frac{5}{135}+\frac{63}{135}=\frac{5+63}{135}=\frac{68}{135}[/tex]Since 68 and 135 don't share any divisors, this is the simplest form of this fraction. The result is 68/135.
You are asked to use the grouping method to factorx² − 14x + 33. How should the term - 14x berewritten?O 3x + 11xO-3x - 11xO -1x - 33xO 1x +33x
Given the Quadratic Polynomial:
[tex]x^2-14x+33[/tex]You need to factor it using the Grouping Method.
You can identify that it has this form:
[tex]ax^2+bx+c[/tex]Notice that, in this case:
[tex]\begin{gathered} a=1 \\ b=-14 \\ c=33 \end{gathered}[/tex]In order to rewrite it in a form that then you can apply the Grouping Method, you need to find two numbers whose product is the value of "c" and whose sum is the value of "b".
Notice that:
[tex]\begin{gathered} (-3)(-11)=33 \\ -3-11=-14 \end{gathered}[/tex]Therefore, you can set up that:
[tex]-14x=-3x-11x[/tex]Hence, the answer is: Second option.
help me please !!!
thank youuu
The range of values that can be plugged into a function is known as its domain. In a function like f, this set represents the x values (x). The collection of values that a function can take on is known as its range.
Where can I find a fraction's domain?By factoring the numerator and denominator and setting them both to zero, the domain of a fraction function can be determined. The domain's values are the roots of the ensuing equation. Using the algebraic method of factoring is another method for determining the domain of a fraction function.
The range of values that can be plugged into a function is known as its domain. In a function like f, this set represents the x values (x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.
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The outside temperature decreases by 7 degrees in 3 1/2 hours. How would you represent the temperature change as a unit rate?
In each hour the outside temperature decreases by 2°C/hr.
What is a unitary method?A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.
Given the outside temperature decreases by 7 degrees in 3 1/2 or 7/2 hours.
The representation for the change in temperature as a unit rate will be.
= 7/(7/2) degrees.
= 7×2/7 degrees.
= 2 degrees.
So, The representation of the temperature change as a unit rate will be 2°C/hr.
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Help me solve this algebra 1 homework (question 10) please
From the question,
We are given the equation
[tex]3+7m=4m+3(m+1)[/tex]First, we will expand the RHS of the equation
This will give
[tex]3+7m=4m+3m+3[/tex]By simplifying the RHS we will get
[tex]3+7m=7m+3[/tex]From the equation above, the terms on the LHS equal to the terms on the RHS
This implies that the equation has infinite number of solutions
That is, if we insert any value the equation will always be true
Solve the following system of inequalities graphically on the set of axes below. State the coordinates of a point in the solution set.y < -x - 1y < 1/5x + 7
SOLUTION
Given the question, the following are the solution steps to answer the question.
STEP 1: Write the given inequalities
[tex]\begin{gathered} y<-x-1 \\ y<\frac{1}{5}x+7 \end{gathered}[/tex]STEP 2: Plot the graph of both inequalities
For the first inequality
For the second inequality
STEP 3: Plot the two inequalities on the graph to get the solution set.
The coordinates of a point in the solution set can be given as:
[tex](-10,1)_{}[/tex]three fifths of the students in a room are girls. 1/3 of the girls have blond hair. one half of the boys have brown hair. what fraction of all the students are girls with blonde hair ?what fractions are all this book for boys with brown hair ?
3/5 of the students are girls-
1-3/5 = 2/5
2/5 of the students are boys
1/3 of the girls have blonde hair.
So, multiply, the number of girls that have blonde hair (1/3) by the number of girls (3/5)
1/3 * 3/5 = 3 /15 = 1/5
of all students, 1/5 are girls with blonde hair.
For the boys;
1/2 of the boys have brown hair. of all students 2/5 are boys
2/5 * 1/2 = 2/10 = 1/5
Of all students 1/5 are boys with brown hair
These marbles are placed in a bag and twoof them are randomly drawn.What is the probability of drawing two yellowmarbles if the first one is NOT placed back intothe bag before the second draw?
Given the figure of marbles:
As shown, the number of marbles = 10
Two marbles are randomly drawn
We will find the probability of drawing two yellow marbles
The probability the first marble is yellow:
The number of yellow marbles = 2
so, the probability the first marble is yellow = 2/10 = 1/5
The first one is NOT placed back into the bag before the second draw
So, the number of marbles = 10 - 1 = 9
The number of yellow marbles = 2 - 1 = 1
So, the probability the second marble is yellow = 1/9
So, the probability of drawing two yellow =
[tex]\frac{1}{5}\times\frac{1}{9}=\frac{1}{45}[/tex]So, the answer will be 1/45
if RS = RU, ST = b + 72 and TU = 5b, what is the value of B?
The value of b is 18.
Here, we are given a triangle as shown in the figure above.
RS = RU
ST = b + 72
and TU = 5b
In triangle TRU, by Pythagoras theorem, we get-
(TU)² = (TR)² + (RU)²
⇒ (5b)² = (TR)² + (RU)²
(TR)² = (5b)² - (RU)²
Similarly, in triangle STR, we will get-
(TR)² = (b + 72)² - (SR)²
Equating the two equations, we get-
(5b)² - (RU)² = (b + 72)² - (SR)²
Since RS = RU,
(5b)² - (RS)² = (b + 72)² - (SR)²
25b² = b² + 72² + 2(72)b
24b² = 5,184 + 144b
b² = 216 + 6b
b² - 6b -216 = 0
Solving this quadratic equation will give us 2 values for b
b = 18 or b = -12
Since length of the side cannot be negative, the value of b will be 18.
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simply [tex] \sqrt{3} \times \sqrt{21} [/tex]please help
We have
[tex]\sqrt[]{3}\times\sqrt[]{21}[/tex]we can reduce the expression
[tex]\begin{gathered} \sqrt[]{3}\times\sqrt[]{21} \\ \sqrt[]{3}\times\sqrt[]{3\times7} \\ \sqrt[]{3}\times\sqrt[]{3}\times\sqrt[]{7} \\ 3\sqrt[]{7} \end{gathered}[/tex]the solution is
[tex]3\sqrt[]{7}[/tex]
Jamal's math teacher pointed out that the number of Jamal's free throws and the number of
two-point field goals (FG) were two consecutive odd numbers. He made more two-point
throws and no three-point FGs. If Jamal made a total
FGs
of 19 points, how many field goals did he make?
than free
Answer:
Step-by-step explanation: free throws are worth 1 point?
We have to find how many field goals he made.
We know that the number of free throws (FT) and the number of two-point field goals (FG) are two consecutive odd numbers. As they are consecutive odd numbers, they differ by two, so we can write:
There are no three-point field goals and the total number of points was 19, so this score has to be the sum of the points from free throws and the points from two-point field goals.
Answer:
He made 7 two-point field goals and 5 free throws.
He made 2 more field goals than free throws.
Answer: We have to find how many field goals he made.We know that the number of free throws (FT) and the number of two-point field goals (FG) are two consecutive odd numbers. As they are consecutive odd numbers, they differ by two, so we can write:There are no three-point field goals and the total number of points was 19, so this score has to be the sum of the points from free throws and the points from two-point field goals.Answer:He made 7 two-point field goals and 5 free throws.He made 2 more field goals than free throws.
Step-by-step explanation: hope this helps0^0
Graph the function g(x). I have a picture of the problem.
Let's begin by listing out the given information
[tex]\begin{gathered} g\mleft(x\mright)=\frac{3}{2}x-7 \\ g(x)=y \\ y=\frac{3}{2}x-7 \end{gathered}[/tex]We will proceed to assume values for x to obtain the y-values (x = -2, 0, 4, 8)
[tex]\begin{gathered} y=\frac{3}{2}x-7 \\ x=-2 \\ y=\frac{3}{2}(-2)-7=-3-7=-10 \\ x=0 \\ y=\frac{3}{2}(0)-7=0-7=-7 \\ x=4 \\ y=\frac{3}{2}(4)-7=6-7=-1 \\ x=8 \\ y=\frac{3}{2}(8)-7=12-7=5 \\ (x,y)=(-2,-10),(0,-7),(4,-1),(8,5) \end{gathered}[/tex]We will plot these points on the graph. We have:
a 6 inch cube has the same volume as a box with a base 8in by 9in how tall is the box
Answer: 3 inches tall
Step-by-step explanation:
The formula for the volume of a cube is a to the power of 3
Substitute a with 6 and you get 6^3. 6 X 6 X 6 = 216 so the volume is 216 inches cubed.
The formula for the volume of a rectangular prism is length X width X height. If we substitute the length and with with 8 and 9, we get 8 X 9 X height = 216 (since the volume is the same.)
72 X height = 216. Divide both sides by 72 and you get 3 as an answer.
help i am on limited time
The slope intercept equation of the graph f is y = -1/3x + 5
Slope intercept equation:
The general for of the slope intercept equation is,
y = mx + b
Here,
(x, y) = Every point on the line
m = Slope of the line
b = y-intercept of the line
Given,
Here we have the point (-9, 8) and the line of the graph is perpendicular to the x intercept 6 and y intercept -18.
Now we need to find the slope intercept equation for the graph f.
From the given details, we know that,
The x intercept point (6,0)
Y intercept point (0,-18)
So you are looking for a line perpendicular to a line that passes through the points (6,0) and (0,-18)
The slope of the line going through these points is:
m=(y1-y2)/(x1-x2)
slope of this line = 18/6 = 3
the slope of line perpendicular to this line will have slope of -1/3
( negative reciprocal)
Therefore, the point (-9, 8 ) has the slope = -1/3
Now we can use this slope and the given point (-9,8) to find the y-intercept (b)
y = mx + b
8 = (-1/3)(-9) + b
8 = 9/3 + b
b = 8 - 3
b = 5
Therefore, the equation of the line in point intercept form is:
y = -1/3x + 5
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Find the root of the function f(x) = ³/1.A. x = -5OB. z = 0OC. x = 5OD. noneReset Selection
Explanation
We have
[tex]f(x)=\frac{5}{x}[/tex]Because upon solving we have
[tex]\begin{gathered} \frac{5}{x}=0 \\ 5=0 \\ no\text{ solution} \end{gathered}[/tex]Therefore, it has no root
The answer is none
Op
WA Alvin used 1/2 of a cup of frosting to decorate some cupcakes. He divided all the frosting equally among 5 cupcakes. How much frosting did Alvin use on each cupcake? Write your answer as a fraction or as a whole or mixed number. cups Submit
1) Gathering the data
1/2 a cup of frosting equally divided by 5
2) Let's divide the
Find the values of x, y, z, A, and B in the image below. List the facts that both triangles have 90° angles and that the triangles are similar. What is the value of A and B in degrees? What is the measure of y and z?
Answer:
[tex]\begin{gathered} A=36.87\text{\degree} \\ B=53.13\text{\degree} \\ x=12 \\ y=10.15 \\ z=6.25 \end{gathered}[/tex]Step-by-step explanation:
First, we'll work on the triangle that's on the left side. We'll find the values of A,B and x.
Using the law of sines, we'll have that:
[tex]\frac{\sin(90)}{15}=\frac{\sin(A)}{9}[/tex]Solving for A,
[tex]\begin{gathered} \frac{\sin(90)}{15}=\frac{\sin(A)}{9} \\ \\ \rightarrow\sin(A)=\frac{9\sin(90)}{15} \\ \\ \rightarrow\sin(A)=\frac{3}{5} \\ \\ \rightarrow A=\sin^{-1}(\frac{3}{5}) \\ \\ \Rightarrow A=36.87\text{\degree} \end{gathered}[/tex]Now, since we know that the sum of the interior angles of a triangle is 180°, we'll have that:
[tex]\begin{gathered} 90+A+B=180 \\ \rightarrow B=180-A-90 \\ \rightarrow B=180-36.87-90 \\ \\ \Rightarrow B=53.13\text{\degree} \end{gathered}[/tex]Using the law of sines again, we'll get that:
[tex]\frac{x}{\sin(B)}=\frac{15}{\sin(90)}[/tex]Solving for x,
[tex]\begin{gathered} \frac{x}{\sin(B)}=\frac{15}{\sin(90)} \\ \\ \rightarrow x=\frac{15\sin(B)}{\sin(90)}\rightarrow x=\frac{15\sin(53.13)}{\sin(90)} \\ \\ \Rightarrow x=12 \end{gathered}[/tex]Now, we'll work on the triangle that's on the right side. We'll find the values of y and z.
Since this is a right triangle (it has a 90° angle), we can say that:
[tex]\cos(38)=\frac{8}{y}[/tex]Solving for y,
[tex]\begin{gathered} \cos(38)=\frac{8}{y}\rightarrow y\cos(38)=8\rightarrow y=\frac{8}{\cos(38)} \\ \\ \Rightarrow y=10.15 \end{gathered}[/tex]We can also state that:
[tex]\tan(38)=\frac{z}{8}[/tex]Soving for z,
[tex]\begin{gathered} \tan(38)=\frac{z}{8}\rightarrow z=8\tan(38) \\ \\ \Rightarrow z=6.25 \\ \end{gathered}[/tex]This way, we can conclude that:
[tex]\begin{gathered} A=36.87\text{\degree} \\ B=53.13\text{\degree} \\ x=12 \\ y=10.15 \\ z=6.25 \end{gathered}[/tex]Wouldn’t the angle of fge be 1/2 the distance of the incercepted arc which would 135?
Answer:
m∠FGE=52.5 degrees
Explanation:
Angle FGE is formed by the intersection of two secants (BG and GD).
The intercepted arcs are BD and FE.
Therefore:
[tex]m\angle\text{FGE}=\frac{1}{2}(m\widehat{\text{BD}}-m\widehat{FE})[/tex]Substitute the given values:
[tex]\begin{gathered} m\angle\text{FGE}=\frac{1}{2}((100+35)-30) \\ =\frac{1}{2}(105) \\ m\angle\text{FGE=52.5}\degree \end{gathered}[/tex]
NO LINKS!! Part 3: Please help me with this Similarity Practice
Answer: (10,5) or (14,3) are two possible answers.
Infinitely many answers are possible. Pick one to write as the final answer to your teacher.
=====================================================
Explanation:
Focus on the points B(1,4) and C(5,2)
More specifically, focus on the x coordinates 1 and 5. To go from B to C, we move to the right 4 units since 1+4 = 5
We also move down 2 units since we go from y = 4 to y = 2
In short, the translation motion is "right 4, down 2". We can further abbreviate this into the vector notation <4, -2>. This translation vector only applies going from B to C.
The vector notation <4,-2> is the same as writing [tex](x,y) \to (x+4,y-2)[/tex] but the first method is much faster to write out since it avoids needing to write x or y.
--------------------
Now if we want to construct a similar triangle A'B'C', we will use that vector to scale it up or down. Let's scale it up and double each coordinate.
<4, -2> doubles to <8,-4>
So instead of "right 4, down 2" we now follow the path "right 8, down 4". Take notice how both motions involve the same slope.
Start at B'(2,9) and move right 8 and down 4 to arrive at C'(10,5)
See figure 1 below.
This is one possible answer out of infinitely many. This is because we can change the scale factor to any nonnegative real number we want.
-------------------
Another example:
Instead of doubling the coordinates of the translation vector, let's triple them.
<4,-2> triples to <12,-6>
Then start at B'(2,9) and move right 12 and down 6 to arrive at C'(14,3) which is another possible answer out of infinitely many.
See figure 2 below.
Pick whichever of (10,5) or (14,3) is your favorite to get the final answer, assuming your teacher wants you to write one (x,y) location only. Or pick some other scale factor (other than 2 or 3) and follow the same idea to get some other possible location of point C'.
Answer:
C' = (10, 5)
Dilation by a scale factor of 2 with the origin (0, 0) as the center of dilation, followed by a translation of 1 unit up.
Step-by-step explanation:
If two triangles are said to be similar, their corresponding angles are congruent and their corresponding sides are in the same ratio.
Therefore, to maintain similarity (and thus keep the corresponding angles of both triangles the same) but not maintain congruence, dilate triangle ABC.
Given vertices of triangle ABC:
A = (0, 0)B = (1, 4)C = (5, 2)Given vertex of triangle A'B'C':
B' = (2, 9)If ΔABC is dilated by a scale factor of 2, with the origin as the center of dilation, B' = (2, 8). If the triangle is then translated 1 unit up, B' = (2, 9), which matches the given coordinate of point B'.
Therefore, the series of transformations is:
Dilation by a scale factor of 2 with the origin (0, 0) as the center of dilation.Translation of 1 unit up.Mapping Rule: (x, y) → (2x, 2y + 1)
Therefore, the coordinates of point C' are:
⇒ C' = (2(5), 2(2) + 1) = (10, 5)
Question 4(Multiple Choice Worth 2 points)
(01.03 LC)
Simplify 4x√3x-x√√3x-2x√√3x.
x√3x
x√9x
2x√6x
2x√√6x³
x√3x is value of x in surds.
What is surds in maths?
A square root, cube root, or other root sign is a part of a surd. Irrational numbers cannot be stated accurately in decimal form because their decimals do not finish or recur. Surds are used to write irrational numbers precisely.Surds are employed when precise calculations call for a root that can be a square root, cube root, or another root. As an illustration, the square root of three and the cube root of two are both roots. It is irrational to use the value 5 2.23606 as a square root of 5. 5 is squared, which is a surd.= 4x√3x-x√√3x-2x√√3x
= √3x ( 4x - x - 2x )
= √3x ( 4x - 3x )
= √3x ( x)
= x√3x
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Select the correct choice for now and if necessary fill in the answers box to complete your choice
We have
[tex]\begin{gathered} (A\cup B)^{\prime}=U-(A\cup B)=\mleft\lbrace1,2,3,4,5,6,7\mright\rbrace-\mleft\lbrace2,3,4,5,6\mright\rbrace \\ (A\cup B)^{\prime}=\mleft\lbrace1,7\mright\rbrace \end{gathered}[/tex]Answer: A.
[tex](A\cup B)^{\prime}=\lbrace1,7\rbrace[/tex]Given the base band height hof a triangle, calculate the area A using the formula for the area of a triangle: A = 1/2 bh Calculate A when b 17 feet and h = 6 feet. what is the answer
The area of the triangle of base (b) and a height (h) is A
[tex]A=\frac{1}{2}\cdot b\cdot h[/tex]Given: b = 17 feet and h = 6 feet
So, the area will be :
[tex]A=\frac{1}{2}\cdot17\cdot6=17\cdot3=51ft^2[/tex]so, the answer is : the area of the triangle = 51 square feet.
Using the following coordinates, what is the slope of the line ?
lets take m as slope
[tex]m=\frac{y2-y1}{x2-x1}[/tex]x1=4 y1=13 x2=5 y2=16
[tex]m=\frac{16-13}{5-4}=3[/tex]so we get the slope as 3.
so the answer is 3.
Type the correct answer in the box. Use numerals instead of words.
Consider AABC.
Determine the measure of angle C.
A= 48.36
B= 59.49
C=?
The measure of angle c is 72.15.
What is angle sum property for a triangle?
Angle sum property of triangle states that The measure of all interior angles of a triangle is [tex]180^{o}[/tex] that is sum of all 3 interior angle is 180
We are given a Δ[tex]ABC[/tex]
Measure of interior angles of ABC is 180.
Hence the equation can be given as,
∠A+∠B+∠C=180
48.36+59.49+∠C=180
107.85+∠C=180
∠C=72.15
Hence the measure of ∠C is 72.15
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Answer:72.15
Step-by-step explanation:
Please help me!!!!!!!
Answer:
With what?
Step-by-step explanation:
