Why the following code is giving error NAME="REHMAAN" PRINT ("hello') PRINT ("HI")

Answer:

Declaration: length, width, area

Inputs: length & width

Processing: length & width

Output: area

Explanation:

The area of a rectangle uses the formula: [tex]A=lw[/tex]. In your coding, you need to ask for user input for the length and width in order to calculate the area.

Your processing would simplify multiple the user's input together stored in some type of sum variable.

Now I don't know what program language you are using but I will give you an idea.

Code (Python)

#Define variables equal to user input.

length = int(input("Enter the length of the rectangle: "))

width = int(input("Enter the width of the rectangle: "))

area = length * width

Your output would be the area, but you can manipulate it if you want.

print("The area of the rectangle is", area)

So the program would run like this:

Enter the length of the rectangle: 3 <--you type a number

Enter the width of the rectangle: 5

The area of the rectangle is 15

Sidenotes: if you are using ints, the number MUST be a whole number or the program will throw an error. If you are using decimals, use a float.

Answer:

False.

Explanation:

It's not true.

Answer:

C. Layout Tab – Page setup group – Breaks – Next page button.

Answer:

E=Paste

Explanation:

E= Paste the selected text

Answer:

e

Explanation:

because if you do Ctrl+c it copies and then you have to paste so you use Ctrl+v Therefore the answer is E

The timeline is a representation of a chronological sequence of events that occurred in a specific period. It is an important aspect of analyzing art and photography. Below are the three historical periods, art themes, and trends associated with the era, photographic styles, and most popular or frequently photographed subjects during the period:1.

Renaissance Period (1400-1600)Art Theme: Religious themes, classic myths, and historical events were a prominent theme.

Trend: The dominant trend during this period was the perfection of art as a skill. A focus on balance, symmetry, and realistic human features.

Photographic Style: There were no photographs at this time. The art was created by paint and other art forms.Most Popular/Frequently Photographed Subjects: People, daily life, architecture, and nature2.

Modernism Period (1900-1930)Art Theme: Experimental, abstraction, and simplification were the prominent art themes.

Trend: The dominant trend was the change of perception towards art and creative representation.

Photographic Style: During this period, photographers shifted their interest in capturing events in reality to exploring the abstract.

Most Popular/Frequently Photographed Subjects: Human faces, motion, and landscape3.

Postmodernism Period (1960-1990)Art Theme: The prominent art theme was the exploration of cultural differences and diversity.

Trend: The dominant trend was the creation of art that served as a critique to modernism.

Photographic Style: Photography became a primary source of artistic expression, and photographers created various styles.

Most Popular/Frequently Photographed Subjects: Social changes, women's rights, multiculturalism, and globalization.In conclusion, exploring the history of photography is an essential aspect of analyzing art and understanding the various artistic themes, trends, styles, and subjects that dominated each period.

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Answer:

Punch cards allowed a weaver to give instructions to the loom.

Explanation:

Answer-which type of tools enable you to choose only a portion of the image

selection, paint, exposure or color​?

Explanation:

Your answer is brush,eyedropper,and lasso all work.

Answer:

___I__22. paper

___I__23. glass

___C__24. iron

___I__25. plastic

___C__26. gold

__C___27. copper

___I__28. wood

___I__29. Rubber

___C__30. Aluminum

Materials which do not allow current to flow easily are called insulators.

Materials which allows current to flow easily are called Conductors.

Answer:

The answer to this question is given below in the explanation section.

Explanation:

My laptop's current screen resolution is (1366 by 768 recommended). When you change your screen resolution, your pc automatically suggests the recommended screen resolution that helps you to view more information on your screen and enable you to fit the most information on the screen while still being able to read the display.

To change the screen resolution, you need to go through from the following steps:

Answer:

using System;

namespace FavoriteNumber  

{

class Program

{

static void Main(string[] args)  

{

Console.Write("Enter your favorite number!: ");  

int number = Convert.ToInt32(Console.ReadLine());  

}

}

}

Answer:

public class Main

{

public static void main(String[] args) {

    int[] numbers = {28, 7, 92, 100, 0, 7, 300, 2873};

    int target = 7;

    int count = 0;

    int[] matchedIndexes = new int[numbers.length];

    for(int i = 0; i<numbers.length; i++){

        if (numbers[i] == target){

            matchedIndexes[count] = i;

            count++;

        }

    }

    int[] indexes = new int[count];

    for(int i = 0; i<count; i++){

       indexes[i] = matchedIndexes[i];

    }

    for(int i = 0; i<count; i++){

     System.out.print(indexes[i] + " ");

    }

}

}

Explanation:

Initialize the numbers array, target value and count

Create a new array called matchedIndexes with the size of the numbers array

Create a for loop that iterates through the numbers array and checks if the target is in the numbers array. If it is, put the index of the number in to the matchedIndexes array and increment the count by 1.

Create another array named indexes with size of count

Create a for loop that copies the values from matchedIndexes to indexes

Print the values in the indexes

Answer:

dates

text

drop-down lists

Answer:

B-dates

C-text

E-drop-down lists

Explanation: ;)

Then's a Python program that does this  

num1 =  int( input(" Enter the first integer"))  

num2 =  int( input(" Enter the alternate integer"))  

num3 =  int( input(" Enter the third integer"))  

if num1< num2  

if num1< num3  

lowest =  num1      

lowest =  num3    

if num2< num3  

lowest =  num2      

lowest =  num3  

print(" The  lowest integer is",  lowest)    

In order to write a program that prompts the  stoner to enter three integers one at a time and determines which integer is the  lowest, we need to use nested decision blocks and pay close attention to proper indentation.

Then's a Python program that does this  Prompt the  stoner to enter three integers one at a time:

num1 =  int( input(" Enter the first integer"))  

num2 =  int( input(" Enter the alternate integer"))  

num3 =  int( input(" Enter the third integer"))  

Determine which integer is the  lowest using nested decision blocks  

if num1< num2  if num1< num3   lowest =  num1   additional   lowest =  num3   additional  if num2< num3   lowest =  num2   additional   lowest =  num3  publish the result  print(" The  lowest integer is",  lowest)

In this program, we first prompt the  stoner to enter three integers one at a time using the input() function and convert them to integers using the int() function. Also, we use nested decision blocks to determine which integer is the  lowest.

Eventually, we  publish the result using the print()function.The program will affair the  lowest integer out of the three integers entered by the  stoner.

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public class MixedResults {

   public static void main(String[] args) {

       Tester test = new Tester();

       test.tester_method();

   }

}

class Tester{

   double d1 = 37.9, d2 = 1004.128;

       int i1 = 12, i2 = 18;

   Tester(){  

   }

   void tester_method(){

       System.out.println(57.2*(i1/i2)+1);

       System.out.println(57.2*((double)i1/i2)+1);

       System.out.println(15 - i1 * ( d1 * 3) + 4);

       System.out.println(15 - i1 * (int)( d1 * 3) + 4);

       System.out.println(15 - i1 * ( (int)d1 * 3) + 4);

   }

}

I think this is what you're looking for. Best of luck.

Answer:

payattention in class

Explanation:

En este ejemplo vemos que, por la información dada, no es posible que esta oración tenga coherencia o sentido. En este caso el nexo o conector que une ambas oraciones no debería haberse utilizado, puesto que ambas oraciones no tienen relación. Por ende corresponden a estructuras diferentes y no es posible que mantengan una coherencia. Varias oraciones sin coherencia, generan textos incoherentes.

Answer:

a

Explanation:

Answer:

by simply just logging on and using the internet.

Explanation:

Answer:

They are left by if you search something or post or even if someone else post something about you it will be online forever.

Explanation:

Answer:

Written in Python

G = 6.673 *pow(10,-11)

M = 5.98 *pow(10,24)

d = float(input("Distance: "))

g = (G * M)/(pow(d,2))

print("Acceleration of gravity: "+str(g))

Explanation:

This line initializes the gravititational constant

G = 6.673 *pow(10,-11)

This line initializes the mass of the earth

M = 5.98 *pow(10,24)

This line prompts user for object distance

d = float(input("Distance: "))

This line calculates the object's gravity

g = (G * M)/(pow(d,2))

This line prints the calculated gravity without approximating

print("Acceleration of gravity: "+str(g))

Answer:

G = 6.673e-11

M = 5.98e24

dist_center = 6.3782e6

accel_gravity = (G*M)/(dist_center * dist_center)

print(accel_gravity)

Explanation:

Answer:

See Explanation

Explanation:

To solve this, I'll skip variable declarations

if (dept == 5 && price >= 100){//1

discount = 0.20;

}

else if (price >= 100){ //2

discount = 0.15;

}

else if (dept == 5 && price < 100){//3

discount = 0.10;

}

else if (price < 100){//4

discount = 0.05;

}

The question requires if conditional statements and that has been shown in the above lines of code

Also, the comments (//) indicates the number of each line and it does exactly what is required.

The  four products that normally requires copyright protection are:​

Books and written literary works need copyright protection to keep the original ideas and writings of authors safe. This stops people from copying, sharing, or making more copies without permission.

Copyright protection is important for music compositions and sound recordings to make sure that composers, songwriters, and performers have power over how their works are used, shared, and performed for the public.

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Answer:

input Devices, Processing Devices, Output Devices, Memory/Storage Devices

Explanation:

Answer:

Web 1.0

Explanation:

Web 1.0 was its terminology used during the World Wide Web to reference to the first period of growth that was characterised by basic static websites. Flat pages: Pages did not provide dynamic functionality that modified depending on the activities of website users. Websites were primarily informative at that time.

Web pages which lacks interactivity such that only contents which have been originally posted remains there and hence do not change characterize the earliest form of web pages called Web 1.0.

Therefore, the earliest form of web pages, Web 1.0 are referred to as being flat or stationary.

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Answer:

Here is the Console class:

import java.util.Scanner;  // to accept input from user

public class Console {   // class name

public Console() {}   //class constructor

public int getInt(Scanner sc, String prompt) { //gets user's number  

int i = 0;   //initialize i to 0

boolean isValid = false;   // checks for valid input

while (!isValid) {   //loop iterates as long as input remains valid

System.out.print(prompt);   //displays prompt

if (sc.hasNextInt()) {   // checks for the next token (input number)

i = sc.nextInt();   // scans and reads the next number

isValid = true;   // checks if input is valid

} else {   //if input is not valid

System.out.println("Error! Invalid integer value. Try again.");  }  //displays error message

sc.nextLine(); // discard any other data entered on the line   }

return i;  }  //returns number

public int getIntWithinRange(Scanner sc, String prompt, //checks users guess if outside parameters or not  

int min, int max) {  

int i = 0;  

boolean isValid = false;   //sets isValid to false

while (!isValid) {   //keeps iterating and stops when isValid is false

i = getInt(sc, prompt);   //calls getInt method to get users number

if (i <= min) {   //if number is less than value of min

System.out.println("Error! Number must be greater than " + min);   //displays this message

} else if (i >= max) {   //if number is greater than that of max

System.out.println("Error! Number must be less than " + max);   //displays this message

} else {   //if guess is right

isValid = true;   } } //sets isValid to true

return i;  } //returns that number

public  String getRequiredString(Scanner sc, String prompt) { //Asks for user's string input  

String s = "";  

boolean isValid = false;   //sets isValid to false

while (!isValid) {      //keeps iterating and stops when isValid is false

System.out.print(prompt);    //displays prompt

s = sc.nextLine();   //reads next line (read next string input value)

if (s.equals("")) {   //if user enters nothing

System.out.println("Error! This entry is required. Try again.");   //display this message

} else {   //if user enters a string input

isValid = true;   }  }  //sets isValid to true

return s; }  //returns string

public  String getChoiceString(Scanner sc, String prompt, //Checks for users input for Y/y ignores caps  

String s1, String s2) {

String s = "";  

boolean isValid = false;   //sets isValid to false

while (!isValid) {   //iterates until isValid is false

s = getRequiredString(sc, prompt);   //calls method to get the input string

if (!s.equalsIgnoreCase(s1) && !s.equalsIgnoreCase(s2)) {  // checks users input for Y/y ignores caps  

System.out.println("Error! Entry must be '" + s1 + "' or '" + s2 + "'. Try again.");   // displays error message that entry must be y or Y

} else {   //if user enters y or Y

isValid = true;   } }   //sets isValid to true

return s;  } } //returns y or Y

Explanation:

Here is the Game class

public class Game {  // class name

public Game() {}   //class constructor

public void displayWelcomeMessage() { //displays message  

System.out.println("Welcome to the Guess the Number Game");  

System.out.println("++++++++++++++++++++++++++++++++++++");  

System.out.println(); }

public  void displayPleaseGuessMessage() { //displays message for user to guess from 1-100  

System.out.println("I'm thinking of a number from 1 to 100.");  

System.out.println("Try to guess it.");  

System.out.println();}

public  void displayCorrectGuessMessage(int counter) { //display user's current guess count

System.out.println("You got it in " + counter + " tries.");  

if (counter <= 3) {   //if user guesses the number in 3 or less tries

System.out.println("Great work! You are a mathematical wizard.\n");  

} else if (counter > 3 && counter <= 7) {   //if user guesses the number greater than 3 but less than or equals to 7 tries

System.out.println("Not too bad! You've got some potential.\n");  

} else {   //if user guesses the number after more than 7 tries

System.out.println("What took you so long? Maybe you should take some lessons.\n"); }}

public  void displayGuessAgainMessage(int number, int guessNumber) { //Asks user to guess again  

int difference = guessNumber - number;  

if (guessNumber > number) {   //if guessNumber is greater than number

if (difference > 10) {   //if difference between guessNumber and number is greater than 10

System.out.println("Way too high! Guess again.\n");   //guessed number is higher than correct one

} else {  

System.out.println("Too high! Guess again.\n");  }

} else {  

if (difference < -10) {   //if difference between guessNumber and number is less than -10

System.out.println("Way to low! Guess again.\n");   //guessed number is lower than correct one

} else {  

System.out.println("Too low! Guess again.\n");}}}}

The main program and explanation of these above programs are given in the attached document.

The output of the program is attached.

Answer:

The following are the answer to the given points:

Explanation:

In point (a):

Calculating the long-distance call cost:

[tex]= 4 \times 5 \times 0.40 \\= 20 \times 0.40\\= 8[/tex]

Calculating the local call cost:

[tex]= 10 \times 3 \times 0.05\\ = 30 \times 0.05\\= 1.5[/tex]

Calculating the overall cost of PSTN:

[tex]= 25 + (4 \times 5 \times 0.40) + (10 \times 3 \times 0.05) + 2000 + 275 \\= 25 + 8 + 1.5 + 2000 + 275 \\= 2309.5[/tex]

In point (b):

Calculating the call rate per second and the average arrival rate:

[tex]\to (\lambda) = 0.2[/tex]

The call average length:

[tex]\to (T_s) = - 8 \\\\ = (8 \times 60) \ seconds \\\\ = 480 \ seconds[/tex]  

The complete agent number:

[tex]\to (m) = 9[/tex]

The strength of traffic:

[tex]\to u = \lambda \times T_s \\\\ = (0.2 \times 480) \\\\ = 96[/tex]    

The occupancy of the agent:

[tex]\to p = \frac{u}{m} \\\\[/tex]

      [tex]= \frac{96}{9} \\ \\= 10.66[/tex]  

Calculation of obtained:

[tex]= \frac{(\frac{um}{m!})}{(\frac{um}{m!})} + (1-p) \sum {m-1} _{k=0} \ \frac{uk}{k!}[/tex]

We get = 0.329 to substitute values.  

In point (c):

The rate of blocking = [tex]5 \%[/tex]

average call time [tex](T_s) = 480 \ seconds[/tex]

                                    [tex]= 0.05 \times 480 \ seconds \\ = 24 \ second[/tex]

In point (d):

Calculating the number of link, which is required:  

[tex]= \frac{275}{5} \\\\ =55[/tex]

In point (e):

Calculating the Line Number:

[tex]= \frac{275}{5} \\\\ =55[/tex]

PSTN line number:

[tex]= (\frac{2000}{55}) \\\\ = 36.3636\\\\= 37[/tex]

In point (f):

The gross design expense = $ 2309. 5