Why was Rutherford's Gold Foil Experiment so important?

a
because of this experiment, Rutherford determined that atoms have positively charged centers

b
it is because of this experiment that we know that atoms do exist

c
because it led to the discovery of subatomic particles

d
because of this experiment, Rutherford determined that electrons move in fixed paths around the nucleus

Answer: Neon is not reactive (full valence shell)

Explanation:

Neon is a noble gas and has a stable structure (8 valence electrons) -therefore, is not very reactive.

Answer:

type of gasoline

Explanation:

Independent variable in an experiment is the variable that the experimenter changes or manipulates in order to bring out a measurable outcome or response.

In this experiment involving how the type of gasoline put in a car affect how fast the car can drive, the independent variable is the TYPE OF GASOLINE because it is what the experimenter changes in order to see it's effect on the speed of the car (dependent variable).

Answer:

Physical weathering is caused by purely mechanical changes to the rock, while chemical weathering is caused by chemical reactions.

Explanation:

Chemical weathering happens when the chemicals get diluted and dissolved in water and seep and percolate down the rock surfaces.

Physical weathering happens when rocks are fragmented into minor fragments while ensuring no alterations in their chemical makeup. The main causes behind physical weathering include spontaneous fluctuations in temperature like too high or too low heat or cold

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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The energy required to break one mole of hydrogen-hydrogen bonds in H2 is 436 kJ/mol divided by Avogadro's number, which is equal to 7.246 x 10-19 J/bond. To calculate the longest wavelength of light, we substitute the values in the formula as given below:  = (6.626 x 10-34 J.s) x (2.998 x 108 m/s) / (7.246 x 10-19 J/bond).The longest wavelength of light with sufficient energy to break a single hydrogen-hydrogen bond is 2.742 x 10-7 m.

To calculate the longest wavelength of light, we will use the formula: Energy of a photon (E) = Planck's constant (h) x speed of light (c) / wavelength (λ)Rearranging the above formula we can get,

λ = hc/E where λ is the wavelength, h is Planck's constant, c is the speed of light, and E is the energy of the photon.

The energy required to break one mole of hydrogen-hydrogen bonds in H2 is 436 kJ/mol.

The energy required to break one bond in H2 is 436 kJ/mol divided by Avogadro's number (6.022 x 1023), which is equal to 7.246 x 10-19 J/bond.

So the energy of the photon required to break a single hydrogen-hydrogen bond is 7.246 x 10-19 J/bond.To calculate the wavelength of this photon, we need to substitute the values in the formula as given below:

λ = (6.626 x 10-34 J.s) x (2.998 x 108 m/s) / (7.246 x 10-19 J/bond)λ

= 2.742 x 10-7 m

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The mass of the trifluoroacetic acid sample is approximately 205.2 g.

Given, a sample of trifluoroacetic acid, C2HF3O2, contains 51.3 g of carbon.To find: The mass of the trifluoroacetic acid sample.Step-by-step explanation:To calculate the mass of the trifluoroacetic acid sample, we need to find the molecular mass of the compound.To find the molecular mass of trifluoroacetic acid, we need to add the atomic masses of all the atoms present in the molecule.C2HF3O2Number of carbon atoms (C) in the compound = 2Number of hydrogen atoms (H) in the compound = 3 Number of fluorine atoms (F) in the compound = 3Number of oxygen atoms (O) in the compound = 2Atomic masses:C = 12.01 g/molH = 1.008 g/molF = 18.998 g/molO = 15.999 g/molNow, let's calculate the molecular mass of trifluoroacetic acid.Molecular mass of trifluoroacetic acid= (2 × 12.01) + (3 × 1.008) + (3 × 18.998) + (2 × 15.999)= 96.02 g/molThus, the molecular mass of trifluoroacetic acid is 96.02 g/mol.Now, we have to find the mass of the sample containing 51.3 g of carbon.Carbon content in the compound = (2 × 12.01)/96.02= 0.250 g/gmoleMass of the sample containing 51.3 g of carbon= (51.3/0.250) gmole= 205.2 g (approx.).

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Cis-acting proteins directly interact with DNA elements, controlling gene expression without the need for nuclear transport. They bind to specific DNA sequences and regulate transcription factors.

Cis-acting elements are DNA sequences that are located near the genes they regulate. These elements contain binding sites for transcription factors, which are proteins that control the transcription of genes. Cis-acting proteins are proteins that bind to these DNA elements and regulate the expression of nearby genes. They can enhance or repress gene expression by influencing the binding of transcription factors and the recruitment of RNA polymerase to the promoter region of a gene.

In contrast, trans-acting factors are proteins or other molecules that are not directly bound to the DNA sequence they regulate. They can diffuse within the cell and interact with cis-acting elements on different DNA molecules. Trans-acting factors include transcription factors, which can bind to specific DNA sequences and regulate gene expression by interacting with the RNA polymerase complex.

Therefore, the correct statement is that cis-acting proteins are DNA elements where transcription factors bind. They act directly on the DNA sequence to regulate gene expression.

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Answer:

atomic structure

Explanation:

Its pretty obvious. Nothing here can test atomic structure. You can test melting point, with a hot plate. You can test the ability to dissolve something with the container of water. You can test brittleness  with the hammer.

Answer:

Atomic Structure

Explanation:

This chemical element has Solids,Gasses, Liquids, and Plasma that are composed from ionized atoms.

The food containing 30 grams of carbohydrates, 10 grams of protein, and 5 grams of fat has a total of 205 calories.

To determine the number of calories in a food containing carbohydrates, proteins, and fats, we need to know the caloric values per gram for each macronutrient. The standard values are:

Carbohydrates: 4 calories per gram

Protein: 4 calories per gram

Fat: 9 calories per gram

Given that the food contains 30 grams of carbohydrates, 10 grams of protein, and 5 grams of fat, we can calculate the total calories from each macronutrient and sum them to find the total caloric content of the food.

Calories from carbohydrates = 30 grams × 4 calories/gram = 120 calories

Calories from protein = 10 grams × 4 calories/gram = 40 calories

Calories from fat = 5 grams × 9 calories/gram = 45 calories

Therefore, the total caloric content of the food is:

Total calories = Calories from carbohydrates + Calories from protein + Calories from fat

Total calories = 120 calories + 40 calories + 45 calories = 205 calories

It's important to note that this calculation assumes the food is pure carbohydrates, protein, and fat, and does not take into account the calories from other components such as fiber or alcohol if present. Additionally, individual foods may have slightly different caloric values depending on their specific composition and processing. Therefore, it's always a good idea to consult nutrition labels or reliable sources for accurate caloric information about specific food products.

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The freezing point of the solution is -11.8 °C.

The boiling point of the solution is 103.31 °C.

To determine the freezing point of the solution, we can use the equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression,

Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),

m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the solution:

Molar mass of ethylene glycol (C2H6O2):

C = 12.01 g/mol

H = 1.01 g/mol (x 6) = 6.06 g/mol

O = 16.00 g/mol (x 2) = 32.00 g/mol

Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol

Number of moles of ethylene glycol (C2H6O2) = mass / molar mass

Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol

Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g

Now, let's calculate the molality:

Molality (m) = moles of solute / mass of solvent (in kg)

Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg

Now we can calculate the freezing point depression (ΔTf):

ΔTf = Kf * m

ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C

To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):

Freezing point = 0 °C - 11.8 °C = -11.8 °C

To determine the boiling point of the solution, we can use the equation:

ΔTb = Kb * m

where:

ΔTb is the boiling point elevation,

Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),

m is the molality of the solution (same value as calculated before: 6.36 mol/kg).

ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C

To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):

Boiling point = 100 °C + 3.31 °C = 103.31 °C

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Answer:

-2 charge

Explanation:

Each electron has a -1 charge so assuming at the was originally neutral, 2 more electrons would give it a -2 charge.

Answer:

[tex]6.5714\text{M}[/tex]

Explanation:

Number of moles of NaCl = 2.3 moles

Volume = 350 mL = [tex]350\times 10^{-3}\ \text{L}=0.35\ \text{L}[/tex]

Molarity is given by

[tex]M=\dfrac{\text{Number of moles of NaCl}}{\text{Volume}}[/tex]

[tex]\Rightarrow M=\dfrac{2.3}{0.35}[/tex]

[tex]\Rightarrow M=6.5714\text{M}[/tex]

Molarity of the solution is [tex]6.5714\text{M}[/tex]

Answer:

lilpeep66661

Explanation:

add me i play

the ligand to coordinate anionic compound of oxalate is known as oxalate. Let's take a closer look at the process of synthesis and analysis of an Iron(III)-Oxalate Complex in Experiment 4.What is Experiment 4?The synthesis and analysis of an Iron(III)-Oxalate Complex is referred to as Experiment 4. This experiment involves the conversion of Fe(III) salt into an Iron(III)-Oxalate complex by a complexation reaction of Fe(III) and Oxalate.

The resulting Iron(III)-Oxalate complex is yellow-green in color. The reaction can be represented by the following chemical equation:Fe+3 + 3C2O4−2 → Fe(C2O4)33−This reaction is an example of a complexation reaction, which involves the formation of coordination compounds from metal ions and complexing agents known as ligands. In this case, the ligand is Oxalate, a bidentate ligand with two binding sites to coordinate to the metal ion. This results in the formation of a stable complex with Fe(III).ConclusionIn summary, the ligand to coordinate anionic compound of oxalate in Experiment 4 is oxalate.

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The process of hydrolyzing the acetamide group of 4-acetamidobenzenesulfonamide can be carried out under acidic conditions without affecting the sulfonamide group, which hydrolyzes much more slowly. Sodium carbonate is used in the final step to isolate sulfanilamide from the acidic hydrolysis solution

The hydrolysis of an amide group in the presence of an acidic environment is a straightforward approach for the synthesis of carboxylic acids and amines. In general, the amide bond is hydrolyzed under acidic conditions, resulting in the breakdown of the molecule into its parent acid and amine. As a result, it is a commonly used process in organic synthesis.For the given compound, 4-acetamidobenzenesulfonamide, the acetamide group is more susceptible to hydrolysis under acidic conditions than the sulfonamide group. This is due to the resonance stabilization of the sulfonamide group.

As a result, under acidic conditions, the acetamide group is hydrolyzed much faster than the sulfonamide group. This is done in order to create the free sulfanilamide.To achieve the free sulfanilamide, the acidic hydrolysis solution is neutralized with sodium carbonate. This is the final step in the process of obtaining sulfanilamide from 4-acetamidobenzenesulfonamide. The acidic hydrolysis solution can be neutralized with any base that is strong enough to deprotonate the acid. Sodium carbonate is a strong enough base to neutralize the solution and isolate the sulfanilamide.The acidic hydrolysis of the acetamide group and the isolation of the sulfanilamide from 4-acetamidobenzenesulfonamide is a useful process in organic synthesis.The acetamide group of 4-acetamidobenzenesulfonamide can be hydrolyzed under acidic conditions without affecting the sulfonamide group, which hydrolyzes much more slowly. Sodium carbonate is used in the final step to isolate sulfanilamide from the acidic hydrolysis solution.

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The molar mass of chromium is 51. 966 gmol , the number of atoms of chromium in 125.8 g is 1.46 × 10²⁴ atoms.

Step 1: Find the number of moles of chromium using the formula:

n = m/M. Where,

m = mass of chromium = 125.8 g

M = molar mass of chromium = 51.966 g/mol

n = 125.8 g/51.966 g/mol = 2.42 mol

Step 2: Find the number of atoms of chromium using Avogadro's number (6.022 × 10²³ atoms/mol).

The formula is: Number of atoms = n × N where N is Avogadro's number. Number of atoms of chromium = 2.42 mol × 6.022 × 10²³ atoms/mol = 1.46 × 10²⁴ atoms (Answer).Therefore, the number of atoms of chromium in 125.8 g is 1.46 × 10²⁴ atoms.

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When 1.8 moles of Fe₂O₃ react with CO, it will produce 3.6 moles of Fe.

The balanced chemical equation for the reaction between Fe₂O₃ and CO is:

Fe₂O₂ + 3CO → 2Fe + 3CO₂

From the balanced equation, we can see that 1 mole of Fe₂O₃ reacts with 3 moles of CO to produce 2 moles of Fe.

Therefore, if 1.8 moles of Fe₂O₃ react, we can determine the number of moles of Fe produced by setting up a ratio:

(1.8 moles Fe₂O₃) x (2 moles Fe / 1 mole Fe₂O₃) = 3.6 moles of Fe

Hence, when 1.8 moles of Fe₂O₃ react with CO, it will produce 3.6 moles of Fe.

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The reaction in the coffee-cup calorimeter is an exothermic reaction.  The water lost a heat of 2799.4 J of heat during the reaction

a. The reaction between HCl and water in the coffee-cup calorimeter is exothermic. This can be determined by comparing the initial and final temperatures of the substances.

The initial temperature of the HCl was higher than the initial temperature of water, indicating that the HCl had more thermal energy.

However, after the reaction, the final temperature of both substances decreased, which means heat was released into the surroundings. Therefore, the reaction is exothermic.

b. To calculate the heat gained or lost by the water, we can use the equation q = mcΔT, where q represents the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

The mass of water is given as 100.0 g, and the specific heat capacity of water is approximately 4.18 J/g·°C. The change in temperature is calculated as (31.3 - 24.6) = 6.7 °C.

Plugging these values into the equation, we get q = (100.0 g)(4.18 J/g·°C)(6.7 °C) = 2799.4 J. Therefore, the water lost 2799.4 J of heat.

In the second part of the question, the total pressure in the 20.0 L flask can be calculated using the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

The total number of moles of gas in the flask is given as 0.400 mol of H2(g) and 0.215 mol of N2(g), which sums up to 0.615 mol. The temperature is given as 293.15 K.

Plugging these values into the equation, we get (P)(20.0) = (0.615)(0.0821)(293.15), which simplifies to P = 0.765 atm. Therefore, the total pressure in the flask is 0.765 atm.

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Answer:

d

Explanation:

The correct answer is option D: all of the above.

Environmental science is a multidisciplinary field of study that encompasses; physical science, biological sciences, social sciences and even aspects of the humanities.

Social sciences like anthropology have a lot of bearing on environmental science.

Physics, chemistry, biology and earth sciences play a key role in understanding important aspects of the natural environment.

Therefore; Physics, chemistry, biology and earth sciences and social sciences are all relevant in environmental science.

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Clean rooms used for sterile biological research are sealed and operate at slightly above atmospheric pressure is a crucial measure to maintain the sterility and integrity of the environment.

Clean rooms in sterile biological research facilities are designed to maintain a controlled and clean environment, free from contaminants that could compromise experiments or the integrity of biological samples. One important aspect of clean rooms is their positive pressure. Operating clean rooms at slightly above atmospheric pressure helps to prevent the ingress of contaminants from the surrounding environment. When a clean room has positive pressure, it means that the air inside the room is at a slightly higher pressure than the air outside. This pressure differential helps to keep the clean air inside the room and creates a barrier that prevents particles and contaminants from infiltrating the space.

By maintaining positive pressure, any leaks or openings in the clean room system will cause air to flow outward rather than inward. This outward flow of air helps to ensure that the clean room remains a controlled environment with filtered and purified air. It reduces the chances of airborne contaminants, such as dust, pollen, microorganisms, or chemicals, from entering the clean room and potentially contaminating sensitive experiments or samples. Positive pressure in clean rooms is achieved by employing specialized ventilation systems, including high-efficiency particulate air (HEPA) filters. These filters remove particles as small as 0.3 micrometers in size, ensuring the cleanliness of the air within the clean room. The positive pressure is maintained by adjusting the airflow and controlling the exhaust systems to balance the air pressure and prevent any unwanted pressure differentials.

Overall, operating clean rooms at slightly above atmospheric pressure is a crucial measure to maintain the sterility and integrity of the environment. It helps to minimize the risk of contamination and ensures that sterile biological research can be conducted under controlled conditions, providing accurate and reliable results.

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Answer:

B

Explanation:

The electrons are placed in 4 sublevels: s, p, d, and f. The sublevels contain orbitals and each orbital can carry maximum 2 electrons.

s is the lowest sublevel having only one orbital and can hold a maximum of 2 electrons; p has 3 orbitals and can carry a maximum of 6 electrons, d has 5 orbitals and can carry a maximum of 10 electrons; and f is the highest orbital having 7 orbitals and can hold maximum 14 electrons.

Hence, B is not one of the four sublevels that electrons can be placed in.

In the experiment, the use of the ammonia/ammonium chloride buffer is crucial. It is important to add enough buffer to reach pH 10 because the buffer will stabilize the pH of the solution.

In this experiment, the ammonia/ammonium chloride buffer is utilized to maintain the pH level of the solution when a base, such as NaOH, is added. The buffer is able to do this because it contains both a weak acid (ammonium ion, NH4+) and its conjugate base (ammonia, NH3).

When a base is added to the solution, it will react with the ammonium ions present in the buffer to produce ammonia, which will then react with any excess base added. By doing so, the buffer can help keep the pH of the solution from becoming too basic. When the pH is too low, the solution can become too acidic, which can have a negative impact on the results of the experiment. Conversely, if the pH is too high, the solution can become too basic, which can also impact the experiment's results. Thus, it is important to add enough ammonia or ammonium chloride buffer to maintain a pH of 10 throughout the experiment.

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Answer:

Option A. 52.00 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 49.946 amu

Abundance (A%) = 4.345%

Isotope B:

Mass of B = 51.941 amu

Abundance (B%) = 83.789%

Isotope C:

Mass of C = 52.941 amu

Abundance (C%) = 9.501%

Isotope D:

Mass of D = 53.939 amu

Abundance (D%) = 2.365%

Average atomic mass =.?

The average atomic mass of the unknown element can be obtained as follow:

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] [(Mass of C × C%)/100] + [(Mass of D × D%)/100]

Average atomic mass = [(49.946 × 4.345)/100] + [(51.941 × 83.789)/100] + [(52.941 × 9.501)/100] + [(53.939 × 2.365)/100]

= 2.170 + 43.521 + 5.029 + 1.276

= 51.996 ≈ 52.00 amu

Therefore, the average atomic mass of the unknown element is 52.00 amu

Answer:

To make a 1 M solution of CaCl2, you need to dilute the stock solution of 3.2 M CaCl2. The equation to use is:

C1V1 = C2V2

where C1 is the concentration of the stock solution (3.2 M), V1 is the volume of the stock solution used, C2 is the concentration of the desired solution (1 M), and V2 is the final volume of the desired solution.

To calculate how much of the stock solution you need to use, you rearrange the equation to get:

V1 = (C2 x V2) / C1

Substituting the values given, we get:

V1 = (1 M x 900 ml) / 3.2 M

V1 = 253.125 ml

Therefore, to make a 1 M solution of CaCl2, you need to measure 253.125 ml of the 3.2 M stock solution and add enough water to make the final volume up to 900 ml.

Given that Koxygen (Henry's Law constant) is 1.3 x 10^-3 mol/L atm, we can calculate the mass of oxygen dissolved in grams.

Henry's Law states that the concentration of a gas dissolved in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's Law is C = K * P, where C is the concentration of the gas, K is the Henry's Law constant, and P is the partial pressure of the gas.

First, let's convert the given partial pressures to atm:

Partial pressure of O2 in lungs (P) = 25 mmHg to 40 mmHg

P = 25 mmHg * (1 atm / 760 mmHg) = 0.0329 atm

P = 40 mmHg * (1 atm / 760 mmHg) = 0.0526 atm

Now, we can calculate the concentration of oxygen using Henry's Law:

C = K * P

Concentration of O2 at 25 mmHg:

C1 = (1.3 x 10^-3 mol/L atm) * (0.0329 atm) = 4.267 x 10^-5 mol/L

Concentration of O2 at 40 mmHg:

C2 = (1.3 x 10^-3 mol/L atm) * (0.0526 atm) = 6.838 x 10^-5 mol/L

To calculate the mass of oxygen dissolved, we need to multiply the concentration by the molar mass of oxygen (32 g/mol) and the volume of water (1.0 L):

Mass of oxygen dissolved at 25 mmHg = (4.267 x 10^-5 mol/L) * (32 g/mol) * (1.0 L) = 0.001366 g

Mass of oxygen dissolved at 40 mmHg = (6.838 x 10^-5 mol/L) * (32 g/mol) * (1.0 L) = 0.002188 g

Therefore, the mass of oxygen that can dissolve in 1.0 L of water at 25°C at a partial pressure ranging from 25 mmHg to 40 mmHg is approximately 0.001366 g to 0.002188 g.

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The sulfate test requires the addition of barium chloride to the unknown solution to precipitate sulfate ions. The supernatant is then tested for chloride ions using silver nitrate, but if chloride ions remain, the next reagent will react with them and give false results.

In the sulfate test (test 3b), the first step is the addition of the barium chloride solution to the unknown solution to precipitate the sulfate ions. The precipitation reaction of sulfate ions and barium chloride solution is:BaCl2 (aq) + SO4^2- (aq) → BaSO4 (s) + 2Cl^-(aq)After the precipitation of sulfate ions, the mixture is centrifuged to separate the precipitate (BaSO4) and supernatant (containing chloride ions). The supernatant is then tested for chloride ions using the silver nitrate solution.The silver nitrate reacts with the chloride ions in the supernatant to form a white precipitate of silver chloride.AgNO3 (aq) + Cl^-(aq) → AgCl (s) + NO3^-(aq)

if chloride ions are still present in the precipitate, the next reagent (silver nitrate) will react with them and give a false-positive result for the presence of sulfate ions. Therefore, it is essential to eliminate chloride ions by washing the precipitate to get accurate results.

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To precipitate all the bromide ions in 35.0 mL of 0.128 M calcium bromide as silver bromide, approximately 21.6 mL of 0.415 M silver nitrate is required.

The balanced chemical equation for the precipitation reaction between silver nitrate (AgNO3) and calcium bromide (CaBr2) is:

2 AgNO3 (aq) + CaBr2 (aq) -> Ca(NO3)2 (aq) + 2 AgBr (s)

According to the stoichiometry of the reaction, 2 moles of silver nitrate react with 1 mole of calcium bromide to form 2 moles of silver bromide. This means that the ratio of silver nitrate to calcium bromide is 2:1.

To determine the volume of silver nitrate required, we can set up a proportion using the molarity and volume of the calcium bromide and silver nitrate solutions:

(0.128 M CaBr2) / (35.0 mL CaBr2) = (0.415 M AgNO3) / (x mL AgNO3)

Solving for x, the volume of silver nitrate, we find that x is approximately 21.6 mL.

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