Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters

Answers

Answer 1
Other clusters with hundreds to thousands of galaxies are called rich clusters. The low mass of a poor cluster prevents the cluster from holding onto its members tightly. The poor cluster tends to be a bit more irregular in shape than a rich cluster. Each large spiral has several smaller galaxies orbiting them.
Answer 2

These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).

What clusters of galaxies likely to have irregular shapes?

In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.

When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.

Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.

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Related Questions

fffffrrrrreeeeee points you can have them!

Answers

Answer:

Thank you so much!

Explanation:

Answer:

joe

Explanation:

mama

Which of the following is true for gravitational force?

Group of answer choices
Decreases with decrease in distance

Increases with increase in distance

Decreases with increase in mass

Increases with increase in mass

Answers

Answer:

The gravitational force b) Increases with increase in mass.

Explanation:

The gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}F=Gr2m1m2

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

From the equation, we notice that:

- The force is proportional to the masses, m1 and m2: so, if the masses increase, the force will increase, and if the masses decrease, the force will decrease

- The force is inversely proportional to the distance between the masses, r: so, if the distance increases,  the force will decreases, and if the distance decreases , the force will increases

Therefore, the correct options is only:

Increases with increase in mass

Answer: The answer is b increases in increase of mass because the heavier the object is the more gravitional pull it will have.

Explanation: Which of the following is true for gravitational force?

Group of answer choices

Decreases with decrease in distance

Increases with increase in distance

Decreases with increase in mass

Increases with increase in mass

Read the picture, please. I am a bit confused about what it means when it says which one supports it.

Answers

Answer:

not suppoted

not supported

support

A father places his daughter in a swing that is 0.60\,\text{m}0.60m0, point, 60, start text, m, end text above ground. Then he raises the swing to a height of 1.3\,\text{m}1.3m1, point, 3, start text, m, end text and lets go. The girl and the swing have a combined mass of 14\,\text{kg}14kg14, start text, k, g, end text. Assume friction is negligible and use g = 9.8\,\text{m/s}^2g=9.8m/s
2
g, equals, 9, point, 8, start text, m, slash, s, end text, squared.
Calculate the girl’s fastest speed.

Answers

This question involves the concepts of the law of conservation of energy and kinetic energy.

The girl's fastest speed is "3.7 m/s".

According to the law of conservation of energy, the girl will have the fastest speed at mean position, which will be calculated as follows:

Loss in Potential Energy = Gain in Kinetic Energy

[tex]mg\Delta h=\frac{1}{2}mv^2\\\\v=\sqrt{2g\Delta h}[/tex]

where,

v = maximum speed = ?

g = acceleration due to gravity = 9.81 m/s²

Δh = change in height = 1.3 m - 0.6 m = 0.7 m

Therefore,

[tex]v=\sqrt{2(9.81\ m/s^2)(0.7\ m)}[/tex]

v = 3.7 m/s

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pls help quickly

Which of these materials best scatters the light that strikes it?
a pure water
b shiny mirror
c frosted glass
d eyeglass lens

Answers

Answer: frosted glass

Explanation:

Answer:

C

Explanation:

Frosted Glass

Part A
As an object moves around, on which quantities does the change in its gravitational potential energy depend? Choose all that
apply.

Answers

As expressed by the equation, potential energy depends upon the mass and the height of the object. Any increase in these two quantities will lead to an increase in the amount of potential energy possessed by the object.

A seashell is suspended in the air at rest by two strands of spider silk. Each strand of silk makes an angle of 75 degrees above the horizontal, and experiences a tension of 1.42 N.

What is the mass of the seashell?

Answers

The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

The given parameters:

Tension on each strand of silk, T = 1.42 NAngle of inclination of each strand, θ = 75⁰

The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

[tex]\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0[/tex]

where;

W is the weight of the seashell

The weight of the seashell is calculated as;

[tex]1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N[/tex]

The mass of the seashell is calculated as follows;

[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg[/tex]

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

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Answers

What happened the thing is kinda glitched

what is volume help plz

Answers

Answer:

Explanation:

Volume = Length x width x height

Multiply the length, width and, height to get the volume of the question.

define the unit of work​

Answers

[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]

1. A student adds water and sugar to a jar and seals the jar so that nothing can get in or out. The
student then finds the mass of the jar containing the water and sugar. After some sugar dissolves, the
student finds the mass of the jar and its contents again.
Water
Sugar
and
Water
Sugar
Sugar
Before
After
Vhat will happen to the mass of the jar containing the water and sugar after some of the sugar
issolves?
a. The mass will stay the same
b. The mass will increase
c. The mass will decrease
The moon will donend on how much sunar dissolves

Answers

Answer:

The mass will stay the same throughout time

Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
All rights reserved

Answers

The order of the location of each process in the carbon cycle are as follows;

Ingestion → Decomposition → Fossilization → Combustion

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?

A. F2

B. 1/2F

C. 0.1F

D. 2F/5

E. 5F

J. 10F

Please help will mark brainliest

Answers

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

Hi there!

Using Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]

Fg = Force of gravity (N)

G = Gravitational Constant

m₁ = mass of object 1 (kg)

m₂ = mass of object 2 (kg)

d = distance between the objects (m)

There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:

[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]

Thus, the correct answer is J. 10Fg.

electromagnetic radiation at its maximum wavelength is:

Answers

Answer:

the radio wave. - The frequency ranges between 300 gigahertz (GHz) to 30 hertz (Hz).

Explanation:

A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.

Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.

A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is

A. 1350 J

B. 8820 J

C. 4410 J

D. 0 J

and his velocity is

E. 4.5 m/s

F. 0 m/s

G. 3.2 m/s

H. 9.9 m/s

Please help will mark brainliest

Answers

Mass of the diver (m) = 90 Kg.Height of the board from the ground (h) = 10 m.Acceleration due to gravity (g) = 9.8 m/s^2.Height of the diver from the ground when he reaches point C (x) = 5mInitial velocity (u) = 0 m/sWe know, gravitational potential energy of a body = mass × acceleration due to gravity × height.Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)or, GPE = [90 × 9.8 × (10-5)] Jor, GPE = [90 × 9.8 × 5] Jor, GPE = 4410 JFor a freely falling body,v^2 - u^2 = 2ghor, v^2 = 2ghWe know, kinetic energy of a body = 1/2 mv^2Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2We have already seen v^2 = 2gh or, v = √2ghSo, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s

Answers:

The gravitational potential energy of the diver when he reaches point C is 4410 J.

The velocity of the diver is 9.9 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

h=10m-5m=5mm=90Kgg=9.8m/s^2

[tex]\\ \sf\longmapsto PE=mgh[/tex]

[tex]\\ \sf\longmapsto PE=90(5)(9.8)[/tex]

[tex]\\ \sf\longmapsto PE=4410J[/tex]

Now

It's converted to kinetic energy while reaching ground.

[tex]\\ \sf\longmapsto K.E=4410[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410[/tex]

[tex]\\ \sf\longmapsto 90v^2=8820[/tex]

[tex]\\ \sf\longmapsto v^2=98[/tex]

[tex]\\ \sf\longmapsto v=9.9m/s[/tex]

The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)​

Answers

Answer:

F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2

F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons

F = 3.53E22 N

i do believe that i need help

Answers

WHAT IS THAT omg Helpppp

Mass can be measured with a triple
beam balance in units of
Resources
A. grams
B. Newtons
C. cubic centimeters
D. millimeters

Answers

Answer:

A

Explanation:

How charged objects can affect other objects without touching them. ?

Answers

By gravity as well as electrostatic and magnetic attraction and repulsion
Example forces being exerted by one object on another without them being in contact with each other

Jeremiah rides his bicycle 4 miles in 30 minutes. If he maintains this rate, how far will he ride in 3 hours?

Answers

Answer:

24 miles.

Explanation:

3 hours=180 minutes

180÷30=6

6x4=24

Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)

Answers

Answer:

mass= 20kg

g=10m/s2

weight is F=mg

F=20×10

F=200N

A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?

Answers

The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 N

The net force on the pail of water at the top of the vertical circle is calculated as follows;

[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

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NEES HELP!!!!
Which of the following is "NOT" a theory of the formation of the universe?
A. Steady State Theory
B. Doppler Theory
C. Oscillating Theory
D. Big Bang Theory

Answers

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

A loaded truck collides with a car causing huge damage to the car. Which of the following is true about the collision? *

A. The force on the truck is greater than the force on the car
B. The force on the car is greater than the force on the truck
C. The force on the truck is the same in magnitude as the force on the car
D. During the collision the truck makes greater displacement than the car
E. During the collision the truck has greater acceleration than the car

Answers

The force on the truck is the same in magnitude as the force on the car.

The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.

J = Ft

where;

J is the impulse experienced by the objectt is the time

The increase in the force applied to an object causes an increase in the impulse experienced by the object.

Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.

Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.

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Give 4 facts about the alkali metals

Answers

Answer:

there very old

Explanation:

please help answer the question in the image!!!

Answers

Answer:

  C (only)

Explanation:

Often, we consider the 0 position on a graph like this to be the starting point. However, the position on this graph is indicated as positive at time = 0. The motion shown can be described in each stage as follows.

A: moving away from the starting position toward the reference position (position = 0)

B: stationary at the reference position

C: moving away from the reference position toward the starting position

D: stationary at a point just short of the starting position

E: moving away from the starting position toward, then beyond, the reference position

The solar mass of the Sun is 1. The orbital period of Jupiter is 11. 9 Earth years. What is the distance between Jupiter and the Sun? 5. 2 AU 41 AU 52 AU 410 AU.

Answers

The distance between Jupiter and the sun is 5.2 AU.

According to Kepler's third law, the square of the period of revolution of planets is proportional to the cube of their mean distances from the sun. From this; T^2 = r^3.

Now, we are told that the orbital period (T) is 11. 9 Earth years. We have to make the distance the subject of the formula.

r =T^2/3

r = (11.9)^2/3

r = 5.2 AU

Learn more: https://brainly.com/question/15207516

Answer:

The answer is A. 5.2 AU

Explanation:

in jus dat ni ni fr

PLEASE HELP!! 10 points!!!! brainliest!!!
Why is a sound wave considered to be a mechanical wave? What properties of sound
waves are responsible for pitch and volume

Answers

Answer:

Mechanical Sound Waves - A sound wave moves through air by displacing air particles in a chain reaction. ... Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave. For pitch the higher the frequency, the higher the pitch. Frequency is measured in hertz, or cycles per second. Frequency also affects loudness, with higher-pitched sounds being perceived as louder. Amplitude and frequency of sound waves interact to produce the experiences of loudness and pitch.

Mechanical Sound Waves - A sound wave moves through air by displacing air particles in a chain reaction. ... Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave. For pitch the higher the frequency, the higher the pitch. Frequency is measured in hertz, or cycles per second. Frequency also affects loudness, with higher-pitched sounds being perceived as louder. Amplitude and frequency of sound waves interact to produce the experiences of loudness and pitch.

A moving car hits the breaks and starts to slow down. The car was moving 35 m/s when hitting the breaks and slows at a rate of 7 m/s/s. What is the final velocity of the car after 4 seconds?

Answers

7 miles per second.

It would take 5 seconds to stop because 35 divided by 7 = 5.

It would slow 28 miles in 4 seconds because 7 x 4 = 28.

35 - 28 = 7.

AB
ca
The trough of a transverse wave is BEST shown by choice
es - )
8
8

Answers

Answer:

bro the way you worded it makes no since

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