how do I convert 0.063 m to centimeters
Answer:
6.3
Explanation:
multiply the length value by 100
please mark me as brainly listURGENT!! WILL MARK ANYONE WITH ALL ANSWERS AS BRAINLIEST!!!
Answer:
1) 9 moles
2) 8.75 moles
3) 1.76 moles
4) 10.2 moles
Explanation:
Okay so mole ratio is 2:1
So, 9 moles of HI is required for 4.5 moles of Iodine gas
Mol ratio of water to CaCl2 is 2:1
So, 17.5 moles of water produced is (17.5/2) moles of CaCl2 i.e. 8.75 moles
Okay so mol ratio of Hydrogen to NH3 is 3:2
So, 2.64 moles of hydrogen is (2.64 * 2)/3 moles of NH3 i.e. 1.76 moles
Once again, mol ratio of Hydrogen to NH3 is 3:2
When 15.3 moles of hydrogen is used, (15.3 * 2)/3 moles of NH3 i.e. 10.2 moles
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Determine the molarity (M) of 0.2074 g of calcium hydroxide, Ca(OH)₂ (74.09 g/mol), in 40.00 mL of solution.
Answer:
M=0.06998 mol/L
Explanation:
A tapeworm is an organism that may live in the intestines of an animal. When the animal eats, the tapeworm feeds upon the nutrients of the ingested food. This relationship between the tapeworm and the animal is an example of _______.
A.
predation
B.
commensalism
C.
mutualism
D.
parasitism
Answer:
D
Explanation:
It is parasitism because only the tapwworm benefits from the host
What is the value of Ksp for Ag2SO4 if 5.40g is soluble in 1.00 L of water?
The expression for the equilibrium constant is Ksp (= [Ag+][I-] = (x)(x) = x2. Step 3: Use the solubility of AgI to calculate the molar solubility. At 100oC, silver sulphate dissolves in water at a rate of around 1. 4 grams per mL.
How should a Ksp equation be written?The equilibrium formula, Ksp, can be expressed as Ksp (= [products]/[reactants] and represents a ratio of products to reactants. Equilibrium balance between a cationic solid as well as its solution's ions is shown by this statement.
What is the Ksp equivalent of solubility?The greater a substance's K s p chemical value, the more soluble it is. What exactly are K sandeep units. In actuality, it lacks a unit! Since the molar quantities of the products and reactants vary for each equation, the K s p value lacks units.
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whats the answer and why?
I would say C
Since the nitro group (NO2) contains a positively charged nitrogen atom, it tends to attract electron from the aromatic ring and, therefore, the other group/atom. In the first case, I think piridine (II) makes a stronger bond with water since the nitrogen in the aromatic ring needs its electrons in order to be have a slight negative charge that can interact with the slightly positive charged hydrogen atom in water. If the nitro group is present, it will attract to some extent the electrons of the nitrogen atom in the ring, thus making the H-bond less stronger.
In the second case the hydrogen, which is slightly positive, of the OH group interacts with the oxygen, which is slightly negative, of water. If the nitro group is present, it will attract the electrons of oxygen of the hydroxyl group, therefore making the bond between the oxygen and the hydrogen more polar (which basically means that the bonding electron of hydrogen is even more attracted by the oxygen atom) making the hydrogen atom more positive, which means that the H-bond will be stronger
How many moles is 3.4 g of HCI?
3.4 g of HCl is therefore equivalent to roughly 0.0932 moles of HCl.
What is the HCI's mole count?Since each molecule of HCl contains one mole of hydrogen and one mole of chlorine, the mole quantity of HCl equals the mole quantity of hydrogen and chlorine in the sample.
Approximately 36.46 g/mol is the molar mass of hydrochloric acid (HCl). We must divide the mass by the molar mass to determine the number of moles of HCl in 3.4 g of HCl:
Mass of HCl / molar mass of HCl equals moles of HCl.
3.4 grams per 36.46 grams per mole of HCl
A mole of HCl is equal to 0.0932 mol.
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Use the periodic table to select the element from the drop-down menu that has the correct relative electronegativity.
yo its been 3 minutes where my answer at
Mg>
P>
C >
Br>
The correct answer based on relative electronegativity would be:
Br > P > C > Mg
What is Electronegativity?
Electronegativity is a measure of an element's tendency to attract a bonding pair of electrons towards itself when it forms a chemical bond with another element. It is a property of elements that reflects their ability to attract and hold onto electrons in a chemical bond.
Electronegativity is a measure of an element's tendency to attract a bonding pair of electrons. In general, electronegativity increases from left to right across a period in the periodic table and decreases from top to bottom within a group. Therefore, Bromine (Br) would have the highest electronegativity among the given options, followed by Phosphorus (P), Carbon (C), and Magnesium (Mg) with the lowest electronegativity.
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Which amount of sodium hydroxide is would react exactly with 7.5g of a diprotic acid,H2A(Mr = 150)?
0.1 mol of sodium hydroxide (NaOH) would react exactly with 7.5 g of the diprotic acid [tex]H_{2}[/tex]A.
What is Molar Mass?
Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or the formula mass of all the ions in an ionic compound.
The balanced chemical equation for the reaction between diprotic acid, [tex]H_{2}[/tex]A, and sodium hydroxide, NaOH, can be represented as follows:
2[tex]H_{2}[/tex]A + 2 NaOH -> [tex]Na_{2}[/tex]A + 2 [tex]H_{2}[/tex]O
From the balanced equation, we can see that 2 moles of [tex]H_{2}[/tex]A react with 2 moles of NaOH to produce 1 mole of [tex]Na_{2}[/tex]A and 2 moles of water ([tex]H_{2}[/tex]O).
First, we need to calculate the number of moles of [tex]H_{2}[/tex]A in 7.5g using the formula:
moles = mass / molar mass
moles of [tex]H_{2}[/tex]A = 7.5g / 150 g/mol = 0.05 mol
Since diprotic acid, [tex]H_{2}[/tex]A, reacts in a 1:2 ratio with NaOH, we need to multiply the moles of [tex]H_{2}[/tex]A by 2 to determine the moles of NaOH required for complete reaction:
Moles of NaOH = 2 * Moles of [tex]H_{2}[/tex]A
Moles of NaOH = 2 * 0.05 mol
Moles of NaOH = 0.1 mol
0.1 mol of sodium hydroxide (NaOH) would react exactly with 7.5 g of the diprotic acid [tex]H_{2}[/tex]A.
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HELP PLEASE
In what ways is the lewis structure misleading regarding is charge distribution (near left) and when attempting to describe the bonding in this molecule using valence bond theory? How could you use hyperconjugation and donor/accepter interactions to better describe the bonding in the molecule?
The Lewis structure of SNF3 is misleading because it does not accurately represent the charge distribution in the molecule.
What is the Lewis structure of the molecule?
The Lewis structure of SNF3 shows that sulfur (S) is the central atom with three fluorine (F) atoms bonded to it and one lone pair of electrons. The Lewis structure suggests that each F atom is bonded to S with a single bond, and that S has a formal charge of +1.
In reality, the S atom in SNF3 has a trigonal pyramidal shape with a net dipole moment. This means that the electron density is not evenly distributed throughout the molecule. The electronegativity of F atoms is higher than that of S, so the F atoms pull electron density away from S, making it slightly positive and the F atoms slightly negative. This creates a partial negative charge on the F atoms and a partial positive charge on the S atom.
When attempting to describe the bonding in SNF3 using valence bond theory, the Lewis structure does not give an accurate representation of the actual bonding. In valence bond theory, the bonding in SNF3 is described as sp3 hybridization of the S atom and overlap of the hybrid orbitals with the 2p orbitals of the F atoms to form four sp3 hybrid orbitals.
Hyperconjugation and donor/acceptor interactions can be used to better describe the bonding in SNF3. Hyperconjugation involves the delocalization of electrons from a sigma bond to an empty or partially filled antibonding orbital. In SNF3, hyperconjugation can occur between the S-F bonds and the S lone pair, which can increase the strength of the S-F bonds.
Donor/acceptor interactions occur when there is overlap between the filled orbital of a donor atom and the empty or partially filled orbital of an acceptor atom. In SNF3, the S lone pair acts as a donor to the empty 3d orbital of F atoms, creating a weak dative bond.
Overall, the charge distribution in SNF3 is better described as a partially negative charge on the F atoms and a partially positive charge on the S atom, rather than the formal charge shown in the Lewis structure. Using hyperconjugation and donor/acceptor interactions can provide a more accurate description of the bonding in the molecule.
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A 2.6 mol sample of N2 is held in a 4191 mL balloon at 89.9 atm. What temperature (in Celcius) is the gas at? Answer to one decimal place.
To convert to Celsius, we subtract 273.15 from the Kelvin temperature, giving us a final answer of 42.1°C.
What is temperature?Temperature is a physical quantity that measures the average kinetic energy of the particles in a system. It is an important parameter for understanding the behavior of matter and the underlying physical processes at work. Temperature is measured in units such as degrees Celsius (°C), Fahrenheit (°F), Kelvin (K), or Rankine (°R). Temperature affects the rate at which chemical reactions occur and the movement of particles in solids, liquids, and gases.
The ideal gas law states that PV = nRT,
where n is the number of moles,
P is the pressure,
V is the volume, R is the ideal gas constant (8.314 J/molK), and
T is the temperature in Kelvin.
Rearranging the equation, we get T = (PV)/(nR).
Plugging in our values, we get T = (89.9 atm * 4191 mL)/(2.6 mol * 8.314 J/molK) = 115.2 K.
To convert to Celsius, we subtract 273.15 from the Kelvin temperature, giving us a final answer of 42.1°C.
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At 25 ∘C
, the equilibrium partial pressures for the reaction
A(g)+2B(g)↽−−⇀C(g)+D(g)
were found to be A=5.63
atm, B=5.00
atm, C=5.47
atm, and D=5.63
atm.
What is the standard change in Gibbs free energy of this reaction at 25 ∘C
?
The standard change in Gibbs free energy of the reaction at 25 ∘C is -1.69 kJ/mol.
What is standard change?
To find the standard change in Gibbs free energy of the reaction, we need to use the following equation:
ΔG° = -RT ln(K)
where ΔG° is the standard change in Gibbs free energy, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25 °C = 298 K), and K is the equilibrium constant.
To find K, we need to use the equilibrium partial pressures:
K = (PC × PD) / (PA × PB²)
where PA, PB, PC, and PD are the equilibrium partial pressures of A, B, C, and D, respectively.
Substituting the values, we get:
K = (5.47 atm × 5.63 atm) / (5.63 atm × (5.00 atm)²)
K = 0.6176
Now we can calculate the standard change in Gibbs free energy:
ΔG° = -RT ln(K)
ΔG° = -(8.314 J/mol·K) × (298 K) × ln(0.6176)
ΔG° = -1,690 J/mol or -1.69 kJ/mol
Therefore, the standard change in Gibbs free energy of the reaction at 25 ∘C is -1.69 kJ/mol.
What is free energy?
Free energy, also known as Gibbs free energy, is a thermodynamic quantity that represents the amount of energy in a system that is available to do work at a constant temperature and pressure. It is denoted by the symbol G and is expressed in units of joules (J) or calories (cal).
In simple terms, free energy is the energy that can be used to do work. It is defined by the equation:
ΔG = ΔH - TΔS
where ΔH is the change in enthalpy (heat content) of the system, ΔS is the change in entropy (disorder) of the system, and T is the absolute temperature in Kelvin.
If ΔG is negative, the reaction is spontaneous and can proceed without the input of external energy. If ΔG is positive, the reaction is non-spontaneous and requires energy input to proceed. If ΔG is zero, the system is at equilibrium.
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40 grams of KCI are dissolved in 100 mL of water at 45C. How many additional grams of KCI are needed to make the solution saturated at 80 C?
According to the question 32 g of KCI are needed to make the solution saturated at 80 C
What is solution saturated?Solution saturated is a term used to describe a solution that has reached its maximum solute concentration and can no longer dissolve any more solute. This occurs when the number of solute particles in the solution is equal to the number of solvent molecules. When the solution is saturated, any additional solute added to it will simply form a precipitate or settle out of the solution.
At 80°C, the saturation point of KCl is approximately 132 g/L, so in order to make the solution saturated, you need to add an additional 32 g of KCl. To calculate this, you can use the following equation:
(Saturation concentration at 80°C - Initial concentration at 45°C) x Volume = Additional grams of KCl
(132 g/L - 40 g/L) x 100 mL = 32 g.
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How much energy is involved when 100g of water is heated from 35°C to 115°C water vapor?
252,212 Joules of energy are required to heat 100g of water from 35°C to 115°C water vapor.
To calculate the amount of energy required to heat water from 35°C to 100°C, we use the specific heat capacity of water, which is 4.18 J/(g°C). This means that it takes 4.18 Joules of energy to heat one gram of water by one degree Celsius.
So, the energy required to heat 100 g of water from 35°C to 100°C can be calculated as follows:
Q1 = m × c × ΔT
Q1 = 100 g × 4.18 J/(g°C) × (100°C - 35°C)
Q1 = 26,212 Joules
Next, we need to calculate the amount of energy required to vaporize the water at 100°C. This is done using the heat of vaporization of water, which is 2260 J/g.
So, the energy required to vaporize 100 g of water at 100°C is:
Q2 = m × Lv
Q2 = 100 g × 2260 J/g
Q2 = 226,000 Joules
Therefore, the total energy required to heat 100 g of water from 35°C to 115°C water vapor is:
Q = Q1 + Q2
Q = 26,212 Joules + 226,000 Joules
Q = 252,212 Joules
Thus, 252,212 Joules of energy are required to heat 100g of water from 35°C to 115°C water vapor.
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the rate constant for a specific reaction has been determined at the following temps. 82 C, k= 3.97x10^-3 M^-1 x s^-1 , 125 C, k= 2.07x10^-2 ,M^-1 x s^-1. a) calculate the activation energy for the reaction
b) If data points were plotted in Arrhenius plot, what would the slope of the line be?
c) at what temp will the rate constant have k=1.00x10^-3 M^-1 x s^-1
A) the activation energy is = 66.5 kJ/mol
B) the slope of the line in this case would be -8000 K^-1
C) the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1 is 408 K (135°C).
The activation energy, slope and temperaturea) To calculate the activation energy, we can use the Arrhenius equation:
k = Ae^(-Ea/RT)
where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol x K), and T is the temperature in Kelvin.
Taking the natural logarithm of both sides of the equation, we get:
ln(k) = ln(A) - (Ea/RT)
We can use the two sets of data to set up two equations:
ln(k1) = ln(A) - (Ea/RT1)
ln(k2) = ln(A) - (Ea/RT2)
Solving for Ea by taking the difference between the two equations:
ln(k2/k1) = (Ea/R) [(1/T1) - (1/T2)]
Ea = -R ln(k2/k1) / [(1/T1) - (1/T2)]
Plugging in the values:
Ea = -8.314 J/mol x K x ln(2.07x10^-2 / 3.97x10^-3) / [(1/398 K) - (1/398 K)]
Ea = 66.5 kJ/mol
b) In an Arrhenius plot, ln(k) is plotted against 1/T, and the slope of the line is equal to -Ea/R. Therefore, the slope of the line in this case would be:
slope = -Ea/R = -(66.5 x 10^3 J/mol) / (8.314 J/mol x K) = -8000 K^-1
c) To solve for the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1, we can rearrange the Arrhenius equation:
k = Ae^(-Ea/RT)
ln(k) = ln(A) - (Ea/RT)
1/T = (ln(k) - ln(A)) / (-Ea/R)
T = -R / (Ea ln(k) - ln(A))
Plugging in the values:
T = -8.314 J/mol x K / [(66.5 x 10^3 J/mol) ln(1.00x10^-3) - ln(3.97x10^-3)]
T = 408 K
Therefore, the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1 is 408 K (135°C).
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Balance the following equation:
NHa(g) + F2(g) - NaF4(g) + HF(g)
a. How many moles of each reactant are needed to produce 4.00 moles of HF?
b. How many grams of F2 are required to react with 1.50 moles of NH;?
c. How many grams of N2F4 can be produced when 3.40 grams of NHs reacts?
Answer:NH3: 4.00 moles
F2: 4.00 moles
Explanation:The balanced equation for the given chemical reaction is:
NH3(g) + F2(g) → NF3(g) + HF(g)
According to the balanced equation, 1 mole of NH3 reacts with 1 mole of F2 to produce 1 mole of NF3 and 1 mole of HF.
To produce 4.00 moles of HF, we need to determine how many moles of NH3 and F2 are required. Since the mole ratio between NH3 and HF is 1:1, we would need 4.00 moles of NH3. Similarly, since the mole ratio between F2 and HF is also 1:1, we would need 4.00 moles of F2 as well.
So, the answer is:
NH3: 4.00 moles
F2: 4.00 moles
A mixture of 80.0 g of chromium(III) oxide (Cr2O3) and 8.00 g of carbon (C) is used t produce elemental chromium (Cr) by the reaction Cr2O3 + 3 C 2 Cr+3 CO (a) What is the theoretical yield of Cr that can be obtained from the reaction mixture! (b) The actual yield is 21.7 g Cr. What is the percent yield for the reaction?
Here's a more detailed step-by-step calculation for the theoretical yield and percent yield of chromium (Cr) in the given reaction:
Given: Mass of chromium(III) oxide (Cr2O3) = 80.0 g Mass of carbon (C) = 8.00 g Actual yield of Cr = 21.7 g
Step 1: Calculate the molar mass of Cr2O3 and C. Molar mass of Cr2O3 = 2 x (51.996 g/mol) + 3 x (15.999 g/mol) = 151.996 g/mol Molar mass of C = 12.011 g/mol
Step 2: Convert the masses of Cr2O3 and C to moles. Moles of Cr2O3 = Mass of Cr2O3 / Molar mass of Cr2O3 = 80.0 g / 151.996 g/mol = 0.527 mol (rounded to three decimal places)
Moles of C = Mass of C / Molar mass of C = 8.00 g / 12.011 g/mol = 0.666 mol (rounded to three decimal places)
Step 3: Determine the limiting reactant. The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed. In this case, we compare the moles of Cr2O3 and C to see which one is limiting.
From the balanced equation: Cr2O3 + 3C -> 2Cr + 3CO
We can see that 1 mol of Cr2O3 requires 3 moles of C to react completely and produce 2 moles of Cr. Therefore, the limiting reactant is C, as we have 0.666 mol of C, which is less than the 0.527 mol of Cr2O3.
Step 4: Calculate the theoretical yield of Cr. The theoretical yield of Cr is the maximum amount of Cr that can be obtained based on the limiting reactant.
Moles of limiting reactant (C) = 0.666 mol Molar mass of Cr = 51.996 g/mol
Theoretical yield of Cr = Moles of limiting reactant (C) x Molar mass of Cr = 0.666 mol x 51.996 g/mol = 34.65 g (rounded to two decimal places)
Step 5: Calculate the percent yield of Cr. The percent yield is a measure of how much of the theoretical yield was actually obtained.
Actual yield of Cr = 21.7 g Theoretical yield of Cr = 34.65 g
Percent yield = (Actual yield / Theoretical yield) x 100% = (21.7 g / 34.65 g) x 100% = 62.7% (rounded to three significant figures)
Therefore, the percent yield for the reaction is approximately 62.7%.
if only 11.00g SnF2 were produced calculate percent yield
A. The mass (in grams) of SnF₂ that can be produced theoretically from the reaction is 13.20 g
B. The percentage yield of the reaction is 83.3%
A. How do i determine the mass produced theoretically?The mass of SnF₂ produced theorethically, can be obtained as shown below:
Sn + 2HF -> SnF₂ + H₂
Molar mass of Sn = 118.71 g/molMass of Sn from the balanced equation = 1 × 118.71 = 118.71 g Molar mass of SnF₂ = 156.71 g/molMass of SnF₂ from the balanced equation = 1 × 156.71 = 156.71 gFrom the balanced equation above,
118.71 g of Sn reacted to produce 156.71 g of SnF₂
Therefore,
10 g of Sn will react to produce = (10 × 156.71) / 118.71 = 13.20 g of SnF₂
Thus, the mass of SnF₂ produced is 13.20 g
B. How do i determine the percentage yield?The percentage yield for the reaction can be obtained as follow:
Actual yield of SnF₂ = 11 gTheoretical yield of SnF₂ = 13.20 gPercentage yield of SnF₂ =?Percentage yield = (Actual /Theoretical) × 100
Percentage yield of SnF₂ = (11 / 13.20) × 100
Percentage yield of SnF₂ = 83.3%
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Complete question:
See attached photo
4FeS(s)+7O2(g)→2Fe2O3(s)+4SO2(g)
Due to the presence of FeS(s) as an impurity, the combustion of some types of coal results in the formation of SO2(g), as represented by the equation above. Also, SO2(g) can react with O3(g) to form SO3(g), as represented by the equation below.
SO2(g)+O3(g)⇄SO3(g)+O2(g)
∆H∘298=−242kJ/molrxn;∆S∘298=−25J/(K⋅molrxn)
Question
Which of the following is most likely to be true about the reaction between SO2(g)
and O3(g) at 298 K?
a) ΔG°<0 and TΔS∘ is smaller in magnitude than ΔH∘
b) ΔG°<0 and TΔS∘ is larger in magnitude than ΔH∘
c) ΔG°>0 and TΔS∘is smaller in magnitude than ΔH∘
d) ΔG°>0 and TΔS∘ is larger in magnitude than ΔH∘
To determine the answer, we need to calculate the standard free energy change of the reaction using the equation ΔG° = -234.55 kJ/mol.
What is an enthalpy ?Enthalpy is a thermodynamic property of a system that expresses the heat energy involved in a process, as well as the work that may be done at a constant pressure. It is represented by the symbol "H" and is usually measured in units of Joules or Calories.
Enthalpy change (ΔH) is often used to describe the difference between the enthalpy of the reactants and the products in a chemical reaction. It can be either positive endothermic or negative exothermic, depending on whether heat is absorbed or released during the reaction.
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The diagram below illustrates that the mass of an atom of element X is equivalent to the total mass of 7 hydrogen atoms. X H H H H H H X H 14
The total mass of protons and neutrons makes up an element's atomic mass. Lithium is the element X; it has a mass of 6.941 u.
What is element?When an atom has the same number of protons in its atomic nucleus, it is said to be an element. The number of protons in the nucleus of each element's atoms, or atomic number, serves as the element's sole means of identification.
Seven hydrogen atoms will weigh 7.056 g as each hydrogen atom has an atomic mass of 1.008. The periodic chart shows that an atomic mass of 7.056 g is the one that is closest to that of a lithium atom (6.941 u).
Seven hydrogen atoms have a mass comparable to one lithium atom in the periodic table, based on their mass. With an atomic mass of 6.941 g/mol, the lithium atom bears the atomic number 3.
Lithium is the name of element X.
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At what temperature do saturated solutions of potassium nitrate (KNO3) and sodium nitrate (NaNO3) contain the same weight of solute per 100 mL of water?
At 40°C is the temperature at which saturated solutions of potassium nitrate and sodium nitrate contain the same weight of solute per 100 mL of water contain the same weight of solute per 100 mL of water.
Temperature is a unit of warmth or coldness that can be defined in the context of any number of arbitrary scales. It indicates the direction that heat energy will naturally flow, i.e., through a hotter (body) to a colder (body) body.
Temperature is not the same as the energy in a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at an extremely high temperature. At 40°C is the temperature at which saturated solutions of potassium nitrate and sodium nitrate contain the same weight of solute per 100 mL of water.
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Question
In which of the following processes will ΔS°
be negative?
a) C2H5OH(l)→C2H5OH(g)
b) NaCl(s)→NaCl(l)
c) CO2(s)→CO2(g)
d) Cl2(g)→Cl2(l)
Cl2(g)→Cl2(l): ∆S° will be negative because the disordered gas is converted to the ordered liquid. Therefore, option (D) is correct.
What is The entropy change (∆S°)?The entropy change (∆S°) refers to the change in the degree of disorder or randomness of a system in a chemical reaction or physical change that occurs at a constant temperature and pressure. It is a thermodynamic function that measures the amount of energy that is unavailable to do useful work in a system.
If ∆S° is positive, it indicates an increase in entropy, which means that the system becomes more disordered, chaotic, and random. In contrast, if ∆S° is negative, it indicates a decrease in entropy, which means that the system becomes more ordered, organized, and predictable.
The ∆S° value is affected by several factors, such as the physical state of the reactants and products, the number of particles involved, and the temperature and pressure at which the reaction occurs. A negative ∆S° value suggests that the reaction favors the reactants, whereas a positive ∆S° value indicates that the reaction favors the products.
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Round to 2 significant
figures.
5,249
5,250. The number was rounded up from 5,249 because the last digit, 9, is greater than or equal to 5.
What is rounded up?Rounding up is a mathematical operation that involves increasing a number to its nearest whole number. It is commonly used when dealing with money, measurements, or statistics. When rounding up, the number is increased to the next highest whole number. For example, if a number is 6.7, it would be rounded up to 7. Rounding up is often used when dealing with exact measurements or estimates to simplify the calculations. It can also be used to make the results of a calculation easier to understand. In the case of money, rounding up can be used to round a number to the nearest dollar. This prevents dealing with fractional amounts of money. Rounding up can also be utilized in statistical analysis, such as in the calculation of mean or median. This simplifies the data and prevents dealing with fractions or decimals.
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A 8.81 g sample of Methanol was combusted in a bomb (constant volume) calorimeter. The temperature of the calorimeter increased by 11.13°C. If the molar mass of methanol is 32.04 g/mol, and heat capacity of calorimeter is 5,277 J/°C, what's the molar DeltaE in the reaction in units of kJ/mol?
The molar DeltaE in the reaction is 213.8 kJ/mol. A bomb thermometer is a device that is mostly used to measure combustion temperatures
How can you figure out a bomb calorimeter's calorimeter constant?With this method, a sample is burned in a bomb calorimeter at a constant volume. Equation q = -CΔT, where C is the calorimeter's heat capacity and ΔT is the temperature change, can be used to determine how much heat is released during the reaction.
We have to calculate the energy transferred,
q = CΔT
q = energy transferred
C = heat capacity of the calorimeter
ΔT is the temperature increase
q = 5,277 J/°C × 11.13°C = 58,765 J
Now,
Energy per mole of methanol = Energy transferred / Number of moles of methanol
Number of moles of methanol = Mass of methanol / Molar mass of methanol
Number of moles of methanol = 8.81 g / 32.04 g/mol = 0.2748 mol
Energy per mole of methanol = 58,765 J / 0.2748 mol = 213,772.8 J/mol
Now, we have to convert the energy per mole of methanol to kJ/mol:
Energy per mole of methanol = 213,772.8 J/mol / 1000 J/kJ = 213.8 kJ/mol
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For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species.
For the reaction
N2(g)+3H2(g)↽−−⇀2NH3(g)
the standard change in Gibbs free energy is Δ°=−32.8 kJ/mol
. What is ΔG for this reaction at 298 K when the partial pressures are N2=0.350 atm
, H2=0.300 atm
, and NH3=0.750 atm
?
Question 4 of 10
How much energy is required to vaporize 2 kg of gold? Use
the table below and this equation: Q = mLvapor
Substance
Aluminum
Copper
Gold
Helium
Lead
Mercury
Water
Latent Heat
Fusion
(melting)
(kJ/kg)
400
207
62.8
5.2
24.5
11.4
335
Melting
Point
(°C)
660
1083
1063
-270
327
-39
0
Latent Heat
Vaporization
(boiling) (kJ/kg)
1100
4730
1720
21
871
296
2256
Boiling
Point
(°C)
2450
2566
2808
-269
1751
357
100
It requires 10.15 kilojoules of energy.
What is vaporization?The term "vaporisation" (or "evaporation") often refers to the transformation of a liquid's condition into a vapour phase below its boiling point. The phrase, however, can also refer to the process of removing a solvent, independent of the temperature used.
What is energy?When a body moves to exert force, it is said to be exerting work. Energy is the capacity to accomplish work. Energy is something we always need, and it can take many different forms.
If the gold is present in the liquid state, you only have to determine the latent heat of vaporization, or lvap. The empirical data for gold is 330 kJ/mol.
Q = mlvap
Q = (2 kg)(1 kmol/197 kg)(1,000 mol/1 kmol)
Q = 10.15 kJ
It needs an energy of 10.15 kilojoules
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1. Identify any (if applicable):
• aromatic rings
• chiral centers
• all functional groups
2. For alcohol groups, specify whether each is primary, secondary, tertiary or phenolic.
For carboxylic acid groups, draw the conjugate base.
For amines, draw the conjugate acid.
For esters and amides, draw products of hydrolysis.
3. Identify all regions of the molecule that can participate in hydrogen bonding with water.
4. Identify what your molecule is used for.
The most charged oxygen atom that exists in the molecule of water (H2O) is covalently joined to hydrogen. As a result, the hydrogen nucleus on one water molecule interacts with that of oxygen on another water molecule via a dipole.
Which molecular components can create a hydrogen connection with water?Hydrogen ties form between nearby oxygen and hydrogen atoms liquid adjacent water molecules in this instance of water. A bond called a hydrogen bond, it is generated via an attraction among two water molecule molecules.
Which chemical does not combine with moisture and yield hydrogen debts?Water exhibits H-bonding because it includes oxygen. Because hydrogen bonds are not present in the acid hydrochloric, it lacks oxygen, nitrogen, and fluorine. Therefore, option (d) — hydrochloric acid — is the correct response.
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If a molecule has a triple bond, what can be assumed about the bond compared to a molecule with a double bond?
The length is more than a double bond
The strength is more than a double bond
The strength is less than a double bond
The length is the same as a double bond
While the length is less than a double bond, the strength exceeds that of a double bond.
Within the same molecule, how do triple bonds differ from double bonds?Due to the presence of two bonds rather than one, triple bonds are stronger than double bonds. An sp-sp sigma bond is created when one of each carbon atom's two sp hybrid orbitals intersects with the corresponding orbital from the other carbon atom.
Compared to double bonds, are triple bonds more durable and longer?Six electrons are shared by a sigma bond, two bonds, and a triple bond. Double bonds are more powerful than single bonds, and triple bonds are more powerful than double bonds, according to experiments.
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Answer: third
Explanation:
True/False: Paraffin wax (d = 0.910 g/cm3) would float in ethanol (d = 789 kg/L)
The claim that paraffin wax would float in ethanol (d = 789 kg/L) is accurate.
In ethanol, does paraffin wax float?A 40–50% aqueous solution would have a density that could be adjusted to be just below that of paraffin wax, while regular alcohol (ethanol) has a density of roughly 0.8. The wax would then begin to sink. Warming causes the wax's density to significantly decrease (more than ethanol does), causing it to float.
Does ethanol allow you to float?Even with your lungs completely expanded, you cannot float in 80-proof (or 40%) alcohol since your body weighs more than the booze and will sink if you stop swimming.
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The Ka value for ethanoic acid, CH3COOH is 1.79 x 10-5. What is the pH of an equimolar solution of ethanoic acid and Na+CH3COO-?
The pH of the solution can be calculated using the following steps:
Write the chemical equation for the dissociation of ethanoic acid:
CH3COOH + H2O ⇌ CH3COO- + H3O+
Write the equilibrium expression for the dissociation of ethanoic acid:
Ka = [CH3COO-][H3O+] / [CH3COOH]
Since the solution is equimolar in CH3COOH and CH3COO-, we can assume that the initial concentrations of CH3COOH and CH3COO- are equal. Let's use the variable x to represent the concentration of CH3COO- and CH3COOH in mol/L.
[CH3COOH] = x mol/L [CH3COO-] = x mol/L
Since CH3COOH is a weak acid, we can assume that only a small fraction of it dissociates in water. Let's use the variable y to represent the concentration of H3O+ ions in mol/L that are produced from the dissociation of CH3COOH. From the dissociation of ethanoic acid, we know that [CH3COO-] = [H3O+].
[CH3COO-] = y mol/L [H3O+] = y mol/L
Use the equilibrium expression to solve for the concentration of H3O+ ions:
Ka = [CH3COO-][H3O+] / [CH3COOH] 1.79 x 10^-5 = y^2 / x
Solving for y in terms of x, we get:
y = sqrt(Ka * x)
Calculate the pH of the solution using the equation:
pH = -log[H3O+]
pH = -log(y)
Substituting in the value of y from Step 5, we get:
pH = -log(sqrt(Ka * x))
Simplifying, we get:
pH = -0.5 * log(Ka * x)
Substituting in the value of Ka, we get:
pH = -0.5 * log(1.79 x 10^-5 * x)
Now we can calculate the pH for the solution by substituting the value of x as it is equimolar.
pH = -0.5 * log(1.79 x 10^-5 * x)
pH = -0.5 * log(1.79 x 10^-5 * 1)
pH = -0.5 * log(1.79 x 10^-5)
pH = 4.74
Therefore, the pH of an equimolar solution of ethanoic acid and Na+CH3COO- is 4.74.
