Answer: heat is transferred to and from objects -- such as you and your home -- via three processes: conduction, radiation, and convection.
Explanation:
Hopes this helps!
1. Why is Earth more suitable for life than Venus?
2. How do plants increase the viability of life on Earth?
3. Are volcanoes present throughout the terrestrial planets? Why or why not?
4. What are the characteristics of the inner planets? How do these vary from the outer planets?
5. What evidence is there to support that planets exist outside of our Solar System?
The picture represents the respiratory system.
The respiratory system. X points to the windpipe.
Which structure is represented by the X?
the pharynx
the larynx
the trachea
the bronchus
Answer:
c.
Explanation:
i took the test.
Answer:
c the trachea
Explanation:
to jump, you exert 1400N of force on the ground. (it exerts 1400N back on you) you applied this force over a distance of 0.3 m as your extend your legs. how much work have you done? how high will you ride into the air if your mass is 70 kg?
Answer:
Explanation:
Work done is expressed as;
Work done = Force × distance
Given
Force = 1400N
Distance = 0.3m
Workdone = 1400×0.3
Work done = 420joules
Given mass = 70kg
Weight = 700N
To know how high you will ride into the air
420 = 700×d
d = 420/700
d = 0.6m
You ride 0.6m into the air
Which mineral is also an element graphite courts calcite hematite
Answer:
look in lesson brainly can some time be wrong
Beth drives east at 30m/s then slows to a stop at the red
light. A graph of her velocity over time is shown below,
where eastward is the positive velocity direction. which graph shows the acceleration over time
Answer:
c
Explanation:
when i did khan academy and chose the other answer provided on this post i got it wrong so just answer until it said i got it right
The graph shows the acceleration over time will be constant. Then the correct option is C.
What is velocity?Velocity is the time rate of change of displacement. The displacement and velocity both are vector quantities. They represent magnitude and direction as well.
Beth drives east at 30m/s then slows to a stop at the red light.
A graph of her velocity over time is shown below, where eastward is the positive velocity direction.
As he slows at a red light, deceleration occurs. Deceleration is negative acceleration.
Acceleration is the time rate of change of velocity.
Let's say for stopping 10 s. Then deceleration will be
a = 0 -30 /10 = - 3 m/s²
The negative sign represents the deceleration of the vehicle.
Thus, the graph shows the acceleration over time will be constant.
Then the correct option is C.
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What is the weight of a 5.0-kilogram object at the surface of Earth?
A
5.0 kg
B
25 N
C
49 kg
D
49 N
Answer:
49 N (d)
Explanation:
w= mg = 5 kg * 9.8 m/s^2 = 49 N
The weight of a 5.0-kilogram object at the surface of Earth is 49 N. Hence, option (C) is correct.
What are mass and weight?Mass is a fundamental quantity in physics and the most fundamental attribute of matter. Mass can be defined as the amount of matter contained in a body. Kilogram is the SI unit of mass (kg).
A body's mass does not alter at any time. Only in severe instances where a massive amount of energy is provided or removed from the body.
The force of gravity acting on a body is measured by weight. The weight formula is as follows: w = mg. Because weight is a force, it has the same SI unit as force; the SI unit of weight is Newton (N).
The weight of the object is = 5.0 × 9.8 N
= 49.0 N.
Hence, option (B) is correct.
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A ray of light approaches a jar of honey at an angle of 30.0. If the angle of refraction is 19.5, what is the refractive index of honey?
Answer:
n = 1.49
Explanation:
Given that,
Angle of incidence = 30 degrees
Angle of refraction = 19.5 degrees
We need to find the refractive index of the honey. Using Snell's law, we can find it as follows :
[tex]n=\dfrac{\text{sin i}}{\text{sin r}}\\\\=\dfrac{\text{sin 30}}{\text{sin 19.5}}\\\\n=1.49[/tex]
So, the refractive index of honey is 1.49.
The refractive index of honey will be "1.49".
Given:
Angle of incidence,
i = 30 degreesAngle of refraction,
r = 19.5 degreesAs we know, the formula:
→ [tex]Refractive \ index, n = \frac{Sin \ i}{Sin \ r}[/tex]
By substituting the values, we get
→ [tex]= \frac{Sin \ 30}{Sin \ 19.5}[/tex]
→ [tex]=1.49[/tex]
Thus the above answer is right.
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g Initially, the motorcycle travels along a straight road with a speed of 35 m/s (this is almost 80 mph). The maximum deceleration of the motorcycle is -1.2 m/s2. If the biker is skilled and uses maximum deceleration, how long will it take them to come to a complete stop
Given:
Initial speed of the motorcycle (u) = 35 m/s
Final speed of the motorcycle (v) = 0 m/s (Complete Stop)
Maximum deceleration of the motorcycle (a) = -1.2 m/s²
Required Equation:
[tex] \boxed{\bf{ v = u + at}}[/tex]
Answer:
By substituting values in the equation, we get:
[tex] \rm \longrightarrow 0 = 35 + ( - 1.2)t \\ \\ \rm \longrightarrow 0 = 35 - 1.2t \\ \\ \rm \longrightarrow 35 - 1.2t = 0 \\ \\ \rm \longrightarrow 35- 35 - 1.2t = 0 - 35 \\ \\ \rm \longrightarrow - 1.2t = - 35 \\ \\ \rm \longrightarrow \dfrac{ - 1.2t}{ - 1.2} = \dfrac{ - 35}{ - 1.2} \\ \\ \rm \longrightarrow t = 29.167 \: s[/tex]
[tex] \therefore [/tex] Time taken by motorcycle to come to a complete stop (t) = 29.167 s
Which of the following is an example of a speed?
A. 7 km/hr west
B. 12 m/s2 east
C. 3 m/s south
OD. 11.5 km/hr
Water flows at speed v in a pipe of radius r. Neglecting viscosity, at what speed does the water flow through a constriction in which the radius of the pipe is r/3
Answer:
9v
Explanation:
Given that the water flows at speed v in a pipe of radius r.
Let [tex]v_2[/tex] is the speed of water flow where the radius of the pipe is r/3.
By using the continuity equation, the mass flow rate of water is the same at all the cross-sections of the pipe, wh have
[tex]\rho_1A_1_v_1 =\rho_2A_2_v_2[/tex]
Where [tex]\rho_1, A_1[/tex] and [tex]v_1[/tex] are the density, area of the cross-section and speed at cross-section 1 and [tex]\rho_2, A_2[/tex] and [tex]v_2[/tex] are the density, area of the cross-section and speed at cross-section 2.
As the density of the water remains constant. so [tex]\rho_1=\rho_2[/tex].
[tex]\Rightarrow A_1_v_1 =A_2_v_2 \\\\\Rightarrow (\pi r^2)v=(\pi (r/3)^2v_2 \\\\\Rightarrow r^2v=\frac {r^2}{9}\times v_2 \\\\\Rightarrow v= \frac {v_2}{9} \\\\\Rightarrow v_2=9v.[/tex]
Hence, the speed of the water flow where the radius is r/3 is [tex]9v[/tex].
what happens to the strength of an electromagnet when the number of coils in the solenoid is decreased?
Answer: a . it decreases
Explanation:
1. Newton's third law states that any action will have a(n) and reaction O A. Equal and opposite O B. Greater and opposite C. Equal and similar D. Equal and different
Answer: Equal and Opposite
Explanation:
Two protons are on either side of an electron as shown below:
Diagram
The electron is 30 µm away from the proton on its left and 10 µm away from the proton on its right. What is the magnitude and direction of the net electric force acting on the electron? Note that
P=1.6×10(-19) c=-e
Select one:
a. 2.0×10−18N to the right
b. 7.0×10−24N to the right
c. 2.0×10−18N to the left
d. −9.59×10−24N to the right
e. 7.0×10−24N to the
Answer:
Choice a. approximately [tex]2 \times 10^{-18}\; \rm N[/tex] to the right.
Explanation:
Look up the Coulomb constant, [tex]k[/tex]:
[tex]k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex].
Coulomb's Law may be used to find the magnitude of the electric force between the electron and each proton.
Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of electric charge on two point charges. Let [tex]r[/tex] denote the distance between these two charges.
By Coulomb's Law, the magnitude of the force between these two point charges would be:
[tex]\displaystyle F = \frac{k\, q_1\, q_2}{r^2}[/tex].
The unit of distance in the Coulomb's constant here[tex]k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex] is meters. However, the distance between the electron and each proton is given in micrometers, [tex]\rm \mu m[/tex]. Note that [tex]1\; \rm \mu m = 10^{-6}\; \rm m[/tex].
Convert these units to meters:
[tex]30 \; \rm \mu m = 30 \times 10^{-6}\; \rm m[/tex].
[tex]10 \; \rm \mu m = 10 \times 10^{-6}\; \rm m[/tex].
The question states that the magnitude of electric charge on each proton and each electron is [tex]1.6\times 10^{-19}\; \rm C[/tex].
Using these information, find the magnitude of the electric force between the electron and each proton:
Between the electron and the proton on the left-hand side of the electron: [tex]\begin{aligned}F &= \frac{k\, q_1\, q_2}{r^2}\\ &\approx \frac{\left(8.987552\times 10^{9}\; \rm N \cdot m^2\cdot C^{-2}\right) \times \left(1.6 \times 10^{-19}\; \rm C\right) \times \left(1.6 \times 10^{-19}\; \rm C\right)}{\left(30 \times 10^{-6}\; \rm m\right)} \\ &\approx 0.26 \times 10^{-18}\; \rm N\end{aligned}[/tex].Between the electron and the proton on the right-hand side of the electron:[tex]\begin{aligned}F &= \frac{k\, q_1\, q_2}{r^2}\\ &\approx \frac{\left(8.987552\times 10^{9}\; \rm N \cdot m^2\cdot C^{-2}\right) \times \left(1.6 \times 10^{-19}\; \rm C\right) \times \left(1.6 \times 10^{-19}\; \rm C\right)}{\left(10 \times 10^{-6}\; \rm m\right)} \\ &\approx 2.56 \times 10^{-18}\; \rm N\end{aligned}[/tex].The two protons in this question will both attract the electron. Therefore, the force between the electron and the proton on the left-hand side of the electron would point to the left. Similarly, the force between the electron the proton on the right-hand side of the electron would point to the right.
The magnitude of the net electric force on the electron would be:
[tex]2.56 \times 10^{-18}\; \rm N - 0.26\times 10^{-18}\;\rm N \approx 2\times 10^{-18}\; \rm N[/tex].
These two forces act along the same line in opposite direction. Therefore, the resultant force of these two force would be in the direction of the larger force of the two.
In this question, the electric force between the electron and the proton on the right-hand side of the electron is larger. Hence, the net electric force of the protons on the electron should point to the right (towards the proton that is closer to the electron.)
A proton moves perpendicular to a uniform magnetic field B at a speed of 2.30 107 m/s and experiences an acceleration of 2.50 1013 m/s2 in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field.
Answer:
B = 6.18 10⁻⁶ T
the magnetic field is in the negative direction of the y axis
Explanation:
The magnetic force is given by
F = q v x B
as in the exercise indicate that the velocities perpendicular to the magnetic field,
F = q v B
Newton's second law is
F = m a
let's substitute
q v B = m a
B = m a / q v
let's calculate
B = 9.1 10⁻³¹ 2.50 10¹³ / (1.6 10⁻¹⁹ 2.30 10⁷)
B = 6.18 10⁻⁶ T
The direction of the field can be obtained with the right hand rule, where the thumb points in the direction of the velocity, the fingers extended in the direction of the magnetic field and the palm in the direction of the force for a positive charge.
In the exercise indicate that the velocity is the z axis
the acceleration and therefore the force in the x axis
therefore the magnetic field is in the negative direction of the y axis
IF THERE ARE ONLY 118 ELEMENTS, HOW DO YOU
ACCOUNT FOR THE MANY MILLIONS OF THINGS THAT
WE HAVE IN OUR UNIVERSE?
Answer:
Although there are only 118 elements that have been discovered and entered in the Periodic Table, there is an almost infinite multiplicity of things, materials, resources and other objects in the universe.
This is so because each of these elements can be combined with the others, varying its proportion and the inclusion of different elements, forming different things according to the proportion in which each element has been used.
Which of the following best represents stored potential energy?
Air leaking from a flat tire
Stress built up in a rock fault
Heat given off by a forest fire
Water flowing through a hose
Answer:
B
Explanation:
stress built up on a rock fault
Three people are in an elevator, The people have a total 185 kg. The elevator has a mass of 250 kg. When the evelavtor begins to move the elevator and the people accelerate upward with a acceleration of 1.50 m/s ^ 2 What the net force?
The net force will be equal to 4915.5 N when the elevator accelerates upward with an acceleration of 1.50 m/s².
What is tension?Tension can be described as a force along the length of a flexible medium such as a cable, rope, etc. Tension is a pulling force but it can not be a pushing force.
When the elevator moves upward with acceleration (a). The net force will be equal to:
Fₙ = mg + ma
Where m is the mass of the object and 'g' is the gravitational acceleration.
Given the total mass of three people = 185 Kg
The mass of the elevator = 250 Kg
Then the total mass, m = 185 + 250 = 435 Kg
The acceleration of the elevator, a = 1.50 m/s²
The net force of the elevator will be: F = 435 × 9.8 + 435 × 1.50
F = 4915.5 N
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You have a summer job with the telephone company working in a group investigating the vulnerability of underground telephone lines to natural disasters. Your task is to write a computer program which will be used determine the possible harm to a telephone wire from the high electric fields caused by lightning. The underground telephone wire is supported in the center of a long, straight steel pipe that protects it. When lightening hits the ground it charges the steel pipe. You are concerned that the resulting electric field might harm the telephone wire. Since you know that the largest field on the wire will be where it leaves the end of the pipe, you calculate the electric field at that point as a function of the length of the pipe, the radius of the pipe, and the charge on the pipe
Answer:
a because it is go
Explanation:
Calculate the east component of a resultant 32.5 m/s, 35.0° east of north.
Answer:
East component is: 18.64 m/s
Explanation:
If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:
East component = 32.5 m/s * sin(35) = 18.64 m/s
Determine the velocity (in m/s) of the object at 10seconds. Include a numerical answer accurate to the first decimal place. If negative, include the - sign
Answer:
v = 0.5 [m/s]
Explanation:
In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.
The slope of a line is determined by the following mathematical expression.
P₂ = point 2 = (12,12) = (x₂,y₂)
P₁ = Point 1 = (6,9) = (x₁,y₁)
In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.
Now using the slope:
[tex]m =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m = \frac{12-9}{12-6}\\m = 0.5[/tex]
This slope is equal to the speed (velocity)
v = 0.5 [m/s]
6. Find the fundamental units involved in the following derived units.
(i) Newton(N)
(ii) Watt (W)
(iii) Joule (1)
(iv) Pascal (Pa)
(v) Cubic metre
Answer:
I. force
II. electricity.
III. energy.
iv. pressure.
v. volume.
Physical activity is the most important thing you can do to improve and maintain health-related physical fitness. Which list contains factors that contribute to physical fitness?
A.age, environment, heredity, motivation
B.age, environment, height, maturation
C.age, emotional state, heredity, motivation
D.age, environment, heredity, maturation
Answer:
I guess it's d because age environment heredity Nd maturation r more obvious factors if we compre with only physical fitness
The factors that contribute to physical fitness are age, environment, heredity and maturation. Hence, option (D) is correct.
The given problem is based on the factors affecting the physical fitness and physical activities. The physical activities are all those activities, wether of some sort of daily work or the sporting activities, that a individual perform to stay fit and healthy. The prime factors of physical fitness are as follows:
Age : The is obviously a specific age after which the fitness level goes down. For example: At younger age, an athlete can show dominance in its reflexes and at the age of early 50s, the fitness level goes down.Environment : Environment is another important aspect to remain fit, a positive environment helps a most of crowd to be happy.heredity : There is a balanced impact of heredity on the physical fitness, which means it is not necessary that the son of splinter will be as fast as his/her father. Maturation: It is an obvious factor, as maturity over taking dietary supplements, sleeping time, exercises, and many more are to be considered with complete maturity.Thus, we can conclude that the factors that contribute to physical fitness are age, environment, heredity, maturation. Hence, option (D) is correct.
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How can we predict how high a roller coaster can go knowing its velocity?
Answer:
By using law of energy conservation , we can find how high the roller coaster will go.
Explanation:
What is law of energy conservation ?Energy can neither be created nor destroyed , only its form can be changed.
when roller coaster is moving it has kinetic energy .as it will go up , this kinetic energy will convert in to potential energy.it means at the top K.E. = P.E.[tex]m.g.h =\frac{1 }{2} .m.v^{2}[/tex][tex]h =\frac{v^{2} }{2g}[/tex]Hence we can predict how high a roller coaster can go knowing its velocity.
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pls help will give brainlest
Respon
lqiudos ciopatmibes
ly apsamtios ccoriendor sabe r
llpop
io.
Answer:
Solid, liquid, gas, plasma (your right!)
Explanation:
Think about having to add heat(energy) to each state of matter, and then think of which state of matter would be a result.
Solid ice + heat= liquid water
liquid water+ heat= water vapor (steam which is a gas)
Based on what you have read what will be another example of potential energy
A ball resting on the shelf
B hey Ball spinning on a finger
C A ball rolling on the ground
D A ball flying through the air
Answer:
A) A ball resting on a shelf.
Explanation:
because potential energy means the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above her head, and the string angles down slightly (11.9° below the horizontal.). The string is massless and 0.75m long.
A coordinate system lies with its origin a the location where the string comes out of the girl's hand. The positive z-axis points vertically. the projection onto the horizontal plane is such that the string makes an angle of 34.6° with the x-axis.
At a certain instant, the rock makes 2.50 revolutions per second (rev/s) in a counterclockwise direction as seen from above.
What is the tangential velocity vector at this instant?
Complete Question
The diagram of with this question is shown on the first uploaded image
Answer:
The value is [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]
Explanation:
From the question we are told that
The mass of the rock is [tex]m = 0.250 \ kg[/tex]
The length of the string is [tex]L = 0.75 \ m[/tex]
The angle the string makes horizontal is [tex]\theta = 11.9^o[/tex]
The angle which the projection of the string onto the xy -plane makes with the positive x-axis is [tex]\phi = 34.6^o[/tex]
The angular velocity of the rock is [tex]w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s[/tex]
Generally the radius of the circle made by the length of the string is mathematically represented as
[tex]r = L cos(\theta )[/tex]
=> [tex]r = 0.75 cos(11.9 )[/tex]
=> [tex]r = 0.734 \ m[/tex]
Generally the resultant tangential velocity is mathematically represented as
[tex]v__{R}} = w * r[/tex]
=> [tex]v__{R}} = 15.7 *0.734[/tex]
=> [tex]v__{R}} = 11.5 \ m/s[/tex]
Generally the tangential velocity along the x-axis is
[tex]v_x = -v__{R}} * sin(\phi)[/tex]
=> [tex]v_x =- 11.5 * sin(34.6)[/tex]
=> [tex]v_x = -6.543 \ m/s[/tex]
The negative sign show that the velocity is directed toward the negative x-axis
Generally the tangential velocity along the y-axis is
[tex]v_y = v__{R}} * cos(\phi)[/tex]
=> [tex]v_y = 11.5 * cos(34.6)[/tex]
=> [tex]v_y = 9.47 \ m/s[/tex]
Generally the tangential velocity along the y-axis is
[tex]v_z = v__{R}} * cos(90)[/tex]
=> [tex]v_z = 0 \ m/s[/tex]
Generally the tangential velocity at that instant is mathematically represented as
[tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]
If a racquet ball hits the wall with 20 N of force, how much force will it bounce back with?
Please help
Answer:
-20N
Explanation:
The racquet ball will bounce back with the same force.
This is in compliance with newton's third law of motion:
"action and reaction are equal but opposite"
If the ball hits the wall with an action force of 20N, the reaction force will be -20N.
The negative indicates an oppositely directed force.
This question is typical on some driver's li-
cense exams: A car moving at 49 km/h skids
17 m with locked brakes.
How far will the car skid with locked brakes
at 98 km/h? Assume that energy loss is due
only to sliding friction.
Answer in units of m.
Answer:
The car will skid 98 m
Explanation:
Friction Loss
If some object is traveling and the brakes are locked, then the friction force dissipates all the kinetic energy into heat.
The kinetic energy dissipated is equal to the job done by the friction force:
[tex]K = W_f\qquad\qquad[1][/tex]
The kinetic energy is calculated by:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where m is the object's mass and v is the speed.
The work done by the friction force is:
[tex]W=F_r.x[/tex]
Where Fr is the magnitude of the force and x is the distance the object is braking.
The friction force is calculated as
[tex]F_r=\mu .m.g[/tex]
Being [tex]\mu[/tex] the coefficient of friction and g the acceleration of gravity. Please note that the friction force remains constant for a given object and surface of contact.
Keeping all the above in mind, we use [1]
[tex]\displaystyle \frac{1}{2}mv^2=\mu .m.g.x[/tex]
Simplifying and solving for x:
[tex]\displaystyle x=\frac{v^2}{2\mu g}[/tex]
Which means the skidding distance is proportional to the square of the speed. Or, equivalently for x2 and x1 the distances for v1 and v2:
[tex]\displaystyle \frac{x_2}{x_1}=\left(\frac{v_2}{v_1}\right)^2[/tex]
If the car skids 17 m at 49 Km/h, then if it goes at 98 Km/h, it will skid:
[tex]\displaystyle x_2=17*\left(\frac{98}{49}\right)^2=68[/tex]
[tex]x_2=68~m[/tex]
The car will skid 98 m
Answer:
[tex]d=68m[/tex]
Explanation:
Initial | Final
[tex]v^{2} -v_{o} ^{2} =2ad[/tex] | [tex]v^{2} -v_{o} ^{2} =2ad[/tex][tex]0^{2} -49^2=2a(17)[/tex] | [tex]0^{2} -98^2=2ad[/tex][tex]\frac{49^2}{98^2} =\frac{17}{d}[/tex]
[tex]d=68m[/tex]
2CH3OH + ?O2
2CO2 + 4H2O
9. How many molecules of O2 are needed to balance the chemical equation?
a. 1
b. 2
c. 3
d.4
Answer:
c.3
2CH3OH + 3O2====> 2CO2 + 4H2O
attention is always blank
Answer
lol
Explanation: