Will mark brainliest (give me 2 possible answers pls)

Answer: 28 hours over 172$ that mean 6.14 per hour

so 257.88$ minimum for 42 hours

Step-by-step explanation:

28 hours over 172$ that mean 6.14 per hour

so if we say she work in one day 6 hours that mean in one weak 42 hours

so 42*6.14=  257.88 $

Answer:

arc PQ = 124°

Step-by-step explanation:

The inscribed angle PRQ is half the measure of its intercepted arc PQ, so

arc PQ = 2 × 62° = 124°

Answer:

  124°

Step-by-step explanation:

Inscribed angle PRQ is half the measure of intercepted arc PQ.

  1/2(PQ) = 62°

  PQ = 124° . . . . . . multiply by 2

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

[tex]\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}[/tex]

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

[tex]\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}[/tex]

Another identity is:

[tex]\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}[/tex]

Therefore:

[tex]\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}[/tex]

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

[tex]\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}[/tex]

Another identity:

[tex]\displaystyle \large{\sin^2x+\cos^2x=1}[/tex]

Therefore:

[tex]\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}[/tex]

Hence proved, this is proof by using identity helping to find the specific identity.

Answer:

y = - 3x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 2 ← is in slope- intercept form

with slope m = - 3

Parallel lines have equal slopes , then

y = - 3x + c ← is the partial equation

To find c substitute (- 1, 3 ) into the partial equation

3 = 3 + c ⇒ c = 3 - 3 = 0

y = - 3x ← equation of parallel line

Answer:

y = -3x

Step-by-step explanation:

[tex]\text{Given that,}\\\\f(x) = x^2-x -1\\\\f(-5) = (-5)^2 -(-5) -1 = 25 +5 -1 = 29[/tex]

Answer: 15

Step-by-step explanation:

9 x h = 135

9 x 15 = 135

Answer:

x^2 = 9

Step-by-step explanation:

Both 3 and -3 are 9 when squared.

Answer:

I think it's-12

I am not sure

Please ask to some one else please

Answer:

  1×117, 3×39, 9×13, 13×9, 39×3, 117×1

Step-by-step explanation:

The prime factorization of 117 is ...

  117 = 3²·13

Divisors of 117 are 1, 3, 9, 13, 39, 117. Possible formations would be ...

  1×117, 3×39, 9×13, 13×9, 39×3, 117×1

Answer:

y=√x

Step-by-step explanation: here are the steps

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

[tex]\rm h(x) = 40x - 16x^2[/tex]

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

[tex]\rm h(x) = 40x - 16x^2[/tex]

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

[tex]h(x) = 15[/tex]

Substitute the value of h(x) in the equation,

[tex]\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0[/tex]

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

[tex]\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45[/tex]

Hence, The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

For more details about Inequality refer to the link given below.

https://brainly.com/question/17177510

Step-by-step explanation:

the distance between 2 points is the Hypotenuse of a right-angled triangle. its legs are the x and y coordinate differences.

and so, we can use Pythagoras

c² = a² + b²

with c being the Hypotenuse, and a, b being the legs.

so,

the x difference is 9-12 = -3

the y difference is 31-25 = 6

therefore,

distance² = (-3)² + 6² = 9 + 36 = 45

distance = sqrt(45) = 6.708203932...

Answer:

234+112=346

618-346=272

Josh used 272 pounds of strawberries in his fruit salad.

Step-by-step explanation:

Answer:

272

Step-by-step explanation:

Answer:

I think it's 25 meters.

Hope that helps. x

Answer:

I think it will be 25 meters

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

[tex]\mathbf{TQ : FT =1 : 2}[/tex]

Where FT = 12.

Substitute 12 for FT in the above ratio

[tex]\mathbf{TQ : 12 =1 : 2}[/tex]

Express as fraction

[tex]\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}[/tex]

Multiply both sides by 12

[tex]\mathbf{TQ =\frac{1 }{ 2} \times 12}[/tex]

This gives

[tex]\mathbf{TQ =\frac{1 2}{ 2}}[/tex]

Divide 12 by 2

[tex]\mathbf{TQ =6}[/tex]

The measure of FQ is calculated using:

[tex]\mathbf{FQ = FT + TQ}[/tex]

Substitute 12 for FT, and 6 for TQ

[tex]\mathbf{FQ = 12 + 6}[/tex]

Add 12 and 6

[tex]\mathbf{FQ = 18}[/tex]

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

https://brainly.com/question/11891965

The equivalent value of the expression 1, point, 86, divided by, 2 is given by A = 0.93.

Given data:

Let the expression be represented as A.

Now, the value of A is

A = 1, point, 86, divided by, 2.

Substituting the values in the equation:

[tex]A=\frac{1.86}{2}[/tex]

On simplifying the equation:

[tex]A=0.93[/tex]

Therefore, the value of A is 0.93

Hence, the equation is A = 0.93

To learn more about equations, refer:

https://brainly.com/question/19297665

#SPJ6

The complete question is attached below:

Find the equivalent value of the expression "1, point, 86, divided by, 2".

Answer:

1/3 +1/5 per hour

Step-by-step explanation:

hope i helped sorry if i didn't

Answer:

1. SSS

2. SAS

3. SAS

4. 1?

5. SSS

Step-by-step explanation:

Answer:

the answer will zero for sure

Answer:

0

Step-by-step explanation:

-5-2+2+5 = 0

Answer:

X=7

Step-by-step explanation:

Answer:

Step-by-step explanation:

Conclusion:

Therefore

Hoped this helped.

[tex]GeniusUser[/tex]

Answer:

1. B - 12.5 miles per hour

2. A - 0.36 hours

Answer:

k translates a function up or down

Step-by-step explanation:

hope this helped :)

Answer:

We need to see all of the choices, but they are congruent and reflected and rotated.

Step-by-step explanation:

Answer:

I can't see much so take one more than I can help

Answer:

C -5

Step-by-step explanation:

y2 - y1 / x2 - x1   Pick any 2 points

6 - 1 / -1 - 0

5 / -1

-5

Answer: a. [tex]f(x)=3^{x}[/tex]

Step-by-step explanation:

You can plug in the x and y values to get [tex]f(x)=3^{x}[/tex]

Answer:

About 35 or 34.27 if you round to the tenths spot.

Step-by-step explanation:

514 divided by 15 is 34.27 once rounded.