Answer: 4/10, 6/15, 8/20
Hope this helps!
Word Problem On Division
1. a cup can hold 2/9 ( fraction) litres of water. how many cups of water can be filled with 3 litre bottle?
Applying the knowledge of fractions, the number of cups of water that will fill a bottle of 3 liters is calculated as: 13.5 cups.
What are Fractions?Fractions are numbers that indicate a part of whole numbers. For example, 2/9 of a liter means 2/9 of a part of 1 liter.
What is a Proportion?In math, a proportion is simply and equation that sets to ratios equal to each other.
To solve the problem given, create a proportion then use cross product to find the wanted value, which is the number of cups of water that can be filled into a 3-liter bottle.
Let x represent the cups of water we are looking for.
1 cup = 2/9 liter
x = 3 liters
We would have:
(1)(3) = (2/9)(x)
3 = 2x/9
(3)(9) = 2x
27/2 = x
x = 13.5
The number of cups of water to fill a 3-liter bottle is: 13.5.
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which expression shows how the distribuive property can be used to multiply 8x29?
The expression which shows how the distributive property of the can be used to multiply 8×29 as in the task content is; 8(20 + 9).
Which expression can be used to show how the distributive property can help multiply 8×29?It follows from the task content that the given product to be multiplied is; 8×29.
Consequently, it follows from convention that the distributive property of multiplication allows that the multiplication in this case can be rewritten as follows;
8×29 = 8 (20 + 9)
Hence, we have; (8×20) + (8×9).
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Choose the equation that represents a line that passes through points (−1, 2) and (3, 1).
4x − y = −6
x + 4y = 7
x − 4y = −9
4x + y = 2
Answer:
x + 4y = 7
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 1, 2 ) and (x₂, y₂ ) = (3, 1 )
m = [tex]\frac{1-2}{3-(-1)}[/tex] = [tex]\frac{-1}{3+1}[/tex] = - [tex]\frac{1}{4}[/tex] , then
y = - [tex]\frac{1}{4}[/tex] x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (- 1, 2 )
2 = [tex]\frac{1}{4}[/tex] + c ⇒ c = 2 - [tex]\frac{1}{4}[/tex] = 1 [tex]\frac{3}{4}[/tex] = [tex]\frac{7}{4}[/tex]
y = - [tex]\frac{1}{4}[/tex]x + [tex]\frac{7}{4}[/tex] ← in slope- intercept form
multiply through by 4 to clear the fractions
4y = - x + 7 ( add x to both sides )
x + 4y = 7 ← equation in standard form
equation of line in two point form is needed here.
(y - y1) = [ (y2 - y1)/(x2-x1) ] (x - x1)y - (2) = [ (1 - 2)/(3 - (-1)) ] (x - (-1))y - 2 = [ -1/4 ] (x + 1)y = -(x/4) -1/4 + 2y = -x/4 + 7/44y = -x + 7x + 4y = 7for f(x) = x+1 and g(x)= 2x+3, find the following functions. a. (fog)(x); b. (gof)(x); c. (fog)(2); d.(gof)(2)
Answer:
a) 2x + 4
b) 2x + 5
c) 8
d) 9
Step-by-step explanation:
Given functions:
[tex]\begin{cases}f(x)=x+1\\g(x)=2x+3 \end{cases}[/tex]
Function composition is an operation that takes two or more functions and combines them into a single function.
(f o g)(x) means find g(x) first and then substitute the result into f(x).
(g o f)(x) means find f(x) first and then substitute the result into g(x).
Part (a)
[tex]\begin{aligned}(f \circ g)(x) & = f[g(x)]\\& = g(x)+1\\ & = (2x+3)+1\\& = 2x+4\end{aligned}[/tex]
Part (b)
[tex]\begin{aligned}(g \circ f)(x) & = g[f(x)]\\& = 2[f(x)]+3\\& = 2(x+1)+3\\ & = 2x+2+3\\& = 2x+5\end{aligned}[/tex]
Part (c)
[tex]\begin{aligned}(f \circ g)(2) & = f[g(2)]\\& = g(2)+1\\ & = (2(2)+3)+1\\ & = (4+3)+1\\& = 8\end{aligned}[/tex]
Part (d)
[tex]\begin{aligned}(g \circ f)(2) & = g[f(2)]\\& = 2[f(2)]+3\\& = 2(2+1)+3\\ & = 2(3)+3\\ & = 6+3\\& = 9\end{aligned}[/tex]
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(fog)(x)
f(g(x))f(2x+3)2x+3+12x+4(gof)(x)
g(f(x))g(x+1)2x+2+32x+5(fog)(2))
2(2)+48(gof)(2)
2(2)+59Expand 10a(2a-7) pls its very urgent
Answer:
[tex]20a^2-70a[/tex]
Step-by-step explanation:
1) Expand by distributing terms.
[tex]10\times2a+10a\times-7[/tex]
2) Take out the constants.
[tex](10\times2)aa+10a\times-7[/tex]
3) Simplify [tex]10\times2[/tex] to [tex]20.[/tex]
[tex]20aa+10a\times7[/tex]
4) Use Product Rule:[tex]x^ax^b=x^{a+b}[/tex].
[tex]20a^2+10a\times-7[/tex]
5) Simplify [tex]10a\times-7[/tex] to [tex]-70a.[/tex]
[tex]20a^2-70a[/tex]
Thank you,
Eddie
Answer:
20a² - 70a
Step-by-step explanation:
(10a)(2a-7)
= 10a*2a + 10a*-7
= 20a² - 70a
use the fact that there are 2pi radians in each circle to find another angle, smaller than 2pi, that is equivalent to 17pi/6. with detailed steps pleasee
The equivalent angle in the interval [0, 2pi] is 5pi/6.
How to find the equivalent angle?
Remember that for any given angle θ in radians, we define a family coterminal or equivalent angles as:
A = θ + n*(2pi)
Where n is a whole number.
Now we want to find an angle equivalent to 17pi/6 that is on the range between 0 and 2pi.
Then we can write:
A = 17pi/6 + n*(2pi)
If we use n = -1, then we get:
A = 17pi/6 - 2pi = 17pi/6 - 12pi/6 = 5pi/6
This is the equivalent angle in the desired range.
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The length of a rectangular field is 9m longer than its width, if the perimeter of the field is 270m find its width.
==================================================
Work Shown:
width = w
length = w+9
perimeter = 2*(length + width)
P = 2(w+9+w)
P = 2(2w+9)
P = 4w+18
4w+18 = P
4w+18 = 270
4w = 270 - 18
4w = 252
w = 252/4
w = 63 meters is the width
w+9 = 63+9 = 72 meters is the length
Check:
perimeter = 2*(length + width)
perimeter = 2*(72 + 63)
perimeter = 2*(135)
perimeter = 270
The answer is confirmed.
If a sum of money amounts to Rs. 2175 in 3 years and to Rs. 2625 in 5 years.Find the rate of interestsl
The rate of interest applied on the amount is 15%.
According to the statement
we have given that the sum of money amounts to Rs. 2175 in 3 years and to Rs. 2625 in 5 years.
And we have to find the rate of interest on this money.
So, For this purpose,
The given equation is:
Money in 3 years = 2175
Money in 5 years = 2625
Amount increased in 2 years = 2625-2175
Amount increased in 2 years = 450
And amount increased per year = 450/2
Amount increased per year = 225.
SI in 3 years=450/2 *3=Rs. 675
Principal amount= 2175-675=1500
so again,
R=(I*100)/(P*T)
R=15%
So, The rate of interest applied on the amount is 15%.
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________ is the number of defects in a sample divided by the number of opportunities while ________ is the number of defects divided by the number of units tested within a sample.
DPU is the number of defects in a sample divided by the number of opportunities while DPMO is the number of defects divided by the number of units tested within a sample. Option B
What is DPU?Defects per unit (DPU) can be defined as the number of defects divided by the number of opportunities
It is also seen as the universal measure of quality.
For example, if there are 100 defects in 1,000 units produced, then the defects per unit will be 0.01.
Defects per million opportunities can be defined as a mathematical calculation of the estimated quality of a process
From this information, we can conclude that DPU and DPMO are measure of defects in a sample.
Thus, DPU is the number of defects in a sample divided by the number of opportunities while DPMO is the number of defects divided by the number of units tested within a sample. Option B
Complete question is;
________ is the number of defects in a sample divided by the number of opportunities while ________ is the number of defects divided by the number of units tested within a sample.
a. DPMO, DPU
b. DPU, DPMO
c. RTY, FTY
d. FTY, RTY
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Help me solve this it’s very urgent
Answer:
SAVE WATER
Step-by-step explanation:
i)
x + 1 = 20
subtract 1 from both sides
x + 1 - 1 = 20 - 1
x = 19
19 = S
ii)
15 = 2x + 13
subtract 13 from both sides
15 - 13 = 2x + 13 - 13
2 = 2x
divide both sides by 2
2/2 = 2x/2
1 = x
1 = A
iii)
2x + 5 = 49
subtract 5 from both sides
2x + 5 - 5 = 49 - 5
2x = 44
divide both sides by 2
2x/2 = 44/2
x = 22
22 = V
iv)
[tex]\frac{3x + 3}{2}[/tex] = 9
multiply both sides by 2
[tex]\frac{3x + 3}{2}[/tex] x 2 = 9 x 2
3x + 3 = 18
subtract 3 from both sides
3x + 3 - 3 = 18 - 3
3x = 15
divide both sides by 3
3x/3 = 15/3
x = 5
5 = E
v)
8(x - 7) = 128
apply the distributive law
8x - 56 = 128
add 56 to both sides
8x - 56 + 56 = 128 + 56
8x = 184
divide both sides by 8
8x/8 = 184/8
x = 23
23 = W
vi)
16 = 2(x + 7)
apply the distributive law
16 = 2x + 14
subtract 14 from both sides
16 - 14 = 2x + 14 - 14
2 = 2x
divide both sides by 2
2/2 = 2x/2
1 = x
1 = A
vii)
[tex]\frac{7y}{7}[/tex] = 20
sevens cancel out
y = 20
20 = T
viii)
2x - 1 = 9
add 1 to both sides
2x - 1 + 1 = 9 + 1
2x = 10
divide both sides by 2
x = 5
5 = E
ix)
2(x - 8) = 20
apply the distributive property
2x - 16 = 20
add 16 to both sides
2x - 16 + 16 = 20 + 16
2x = 36
divide both sides by 2
2x/2 = 36/2
x = 18
18 = R
Code Word/s: SAVE WATER
hope this helps :)
Answer:
Save Water
Step-by-step explanation:
(I’m sorry it took so long, I had to write it out Σ(＝д＝ﾉ)ﾉ
I hope this helps! ヾ(>ꇴ<) xx
Analyze the diagram below and answer the question that follows. If 2004-02-01-02-00_files/, what is 2004-02-01-02-00_files/? A. 2004-02-01-02-00_files/ B. 2004-02-01-02-00_files/ C. 2004-02-01-02-00_files/ D. 2004-02-01-02-00_files/
Option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively. This can be obtained by knowing what similar triangles are and finding which sides are proportional.
Find the correct option:Similar triangles: If two triangles have proportional sides the are similar.
For example, if ΔABC and ΔDEF are similar then
[tex]\frac{AB}{DE}= \frac{BC}{EF} =\frac{AC}{DF}[/tex]
∠ABC = ∠DEF and ∠ACB = ∠DFE
Then we can write that, ΔABC ~ ΔDEF
Here in this question,
Since A, Y, Z are midpoints of sides XW, VW, XV
XA = AW
WY = VY
XZ = VZ
To consider sides AY and XV we should take triangles ΔWAY and ΔWXV
[tex]\frac{WX}{WA} =\frac{2WA}{WA} = 2[/tex] (since A is the midpoint of WX)
[tex]\frac{WV}{WY} =\frac{2WY}{WY} = 2[/tex] (since Y is the midpoint of WV)
∠AWY = ∠XWV (reflexive property)
Therefore ΔWAY and ΔWXV are similar triangles
[tex]\frac{WX}{WA}= \frac{XV}{AY} =\frac{WV}{WY}[/tex] = 2
∠WAY = ∠WXV and ∠AYW = ∠XVW
Hence,
AY || XV option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively.
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Analyze the diagram below and answer the question that follows. If Z, Y and A are midpoints of ΔVWX what is true about AY and XY?
A. AY || XV
B. 1/2 AY = XV
C. AY = XV
D. AY ≅ XV
Answer:
A
Step-by-step explanation:
If you want to connect your home network to the internet, you will need a ________ in addition to a modem.
Answer:
landline
hshdjdh
dbbdhdhdh
bdbdhdhdhe
Answer:
Router
Step-by-step explanation:
Hope this helps
The total cost of gasoline varies directly with the number of gallons purchased. kathy pays $23.36 for 16 gallons of gasoline. which equation shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n?
Equation (A) C= 1.46n shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n.
What is an equation?An equation is a formula in mathematics that expresses the equality of two expressions by connecting them with the equals sign =. The word equation and its cognates in various languages may have somewhat different definitions; for example, in French, an équation is defined as including one or more variables, whereas in English, an equation is any well-formed formula consisting of two expressions linked by an equals sign.To find the right equation:
In order to find the constant rate, we would divide 23.36/16 which gives you 1.46. That is the price of 1 gallon which would change depending on the amount of falling a purchased (n) and give you the total price of (C).So, C=1.46nTherefore, equation (A) C= 1.46n shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n.
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The complete question is given below:
The total cost of gasoline varies directly with the number of gallons purchased. Kathy pays $23.36 for 16 gallons of gasoline. Which equation
shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n?
A.C= 1.46n
B. n = 1.46c
C.C = 23.361
D. n = 23.36c
A printer has an original value of $7000. if it depreciates at the rate of 8 percent of the original cost per year, what is its value at the end of 9 years?
Based on the given parameters, the value of the printer after 9 years is $3304
How to determine the value in nine years?The given parameters about the exponential function are
Initial value, a = $7000
Depreciation rate, r = 8%
Time, t = 9
Exponential functions are different from linear functions, and they are calculated using the following exponential function
A = a *(1 - r)^t
To calculate the value in nine years, we have:
Substitute the known values in the above equation
A = 7000 * (1 - 8%)^9
Express 8% as decimal
A = 7000 * (1 - 0.08)^9
Evaluate the difference
A = 7000 * (0.92)^9
Evaluate the exponent
A = 7000 * 0.472
Evaluate the product
A = 3304
Hence, the value of the printer after 9 years is $3304
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Answer: 5040
Step-by-step explanation
We need to find how much it will depreciate each year based of of original cost.
8% of 7000
turn the percent into a decimal
.08
multiple .08 by the 7000
.08 * 7000 = 560
The printer depreciates 560 each year , to find the total for 9 years multiply by 9
560*9 =5040
Which number is equivalent to (1/3)^-4
A 81
B −1/81
C −1/12
D 12
The fraction (1/3)⁻⁴ is equal to 81.
Given that:
Fraction: (1/3)⁻⁴
Rewrite the expression by applying the rule that states a negative exponent is equal to the reciprocal of the positive exponent:
(1/3)⁻⁴= 1 / (1/3)⁴
Now, let's simplify (1/3)⁴:
(1/3)⁴ = (1/3) × (1/3) × (1/3) × (1/3)
(1/3)⁴ = 1/81
So, the expression becomes:
1 /(1/3)⁴ = 1 / (1/81)
Now, dividing by a fraction is equivalent to multiplying by its reciprocal:
1 / (1/81) = 1 × 81 = 81
Therefore, the fraction (1/3)⁻⁴ is equal to 81.
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A small pizza has an area of 730 square centimeters.
Write an inequality that describes p, the area of a
pizza that is larger than a small pizza.
The inequality that describes p, the area of a pizza that is larger than a small pizza 730 < p
How to determine the inequality
From the information given, we have that;
Area of the small pizza = 730 square centimeters
p = area of the larger pizza
In writing inequality, we have to use the signs
< less than
> greater than
Since p has greater area, we have
730 < p
Thus, the inequality that describes p, the area of a pizza that is larger than a small pizza 730 < p
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Answer:
the answer is actually p > 730
Step-by-step explanation:
i juts checked on Kahn academy and i got it right..
in a given figure if o is the centre of circle and oabc is a parallelogram find the value of abc
From the given information, we get the value of ABC = 120°.
How to estimate the value of ABC?
Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.
Now, the radius of the circle exists
OA = OB = OC
Opposite sides of a parallelogram are equal
AB = OC and OA = BC
In ∆OAB,
OA = OB = AB and,
In ∆OCB,
OC = OB = BC
Therefore, ∆OAB and ∆OCB exist in equilateral triangles.
All angles of an equilateral triangle are equivalent to 60°.
Hence, ∠ABC = ∠OBA + ∠OBC
∠ABC = 60° + 60°
∠ABC = 120°
Therefore, the value of ∠ABC = 120°.
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The water usage at a car wash is modeled by the equation w(x) = 4x3 6x2 − 11x 7, where w is the amount of water in cubic feet and x is the number of hours the car wash is open. the owners of the car wash want to cut back their water usage during a drought and decide to close the car wash early two days a week. the amount of decrease in water used is modeled by d(x) = x3 2x2 15, where d is the amount of water in cubic feet and x is time in hours. write a function, c(x), to model the water used by the car wash on a shorter day. c(x) = 4x3 4x2 − 11x 8 c(x) = 3x3 4x2 − 11x − 8 c(x) = 3x3 4x2 − 11x 8 c(x) = 4x3 4x2 − 11x − 8
A function, C(x), to model the water used by the car wash on a shorter day will be (B) 3x³ + 4x² - 11x - 8.
What is an equation?A relationship between two variables is defined as an equation; if we plot the graph of the linear equation, we will get a straight line.To find a function, C(x), to model the water used by the car wash on a shorter day:
Given information -
The water usage at a car wash is modeled by the equation W(x) = 4x³ + 6x² − 11x + 7, where W is the amount of water in cubic feet and x is the number of hours the car wash is open.The amount of decrease in water used is modeled by D(x) = x³+ 2x² + 15, where D is the amount of water in cubic feet and x is time in hours.Now the amount of water is cut from the total water usage so to find out the new model c(x) we need to subtract the decrease in water from the total water usage.
We are trying to find:
C(x) = W(x) - D(x)C(x) = (4x³ + 6x²− 11x + 7) - (x³ + 2x² + 15)C(x) = 4x³ - x² + 6x² - 2x³ - 11x + 7 - 15C(x) = 3x³ + 4x² - 11x - 8Therefore, a function, C(x), to model the water used by the car wash on a shorter day will be (B) 3x³ + 4x² - 11x - 8.
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The correct question is given below:
The water usage at a car wash is modeled by the equation W(x) = 4x3 + 6x2 − 11x + 7, where W is the amount of water in cubic feet and x is the number of hours the car wash is open. The owners of the car wash want to cut back their water usage during a drought and decide to close the car wash early two days a week. The amount of decrease in water used is modeled by D(x) = x3 + 2x2 + 15, where D is the amount of water in cubic feet and x is time in hours.
Write a function, C(x), to model the water used by the car wash on a shorter day
graph the reflection of f(x) = 1.5(0.5) across the y-axis
See attachment for the graph of the reflection of f(x) across the y-axis
How to reflect the function?The function is given as:
f(x) = 1.5(0.5)^x
The rule of reflection across the y-axis is
(x, y) = (-x, y)
So, we have the following equation
f'(x) = 1.5(0.5)^-x
Rewrite the function as
g(x) = 1.5(0.5)^-x
So, we plot the graph of the function g(x)
See attachment for the graph of the reflection of f(x)
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step 1 :
g(x) = 1.5
step 2 :
g(0): 1.5
step 3 :
plot at (0,1.5)
step 4 :
g(1) = 3
g(-1) = .75
step 5 :
plot (1,3) & (-1,0.75)
step 6:
y=0
A package is oscillating on a spring scale with a period of 5.00 s. at time t = 0.00 s the package has zero speed and is at x = 8.50 cm. at what time after t = 0.00 s will the package first be at x = 4.50 cm?
Under the assumption of simple harmonic motion, the package will be at x = 4.50 centimeters at a time of 0.805 seconds.
How to analyze an object on simple harmonic motion
Simple harmonic motion is a kind of periodic motion represented by sinusoidal functions. Physically speaking, it is a good approximation for periodic motion due to small perturbations and with absence of frictions and viscous forces on the system.
The position of an object under simple harmonic motion is described by the following equation:
x (t) = A · cos (2π · t / T + Ф) (1)
Where:
A - Amplitude, in centimetersT - Period, in secondsФ - Angular phase, in radiansx(t) - Position, in centimetersIf we know that T = 5 s, A = 8.50 cm, Ф = 0 rad and x = 4.50 cm, then the time when the package will reach x = 4.50 cm is:
4.50 = 8.50 · cos (2π · t / 5)
9 / 17 = cos (2π · t / 5)
0.322π = 2π · t / 5
t = 0.805 s
Under the assumption of simple harmonic motion, the package will be at x = 4.50 centimeters at a time of 0.805 seconds.
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A fruit basket contains only apples and bananas. If there are 8 apples and 13 bananas, what is the ratio of bananas to fruit? Select all that apply.
13:8
13:21
StartFraction 8 Over 13 EndFraction
21 to 13
StartFraction 13 Over 21 EndFraction
The ratio of bananas to fruit is 13 : 21
How to determine the ratio of bananas to fruit?The given parameters are
Banana = 13
Apple = 8
The total number of fruits is
Fruit = Banana + Apple
Substitute the known values in the above equation
Fruit = 13 + 8
Evaluate the sum
Fruit = 21
The ratio of bananas to fruit is then represented as:
Ratio = Banana : Fruit
Substitute the known values in the above equation
Ratio = 13 : 21
Hence, the ratio of bananas to fruit is 13 : 21
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Which graph represents the equation y2 = –4x?
On a coordinate plane, a parabola opens to the left. It has a vertex at (0, 0), a focus at (negative 1, 0), and a directrix at x = 1.
On a coordinate plane, a parabola opens down. It has a vertex at (0, 0), a focus at (0, negative 1), and a directrix at y = 1.
On a coordinate plane, a parabola opens to the left. It has a vertex at (0, 0), a focus at (negative 4, 0), and a directrix at x = 4.
On a coordinate plane, a parabola opens down. It has a vertex at (0, 0), a focus at (0, negative 4), and a directrix at y = 4.
Answer:
its A
Step-by-step explanation:
Answer: The first one (A)
Step-by-step explanation:
please help i need
this asap!! drag each measure to the correct location on the table classify each measure as a measure of center or a measure or variation
The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
what is measure centre and measure of variation?A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.
The measure of central tendency includes the mean, median and mode.
The measure of variation describes the amount of variability or spread in a set of data.
The common measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.
Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
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A and B are two cylinders that are mathematically similar.
The area of the cross-section
of cylinder A is 18 cm².
Work out the volume of cylinder B.
+
18 cm²
A
5 cm
1
B
61%
10 cm
The Volume of the Cylinder B is gotten as; 720 cm³
What is the Volume of the Cylinder?We are given 2 similar cylinders with;
ratio of heights = a : b
Thus;
ratio of areas = a² : b²
We are given that;
Height of A is 5cm.
Height of B is 10cm.
Thus;
Ratio of heights = 5 : 10 = 1 : 2
Therefore;
ratio of areas = 1² : 2² = 1 : 4
The cross sectional area of B is 4 times the cross sectional area of A. Thus;
Cross sectional area of B = 4 × 18 = 72 cm²
Volume of cylinder = cross section area × height
Volume of cylinder B = 72 × 10 = 720 cm³
The complete question is;
A and B are two cylinders that are mathematically similar.
The area of the cross-section of cylinder A is 18cm².
Height of A is 5cm.
Height of B is 10cm.
Work out the volume of cylinder B
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Every person has blood type O, A, B, or AB. A random group of people are blood-typed, and the results are shown in the table. A 2-column table with 4 rows is shown. The first column is labeled Blood Type with entries O, A, B, AB. The second column is labeled Number of People with entries 22, 20, 6, 2. Use the table to determine the following probabilities. The probability that a randomly chosen person from this group has type B is . The probability that a randomly chosen person from this group has type AB is . The probability that a randomly chosen person from this group has type B or type AB blood is .
Does anyone know this? Evalute the power type your answer in the open box. Look at picture.
13. The average of 15, 19, 23, 41, and x is 20. What is the value of x? (A) 2 (B) 20 (C) 23.6 (D) 31
Answer:
A
Step-by-step explanation:
(x + 15 + 19 + 23 + 41) / 5 = 20
x + 15 + 19 + 23 + 41 = 100
x + 98 = 100
x = 2
Answer: it’s 2 (A)
Step-by-step explanation:
20 * 5 = 100
15 + 19 + 23 + 41 = 98
100-98=2
Check the true statements
Answer:
This the only one I know for sure right
I think the second one mn/on=qn/pn
I think the last one and the first one too but let me know which was right!
Step-by-step explanation:
Hi what unit of algebra or geometry is this because I did this before, and I can help you.
If a polynomial function, f(x), with rational coefficients has roots 0, 4, and 3 startroot 11 endroot, what must also be a root of f(x)? 3 i startroot 11 endroot negative 3 i startroot 11 endroot 3 minus startroot 11 endroot negative 3 minus startroot 11 endroot
Answer:
C
Step-by-step explanation:
C
Answer:
Step-by-step explanation:
its c
Una estrategia de cálculo mental con
números decimales consiste en buscar
parejas de números cuya suma sea un
número entero. Aplica esta estrategia para
calcular mentalmente:
a. 15,75 + 1,2 + 0,25
b. (–1,8) + 2,45 + (–0,20)
c. 3,5 + 11,8 + 12,5
d. 7,38 – 1,5 + 2,62
Esta estrategia se puede aplicar sumando 15,75 + 0,25, –1,8 + –0,20, 3,5 + 12,5 y 2,62 + 7,38 antes de sumar el tercer número dado en cada caso.
¿En qué consiste está estrategia?La estrategia propuesta consiste en sumar dos números decimales que den como resultado un número entero antes de sumar el tercer número decima. Por ejemplo si teneos 1,4 + 0,6 + 1,2, se debe sumar primero 1,4 + 0,6 lo que es igual a 2 antes de sumar el 1,2.
¿Por qué utilizar esta estrategia?Este estrategia es beneficiosa porque facilita sumar números decimales.
¿Cómo aplicar está estrategia?15,75 + 1,2 + 0,25 = 16 (0,25+15,75) + 1,2 = 17,2 (–1,8) + 2,45 + (–0,20) = -2 (-1,8-0,20) + 2,45 = 0,453,5 + 11,8 + 12,5 = 16 (12,5+3,5) +11,8 = 27.87,38 – 1,5 + 2,62 = 10 (7,38+2,62) + 2,62 = 12,62Aprenda más sobre números decimales en: https://brainly.com/question/24620232
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