The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,
[tex]2C(gr) +2H_{2} (g) +O_{2} (g)[/tex] → [tex]CH_{3} COOH(l)[/tex]
The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.
[tex]C(gr) +H_{2} (g) +O_{2} (g)[/tex] → [tex]CH_{3} COOH(l)[/tex]
The balanced chemical equation for the standard formation reaction of liquid acetic acid as,
[tex]2C(gr) +2H_{2} (g) +O_{2} (g)[/tex] → [tex]CH_{3} COOH(l)[/tex]
The combustion of liquid acetic acid is given as,
[tex]CH_{3} COOH(l) + 2O(g)[/tex] → [tex]2CO_{2}((g) +2H_{2} O(l)[/tex] ΔH =-873
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What is the milliosmolarity of a 0. 2 m glucose solution, assuming that the atoms in a glucose molecule are held together by covalent bonds?
There is 200 milliosmolarity of a 0. 2 m glucose solution, assuming that the atoms in a glucose molecule are held together by covalent bonds .
Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution. Dilution is a process of decreasing the concentration of a solution by adding a number of solvents
Calculation ,
The molarity of the glucose = 0.2 M
the mili means [tex]10^{-3}[/tex] of any unit.
So , the 1mM = 1 × [tex]10^{-3}[/tex] M
So , 0.2 M = 0.2/ [tex]10^{-3}[/tex] M = 0.2 × [tex]10^{3}[/tex] = 200 mM
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Prove the following:V=U + AT
We know that,
acceleration (a) = final velocity(V)-initial velocity(U)/ Time taken(T)
What would be the effect on the percentage recovery if not enough naoh were added in step 2 to react with both the unreacted hno3 and the cu2 present at the end of step 1?
The metallic cu⁺ will not be formed to calculate percentage recovery.
What is percentage recovery?
Most commonly "percent recovery" in chemistry refers to the quantity of recovered substance following a purifying procedure. This purification procedure could involve anything from completely separating a particular ingredient to removing a molecule totally.
If we do not completely react the HNO₃ in the reacion mixture, it will not fully reduce Cu ions which will not form all the metallic copper or if at all its formed the quantity will be very low that we will use to calculate the percentage recovey at the end.
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how small atom partical are?
Atoms of particles are so small that they cannot be divided further by any physical means.
What are atoms?According to John Dalton, atoms are the smallest, indivisible particles of elements.
However, it was later found out that chemically, atoms consist of protons, neutrons, and electrons.
Thus, the indivisibility of atoms that John Dalton was referring to must be that of physical division.
In other words, the particles of atoms are so small that dividing them further using physical means is absolutely impossible.
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Why do night bird have extraordinary night vision
Answer:
The low light eye sight depends on the rod cells of the eye,and the birds have more amount of rod cell in their eyes, that's why they have an extraordinary night vision
type of molecule is shown below?
H
O=C
H
Answer:
Carbonyl
Explanation:
While the diagram is slightly unclear, the molecule most likely being shown is a carbonyl. A molecule is a carbonyl when there is a carbon double-bonded to an oxygen.
What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?
Mass of copper would be=92.46 g
I = Current = 19.5 A
t = 4 hours =4×60×60=14400 s
F = Faraday constant = 96485.33 C/mol
Molar mass of copper = 63.546 g/mol
A charge is given by
Q=19.5×14400=280880 C
Moles of electrons are given by Q/F=280880/96485.33=2.91 mol
Moles of copper is=1/2×2.91=1.455 mol
Mass of copper would be=1.455×63.546=92.46 g
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The mass of Copper electroplated is 68.76 g
What is electroplating?The process of plating a metal onto another is known as electroplating.
It is often used to prevent corrosion of metal or for the decorative purposes
In this process, electric current is passed through an aqueous solution containing dissolved cations.
The dissolved cations are reduced developing a thin metal coating on the electrode.
At cathode,
[tex]Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)[/tex]
Current, I = 14.5 A
Time, t = 4 hrs = 4×60×60 = 14400 sec
Charge, q = It = 14.5×14400= 208800 C
Copper metal deposited by 2×96487 C = 63.55 g
Copper metal deposited by 208800 C = [tex]\frac{63.55 \times208800}{2\times96487}[/tex]
= 68.76g
Hence, The mass of Copper electroplated is 68.76 g
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Dosage calculation order: 3 mg available: 2 mg per 6 ml how many ml will be given?
9ml will be given for the case of dosage calculation order: 3 mg available: 2 mg per 6 ml
Conversion factors are necessary for dosage calculation, such as when translating from pounds to kilograms or liters to milliliters. This approach, which is straightforward in design, enables physicians to deal with different units of measurement and convert factors to arrive at the solution.
dosage calculation techniques serve as a second or third check on the accuracy of the previous computation techniques. Dimensional Analysis, Ratio Proportion, and Formula or Desired Over Have Method are the three main approaches for dosage calculation. dosage calculations are frequently prescribed and labeled based on their weight or, for solutions, their strength, which is the amount of weight dissolved or suspended in a given volume.
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Why is the vapor pressure of a warm lake higher than the vapor pressure of a cold lake?
Answer:
Explanation:
Warm lake vapor pressure is higher than cold lake vapor pressure because it evaporates more quickly. In other words, as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases. As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases, thereby increasing the vapor pressure of warm water.
Answer:
B.
Warm water evaporates more quickly.
Explanation:
i got it right on edmentum!!
The empirical formula of the sugar glucose is ch2o. if the relative molecular mass of glucose is measured to be 180.16 g/mol then what is the molecular formula for glucose?
Answer:
18016
Explanation:
(empirical formula)n=molar mass
Answer: C_6 H_12 O_6
Explanation: The molar mass of glucose is given as 180.16 gm/mol.
It is 40% carbon, so the weight of the carbon is 40% of 180.16 =72.06 gm. The molar weight of the carbon is 12.011 gm, so the total number of the moles of carbon are 72.06/12.011 = 6 moles.
It is 6.719% of hydrogen, so the weight of the hydrogen is 6.719% of 180.16 = 12.105 gm. The molar weight of the hydrogen is 1.008 gm, so the total number of the moles of hydrogen are 12.105/1.008 = 12 moles.
It is 53.27% of oxygen, so the weight of the oxygen is 53.27% of 180.16 = 95.97 gm. The molar weight of the oxygen is 16 gm, so the total number of the moles of oxygen are 95.97/16 = 6 moles.
A student makes up 2 l of a 3. 0 m aqueous solution of hbr. to this solution she adds 1 l of a 4 m naoh solution. what is the ph of the resulting solution?
A student makes up 2 l of a 3. 0 m aqueous solution of HBr. to this solution she adds 1 l of a 4 m NaOH solution, then the pH of the resulting solution is 13.83.
What is normality?Normality is defined as the ratio of equivalent mass of compound to the volume of solution in litre.
N1 is the normality of HBR = 3m
N2 is the normality of NaOH = 4m
V1 is the volume of the HBr = 2l
V2 is the volume of the NaOH = 1l
V is the total volume of solution = V1 + V2 = 2l +1l
= 3l
Normality of the solution = N
As we know that,
N1V1 - N2V2 = NV
3 × 2 – 4 × 1 = N × 3
6 – 4 = N – 3
N = 2/3 = 0.67 m
(OH-) = N = 0.67 m
Since normality of NaOH is greater than BR . Hence the resulting solution is alkaline.
pOH = -log[OH-]
POH = - log (0.67) = 0.17
As we know that,
PH + pOH = 14
pH = 14 – 0.17
= 13.83
Thus, we calculate that the pH of the resulting solution is 13.83.
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What is the expected markovnikov addition product from the addition of hi to 2-methyl-2-butene?.
Markovnikov addition product from the addition of hi to 2-methyl-2-butene is 2-iodo-2-mehtylbutane.
What is Markonikov rule?
In natural science, Markovnikov's standard or Markownikoff's standard portrays the result of some expansion responses. The standard was formed by Russian scientist Vladimir Markovnikov in 1870.Markovnikov's standard is an exact rule used to foresee regioselectivity of electrophilic expansion responses of alkenes and alkynes.Markovnikov predicts the results of an electrophilic expansion of hilter kilter reagents (for example hydrogen halides, water and alcohols) to hilter kilter alkenes.To learn more about Markonikov rule from the given link
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What happens to the kinetic energy of the particles in a sample of gas as
the temperature of the sample increases?
Answer:
See below
Explanation:
Temperature is basically a measure of the average kinetic energy of the particles in the sample ....so as temp goes up, kinetic energy increases
90cm3 of 1 m hcl solution and 10cm3 of 0.5 m naoh solution are mixed together. the concentration of hcl contained in the final solution
The concentration of HCl contained in the final solution is 0.95 M.
Calculation:Here, we use the dilution formula, which is,
M (V₁ + V₂) = M₁V₁ + M₂V₂
where,
M = resultant concentration
M₁ = concentration of HCl
V₁ = volume of HCl
M₂ = concentration of NaOH
V₂ = volume of NaOH
Given,
M₁ = 1 M
V₁ = 90 cm³ = 90 mL
M₂ = 0.5 M
V₂ = 10 cm³ = 10 mL
To find,
M =?
Put the values in the above formula,
M (V₁ + V₂) = M₁V₁ + M₂V₂
M (90 + 10) = (1 × 90) + (0.5 × 10)
M × 100 = 90 + 5
M × 100 = 95
M = 95/100
M = 0.95 M
Therefore, the concentration of HCl contained in the final solution is 0.95 M.
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Treatment of tetrahydrofuran with excess hbr results in the formation of what major organic product?
The treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .
THF which is tetrahydrofuran is reated with excess of HBr at 373 K .The product is 1,4-dibromobutane as a major organic product .
In the mechanism proton having positive charge is attack on electron rich oxygen and protonated it then bromine anion attack at adjacent carbon and break carbon - protonated oxygen bond and in he final step the hydroxyl group is protonated and remove as a water with attack at bromine anion .
Therefore , on treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .
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_________ is generally an intermolecular force, and __________ is only an intramolecular attractive force.
Hydrogen bonding is generally an intermolecular force, and covalent bonding is only an intramolecular attractive force.
When a hydrogen atom gets bound to a powerfully electronegative atom and is in close proximity to some other electronegative atom with such a single electron pairs, a hydrogen bond occurs as an intermolecular force (IMF).
The three types of intermolecular interactions include dipole-dipole, London dispersion, and hydrogen bonding forces. Metal bonds, ionic bonds, as well as covalent bonds are mostly the three types of intramolecular forces.
Therefore, Hydrogen bonding is generally an intermolecular force, and covalent bonding is only an intramolecular attractive force.
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Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.
Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.
What if you don't add it ?If hydroxide is not added, the NH₂ groups will get protonated by H⁺ ions present to give NH₃⁺ groups, which cannot react.
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If 38. 2 ml of a 0. 163 m KOH solution is required to neutralize 25. 0 ml of H2SO4 solution. Calculate the morality of the H2SO4 solution.
Answer:
.24 mol / liters
Explanation:
38. 2 ml = .0382 liters
.0382 liters times ( 0. 163 m KOH/1 liter) times ( 1 mol H2SO4/ 1 mol koh) =
.006/.025 liters = .24 mol / liters
chegg
The _______________________________ css3 property can be used to create multiple columns of text within a single element.
The column count property can be used to create multiple columns of text within a single element.
When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 600 k is equal to 1. 4×10^5j/mol. Calculate the equilibrium constant at 600 k.
The standard free energy change ΔG° at 600 K is equal to 1. 4×[tex]10^5[/tex]J/mol then the equilibrium constant at 600K is 0 .
Calculation ,
ΔG° = - RT㏑Kp
Where ΔG° = standard free energy change = 1. 4×[tex]10^5[/tex]J/mol
R = universal gas constant = 8.3 J / K mol
T = temperature = 600K
Kp = equilibrium constant
Now putting the value of all data in equation (i) we get ,
1. 4×[tex]10^5[/tex]J/mol = - 8.3 J / K mol × 600K ㏑Kp
- 1. 4×[tex]10^5[/tex]J/mol /8.3 J / K mol × 600K = ㏑Kp
㏑Kp = - 6972×[tex]10^5[/tex]
Kp = 0
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Which is an aspect of the kinetic-molecular theory and can be used to explain the compressibility of plasma
The answer choice which represents an aspect of the kinetic-molecular theory and can be used to explain compressibility of plasma is; Particles move independently of one another and are widely spaced.
What is the kinetic-molecular theory?The kinetic-molecular theory in discuss postulates about the states of matter.
Also, it is built upon the idea that matter is composed of tiny particles that are constantly in motion.
Hence, the theory is explanatory of the observable properties and behaviours of solids, liquids and gases and hence, explains the compressibility of plasma.
Remarks;
Particles move independently of one another and are widely spaced. Particle kinetic energy increases with increasing temperature. Particles exert no attractive or repulsive force on one another. Particles always move even when they have fixed positions.Read more on kinetic molecular theory;
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Examples of the surface area change the rate of chemical reactants applied in industry or products, materials?
What's the effect of surface area change
We know
Pressure is indirectly proportional to area
If surface area increases pressure decreasesIf pressure decreases volume increasesIf volume increases no of moles increasesSo production increases.A piece of wood near a fire is at 23°c. it gains 1,160 joules of heat from the fire and reaches a temperature of 42°c. the specific heat capacity of wood is 1.716 joules/gram degree celsius. what is the mass of the piece of wood?
The mass of the piece of wood is 35.58 g.
Joule = M × T × C
Where, M = mass
T = change in temperature(42C-23C=19 C)
C = specific heat capacity = 1.716 joules/gram
Substituting the values in the equation,
1160 = M × 19 × 1.716
M = 1160/32.604 = 35.58 g
Therefore, the mass of the piece of wood = 35.58 g
What is meant by specific heat capacity?A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)
What is mass?Mass is the quantity of matter in a physical body.
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What is the IUPAC name of the compound shown here?
Answer:
2-methylpropanoic acid
Explanation:
no probs chief
In an electric current, the ___ particles flow or are pushed along a path
positive
negative
neutral
Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility. the molar solubility is ___________ and the solubility is ____________
The molar solubility is 7.4×[tex]10^{-3}[/tex] M and the solubility is 7.4×[tex]10^{-3}[/tex] g/L .
Calculation ,
The dissociation of silver bromide is given as ,
[tex]AgBr[/tex] → [tex]Ag ^{+}[/tex] + [tex]Br^{-}[/tex]
S
- S S
Ksp = [[tex]Ag ^{+}[/tex] ] [ [tex]Br^{-}[/tex] ] = [S] [ S ] = [tex]S^{2}[/tex]
S = √ Ksp = √ 5. 5×[tex]10^{-5}[/tex] = 7.4×[tex]10^{-3}[/tex]
The solubility =7.4×[tex]10^{-3}[/tex] g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of [tex]AgBr[/tex] is dissociates and form one mole of each [tex]Ag ^{+}[/tex] and [tex]Br^{-}[/tex] ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4×[tex]10^{-3}[/tex] mol/L = 7.4×[tex]10^{-3}[/tex] M
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What type of reaction is a grignard reaction? What is the critical intermediate (which can be isolated and enables the final product)?
Organometallic Chemical reaction is a Grignard reaction. The critical intermediate (which can be isolated and enables the final product) is the formation of a carbon bond.
The Grignard Reaction is an organometallic chemical reaction that mostly produces C-C bonds. When organic molecules are combined with the Grignard reagent, the Grignard reaction occurs (Rmgx).
The Grignard Reaction is the conversion of an aldehyde or ketone into secondary or tertiary alcohol by the addition of an organomagnesium halide (Grignard reagent). A primary alcohol is produced when formaldehyde and oxygen react.
Alcohol and water molecules have acidic hydrogen atoms that Grignard reagents quickly react with. A proton substitutes the halogen in a Grignard reaction with water, producing an alkane as the end result. Therefore, the Grignard reagent offers a two-step process for changing a haloalkane into an alkane.
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C4h5n(aq) h2o(l)⇌c4h5nh (aq) oh−(aq) express your answers as chemical formulas. enter your answers in the order given in the question separated by commas
In aqueous solutions, the hydrogen ion, also known as the hydronium ion, is a Bronsted-Lowry acid, while the hydroxide ion is a base as a result of the self-dissociation reaction.
[tex]C_4H_5N(aq) + H_2O(l)[/tex] ⇄ [tex]C_4H_5NH (aq) + OH^-(aq)[/tex]
[tex]Bronsted-\\Lowry Acid[/tex] [tex]Conjugate Acid[/tex]
Brønsted–Lowry acid-base theory:Any species that may transfer a proton (H+) to another molecule is a Brnsted-Lowry acid. Any species that can take a proton from another molecule is a Brnsted-Lowry base. In essence, a Brnsted-Lowry base is a proton acceptor (PA) and an acid is a proton donor (PD).
According to the Arrhenius theory, acids are defined as chemicals that dissociate in an aqueous solution to produce hydrogen ions (H+), whereas bases are defined as substances that produce OH (hydroxide ions).
The hydrogen ion, or hydronium ion, is a Brønsted–Lowry acid in aqueous solutions, and the hydroxide ion is a base, by virtue of the self-dissociation reaction.
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What is the "average atomic mass" of this set of pennies.
(can you guys also include a formula on how i can solve future problems like this, please.)
Answer:
A. 2.74g is the correct answer
Explanation:
Greetings![tex]average \: mass = \frac{(mass \: pre - 1982 \times abundance) + (mass \: post - 1982 \times abundance}{100 } \\ ave = \frac{ (3.1g \times 40.0) + (2.5g \times 60.0)}{100} \\ ave = \frac{124 + 150}{100} \\ ave = \frac{274}{10} = 2.74g[/tex]
where, the sum of abundance always have to be 100%
Thus, 40.0 +60.0= 100.0
What is the binding energy of the electron in kj/molkj/mol? [note that keke = 12mv212mv2 and 1 electron volt (evev) = 1. 602×10−19j. 1. 602×10−19j. ]
The binding energy of the electron is 1.237 ×10^(-16) kj/ mol.
The given parameter
wavelength of photon,
λ = 0.999nm
= 0.999x10⁻⁹ m
K.E of emitted photon,
K.E = 940 ev
The binding energy of electron is calculated as follows:
From Einstein's mass defect equation=
ΔE = Δmc²
Also, from Einstein's photo electric equation=
E = Ф + K.E
Where;
Ф is binding energy of electron on metal surface.
The energy of on mole of electron, the emitted is calculated as:
[tex]E = hf =h \frac{c}{λ} = (6.626×10^{-34} ) × \frac{{3×10^{8} }}{0.999×10^{-9} } \\\\E= 1.989×10^{-16}[/tex]
The K.E of emitted electron in Joules is
[tex]K.E = 940 × \frac{1}{2} ×1.602 ×\ 10^{-19} J\\\\ = 0.752 × 10^{-16} J[/tex]
The binding energy is electron is calculated as:
[tex]Ф = E - K.E\\= (1.989 - 0.752) ×10^{-16}\\ =1.237 × 10^{-16} J[/tex]
Question: An X-ray photon of wavelength 0.999nm strikes a surface. The emitted electron has a kinetic energy of 940 eV. What isthe binding energy of the electron in kJ/mol? (KE=1/2mv2; 1 electron volt (eV) = 1.602 x10-19J)
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