Write a balanced equation for the following redox reaction using the oxidation number method:

Cl2 (g) + KI (aq) ---> I2 (s) + KCl (aq)

Answers

Answer 1

The balanced equation for the following redox reaction using the oxidation number method is as follows:

2K + 2I− + Cl 2 → I2 +2Cl− +2K+

What is a redox reaction?

A redox reaction in chemistry is a chemical reaction in which some of the atoms have their oxidation number changed.

According to this question, the following balanced chemical equation is given:

Cl2 (g) + KI (aq) → I2 (s) + KCl (aq)

The oxidation number of the ions in a redox reaction changes, and in this case, the ionic reaction is as follows:

2K + 2I− + Cl 2 → I2 + 2Cl− +2K+

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Related Questions

Consider the following reaction at 298K.
Pb2+ (aq) + Cu (s) Pb (s) + Cu2+ (aq)

Which of the following statements are correct?

Choose all that apply.
The reaction is product-favored.
delta G^o < 0
n = 4 mol electrons
K < 1
Eo cell < 0

Answers

The true statements are;

K < 0Eocel  < 0

What is a redox reaction?

We define a redox reaction as one in which a specie is oxidized and another is reduced.

Now;

Eo cell = cell potential = -0.13 V - (+0.34 V) = -0.47 V

n =number of moles of electrons = 2 mole of electrons

K = equilibrium constant

ΔG = change in free energy

Eo cell = 0.0592/n log K

-0.47 =  0.0592/2 log K

log K =  -0.47  * 2/0.0592

K = 1.3 * 10^-16

ΔG = -nFEo cell

ΔG = -(2 * 96500 * -0.47)

ΔG = 90.7kJ

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silver
nitrate
solution
A current was passed through the circuit shown in figure above. In the
experiment, 5.4 g of silver metal was discharged at the cathode in electrolysis cell
B. What mass of copper was discharged at the cathode in cell A?
[Molar mass: Ag = 108 gmol¹; Cu= 63.5 gmol ¹]

Answers

Answer:

Silver

Explanation:

What mass of copper was discharge at the cathode in a cell


Calculate the number of moles in 15 liters of oxygen at STP.
O 0.67 mol
O 67 mol
O 360 mol
O 1.5 mol

Answers

Answer:

.67 mole

Explanation:

Using ideal gas law

PV = n RT

P = pressure = 1 atm at STP

T = 273.15 K   at STP

V = 15 L

R = .082057  L-atm / K-mol

Subbing in those values:

1 (15) = n  (.082057) (273.15 )      results in n = .669 moles

1. Consider the unbalanced equation:

Al4C3 (s) + H2O (l) ---> Al(OH)3 (s) + CH4 (g)

How many moles of H2O are needed to react with 1.48 moles of Al4C3 ?

Hint: Write the balanced equation first

2.
Consider the balanced equation:

2 CH4 (g) + 3 O2 (g) + 2 NH3 ---> 2 HCN (g) + 6 H2O (g)

If 203.6 g of NH3 is reacted with excess CH4 and O2, what mass in grams of HCN is produced?

Answers

Answer:

1.) 17.76 moles H₂O

2.) 323.1 g HCN

Explanation:

1.) An equation is balanced when there is an equal amount of each element on both sides of the reaction. The quantities can be modified by adding coefficients in front of the molecules.

The unbalanced equation:

Al₄C₃(s) + H₂O -----> Al(OH)₃(s) + CH₄(g)

Reactants: 4 aluminum, 3 carbon, 2 hydrogen, 1 oxygen

Products: 1 aluminum, 1 carbon, 7 hydrogen, 3 oxygen

The balanced equation:

Al₄C₃(s) + 12 H₂O -----> 4 Al(OH)₃(s) + 3 CH₄(g)

Reactants: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen

Products: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen

Now that the equation is balanced, you can use the relevant coefficients to construct a mole-to-mole ratio. This will allow you to convert between moles Al₄C₃ to moles H₂O.

 1.48 moles Al₄C₃           12 moles H₂O
----------------------------  x  ------------------------  =  17.76 moles H₂O
                                         1 mole Al₄C₃

2.) To find the mass of HCN, you need to (1) convert grams NH₃ to moles NH₃ (via molar mass), then (2) convert moles NH₃ to moles HCN (via mole-to-mole from equation coefficients), and then (3) convert moles HCN to grams HCN (via molar mass). It is important to arrange the coefficients in a way that allows for the cancellation of units.

Molar Mass (NH₃): 14.009 g/mol + 3(1.008 g/mol)

Molar Mass (NH): 17.033 g/mol

Molar Mass (HCN): 1.008 g/mol + 12.011 g/mol + 14.009 g/mol

Molar Mass (HCN): 27.028 g/mol

2 CH₄(g) + 3 O₂(g) + 2 NH₃(g)  ------> 2 HCN(g) + 6 H₂O(g)

203.6 g NH₃            1 mole            2 moles HCN           27.028 g
---------------------  x  ----------------  x  ------------------------  x  -----------------  =
                                17.033 g           2 moles NH₃             1 mole

=  323.1 g HCN

Ideal Gas Law: Tutorial. At a party, you use a gas canister to fill balloons. The canister holds 4.47 moles of air. If the room is at 26.0°C and the gas pressure is 855 kilopascals, what is the volume of the canister? The volume of the canister is ___ liters. Type the correct answer in the box. Express your answer to the correct number of significant figures. Use the gas laws Fact sheet to help you.​

Answers

Answer:

13.0 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (kPa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and simplify to find "V". The final answer should have 3 sig figs to match the sig figs of the given values.

P = 855 kPa                                  R = 8.314 kPa*L/mol*K

V = ? L                                           T = 26.0 °C + 273.15 = 299.15 K

n = 4.47 moles

PV = nRT

(855 kPa)V = (4.47 moles)(8.314 kPa*L/mol*K)(299.15 K)

(855 kPa)V = 11117.48496

V =  13.0 L

At the equivalence point of a titration of the [H+] concentration is equal to:
Group of answer choices

A. 1 x 107 M

B. 7

C. [OH-]

D. 1 x 10-7 M

Answers

B. At the equivalence point of a titration of the [H+] concentration is equal to 7.

What is equivalence point of a titration?

The equivalence point of a titration is a point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution.

At the equivalence point in an acid-base titration, moles of base equals moles of acid and the solution only contains salt and water.

At the equivalence point, equal amounts of H+ and OH- ions combines as shown below;

H⁺ + OH⁻  → H₂O

The pH of resulting solution is 7.0 (neutral).

Thus, the pH at the equivalence point for this titration will always be 7.0.

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Why does direct titration of aspirin with NaOH have a side reaction and how to prevent it?

Answers

Direct titration of aspirin with NaOH have a side reaction simply because aspirin is a weak acid

What is direct titration?

Direct titration can simply be defined as a type of titration in which a titrant of known concentration and volume is added to a substance in order to analyze it.

As the name implies, it is called direct titration simply because the one approaches the endpoint of the experiment directly.

Furthermore, the significance of direct titration is that it is used to find the quantity of a substance within a solution with chemical reactions.

So therefore, direct titration of aspirin with NaOH have a side reaction simply because aspirin is a weak acid

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Select the correct answer. A ball hits a wall. What is true about the magnitude of the force experienced by the ball compared with the force experienced by the wall? A. The ball experiences more force than the wall. B. The ball experiences less force than the wall. C. The ball and the wall experience the same force. D. The ball experiences half the force of the wall.

Answers

Answer:

C

Explanation:

For every action there is an equal but opposite reaction..... the forces are the same

The ball hits the wall at the same force, so the answer would be, C.)!

What is the
molality of 30g of NACI dissolved in 350g of water

Answers

Answer:

1.45 mol/kg

Explanation:

nilered videos

Answer:

1.47 m

Explanation:

The molality can be found using the following equation:

Molality = moles solute / mass (kg) solvent

In this case, NaCl is the solute and H₂O is the solvent. To find the molality, you need to (1) convert grams NaCl to moles (via the molar mass), then (2) convert grams H₂O to kilograms, and then (3) calculate the molality.

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

 30 grams NaCl                 1 mole
--------------------------  x  ------------------------  =  0.513 moles NaCl
                                      58.443 grams

(Step 2)

1,000 grams = 1 kg

350 grams H₂O                   1 kg
--------------------------  x  -----------------------  =  0.35 kg H₂O
                                      1,000 grams

(Step 3)

Molality = moles solute / mass (kg) solvent

Molality = 0.513 moles NaCl / 0.35 kg H₂O

Molality = 1.47 m

Question 6(Multiple Choice Worth 5 points)
(08.01 LC)
Which of the following is a property of water?
It can freeze very fast.
OIt has low heat capacity.
It exists in all three states on Earth.
It repels other water molecules.

Answers

The property of water is that It exists in all three states on Earth.

The major residences to be able to be mentioned in this text are its appeal to polar molecules, its high specific warmth, the excessive warmness of vaporization, the decrease density of ice, and its high polarity.

The primary homes of water are its polarity, concord, adhesion, floor anxiety, excessive unique warmth, and evaporative cooling. A water molecule is barely charged on each ends. this is because oxygen is more electronegative than hydrogen.

Water is good sized functionality to dissolve a ramification of molecules has earned it the designation of “standard solvent,” and it's far this capacity that makes water such an invaluable life-sustaining pressure. On a biological level, water's role as a solvent facilitates cells transport and use substances like oxygen or vitamins.

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What is an expression of Boyle's law (k = constant)?
A. V/T=K
B. V = kn
C. PV = k
D. Ptotal= P₁ + P₂ + P3 + &

Answers

Answer:

C.) PV = k

Explanation:

Boyle's Law is a variation of the Ideal Gas Law when all variables, except for pressure and volume, are held constant.

Pressure is represented by "P" and volume is represented by "V". In the Ideal Gas Law, pressure and volume are inversely proportional (if one goes up, the other goes down). That being said, the equation which best represents Boyle's Law is PV = k.

If 1.240g of carbon dioxide dissolves in 1.01L of water at 755mmHg, what quantity of carbon dioxide in grams will dissolve at 790mmHg?

Answers

Taking into account the Henry's Law, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.

Henry's Law

A change in pressure does not appreciably influence the solubility of solids or liquids or liquids in liquids; however, that of gases in solvents increases when the partial pressure of the gases increases. The solubility of a gas depends on pressure and temperature.

In this way, Henry's Law describes the effect of pressure on the solubility of gases. This law states that the solubility of a gas in contact with the surface of a liquid at a given temperature is directly proportional to the partial pressure of said gas on the liquid.

Mathematically, Henry's law is expressed as:

C=k×P

Where:

P is the partial pressure of the gas.C is the concentration of the gas.k is Henry's constant, which depends on the nature of the gas, the temperature, and the liquid.

At 2 different partial pressure values, the Henry's law is expressed as:

[tex]\frac{C1}{C2} =\frac{P1}{P2}[/tex]

Quantity of carbon dioxide

In this case, you know:

C₁ = [tex]\frac{1.240 g}{1.01 L}[/tex] =1.228 [tex]\frac{g}{L}[/tex]C₂ = ?P₁ = 755 mm HgP₂ = 790 mm Hg

Replacing in Henry's Law:

[tex]\frac{1.228\frac{g}{L} }{C2} =\frac{755 mmHg}{790mmHg}[/tex]

Solving:

[tex]1.228\frac{g}{L} =\frac{755 mmHg}{790mmHg}xC2[/tex]

C2= [tex]\frac{1.228\frac{g}{L} }{\frac{755 mmHg}{790mmHg}}[/tex]

C2= 1.285 [tex]\frac{g}{L}[/tex]

Then, the concentration of carbon dioxide at 790 mmHg is 1.285 g/L. But you have 1.01 L of water. So the amount of gas dissolved can be calculated as 1.01 L×1.285 g/L = 1.297 g

Finally, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.

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What mass (g) of calcium chloride, CaCl2, is needed to prepare 2.451 L of a 1.56 M solution

Answers

Answer:

424 grams CaCl₂

Explanation:

To find the mass of CaCl₂, you need to (1) calculate the moles (using the molarity ratio) and then (2) convert moles to grams (using the molar mass). The final answer should have 3 sig figs to match the given value with the least amount of sig figs.

(Step 1)

Molarity (M) = moles / volume (L)

1.56 M = moles / 2.451 L

3.82 = moles

(Step 2)

Molar Mass (CaCl₂): 40.078 g/mol + 2(35.453 g/mol)

Molar Mass (CaCl₂): 110.984 g/mol

3.82 moles CaCl₂           110.984 g
----------------------------  x  -------------------  =  424 grams CaCl₂
                                          1 mole

Determine the acid dissociation constant (Ka) for a 0.200 M solution of hydrogen sulfate ion with
the pH of 1.35 if the reaction for the dissociation of this acid is
HSO 4 →→ H+ + SO 4-²
(Hint: [H+] = 10-PH; Ka = [product]/[reactant])

Answers

The acid dissociation constant(Ka) is 0.0095

The reaction for this dissociation of acid is

HSO4 ⇄H+ + SO4 -2

The dissociation constant can be determined from the following expression

[tex]Ka= \frac{[H+] [SO4]-2}{[HSO4}[/tex]  

[H+] = 10-PH

       = 10-1.35

[H+]  = 0.0447

[H+] = 0.0447 mol / L

From equation, [H+] = [SO4-2] = 0.0447 mol / L

[SO4-2] = 0.0447 mol / L

From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,

Ka = 0.0447 * 0.0447 / 0.200

     = 0.0019 / 0.200

     = 0.0095

Hence the value of the acid dissociation constant (Ka) for the given reaction is  0.0095

                           

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Find the amount of heat energy needed to convert 400 grams of ice at -38°C to steam at 160°C.
Group of answer choices

A. 246840 Joules

B. 159984 Joules

C. 331056 Joules

D. 1284440 Joules

Answers

The amount of heat energy needed to convert 400 g of ice at -38 °C to steam at 160 °C is 1.28×10⁶ J (Option D)

How to determine the heat required change the temperature from –38 °C to 0 °C Mass (M) = 400 g = 400 / 1000 = 0.4 KgInitial temperature (T₁) = –25 °C Final temperature (T₂) = 0 °Change in temperature (ΔT) = 0 – (–38) = 38 °C Specific heat capacity (C) = 2050 J/(kg·°C)Heat (Q₁) =?

Q = MCΔT

Q₁ = 0.4 × 2050 × 38

Q₁ = 31160 J

How to determine the heat required to melt the ice at 0 °CMass (m) = 0.4 KgLatent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/KgHeat (Q₂) =?

Q = mL

Q₂ = 0.4 × 334000

Q₂ = 133600 J

How to determine the heat required to change the temperature from 0 °C to 100 °C Mass (M) = 0.4 KgInitial temperature (T₁) = 0 °C Final temperature (T₂) = 100 °CChange in temperature (ΔT) = 100 – 0 = 100 °C Specific heat capacity (C) = 4180 J/(kg·°C)Heat (Q₃) =?

Q = MCΔT

Q₃ = 0.4 × 4180 × 100

Q₃ = 167200 J

How to determine the heat required to vaporize the water at 100 °CMass (m) = 0.4 KgLatent heat of vaporisation (Hv) = 2260 KJ/Kg = 2260 × 1000 = 2260000 J/KgHeat (Q₄) =?

Q = mHv

Q₄ = 0.4 × 2260000

Q₄ = 904000 J

How to determine the heat required to change the temperature from 100 °C to 160 °C Mass (M) = 0.4 KgInitial temperature (T₁) = 100 °C Final temperature (T₂) = 160 °CChange in temperature (ΔT) = 160 – 100 = 60 °C Specific heat capacity (C) = 1996 J/(kg·°C) Heat (Q₅) =?

Q = MCΔT

Q₅ = 0.4 × 1996 × 60

Q₅ = 47904 J

How to determine the heat required to change the temperature from –38 °C to 160 °CHeat for –38 °C to 0°C (Q₁) = 31160 JHeat for melting (Q₂) = 133600 JHeat for 0 °C to 100 °C (Q₃) = 167200 JHeat for vaporization (Q₄) = 904000 JHeat for 100 °C to 160 °C (Q₅) = 47904 JHeat for –38 °C to 160 °C (Qₜ) =?

Qₜ = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Qₜ = 31160 + 133600 + 167200 + 904000 + 47904

Qₜ = 1.28×10 J

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How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)2?

Answers

The number of mole of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)₂ is 0.000004 mole

What is molarity?

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

With the above formula, we can determine the number of mole present in the solution. Detail below:

How to determine the mole of the solute in the solutionVolume of solution = 1 mL = 1 / 1000 = 0.001 LMolarity of solution = 0.004 MMole of solute =?

Molarity = mole / Volume

Cross multiply

Mole = Molarity × volume

Mole of solute = 0.004 × 0.001

Mole of solute = 0.000004 mole

Thus, the mole of the solute in the solution is 0.000004 mole

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You have 250.0 mL of 4.00 M sugar solution. You add 332.4 mL of water to this solution.

Determine the concentration of the sugar solution after the water has been added

Answers

Answer:

1.72 M

Explanation:

To find the new molarity, you need to (1) convert both volumes from mL to L, then (2) calculate the moles (using the molarity equation), and then (3) calculate the new molarity (using the new volume and molarity equation). The final answer should have 3 sig figs.

(Step 1)

1,000 mL = 1 L

250.0 mL / 1,000 = 0.250 L

332.4 mL / 1,000 = 0.3324 L

(Step 2)

Molarity = moles / volume (L)

4.00 M = moles / 0.250 L

1.00 = moles

(Step 3)

New Volume = 0.3324 L + 0.250 L = 0.5824 L

Molarity = moles / volume

Molarity = 1.00 moles / 0.5824 L

Molarity = 1.72 M

Heating up a reaction does which of the following:
Group of answer choices

A. Increases the number of collisions as well as the strength of the collision

B. Increases the strength of the collisions only.

C. Increases the number of collisions only.

D. No effect is found on the reaction by increasing the temperature.

Answers

Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

What is Collision Theory ?  

According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.

The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.

How temperature affect the collision theory ?

With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.

Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

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write three disadvantages of hard water.​

Answers

The three disadvantages of hard water are:

1. Hard water is unsuitable for washing because soap does not readily create a lather in it.

2. Soap may react and produce, wasting the soap.

3. Due to the development of calcium and magnesium carbonates, tea kettles will get furred.

Hard water

Water that contains a lot of minerals is referred to as hard water. In limestone, chalk, or gypsum deposits, which are mostly composed of calcium and magnesium carbonates, bicarbonates, and sulphates, hard water is created as a result of percolation. A moderate health advantage from drinking hard water is possible. In industrial settings where water hardness is regulated to prevent expensive breakdowns in boilers, cooling towers, and other water-handling equipment, it can present serious issues. Hard water is frequently detected in home settings by the build-up of lime scale in kettles and water heaters as well as by the absence of foam when soap is agitated in water. Wherever there is a worry about water hardness, water softening is frequently employed to lessen the negative impacts of hard water.

write three disadvantages of hard water.​

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Which of these is an example of a physical property? A. Iron rusts when exposed to air. B. Table salt is a white crystal. C. Sodium oxidizes in air. D. Potassium ignites when placed in water.


Answers

Table salt is a white crystal.

Explanation:

Iron rusts when exposed to air,Sodium oxidizes in air,Potassium ignites when placed in water.These all are irreversible reaction .

What is physical change ? When a substance change its physical state No new chemical is formedExamples :- Boling of water, melting of solids, shredding of paper.

what does it mean Emphasis on object vs woman

Answers

Emphasis on object vs woman simply means s- e- x- ual objectification

This goes to say that it emphasizes seeing women as objects of se- xu- al pleasure

What is objectification?

Objectification simply refers to the act of treating or viewing a person as an object, devoid of thought or feeling.

Most of the time, objectification is targeted at women and reduces them to objects of se- xu- al pleasure

So therefore, emphasis on object vs woman simply means se- xu- al objectification

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The isotope sodium-24 has a half-life of 15 hours. Starting with 22 grams, how much remains in 30
hours?

Answers

Answer:

5.5 grams

Explanation:

To find how much of the isotope remains, you need to use the half-life equation:

[tex]N(t) = N_0(\frac{1}{2})^\frac{t}{h}[/tex]

In this equation,

-----> N(t) = remaining mass (g)

-----> N₀ = initial mass (g)

-----> t = time (hrs)

-----> h = half-life (hrs)

You can find the remaining mass by plugging the given values into the equation and solving.

N(t) = ? g                          t = 30 hrs

N₀ = 22 g                         h = 15 hrs

[tex]N(t) = N_0(\frac{1}{2})^\frac{t}{h}[/tex]                                         <----- Half-life equation

[tex]N(30) = (22)(\frac{1}{2})^\frac{30}{15}[/tex]                                    <----- Insert values

[tex]N(30) = (22)(\frac{1}{2})^2[/tex]                                      <----- Simplify exponent

[tex]N(30) = (22)(0.25)[/tex]                                   <----- Solve [tex](\frac{1}{2} )^2[/tex]

[tex]N(30) = 5.5[/tex]                                              <----- Multiply 22 and 0.25

The value of the entropy change for the process N₂ (g) + 3H₂ (g) --> 2NH₃ (g) is ________.


positive


unchanged


zero


negative

Answers

Answer:

negative

Explanation:

Entropy is a measure of the "disorder" in a system.

In this reaction, the amount of disorder decreases. This is because one gas molecule (NH₃) has more order than two gas molecules (N₂ and H₂). Therefore, the entropy change should be negative.

PLS
PLA HELP WOTH THIS CHEMISTRY WORK!!!

Answers

If you need help in the rest lmk

What is the amount of energy required to raise the temperature of 150 grams of aluminum by 10°C?
Group of answer choices

A. 13.45 J

B. 0.897 J

C. 1345.5 J

D. 4.18 J

Answers

Answer:

C.) 1345.5 J

Explanation:

To find the energy, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of aluminum is 0.89 J/g°C. You can plug the given values into the equation and solve.

Q = mcΔT

Q = (150 g)(0.89 J/g°C)(10 °C)

Q = 1335

*It is up to you whether you wish to trust this answer. My answer may be slightly different due to using a different specific heat.

Which of the following is NOT an example of a colligative property?
Group of answer choices

A. Salt is added to ice to make homemade ice cream.

B. Salt is added to roads before a snow storm.

C.Antifreeze is added to a radiator of a car.

D. Salt water dehydrates someone that drinks it.

Answers

Salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).

What are Colligative Properties?

Colligative Properties make reference to physical properties associated with solute concentration instead of its intrinsical characteristics.

Some examples of colligative properties include boiling state, vapour pressure, and osmotic pressure due to the presence of ionic particles.

In conclusion, salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).

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28. What mass
0.120M HCI?
of Na₂CO3 (Molar Mass = 106.0 g/mol) is required to react completely with 21.6 mL of.

Answers

Mass of [tex]$\mathrm{Na}{2} \mathrm{CO} 3$[/tex] required [tex]$=0.55 \mathrm{~g}$[/tex]

What is meant by molar mass?The mass of one mole of a sample is its molar mass. Add the atomic masses (atomic weights) of all the atoms in the molecule to obtain the molar mass. Using the mass listed in the Periodic Table or atomic weights table, determine the atomic mass for each element.The total mass of all the atoms that make up a mole of a specific molecule, measured in grams, is known as the molar mass or molecular weight. The measurement is made in grams per mole.Molar mass is a crucial factor to consider while planning an experiment. The molar mass enables you to calculate the quantity you should weigh on your scale if you are testing theories involving precise amounts of a substance. Take a look at an experiment that needs 2 moles of pure carbon as an illustration.

The mass 0.120M HCI:

Moles of [tex]$\mathrm{HCl}$[/tex]reacted [tex]$=0.120 \times 21.6 / 1000=0.00260$[/tex]

according to balanced reaction, [tex]$\mathrm{HCl}$ and $\mathrm{Na} 2 \mathrm{CO} 3$[/tex] reacts in [tex]$2: 1$[/tex] the ratio

moles of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.00260 \times 2=0.00520$[/tex]

convert moles to mass

mass [tex]$=$[/tex]moles [tex]$\times$[/tex]molar mass

mass [tex]$=0.00520 \times 106.0$[/tex]

mass [tex]$=0.55 \mathrm{~g}$[/tex]

mass of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.55 \mathrm{~g}$[/tex]

Mass 0.120M HC is [tex]$=0.55 \mathrm{~g}$[/tex]

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What is an alkaline

Answers

Answer:

is a solution whose pH is above 7or is a basic solution

An alkaline that has a pH scale above 7
It’s between 8-14, for example and alkaline could be our blood which has the pH of 7.4

What volume of a 0.550 M solution of potassium hydroxide (KOH) can be made with 19.9 g of potassium hydroxide?

Answers

Answer:

0.645 L

Explanation:

To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (KOH): 56.104 g/mol

19.9 grams KOH              1 mole
--------------------------  x  -----------------------  =  0.355 moles KOH
                                     56.014 grams

(Step 2)

Molarity = moles / volume                            <----- Molarity ratio

0.550 M = 0.355 moles / volume                 <----- Insert values

(0.550 M) x volume = 0.355 moles              <----- Multiply both sides by volume

volume = 0.645 L                                          <----- Divide both sides by 0.550


What is the chemical symbol of the terminal atom in the lewis structure of OH- ?

Answers

Answer:

kindly refer to the picture attached

Explanation:

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