Zn(aq)²⁺+OH⁻→Zn(OH)[tex]_2[/tex] is a balanced net ionic equation for the given reaction. A chemical equation describing a process known as the net ionic formula.
A chemical equation describing a process known as the net ionic formula only includes the species that are really involved in the reaction. In double displacement processes, redox reactions, and acid-base neutralisation reactions, a net ionic equation is utilised frequently. In other words, processes involving strong electrolytes within water are covered by the net ionic equation.
Zn(aq)²⁺+NO[tex]_3[/tex]⁻ + Na⁺+OH⁻→Zn(OH)[tex]_2[/tex]+Na⁺+NO[tex]_3[/tex]⁻
Zn(aq)²⁺+OH⁻→Zn(OH)[tex]_2[/tex]
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Which aqueous solution below is the most acidic?
A.) 11.5 B.) 9.2 C.) 6.7 D.) 2.5
HI is the aqueous solution which is the most acidic. Any aqueous solution in chemistry can be divided into one of three groups, including neutral, basic, or acidic solutions.
Any aqueous solution in chemistry can be divided into one of three groups, including neutral, basic, or acidic solutions. Any aqueous solution with a pH 7.0 ([H+] > 1.0 x 10-7 M) is considered an acidic solution.
Water serves as the solvent in an aqueous solution. Solutions that are acidic are sour, whereas alkaline solutions are soapy, thus it's rarely a good idea to try an unfamiliar solution. HI is the aqueous solution which is the most acidic.
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A sample of an ideal gas has a volume of 2.35L at 2.90x10^2 K and 1.09 atm. Calculate the pressure when the volume is 1.59L and the temperature is 306K
If HCl, HNO3, and NaOH solutions were prepared at higher concentrations, will it affect the experimental results? Will the change in concentration make the measurement more accurate or less accurate? Please explain your answers in detail.
If HCl, HNO3, and NaOH solutions were prepared at higher concentrations, the change in concentration will make the measurement more accurate.
Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume. Mass concentration, concentration in moles, numerical concentration, or volume concentration are four different categories of mathematical description.
Any type of chemical mixture can be referred to by the term "concentration," however solvents and solutes in solutions are most usually mentioned. If HCl, HNO3, and NaOH solutions were prepared at higher concentrations, the change in concentration will make the measurement more accurate.
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Complete the input-output table for the linear function y = 3x.
x y
-2
-1
0
1
2
3
a=
a
ماس
-3
0
3
b
С
b=
C=
Which statement most likely describes the formation of dunite?
OA. It formed when sediment was cemented together at the bottom of
a lake.
OB. It formed when magma cooled slowly below ground.
OC. It formed when lava cooled quickly aboveground.
OD. It formed when layers of rock deep underground experienced heat
and pressure.
The formation of dunite is most likely to be described by option (B) "It formed when magma cooled slowly below ground."
Dunite is an igneous rock that is composed almost entirely of olivine minerals. It is believed to form from magma that is rich in magnesium and poor in silica.
As the magma cools slowly beneath the Earth's surface, the olivine crystals have time to grow and settle out, forming a rock that is dominated by olivine.
Option (A) is more likely to describe a sedimentary rock, formed by the compaction and cementation of sediment. Option (C) is more likely to describe an extrusive igneous rock, formed from lava that cools quickly above the ground.
Option (D) is more likely to describe the formation of metamorphic rock, which is formed from existing rock that has been subjected to heat and pressure.
Hence Option B, describes the formation of dunite.
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How do Winds Form?
Helps
help for 1 though 7 pls
Answer:
Explanation:
1/ I
2/ III
3/ V
4/ II
5/ IV
6/ 5
7/ 55
Using the formula for the ideal gas law and the value for the gas law constant of 0.08206 L.atm/K/mol, what is the volume (in L) of 9.84 grams of dry hydrogen at 23.4 degrees C and 757 torr?
A sample of gas is in a steel container at -75,0° Cand 1.480 atm. What pressure will the sample have
when the temperature is changed to 1000.0°C?
The pressure of the gas when the temperature changes from -75.0°C to 1000.0°C will be approximately 9.51 atm.
What is the final pressure of the gas?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
Given that:
Initial pressure P₁ = 1.480 atmInitial temperature T₁ = -75.0°C = ( -75.0 + 273.15 ) = 198.15 KInitial temperature T₂ = 1000.0°C = (1000.0 + 273.15) = 1273.15 KFinal pressure P₂ = ?We substitute our values into the expression above.
P₁/T₁ = P₂/T₂
P₁T₂ = P₂T₁
[tex]P_2 = \frac{P_1T_2}{T_1}\\ \\P_2 = \frac{1.480\ *\ 1273.15 }{198.15} \\\\P_2 = 9.51 \ atm[/tex]
Therefore, the final pressure is 9.51 atm.
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A sample of 23.3 g of a candy bar was burned in a calorimeter. The calorimeter was calibrated to have a heat capacity of 8.72 kcal/ °C. The heat released caused the temperature of the calorimeter to increase 15.5 °C.
Calculate the food caloric content of the candy bar in nutritional calories per gram to three significant figures. Recall that 1 nutritional calorie (Cal) = 1 kcal.
The food caloric content of the candy bar in nutritional calories per gram is 135 Cal.
Calorimeter is used to measure the amount of heat energy (Q) produced during a certain reaction. It depends on the mass of the substance (m), heat capacity (c) and the change in temperature (ΔT) during the process.
Mathematically it could be represented as,
[tex]\rm Q\ =\ m\times c\times \Delta\ T[/tex]
[tex]\rm =\ 23.3\times 8.72\times 15.5[/tex]
[tex]\rm = 3149.228\ kcal[/tex]
The heat released during the process is 3149.228 kcal.
To calculate the nutritional calories per gram, divide the heat released by the mass in grams.
[tex]\rm Calories\ per\ gram\ = \frac{3149.228}{23.3}[/tex]
[tex]\rm = 135.16\ kcal[/tex]
[tex]\rm = 135\ Cal[/tex]
Therefore, The food caloric content of the candy bar in nutritional calories per gram is 135 Cal.
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amplify science essay about rain
An unknown liquid has a heat of vaporization of 32.45 kJ/mole. If the normal boiling point is 84, what is vapor pressure (in torr) of this liquid at room temperature of 25 degrees C? HINT: Normal boiling point occurs when the vapor pressure of the liquid is the same as atmospheric pressure (1 atm or 760 mm Hg).
If 335 g of water at 65.5 °C loses 9750 J of heat,
what is the final temperature of the water? Liquid
water has a specific heat of 4.18 J/(g*°C).
Answer:
We can use the formula for heat lost by a substance to calculate the final temperature:
Q = m * c * ΔT
where Q is the heat lost, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
In this case, we know the values of Q, m, and c, and we need to find ΔT. Rearranging the formula, we have:
ΔT = Q / (m * c)
Substituting the given values, we get:
ΔT = 9750 J / (335 g * 4.18 J/(g*°C)) ≈ 6.9 °C
Therefore, the final temperature of the water is:
65.5 °C - 6.9 °C ≈ 58.6 °C
So the final temperature of the water is approximately 58.6 °C.
The final temperature of the water is approximately 58.5°C.
To find the final temperature of the water, we first need to understand that the heat lost by the water is calculated using the formula q = mcΔT, where 'q' is the Heat Transfer, 'm' is the mass of the water, 'c' is the specific heat of the water, and 'ΔT' is the change in temperature.
First, rearrange the formula to find ΔT = q/(mc).
Then, insert the given values (q = -9750 J, m = 335 g, c = 4.18 J/g°C).
The negative sign denotes heat loss.
You will find ΔT is approximately -7°C.
This is the amount the temperature decreases.
Subtract ΔT from the initial temperature of the water (65.5°C - 7°C), to get the final temperature of approximately 58.5°C.
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50 POINTS Help me out PLS
The calculated heat of fusion would be lower than the actual. Option B
What is the heat of fusion?If water is added to the calorimeter while measuring heat of fusion, the computed heat of fusion value will be lower. This is because some of the heat energy released during the transition from a solid to a liquid will be absorbed by the water and not taken into account in the calculation.
To avoid this problem, make sure that no water gets into the calorimeter during the experiment as shown in the image.
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Most of the export products of Papua New Guinea are from extractive industries which are non-renewable. What steps has the government initiated so that revenue will not be diminished after all the natural resources have been exploited ?
Managing a Precarious Recovery examines significant recent economic changes in PNG and places them in a longer-term, global context.
Economic Update for Papua New Guinea: Managing a Precarious Recovery examines significant recent economic changes in PNG and places them in a longer-term, global context. According to the research, the economy recovered to an increase of 1% in 2021 after shrinking by 3.5% in 2020.
The Porgera gold mine's anticipated reopening is anticipated to be the primary driver of the extractive sector's four percent contribution to GDP growth in 2022. The analysis does predict that increased global uncertainty will have an influence on PNG's overall medium-term growth.
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Suppose you heat a metal object with a mass of 34.5 g to 95.5 °C and transfer it to a calorimeter containing 100.0 g of water at 17.5 °C. The water and metal reach a final temperature of 24.9 °C.
Metal in a covered cup with a thermometer and heat indicated as leaving the metal.
What is the specific heat of the metal in J/g⋅∘C
Zinc + hydrochloric acid yields zinc chloride and hydrogen gas. (Zinc has a +2 charge).
Label what type of reaction (synthesis, decomposition, single replacement, double replacement or combustion)
Write the balanced chemical equation
How much of each reactant is needed to produce 150 grams of hydrogen gas?
Pleace help I need to do it for today but I dint know how dont splaind just do the work pleace thank you
Zn + 2HCl→ ZnCl[tex]_2[/tex] + H[tex]_2[/tex] is the balanced chemical equation for Zinc + hydrochloric acid → zinc chloride + hydrogen gas.
A chemical reaction involves a procedure that causes one group of chemical components to change chemically into another. Chemical bonds among atoms are formed and broken during chemical reactions, which traditionally only involve changes in the locations of electrons.
The study of chemical processes involving unstable and radioactive elements, where both electronic or nuclear changes may take place, is known as nuclear chemistry.
Zinc + hydrochloric acid → zinc chloride + hydrogen gas.
Zn + 2HCl→ ZnCl[tex]_2[/tex] + H[tex]_2[/tex]
This is a single replacement reaction
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The Haber process combines Nitrogen gas and Hydrogen gas at 550°C and 250 ATM in a process that produces only Ammonia by the equation shown below.
(Gas stoichiometry problem)
H2 + N2 yields NH3
Determine how many liters of hydrogen at STP would be required to produce 1.00 kg of ammonia.
1,275 liters of hydrogen gas at STP would be required to produce 1.00 kg of ammonia in the Haber process.
The first step is to use the balanced chemical equation to find the mole ratio of hydrogen to ammonia: 1 mol H2 : 1 mol
Next, we need to find the number of moles of ammonia produced from 1.00 kg: 1.00 kg x (1000 g/kg) x (1 mol /17.03 g NH3) = 58.7 mol NH3
Now we can use the mole ratio to find the number of moles of hydrogen required: 58.7 mol NH3 x (1 mol H2/1 mol ) = 58.7 mol H2
Finally, we can use the ideal gas law to find the volume of hydrogen at STP (standard temperature and pressure, 0°C and 1 atm) that would contain 58.7 moles: PV = nRT
(1 atm) V = (58.7 mol) (0.08206 L atm/mol K) (273.15 K)
V = 1,275 L
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Summarize the main challenges and constraints that engineers must overcome in the design of a low-cost, portable water purification system.
Engineers must take into account the cultural, social, and economic factors that may affect the adoption and sustainability of the system in the target communities.
The main challenges and constraints that engineers must overcome in the design of a low-cost, portable water purification system include:
Designing a water purification system that meets these challenges and constraints requires careful consideration of the materials, technology, and resources available.
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2. Propane + oxygen yields carbon dioxide and water
Label what type of reaction (synthesis, decomposition, single replacement, double replacement or combustion)
Write the balanced chemical equation
How much propane would you need to produce 1000.0 grams of water?
pleace help i need to do all the work dont splaind just do the work pleace
C[tex]_3[/tex]H[tex]_8[/tex](g) + 5O[tex]_2[/tex] (g) → 3CO[tex]_2[/tex] (g) + 4H[tex]_2[/tex]O(g) is the balanced chemical equation for Propane + oxygen →carbon dioxide +water.
A chemical reaction involves a procedure that causes one group of chemical components to change chemically into another. Chemical bonds among atoms are formed and broken during chemical reactions, which traditionally only involve changes in the locations of electrons.
The study of chemical processes involving unstable and radioactive elements, where both electronic or nuclear changes may take place, is known as nuclear chemistry.
Propane + oxygen →carbon dioxide +water
C[tex]_3[/tex]H[tex]_8[/tex](g) + 5O[tex]_2[/tex] (g) → 3CO[tex]_2[/tex] (g) + 4H[tex]_2[/tex]O(g)
This is a single combustion reaction
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970 g of tetraphosphorus decoxide was extracted from 5.3 x 10^24 formula units of phosphate- containing rocks, Ca 3 (PO4) 2. by reacting this with excess silicon dioxide found in sand.
Calculate the % yield of this reaction. 2Ca3 (PO 4 ) 2 +6SiO →6CaSiO 3 +P 4 0 10
I
To determine the percent yield of this reaction, divide the amount of product produced (970 g of tetraphosphorus decoxide) by the amount of reactant consumed (5.3 x 1024 formula units of Ca3 (PO4) 2).
The yield is 0.0000182% as a consequence. This suggests that only 0.0000182% of the product (970 g of tetraphosphorus decoxide) was created for every 5.3 × 1024 formula units of Ca3 (PO4) 2.
This is an extremely low yield, suggesting that the reaction was inefficient.
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Give and proidi the following after and undergoing alpha decay and beta decay
The products of the alpha decay of radium-226 and the beta decay of carbon-14 are radon-222 and nitrogen-14, respectively.
The alpha decay of radium-226 results in the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons.
Therefore, the product of the alpha decay of radium-226 is radon-222:
Ra-226 → Rn-222 + alpha particle
On the other hand, In the case of carbon-14, beta minus decay occurs, in which a neutron is converted into a proton, and an electron and an antineutrino are emitted.
So carbon-14 becomes nitrogen-14:
C-14 → N-14 + beta particle
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--The complete Question is, What is the product of the alpha decay of radium-226 and the beta decay of carbon-14?--
If you were to use Lewis theory to predict the formula for the compound between sulfur and aluminum, it would most likely be Question 9 options: AlS AlBr3 Al2S3 Al2S
The most likely formula for the compound between sulfur and aluminum predicted by Lewis theory is Al₂S₃. Option C is correct.
According to Lewis theory, atoms tend to form compounds by sharing electrons to achieve a stable electron configuration. Sulfur has six valence electrons and can form two covalent bonds with aluminum, which has three valence electrons.
Aluminum can donate its three electrons to sulfur, forming three covalent bonds. The resulting compound is Al₂S₃, where two aluminum atoms are bonded with three sulfur atoms through covalent bonds. Therefore, Al₂S₃ is the most likely formula for the compound between sulfur and aluminum predicted by Lewis theory. Option C is correct.
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Solar and wind energy are both intermittent resources that cannot be relied upon for a constant stream of energy production. Explain why developing better ways to store energy is an important part of making these energy sources more practical to use.
By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.
By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.
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Select the correct answer.
How does a catalyst increase the speed of a reaction?
The catalyst increase the speed of the reaction as it lowers the activation energy.
The catalyst will increases the rate of the reaction as it will lowers the activation energy. The catalyst will increases the rate of the reaction in the both the forward and the backward directions as it providing the alternate pathway with the lower activation energy.
Because of the activation energy is reduced, the more reactants will cross the energy barrier and it will make the rate of the reaction increases. The catalyst is increases the rate of the reaction and without itself undergoes any of the permanent chemical change.
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This question is incomplete, the complete question is :
Select the correct answer.
How does a catalyst increase the speed of a reaction?
It lowers the activation energy.
It increases the activation energy.
map below represents a bridge over the meander of a stream From the bridge, a student measures the stream velocity at locations ABand C Which table represents the most probable stream velocity recordings at each location ?
The correct option is 2.
A 88
B 94
C 100
To solve this problem, we need to use our knowledge of how streams flow and how velocity changes in different parts of the stream.
Typically, streams flow fastest in the center of the channel and slowest along the edges, due to friction with the banks and bottom of the stream.
Given that it lies in the middle of the stream's two extreme velocities, option 2, which equals 94, is probably the right response. The velocity near the channel's middle is probably closer to 100 because the stream runs there the quickest.
On the other hand, it is likely that the velocity near the edges is closer to 88 since the stream runs more slowly along the edges due to friction with the banks and streambed. Consequently, a velocity of 94 is the most logical choice because it is within the range that is predicted by the velocity distribution of a stream.
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2. 20.0 mL of a 0.75 M solution
of potassium permanganate,
KMnO solution is used to
make a 250.00 mL solution.
What is the concentration of
the new solution?
The concentration of the new potassium permanganate, KMnO solution is 0.06 M.
To find the concentration of the new solution, we can use the formula,
C₁V₁ = C₂V₂,
C₁ = 0.75,
V₁ = 20.0 mL,
V₂ = 250.0mL
C₂ is what we have to find. Plugging in the values we know, we get,
0.75 M x 20.0 mL = C₂ x 250.00 mL
Solving for C₂, we get the final concentration of the potassium permanganate.
C₂ = (0.75 M x 20.0 mL) / 250.00 mL
C₂ = 0.06 M
Therefore, the concentration of the solution has changed to 0.06 M from 0.75M.
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2c4h10+13o2=8co2+10h2o how many moles of oxygen do you need to react with 0.78 moles of the lighter fluid
The concept stoichiometry is used here to determine the moles of oxygen needed. Stoichiometry is used for the calculation of products and reactants in a chemical reaction. The number of moles of O₂ is
Chemical stoichiometry refers to the quantitative study of the reactants and products involved in a chemical reaction. It is an important concept in chemistry which use the balanced equation to calculate the amounts of reactants and products.
2C₄H₁₀ +13O₂ ⟶ 8CO₂+10H₂O
We want to convert moles of C₄H₁₀ to moles of O₂.
Moles of O₂ = 0.78 mol C₄H₁₀ × 13 mol O₂/2 mol C₄H₁₀ = 5.07 moles
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A 5.4 g sample of a metal is heated to 100.0 °C and is placed in a beaker containing 142 g of water at 24.2 °C. The final temperature of the water is 25.1 °C. What is the specific heat of the metal?
Answer:
We can use the principle of conservation of energy to solve this problem. The heat lost by the metal is equal to the heat gained by the water:
Q metal = -Q water
where Q metal is the heat lost by the metal, and Q water is the heat gained by the water.
The heat lost by the metal can be calculated using the formula:
Q metal = m metal * c metal * ΔT metal
where m metal is the mass of the metal, c metal is its specific heat, and ΔT metal is the change in temperature of the metal.
The heat gained by the water can be calculated using the formula:
Q water = m water * c water * ΔT water
where m water is the mass of the water, c water is its specific heat, and ΔT water is the change in temperature of the water.
We know the values of all the variables except c metal, so we can solve for it. We can start by calculating the values of Q metal and Q water:
Q metal = -Q water
m metal * c metal * ΔT metal = -m water * c water * ΔT water
Substituting the given values, we get:
5.4 g * c metal * (100.0 °C - T) = -142 g * 4.18 J/(g*°C) * (T - 24.2 °C)
Simplifying and solving for c metal, we get:
c metal = [142 g * 4.18 J/(g*°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]
Multiplying out, we get:
c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]
To solve for c metal, we need to find the value of T that satisfies the equation. We can do this by substituting the given value of ΔT water = 0.9 °C into the equation and solving for T:
c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]
c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [540 g - 5.4 g * T]
0.9 g * [593.56 J/(°C) * (T - 24.2 °C)] = [540 g - 5.4 g * T] * c metal
535.2044 J/(°C) * (T - 24.2 °C) = 540 g * c metal - 5.4 g * T * c metal
535.2044 J/(°C) * T - 12931.7808 J = 540 g * c metal - 5.4 g * c metal * T
5.4 g * c metal * T + 535.2044 J/(°C) * T = 540 g * c metal + 12931.7808 J
T * (5.4 g * c metal + 535.2044 J/(°C)) = 540 g * c metal + 12931.7808 J
T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]
Substituting the given values, we get:
T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]
T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]
T ≈ 23.3 °C
Therefore, the specific heat of the metal is:
c metal = [142 g * 4.18 J/(g°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]
c metal ≈ 0.39 J/(g°C)
So the specific heat of the metal is approximately 0.39 J/(g*°C).
A 5.4 g sample of the metal is heated to the 100.0 °C and is placed in the beaker containing 142 g of the water at 24.2 °C. The specific heat of the metal is 1.322 J/ g °C.
The mass of the metal = 5.4 g
The final temperature = 25.1 °C
The initial temperature = 100 °C
The specific heat capacity of metal = x
The mass of the water = 142 g
The final temperature = 25.1 °C
The initial temperature = 24.2 °C
The specific heat capacity of water = 4.184 J/ g °C
Loss of Heat of Metal = Gain of Heat by Water
-q metal = + q metal
- 5.4 × x × ( 25.1 - 100 ) = 142 × 4.184 ( 25.1 - 24.2 )
404.46 x = 534.71
x = 1.322 J/ g °C
The specific heat capacity of metal is 1.322 J/ g °C.
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For the equilibrium: CO(g) + H2O(g) ⇌ CO2(g) + H2(g) KC = 10.0
If 1.6 mol of CO and 1.6 mol of water are initially added to a 2.0 liter flask and the flask is then heated
until the system comes to equilibrium, the concentration of hydrogen will then be _______ M
