Write a function of the form y= A sin (Bx-C)+D that has period 8, phase shift -2, and the range -12 ≤y≤-4.

y =

If the Lions in their "seventh-game" scored 14 runs, then the true statement is (b) The mean increases and the median remains the same.

To determine how the additional 14 runs affect the mean and median, we need to calculate the original mean and median.

The mean is the sum of all the runs divided by the number of games:

So, Mean = (5 + 8 + 1 + 5 + 2 + 7)/6 = 28/6 = 4.67,

The median is defined as "middle-value" when data is arranged in order. In this case, the data in order is : 1, 2, 5, 5, 7, 8

So, the median is 5.

If the Lions scored 14 runs in their seventh game, the total number of runs for seven games is:

⇒ 5 + 8 + 1 + 5 + 2 + 7 + 14 = 42,

The new mean is the sum of all the runs for seven games divided by the number of games:

⇒ Mean = 42/7 = 6,

The new data in order is : 1, 2, 5, 5, 7, 8, 14,

So, the new median is also 5.

Comparing the original mean and median to the new mean and median, we can see that:

⇒ The median remains the same.

⇒ The mean increases from 4.67 to 6.

Therefore, the correct option is (b).

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Using trigonometric identities, the given expression, tan(x) × cos(x), simplified to a single trigonometry is sin(x)

From the question, we are to simplify the given trigonometric expression

From the given information

The given expression is

tan(x) × cos(x)

From trigonometric identities, we know that

tan(x) = sin(x) / cos(x)

Now,

Substituting this value in the given expression

tan(x) × cos(x)

We get

sin(x) / cos(x) × cos(x)

Simplifying further

sin(x) / cos(x) × cos(x) = sin(x)

Hence,

The simplified expression is sin(x)

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The likelihood that they will choose to work in an animal shelter for each of the six options they choose is around 0.2214 or 22.14%

The probability is given as,

P = (Favorable event) / (Total event)

The likelihood of choosing an opportunity at an animal shelter is 7/9. If each chance is equally likely to be chosen, the likelihood of choosing six in a row from an animal shelter may be estimated by multiplying the likelihood of choosing one opportunity by itself six times:

P = (7/9) x (7/9) x (7/9) x (7/9)

P = (7/9)⁶

P = 0.2214 or 22.14%

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The number of friends that get 7 walnuts is 3 and there are 5 walnuts are left over

Here, we have

So, we have

Friends = 26/7 = 3 R 5

This means that 3 friends get 7 walnuts and there are 5 walnuts are left over

Here, we have

Oranges = 57

Oranges in each bags = 6

So, we have

Bags  57/6 = 9 R 3

This means that there are 9 full bags of oranges, 3 oranges are not in the bag and Juan needs 10 bags in total

Here, we have

Craft sticks = 85

Friends = 9

So, we have

Sticks left = 85\9

Evaluate

Sticks left = 4

Hence, there will be 4 sticks left

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The dragging of the tiles to the appropriate places is given below.

1. 5.83 m/s > magnitude 4.5 m/s, direction angle 55˚ magnitude 3m/s, direction angle 135°

2. 4.05 m/s > magnitude 3.5 m/s, direction angle 35˚ magnitude 4 m/s, direction angle 150˚

3. 5.29 m/s > magnitude 6 m/s, direction angle 120˚ magnitude 2 m/s, direction angle 240˚

4. 3.32 m/s > magnitude 3 m/s, direction angle 70° magnitude 5 m/s, direction angle 210˚

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Answer:

A. V = 81π(7.25) = 1,844.90 cubic inches

V = 81(3.14)(7.25) = 1,843.97 cubic inches

B. Let p be the number of cans of paint.

1,843.97p = 10,000, so p = 5.42

Jessie will need 6 cans of paint.

C. Area of each storage area = π(9.5^2) = 283.53 square inches. Using 3.14 for π, this area is (3.14)(9.5^2) = 283.385 square inches. The base area of each paint can is 81π = 254.46 square inches (254.34 square inches if we use 3.14 for π). Jessie can't use the carrier because the area of each storage area exceeds the base area of each paint can.

The Present value is $6,139.132.

We have,

FV=100000, pmt = 4000, I =5%, n=10

So, The present value formula is

PV=FV / (1 + [tex]i)^n[/tex]

So, PV =  100, 000 / (1+ 5/100[tex])^{10\\[/tex]

PV = 100,000 / (1+ 0.05[tex])^{10\\[/tex]

PV = 100, 000/ (1.05[tex])^{10\\[/tex]

PV = 100,000 / 1.6288946

PV= $6,139.132

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The measure of the third outgoing current will be 0.5 amperes.

We know that,

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The three incoming currents at a node in an electrical circuit measure 0.7 amps, 0.68 amps, and 0.47 amps two of the three outgoing currents measure 0.8 amps and 0.55 amps.

Then the measure of the third outgoing current will be

We know that the sum of the incoming current will be equal to the sum of the outgoing current at a junction.

Let the incoming current be I₁, I₂, and I₃. And the outgoing current is I₄, I₅, and I₆.

Then we have

I₁ + I₂ + I₃ = I₄ + I₅ + I₆

0.7 + 0.68 + 0.47 = 0.8 + 0.55 + I₆

1.85 = 1.35 + I₆

I₆ = 0.5

Thus, the measure of the third outgoing current will be 0.5 amperes.

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complete question:

The three incoming currents at a node in an electrical circuit measure 0.7 amps, 0.68 amps, and 0.47 amps two of the three outgoing current measure 0.8 amps and 0.55 amps find the measure of the third outgoing current

4 is the value of the variable x.

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

We can simplify the left side of the equation by using the properties of exponents:

[tex](7q^{3x})^3 = 7^3 * (q^{3x})^3 = 343q^{9x}\\\\343q^{9x} = 343q^{36}\\\\q^{9x} = q^{36[/tex]

Now we can use the property that if [tex]a^b = a^c[/tex], then b = c. Therefore:

9x = 36

Dividing both sides by 9, we get:

x = 4

Therefore, the value of x that satisfies the equation is 4.

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The probability that Mia and Lia place in 1st or 2nd is 99/2450. There are two possible scenarios in which Mia and Lia can place in 1st or 2nd: Mia places 1st and Lia places 2nd, or Mia places 2nd and Lia places 1st. The probability of the first scenario is (1/50) * (1/49) = 1/2450. The probability of the second scenario is also (1/50) * (1/49) = 1/2450. Since these two scenarios are mutually exclusive, we can add their probabilities to find the total probability: 1/2450 + 1/2450 = 2/2450. However, we must also account for the fact that there are 49 other people who could place in 3rd. So the final probability is (2/2450) * 49 = 98/2450. Adding the probability that neither Mia nor Lia place in 3rd (1/2450), we get 98/2450 + 1/2450 = 99/2450.

Received message. The probability that Mia and Lia place in 1st or 2nd is **99/2450**. There are two possible scenarios in which Mia and Lia can place in 1st or 2nd: Mia places 1st and Lia places 2nd, or Mia places 2nd and Lia places 1st. The probability of the first scenario is `(1/50) * (1/49) = 1/2450`. The probability of the second scenario is also `(1/50) * (1/49) = 1/2450`. Since these two scenarios are mutually exclusive, we can add their probabilities to find the total probability: `1/2450 + 1/2450 = 2/2450`. However, we must also account for the fact that there are `49` other people who could place in 3rd. So the final probability is `(2/2450) * 49 = 98/2450`. Adding the probability that neither Mia nor Lia place in 3rd (`1/2450`), we get `98/2450 + 1/2450 = 99/2450`.

Answer: okay ill help

Step-by-step explanation:

Answer: 504 different ways.

Step-by-step explanation:

      This situation uses a permutation. We will use the given formula and simplify to solve. n is equal to the number of contestants and r is 3 since we are selecting and first-, second-, and third-place winner.

Given:

      [tex]\displaystyle P = \frac{n!}{(n-r)!}[/tex]

Substitute values:

      [tex]\displaystyle P = \frac{9!}{(9-3)!}[/tex]

Subtract:

      [tex]\displaystyle P = \frac{9!}{6!}[/tex]

Multiply:

      [tex]\displaystyle P = \frac{9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}[/tex]

Simplify using the knowledge that something divided by itself is 1:

      P = 9 * 8 * 7

Multiply:

      P = 504

      We can also think of it as 9 different people could win 1st, 8 different people could win 2nd, and 7 different people could win 3rd. 9 * 8 * 7 = 504. However, the steps above show why this works with the formula as well.

The labelled parts are described as follows

1. BC - Tangent

3. DH - Chord

4. EH - Diameter

5. G - center of the circle

6. GF Radius of the circle

7. B. a point of tangency

Tangent: Referenced as a point of tangency, a tangent to a circle is a line that meets the circumference at one solitary area while never penetrating inside its bounds. To explain further, this line is perpendicular to the radius of the circle right at the tip of contact.

Chord: Referring to such an element, a chord of a circle is a straight piece between two areas that lay along the circumference. Without having any relation to the middle of the target object, it has both of its extremities on the peripheral border.

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The value of x in the triangle is 12.285.

We have,

We use cosine identities.

So,

Cos Ф = Base / Hypotenuse

Now,

Cos 35= x/15

0.819 = x/15

x = 0.819 x 15

x = 12.285

Thus,

The value of x is 12.285.

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Beyond doubt, owing to the confidence interval administered, there is incontrovertible proof that the genuine percentage of male births in this community deviates from 0.5. The confidence interval excludes 0.5, with both its lower and upper bounds either larger or lesser than 0.5.

The confidence interval yields insights into the selection of conceivable proportions for the authentic percent of male births attained within the population; as opposed to a significance test exclusively revealing whether we can deny or not disavow a nonentity hypothesis.

The confidence interval details a more comprehensive reflection of the data by disseminating awareness regarding the accuracy of the evaluation and the latitude of uncertainty adjacent to it.

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The conclusion is there is not a significant difference between the preference for the three food containers.

The appropriate statistic to use in this case is a chi-squared test. This test will help us determine if there is a significant difference between the preference of the three food containers.

The critical value for the chi-squared test with 2 degrees of freedom is 5.991.

The chi-squared statistic is calculated as follows:

(74-103)²/103 + (103-123)²/123 + (123-103)²/103

= 3.9/3.9

= 1.0

The chi-squared statistic (1.0) is less than the critical value (5.991). Therefore, there is not a significant difference between the preference for the three food containers.

The statistical results can be presented in the following form:

Chi-squared statistic = 1.0

Critical value = 5.991

Therefore, the conclusion is there is not a significant difference between the preference for the three food containers.

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If three squares are placed to form a right triangle as shown. The statement that must be true is: C .The difference of the areas of the smaller squares is always equal to the area of the largest square.

Let's use the letters a, b, and c to denote the side lengths of the squares, with c standing for the hypotenuse of the right triangle. Assuming that an is the shortest side length to preserve generality a2 is the area of the smallest square. The largest square has a surface area of c2 whereas the medium square has a surface area of b2.

The Pythagorean theorem demonstrates that a + b equals c. If we rewrite this equation, we obtain:

c^2 - b^2 = a^2

c^2 - a^2 = b^2

This means that the size of the largest square is equal to the difference between the areas of the two smaller squares, which is either a2 or b2.

Therefore the correct option is C.

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Answer:

three

Step-by-step explanation:

All other numbers are even except three

The figures that complete the two-way frequency table are attached accordingly.

Let represent the table like this:


                      Chcken       Veggie             Tuna               Total

Seltzer            38                 45                     A                    90
Iced Tea           B                  C                        D                    E
Total                 75                 F                       G                    160

NOte that:

A = 90 - 38 - 45 = 7
B = 75 - 38 = 37
E = 160-90 = 70
C = D + 11
D + 11 + D = 70-37
2D = 33-11
D=22/2

D=11

Thus C = 22
F = 45 + C
F = 45 + 22
F = 22


G = A + D = 18

?thus, the completed two-way frequency table is:


                    Chcken       Veggie             Tuna               Total

Seltzer            38                 45                     7                    90
Iced Tea           B                  22                     11                    70
Total                 75                 67                    18                    160

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Answer:

28+36+y=180

64+y=180

y=180-64

y=116°

Answer:

I believe the answer is 30%

The total height of the three jumps is A = 20.744 feet

Given data ,

1st high jump score: 7.016 feet

2nd high jump score: 5.42 feet

3rd high jump score: 8.308 feet

On adding the scores , we get

7.016 + 5.42 + 8.308 = 20.744 feet

On simplifying the equation , we get

A = 20.744 feet

Hence , Oliver jumped a total of 20.744 feet in the three high jumps

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Answer:250

Step-by-step explanation:

I think they just want you to multiply the 25 and the 10 (radius squared times the height)

Answer:0.5.

Step-by-step explanation:

Answer:

0.5

Step-by-step explanation:

hope this helps

The crocodile weighs 0.005 times as much as the hippopotamus.

To determine how many times as much as the hippopotamus a crocodile weighs, we need to compare the weights of both animals. However, they are currently in different units, so we need to convert them to a common unit.

We can convert the weight of the hippopotamus from tons to pounds by multiplying by 2,000, since there are 2,000 pounds in a ton. This gives us:

Hippopotamus weight = 2 tons × 2,000 pounds/ton = 4,000 pounds

Now that both weights are in pounds, we can compare them. To determine how many times as much as the hippopotamus the crocodile weighs, we can divide the weight of the crocodile by the weight of the hippopotamus. This gives us:

Crocodile weight / Hippopotamus weight = 20 pounds / 4,000 pounds = 0.005

Alternatively, we could say that the hippopotamus weighs 200 times as much as the crocodile.

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The value of the Expression is 610, 919.

We have,

Expression : [tex]\sum_{n=0}^{61[/tex] 700 (1.07[tex])^{n+1[/tex]

The expression is a summation formula, representing the sum of a series of values.

Here r= 1.07 and n is number of terms.

So, [tex]\sum_{n=0}^{61[/tex] 700 (1.07[tex])^{n+1[/tex]

= 700 (1) +  [tex]\sum_{n=0}^{61[/tex] 700 (1.07[tex])^{n[/tex]

= 700 + 700 ([tex]r^{61[/tex] - 1)/ (r-1)

= 700 + 700 ([tex](1.07)^{61[/tex]-1)/ (0.07)

= 700+ 700 (871.7428)

= 610, 919

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