Write a linear function f with the values ƒ (0) = -3 and ƒ (7) = 11.

According to the triangle inequality, the length of a triangle's third side must be greater than the sum of any two other triangle lengths, so the length of the steel piece will likely be 4 or 5 inches.

Triangle inequality is a theorem in Euclidean geometry that states any two triangle sides added together must be greater than or equal to the third side; it is represented by the symbols a + b≥ c. The basic tenet of the theorem is that a straight line connects any two points.

Here,

If they are an integer number of inches long and less than six, the following lengths are possible: 4 ,5

According to the triangle inequality, any two other triangle lengths must be greater than the third side of a triangle's length:4+4 = 8 > 6

4+6 = 10 > 4

5+5 = 10 > 6

6+5 = 11 > 5

According to "The Triangle Inequality," which states that the length of a triangle's third side must be greater than the sum of any two other triangle lengths, the piece of steel's potential length will be 4 or 5 inches.

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ann made a rectangle with the

right perimeter & area

ann doesn't try any other

rectangles to see if their areas are

different.

splitting the land , ann confuses perimeter and area

mapmathshellorg

The statements that are true are:

It should be noted that the two figures can be regrdedas as one that are similar in the case whereby their corresponding angles are congruent ,also their ratios of the lengths with respect to their corresponding sides would also be equal.

In conclusion, when two figures are similar then it can be concluded that their  corresponding angles are congruent .

Hence, the second and third options are correct.

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Answer:

Corresponding angles of congruent figures are the same.

The corresponding sides of congruent figures are the same.

Step-by-step explanation:

Answer:

For part a you would decompose the fraction into two independent fractions with the following form:

() = ()/( x^2+5)(x ^2+3x−4)  = (Ax + B)/(x^2+5) + (Cx + D)/(x ^2+3x−4)

Combining these fractions we get:

((Ax + B)*(x ^2+3x−4) + (Cx + D)*( x^2+5))/( x^2+5)(x ^2+3x−4) = ()/( x^2+5)(x ^2+3x−4)

Thus we can say: (Ax + B)*(x ^2+3x−4) + (Cx + D)*( x^2+5) = ()

You then simplify the equation on the left by combining like terms and solve the system of equations that arise corresponding with ().

You would follow a similar process for part b as well.

Step-by-step explanation:

Answer:

not a solution

Step-by-step explanation:

we can just fill it in on both equations

-4(4)+3(1)=2

-16+3=2

-13=2

It doesn’t work for this equation so it’s not a solution

Hopes this helps please mark brainliest

Answer:

No

Step-by-step explanation:

For (4, 1 ) to be a solution then both equations must be true

substitute x = 4 and y = 1 into both equations

- 4(4) + 3(1) = - 16 + 3 = - 13 ≠ 2

3(4) - 9(1) = 12 - 9 = 3

Since both equations are not true then (4, 1 ) is not a solution of the system.

1.because sample is random and (130)

(0.923) and (130)(0.077) are both at least 10.

This means the normal model is a good fit for the sampling distribution.

Consider the provided information.

130 randomly selected flights and find that

120 of the flights arrived on time.

n=130

The on-time arrival performance was 91.9%

p=0.923 and q=1-0.923=0.077

np = 130 x 0.923

np = 120 ≥ 10

nq = 130 × 0.077

nq = 10 = 10

Hence, Yes, because sample is random and

(130)(0.923) and (130)(0.077) are both at least 10. This means the normal model is a good fit for the sampling distribution.

2.because sample is random and (130)

(0.919) and (130)(0.081) are both at least 10.

This means the normal model is a good fit for the sampling distribution.

Consider the provided information.

130 randomly selected flights and find that

120 of the flights arrived on time.

n=130

The on-time arrival performance was 91.9%

p=0.919 and q=1-0.919=0.081

np = 130 x 0.919

np = 119.5 ≥ 10

nq = 130 × 0.081

nq = 10.5 ≥ 10

Hence, Yes, because sample is random and

(130)(0.919) and (130)(0.081) are both at least 10. This means the normal model is a good fit for the sampling distribution.

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The answer to the given quadratic equation is y =  ( x + 4 )²

A(x + m)2 + n is the formula for completing the square, where m is any real number and n is a constant factor.

The following straightforward formula can be used to finish the square instead of the intricate step-by-step procedure. Find the following in order to complete the square in the phrase ax2 + bx + c:

N = c - (b2/4a) and m = b/2a

Enter these numbers where they belong: ax2 + bx + c = a(x + m)2 + n. These equations are geometrically derived.

Given : A quadratic equation y = 7x² + 56x + 117

this can also written as y = x² + 8 x + 17

y = x² + 4² - 4² + 17

y =  ( x + 4 )²

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The most reasonable estimate of the correlation coefficient is 0.9

The correlation coefficient gives an estimate of how strong is the linear relationship between two variables.

The correlation coefficient, r, is given by the formula;

[tex]r = \dfrac{\sum(x_i-\overline x)\cdot (y_i-\overline y)}{\sqrt{\sum (x_i-\overline x)^2\sum(y_i-\overline y)^2} }[/tex]

Where;

[tex]x_i[/tex] = The ith x-value

[tex]\overline x[/tex] = The mean (average of the x-values)

[tex]y_i[/tex] = The ith y-value

[tex]\overline y[/tex] = The mean (average of the y-values)

The give points on the scatter plot graph are;

(8, 9), (6, 9), (6, 6), (5, 5), (4, 5), (3, 4), (3, 3), (2, 4), (1, 2), (1, 3)

Plotting the above points on MS Excel gives;

The equation of the regression line is; y = 0.9407·x + 1.3313

The square of the correlation coefficient, R² = 0.8322

Therefore, R = √(0.8322) ≈ 0.9122

The option that is the most reasonable estimate of the correlation coefficient is therefore; 0.9

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Answer: 13,8 litres

Step-by-step explanation:

£1.45 ------------ 1 L

 £20 ------------- ?

?= [tex]\frac{20 *1}{1.45} = 13,79310345 L[/tex] = 13,8 L

The distance from one corner of the field to the opposite corner, using the Pythagorean Theorem, is of:

125 meters.

The Pythagorean Theorem is a geometry axiom relating the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the sum of the legs squared, according to the equation presented as follows:

[tex]h^2 = l_1^2 + l_2^2[/tex]

From the situation described in this problem, we have that:

Hence the distance from one corner of the field to the opposite corner is obtained as follows:

d² = 68² + 105²

d = sqrt(68² + 105²)

d = 125 meters.

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The number 1/8 represent the fraction of full sheet of paper the teacher asked each student to color.

The information given are;

The information given are

= 1/4 of 1/2x

= 1/4 × 1/2x

= 1/8x

So therefore, the student colored 1/8 of the original piece of paper.

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The system of equations has its solutions to be (1, -1) and (7, -1)

The system of equations is given as

(x−4)² + (y+1)² = 9

(x−4)²/9 + (y+1)²/81 = 1

Make (y + 1)² the subject in the equation (x−4)² + (y+1)² = 9

So, we have

(y+1)² = 9 - (x−4)²

Substitute (y+1)² = 9 - (x−4)² in (x−4)²/9 + (y+1)²/81 = 1

This gives

(x−4)²/9 + [9 - (x−4)²]/81 = 1

Split

(x−4)²/9 + 9/81 - (x−4)²/81 = 1

Collect the like terms

(x−4)²/9 - (x−4)²/81 = 1 - 9/81

Evaluate the like terms

[9(x−4)² - (x−4)²]/81 = 72/81

So, we have

9(x−4)² - (x−4)² = 72

Evaluate the difference

8(x−4)² = 72

Divide by 8

(x−4)² = 9

Take the square roots

x - 4 = ±3

So, we have

x = 4 ± 3

Evaluate

x = 1 or 7

Substitute x = 1 or 7 in (y+1)² = 9 - (x−4)²

(y + 1)² = 9 - (1−4)² or (y + 1)² = 9 - (7−4)²

This gives

(y + 1)² = 0 or (y + 1)² = 0

This gives

y + 1 = 0

Evaluate

y = -1

Hence, the solution is (1, -1) and (7, -1)

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Equation in standard form with an x-intercept of 4 and a y-intercept of 5 is y = -5/4(x) + 5.

Given:

x - intercept = 4

y - intercept = 5

At x intercept y = 0 and at y intercept x = 0

(4,0) and (0,5)

slope = 5-0/0-4

= 5/-4

m = -5/4

substitute (4,0) and m value,

y = mx+c

0 = -5/4*4 +c

0 = -5 + c

c = 5

y = mx + c

y = -5/4(x) + 5.

Therefore equation in standard form with an x-intercept of 4 and a y-intercept of 5 is y = -5/4(x) + 5.

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Domain of the function is,  (0, ∞).

Range of the function is, (-∞, ∞).

x - intercept of the function is, (1, 0).

Vertical asymptote of the function is,  None.

What is domain and range?

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x).

A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

First to find the domain of the function,

Since, all input values shown on the x-axis make up a graph's domain.

We can see that values of x values are from 0 to ∞.

Hence, the domain is (0, ∞).

Now to find the range.

Since, the y-axis on a graph represents the possible output values, or range.

The y - axis having the values from -∞ to ∞.

Hence, the range of the function is, (-∞, ∞).

x - intercept is the point where function crosses the x - axis.

Here function crosses x - axis at (1, 0).

Hence, the x - intercept is (1, 0).

A graph's vertical asymptote is the vertical line at x = a where the graph trends toward positive or negative infinity as the inputs go closer to a.

So, the vertical asymptote is x = 0.

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Answer:

37=18q+1

subtract 1 on both sides

then divide both sides by 18

q=2

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\sf 37=18q+1[/tex]

[tex]\sf 18q+1=37[/tex]

Subtract 1 from both sides:-

[tex]\sf 18q+1-1=37-1[/tex]

Simplify:-

[tex]\sf 18q=36[/tex]

Divide both sides by 18:-

[tex]\sf \cfrac{18q}{18}=\cfrac{36}{18}[/tex]

[tex]\sf q=2[/tex]

_____________________

Hope this helps!

Have a great day!

The change  y=210(1.092)^x represent exponential growth

The percentage rate of increase is 9.2 percent increase

Exponential functions are functions that consist of three part say c(b)^d

the part that says whether the function is growth or decay is b

b is called the base function and it is used as follows to determine growth or decay function

Comparing with the given function 1.092 > 1 hence a growth function

The percentage is solved as follows

1.092 * 100 = 109.2%

109.2% is also referred to as 9.2 percent increase since it is an increment of 9.2%. this is shown below

100% + 9.2% = 109.2%

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Applying the transformation rule (x - 2.y + 4) and using the scale factor k = 3 for dilation gives

preimage      translation image     Dilation image

A (1.-2)             A' (-1, 2)                   A'' (-3, 6)  

B (4,-1)             B' (2, 3)                    B'' (6, 9)

C (5.-3)            C' (3, 1)                     C'' (9, 3)

Transformation is a term used in mathematics to refer to the movements made by objects.

Translation refers to a type of transformation that involve a linear movement.

Applying the transformation rule (x - 2.y + 4 ) gives

A (1.-2) = (1 - 2, -2 + 4) = (-1, 2)

B (4,-1) = (4 - 2, -1 + 4) = (2, 3)

C (5.-3) = (5 - 2, -3 + 4) = (3, 1)

preimage        image

A (1.-2)             A' (-1, 2)

B (4,-1)             B' (2, 3)

C (5.-3)            C' (3, 1)

Dilation involves making the image bigger or smaller. In this case K > 1 hence the image is bigger

Using the scale factor k = 3 for dilation rule (kx, ky) gives

A' (-1, 2) = (-1 * 3, 2 * 3) = (-3, 6)

B' (2, 3) = (2 * 3, 3 * 3) = (6, 9)

C' (3, 1) = (3 * 3, 1 * 3) = ( 9, 3)

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Answer:

  y = x² +8x -9

Step-by-step explanation:

You want the least-degree polynomial with roots 1 and -9, written in standard form.

Each root p means there is a factor (x-p). The two roots make the factored form of the polynomial be ...

  y = (x -1)(x +9)

Expanding this to standard form, we get ...

  y = x² +8x -9

__

Additional comment

A quadratic that has two roots, p and q, will have the standard form ...

  y = (x -p)(x -q) = x² -(p+q)x +pq

That is, the linear term coefficient is the opposite of the sum of the roots, and the constant is their product. This means you can write down the equation directly from the roots:

  y = x² -(1-9)x +(1)(-9) = x² +8x -9

The number of real roots found are-

1. (x-4)(x+3)^2(x-1)^3=0 ; 6 real roots.

2. X^2(x^3-1)=0 ; 3 real roots.

3. X(x+3)(x-6)^2=0 ; 4 real roots.

4. 3x(x^3-1)^2=0 ; 3 real roots.

5. (x^3-8)(x^4+1)=0​ ; 1 real roots.

Consider the given cases-

1. (x-4)(x+3)^2(x-1)^3=0,

Put each equals zero.

x – 4 = 0 or (x + 3)^2 = 0 or (x – 1)^3 = 0,

Thus,

x = 4

x = –3 twice

x = 1 thrice

All are real numbers, thus given polynomial has 6 real roots.

2. x^2(x^3-1)=0

Put each equals zero.

x² = 0

x³ – 1 = x³ – 1³ = (x – 1)(x² + x + 1) = 0

The quadratic expressions has 2 imaginary roots.

Use the discriminant formula to find-

D = b² – 4ac = 1² – 4(1)(1) = 1 – 4 = –3 < 0.

Thus, roots that are not real.

So, the real roots of this polynomial : 0(twice) and 1.

Hence, thus given polynomial has 3 real roots.

3. x(x+3)(x-6)^2=0

Put each equals zero.

x = 0

x = 3

x = 6 twice

Hence, thus given polynomial has 4 real roots.

4. 3x(x^3-1)^2=0

Put each equals zero.

3x = 0 and  x = 0

(x^3 – 1)² = [(x – 1)(x² + x + 1)]² = (x – 1)²(x² + x + 1)² = 0,

Here, only two roots are real

The quadratic expression do have unreal roots, thus 1 twice are the real roots.

Hence, thus given polynomial has 3 real roots..

5. (x^3-8)(x^4+1)=0

Put each equals zero.

x³ – 8 = x³ – 2³ = (x – 2)(x² + 2x + 4) = 0

There is only one real root i.e, 2, the quadratic expression do have imaginary roots

Check using the discriminant formula

D = b² – 4ac = 2² – 4(1)(4) = 4 – 16 = – 12 < 0.

x⁴ + 1 = 0 has imaginary roots.

Hence, thus given polynomial has 1 real roots..

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If the original price of the radio is 2,400 Naira and it is reduced by one third, then the discounted price is 1,600 Naira.

A store usually provides discount of some items to attract more customers and make greater sales.

Suppose the original price is p, the discount rate is d%, and the discounted price is q, then the discounted price can be calculated as:

q = (1 - d%) x p

Parameters given in the problem:

p = 2,400 Naira

d = 1/3

Hence,

q = (1 - 1/3) x 2400

q = 2/3 x 2400 = 1600

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The value of R when A equal 5 is 3.6 and the value of A when R equal 9 is 2 as R is varies inversely to A.

Proportional relationships are relationships between two variables where their ratios are equivalent.

If R is inversely proportional to A.

R ∝ 1/A, then

R = k/A

Where k is the proportionality constant.

Given that;

First, we determine the proportionality constant.

R = k/A

Plug in R = 12 and A = 1.5 and solve for k

k = R × A

k = 12 × 1.5

k = 18

a) The value of R when A = 5 will be;

R = k/A

R = 18 / 5

R = 3.6

b) The value of A when R = 9

R = k/A
R × A = k

A = k/R

A = 18 / 9

A = 2

Therefore, the value of A when R equal 9 is 2.

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The rate per minute at which Karama can paint banisters is 0.02.

In the given question,

Karama can paint a staircase banister in 50 minutes.

We have to find the rate per minute at which Karama can paint banisters.

Since we have to find the rate per unit. Rate per unit means how much Karama can paint in one minute.

To find the rate per unit we divide 1 by 50.

As we know that Karama can paint one staircase banister in 50 minute.

So we can write it as

50 minute = 1 staircase banister paint

Now in 1 minute.

1 minute = 1/50 staircase banister paint

Simplifying

1 minute = 0.02 staircase banister paint

Hence, the rate per minute at which Karama can paint banisters is 0.02.

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Preston left with $5 and correct expression for to find solution is option(B) i.e, 15 - (6.5 + 2 * 1.75)

What is an Algebraic Expression?

An expression constructed using integer constants, variables, and algebraic operations is known as an algebraic expression. For example, 3x² − 2xy + c is an algebraic expression.

Given,

Total money Preston have = $15

He buys the ticket for = $6.50

And, two snacks = $1.75 each

so the cost of two snacks is = 1.75 * 2 = $3.5

Total cost for ticket and snacks = $3.5 + $6.50 = $10

Now, he spent money on snacks and ticket $10 and he have total money $15 so,

Preston left with = $15 - $10

                           = $5

Therefore, Preston left with $5 and correct expression for to find solution is option(B) i.e, 15 - (6.5 + 2 * 1.75)

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The Pythagorean Theorem indicates the following relationship between the squares and triangles.

Part A

Part E

Pythagoras theorem can be stated as follows; The square of the length of the hypotenuse side of a right triangle is equal to the sum of the squares of the other two sides.

Part A

The possible squares in the question are the three squares arranged on the three sides of the triangle, and having a side length which is the same as the length of the side of the triangle to which the square is attached

The relationship between the three squares of side length a, b, and c according to Pythagorean theorem is; a² + b² = c²

Therefore, the area of the largest square that is located on the hypotenuse side of the triangle is equal to the sum of the areas of the other two squares.

Part E

The length of the sides of the triangles, obtained from a similar question on the site are; a, b, and c and a, b, and n

It was shown that c² = n²

Therefore;

c = n

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You can see pic..

Answer:

que tienes que realizar no se entiende tu pregunta lo siento

The percent decrease in screen time this week is 40%. Therefore, option C is the correct answer.

Given that, last week, Lora used 840 minutes. This week, Lora used 504 screen time minutes on the phone.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Now,

Difference=840-504

= 336

Percentage decrease = Difference in value/Original value ×100

= 336/840 ×100

= 0.4 ×100

= 40%

The percent decrease in screen time this week is 40%. Therefore, option C is the correct answer.

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Answer:

5 and 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

(a)

y = 5x - 3 ← is in slope- intercept form

with gradient m = 5

(b)

3y - 12x + 7 = 0 ( add 12x to both sides )

3y + 7 = 12x ( subtract 7 from both sides )

3y = 12x - 7 ( divide through by 3 )

y = 4x - [tex]\frac{7}{3}[/tex] ← in slope- intercept form

with gradient m = 4