Write a program that uses the map template class to compute a histogram of positive numbers entered by the user. The map’s key should be the number that is entered, and the value should be a counter of the number of times the key has been entered so far. Use –1 as a sentinel value to signal the end of user input.512355321-1Then the program should output the followings:The number 3 occurs 2 timesThe number 5 occurs 3 timesThe number 12 occurs 1 timesThe

Step-by-step Explanation:

SIS stands for: The Student Information System (SIS).

This system (a secure, web-based accessible by students, parents and staff) supports all aspects of a student’s educational experience, and other information. Examples are academic programs, test grades, health information, scheduling, etc.

It is difficult to convince top management to commit funds to develop and implement SIS, this can be due to a thousand reasons.

The obvious is that the management don't see the need for it. They would rather have students go through the educational process the same way they did. Perhaps, they just don't trust the whole process, they feel more in-charge while using a manual process.

   //Method definition of words_typed

   //The return type is int

   //Takes two int parameters: typingSpeed and timeInterval

   public static int words_typed(int typingSpeed, int timeInterval) {

       //Get the number of words typed by  

       //finding the product of the typing speed and the time interval

       //and then dividing the result by 60 (since the typing speed is in "words

       // per minute"  and the time interval is in "seconds")

       int numberOfWords = typingSpeed * timeInterval / 60;

       //return the number of words

       return numberOfWords;

   }        //end of method declaration

The code above has been written in Java and it contains comments explaining each of the lines of the code. Please go through the comments.

Answer:

I am writing the program in Python.

def words_typed(typing_speed,time_interval):

   typing_speed>=0

   time_interval>0

   no_of_words=int(typing_speed*(time_interval/60))

   return no_of_words

output=words_typed(20,30)

print(output)

Explanation:

I will explain the code line by line.

First the statement def words_typed(typing_speed,time_interval) is the definition of a function named words_typed which has two parameters typing_speed and time_interval.

typing_speed variable of integer type in words per minute.

time_interval variable of int type in seconds

The statements typing_speed>=0 and time_interval>0 means that value of typing_speed is greater than or equal to zero and value of time_interval is greater than zero as specified in the question.

The function words_typed is used to return the number of words that a  person with typing speed would type in that time interval. In order to compute the words_typed, the following formula is used:

   no_of_words=int(typing_speed*(time_interval/60))

The value of typing_speed is multiplied by value of time_interval in order to computer number of words and the result of the multiplication is stored in no_of_words. Here the time_interval is divided by 60 because the value of time_interval is in seconds while the value of typing_speed is in minutes. So to convert seconds into minutes the value of time_interval is divided by 60 because 1 minute = 60 seconds.

return no_of_words statement returns the number of words.

output=words_typed(20,30) statement calls the words_typed function and passed two values i.e 20 for typing_speed and 30 for time_interval.

print(output) statement displays the number of words a person with typing speed would type in that time interval, on the output screen.

Answer: I would suggest you consider your audience and how you can connect to them. Is your presentation, well, presentable? Is whatever you're presenting reliable and true? Also, no more than 6 lines on each slide. Use colors that contrast and compliment. Images, use images. That pulls whoever you are presenting to more into your presentation.

Explanation:

Answer:

Explanation:

We can use the following method to solve the given problem.

The two input NAND gate logic expression is Y=(A*B)'

we can be able to make us of this function by using complete set AND, OR and NOT

we take one AND gate and one NOT gate

we are going to put the inputs to the AND gate it will give us the output = A*B

we collect the output from the AND and we put this as the input to the NOT gate

then we will get the output as = (A*B)' which is needed

Answer:

Solid state drive

Explanation:

The term solid-state drive is used for the electronic circuitry made entirely from semiconductors. This highlights the fact that the main storage form, in terms of a solid-state drive, is via semiconductors instead of a magnetic media for example a hard disk.  In lieu of a more conventional hard drive, SSD is built to live inside the device. SSDs are usually more resistant to physical shock in comparison to the electro-mechanical drives and it functions quietly and has faster response time. Therefore,  SSD will be best suitable for the Dave.

Answer:

The best advice for Zoom Vacuum is  to start with a Transaction Processing System(TPS). This system will process all the day to day transactions of the system. It is like a real time system where users engage with the TPS and generate, retrieve and update the data. it would be very helpful in lowering the cost of production and at the same time manufacture and produce standard quality products.

Although, TPS alone would not be sufficient enough. so Management Information System(MIS) would be needed, that can get the data from the TPS and process it to get vital information.

This MIS will bring about information regarding the sales and inventory data about the current and well as previous years.

With the combination of TPS as well as MIS is a minimum requirement for a Zoom Vacuum to become successful in the market.

Explanation:

Solution

When we look at the description of the Zoom Vacuum manufacturing company closely, we see that the business is currently a small scale business which is trying to become a small to mid scale business. This claim is supported by the fact that there is only one manufacturing plant and three warehouses. And here, we also need to have the knowledge of the fact that small business major aim is to keep the cost low and satisfy the customers by making good products. So we need to suggest what information system is best suited for small scale business enterprises.

The best recommendation would be to start with a Transaction Processing System(TPS). This system will process all the day to day transactions of the system. It is like a real time system where users interact with the TPS and generate, retrieve and modify the data. This TPS would be very helpful in lowering the cost of production and at the same time manufacture and produce standard quality products . Also TPS can help in communicating with other vendors.

But TPS along would not be sufficient. Also Management Information System(MIS) would be required that can get the data from the TPS and process it to get vital information. This MIS will help in generating information regarding the sales and inventory data about the current and well as previous years. Also MIS can create many types of graphical reports which help in tactical planning of the enterprise.

So a combination of TPS as well as MIS is a minimum requirement for a Zoom Vacuum to become successful in the market.

Answer:

See explaination

Explanation:

public class PalindromeChange {

public static void main(String[] args) {

System.out.println("mom to non palindrom word is: "+changTONonPalindrom("mom"));

System.out.println("mom to non palindrom word is: "+changTONonPalindrom("aaabbaaa"));

}

private static String changTONonPalindrom(String str)

{

int mid=str.length()/2;

boolean found=false;

char character=' ';

int i;

for(i=mid-1;i>=0;i--)

{

character = str.charAt(i);

if(character!='a')

{

found=true;

break;

}

}

if(!found)

{

for(i=mid+1;i<str.length();i++)

{

character = str.charAt(i);

if(character!='a')

{

found=true;

break;

}

}

}

// This gives the character 'a'

int ascii = (int) character;

ascii-=1;

str = str.substring(0, i) + (char)ascii+ str.substring(i + 1);

return str;

}

}

Answer:

yes you can do that it's utter logic

Answer:

Yes.

Explanation:

Itunes gift cards do buy you games/movies/In app purchases/ect.

Answer: Provided in the explanation segment

Explanation:

Below is the code to carry out this program;

/* C++ program helps prompts user to enter the size of the array. To display the array elements, sorts the data from highest to lowest, print the lowest, highest and average value. */

//main.cpp

//include header files

#include<iostream>

#include<iomanip>

using namespace std;

//function prototypes

void displayArray(int arr[], int size);

void selectionSort(int arr[], int size);

int findMax(int arr[], int size);

int findMin(int arr[], int size);

double findAvg(int arr[], int size) ;

//main function

int main()

{

  const int max=50;

  int size;

  int data[max];

  cout<<"Enter # of scores :";

  //Read size

  cin>>size;

  /*Read user data values from user*/

  for(int index=0;index<size;index++)

  {

      cout<<"Score ["<<(index+1)<<"]: ";

      cin>>data[index];

  }

  cout<<"(1) original order"<<endl;

  displayArray(data,size);

  cout<<"(2) sorted from high to low"<<endl;

  selectionSort(data,size);

  displayArray(data,size);

  cout<<"(3) Highest score : ";

  cout<<findMax(data,size)<<endl;

  cout<<"(4) Lowest score : ";

  cout<<findMin(data,size)<<endl;

  cout<<"(5) Lowest scoreAverage score : ";

  cout<<findAvg(data,size)<<endl;

  //pause program on console output

  system("pause");

  return 0;

}

/*Function findAvg that takes array and size and returns the average of the array.*/

double findAvg(int arr[], int size)

{

  double total=0;

  for(int index=0;index<size;index++)

  {

      total=total+arr[index];

  }

  return total/size;

}

/*Function that sorts the array from high to low order*/

void selectionSort(int arr[], int size)

{

  int n = size;

  for (int i = 0; i < n-1; i++)

  {

      int minIndex = i;

      for (int j = i+1; j < n; j++)

          if (arr[j] > arr[minIndex])

              minIndex = j;

      int temp = arr[minIndex];

      arr[minIndex] = arr[i];

      arr[i] = temp;

  }

}

/*Function that display the array values */

void displayArray(int arr[], int size)

{

  for(int index=0;index<size;index++)

  {

      cout<<setw(4)<<arr[index];

  }

  cout<<endl;

}

/*Function that finds the maximum array elements */

int findMax(int arr[], int size)

{

  int max=arr[0];

  for(int index=1;index<size;index++)

      if(arr[index]>max)

          max=arr[index];

  return max;

}

/*Function that finds the minimum array elements */

int findMin(int arr[], int size)

{

  int min=arr[0];

  for(int index=1;index<size;index++)

      if(arr[index]<min)

          min=arr[index];

  return min;

}

cheers i hope this help!!!

Program explanation:

Program code:

def sum_divisors(n):#defining a method sum_divisors that takes a parameter

   s = 0#defining a variable s that hold a value 0

   for x in range(1,n):#defining a for loop that use n variable to check range value

       if(n%x==0):#use if to check remainder value equal to 0  

           s += x#adding value in s variable

   return s#return s value

print(sum_divisors(6))#calling method

print(sum_divisors(12))#calling method

Output:

Please find the attached file.

Learn more:

brainly.com/question/14704583

Answer:

All the classes are mentioned with code and screenshots. . That class is shown at last.

Explanation:

Solution

Class.Java:

Code

**

* atauthor your_name

* This class denotes Class at the college.

*

*/

public class Class {

  private String className,classID;

  private Professor professor;

  /**

  * atparam className

  * atparam classID

  * atparam professor

  */

  public Class(String className, String classID, Professor professor) {

      this.classID=classID;

      this.className=className;

      this.professor=professor;

  }

     /**

  * at return classID of the class

  */

  public String getClassID() {

      return classID;

  }

    /**

  * Override toString() from Object Class

  */

  public String toString() {    

      return classID+" "+className+" "+professor.getName()+" "+professor.getEducation();        

  }  

}

Person.Java:

Code:

/**

* atauthor your_name

* This class represents Person

*

*/

public class Person {    

  protected String name;  

  /**method to fetch name

  * at return

  */

  public String getName() {

      return name;

  }

  /**method to set name

  * at param name

  */

  public void setName(String name) {

      this.name = name;

  }

Professor.java:

Code:

import java.util.ArrayList;

import java.util.List;  

/**

* at author your_name

*

*This class represents professors

*

*/

public class Professor extends Person{    

  private String professorID, education;

  private List<Class> classes=new ArrayList<Class>();    

  /**

  * at param name

  * at param professorID

  * at param education

  */

  public Professor(String name,String professorID,String education) {        

      this.name=name;

      this.professorID=professorID;

      this.education=education;        

  }

  /**

  * at return

  */

  public String getEducation() {

      return this.education;

  }    

  /**

  * at return

  */

  public String getprofessorID() {

      return this.professorID;

  }  

  /** to add classes

  * at param Class

  */

  public void addClass(Class c) {

      classes.add(c);

  }  

  /**

  * Override toString() from Object Class

  */

  public String toString() {

      String result=this.getName()+" - "+professorID+" - "+education;

      for(Class c:classes) {

          result+=c.toString()+"\n";

      }      

      return result;

  }

}

}

Student.java:

Code:

import java.util.ArrayList;

import java.util.List;  

/**

* This class represents students

*  at author your_Name

*

*/

public class Student extends Person{    

  private String studentID;

  private List<Class> classes=new ArrayList<Class>();    

  /**

  * atparam name

  * atparam studentID

  */

  public Student(String name,String studentID) {      

      this.name=name;

      this.studentID=studentID;      

  }  

  /**

  * atreturn

  */

  public String getStudentID() {

      return studentID;

  }

     /**

  * atparam c

  */

  public void addClass(Class c) {

      classes.add(c);

  }    

  /**

  * atreturn

  */

  public int getClassCount() {

      return classes.size();

  }

  /**

  * Override toString() from Object Class

  */

  public String toString() {

      String result=this.getName()+" - "+studentID+"\n";

      for(Class c:classes) {

          result+=c.toString()+"\n";

      }    

      return result;

  }  

}

NOTE: Kindly find an attached copy of screenshot of the output, which is a part of the solution to this question

Answer:

Struck by rolling object is commonly defined as Struck-By Rolling Object Hazard because it was caused by rolling objects or any objects that moves in circular motion that could cause an injury or accident.

Explanation:

Answer:

A Program was written to carry out some set activities. below is the code program in C++ in the explanation section

Explanation:

Solution

CODE

#include <iostream>

using namespace std;

int main() {

string name; // variables

int number;

cin >> name >> number; // taking user input

while(number != 0)

{

// printing output

cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;

// taking user input again

cin >> name >> number;

}

}

Note: Kindly find an attached copy of the compiled program output to this question.

In this exercise we have to use the knowledge in computational language in C++ to describe a code that best suits, so we have:

The code can be found in the attached image.

In a very summarized way, we can describe the loop or looping in software as an instruction that keeps repeating itself until a certain condition is met.

To make it simpler we can write this code as:

#include <iostream>

using namespace std;

int main() {

string name; // variables

int number;

cin >> name >> number; // taking user input

while(number != 0)

{

// printing output

cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;

// taking user input again

cin >> name >> number;

}

}

See more about C++ at brainly.com/question/19705654

Answer:

The java program including classes is shown below.

import java.util.*;

import java.lang.*;

//base class

class Rectangle1

{

   //variables to hold dimensions and area

   static double l;

   static double b;

   static double a;

   //setter

   static void setWidth(double w)

   {

       b=w;

   }

   //getter

   static double getWidth()

   {

       return b;

   }

   //setter

   static void setLength(double h)

   {

       l=h;

   }

   //getter

   static double getLength()

   {

       return b;

   }

   //area calculation for rectangle

   static void computeArea()

   {

       a = getLength()*getWidth();

       System.out.println("Area of rectangle = " +a);

   }

}

//derived class

class Square1 extends Rectangle1

{

   //variables to hold dimensions and perimeter

   static double s;

   static double peri;

   //settter

   static void setSide(double d)

   {

       s=d;

   }

   //getter

   static double getSide()

   {

       return s;

   }

   //perimeter calculation for square

   static void computePerimeter()

   {

       peri = 2*(getSide()+getSide());

       System.out.println("Perimeter of square = "+peri);

   }

}

public class MyClass {

   public static void main(String args[]) {

     //object of derived class created

     Square1 ob = new Square1();

     ob.setLength(1);

     ob.setWidth(4);

     ob.setSide(1);

     ob.computeArea();

     ob.computePerimeter();

   }

}

Explanation:

1. The class for rectangle is defined having variables to hold the dimensions of a rectangle.

2. The getters and setters are included for both the dimensions.

3. The method to compute the area of the rectangle is defined.

4. The class for square is defined having variables to hold the side of a square.

5. The getter and setter are included for the dimension of the square.

6. The method to compute the perimeter of the square is defined.

7. The class Square1 is the derived class which inherits the class Rectangle1 through the keyword extends.

8. All the variables, getters, setters and methods are declared as static.

9. Another class is defined having only the main() method.

10. Inside main(), the object of the derived class, Square1, is created.

11. The setters and the methods are called through this object.

12. The value of the dimensions are passed as arguments to the setters.

13. The output is attached in an image.

Answer:

They can communicate over the phone or have meetings describing what is and isn't working for Joe. It's also very important that Darla makes eye contact and is actively listening to effectively handle their customer.

Explanation:

Explanation:

a.I would choose an advanced data structure like  dispersion tables.

Scatter tables, better known as hash tables, are one of the most frequently used data structures. To get an initial idea, scatter tables make it possible to have a structure that relates a key to a value, such as a dictionary. Internally, the scatter tables are an array. Each of the array positions can contain none, one or more dictionary entries.

It will normally contain a maximum of one, which allows quick access to the elements, avoiding a search in most cases. To know at which position in the array to search or insert a key, a scatter function is used. A scatter function relates each key to an integer value. Two equal keys must have the same dispersion value, also called a hash value, but two different keys can have the same dispersion value, which would cause a collision.

B. If I eliminated the characteristic b, a possible candidate keeping the previous characteristics would be: Balanced binary trees

Balanced binary trees are data structures that store key-data pairs, in an orderly way according to the keys, and allow quick access to the data, given a particular key, and to go through all the elements in order.

They are appropriate for large amounts of information and have less overhead than a scatter table, although the access time is of greater computational complexity.

Although the storage form has a tree structure internally, this is not externalized in the API, making the handling of the data transparent. They are called balanced because, each time they are modified, the branches are rebalanced in such a way that the height of the tree is as low as possible, thus shortening the average time of access to the data.

Answer:

can you give more detail

Explanation:

Answer: Provided in the explanation segment

Explanation:

Below is the code to run this program.

we have that the

Program

import java.util.Scanner;

public class CharMatching {

  public static void main(String[] args) {

      //Scanner object for keyboard read

      Scanner scnr=new Scanner(System.in);

      //Variable for user input string

      String userInput;

      //Variable for firstletter input

      char firstLetter;

      //Read user input string

      userInput=scnr.nextLine();

      //Read first letter from user

      firstLetter=scnr.nextLine().charAt(0);

      //Comparison without case sensititvity and result

      if(Character.toUpperCase(firstLetter)==Character.toUpperCase(userInput.charAt(0))) {

          System.out.println("Found match: "+firstLetter);

      }

      else {

          System.out.println("No match: "+firstLetter);

      }

  }

}

Output

Hello

h

Found match: h

cheers i hope this helped !!!

Answer:

YOUR NAME

YOUR CITY, STATE, AND ZIP CODE

YOUR PHONE NUMBER

YOUR EMAIL

Professional Summary

Reliable, top-notch sales associate with outstanding customer service skills and relationship-building strengths. Dedicated to welcoming customers and providing comprehensive service. In-depth understanding of sales strategy and merchandising techniques. Dependable retail sales professional with experience in dynamic, high-performance environments. Skilled in processing transactions, handling cash, using registers and arranging merchandise. Maintains high-level customer satisfaction by smoothly resolving customer requests, needs and problems. Seasoned Sales Associate with consistent record of exceeding quotas in sales environments. Delivers exceptional customer service and product expertise to drive customer satisfaction ratings. Proficient in use and troubleshooting of POS systems.

Skills

Returns and Exchanges

Adaptable and Flexible

Excellent Written and Verbal Communication

Meeting Sales Goals

Strong Communication and Interpersonal Skills

Time Management

Cash Handling

Reliable and Responsible

Work History

March 2020 to September 2021

Goodwill OF YOUR STATE

Retail Sales Associate    

Helped customers complete purchases, locate items and join reward programs.

Checked pricing, scanned items, applied discounts and printed receipts to ring up customers.

Folded and arranged merchandise in attractive displays to drive sales.

Greeted customers and helped with product questions, selections and purchases.

Organized store merchandise racks and displays to promote and maintain visually appealing environments.

Monitored sales floor and merchandise displays for presentable condition, taking corrective action such as restocking or reorganizing products.

Balanced and organized cash register by handling cash, counting change and storing coupons.

Trained new associates on cash register operations, conducting customer transactions and balancing drawer.

Answered questions about store policies and addressed customer concerns.

Issued receipts and processed refunds, credits or exchanges.

Maintained clean sales floor and straightened and faced merchandise.

Education

YOUR HIGH SCHOOL THAT YOU ATTEND  

Languages

Spanish

Explanation:

THIS IS MY RESUME IF YOU HAVE MORE WORK EXPERIENCE THEN ADD IT AFTER THE GOODWILL. I GOT A 100% ON EDGE.

Answer:

See explaination

Explanation:

Clearly the entities are as follows:-

Course

Section

Room

Test

The relationship among entities are as follows:-

Course has Section

Test is conducted for Course

Test is conducted in Section

Test is conducted in Room

Attributes of each entities are as follows:-

Course (CourseID, Name, Department)

Section (SectionID, Enrollment)

Room (RoomNumber, Capacity, Building)

Test (Time)

Section is a week entity as, there may be same sections for different courses, therefore section uses the primary key of course entity as foreign key.

Also entity Test is dependent upon the entities Room,Section and Course, therefore primary keys of these entities will be used as foreign key in the Test entity.

Check attachment for the ER diagram

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

Answer:

See explaination

Explanation:

#include <cstring>

#include <cstdio>

#include <string>

#include <array>

#include <random>

#include <algorithm>

struct RandomGenerator {

RandomGenerator(const size_t min, const size_t max) : dist(min, max) {}

std::random_device rd;

std::uniform_int_distribution<size_t> dist;

unsigned operator()() { return dist(rd); }

};

struct Gallow {

void Draw() const

{

std::printf(" ________\n"

"| |\n"

"| %c %c\n"

"| %c%c%c\n"

"| %c %c\n"

"|\n"

"|\n", body[0], body[1], body[2], body[3],

body[4], body[5], body[6]);

}

bool Increment()

{

switch (++errors) {

case 6: body[6] = '\\'; break;

case 5: body[5] = '/'; break;

case 4: body[4] = '\\'; break;

case 3: body[3] = '|'; break;

case 2: body[2] = '/'; break;

case 1: body[0] = '(', body[1] = ')'; break;

}

return errors < 6;

}

char body[7] { '\0' };

int errors { 0 };

};

struct Game {

void Draw() const

{

#ifdef _WIN32

std::system("cls");

#else

std::system("clear");

#endif

gallow.Draw();

std::for_each(guess.begin(), guess.end(), [](const char c) { std::printf("%c ", c); });

std::putchar('\n');

}

bool Update()

{

std::printf("Enter a letter: ");

const char letter = std::tolower(std::getchar());

while (std::getchar() != '\n') {}

bool found = false;

for (size_t i = 0; i < word.size(); ++i) {

if (word[i] == letter) {

guess[i] = letter;

found = true;

}

}

const auto end_game = [this](const char* msg) {

Draw();

std::puts(msg);

return false;

};

if (not found and not gallow.Increment())

return end_game("#### you lose! ####");

else if (found and word == guess)

return end_game("#### you win! ####");

return true;

}

RandomGenerator rand_gen { 0, words.size() - 1 };

const std::string word { words[rand_gen()] };

std::string guess { std::string().insert(0, word.size(), '_') };

Gallow gallow;

static const std::array<const std::string, 3> words;

};

const std::array<const std::string, 3> Game::words{{"control", "television", "computer"}};

int main()

{

Game game;

do {

game.Draw();

} while (game.Update());

return EXIT_SUCCESS;

}

Answer:

see explaination

Explanation:

#include <iostream>

#include <string>

#include <vector>

using namespace std;

vector<string> split(string, string);

int main()

{

vector<string> splitedStr;

string data;

string delimiter;

cout << "Enter string to split:" << endl;

getline(cin,data);

cout << "Enter delimiter string:" << endl;

getline(cin,delimiter);

splitedStr = split(data,delimiter);

cout << "\n";

cout << "The substrings are: ";

for(int i = 0; i < splitedStr.size(); i++)

cout << "\"" << splitedStr[i] << "\"" << ",";

cout << endl << endl;

cin >> data;

return 0;

}

vector<string> split(string target, string delimiter)

{

unsigned first = 0;

unsigned last;

vector<string> subStr;

while((last = target.find(delimiter, first)) != string::npos)

{

subStr.push_back(target.substr(first, last-first));

first = last + delimiter.length();

}

subStr.push_back(target.substr(first));

return subStr;

}

Answer:

500gbs of ssd storage. Microsoft also allows for multi platform cloud cross-saving.

Explanation:

Answer: (a). 11.3137

(b). 22.849

Explanation:

Provided below is a step by step analysis to solving this problem

(a)

clc;close all;clear all;

a=2;x=3.5;

E=10;n=0;k=1;sn1=0;

while E >0.000001

cn=((log(a))^n)*(x^n)/factorial(n);

sn=sn1+cn;

E=abs((sn-sn1)/sn1);

sn1=sn;

n=n+1;

k=k+1;

end

fprintf('2^3.5 from tailor series=%6.4f after adding n=%d terms\n',sn,n);

2^3.5 from tailor series=11.3137 after adding n=15 terms

disp('2^3.5 using calculator =11.3137085');

Command window:

2^3.5 from tailor series=11.3137 after adding n=15 terms

2^3.5 using calculator =11.3137085

(b)

clc;close all;clear all;

a=6.3;x=1.7;

E=10;n=0;k=1;sn1=0;

while E >0.000001

cn=((log(a))^n)*(x^n)/factorial(n);

sn=sn1+cn;

E=abs((sn-sn1)/sn1);

sn1=sn;

n=n+1;

k=k+1;

end

fprintf('6.3^1.7 from tailor series=%6.4f after adding n=%d terms\n',sn,n);

disp('6.3^1.7 using calculator =22.84961748');

Command window:

6.3^1.7 from tailor series=22.8496 after adding n=16 terms

6.3^1.7 using calculator =22.84961748

cheers i hope this helped !!!

Explanation:

See the attached image for The interface (.h file) of a class Counter

Answer:

Line 4 = 28   40

Line 5 = 28   40

Line 6 = 28   40

Line 8 = 28   40

Line 11 = None

Line 12 = 17   16

Line 13 = 18   16

Line 14 = 19   16

Line 15 = 9

Explanation:

Main line number  ||  Matrix object line number (in order)

2                                 9, 9

3                                 9

4                                 28  40

5                                 28  40

6                                 28  40

7                                 None

8                                 28  40

9                                 20

10                                20

11                                 None

12                                17  16

13                                18  16

14                                19  16

15                                9

Answer:

There are various ways: Handing out papers/fliers to people, or presenting slides.

Answer:

part (a).

The program in cpp is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   std::cout << "Loan balance: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>0)

   {

       if(balance<payment)    

         { payment = balance;}

       else

       {  

           std::cout << balance <<"\t\t\t"<< payment << std::endl;

           balance = balance - payment;

       }

   }

   return 0;

}

part (b).

The modified program from part (a), is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   double charge=0.01;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   balance = balance +( balance*charge );

   std::cout << "Loan balance with 1% finance charge: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>payment)

   {

           std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

           balance = balance +( balance*charge );

           balance = balance - payment;

       }

   if(balance<payment)    

         { payment = balance;}          

   std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

   return 0;

}

Explanation:

1. The variables to hold the loan balance and the monthly payment are declared as double.

2. The program asks the user to enter the loan balance and monthly payment respectively which are stored in the declared variables.  

3. Inside a while loop, the loan balance and monthly payment for each month is computed with and without finance charges in part (a) and part (b) respectively.

4. The computed values are displayed for each month till the loan balance becomes zero.

5. The output for both part (a) and part (b) are attached as images.