Answer:
Sample answer: part 1:
What was your hypothesis?
This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:
"The viscosity of honey decreases as temperature increases".
According to your data, do you think your hypothesis was correct?
Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.
The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.
Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:
"one problem was that the temperature of the honey increased too fast"
And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.
part 2:
Viscosity depends strongly on temperature, but this relation depends also on the given material.
Generally, we would see that the viscosity decays exponentially as the temperature increases.
So for the first question:
What effect did the temperature have on the viscosity of the honey?
You should have seen that, as the temperature increased, the viscosity decreased.
Now, we need to give some practical examples where knowledge of viscosity is important.
The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.
Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.
So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.
Explanation:
An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of
the accumulating sand, what happens to the speed of the train car? (Assume negligible friction and the cart is
just rolling along, not receiving any additional force to regulate its speed.)
Answer:
Explanation:
that`s a the train car, that you asked the meaning, of that if the train car rolls it`s doing it`s speed, and it`s not ganna fall off the the trail of the train, car.An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.
What is friction?Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.
Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.
Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.
Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.
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A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?
The initial velocity of the ball when it was projected is 15.64 m/s.
The given parameters:
Angle of the projection, θ = 37⁰The range of the projectile, R = 24 mThe initial velocity of the ball is calculated by applying formula for range of projectile as follows;
[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]
Thus, the initial velocity of the ball when it was projected is 15.64 m/s.
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A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 JThe change in the energy applied to the car is calculated as;
[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]
The final speed of the car is calculated as follows;
[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]
Thus, the final speed of the car at the given conditions is 30.1 m/s.
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A rocket consists of a shuttle and a fuel tank. The rocket flies through the air with a momentum of 180000kgm/s at a velocity of 120m/s. If the fuel tank has a mass of 500kg, what is the mass of the shuttle?
Answer:
Answer is 1000kg
Hope it help
how many kilojoules is this?
Answer:
How to convert joules to kilojoules
One joule is equal to thousandth of a kilojoule:
1J = 0.001kJ
The energy in kilojoules E(kJ) is equal to the energy in joules E(J) divided by 1000:
E(kJ) = E(J) / 1000
Example
Convert 500 joules to kilojoules.
The energy E in kilojoules (kJ) is equal to 500 joules (J) divided by 1000:
E(kJ) = 500J / 1000 = 0.5kJ
Joules to kilojoules conversion table
Energy (J) Energy (kJ)
1 J 0.001 kJ
2 J 0.002 kJ
3 J 0.003 kJ
4 J 0.004 kJ
5 J 0.005 kJ
6 J 0.006 kJ
7 J 0.007 kJ
8 J 0.008 kJ
9 J 0.009 kJ
10 J 0.01 kJ
20 J 0.02 kJ
30 J 0.03 kJ
40 J 0.04 kJ
50 J 0.05 kJ
60 J 0.06 kJ
70 J 0.07 kJ
80 J 0.08 kJ
90 J 0.09 kJ
100 J 0.1 kJ
200 J 0.2 kJ
300 J 0.3 kJ
400 J 0.4 kJ
500 J 0.5 kJ
600 J 0.6 kJ
700 J 0.7 kJ
800 J 0.8 kJ
900 J 0.9 kJ
1000 J 1 kJ
2000 J 2 kJ
3000 J 3 kJ
4000 J 4 kJ
5000 J 5 kJ
6000 J 6 kJ
7000 J 7 kJ
8000 J 8 kJ
9000 J 9 kJ
10000 J 10 kJ
100000 J 100 kJ
hope it help u
itz by Riddhi
23 and 24 only please help!
Answer:
23: Acceleration 24:1m/s^2
Explanation:
[tex]a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2[/tex]
Calculate the elastic potential energy stored in a spring if it has a force constant of 150 N/m. the spring is extended to a length of 0.30m
Answer:
6.75J
Explanation:
U=1/2KΔx²
U=0.5* 150*0.30^2
A block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as shown above. There is friction present between the block and the surface. The spring exerts no force on the block when the center of the block is located at x=0. At the instant shown above, the block is located at x=0 and moving toward the right with speed v=v0. (a) For the instant shown above, with the block located at x=0 and moving to the right, predict the direction of the net force on the block. If the net force is zero, select “The net force is zero.”
_ To the left _ The net force is zero _ To the right
Briefly justify your prediction.
Answer:
Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point
If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?(1 point)
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km
Answer:
it’s the third option: 4,600,000 km
Explanation:
just took the test and that was correct
A gas in a closed container is heated with 10J of energy, causing the lid of the container to rise 2m with 3N of force. What is the total change in energy of the system
Explanation:
For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.
ΔU=Q−W
We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.
W=FΔx
W=3N×2m
W=6J
Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.
ΔU=Q−W
ΔU=10J−6J
ΔU=4J
Answer is 4J
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free tingsssssssssss
Explanation:
yayyy thx u soo muchihuhuhu
Answer:
thx
Explanation:
A vertical spring stretches 9.6 cm when a 1.3 kg block is hung from its end. (a) Calculate the spring constant. This block is then displaced an additional 5.0 cm downward and released from rest. Find the (b) period, (c) freque
Answer:
F = - K x
a) K = 1.3 kg * 9.8 m/s^2 / .096 m = 133 kg/sec^2
b) ω = (K/m)^1/2 angular frequency of SHM
ω = (133 / 1.3)^1/2 = 10.1 / sec
f = 2 π ω = 6.28 * 10.1 / sec = 63.5 / sec
P = 1/f = .0157 sec
Explain how the potential energy is changed to kinetic energy in the Hoover Dam
The water behind a hydroelectric dam stores gravitational potential energy since it is at a higher level than the water on the other side of the dam. As the water falls, this potential energy is converted into kinetic energy, which turns turbines to generate electricity. Often, the water comes from behind a dam built across a river valley. The water high up behind the dam contains gravitational potential energy . This is transferred to kinetic energy as the water rushes down through tubes inside the dam. The moving water drives electrical generators , which may be built inside the dam.
An object’s mechanical energy is
a
its energy of motion.
b
the sum of its potential (position) energy and kinetic (motion) energy.
c
the waste energy it produces by friction.
d
not related to the object’s mass.
Explanation:
the sum of its potential (position) energy and kinetic (motion) energy.
A wave has a wavelength of 1.5 m and a frequency of 6.0 Hz. What is the
speed of the wave?
Answer:
9 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 6 × 1.5 = 9
We have the final answer as
9 m/sHope this helps you
Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
(a) How far did he travel?
(b) What was his average speed?
(c) What was his displacement?
(d) What was his average velocity?
Answer:
Explanation:
See the attachment for the details. A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times. The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.
The individual driving times and distances are summed to provide:
(a) How far did he travel?
103 km
(b) What was his average speed?
12.88 km/h
(c) What was his displacement?
73.82 km
(d) What was his average velocity?
9.228 km/h
What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2?
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
what is the capacitance of capacitor
Answer:
The capacitance C of a capacitor is defined as the ratio of the maximum charge Q that can be stored in a capacitor to the applied voltage V across its plates. In other words, capacitance is the largest amount of charge per volt that can be stored on the device: C = Q V . 1 F = 1 C 1 V .
Explanation:
A capacitor's capacity to hold an electric charge when a potential difference (voltage) is applied across its plates is measured by the capacitance of the device.
It can be calculated using the formula C = Q/V,
where Q is the electric charge stored on the capacitor in coulombs (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V). The capacitor's physical properties, such as the area of the plates, the space between them (dielectric separation), and the substance between the plates (dielectric constant), all affect capacitance. A better charge storage capability is indicated by a higher capacitance value.
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An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?
Answer:
I = 250N*s
Explanation:
I = F*t
I = impulse or momentum
F = Force
t = time
I = 25N*10s
I = 250N*s
3) A 14 kg object is sitting at the top of a hill that is 100 m high. What is the potential energy of the
object?
Answer:
13,720 joules
Explanation:
Epotential = mgh
mass x gravity x height
Ep= 14 x 9.8 x 100
Ep=13,720 joules
Determine the percent composition of chromium (III) flouride CrF3
(Show your solution)
Answer:
Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol
51.9961+18.9984032·3
Mass percentage of the elements in the composition
Element Symbol Atomic Mass Number of Atoms Mass Percent
Chromium Cr 51.9961 1 47.707%
Fluorum F 18.9984032 3 52.294%
Notes on using the Molar Mass Calculator
Chemical formulas are case-sensitive.
Enter subscripts as simple numbers.
The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.
Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.
Explanation:
please mark my answer in brainlist plz
What is the height of the Golden Bridge?
Answer:
hi your answer to this question is 220'
Explanation:
hope this helped you
PLZZZ HELPPP ASAP
I really need help as soon as possible
Answer:
Friction
Explanation:
As the toy cars rolls away, more friction is created. The more friction there is, the more friction on surface rubs against another which creates friction which in-term slows it down. Hope this helps.
Jonathan is pushing a 25 kg box with a force of 135 N. The friction opposing the motion is unknown. The overall net force for the box is 70 N. Using this information calculate the magnitude of the frictional force of the box.
The magnitude of the frictional force of the box is 65 N
From the question given above, the following data were obtained:
Mass (m) = 25 KgForce applied (Fₐ) = 135 NNet force (Fₙ) = 70 NFrictional force (Fբ) =?The frictional force acting on the box can be obtained as follow:
Fₙ = Fₐ – Fբ
70 = 135 – Fբ
Collect like terms
70 – 135 = – Fբ
–65 = –Fբ
Multiply through by –1
Fբ = 65 NThus, the frictional force of the box is 65 N
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Carlos wanted to know how positive and
negative charges affect balloons. The
balloons shown below are part of his
investigation.
Answer:
it Give only one of them a positive or negative charge
Answer:
Rubbing the balloon against hair or wool causes electrons to move from the hair or wool to the balloon. The balloon's negative charges are attracted to the positive charges in the can, and so the can rolls toward the balloon.
Match the definition with the appropriate word.
temperature
part of internal energy that can be
transferred
heat
measure of the average kinetic energy of a
substance
thermal energy
total potential and kinetic energies of the
particles in a substance
internal energy
thermal energy that flows from one
substance to another
Answer:
Temperature: measure of the average kinetic energy of a substance
Internal energy: total potential and kinetic energies of the particles in a substance
Heat: thermal energy that flows from one substance to another
Thermal energy: part of internal energy that can be transferred
Explanation:
Proof for correct answers on edge :)
draw the following vector quantity Using the coordinate system.
a. 190 newton east
b. 120km/hr, 250 north of east
c. 60 meters southwest
The given vectors quantities can be described by their properties of both
magnitude and direction.
a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.b. The velocity vector extending from (0, 0) to (108.76, 50.714) on the coordinate plane is attached.c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.Reasons:
a. The magnitude of the vector = 190 N
The direction in which the vector acts = East
Therefore, in vector form, we have;
[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i
The vector can be represented by an horizontal line, 190 units long
Coordinate points on the vector = (0, 0) and (190, 0)
The drawing of the vector with the above points using MS Excel is attached.
b. Magnitude of the velocity vector = 120 km/hr. 25° North of east
Solution;
The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;
[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j
[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j
Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)
The drawing of the vector is attached
c. The magnitude of the vector = 60 m
The direction of the vector is southwest = West 45° south
The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j
Which gives;
[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j
Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)
The drawing of the vector is attached
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A woman of mass 49 kg jumps off the bow
of a 78 kg canoe that is intially at rest.
If her velocity is 4.5 m/s to the right, what
is the velocity of the canoe after she jumps?
Answer in units of m/s i.
x x
The woman-canoe system has zero initial momentum. When the woman jumps from the canoe, the total momenta of the woman and canoe is conserved, so that
0 = (49 kg) (4.5 m/s) + (78 kg) v
where v is the velocity of the canoe. Solving for v, we find
(78 kg) v = - (49 kg) (4.5 m/s)
v = - 49/78 (4.5 m/s)
v ≈ -2.8 m/s
which is to say, the boat is given a velocity of 2.8 m/s to the left.
A bullet of mass M1, is fired towards a block
of mass m2 initially at rest at the edge of a
frictionless table of height h as in the figure.
The initial speed of the bullet is vi. Consider
two cases. a соmрlеtеlу inсlаѕtiс one and an
elastic one where the bullet bounces off the block. What is the flight ratio time?
The ratio of time of flight for inelastic collision to elastic collision [tex](t_A :t_B)[/tex] is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂ = 0Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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rube goldberg machine steps
Answer:
Rube Goldberg Machine is "a comically involved, complicated invention, laboriously contrived to preform a simple operation." 2. What are the 6 Simple Machines? A. The 6 Simple Machines are: wedge, screw, lever, wheel and axel, inclined plane and pulley.
