Write an equation in slop intercept form with a given slope. Slope: 5/6, y-intercept: 8

Answer:

762.24

Step-by-step explanation:

Rounded to the hundredth place

Answer:

1253

Step-by-step explanation:

2500/2 is 1250.

so 2506/2 will be a bit above.

1253 is an estimate

Answer:

100

Step-by-step explanation:

A = P(1 + rt)

A = 500(1 + (0.1 × 2)) = 600

A = $600.00

600-500= 100

Answer:

the angles all sum up to 360. is a circle therefore x = 60

Step-by-step explanation:

90 + 2x - 10 + 2x + 40 = 360

120 + 4x = 360

4x = 360 - 120

4x = 240

x = 60

Answer:

the discussion leader will moderate the discussion.

Answer:

hope it helps.

stay safe healthy and happy.

Answer:

In bold below.

Step-by-step explanation:

bf-5k=c(g+2k)

g + 2k = (bf - 5k)/c

g =  (bf - 5k)/c - 2k

Answer:

3(7+33)

Step-by-step explanation:

Answer:

5/7

Step-by-step explanation:

The greatest common factor of 25/35 is 5, 25/5=5, 35/5=7, therefore your answer is 5/7.

Answer:

i am going to but 11 bagels but i am going to buy them for a price under 5$

i am also going to buy 4 extra if we are still hungry

Step-by-step explanation:

i dunno you prob need a anwser with little thought like this becuase of auto grading systems hope this helps

Answer:

First mechanic 10 hours, Second is 15 hours

Step-by-step explanation:

x + y = 25, so y = 25 - x

75x + 45y = 1425

Substitute in the first equation

75x + 45(25 - x) = 1425

75x + 1125 - 45x = 1425

30x = 300

x = 10

Therefore, y = 15

Answer:

they both worked

8 hours

Answer:

88%

Step-by-step explanation:

You can do this pretty easily because percent is just decimals where the decimal is moved 2 units to the right.

Since the base is 25, and 3 of them are oatmeal, you can multiply by 4/4 to get a base of 100, to make this a lot easier.

3 / 25 = x / 100

3 x 4 = 12

12/100 are oatmeal.

Since you don't want the oatmeal, you subtract 100 by 12 to find the remaining of 88.

Answer:

88%

Step-by-step explanation:

1) 25-3=22 not oatmeal

2) proportion: 22/25 = x/100

cross multiply and divide

22x100 = 2200

2200/25 = 88

88%

Answer: y = -x + 2

Step-by-step explanation:

If you are familliar with the point-slope form this is very helpful

Point-slope:

[tex]y-y_1=m(x-x_1)[/tex]

Plug in our values of [tex]m = -1, y_1=-1,x_1=3[/tex] to get:

[tex]y-(-1) = -1(x-3)[/tex]

Simplify

[tex]y+1=-x+3[/tex]

[tex]y=-x+2[/tex]

Answer:

The constant of proportionality is k=1/4

Step-by-step explanation:

For the equation y=kx, y varies directly with x with the constant of proportionality k. Therefore, k=1/4 is the answer.

Answer:

See below

Step-by-step explanation:

I assume the function is [tex]f(x)=1+\frac{5}{x}-\frac{4}{x^2}[/tex]

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, [tex]x=0[/tex] is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

[tex]f(x)=1+\frac{5}{x}-\frac{4}{x^2}[/tex]

[tex]f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}[/tex]

[tex]0=-\frac{5}{x^2}+\frac{8}{x^3}[/tex]

[tex]0=-5x+8[/tex]

[tex]5x=8[/tex]

[tex]x=\frac{8}{5}[/tex]

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

[tex]f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}[/tex]

[tex]f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3[/tex]

Therefore, the function increases on the interval [tex](0,\frac{8}{5})[/tex] and decreases on the interval [tex](-\infty,0),(\frac{8}{5},\infty)[/tex].

C) Since we determined that the slope is 0 when [tex]x=\frac{8}{5}[/tex] from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, [tex]f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}[/tex], meaning there's an extreme at the point [tex](\frac{8}{5},\frac{41}{16})[/tex], but is it a maximum or minimum? To answer that, we will plug in [tex]x=\frac{8}{5}[/tex] into the second derivative which is [tex]f''(x)=\frac{10}{x^3}-\frac{24}{x^4}[/tex]. If [tex]f''(x)>0[/tex], then it's a minimum. If [tex]f''(x)<0[/tex], then it's a maximum. If [tex]f''(x)=0[/tex], the test fails. So, [tex]f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}<0[/tex], which means [tex](\frac{8}{5},\frac{41}{16})[/tex] is a local maximum.

D) Now set the second derivative equal to 0 and solve:

[tex]f''(x)=\frac{10}{x^3}-\frac{24}{x^4}[/tex]

[tex]0=\frac{10}{x^3}-\frac{24}{x^4}[/tex]

[tex]0=10x-24[/tex]

[tex]-10x=-24[/tex]

[tex]x=\frac{24}{10}[/tex]

[tex]x=\frac{12}{5}[/tex]

We then test where [tex]f''(x)[/tex] is negative or positive by plugging in test values. I will use -1 and 3 to test this:

[tex]f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34<0[/tex], so the function is concave down on the interval [tex](-\infty,0)\cup(0,\frac{12}{5})[/tex]

[tex]f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0[/tex], so the function is concave up on the interval [tex](\frac{12}{5},\infty)[/tex]

The inflection point is where concavity changes, which can be determined by plugging in [tex]x=\frac{12}{5}[/tex] into the original function, which would be [tex]f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}[/tex], or [tex](\frac{12}{5},\frac{43}{18})[/tex].

E) See attached graph

Answer:

2a - 5b = 1

3a + 5b = 14

Let's solve this system using elimination. Add the equations together to cancel the b-terms, then solve for a.

   2a - 5b = 1

  3a + 5b = 14

+___________

   5a - 0 = 15

        5a = 15

          a = 3

Next, plug 3 for a into either of the equations and solve for b.

 2a - 5b = 1

2(3) - 5b = 1

   6 - 5b = 1

      - 5b = -5

          b = 1

Lastly, check all work by plugging both values for their respective variables.

    2a - 5b = 1

2(3) - 5(1) = 1

        6 - 5 = 1  --  This is true

    3a + 5b = 14

3(3) + 5(1) = 14

        9 + 5 = 14  --  This is true

The solution to the system of equations is (3, 1).

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

Step-by-step explanation:

When it's clear, the easiest way to do the problem is to used the x and y  intercepts.

This question is one of the clear one.

The x intercept is 2,0

The y intercept is 0,1

You want the slope.

m = (y2 - y1)/(x2 - x1)

y2 = 1

y1 = 0

x2 = 0

x1 = 2

m = (1 - 0)/(0 - 2)

m = 1 / -2

m = -1/2

In this case the slope and gradient have the same value --   - 1/2 or - 0.5

[tex] {5}^{2} + {x}^{2} = {8}^{2} [/tex]

[tex]25 + {x}^{2} = 64[/tex]

Subtract both sides 25

[tex]25 - 25 + {x}^{2} = 64 - 25[/tex]

[tex] {x}^{2} = 39[/tex]

Thus :

[tex]x = \sqrt{39} [/tex]

[tex]x = 6.245[/tex]

Answer:

60 is the answer you're welcome

Answer:

64

Step-by-step explanation:

P E D M A S

() ² ÷ × + -

6 x 8 = 48

114 + 48 = 192

(192) ÷ 3 = g

192 / 3 = 64

g = 64

Answer:

5.32

Step-by-step explanation:

it had a more exact reading than the others

Step-by-step explanation:

1. 0.9862

2. 2.3

3. 7

4. 45.1

5. 18.735

Answer:

-1536

Step-by-step explanation:

By taking the general formula for the geometric sequence, we substitute the variables with the values of our sequence, finding -1536 as the 11th term

Answer:

m=-7/15

Step-by-step explanation:

Answer:

Step-by-step explanation:

7/15

Answer:

1) x>1

2) x<6

3) x>34

4) x>-4

5) x<2

6) x>-36

7) x<=4

8) x>-2

9) x>=2

10) x>14

Answer:

  (a) 43.6490°N, 70.3928°W

  (b) Baker's Field

Step-by-step explanation:

The locations are all within a 7-mile square, so we will make the assumption of a flat Earth with parallel longitude lines. Then the "central" location will be the weighted average of the latitude and longitude coordinates.

Total population is 16000 +22000 +36500 = 74,500. For purposes of the arithmetic, we will subtract 43 from latitude and 70 from longitude, then multiply each fraction by 10. Similarly, we will divide each population by 1000.

The weighted average location is found from ...

  (16/74.5)(6.769, 3.717) +(22/74.5)(5.781, 3.222) +(36.5/74.5)(6.795, 4.447)

  = (1.4537, 0.7983) +(1.7071, 0.9515) +(3.3291, 2.1787) = (6.490, 3.928)

The center of gravity is about 43.6490°N, 70.3928°W.

__

The coordinate differences from the center of gravity are (in (°lat, °long)) ...

  Baker's Field: (0.0294, -0.0101)

  Lonesome Acres: (-0.1371, -.0072)

Clearly, Baker's field is closer to the site of part (a).

_____

Additional comment

Distance calculations could be refined further by considering that a degree of longitude at this latitude represents about 0.72 times the distance of a degree of latitude. In this problem, the location of Lonesome Acres has a latitude difference that is several times any of the other coordinate differences, so it is clearly much farther away from the desired location.

The calculations done here are a sort of first-level approximation. The least-significant digits in the coordinates represent a distance of less than 50 feet. If you really want accuracy to that level, then the (approximately) spherical shape of the Earth needs to be accounted for. As a second-level approximation, some reference point needs to be identified, and coordinates in miles (or feet) need to be expressed in relation to that reference. The best accuracy would be obtained using spherical trigonometry to identify the distances.

We expect any school that is constructed to be somewhat larger than 50 feet in any direction, so accuracy to the 4th decimal place in these locations is probably not required--except to satisfy some answer-checker.

Answer:

4

Step-by-step explanation:

[tex](-4x^3-x^2+3)-(x^3-2x^2-7x+2)\\\\=-4x^3 -x^2 +3 - x^3 + 2x^2 + 7x -2 \\\\= -5x^3 +x^2 +7x +1 \\\\=-5x^3 -5x^2 +6x^2 +6x+ x+1\\\\=-5x^2(x+1) +6x(x+1) + (x+1)\\\\=(x+1)(-5x^2 +6x +1)\\\\=-(x+1)(5x^2 -6x -1)[/tex]

Answer:

check online for more information