Write an equation of the form y = mx for the line shown below. If appropriate,
use the decimal form for the slope.

Answer:

56.25metres

Step-by-step explanation:

Given the height of the ball h meters, above the ground after t seconds modeled by the function h(t) = -5t^2 + 15t + 45, at maximum height, the velocity is zero, hence;

dh/dt = 0

Since dh/dt = -10t + 15

-10t+ 15 = 0

-10t = -15

t = 15/10

t = 3/2

t = 1.5secs

Substitute t = 1.5 into the expression given

h(1.5) =  -5(1.5)^2 + 15(1.5) + 45

h(1.5) = -5(2.25)+22.5+45

h(1.5) = -11.25+67.5

h(1.5) = 56.25

Hence the maximum height is 56.25metres

Answer:

(10, - 1 )

Step-by-step explanation:

Given the 2 equations

x - 3y = 13 → (1)

x + 2y = 8 → (2)

Rearrange (1) making x the subject by adding 3y to both sides

x = 3y + 13 → (3)

Substitute x = 3y + 13 into (2)

3y + 13 + 2y = 8

5y + 13 = 8 ( subtract 13 from both sides )

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = 3(- 1) + 13 = - 3 + 13 = 10

solution is (10, - 1 )

Answer:

x = 5

Step-by-step explanation:

comment if you need explanation

Answer:

Step-by-step explanation:

It just so happens that x is the hypotenuse in the right triangle with sides 3 and 4. To find x we use Pythagorean's Theorem:

[tex]x^2=3^2+4^2[/tex] and

[tex]x^2=9+16[/tex] and

[tex]x^2=25[/tex] so

x = 5

Answer:

x = -6

Step-by-step explanation:

sum means +

36 + 3x = 18

3x = 18 - 36

3x = -18

x = -6

Answer:

Step-by-step explanation:

36 + 3x = 18

subtract 36 from both sides

3x= -18

divide by 3

x = -6

Answer: -16/3

Step-by-step explanation:

[tex]3(x - 2) + 4x = 10(x + 1)\\3x - 2(3) + 4x = 10x +1(10)\\3x - 6 + 4x = 10x + 10\\7x - 6 = 10x + 10\\7x - 10x = 10 + 6\\-3x = 16\\x = \frac{16}{-3} =-\frac{16}{3}[/tex]

Answer:

-16/3

Step-by-step explanation:

3(x – 2) + 4x = 10(x + 1)

Step 1 distribute the 3 to the x and -2

Outcome: 3x - 6 + 4x = 10(x + 1)

Step 2 distribute the 10 to the x and 1

Outcome: 3x - 6 + 4x = 10x + 10

Step 3 combine like terms

Outcome: 7x - 6 = 10x + 10

Step 4 add 6 to both sides

Outcome: 7x = 10x + 16

Step 5 subtract 10x from both sides

Outcome: -3x = 16

Step 6 divide both sides by -3

Outcome: x = -16/3

Answer:

Step-by-step explanation:

z = (k*x*y) / w²

Where,

k = constant of proportionality

z = 72 when x = 80, y = 30 and w = 5

z = (k*x*y) / w²

72 = (k * 80 * 30) / 5²

72 = 2400k / 25

Cross product

72 * 25 = 2400k

1800 = 2,400k

k = 2,400/1800

k = 24/18

= 4/3

k = 1 1/3

k = 1.33

find z when x = 20, y = 60 and w=9

z = (k*x*y) / w²

z = (1.33 * 20 * 60) / 9²

z = (1596) / 81

Cross product

81z = 1596

z = 1596/81

z = 19.703703703703

Approximately,

z = 19.7

Answer:

Step-by-step explanation:

This is from PLATO

Answer:

x = 24

Step-by-step explanation:

mathematically, in a cyclic quadrilateral, two opposite angles are supplementary

what this mean is that they add up to be 180

From what we have in the question, the two angles are supplementary and that means they add up to equal 180 degrees

thus, we have it that;

(4x + 9) + (3x + 3) = 180

4x + 3x + 9 + 3 = 180

7x + 12 = 180

7x = 180-12

7x = 168

x = 168/7

x = 24

Answer:

You need to convert all the units to one unit

Answer:

ok so lets divide 90 by 15 to get 6 so she gets paid 6 per student and that means lisa gets paid 12 so lets just multiply

6*20=120 so mary gets paid 120

and lisa gets paid doable that so 420

but i don't know there base pay so the i can't answer this problem

Hope This Helps!!!

Answer:

the distance between the lines is 2.48

Answer:

122-152z

Step-by-step explanation:

-6+ 8(16 - 19z)

= -6 + 128 - 152z

= 122 - 152z

I hope this helps!

Answer:

See step by Step

Step-by-step explanation:

Both are correct. As long as we undo the operations that was given from the original term to both sides until we get the variable by itself., any way can be applied.

Both, Spencer and Jeremiah are correct. We can verify this by testing their methods.

Spencer's method:

[tex]6x - 2 = - 4x + 2[/tex]

[tex]6x - 2 + 4x= - 4x + 2 + 4x[/tex]

[tex]10x - 2 = 2[/tex]

[tex]10x = 2 + 2[/tex]

[tex]10x = 4[/tex]

[tex]x = \frac{4}{10} [/tex]

[tex]x = 0.4[/tex]

Jeremiah's method:

[tex]6x - 2 = - 4x + 2[/tex]

[tex]6x - 2 - 6x = - 4x + 2 - 6x[/tex]

[tex] - 2 = - 10x + 2[/tex]

[tex] - 2 - 2 = - 10x[/tex]

[tex] - 4 = - 10x[/tex]

[tex] \frac{ - 4}{ - 10} = x[/tex]

[tex]0.4 = x[/tex]

As seen, we get the correct answer by using Spencer's and Jeremiah's method. So, we can say that they both are correct.

[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]

What is the slope of y = - x + 7

[tex] \red{ \bold{ \textit{STANDARD \: EQUATION}}}[/tex]

[tex]y = mx + c[/tex]

[tex]WHERE \\ m = SLOPE \\ c = Y - INTERCEPT[/tex]

[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]

[tex] \blue{A.T.Q}[/tex]

[tex]y = mx + c \sim y = ( - 1)x + 7[/tex]

[tex] \orange{SO}[/tex]

m= (-1)

which is equal to the slope of the equation .

[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]

Answer:

this as a equation looks like this

-1/2x+1+x=11

1/2x=10

x=20

Hope This Helps!!!

20 dollars were originally in the box

Two or more expressions with an Equal sign is called as Equation.

Given,

In an office there was a small cash box.

One day ann took half of the money plus$1 more

Then dan took half of the remaining money plus$1 more

Stan then took the remaining $11

-1/2x+1+x=11

Subtract 1/2x from both sides

1/2x=10

Multiply 2 on both sides

x=20

Hence, 20 dollars were originally in the box

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Answer:

35

Step-by-step explanation:

The exterior sum theorem states the exterior angle is equal to the sum of the opposite interior angles

145 = ?+110

145 - 100 = ?

35 = ?

Answer:

AL= 6.63

Step-by-step explanation:

C = 2[tex]\pi r[/tex]

C = 2[tex]\pi 10[/tex]

C = 20[tex]\pi[/tex]

[tex]AL = \frac{38}{360} 20\pi[/tex]

AL= 6.63

The length of the arc travelled by the car is 6.63 feet.

The distance along the part of circumference of any circle or any curve (arc) is called arc length of a circle.

Arc length = θ×[tex]\frac{\pi }{180}[/tex]× r

where,

θ is central angle of arc

r is the radius of circle

The diameter of a circle is any straight line segment that passes through the center of the circle and whose end points lie on the circumference of the circle.

diameter = 2× radius

According to the given question

we have

θ = 38 degrees

diameter = 20ft

⇒ radius = [tex]\frac{20}{2}[/tex]

⇒ radius = 10

Therefore,

the arc length the car traveled = 38×[tex]\frac{\pi }{180}[/tex]× 10

= 38×[tex]\frac{3.14}{180}[/tex]×10

=[tex]\frac{1193.2}{180}[/tex]

=6.63 feet

Hence, the arc length the car travelled is 6.63feet.

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Answer:

7500 m

Step-by-step explanation:

5500 is the initial height. It increased by 1500, so 5500 + 1500 = 7000. Then it went down 2000 meters, so 7000 - 2000 = 5000. It went up 2500 again. 5000 + 2500 = 7500

Answer:

Kindly check attached picture

Step-by-step explanation:

Based d on the instruction given.

1.)

-3 * 6 = 18

6 * - 2 = - 12

-3 * - 2 = 6

2.)

We use logical reasoning to find 2 numbers whichbwhen multiplied gives the number in the box in between :

The answers are given in the picture attached.

Answer:

[tex]T' = (-7,10)[/tex]

Step-by-step explanation:

Given

[tex]T = (10,7)[/tex]

[tex]r = 270^o[/tex] counterclockwise

Required

Graph of T'

The rule to this is:

[tex](x,y) \to (-y,x)[/tex]

So, we have:

[tex]T(10,7) \to T' (-7,10)[/tex]

Hence:

[tex]T' = (-7,10)[/tex]

See attachment for graph

Answer:

[tex]2y^2-7y+6=0[/tex]

Step-by-step explanation:

We are given that [tex]\alpha[/tex] and [tex]\beta[/tex] are the zeroes of the polynomial [tex]6y^2-7y+2[/tex]

[tex]y^2-\frac{7}{6}y+\frac{1}{3}[/tex]

We have to find a quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex].

General quadratic equation

[tex]x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes[/tex]

We get

[tex]\alpha+\beta=\frac{7}{6}[/tex]

[tex]\alpha \beta=\frac{1}{3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3[/tex]

Substitute the values

[tex]y^2-(7/2)y+3=0[/tex]

[tex]2y^2-7y+6=0[/tex]

Hence, the quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex] is given by

[tex]2y^2-7y+6=0[/tex]

Answer:

90 degrees

Step-by-step explanation:

B is the corner and angle opposite of the side AC.

so, AC is becoming side c, and the other two are a and b (it does not matter which is which).

we use the enhanced Pythagoras formula for general triangles

c² = a² + b² - 2ab×cos(C)

in our example the angle C is named B.

but other than that we simply calculate

10² = 6² + 8² - 2×6×8×cos(B)

100 = 36 + 64 - 96×cos(B)

100 = 100 - 96×cos(B)

0 = -96×cos(B)

cos(B) = 0

=>

B = 90 degrees

Answer:

102471 sq .in the land answer Teri ma ki bosra

Answer:

=256 pi

Step-by-step explanation:

The surface area of a sphere is

SA = 4pi r^2

SA = 4 pi (8)^2

     = 4 * pi *64

     =256 pi

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For question 1:

[tex]\to 3^{-4}= \frac{1}{3^4}=\frac{1}{81}=0.0123456789[/tex]

For question 2:

[tex]\to (-2)^{3}\cdot(-2)^{4}\cdot(-2)^{-1}=-8\cdot-16\cdot -\frac{1}{2}= 128\cdot -\frac{1}{2}=-64[/tex]

For question 3:

[tex]\to 7^{-4} \div 7^{-2}= \frac{1}{7^{4}} \div \frac{1}{7^{2}}=\frac{1}{7^{4}} \times \frac{7^{2}}{1}=\frac{1}{7^{2}} =\frac{1}{49} =0.0204081633[/tex]

For question 4:

[tex]\to [(-3)^{2}]^3= (-3)^{2\cdot 3}= (-3)^{6}=729[/tex]

For question 5:

[tex]\to [5 \cdot (-3)]^{2}= 25 \cdot 9=225[/tex]

For question 6:

[tex]\to [(10 \div 5)]^{3}= [(\frac{10}{5})]^{3}=[2]^{3}=8[/tex]

For question 7:

[tex]\to 10^6 \cdot 10^{-4} \cdot 10^2= 10^6 \cdot \frac{1}{10^{4}} \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000[/tex]

For question 8:

[tex]\to (-4)^{-5}=\frac{1}{(-4)^{5}}=- \frac{1}{1,024}=-0.0009765625[/tex]

For question 9:

[tex]\to \frac{2^3}{2^4}= \frac{8}{16}=\frac{1}{2}=0.5[/tex]

For question 10:

[tex]\to (-6)^3 \cdot (-6)^5 \cdot (-6)^{-5}= (-6)^3 \cdot (-6)^5 \cdot \frac{1}{(-6)^{5}}= (-6)^3 =-216[/tex]

12.

[tex]we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{26 + 22 + 32 + 28 + 35 + x}{6} = 30 \\ = > \frac{143 + x}{6} = 30 \\ = > 143 + x = 30 \times 6 \\ = > 143 + x = 180 \\ = > x = 180 - 143 \\ = > x = 37 \\ [/tex]

This is the answer.

Hope it helps!!

[tex] {\bold{\red{\huge{\mathbb{QUESTION}}}}} [/tex]

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

[tex]\bold{ \red{\star{\blue{GIVEN }}}}[/tex]

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

[tex]\bold{\blue{\star{\red{TO \: \: FIND}}}}[/tex]

Average cost of 7 articles

[tex] \bold{ \green{ \star{ \orange{FORMULA \: USED}}}}[/tex]

[tex] \red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}[/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

[tex]Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k[/tex]

Answer:

49

Step-by-step explanation:

Answer:

[tex]{ \bf{f(x) = {x}^{3} + {ax}^{2} - 1 }} \\ { \tt{f( - 1) : {( - 1)}^{3} + a {( - 1)}^{2} - 1 = 0}} \\ { \tt{f( - 1) : a - 2 = 0}} \\ a = 2[/tex]

The polynomial function [tex]$x^3 + ax^2 -1[/tex] will have -1 as a root at the value of

a = 2.

A polynomial function exists as a function that applies only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

Given: A root exists at a value of x such that the polynomial exists equivalent to zero.

Let, the polynomial equation be [tex]$x^3 + ax^2 -1[/tex]

then [tex]$\mathbf{f}(\mathbf{x})=\mathbf{x}^{3}+a \mathbf{x}^{2}-\mathbf{1}$[/tex]

Put, x = -1, then we get

[tex]$\mathbf{f}(-1)=(-1)^{3}+\mathrm{a}(-1)^{2}-1=0$[/tex]

f(-1) = a - 2 = 0

a = 2

Therefore, the value of a = 2.

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