A compound composed of 3. 3 % h, 19. 3 % c, and 77. 4 % o has a molar mass of approximately 60 g/mol. What is the molecular formula of the compound?.
The molecular formula of the given compound is [tex]$\mathrm{H}_{2} \mathrm{CO}_{3}$[/tex] also known as Carbonic acid.
What is empirical formula and molecular formula?The simplest whole-number ratio of the various atoms in a compound is represented by an empirical formula.
The precise number of various atom types present in a compound's molecule is indicated by the molecular formula.
Given that,
H = 3.3%
C = 19.3%
O = 77.4%
No. of moles of H = 3.3/1
No. of moles of H = 3.3
No. of moles of C = 19.3 / 12
No. of moles of C = 1.60
No. of moles of O = 77.4/16
No. of moles of O = 4.83
Therefore, the ratio of the atoms of C, H and O = 3.3 : 1.60 : 4.83
Divide by smallest value which you get =3.3 / 1.60 : 1.60 / 1.60 : 4.83 / 1.60
The ratio of the atoms of C, H and O = 2 : 1 : 3
So, the empirical formula is [tex]$\mathrm{H}_{2} \mathrm{CO}_{2}$[/tex]
Let the molecular formula is [tex]$\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) \mathrm{n}$[/tex]
Then, molar mass [tex]$=(2 \times 1+1 \times 12+3 \times 16) n\\[/tex]
Molar mass = 62n
As the question, 62 n = 60
n = 0.96 or n = 1 (rounded off to nearest ones)
So, the molecular formula is [tex]$\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) 1=\mathrm{H}_{2} \mathrm{CO}_{3}$[/tex] i.e., the compound is Carbonic acid.
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The hydrolysis of esters in base is called ________. a. the hunsdiecker reaction b. transesterification c. saponification d. the dieckmann condensation
The hydrolysis of esters in base is called saponification .
So, option C is correct one.
The saponification is the process that involves conversion of fats , oils , lipids into soap and water in the presence of alkaline medium. Saponification is the process of making soap.
During the saponification process, the mixture has an acidity, which tells that it's not safe for usage. After the saponification process is complete, the pH should be a base.The process of formation of carboxylic salt and water by hydrolysis of ester in base is called saponification.
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Which of these molecules have all atoms lying in the same plane? a. cbr4 and nh3 b. pf5 c. nh3 and hcn d. so3 and hcn
Molecules having all atoms lying in the same plane is c) HCN
HCN is a molecule in which all the atoms in the same plane i.e. it is a Planar molecule.
A Planar molecule is the one in which atoms are arranged in same plane i.e. atoms arrange themselves to exist in a two dimensional plane around the central atom.
The presence of double bond or triple bond in a molecule allows the molecule to get arranged in a plane.
The presence of triple bond in HCN allows it to be arranged in a plane.
HCN to be specific is a Linear molecule in which the angle between H and CN is 180.
The bond between C and N atom is a triple bond containing two pie bonds and one sigma bond.
Hence c) HCN is a planar molecule.
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Select true or false: if 2mg(s) o2(g) → 2mgo(s), δh° = –1203. 6 kj/mol, then formg(s) (1/2)o2(g) → mgo(s), the enthalpy change is δh = –601. 8 kj/mol
According to the given equation ,if 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6
k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, hence the given statement is true.
What do you mean by enthalpy change?An enthalpy change is roughly equivalent to the energy gained through the production of new chemical bonds in a reaction minus the energy required to break existing chemical bonds.
It describes how a system changes in terms of energy while pressure is constant.
The symbol ΔH stands for enthalpy change. At constant pressure, ΔH is equal to the sum of the system's internal energy and the pressure-volume work it performs on its surroundings.
It is expressed in units of joules per mole.
If 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6
k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, therefore the above given statement is true.
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Name the following compound: CH₂-C- CH₂-CH₂-CH₂-C - H butanal O2-butanol O propyl hydrogen ether 1-propanone
Answer:
butanal
Explanation:
It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
Hope this helps :)
Answer:
Butanal
Explanation:
trust
List the procedural steps, from start to finish, that are required to convert 2‑naphthol and allyl bromide into allyl 2‑naphthyl ether.
Catalysis is the process of boosting the pace of a chemical reaction by using a catalyst. Catalysts are not consumed in the reaction and so survive it.
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What would cause the equilibrium to shift left in this reaction? co 3h2 ⇌ ch4 h2o
option (A) Adding heat to the product mixture is the right answer.
As the reactant side has more moles than the product side, the equilibrium of the reaction shifts to the left to decrease pressure by increasing volume.
If the temperature drops, equilibrium also moves to the left.
Given equation is co+ 3h2 ⇌ ch4+ h2o
When heat is added to the product mixture in this situation, equilibrium moves to the left.
What is meant by equilibrium?A condition where opposing forces or actions are in balance is known as equilibrium.
What two types of equilibrium are there?Equilibrium is of two types:
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9.0 mol Na2S can from 9.0 mol CuS and 8.0 mol CuSO4 can form 8.0 mol Cus.
What mass of Cus forms during the reaction?
Cus; 95.62 g/mol
Answer:
765.0 grams CuS
Explanation:
The limiting reagent is the reactant which completely reacts before the other reactant(s) is used up. When 9.0 moles Na₂S and 8.0 moles CuSO₄ react, it appears that CuSO₄ is the limiting reagent. You can tell because it results in the production of less product.
You can determine the mass of CuS by multiplying the moles by the molar mass. It is important to arrange the ratio in a way that allows for the cancellation of units.
Molar Mass (CuS): 95.62 g/mol
8.0 moles CuS 95.62 g
------------------------- x ----------------------- = 765.0 grams CuS
1 mole
Determine the [oh−] , ph, and poh of a solution with a [h ] of 7. 2×10−8 m at 25 °c
The pH= 7.57 , pOH = 6.86, and [OH-] = 1.58 x 10⁻⁴ M M of the given solution.
What is pH?pH is a scale that measures the acidity and basicity of a solution. Its ranges from 1 to 14. Seven is neutral.
The H given is 7. 2 × 10⁻⁸ m
Calculating the pOH
[H⁺] = 10^(-7.20)
[H⁺] = 6.31 x 10⁻⁹ M
pOH = 14 - 7.2
pOH = 6.8
Calculating the [oh−]
[OH⁻] = 1 x 10⁻¹⁴ / 6.31 x 10⁻⁹
[OH⁻] = 1.58 x 10⁻⁴ M
Calculating the pH
pH = 14 - 6.43
pH = 7.57
Thus, the pH= 7.57 , pOH = 6.86, and [OH-] = 1.58 x 10⁻⁴ M.
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A mixture of three gases containing an equal number of moles of each gas has a total pressure of 12. 0 atm. What is the partial pressure of each gas?
A mixture of three gases containing an equal number of moles of each gas has a total pressure of 12. 0 atm then partial pressure of each gas is 4 atm .
Calculation ,
According to Dalton law the total gas of the container is equal to the sum of partial pressure of each gas .
[tex]P_{t}[/tex] = [tex]P_{1}[/tex] +[tex]P_{2}[/tex]+ [tex]P_{3}[/tex]
Partial pressure = total pressure × mole fraction
mole of each gas is equal . So, mole fraction is also equal for each gas.
Let the number of mole = x
mole fraction = x/3x =1/3
[tex]P_{1}[/tex] = 12. 0 atm/3 = 4 atm
[tex]P_{2}[/tex] = 12. 0 atm/3 = 4 atm
[tex]P_{3}[/tex] = 12. 0 atm/3 = 4 atm
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Helium and methane gases are mixed together in a container. what is the ratio of their root-mean-square speeds, i. e. (vrms,helium) / (vrms,methane) ?
Root mean square speed is the estimation of the effect of temperature and weight on kinetic energy. The root means square speed for a mixture of helium and methane is 2. Thus, option d is correct.
What is the root mean square speed?Root mean square speed is the estimation of the square root of the mean value of the squared speeds of the individual gas particles in the mixture.
As it is known that,
Root mean square speed = √{3RT/M}
Where T is constant temperature and R is gas constant. The molecular mass of helium gas is 4 g/mol and of methane is 16 g/mol.
Vrms = √{3RT/M}
For helium, Vrms = √{3RT/4}
And, for methane = Vrms = √{3RT/16}
So, (Vrms,helium) / (Vrms,methane) = 4 / 2 = 2
Therefore, option d. 2 is the root-mean-square speed for the mixture.
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Your question is incomplete, but most probably your full question was, Helium and methane gases are mixed together in a container. what is the ratio of their root-mean-square speeds, i. e. (Vrms, helium) / (Vrms, methane)?
1/2102cannot tell41/4When the ph of an aqueous solution is changed from 1 to 2, the concentration of hydronium ions in the solution is.
Answer:
decreased by a factor of 10
Explanation:
pH is defined in such a way that;
pH= −log10(H)
Where H represents the concentration of Hydronium or Hydrogen ions
Given that pH is changed from 1 to 2,
By rearranging the above formula , we get 10−pH = H
if pH=1,H=10−1=0.1Mif pH=2,H=10−2=0.01MTherefore, 0.1/0.01 = 10 and 0.1 > 0.01
Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10
If 20. 3 grams of an aqueous solution of iron(ii) chloride, fecl2, contains 2. 71 grams of iron(ii) chloride, what is the percentage by mass of iron(ii) chloride in the solution?
If 20. 3 grams of an aqueous solution of iron(ii) chloride contains 2. 71 grams of iron(ii) chloride, then percentage by mass of iron(ii) chloride in the solution is 13.34%
Calculation,
Given:
mass of an aqueous solution of iron(ii) chloride = 20. 3 grams
mass of iron(ii) chloride = 2. 71 grams
The percentage by Mass is equal to percentage of mass of solute present in total mass of solution. It is also known as Mass percentage.
percentage by Mass = 100× 2. 71 grams/20. 3 grams = 13.34%
Hence, the percentage by mass of iron(ii) chloride in the solution is 13.34% .
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Liquid 1 reacts with liquid 2, producing a solid and a gas. using this scenario, which supports the law of conservation of mass? mass of liquid 1 mass of solid = mass of liquid 2 mass of gas mass of liquid 1 – mass of solid = mass of liquid 2 – mass of gas mass of liquid 1 – mass of liquid 2 = mass of solid mass of gas mass of liquid 1 mass of liquid 2 = mass of solid mass of gas
mass of Liquid 1 + mass of solid = mass of Liquid 2 + mass of gas mass of Liquid
The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as system's mass cannot change, so quantity cannot be added nor removed. Hence, the quantity of mass is conserved over time.
What is Law of conservation of mass ?According to the rule of conservation of mass, mass is neither generated nor destroyed during a chemical process. For instance, when coal is burned, the carbon atom in it transforms into carbon dioxide. The carbon atom transforms from a solid to a gas, yet its mass remains constant.
The understanding that substances do not actually vanish as a result of a reaction, despite what might appear to be the case, but rather change into another material of equal mass, was made possible by the law of conservation of mass, which was essential to the development of chemistry.Learn more about Law of conservation of mass here:
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Anil accidentally swallows a substance that activates the complement cascade in the absence of bound antibodies. this substance would:_______
Answer:
This substance would cause cause an extensive cellular damage to Anil.
How does the body structure of each of these organisms contribute to a particular function?
body structure: the shape of specific organs/attributes of an organism. This includes cells, tissues, organs, and systems.
function: the action or purpose an organ or attribute has.
ExamplesBody structure
Function
Teeth allow organisms to chew food so that it is easier to digest and/or rip food.Certain skin patterns/colors may help an organism camouflage in its surrounding enviornmentCan't Touch ThisSpiny KatydidWhat is a body structure of the Spiny Katydid?
Spines on the body
What is the function of this structure?
The spines on the Spiny Katydid's body prevent predators from having an easy time eating them
Further Notes:
Without the spines on their body, Spiny katydids would be more vulnerable to being eaten. The spines help them survive
Blow on Your FoodLonghorn CowfishWhat is a body structure of the Longhorn Cowfish?
puckered mouth
What is the function of this structure?
The puckered mouth allows the Longhorn Cowfish to blow jets of water.
Further Notes:
The jets of water the Longhorn Cowfish blows move the sand, exposing the organisms it eats. Without the puckered mouth, the Longhorn Cowfish would have difficulty finding food.
Night VisionTarsierWhat is the body structure of the Tarsier?
Huge eyes
What is the function of this structure?
The Tarsier's huge eyes allow it to see well.
Further Notes:
It's excellent vision helps it see and hunt for prey
Key Termsbody structure
function
What is true of a sample of gas particles as the temperature decreases?
Answer:The particles move faster, and their average kinetic energy decreases.
Explanation:
If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
The pH of the monoprotic weak acid is 2.79.
What are weak acids?The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.
The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).
c (monoprotic acid) = 0.33 M.
Ka = 1.2·10⁻⁶
[A⁻] = [H⁺] = x
[HA] = 0.33 M - x
Ka = [A⁻]·[H⁺] / [HA]
2. 6 × 10⁻⁶ = x² / (0.33 M - x)
Solve quadratic equation: [H⁺] = 0.000524 M.
pH = -log[H⁺]
pH = -log(0.000524 M)
pH = 2.79
Thus, the pH of the monoprotic weak acid is 2.79
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How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?
There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .
The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,
[tex]3CaCl_{2} (aq)+Al_{2} O_{3} (s)[/tex] → [tex]3CaO_{2} (s)+2Al Cl_{3} (aq)[/tex]
The molar ratio of above reaction is 3:1
It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.
The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles
The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .
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How many hydrogen bonds exist between this DNA strand and its complementary strand?
5'-TCCGGAG-3'
Answer:
19 hydrogen bonds
Explanation:
Between every thymine and adenine, there are 2 hydrogen bonds.
Between every guanine and cytosine, there are 3 hydrogen bonds.
Since there are 2 total thymines and adenines, they contribute 4 hydrogen bonds overall.
-----> 2 H bonds x 2 nucleotides = 4 H bonds
Since there are 5 total cytosines and guanines, they contribute 15 hydrogen bonds overall.
-----> 3 H bonds x 5 nucleotides = 15 H bonds
Therefore, there are 19 hydrogen bonds between the complementary strands.
How many moles of na2co3 are necessary to reach stoichiometric quantities with cacl2
0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary to reach stoichiometric quantities with cacl2.
Explanation:Based on the reaction
CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃
1 mole of CaCl₂ reacts per mole of Na₂CO₃
we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g
We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue. These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts. Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:Moles CaCl₂.2H₂O:1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂
Moles Na₂CO₃:
0.0102 moles Na₂CO₃
Mass Na₂CO₃:
0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present
Therefore, we can conclude that 0.0102 moles Na₂CO₃ is necessary.to reach stoichiometric quantities with cacl2.
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24. 00 ml of a 0. 25 m naoh solution is titrated with 0. 10m hcl. What is the ph of the solution after 24. 00 ml of the hcl has been added?.
pH of the solution after 24. 00 ml of the hcl has been added is 12.87
millimoles NaOH = mL x M = 24.00 mL x 0.25 M = 6.00
millimoles HCl = 24.00 mL x 0.10 M = 2.40
total volume = 48.00 mL
.................................NaOH + HCl ==>NaCl + H2O
initial.........................6.00.........0............0.........0
added.....................................2.40............................
change.................... -2.40......-2.40.........+2.40.... +2.40
equilibrium.................3.60.........0..............2.40.......2.40
The NaCl contributes nothing to the pH of the final solution. The pH is determined by the excess of NaOH present. (NaOH) = millimoles/mL = 3.60/48.00 = 0.075 M = (OH^-)
pOH = -log (OH^-). Then
pOH = -log (0.075)
pOH =1.1249
As we know,
pH + pOH = pKw = 14.00
pH=14-pOH
pH=14-1.1249
pH=12.87
What is pH?pH is a logarithmic measure of an aqueous solution's hydrogen ion concentration. pH = -log[H+], where log is the base 10 logarithm and [H+] is the concentration of hydrogen ions in moles per liter.
The pH of an aqueous solution describes how acidic or basic it is, with a pH less than 7 being acidic and a pH greater than 7 being basic. A pH of 7 is regarded as neutral (e.g., pure water). pH values typically range from 0 to 14, though very strong acids may have a negative pH and very strong bases may have a pH greater than 14.
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Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?
Cis-platin is a chemotherapy agent used to treat and kill cancerous cells in patients. One mole of cis-platin has a mass of 300.06 grams/mol. Thus, option B is correct.
What is a chemotherapy agent?A chemotherapy agent is an alkylating agent that is used to treat cancer and is given to reduce the infection or to relieve the symptoms. Cis-platin (Pt(NH₃)₂Cl₂) is one of the chemotherapy agents that treat lung, ovarian, and neck cancer, etc.
The mass of one mole of Cis-platin is calculated as,
Moles = mass ÷ molar mass
Where,
Moles = 1 mole
The molar mass of (Pt(NH₃)₂Cl₂) is calculated as,
195.06 g/mole + 2(17g/mole) + (35.5)2 = 300.06 grams
Substituting values to calculate mass:
Mass = Molar mass × moles
= 300. 06 × 1
= 300.06 grams/mol
Therefore, option B. 300.06 gm/mol is the mass of Cis-platin.
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Your question is incomplete, but most probably your full question was, Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?
488.91 g/mol 300.06 g/mol492.37 g/mol283.02 g/mol2860.5 g/molFor the reaction: n2(g) 2 o2(g) ⇌ 2 no2(g), kc = 8. 3 × 10-10 at 25°c. what is the concentration of n2 gas at equilibrium when the concentration of no2 is twice the concentration of o2 gas?
4.8 × 10^9 M is the concentration of n2 gas at equilibrium when the concentration of no2 is twice the concentration of o2 gas.
In some gas-producing fields, such as those in the US Midwest, North Sea, Eastern Europe, and South East Asia, nitrogen (N2) may naturally present in significant concentrations. Around 15% of the world's non-associated gas deposits have nitrogen content levels that are too high to be considered pipeline-quality gas (usually 3–4 mol%). Because it is an inert gas, nitrogen cannot support burning. Consequently, unstable combustion could result from burning a gas that contains too much nitrogen. The recovery of NGL content will be lowered when high nitrogen gas is treated in a gas plant because nitrogen acts as stripping gas. The compression technology and size of the transmission pipeline will rise with increased nitrogen concentration. High nitrogen levels are undesirable in an LNG plant because they lower the LNG temperature, which increases the energy required to liquefy natural gas and also increases the amount of boil-off gas from the LNG storage tanks.
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Potassium reacts with oxygen gas to produce potassium oxide. Determine the percent yield for the reaction between 8.92 grams of potassium and 3.28 grams of oxygen gas if 6.36 grams of potassium oxide are produced?
Answer:
Percent Yield K₂O = 59.2%
Explanation:
Before you can calculate the percent yield, you need to find the theoretical yield. This value is the amount of product produced using the balanced chemical equation and molar masses. However, the question does not specify which reactant is the limiting reagent. Therefore, you have to calculate the mass of the product starting from both values.
To find the theoretical yield, you need to (1) convert grams K/O₂ to moles K/O₂ (via molar masses), then (2) convert moles K/O₂ to moles K₂O (via mole-to-mole ratio from balanced equation coefficients), and then (3) convert moles K₂O to grams K₂O (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given values.
Molar Mass (K): 39.098 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
Molar Mass (K₂O): 2(39.098 g/mol) + 15.998 g/mol
Molar Mass (K₂O): 94.194 g/mol
The balanced equation:
4 K + O₂ -----> 2 K₂O
8.92 g K 1 mole 2 moles K₂O 94.194 g
-------------- x ----------------- x -------------------- x ---------------- = 10.7 g K₂O
39.098 g 4 moles K 1 mole
3.28 g O₂ 1 mole 2 moles K₂O 94.194 g
---------------- x --------------- x --------------------- x -------------- = 19.3 g K₂O
31.996 g 1 mole O₂ 1 mole
Because potassium produces the smaller amount of product, it is the limiting reagent. This means that all the potassium reactant is used up before the oxygen gas runs out. So, the theoretical yield of potassium oxide is 10.7 grams.
Now, you can use the theoretical yield and actual yield to determine the percent yield.
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
6.36 g K₂O
Percent Yield = ------------------------ x 100%
10.7 g K₂O
Percent Yield = 59.2%
During transpeptidation, nucleophilic attack occurs between the α-amine group in the ____ site and the esterified carbon in the ____ site.
During transpeptidation, nucleophilic attack occurs between the α-amine group in the A site and the esterified carbon in the P site
What is transpeptidation ?A chemical process in which an amino acid residue or peptide residue is transferred from one amino compound to another. This process occurs when a protease reversibly converts one peptide to another.
a process where one or more amino acids are transferred from one peptide chain to another, as in the case of a transpeptidase activity, or where a peptide chain itself is produced, as in the case of the production of a bacterial cell wall.Peptidoglycan glyco-syltransferases create the glycan strands (PGTs). The most popular class of antibiotics' fatal targets are enzymes termed transpeptidases (TPs), which produce the peptide crosslinks: using beta-lactamsLearn more about Transpeptidation reaction here:
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Exercise 3 - questions 1. what types of properties about the substance that you tested did you use to determine whether you thought it was an acid or base?
There are some types of properties about the substance that you tested did you use to determine whether you thought it was an acid or base. Some are given below.
Litmus paper : If a blue litmus paper turns red the solution is acid, it means its pH level is less than 7. If a red litmus paper turns blue the solution is basic,It means its pH level is more than 7.Indicators : Different indicators is used to determine whether a solution is acidic or basic. The common examples of indicators are methyl orange and phenolpthalein .Substances that are used to determine whether a particular substance is an acid or base are called indicator. The indicator is a dye that is weak an organic acid or base that changes color when it is added to an acid and base.
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In the lewis structure of HCN. How many nonbonded (lone) electron pairs are present?
In lewis structure of HCN, we can observe one lone pair of electron.
The 7 protons in the nitrogen nucleus are balanced by the 3 electrons from the triple bond, the 2 electrons from its lone pair, and the 2 inner core electrons that make up the nitrogen nucleus. As a result, nitrogen is formally neutral.What is meant by lewis structure?The valence shell electrons in a molecule are depicted in an extremely simplified manner by a Lewis Structure. It is used to demonstrate how the electrons in a molecule are positioned around particular atoms. Electrons are shown as "dots" or, in the case of a bond, as a line connecting the two atoms.How should a Lewis structure be written?Step 1: Finding the total amount of valence electrons.Step 2: Outline the molecule's skeletal structure. Step 3: Form each bond in the skeletal structure using two valence electrons. Step 4: Try to distribute the leftover valence electrons as nonbonding electrons in order to fill the atoms' octets.To learn more about lewis structure visit:
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When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by phosphorus in the pcl4 cations?
When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.
What is sp³ hybridization?Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.
The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.
Therefore, pcl4 cation is sp³ hybridized.
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If a substance x has a solubility of 2. 4×10^−5 mg/l, and a molar mass of 188 g/mol. What is the molar solubility of the substance?
The molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex] M if a substance x has a solubility of 2. 4 × [tex]10^{-5}[/tex] mg/l, and a molar mass of 188 g/mol.
Calculation ,
The number of moles dissolve in one liter of solution is called molar solubility.
Given Solubility = 2.4 × [tex]10^{-5}[/tex] mg/L
Solubility = 2.4 × [tex]10^{-5}[/tex] × [tex]10^{-3}[/tex] g/L = 2.4 × [tex]10^{-8}[/tex] g/L
Molar mass = 188 g/mol
Molar Solubility = 2.4 × [tex]10^{-8}[/tex] g/L / 188 g/mol = 0.012 × [tex]10^{-8}[/tex] mol/L
Molar Solubility = 1.2 × [tex]10^{-10}[/tex] M
Therefore , the molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex] M
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