Write an equation that represents the line.
Use exact numbers.

Answer:

A

Step-by-step explanation:

Two angles whose sum is 90° are complementary angles.

∠ A + ∠ B = 36° + 54° = 90°

Then ∠ A and ∠ B are complementary angles

The solution is: If the measure of < A is 36 °, and the measure of < B is

54 ° , then < A and < B are a. complementary angles

In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.

We know that, a ray is a line that continues on forever inn one direction with a point at it's start.

Here, we have,

Two angles whose sum is 90° are complementary angles.

∠ A + ∠ B

= 36° + 54°

= 90°

so, we get,

Then ∠ A and ∠ B are complementary angles

Hence, The solution is: If the measure of < A is 36 °, and the measure of < B is  54 ° , then < A and < B are a. complementary angles

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Answer:

2/60 = 1/30 = 3.3%

Step-by-step explanation:

Answer:

3 to the power of 4 equals 81 times 3 equals 243

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

because y-intercept is when x=0, so right on the y axis.

Answer: A.Spreads: The weights of the tigers are more spread out.

B.Centers:The leopards have a lower median weight than the tigers

Step-by-step explanation:

On analyzing the dot plots, we find that the weight of Leopards are more spread out and the weight of Leopards has a lower median than Tiger.

Median is a statistical measure that determines the middle value of a dataset listed in ascending order. The measure divides the lower half from the higher half of the dataset.

Median of Weight of Leopard = 50 kg

Median of Weight of Tiger = 125 kg

This implies that the Leopards have a lower median weight than Tigers.

What is spread of data?

Spread describes the variation of the data. One of the measures of spread is range.

Range of weight of Leopards= 40 kg

Range of weight of Tigers = 90 kg

This implies that the weight of Tigers are more spread out.

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Answer:

2.5 years

Step-by-step explanation:

The given amount invested, which is the principal, P = $16,800

The simple interest rate, R = 5% per annum

The intended total value of the investment, A = $18,900

The simple interest on the principal, I = A - P

∴ I = $18,900 - $16,800 = $2,100

The formula for the simple interest, I, is given as follows;

[tex]I = \dfrac{P \times R \times T}{100}[/tex]

Therefore, we have;

[tex]T = \dfrac{I \times 100}{P \times R}[/tex]

Plugging in the values, gives;

[tex]T = \dfrac{2,100 \times 100}{16,800 \times 5} =2.5[/tex]

The time it will take the investment to grow to $18,900 is T = 2.5 years

Answer:

Get all the values of the histogram and put them in order:

For example 2,5,7,1,7,3  becomes 1,2,3,5,7,7 and then you get the middle number, which is in this case (3+5)/2=3.5

Then see which of the readings lie on 3.5.

Step-by-step explanation:

9514 1404 393

Explanation:

The histogram will have a count associated with each class. You may have to read the count from the vertical scale of the graph. If it is a histogram of relative frequencies, each class will have a fraction or percentage instead of a count.

Find the total of all counts. Determine what half that number is. If the total is odd, then round up to the nearest integer. This is the index number of the median value.

Add up the counts in the classes starting at one side of the graph, working toward the other side. (Left-to-right is the usual direction for doing this.) When you find the class that increases the total to a value equal or greater than the index number, this is the class that contains the median.

__

If the histogram is a relative frequency histogram, the class that brings the total to 50% is the one containing the median.

__

There may be cases where the total count is even, and the total of all of the classes up to a point is exactly equal to the index number you're looking for. In that case, the median is between that class and the next. Here's an example:

  class 1: count 3

  class 2: count 5

  class 3: count 4

  class 4: count 4

Total count: 3+5+4+4 = 16. Median index = 16/2 = 8

Total of classes 1 and 2 = 3+5 = 8. This means exactly half of the represented values are in class 2 or below, and half are in class 3 or above. If you had access to the actual data values, you would find the median as the average of the 8th and 9th data values (when they are sorted into increasing order). Here, the median might be estimated as the value halfway between the upper bound of class 2 and the lower bound of class 3.

__

2nd example

Consider the same histogram as above, but with a count of 3 in class 4. This brings the total count to 15, and the index of the median is 15/2 = 7.5, rounds to 8. Again, the 8th data value (median) is in class 2. There is no ambiguity in this case.

Answer:

(-1,1)

Step-by-step explanation:

(x,y), and X is one unit to the left (negative, or -), while Y is one unit up

Answer:

i don't know how to work this

Answer:

x = [tex]\frac{3}{4}[/tex] , x = 20

Step-by-step explanation:

2([tex]\frac{3x-5}{x+2}[/tex] ) - 5 ([tex]\frac{x+2}{3x-5}[/tex] ) = 3

Multiply through by (x + 2)(3x - 5) to eliminate the fractions

2(3x - 5)² - 5(x + 2)² = 3(x + 2)(3x - 5) ← expand factors on both sides

2(9x² - 30x + 25) - 5(x² + 4x + 4) = 3(3x² + x - 10) ← distribute parenthesis

18x² - 60x + 50 - 5x² - 20x - 20 = 9x² + 3x - 30 ← simplify left side

13x² - 80x + 30  = 9x² + 3x - 30 ( subtract 9x² + 3x - 30 from both sides )

4x² - 83x + 60 = 0 factor by splitting the x- term

4x² - 80x - 3x + 60 = 0

4x(x - 20) - 3(x - 20) = 0

(4x - 3)(x - 20) = 0

Equate each factor to zero and solve for x

4x - 3 = 0 ⇒ 4x = 3 ⇒ x = [tex]\frac{3}{4}[/tex]

x - 20 = 0 ⇒ x = 20

Answer

15. 12/25

Step-by-step explanation:

Because the surface value of this question

[tex]\large{\textrm{{{\color{navy}{ax³ + bx² + cx + d}}}}}[/tex]

Answer:

Equal to 1,204-299

Step-by-step explanation:

Anything divided by 1 is equal to itself.

[tex]{ \bf{ \underbrace{Given}}}[/tex]:

Diameter of the circle "[tex]d[/tex]" = [tex]36[/tex]

Value of [tex]π[/tex] = [tex]3[/tex]

[tex]{ \bf{ \underbrace{To\:find}}}[/tex]:

The circumference "[tex]C[/tex]" of the circle.

[tex]{ \bf{ \underbrace{Solution }}}[/tex]:

[tex]\sf\pink{The\:circumference \:"C"\:of\:the\:circle\:is\:108.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

We know that,

[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:πd }[/tex]

[tex] = 3 \times 36[/tex]

[tex] = 108[/tex]

Therefore, the circumference of the circle is [tex]108[/tex].

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Answer:

[tex]\Longrightarrow: \boxed{\sf{108}}[/tex]

Step-by-step explanation:

Apply the formula for the circle's circumference.

[tex]\text{Circumference circle formula:}[/tex]

[tex]\Longrightarrow: \sf{C=\pi d}[/tex]

[tex]\Longrightarrow:\sf{C=?}\\\\\Longrightarrow:\sf{\pi =3}\\\\\Longrightarrow:\sf{d=36}[/tex]

Multiply.

[tex]\sf{3*36=\boxed{\sf{108}}[/tex]

I hope this helps! Let me know if you have any questions.

Answer:

no

Step-by-step explanation:

12 squared plus 5 squared=169

Answer:

Both the answers will be B

With ASA, we need two angles and an included side. An included side is one that is between the two angles.

But, we need to make sure the sides match up. So, triangle KJI is congruent to triangle ZYX.

Therefore, we need to know that side JI is congruent to YX.

Hope this helps!

Answer:

It is the last one: (4x-9)(x+8)

Step-by-step explanation:

You have to split the "b", or split the 23x so that you can perform grouping, and then combine.

Answer:

(4x-9)(x+8)is the correct answer

Answer:

x = 41 degrees

Step-by-step explanation:

Since two of the sides are shown as being congruent, the base angles are the same. We are given the top angle, which is 98 degrees. All the angles of a triangle add up to 180. We can subtract 98 from 180, giving us 82, and divide that by two (since the base angles are congruent), giving us a measure of 41 degrees for each of the bottom angles of the isosceles triangle.

Answer:

Step-by-step explanation:

A prime number (or a prime) is a natural number greater than 1 that is not a product of two smaller natural numbers.

A prime number is a number that has only two divisors: 1 and itself.

Exaples:

2, 3, 5, 7, 11, 13, 17, 19, 23 ...

We know: all primes except 2 are odd.

Let's check the number 199:

We know:

13² = 13 · 13 = 169 < 200

17² = 17 · 17 = 289 > 200

199 : 3 is not an integer

199 : 5 is not an integer

199 : 7 is not an integer

199 : 11 is not an integer

199 : 13 is not an integer

199 : 17 is not an integer

Therefore 199 is thelargest prime number less than 200.

Answer:

Range D = {-7, 1, 9, 17}

Step-by-step explanation:

f(x) = 4x + 9

4(-4) + 9 = -7

4(-2) + 9 = 1

4(0) + 9 = 9

4(2) + 9 = 17

Answer: (-1, 2)

Step-by-step explanation:

Let's start by solving for x in

[tex]-5x+2y=9\\-5x+2y+-2y=9+-2y\\-5x=9+-2y\\\frac{-5x}{-5} =\frac{9+-2y}{-5} \\x=\frac{2}{5} y+\frac{-9}{5}[/tex]

We can now sub this value of x in 3x+5y=7 and solve

[tex]3x+5y=7\\3(\frac{2}{5} y+\frac{-9}{5})+5y=7\\(3)(\frac{2}{5} y)+(3)(\frac{-9}{5})+5y=7\\\frac{6}{5} y+\frac{-27}{5}+5y=7\\\frac{6}{5} y+\frac{25}{5}y +\frac{-27}{5}=7\\\frac{31}{5} y+\frac{-27}{5}=7\\\frac{31}{5} y+\frac{-27}{5}+\frac{27}{5}=7+\frac{27}{5}\\\frac{31}{5} y=\frac{62}{5} \\\frac{\frac{31}{5} y}{\frac{31}{5}} =\frac{\frac{62}{5} }{\frac{31}{5}} \\y=2[/tex]

Now we can sub in 2 for y in one of the equations

[tex]3x+5(2)=7\\3x+10=7\\3x+10-10=7-10\\3x=-3\\\frac{3x}{3} =\frac{-3}{3} \\x=-1[/tex]

x=-1 and y=2 giving us the point (-1, 2)

Answer:

15.87 %

Step-by-step explanation:

z = (.9-1)/.1 = -1

z score of -1 = .1587

The probability that a randomly selected small size package has a weight of less than 0.9 pounds is 15.87 %

We have given that,

A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pounds. If the distribution of weights for the small-size packages of ground meat is approximately normally distributed

[tex]Z = \frac{x - \mu}{\sigma}[/tex]

Z = standard score

x = observed value

[tex]\mu[/tex] = mean of the sample

[tex]\sigma[/tex] = standard deviation of the sample

z = (0.9-1)/0.1 = -1

z of -1 = 0.1587

Therefore the value of the z-score is 0.1587.

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Answer:

C.

Step-by-step explanation:

i guess it's letter c. y=50

Answer:

3x-2

---------

x-1

Step-by-step explanation:

simplify 18x/6x = 3x/1x

simplify 108/54 = 2/1

Answer:

Domain is [-5, 5]

Range is [-3, 17]

Step-by-step explanation:

R1 = {(x, y)| y = 2x + 7, where x∈ R and -5 ≤ x ≤ 5}

The domain is given by the all possible input values of x . Here the function is defined for -5 ≤ x ≤ 5, so the domain is [ - 5, 5].

The range is given by the output values  of he function.

When x = - 5

f (- 5) = 2 (-5 ) + 7 = - 3

When x = 5

f (5) = 2 (5) + 7 = 17

So, the range is [ -3 , 17].

Step-by-step explanation:

Answer:

{\color{#c92786}{6-4y}}=8

6−4y=8

−4+6=8

{\color{#c92786}{-4y+6}}=8

−4y+6=82

Subtract from both sides of the equation

=

−

1

2

Hello,

A:

[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]

B:

[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]