Write an equation to match this graph.
Use the multiplication chart, 120 chart ,1,000 chart to help with the equation

Y _ _ _
---↑ ↑ ↑

1. _

A. X

B. 2

2. _

A. -

B. ÷

C.×

D. +

3._

A. X

B. 2

For Fund 1, the expected return is 5% with a standard deviation of 13.42%. For Fund 2, the expected return is 2% with a standard deviation of 24.66%. If risk-averse, Fund 1 is preferred.

To find the expected value and standard deviation of returns for Fund 1, we use the formula

Expected value = Σ(Probability of state of economy × Return for that state)

Standard deviation = sqrt[Σ(Probability of state of economy × (Return for that state - Expected value)^2)]

Expected value of Fund 1 = (0.2 × 20) + (0.5 × 10) + (0.3 × (-10)) = 5%

Standard deviation of Fund 1 = sqrt[(0.2 × (20-5)^2) + (0.5 × (10-5)^2) + (0.3 × (-10-5)^2)] = 13.42%

To find the expected value and standard deviation of returns for Fund 2, we use the same formula

Expected value of Fund 2 = (0.2 × 40) + (0.5 × 20) + (0.3 × (-40)) = 2%

Standard deviation of Fund 2 = sqrt[(0.2 × (40-2)^2) + (0.5 × (20-2)^2) + (0.3 × (-40-2)^2)] = 24.66%

If you are risk-averse, you would prefer a lower-risk investment with a lower standard deviation. Based on the standard deviations calculated above, Fund 1 is the lower-risk option, so you should pick Fund 1.

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The number represented by each point on the number line is:

Point A: 1 2/3

Point B: 2

A number line is a visual representation of the real number system, where each point on the line corresponds to a specific real number.

Looking at the given number line, you will notice that there are 3 spaces between 0 and 1. This implies:

3 spaces = 1 unit

1 space =  1/3 unit

Thus, we can say the value of the points are:

Point A: 1 2/3

Point B: 2

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The surface area generated by rotating the given curve about the y-axis is approximately 5.37 square units.

For finding the surface area generated by rotating a curve around the y-axis, the formula is S=2π∫aᵇ y√(1+(dy/dx)²) dx. To apply this formula, we find dy/dx and integrate the given curve.

Similarly, for the curve x=9t², y=6t³, we use the formula for parametric equations, Surface Area = ∫[2πx * sqrt((dx/dt)² + (dy/dt)²)] dt, from t=0 to t=5, and integrate it.

To find the surface area generated by rotating the given curve about the y-axis, we need to use the formula:

S = 2π∫aᵇ y√(1+(dy/dx)²) dx

First, we need to find dy/dx:

dx/dt = 18t
dy/dt = 18t²

dy/dx = dy/dt ÷ dx/dt = 18t² ÷ 18t = t

Now, we can plug in y and dy/dx into the formula and integrate from 0 to 5:

S = 2π∫0⁵ 6t³ √(1+t²) dt
S = 2π∫0⁵ 6t³(1+t²)⁽¹/²⁾ dt

This integral is a bit tricky to solve, so we can use integration by substitution. Let u = 1+t², then du/dt = 2t and dt = du/2t. Substituting into the integral:

S = 2π∫1²⁶(u-1)⁽¹/²⁾ du/2
S = π∫1² (u-1)⁽¹/²⁾ du
S = π(2/3)(2⁽³/²⁾ - 1)

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If n is the degree of PG(x), then n = V = 1, which means that PG(x) consists of a single vertex.  In this context, the degree "n" of PG(x) represents the highest power of the variable "x" in the polynomial function.

The number of vertices "V" represents the points where the graph changes direction. Using the given hint, it is important to note that for a polynomial of degree "n", there will be at most (n-1) turning points (vertices) in the graph. However, this does not guarantee that n = V, since there can be fewer vertices than the maximum possible. The relationship between the degree "n" and the number of vertices "V" is that V is less than or equal to (n-1). So, for a polynomial graph PG(x) with a degree of n, the number of vertices V will be less than or equal to (n-1). The degree of a vertex in a graph is defined as the number of edges incident to that vertex. Therefore, if n is the degree of PG(x), it means that the vertex x has n edges incident to it.  Now, we know that the sum of the degrees of all vertices in a graph is equal to twice the number of edges.

In other words,
∑deg(v) = 2E
where deg(v) represents the degree of vertex v, and |E| represents the number of edges in the graph.
Using this formula, we can write:
n + ∑deg(v) = 2E
Since vertex x has degree n and all other vertices have degrees that are less than or equal to n (because PG(x) is a subgraph of PG), we can rewrite the above equation as:
n + (V-1)n ≤ 2E
Simplifying this expression, we get:
nV ≤ 2E
But we also know that the number of edges in a graph is equal to half the sum of the degrees of all vertices (because each edge contributes to the degree of two vertices). In other words,
E = (1/2)∑deg(v)
Substituting this into the previous expression, we get:
nV ≤ ∑deg(v)
But we already know that vertex x has degree n, so we can simplify this to:
nV ≤ n + ∑deg(v)
Since we are given that n is the degree of PG(x), we can rewrite this as:
nV ≤ n + n

Simplifying further, we get:
nV ≤ 2n
Dividing both sides by n (which is nonzero since the degree of a vertex is always positive), we get:
V ≤ 2
But we also know that V is a positive integer, so the only possible value for V is 1 (because 0 and negative values are not allowed).
Therefore, if n is the degree of PG(x), then n = V = 1, which means that PG(x) consists of a single vertex.

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For this study, what is the response variable is b. Whether or not a student graduates from college.

The outcome of an experiment in which the explanatory variable is altered is the response variable. It is a variable whose variation can be accounted for by other variables. It is also known as the outcome variable or the dependent variable. As an illustration, the students wish to utilise height to predict age; hence, height is the explanatory variable and age is the response variable.

Whether a student in the example graduates from college. The university official is interested in examining this variable to see whether it has any associations with the predictor variable, which is whether students declare their majors before their junior year. A is the predictor variable. if a student chooses a major prior to entering their junior year.

Complete Question:

A university official wants to determine if a relationship exists between whether students choose their majors before their junior year and whether they graduate from college. For this study, what is the response variable?

a. Whether a student decides on his/her major before their junior year

b. Whether or not a student graduates from college.

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The exponential functions which are equivalent to the given function; g(x) = 650(1.3)^6x as required are;

As evident in the task content; the given exponential function is; g(x) = 650(1.3)^6x

Recall from the laws of indices that;

(1.3)^6x can be written as; (1.3²)^3x Or (1.3³)^2x.

Ultimately, resulting in; (1.69)^3x Or (2.197)^2x.

Therefore, the equivalent exponential functions are; h (x) = 650 (2.197)^2x and n (x) = 650 (1.690)^3x.

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To start, let's simplify the Algebriac expresssion 2 - 2:

2 - 2 = 0

Now, let's find f(x) by plugging in the simplified expression:
f(x) = 0 - (2/x-2)
To find f'(2), we need to use the definition of the derivative:
f'(2) = lim h→0 [f(2+h) - f(2)]/h
Plugging in f(x), we get:
f'(2) = lim h→0 [0 - (2/(2+h)-2)]/h

Simplifying this expression using algebra, we get:
f'(2) = lim h→0 [-2/(h(h+2))]
Now, we use expression (5) on page 144 to simplify further:
f'(2) = lim g(x), where g(x) = -2/(x(x+2))
To find g(1), we simply plug in x=1:
g(1) = -2/(1(1+2))
g(1) = -2/3

Therefore, g(1) = -2/3.
 I understand that you want to compute f'(2) using the definition of the derivative and eventually find g(1) for a rational function g(x). However, the given information seems incomplete, as the function f(x) is not provided. Please provide the complete function f(x) so I can help you calculate the derivative and find g.

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The least squares estimate of the slope is -1.

To find the value of b1, we need to first calculate the means of X and Y:

x = (1 + 2 + 3 + 4 + 5) / 5 = 3

y = (5 + 4 + 3 + 2 + 1) / 5 = 3

Next, we calculate the numerator and denominator of the above formula:

Numerator = (1-3)(5-3) + (2-3)(4-3) + (3-3)(3-3) + (4-3)(2-3) + (5-3)(1-3) = -10

Denominator = (1-3)² + (2-3)² + (3-3)² + (4-3)² + (5-3)² = 10

Hence, the slope of the regression line is:

b1 = -10 / 10 = -1

This means that for every one unit increase in X, we can expect a decrease of one unit in Y.

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Complete Question:

You are given the following information about Y and X.

Y (Dependent Variable)        X (Independent Variable)

5                                                                   1

4                                                                   2

3                                                                    3

2                                                                    4

1                                                                     5

The least squares estimate of b1 (slope) equals:

If the xylem vessel radii are related by Murray's law for plants, then the total cost of transport and maintenance is minimized.

a. To minimize the total cost T(r) + M(r), we need to find the value of r that minimizes the sum of these two functions. We can do this by taking the derivative of the sum with respect to r and setting it equal to zero:

d/dR(T(R) + M(R)) = 0

Using the given equations for T(r) and M(r), we can simplify this expression:

d/dR(0.071(f^2L/R^2)(R^2 + (rT)^2) + bπR^2L) = 0

Expanding the first term and simplifying, we get:

d/dR(0.071f^2L + 0.071rT^2L/R^2 + bπR^2L) = 0

Simplifying further, we get:

-0.142f^2L/R^3 + 2bπRL = 0

Solving for R, we get:

R = (2bπL/0.142f^2)^(1/4)

Substituting the given value for rT, we get:

R = 1.76(f^2L/b)^(1/4)

b. To show that the radii of the vessels are related by Murray's law for plants, we need to minimize the total cost for the two vessels subject to the constraint that the total flow rate is conserved. That is, we have:

f = f1 + f2

where f1 and f2 are the flow rates in the two vessels.

The total cost is given by:

T(R) + M(R) = 0.071(f1^2L/R^2)(R^2 + (rT)^2) + bπR^2L + 0.071(f2^2L/R^2)(R^2 + (rT)^2) + bπR^2L

Simplifying and setting the derivative with respect to R equal to zero, we get:

-0.142L/R^3(f1^2 + f2^2) + 2bπL = 0

Using the relationship between R and flow rate derived in part (a), we can substitute for R:

-0.142L(2bπL/f^2)^(3/4)(f1^2 + f2^2)/f^3 + 2bπL = 0

Simplifying and using the conservation of flow rate, we get:

f1^2 + f2^2 = f^2/2

Substituting for f1 and f2 in terms of the radii r1 and r2, we get:

πr1^4 + πr2^4 = (f^2/2bπL)^(2/3)

This equation is equivalent to Murray's law for plants:

R^3 = r1^3 + r2^3

So we have shown that if the xylem vessel radii are related by Murray's law for plants, then the total cost of transport and maintenance is minimized.

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Answer:

sin A is

[tex] \frac{ \sqrt{84} }{10} = \frac{2 \sqrt{21} }{10} = \frac{ \sqrt{21} }{5} [/tex]

The approximate value of f(5.2, 2.9) is 1.619.

(a) To find f(x, y) suitable for the problem, we can let f(x, y) = √(x^2) - y^2. Taking the total differential of f, we have:

df = (∂f/∂x)dx + (∂f/∂y)dy
df = (x/√(x^2))dx - 2ydy

(b) Let xo = 5.2 and yo = 2.9 be the starting point. Let Δx = Δy = 0.1. Then we have:

f(xo + Δx, yo + Δy) ≈ f(xo, yo) + (∂f/∂x)Δx + (∂f/∂y)Δy
f(5.3, 3) ≈ f(5.2, 2.9) + (5.2/√(5.2^2))(0.1) - 2(2.9)(0.1)
f(5.3, 3) ≈ 1.619

The approximate value of f(5.2, 2.9) is 1.619.

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The area under the standard normal curve to the right of Z = 1.43 is 0.0764

The correct option is 0.0764

We will use the concept of probability and the Normal Distribution Formula.

Z = 1.43

According to the concept of probability:  P(Z > 1.43) + P(Z < 1.43) = 1

P(Z > 1.43) = 1 - P(Z < 1.43)

We have to use the z-table and locate 1.4 in the left-most column, move across the row to the right under 0.03 to find the value 0.9236.

⇒ P(Z < 1.43) = 0.9236

P(Z > 1.43) = 1 - P(Z < 1.43) = 1 - 0.9236

P(Z > 1.43) = 0.0764

Hence, the area under the standard normal curve to the right of Z = 1.43 is 0.0764

The correct option is 0.0764

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It would require 490 joules of work to pull 5m of the cable up to the top.

To solve this problem, we need to use the formula for work:

Work = force x distance x cos(theta)

where force is the tension in the cable, distance is the distance moved, and theta is the angle between the force and the distance.

First, let's find the tension in the cable. The weight of the cable itself is negligible compared to the weight of the weight, so we can assume that the tension is equal to the weight of the weight:

Tension = weight of weight = 10kg x 9.8m/s² = 98N

Next, let's find the angle between the force and the distance. Since we are pulling the cable straight up, the angle is 0 degrees, so cos(theta) = 1.

Now we can plug in the values and solve for work:

Work = 98N x 5m x 1
Work = 490J

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Finally, Alicia could finish the edges of the quilt by sewing on binding or hemming the edges to create a polished look.

What is Trapezoid ?

A trapezoid is a quadrilateral with at least one pair of parallel sides. The parallel sides are called the bases, and the non-parallel sides are called the legs. The height of a trapezoid is the perpendicular distance between the two bases.

it seems like Alicia has started to create a patchwork quilt using triangular and trapezoidal pieces of fabric arranged in a tessellation pattern.

To continue making the quilt, Alicia could continue adding more triangular and trapezoidal pieces of fabric in a similar tessellation pattern until the entire quilt is filled. She could experiment with different colors and patterns of fabric to create a unique and interesting design.

Once Alicia has arranged all the pieces of fabric, she could sew them together using a sewing machine or by hand to create a finished patchwork quilt. She may need to trim the edges of the quilt to ensure that they are straight and even, and then she could add a backing fabric and batting to create a comfortable and warm quilt.

Therefore, Finally, Alicia could finish the edges of the quilt by sewing on binding or hemming the edges to create a polished look.

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Answer: 60%

Step-by-step explanation:

Since the ratio of boys to girls is 3:2, we can say there are five "parts"

of these 5 "parts" 3 are boys, so the percentage is 3/5 which is 60%

60% of the class are boys

Answer:

60%.

Step-by-step explanation:

The ratio is 3:2, which means that for every 3 boys there are 2 girls. Because there can be only boys and girls, we can add the two ratios together to get 5.

Now, we'll convert the 3:2 ratio into 3/5. 3/5 is 0.6, or 60%.

To estimate the error in using s3 as an approximation of the sum of the series, we can use the integral test. Let f(x) be the function defining the series. Then, we have:

∫[infinity]3 f(x) dx ≤ S - s3 ≤ ∫3[infinity] f(x) dx

where S is the sum of the series and s3 is the sum of the first three terms of the series.

Since we know that ∫[infinity]3 f(x) dx ≥ r3 (where r3 is the remainder after the third term), we can use this lower bound to estimate the error:

Estimate = ∫[infinity]3 f(x) dx - (S - s3) ≤ r3

To use n = 3 and sn+ ∫n+1 [infinity] f(x) dx to approximate the sum of the series, we can use the formula for the nth partial sum:

sn = s3 + ∑[n-1]k=1 ak

where ak is the kth term of the series. Thus, we have:

s3 + ∫4[infinity] f(x) dx = s4

where s4 is the sum of the first four terms of the series. We can continue this process to obtain:

s3 + ∫4[infinity] f(x) dx + ∫5[infinity] f(x) dx + ... = S

where S is the sum of the series. Note that the integral from n+1 to infinity represents the remainder after the nth term.

(b) To estimate the error in using s3 as an approximation of the sum of the series, we can use the remainder term r3:

Error estimate = r3 = ∫[3,∞]f(x)dx

This integral represents the error when using the first three terms of the series (s3) as an approximation.

(c) To find a better approximation using n = 3 and sn + ∫[n+1,∞]f(x)dx, you can calculate:

Approximation = s3 + ∫[4,∞]f(x)dx

Here, s3 represents the sum of the first three terms of the series, and the integral term estimates the remainder of the series from the fourth term onwards.

Note that I didn't provide specific values for f(x), as they were not given in the question. If you provide the function f(x), I can help you further with the calculations.

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To get the indefinite integral of ∫sin(4x)sin(3x) dx, we can use the product-to-sum identity for sine functions, which is given by: sin(A)sin(B) = (1/2)[cos(A-B) - cos(A+B)]

In our case, A = 4x and B = 3x. Applying the identity, we have:
∫sin(4x)sin(3x) dx = ∫(1/2)[cos(4x-3x) - cos(4x+3x)] dx
Simplify the expression: ∫(1/2)[cos(x) - cos(7x)] dx
Now, integrate each term separately: (1/2)∫cos(x) dx - (1/2)∫cos(7x) dx
The indefinite integral of cos(ax) is (1/a)sin(ax) + C, where a is a constant and C is the constant of integration. Thus, we have: (1/2)[(1/1)sin(x) - (1/7)sin(7x)] + C
Finally, simplify the expression: (1/2)sin(x) - (1/14)sin(7x) + C
So, the indefinite integral of ∫sin(4x)sin(3x) dx is (1/2)sin(x) - (1/14)sin(7x) + C.

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a. The function f(n) = n + 1 is one-to-one (injective), but not onto (not surjective). To see why, consider that for any two distinct integers n1 and n2, f(n1) = n1 + 1 ≠ n2 + 1 = f(n2). However, there is no integer m such that f(m) = n for all n in the codomain (all integers). For example, there is no integer m such that f(m) = 1.

b. The function f(n) = |n| is not one-to-one (not injective) and not onto (not surjective). To see why, consider that f(2) = f(-2) = 2, so the function is not one-to-one. Also, there is no integer m such that f(m) = -1, for example.

c. The function f(n) = 2n is one-to-one (injective) and onto (surjective). To see why, consider that for any two distinct integers n1 and n2, f(n1) = 2n1 ≠ 2n2 = f(n2). Also, for any integer m in the codomain (all integers), there exists an integer n in the domain such that f(n) = m. Specifically, if m is even, we can take n = m/2; if m is odd, there is no integer n such that f(n) = m.

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The median of a sample will always be equal to 50th percentile.

The median is defined as the middle value in a set of data, where half the values are below it and half are above it. It is also sometimes referred to as the 50th percentile, as it represents the point at which 50% of the data falls below and 50% falls above. Therefore, the correct answer is c) 50th percentile.The median is the middle number in a sorted, ascending or descending list of numbers and can be more descriptive of that data set than the average.

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(a) To find the dot product of v and w, use the formula v∙w = (v1)(w1) + (v2)(w2). In this case, v = -3i - 3j and w = -i - j. So, v∙w = (-3)(-1) + (-3)(-1) = 3 + 3 = 6.
(b) cos(θ) = 6 / (√18 * √2) = 6 / (3√2 * √2) = 6 / 6 = 1
θ = arccos(1) = 0 degrees
(c) Since the angle between v and w is 0 degrees, the vectors are parallel.

(a) To find the dot product of v and w, we use the formula v · w = (v1)(w1) + (v2)(w2) + (v3)(w3), where v1, v2, v3 are the components of v and w1, w2, w3 are the components of w. Plugging in the values, we get:
v · w = (-3i-3j) · (-i-j)
     = (-3)(-1) + (-3)(-1)
     = 6
Therefore, v · w = 6.

(b) To find the angle between v and w, we use the formula cos(theta) = (v · w) / (|v| |w|), where theta is the angle between the two vectors and |v|, |w| are the magnitudes of the vectors. Plugging in the values, we get:
cos(theta) = (v · w) / (|v| |w|)
          = 6 / (sqrt(18) * sqrt(2))
          = 1 / sqrt(2)
Using a calculator, we find that cos(theta) is approximately 0.707. To find the angle itself, we take the inverse cosine of this value:
theta = cos^-1(0.707)
     = 45 degrees      
Therefore, the angle between v and w is 45 degrees.

(c) To determine whether the vectors are parallel, orthogonal, or neither, we can look at their dot product. If the dot product is 0, the vectors are orthogonal (perpendicular). If the dot product is nonzero, we can determine whether the vectors are parallel or neither by comparing their magnitudes and direction.
For v and w, we found that their dot product is 6, which is nonzero. To determine whether they are parallel or neither, we can compare their magnitudes and direction. The magnitude of v is sqrt(18), and the magnitude of w is sqrt(2). Since these are not equal, the vectors are not parallel. Additionally, since the angle between the vectors is not 0 or 180 degrees (which would indicate parallel or antiparallel), the vectors are neither parallel nor antiparallel. Therefore, the vectors are neither parallel nor orthogonal.

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To find the sum of the series 2/(9n^2 + 3n - 2), use partial fraction decomposition to obtain A/(3n-1) + B/(3n+2). Solve for A and B, substitute them back in, and take the limit as n approaches infinity, resulting in the sum of the series as (3inf - 19)/(5(3inf+2)).

To find the sum of the convergent series 2/(9n^2 + 3n - 2) as n goes from 1 to infinity, we can use the partial fraction decomposition method. First, we factor the denominator into (3n-1)(3n+2):
2/[(3n-1)(3n+2)]
Then, we can express this fraction as a sum of two simpler fractions:
A/(3n-1) + B/(3n+2)
To solve for A and B, we multiply both sides by the common denominator and equate the numerators:
2 = A(3n+2) + B(3n-1)
Setting n=1, we get:
2 = 5A - 2B
Setting n=2, we get:
2 = 8A + 5B
Solving this system of equations, we find A=1/5 and B=-2/5. Therefore, the sum of the series is:
2/[(3n-1)(3n+2)] = 1/5(3n-1) - 2/5(3n+2)
To find the sum as n goes from 1 to infinity, we can take the limit as n approaches infinity:
lim (n->inf) [1/5(3n-1) - 2/5(3n+2)] from n=1 to infinity
= [1/5(3n-1) - 2/5(3n+2)] evaluated at n=inf - [1/5(3n-1) - 2/5(3n+2)] evaluated at n=1
= [1/5(3inf-1) - 2/5(3inf+2)] - [1/5(3-1) - 2/5(3+2)]
= [1/5(3inf-1) - 2/5(3inf+2)] - [1/5(2) - 2/5(5)]
= [1/5(3inf-1) - 2/5(3inf+2)] - [2/5 - 4/5]
= [1/5(3inf-1) - 2/5(3inf+2)] - (-2/5
= [1/5(3inf-1) - 2/5(3inf+2)] + 2/5
= [1/5(3inf-1) - 6/5(3inf+2) + 2]
= [3inf - 19]/[5(3inf+2)]
Therefore, the sum of the series is (3inf - 19)/(5(3inf+2)).

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The probability of observing at most 2 defective fuses in a sample of 15 fuses is approximately 0.942. The probability that exactly 14 recover is 0.236, at least 10 recover is 0.996, at least 12 but not more than 14 recover is 0.849 at most 14 recover is 0.999.

Use the binomial distribution. Let X be the number of defective fuses in a sample of 15 fuses. Then X follows a binomial distribution with parameters n=15 and p=0.2. We want to find P(X ≤ 2).

Using the binomial cumulative distribution function (CDF), we have:

P(X ≤ 2) = Σ(i=0 to 2) P(X=i) = Σ(i=0 to 2) (15 choose i) * (0.2)^i * (0.8)^(15-i)

Using a calculator,

P(X ≤ 2) ≈ 0.942

For the second question, we can use the binomial distribution again. Let X be the number of patients who recover from the stomach disease in a sample of 16 patients. Then X follows a binomial distribution with parameters n=16 and p=0.8.

We want to find P(X=14). Using the binomial probability mass function (PMF), we have:

P(X=14) = (16 choose 14) * (0.8)^14 * (0.2)^2 ≈ 0.236

Therefore, the probability that exactly 14 patients recover from the stomach disease is approximately 0.236.

We want to find P(X ≥ 10). Using the binomial CDF, we have:

P(X ≥ 10) = 1 - P(X ≤ 9) = 1 - Σ(i=0 to 9) P(X=i) = 1 - Σ(i=0 to 9) (16 choose i) * (0.8)^i * (0.2)^(16-i)

Using a calculator, we get:

P(X ≥ 10) ≈ 0.996

Therefore, the probability that at least 10 patients recover from the stomach disease is approximately 0.996.

We want to find P(12 ≤ X ≤ 14). Using the binomial CDF again, we have:

P(12 ≤ X ≤ 14) = P(X ≤ 14) - P(X ≤ 11) = Σ(i=12 to 14) P(X=i) = Σ(i=12 to 14) (16 choose i) * (0.8)^i * (0.2)^(16-i)

Using a calculator, we get:

P(12 ≤ X ≤ 14) ≈ 0.849

Therefore, the probability that at least 12 but not more than 14 patients recover from the stomach disease is approximately 0.849.

We want to find P(X ≤ 14). Using the binomial CDF, we have:

P(X ≤ 14) = Σ(i=0 to 14) P(X=i) = Σ(i=0 to 14) (16 choose i) * (0.8)^i * (0.2)^(16-i)

Using a calculator, we get:

P(X ≤ 14) ≈ 0.999

Therefore, the probability that at most 14 patients recover from the stomach disease is approximately 0.999.

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If a "triangle-QSR" right angled at S, QS = 16 and SR = 30 , QR is the hypotnuse, then the value of trigonometric ratio are

(a) Sin(Q) = 8/17

(b) Cos(Q) = 15/17

(c) tan(Q) = 8/15.

The "Pythagorean-Theorem" states that in a right-angled triangle, the square of the length of hypotenuse (the side opposite the right angle) is equal to sum of squares of lengths of other two sides.

In the right-angled triangle QSR, we have:

⇒ QS = 16

⇒ SR = 30

⇒ QR = hypotenuse

Using the Pythagorean theorem, we find the length of the hypotenuse QR:

⇒ QR² = QS² + SR²,

⇒ QR² = 16² + 30,

⇒ QR² = 256 + 900,

⇒ QR² = 1156

⇒ QR = √1156 = 34,

So,

Part (a) : Sin(Q) = opposite/hypotenuse = QS/QR = 16/34 = 8/17

Part (b) : Cos(Q) = adjacent/hypotenuse = SR/QR = 30/34 = 15/17

Part (c) : tan(Q) = opposite/adjacent = QS/SR = 16/30 = 8/15.

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The given question is incomplete, the complete question is

Find each trigonometric ratio. Give your answer as a fraction in simplest form.

A triangle QSR right angled at S, QS = 16 and SR = 30 , QR is the hypotnuse,

(a) Sin(Q) =

(b) Cos(Q) =

(c) tan(Q) =

Answer:

21 degrees

Please read step-by-step explanation to understand how I came to this conclusion.

Step-by-step explanation:

We know that all angles on a straight line add up to 180 degrees.

We also know that all interior angles of a triangle add up to 180 degrees.

Angle 1: a-32 (given)

Angle 2: a-31 (given)

Angle 3: 180-a

We subtracted A from 180 to find the other angle. Adding up both angles on that line, a + 180 - a = 180, meaning that both angles are valid.

Now let's add up the angles to 180 degrees

a-32 + a-31 + 180-a = 180

3a-63+180 = 180

3a = 63

a = 21 degrees

Answer:

The missing angle will be 64

Step-by-step explanation:

If you do 180 + 90 you will get 270. If you do 270 + 26 you will get 296.

A full turn or circle is 360 degrees. If you do 360 - 296 you will end up with 64 degrees.

The area of rectangle 2 is 6.44 square inches. The area of triangle 2 is 8.82 square inches. Total area is 30.42 sq.in

Area is a unit of measurement used to describe the size of a two-dimensional surface or region. It refers to the volume of a closed figure or shape. For instance, to find the area of a rectangle, multiply its length by its width; to find the area of a circle, multiply (pi) by the square of its radius. In many disciplines, such as geometry, physics, and engineering, as well as in daily life, such as determining the size of a room or determining how much paint is required to cover a wall, the idea of area is used.

Given that, area of Rectangle 1 is 8.68 square inches. and area of Triangle 1 is 6.48 square inches.

Also, from the figure we have:

AE = 2.4

EB = 2.8

BC = 11.7

Now, for area of 1 we have:

FH (HI) = 8.68

EB(HI) = 8.68

2.8(HI) = 8.68

HI = 3.1

Now, from area of triangle 1 we have:

1/2(AE)(FG) = 6.48

1/2(AE)(EF + FG) = 6.48

1/2 (AE)(EF + HI) = 6.48

EF + 3.1 = 5.4

EF = 2.3

BH = 2.3

Now,

BC = BH + HI + IC

11.7 = 2.3 + 3.1 + IC

IC = 6.3

The area of rectangle 2 is:

EB (BH) = 2.8 (2.3) = 6.44 square inches.

The area of triangle 2 is:

1/2(GI)(IC) = 1/2(EB)(IC) = 1/2(2.8)(6.3) = 8.82 square inches.

Total area is:

= 6.48 + 8.68 + 8.82 + 6.44 = 30.42 sq.in

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The volume of the pyramid is B) 192ft

The volume of a pyramid can be calculated utilizing the condition:

V = (1/3) * base region * height...........(1)

In the case of a square pyramid, the base area is given by the condition:

base area = (edge length)²

Thus, in this issue, we have:

base area = (6 ft)² = 36 ft²

height = 16 ft (given)

Substituting these values into the condition for the volume of a pyramid ( equation (1) ), we get:

V = (1/3) * 36 ft² * 16 ft

V = 192 cubic feet

In this way, the volume of the pyramid is 192 cubic feet.

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It would take Bentley 9 minutes to text 54 words at his rate of 36 words in 6 minutes.

Equivalent ratios are those that, when compared, are the same. It is possible to compare two or more ratios side by side to see if they are equivalent. For example, the ratios 1:2 and 2:4 are equivalent.

To find the value of X, we need to set up a proportion using the equivalent ratios:

36 words/6 minutes = 54 words/x minutes

To solve for x, we can cross-multiply and simplify:

36x = 6(54)

36x = 324

x = 9

Therefore, it would take Bentley 9 minutes to text 54 words at his rate of 36 words in 6 minutes.

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The Stony Brook University has been ranked as the third best university to pursue a degree in applied mathematic among all the other public and private universities.

Stony Brook University—SUNY is placed #77 in the Best Colleges rating for 2022–2023's National Universities category.

The tuition fees is $10,556 and $28,476 for in-state and out-of-state respectively. The Stony Brook University comes under the state University of New York along with the other 64 universities.

The Stony Brook AMS major has reportedly been listed by College Factual as one of the top five undergraduate applied mathematics degrees in the US for a number of years, according to USA Today. The top five schools for 2020 are CalTech, Stanford, Harvard, Brown, and Stony Brook.

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For a survey related to response of persons on asking about leisure or recreational activities done by them. The percentage of the people who answered Yes were surveyed in 2002 is equals to the 72.7%. So, the option(b) is right one here.

Percentage is a numerical number value. It is calculated by dividing the observed value to total value and then resultant multipling by 100. We have a table present in above figure which contain a responses to a question by the GSS survey from 1988 and 2002, asked about recreational activities that people do during their free time. We have to determine the percentage of people who answered Yes were surveyed in 2002. Now, The number of persons who answered Yes were surveyed in 2002

= 987

The number of persons who answered No were surveyed in 2002 = 371

Total number of persons who participated in survay 2002 = Sum of both who answered No or yes = 987 + 371 = 1358

So, the percentage of people who answered Yes were surveyed in 2002 =

[tex] (\frac{987}{1358})100[/tex]

= 0.7268× 100

Hence, required value is 72.7%.

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Complete question:

Below is a table of responses to a question by the GSS survey. In 1988 and in 2002, they asked about leisure or recreational activities that people do during their free time. "Have you read novels, short stories, poems, or plays, other than those required by work or school in the past twelve months?"

1998 2002

Yes 968 987

No. 466 371

What percentage of the people who answered Yes were surveyed in 2002?

A. 35.4% B. 72.7% C. 50.5%