The ordered pairs for t = 1 and t = 2 are (1, 1200) and (2, 2,400).
An equation to represent the relationship between the time t and the number of hard drives produced p is p = 1200t.
What is a proportional relationship?In Mathematics, a proportional relationship can be represented by the following mathematical expression:
p = kt
Where:
t represents the time.p represents the number of hard drives.k represents the constant of proportionality.In order to have a proportional relationship and equivalent ratios, the variables p and t must have the same constant of proportionality. Therefore, we would determine the constant of proportionality (k) as follows:
Constant of proportionality (k) = p/t
Constant of proportionality (k) = 1,200/1
Constant of proportionality (k) = 1,200.
Therefore, the required equation is given by;
p = kt
p = 1,200t.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
y= x^5/4 sin x^2
find dy/dx
Answer:Xmin:
-10
Xmax:
10
Ymin:
-10
Ymax:
10
Step-by-step explanation:
And iron home has a listed price of $65 and the sales tax rate is 5%. How much is sales tax what is the total cost?
find the geometric mean of 5 and 320
Answer:
B. 40
Step-by-step explanation:
you would multiply 5 and 320 and then do the square root of the number
The function V(x)=x3 may be used to find the volume of a cube with side of length x. Find the volume of a cube whose side is 19 inches.
The volume of the cube is?
The volume of a cube is 6859 cubic inches if the side of the cube is 19 inches.
The given function = V(x) = [tex]x^{3}[/tex]
Side of cube = 19 inches
The cube has six faces with 12 edges. That means three faces are visible at a time. That means the product of the three faces of a cube gives the volume of a cube.
In the question, it is stated that the length of the cube is to be substituted in the value of x in order to calculate the volume of a cube.
The volume V of a cube = V = [tex]x^{3}[/tex].
Substituting x = 19,
The volume of the cube = [tex]19^3[/tex]
Volume of cube = 6859
Therefore, we can conclude that the volume of a cube is 6859 cubic inches.
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Identify the conic basic. x^2-4x+y^2+2y=4
The type of the conic basic x² - 4x + y² + 2y = 4 is a circle
Identifying the type of the conic basicFrom the question, we have the following parameters that can be used in our computation:
x² - 4x + y² + 2y = 4
The above equation has the following features
Squared expression of x and yLinear expressions of x and yA constant term 4Using the above as a guide, we have the following:
A conic section that has the above features is a circle
This means that the type of the conic basic is a circle
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Please someone help me answer this
[tex]Given:\ x_{n+1}=\sqrt[3]{6x_{n}-1}\ ,\ x_{1}=4\\\\The\ iterative\ formula\ can\ be\ re-written\ as:\\x_{n}=\sqrt[3]{6x_{n-1}-1}\\\hrule\ \\x_2=\sqrt[3]{6x_{1}-1}\\x_2=\sqrt[3]{6(4)-1}\\x_2=\sqrt[3]{23}\approx 2.84\\\hrule\ \\x_3=\sqrt[3]{6x_{2}-1}}\\x_3=\sqrt[3]{17.04-1}\\x_3=\sqrt[3]{16.04}\approx 2.52\\\hrule\ \\x_4=\sqrt[3]{6x_{3}-1}}\\x_4=\sqrt[3]{15.12-1}\\x_4=\sqrt[3]{14.12}\approx 2.41[/tex]
 33. Find the quotient and remainder if f(x) = 2x ^ 4 - x ^ 3 - 7x ^ 2 + 7x - 13 is divided by p(x) = x ^ 2 - 3 (Related Objective: Divide polynomials using synthetic or long division.)
The quotient is 2x² + 3x + 2 and the remainder is -32x - 13.
We have,
We can use long division to divide f(x) by p(x) as follows:
x² - 3 | 2x^4 - x³ - 7x² + 7x - 13
- (2x^4 - 0x³ + 6x²)
---------------------
- 13x² + 7x
- (-13x² + 39x)
-----------------
-32x - 13
The quotient is 2x² + 3x + 2 and the remainder is -32x - 13.
We can write the division in the form:
f(x) = p(x) x q(x) + r(x)
where p(x) is the divisor, q(x) is the quotient, and r(x) is the remainder. In this case, we have:
f(x) = (x² - 3) x (2x² + 3x + 2) - (32x + 13)
This means that we can write f(x) as the product of p(x) and q(x), plus the remainder r(x).
Thus,
The quotient is 2x² + 3x + 2 and the remainder is -32x - 13.
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Identify the sides of APQR.
Q
48°
83°
P
6. Which side is the longest?
7. Which side is the shortest?
R
#0
The sides of the triangle can be identified as follows:
6. The longest side is PR 7. The shortest side is QR
How to Identify the Sides of a Triangle?Based on the relationship between the sides of a triangle and its relative angle measures, we recall that the longest side will be opposite the largest angle measure and vice versa.
Therefore, we have the following:
m<Q = 83 degrees
m<P = 48 degrees
m<R = 180 - 83 - 48 = 49 degrees.
Angle Q is the largest angle, while angle P is the smallest.
Thus, we can conclude that:
6. The side that is the longest is PR
7. The side that is the shortest is QR
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Compare the functions shown below: f(x) = (x + 3)2 − 2 g(x) linear graph with y intercept of negative 3 over 2 and x intercept of 3 h(x) x y −3 2 −2 7 −1 14 0 23 1 34 2 47 3 62 What is the correct order of the functions from least to greatest according to the average rate of change on the interval from x = −1 to x = 3? Select one: a. f(x), g(x), h(x) b. g(x), f(x), h(x) c. h(x), g(x), f(x) d. g(x), h(x), f(x)
Answer:
Step-by-step explanation:
To find the order of the functions from least to greatest according to the average rate of change on the interval from x = −1 to x = 3, we need to calculate the average rate of change of each function over that interval and compare them.
For f(x), we have:
average rate of change = [f(3) - f(-1)] / (3 - (-1))
= [(3+3)^2 - 2 - ((-1)+3)^2 + 2] / 4
= 23
For g(x), we have:
average rate of change = [g(3) - g(-1)] / (3 - (-1))
= [0 - (-3/2)] / 4
= 3/8
For h(x), we have:
average rate of change = [h(3) - h(-1)] / (3 - (-1))
= [(62-14)/(3-(-1))]
= 12
Therefore, the correct order of the functions from least to greatest according to the average rate of change on the interval from x = −1 to x = 3 is:
g(x), f(x), h(x)
So the answer is option (b).
the point r is a weighted average of points s and t. The weight on point t is 0.625. What is the weight on point s?
Let w be the weight on point s. Since the sum of the weights is 1, the weight on point t is 0.625, we can write:
w + 0.625 = 1
Subtracting 0.625 from both sides, we get:
w = 1 - 0.625 = 0.375
Therefore, the weight on point s is 0.375.
If Line A has a slope of 2, what would the slope of Line B have to be in order for A and
B to be perpendicular?
The slope of Line B would have to be -1/2.
Two lines are perpendicular to each other if the product of their slopes is -1. The slope of Line A is given as 2. Therefore, the slope of Line B would have to be the negative reciprocal of 2, which is -1/2. This ensures that the product of the slopes of Line A and Line B is -1, satisfying the condition for perpendicularity.
In general, if the slope of Line A is m, then the slope of a line perpendicular to Line A would be -1/m. This relationship holds because perpendicular lines form right angles, and the slopes of perpendicular lines are negative reciprocals of each other.
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There are 143 boys in the senior class. 21 wrestle. 27 play football. 104 do not either. What is the probability that a senior boy does both football and wrestling?
Answer:
87
Step-by-step explanation:
I am not sure but try (143-104=39)39+21+27 you get 87
find an equation that passes through (1 ,2) and is parallel y=3x-9
Answer:
A line that is parallel to y = 3x - 9 will have the same slope as the given line. The slope of y = 3x - 9 is 3. Therefore, the equation of the line that passes through (1, 2) and is parallel to y = 3x - 9 is:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is the point (1, 2)
Substituting the values we get:
y - 2 = 3(x - 1)
Simplifying the equation we get:
y - 2 = 3x - 3
y = 3x - 1
Therefore, the equation of the line that passes through (1, 2) and is parallel to y = 3x - 9 is y = 3x - 1 .
;>
a rectangular walkway is squareroot of 5 ft wide and 8 squareroot 5 ft long. find the perimeter of the walkway
The Perimeter of the walkway is 18√5 ft.
Explanation:-
The perimeter of the rectangular walkway is the sum of the lengths of its four sides. If the width of the walkway is √5 ft and the length is 8√5 ft, then we can label the sides as follows:
Width = √5 ft
Length = 8√5 ft
Width = √5 ft
Length = 8√5 ft
The perimeter P is given by:
P = Width + Length + Width + Length
= 2(Width + Length)
= 2(√5 + 8√5)
= 2(9√5)
= 18√5 ft
Therefore, the perimeter of the walkway is 18√5 ft.
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Using the figures below, determine the coordinates of the new figure.
15.
B
-4 -3
-2
A'
-1
5
4
2
-
0
-1
0
B
C
1
2
3
4
C
5
A(3, 5) →
'A'(___________
B(1, 3) -
B',
C(5,2)→
C'C
The coordinates of the new figure are:
A' = (-1, 4)
B' = (-3, 2)
C' = (1, 1)
We have,
The coordinates are in the form of an ordered pair as (x, y).
Where x is the x-axis value and y is the y-axis value.
From the figure,
We see that,
A' = (-1, 4)
B' = (-3, 2)
C' = (1, 1)
Thus,
The coordinates are:
A' = (-1, 4)
B' = (-3, 2)
C' = (1, 1)
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The ratio fu is 4: 3.
The ratio f: w is 12: 5.
What is the ratio fu w in its simplest
form?
Answer:
f : u = 12 : 9, so f : u : w = 12 : 9 : 5.
Restate the problem in a way that can be easily translated into an equation.
It took Dani 5 minutes longer to run the course than it did Candice.
A. Dani’s rate is slower than Candice’s rate.
B. Dani’s time is greater than Candice’s time.
C. Dani’s time equals Candice’s time plus 5
C. Candice’s time equals Dani’s time plus 5 minutes.
The relationship between Dani's time and Candice's time, taking into account the fact that Dani took 5 minutes longer to run the course. it is Reasonable time to assume that the runners' rates were constant. Option C is the correct answer.
Let "t" be the time it took Candice to run the course.
Then, according to the problem statement, Dani took 5 minutes longer than Candice to run the course. Therefore, Dani's time is equal to Candice's time plus 5 minutes, which can be expressed as:
D = C + 5
where D is Dani's time and C is Candice's time.
This equation represents the relationship between Dani's time and Candice's time, taking into account the fact that Dani took 5 minutes longer to run the course. It can be used to solve problems related to the two runners' times, such as finding their individual times or comparing their rates. Option C is the correct answer.
It is important to note that this equation assumes that both runners ran the course at a constant rate. If the runners' rates varied throughout the course, then the equation would not accurately represent their times. However, for the purposes of this problem, it is reasonable to assume that the runners' rates were constant.
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OMG PLEASE I BEG I NEED HELP 5th grade math
Answer: A
Step-by-step explanation:
Volume= LxWxH so we get 20x28x24 as given.
Volume= 13,440 which is the volume of the box given. ANd so if the box is 10,500cubic inches, we subtract to find the difference.
13,440-10,500= 2,940 Cubic Inches
Option A
Answer:
Part A: 13440 cubic inches.
Part B: A - 2940 cubic inches.
Step-by-step explanation:
The volume of the box = 24x20x28 = 13440 cubic inches.
The problem tells us that his gift is 10,500 cubic inches. So subtract that from the volume of the box.
13440-10500 = 2940 cubic inches. The answer is A.
The slope of MN¯¯¯¯¯¯¯ is −3.
Which segments are parallel to MN¯¯¯¯¯¯¯?
Select each correct answer.
Responses
WX¯¯¯¯¯¯, where W is at (2, 6) and X is at (4, 0)
segment W X, , where , W, is at , begin ordered pair 2 comma 6 end ordered pair, and , X, is at , begin ordered pair 4 comma 0 end ordered pair
RS¯¯¯¯¯, where R is at (1, 3) and S is at (4, 2)
segment R S, , where , R, is at , begin ordered pair 1 comma 3 end ordered pair, and , S, is at , begin ordered pair 4 comma 2 end ordered pair
TU¯¯¯¯¯, where T is at (8, 1) and U is at (5, 10)
segment T U, , where , T , is at , begin ordered pair 8 comma 1 end ordered pair, and, U, is at , begin ordered pair 5 comma 10 end ordered pair
PQ¯¯¯¯¯, where P is at (5, 6) and Q is at (8, 7)
TU is parallel to MN.
Given that the slope of a line MN is -3, we need to find a line which is parallel to the MN.
So we know that the parallel lines are having equal slope so the line which is parallel to the MN it must have slope of -3.
Therefore,
Considering the line TU, find the slope = y₂-y₁ / x₂-x₁
= 10-1 / 5-8 = -9/3 = -3
Since, the slope of the line TU is -3 therefore we can say the lines TU and MN are parallel liens.
Hence TU is parallel to MN.
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Need immediate help in Q11 PLEASE
The length of the perpendicular from Q to PR is approximately 3.86 units.
How to calculate the lengthslope of PR = (y2 - y1) / (x2 - x1)
slope of PR = (15 - 3) / (5 - 1)
slope of PR = 3
Using the point-slope form of a line, we have:
y - y1 = m(x - x1)
y - 3 = 3(x - 1)
y - 3 = 3x - 3
y = 3x
The equation of the line perpendicular to PR and passing through Q is y = (-1/3)x + (17/3).
Finally, we can find the point where this line intersects PR by solving the system of equations:
y = 3x
y = (-1/3)x + (17/3)
Substituting the first equation into the second equation, we have:
3x = (-1/3)x + (17/3)
10/3 x = 17/3
x = 1.7
Substituting x = 1.7 into the first equation, we have:
y = 3(1.7)
y = 5.1
the point where the line perpendicular to PR intersects PR is (1.7, 5.1).
Now we can find the distance between Q and (1.7, 5.1) using the distance formula:
d = ✓((x2 - x1)² + (y2 - y1)²)
d = ✓((5 - 1.7)² + (4 - 5.1)²)
d = ✓(14.89)
d = 3.86
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When writing a proof, how do you construct the first statement?
A) By writing the justification for the first statement in the right column.
B) By copying the “prove” statement(s) from the original problem.
C) By writing the next logical statement from the current one.
D) By copying the “given” statement(s) from the original problem.
When writing a proof , by copying the “given” statement(s) from the original problem
Given data ,
A true assertion that is provided in the problem or is known to be true should be the first statement in a proof. The subsequent logical argument has this as its foundation.
We can provide the groundwork for the proof and proceed to the desired conclusion by duplicating the "given" statement(s) from the original problem.
Once the first statement is established, we can move on to writing additional statements that are each logically supported by the first statement.
The logical evolution of the preceding assertions demonstrates that the last statement should be the intended conclusion.
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Find the equations of the three mediators of the triangle ABC where A, B and C have coordinates
(1, 2), (5,2) and (3, 6) respectively.
The equations of the three mediators of triangle ABC are:
x = 3 (the mediator of AB)
y = (-1/2)x + 5 (the mediator of AC)
y = (1/2)x + 2 (the mediator of BC)
How to explain the equationThe coordinates of A are (1,2) and the coordinates of B are (5,2), so the midpoint of AB is:
((1+5)/2, (2+2)/2) = (3,2)
The coordinates of A are (1,2) and the coordinates of C are (3,6), so the midpoint of AC is:
((1+3)/2, (2+6)/2) = (2,4)
The coordinates of B are (5,2) and the coordinates of C are (3,6), so the midpoint of BC is: ((5+3)/2, (2+6)/2) = (4,4)
The slope of BC is: (6-2)/(3-5) = -2
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GIVE BRAINLIST!! HELP PLEASE
Answer:
P = (1/2)(6)(8)/(π(5^2))
= 12/(25π)
= .31 (about 31%)
What is the next step in the construction of a regular hexagon?
A. Use a compass and straightedge to continue drawing equilateral
triangles until you have six.
OB. Use a compass and straightedge to continue drawing equilateral
triangles until you have eight.
OC. Use a compass and straightedge to continue drawing equilateral
triangles until you have five.
OD. Use a compass and straightedge to continue drawing equilateral
triangles until you have four.
The next step in the construction of a regular hexagon is A. Use a compass and straightedge to continue drawing an equilateral
A circle with the required radius must first be drawn in order to make a regular hexagon. Draw a second circle whose centre is one of the spots on the first circle using the same radius. These two circles' intersection points will form the vertices of an equilateral triangle. Three of these equilateral triangles, with their vertices on the circle, must be drawn inside a circle. At the circle's centre, these three triangles will have a common vertex.
Drawing three more equilateral triangles, each of which shares a side with one of the previously drawn triangles, is necessary to finish the building of a regular hexagon. Drawing equilateral triangles keeps on until there are six of them, each of which has a side in common with a preceding triangle.
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Solve What’s In This Image
The expressions 1 and 4 are having values less than 1.
Given are the expressions, we need to solve them,
1) -7 · 1/2 - 4
= -7/2-4
= -7-8 / 2
= -15/2
= -7.5 < 1
2) -7 · (1/2 - 4)
= -7 · -7/2
= 49/2
= 24.5 > 1
3) -7 · 1/2 · (- 4)
= -14/2 · (- 4)
= 56/2
= 28 > 1
4) -7 + 1/2 · (- 4)
= -7 -4/2
= -7 -2
= -9 < 1
5) -7 ÷ 1/2 · (- 4)
= -7 × 2 × -4
= -14 × -4
= 56 > 1
Hence, the expressions 1 and 4 are having values less than 1.
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HELP ME WITH THIS QUICK
Answer:
A = (1/2)(5.5)(8.5 + 12.5) = 57.75 m^2
Please help and show work
Answer:
5.25
Step-by-step explanation:
not much to show, go 3 topping across then up to see the price
FASTEST GETS MOST POINTS
a tuxedo rental service charges $150 flat fee for a suit plus $50 per additinal day. The total cost of the tuxedo is $300. How many days was the tuxedo rental for?
The tuxedo was rented for 4 days.
Let's start by assigning variables to the unknowns. Let "x" be the number of additional days rented, and "d" be the total number of days rented (including the first day).
From the given information, we know that the flat fee for the rental is $150, so the cost of the additional days is the total cost minus the flat fee, which is $300 - $150 = $150. We also know that the cost for each additional day is $50. Therefore, we can set up the equation:
$150 + $50x = $300
Subtracting $150 from both sides, we get:
$50x = $150
Dividing both sides by $50, we get:
x = 3
So the tuxedo was rented for 3 additional days, making the total number of days rented:
d = 1 + 3 = 4
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can someone please help me out with these!! asap!!
Answer:
Question 3 : Less than one
Question 4 : Starting value
Step-by-step explanation:
Answer:
less than one + Starting value
Step-by-step explanation:
The answer for #3 is less than one because any number greater than one when multiplied increases the value of the number,
and #4 is starting value because it is what you are multiplying the change by. Please mark brainliest + enjoy the night!
Compare the functions shown below:
g(x)
X
O f(x)
O g(x)
-16
01
f(x) = 4 sin (2x-1)-11 -2 h(x)=(x-2)² +4
2 -3
3-2
1
4
5
6
Which function has the smallest minimum y-value? (2 points)
Answer:
Step-by-step explanation:
To compare the minimum y-values of the given functions, we need to find the minimum point of each function and compare their respective y-values.
For the function f(x) = 4 sin(2x-1) - 11, we know that the sine function oscillates between -1 and 1, and is multiplied by a factor of 4, which will change the amplitude of the function. We can find the minimum point of the function by setting its derivative equal to zero:
f'(x) = 8 cos(2x-1) = 0
cos(2x-1) = 0
2x-1 = (2n+1/2)π, where n is an integer
x = (2n+1/4)π + 1/2, where n is an integer
The minimum point will occur at x = (2n+1/4)π + 1/2, and the corresponding y-value can be found by substituting this value of x into the original function:
f(x) = 4 sin(2x-1) - 11
f((2n+1/4)π + 1/2) = 4 sin(2[(2n+1/4)π + 1/2]-1) - 11
f((2n+1/4)π + 1/2) = 4 sin(2nπ + π/2) - 11
f((2n+1/4)π + 1/2) = 4 (-1)^n - 11
We can see that the y-value of the minimum point alternates between -15 and -7 as n changes. Therefore, the smallest minimum y-value for the function f(x) is -15.
For the function h(x) = (x-2)² + 4, we know that it is a quadratic function with a minimum point at x=2. The y-value of the minimum point can be found by substituting x=2 into the function:
h(2) = (2-2)² + 4
h(2) = 4
Therefore, the smallest minimum y-value among the two given functions is 4, which is the minimum y-value of the function h(x) = (x-2)² + 4.