Answer:
Explanation:
To write the given numbers as fractions of 100, percentages, and decimals, we first need to estimate their values on the number line. Once, we have the values of the numbers, we can write the as a fraction of 100 as
[tex]\frac{Num}{100}[/tex]As percentages as
[tex]\frac{Num}{100}\times100[/tex]And as decimals as
[tex]Num\div100[/tex](a).
The estimate of the value of three numbers is 27, 45, 67.
Writing the above as fractions of 100 gives
[tex]\frac{27}{100},\frac{45}{100},\frac{67}{100}[/tex]As a percentage, these numbers are
[tex]\frac{27}{100}\times100,\frac{45}{100}\times100,\frac{67}{100}\times100[/tex][tex]\rightarrow27\%,45\%,67\%[/tex]To write the numbers as decimals we divide them by 100 to get
[tex]0.27,0.45,0.67[/tex](remember that dividing by 100 shifts the decimal point to the left by 2 digits)
(b).
The estimate of the values of the three numbers are 57, 74, and 89
Writing these numbers as fractions gives
[tex]\frac{57}{100},\frac{74}{100},\frac{89}{100}[/tex]As a percentage these numbers are
[tex]\frac{57}{100}\times100,\frac{74}{100}\times100,\frac{89}{100}\times100[/tex][tex]57\%,74\%,89\%[/tex]And as decimals
[tex]0.57,0.74,0.89[/tex](c).
The estimate of the value of the three numbers is 22, 36, 55.
Writing them as a fraction gives
[tex]\frac{22}{100},\frac{36}{100},\frac{55}{100}[/tex]As a per cent these numbers are written as
[tex]undefined[/tex]how do I solve x+6y=36
Answer:
If you're solving for x and y, the answers are there!
Step-by-step explanation:
Hope this helps!
The volleyball team is selling snack bags to raise money for new uniforms. The table shows the percent of the total bags sold for each type of snack bag. If they sold 210 bags of pretzels and cheese puffs, how many snack bags did they sell in all? If each snack bags costs $1.75, how much money did they raise?
Snack
Percent
Cheese Puffs
10
Corn Chips
15
Popcorn
25
Potato Chips
30
Pretzels
20
The total amount that was raised by the volleyball team is $1,225.
What is the total amount raised?
Percentage is the fraction of an amount that is usually expressed as a number out of hundred. The sign that is used to represent percentages is %.
The first step is to determine the total number of snacks sold.
Total number of snacks sold = number of pretzels and cheese puffs sold / percentage representing pretzels and cheese puffs
210 / (10% + 20%)
210 / 30%
210 / 0.30 = 700
The second step is to multiply the total number of snacks by the cost per snack
Total cost of the snacks = cost per snack x total number of snacks
700 x $1.75 = $1,225
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An experimental calculation of the boiling point of olive oil yields 550°F the actual boiling point of olive oil is 570°F use the values in the box below to set a proportion which can be used to find the percent of error in the experimental calculation.
To calculate the percentage error, the following formula would be applied;
[tex]\begin{gathered} \text{Percentage error}=\frac{|approximate\text{ value-exact value|}}{exact\text{ value}}\times\frac{100}{1} \\ \text{Percentage error}=\frac{|550-570|}{570}\times100 \\ \text{Percentage error}=\frac{20}{570}\times\frac{100}{} \\ \text{Percentage error}=3.50877192 \\ \text{Percentage error}\approx3.5\text{ (nearest tenth of a percent)} \end{gathered}[/tex]ANSWER:
The percentage error, as shown in the calculations above is 3.5 % (to the nearest tenth of a percent)
A student downloaded a new game on her phone that was recommended by her friend. Shewanted to show her friend how good she was doing, so she wrote down all her scores on thegame. Her first five scores on the game were 432,543, 348, 788, and 823. On the twoquestions below, round to the nearest whole number when relevant.a. What is her mean, or average, score on the game?b. What is her median score on the game?
a) mean = (432 + 543 + 348 + 788 + 823) / 5
= 586.8
rounded = 587
b) median = 348, 432, 543, 788, 823
Median = 543
Find the simple interest.Principal: $6000 Rate: 4% Time in months: 3
Given:
Principal, P = 6000
Rate, r = 4%
Time, t = 3 months
To find:
The simple interest
Explanation:
Using the simple interest formula,
[tex]SI=P\times\frac{r}{100}\times\frac{t}{12}[/tex]Where t represents the number of months.
On substitution, we get
[tex]\begin{gathered} SI=6000\times\frac{4}{100}\times\frac{3}{12} \\ SI=\text{ \$}60 \end{gathered}[/tex]Final answer:
The simple interest is $60.
Suppose X ~ N(4, 2). What value of x is two standard deviations to the right of the mean?
By applying the Empirical Rule, the value of x is equal to: A. 8.
What is the Empirical Rule?The Empirical Rule is also known as the 68-95-99.7 rule and it simply refers to a statistical rule which states that the middle 95% of a normal distribution would be within two (2) standard deviations of its mean.
This ultimately implies that, 95% of a normal distribution would fall within two (2) standard deviations of its mean in accordance with the Empirical Rule.
By applying the Empirical Rule, the value of x is given by:
x = μ + 2σ
Substituting the given points into the formula, we have;
x = 4 + 2(2)
x = 4 + 4
x = 8.
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Complete Question:
Suppose X ~ N(4, 2). What value of x is two standard deviations to the right of the mean?
8
10
7
6
What is the determinant of H=[ matrix 2&4&9\\ 3&3&1\\ 4&5&3 matrix ]? 15 18 154 169
Answer:
Step-by-step explanation:
What is the determinant of H=[ matrix 2&4&9\\ 3&3&1\\ 4&5&3 matrix ]? 15 18 154 169Question
What is the determinant of H=[ matrix 2&4&9\\ 3&3&1\\ 4&5&3 matrix ]? 15 18 154 169
Mr. Clayton is contemplating which chauffeured car service to take to the airport. The first costs $5 up front and $4 per kilometer. The second costs $15 plus $3 per kilometer. For a certain driving distance, the two companies charge the same total fare. What is the distance? Write a system of equations, graph them, and type the solution.______ kilometers
Given in the question:
a.) The first costs $5 upfront and $4 per kilometer.
b.) The second costs $15 plus $3 per kilometer.
Let's generate the equation of each of the car service charges,
Let,
y = total cost of service
x = distance traveled
a.) The first costs $5 upfront and $4 per kilometer.
[tex]\text{ y = 5 + 4x}[/tex]b.) The second costs $15 plus $3 per kilometer.
[tex]\text{ y = 15 + 3x}[/tex]Let's determine the driving distance when the two companies charge the same.
We get,
[tex]y_{1st\text{ Company}}=y_{2nd\text{ Company}}_{}[/tex][tex]\text{ 5 + 4x = 15 + 3x}[/tex][tex]\text{ 4x - 3x = 15 - 5}[/tex][tex]\text{ x = 10}[/tex]Therefore, the two companies charge the same at a driving distance of 10 kilometers.
Summary:
1. The system of equations.
y = 5 + 4x
y = 15 + 3x
2. The solution.
x = 10
3. Graphing the system of equations.
A junk drawer at home contains eight pens for of which work what is the probability that you randomly grab three pens from the drawer and don’t end up with a Penn that works express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth
Given:
Total no of pens is 8.
No of pens that works =4
No of pens that don't work = 4
[tex]\text{Probability }of\text{ selecting 3 pens }from\text{ the drawer=}\frac{3}{8}[/tex][tex]\text{Probability of selecting }a\text{ pen thta don't work=}\frac{4}{8}[/tex][tex]\begin{gathered} \text{Probability of getting 3 pens from a drawer }and\text{ don't} \\ \text{ end up with a pen }that\text{ work is } \end{gathered}[/tex][tex]=\frac{3}{8}\times\frac{4}{8}[/tex][tex]=\frac{3}{16}[/tex][tex]=0.1875[/tex]I was going back over this and saw i got it wrong what was the right awnser
ANSWER
E. None of these
EXPLANATION
We want to find the converse of the statement.
A statement is made up of an hypothesis, then a conclusion.
So the converese is found by switching the hypothesis and the conclusion.
The statement given is:
If it is raining then we will go to the beach
The converse of this statement will therefore be:
If we will go to the beach then it is raining
The answer is Option E since the converse is not among the other options.
f(x) = x + 1g(x) = 1 - x^2h(x) = f(x)/g(x)a) what are the zeroes?b) are there any asymptotes? c) what is the domain and range for this function?d) it it a continuous function?e) are there any values of y= f(x)/g(x) that are undefined? Explain
Given the functions:
[tex]\begin{gathered} f(x)=x+1, \\ g(x)=1-x^2. \end{gathered}[/tex]We must answer the question for the function:
[tex]h(x)=\frac{f(x)}{g(x)}=\frac{x+1}{1-x^2}\text{.}[/tex]c) Domain and range
First of all, we must analyze the domain of the function. Because the funcion h(x) is given by the equotient of two functions, f(x) and g(x), the domain of h(x) are all the values of x = 1 for which we have
g(x) ≠ 0. We see that the function g(x) is zero when x = 1 or x = -1. So the domain of the function is:
[tex]Domain=(-\infty,-1)\cup(-1,1)\cup(1,\infty).[/tex]The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually) after we have substituted the domain. Plotting the function, we get the following graph:
From the graph, we see that the function h(x) takes all the values from -∞ to +∞. So we conclude that the range of the function is:
[tex]Range=(-\infty,\infty).[/tex]a) Zeros
The zeros of a function are the values for which we have h(x) = 0. Looking at the function, we see that it seems to be zero at x = -1 but that number is not in the domain of the function. So we conclude that the function has not any zero.
b) Asymptotes
By definition, an asymptote is a straight line that constantly approaches a given curve but does not meet at any infinite distance. Looking again at the graph of the function, we see that the function has one asymptote at:
[tex]x=1.[/tex]d) Continuity
Looking at the domain of the function, we see that the domain is a union of intervals because the function is not defined at the values x = -1 and x = 1. So we conclude that the function is not continuous.
e) Not defined values
As we mentioned in the point of the domain, the function is not defined at the values x = -1 and x = 1. The explanation is the one given in that point.
End behaviour of the function
To find the end behaviour of the function, we can look at the graph, or we can also rewrite the function in the following way:
[tex]h(x)=\frac{x+1}{1-x^2}=\frac{(x+1)}{(x+1)\cdot(1-x)}\text{.}[/tex]For x ≠ -1 we can cancel the repeated terms in numerator and denominator, and we get:
[tex]h(x)=\frac{1}{(1-x)}\text{ for }x\ne-1.[/tex]If we compute the limits of the function as x → -∞ and x → ∞, we get:
[tex]\begin{gathered} \lim _{x\to-\infty}h(x)=\lim _{x\to-\infty}\frac{1}{1-x}=0, \\ \lim _{x\to+\infty}h(x)=\lim _{x\to+\infty}\frac{1}{1-x}=0, \end{gathered}[/tex]So the end behaviour of the function is y → 0.
Answers
a) The function has not any zeros
b) x = 1
c) Domain = (-∞,-1) U (-1,1) U (1,∞)
Range = (-∞,∞)
d) The function is not continuous.
e) The function is not defined at x = -1 and x = 1
Describe how to find the anti logarithm of ln x= 2 to the nearest ten-thousandths
The expression is given as
lnx=2.
ExplanationTo find the antilogarithm of the expression,
To compute the antilogarithm of a natural logarithm, take e to that power.
[tex]lnx=2[/tex][tex]x=e^2[/tex][tex]x=7.389[/tex]AnswerHence the antilogarithm of lnx =2 to the nearest ten-thousandths is 7.3891.
The expression 1.04 (0.9x) + 50 represents the total cost of a catered meal at a conference.The organizers of the conference were given a reduction in the cost of the catered meal due to the size of the event. Sales tax wascharged on the reduction price The organizers were also charged a set-up fee. The variable x represents the price of catered mealbefore the reduction.
Answer:
- The set-up fee is $50 ---- True
- The organizers were given a 10% discount on the catered meal. ---- True
Explanation:
Given that the expression that represent the total cost of a catered meal at a conference is;
[tex]1.04(0.9x)+50[/tex]The organizers of the conference were given a reduction in the cost of the catered meal due to the size of the event.
let a represent the percentage discount;
[tex](1-\frac{a}{100})x[/tex]Sales tax was charged on the reduction price;
let b represent the sales tax;
[tex](1+\frac{b}{100})(1-\frac{a}{100})x[/tex]The organizers were also charged a set-up fee.
Let c represent the set-up fee;
[tex](1+\frac{b}{100})(1-\frac{a}{100})x+c[/tex]Comparing to the given equation;
[tex]\begin{gathered} c=\text{ \$50} \\ (1-\frac{a}{100})=0.9 \\ a=10\text{\%} \\ (1+\frac{b}{100})=1.04 \\ b=4\text{\%} \end{gathered}[/tex]So,
discount = 10%
sales tax = 4%
set up fee = $50.
Now let us determine which of the given options are true;
- The cost of the catered meal was less than the set-up fee -- Not enough information, Probably false.
- The sales tax rate was 10% -- false ( sales tax rate is 4%)
- The set-up fee is $50 ---- True
- The organizers were given a 10% discount on the catered meal. ---- True
after how many minutes m Novak have eaten more hot dogs than Roger?
Data input
After 2 min
Roger 8 hot dogs
Novak 7 hot dos
Then,
Roger 3 hot dogs each minute
Novak 4 hot dogs each minute
Equation:
Roger < Novak
8+3m < 7+4m
The answer would be option B. 8 + 3m < 7 + 4m
Can someone help me with this question.
A line passes through the point (-4,-9) and has a slope -5/4 using the Ax+By=C form!!!
The equation of the line passing through point (-4,-9) and has a slope -5/4 is 5x + 4y = 40
How to find the equation of the linegiven data
A line passes through the point (-4,-9)
slope = -5/4
Ax + By= C
slope = ( y - y1 ) / ( x - x1 )
-5/4 = ( y - 9 ) / ( x - -4 )
-5/4 ( x + 4 ) = ( y - 9 )
-5( x + 4 ) = 4( y - 9 )
-5x + 4 = 4y -36
4 + 36 = 4y + 5x
40 = 4y + 5x
rearranging to suit Ax + By = C
5x + 4y = 40
5x + 4y = 40 is the required equation of the line
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HELP PLEASEEEEEEEEE!!!!!!!! ILL MARK BRAINLIEST
Answer:
Step-by-step explanation:
here are is answer and the steps it's in the pic below go check it out sorry if it's wrong have a nice day:)
The point A(7, -3) is reflected over the point (6, -5) and it's image is pointB. What are the coordinates of point B?
We have a point A=(7,-3) that is reflected over point C=(6,-5). This means that is refected in an axis that is perpendicular to the segment AC.
The image is point B, and we need to calculate its coordinates.
We can relocate the center of coordinates to point C, do the reflection and then relocate the original center of coordinates.
If now C became the center of coordinates A becomes:
[tex]A^{\prime}=A-C=(7-6,-3-(-5))=(1,2)[/tex]Now, we can reflect it as normal:
[tex]\begin{gathered} (x,y)\longrightarrow(-x,-y) \\ A^{\prime}=(1,2)\longrightarrow B^{\prime}=(-1,-2) \end{gathered}[/tex]Now, we convert this to the original coordinates as:
[tex]B^{\prime}=B-C\longrightarrow B=B^{\prime}+C=(-1+6,-2-5)=(5,-7)[/tex]The point B is (5,-7).
explain the structure and creation of regular and semi-regular tessellations
A regular polygon is repeated to create a tessellation known as a normal tessellation. Recognize that the angles and sides of an ordinary polygon are the same. An equilateral triangle, a rectangular shape, or a hexagon can all be used to create regular tessellations.
Tessellations made from or larger than common polygons are known as semi-regular tessellations. Hexagons and equilateral triangles make up the semi-typical tessellation shown in the image. If we concentrate on the hexagons, we can see that the triangles are rotated around the hexagonal components to generate the pattern. It is a three.3.6 tessellation, as determined by our system for naming tessellations. The hexagon is represented by the six and the trees are the two triangles.
Regular polygons of the same size and shape make up regular tessellations. Multiple regular polygons combine to form semi-regular tessellations. There are only eight ways to arrange regular polygons to produce semi-regular tessellations.
Hence we derived the necessary information.
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It takes 3/8 cup of sugar to make bread how much sugar do u need for 16 loaves
Answer:
6 cups
Step-by-step explanation:
I need help on this question
Definition of segment bisector.
What question? It might just be a glitch for me, but I don't see any question. Maybe your forgot to add an image?
Triangles DF and HJK are similar. Def has side lengths D equal 4, EF equal 6, and FD equal 8th period which of the following could be the side links of HJK?
The possible side lengths of HJK are 6,9,12
Mathematically, when two triangles are similar, then the ratio of their sides are equal
For the first triangle, we have the side dimensions of 4, 6 and 8
This can be written in its lowest ratio as 2:3:4
Any triangle that would be of similar measure should have dimensions of same ratio
Thus, we have this as;
6:9:12
If we reduce this ratio using 3, we will have 2:3:4
Find the slope of the line passing through the points (-6 ,2) and (2,2)
Answer: 8
Step-by-step explanation:
When 3a^2-7a+6 subtracted from 4a^2-3a+4, the result is
The result when 4a² - 3a + 4 is subtracted from 3a² - 7a + 6 is
(-1)a² + (-4)a + 2.
What is subtraction?
The act of deleting items from a collection is represented by subtraction. The negative sign ("-") stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.
Given, the minuend for the situation is= 3a² - 7a + 6
The subtrahend for the situation is= 4a² - 3a + 4
Therefore, the subtraction= Minuend - Subtrahend
= (3a² - 7a + 6) - (4a² - 3a + 4) = (-1)a² + (-4)a + 2
Thus, the result is (-1)a² + (-4)a + 2.
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The students in Mr. Kim's class are discussing how to apply the properties of equality. Juan started with the equation 4 +5 = 9. He multiplied the left side by 3. He said that he could divide the right side by another
B. 3
1) Let's examine Juan's work
4+5 = 9 Multiplying the left side
(4+5)*3 =9
27 = 9 Divide only the right side by 3
9 = 3 False!
2) Then we can state that
B.
The only way Juan can maintain equality is by multiplying the right side by
3
27= 9
27 = 9 x 3
27 = 27 True!
3) The answer is B and 3.
The ages of people who attend a local church are normally distributed . The mean age is 39.5 , and the standard deviation is 18. First sketch a normal curve. Then find the probability that that a person chosen at random from this church is ages 21.5 or younger
Given:
The ages of people who attend a local church are normally distributed.
The mean age = μ = 39.5
And the standard deviation = σ = 18
The sketch of the normal curve will be as follows:
As shown the peak of the curve at the mean value = 39.5
and the distance between the consecutive numbers = 18
now, we will find the probability that a person chosen at random from this church is ages 21.5 or younger
So, we will find P( x < 21.5)
As shown, from the graph:
The answer will be = 0.1587
Find three rational numbers between (-6) and (-7)
Answer: Option (b) 21:18, option(c) 42:36, option(d) 63:54, option(e) 84:62 are equivalent ratios of 7:6
Step-by-step explanation: Hope this helped
Answer: -6 1/4, -6 9/10, -6 11/20
Step-by-step explanation: You find any number in decimals between them, then you covert into fractions if needed.
What is the initial value and what does it represent?The table shows the total cost of purchasing x same-priced items and a catalog.Total CostNumber of Items Total Cost(x)1$102$143$184$22O $4, the cost per itemO $4, the cost of the catalog$6, the cost per item$6, the cost of the catalogMy
Duck if the cost of 1 item and the catalog is $ 10 and onwards, the cost for every additional item is $ 4, then:
• The cost per item is $ 4
,• The cost of the catalog is $ 6
I know you are able to select the correct choices.
Thanks for coming, Duck!
Answer:
Step-by-step explanation:
6$ cost of the catalog
7) 5x² - y² +41x-3y + 24 = 0
3x-y=-4
A) (7,0), (6,0)
B) No solution.
C) (1,7), (7,0)
D) (1,7)
Answer:
D (1, 7)
Step-by-step explanation:
From equation 2
y = (-4 + y)/3
Plug this value into the first equation which will give an equation involving only y. Solve for y which should give y = 7
Plug this value of y = 7 into 3x -y = -4
=> 3x - 7 = -4
=> 3x = 3
x = 1
So solution is x =1, y = 7 which can be represented as (1, 7)
help meeeeeeeeee pleaseee !!!!!
For the functions f(x) and g(x), the two compositions are:
(f o g)(x) = 9x² + 5(g o f)(x) = 3x² + 15How to find the two compositions?Here we have the next two functions:
f(x) = x² + 5
g(x) = 3x
The compositions are:
(f o g)(x) = f( g(x))
So we need to evaluate the function f(x) in g(x), this will give:
(f o g)(x) = f( g(x)) = g(x)² + 5
(f o g)(x) = (3x)² + 5
(f o g)(x) = 9x² + 5
The other composition is:
(g o f)(x) = g( f(x)) = 3*f(x)
(g o f)(x) = 3*(x² + 5)
(g o f)(x) = 3x² + 15
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Which is the graph of f(x) = -√x?414x-8-42-2-4O4 8-4 -2844-8Oy2x↑4-8-4k42-2OUx4 84
Notice that the graph of
[tex]-\sqrt[3]{x}[/tex]is the graph of
[tex]\sqrt[3]{x}[/tex]reflected over the x-axis.
Now, the graph of the parent function is:
therefore, the graph of f(x) is:
Answer: