Write the equation of the graph shown below in the factored form f(x) = (x + 2) (x - 1) (x - 3) f(x) = (x - 2) (x + 1) (x + 3) f(x) = (x + 2) (x + 1) (x + 3) f(x) = (x - 2) (x - 1) (x - 3)

Answer:

The answer is B. 40 inches.

Step-by-step explanation:

The question starts by telling you that line VW is equal to 40 in. If you look at the picture you can see it is divided into 2 equal parts of 20 in each. If you look at line CT, you can see that there are the same marks meaning that those segments are also 20 in. That means that line CT and line VW are equal and that line CT is equal to 40 in.

Answer:

Step-by-step explanation:

f(x) = 4x + 1

g(x) = x² – 5

To find (f – g)(x) subtract g(x) from f(x)

That's

(f – g)(x) = 4x + 1 - ( x² - 5)

Remove the bracket

(f – g)(x) = 4x + 1 - x² + 5

Group like terms

(f – g)(x) = - x² + 4x + 1 + 5

We have the final answer as

Hope this helps you

The area of the rectangle is [tex]25q^2-9[/tex].

The area of the rectangle is the product of length and width.

The length of the sides of the square is 5q.

3 is added and 3 is subtracted to the length and the width of the square so, the dimensions of the new quadrilateral is (5q+3) and (5q-3).

So, the area of the rectangle is-

[tex]A=(5q+3)\times (5q-3)\\=25q^2-9[/tex]

Thus, the area of the rectangle is [tex]25q^2-9[/tex].

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Answer:25q^2-9

Step-by-step explanation:

your welcomeeeeeeee

The answer is (180,80)

To solve this problem, we have to plot the graph, using a tool. This question relates to an inequality and graphical method is a reliable approach to solve inequality problem.

The given question is an inequality situation where we are asked to use graph to solve.

The data given are

The inequality for this problem is given is as

[tex]12x + 8y > 2500\\x + y < 280[/tex]

Kindly find the attached image as the graph and solution to this problem.

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Answer:  b.  24(x + 2) = (y + 3)²

Step-by-step explanation:

Vertex: (-2, -3)

Focus:  (4, -3)

                  ↓

                same y-value so equation will be y²

Equation: a(x - h) = (y - k)²

Given: h = -2,  k = -3,   a = 4[4 - (-2)] --> a = 24

Input those values into the equation:  24(x + 2) = (y + 3)²

Answer:

Probability ball is an even numbered ball or a 4 [P(A or B)] = 9 / 19

Step-by-step explanation:

Given:

Number of balls = 1 to 19

Find:

Probability ball is an even numbered ball or a 4

Computation:

Total even number = 2, 4, 6, 8, 10, 12, 14, 16, 18

Probability to get even number P(A) = 9 / 19

Probability to get 4 number P(B) = 1 / 19

P(A and B) = 1 / 19 (4 common)

Probability ball is an even numbered ball or a 4 [P(A or B)]

P(A or B) = P(A) + P(B) -P(A and B)

P(A or B) = [9 / 19] + [1 / 19] - [1 / 19]

Probability ball is an even numbered ball or a 4 [P(A or B)] = 9 / 19

========================================================

Explanation:

The angle 945 degrees is not between 0 and 360. We need to adjust it so that we find a coterminal angle in this range. To do this, subtract off 360 repeatedly until we get into the right range

945 - 360 = 585, not in range, so subtract again

585 - 350 = 225, we're in range now

Since 945 and 225 are coterminal angles, this means cos(945) = cos(225)

From here, we use the unit circle. Your unit circle should show the angle 225 in quadrant 3, which is the lower left quadrant. The terminal point here at this angle is [tex]\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right)[/tex]

The x coordinate of this terminal point is the value of cos(theta). Therefore  [tex]\cos(225^{\circ}) = -\frac{\sqrt{2}}{2}[/tex] and this is also the value of cos(945) as well

Using the periodic property of cos function, you can evaluate the value of cos(945°).

The value of cos(945°) is given by:

[tex]cos(945^\circ) = -\dfrac{1}{\sqrt{2}}[/tex]

A function returning to same value at regular intervals of specific length(called period of that function).

It is [tex]2\pi[/tex]

Thus, we have:

[tex]cos(x) = cos(2\pi +x) \: \forall \: x \in \mathbb R[/tex]

[tex]cos(945^\circ) = cos(2 \times 360^\circ + 225^\circ) = cos(2\pi + 2\pi + 225)\\ cos(945^\circ) = cos(2\pi) + 225) = cos(225^\circ)[/tex]

[tex]cos(\pi + \theta) = -cos(\theta)[/tex]

Thus:

[tex]cos(945^\circ) = cos(225^\circ) = cos(180^\circ + 45^\circ) = -cos(45^\circ) = -\dfrac{1}{\sqrt{2}}\\ cos(945^\circ) = -\dfrac{1}{\sqrt{2}}[/tex]

Note that wherever i have used [tex]\pi[/tex], it refers to [tex]\pi ^ \circ[/tex] (in degrees).

Thus, the value of cos(945°) is given by:

[tex]cos(945^\circ) = -\dfrac{1}{\sqrt{2}}[/tex]

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Answer:

12

Step-by-step explanation:

let

x= no. for English

y= no. for maths

z= no. for fine arts

a= no. for all subjects

x= 22

y= 21

z= 17

x+y+z= 39

x intersect y= 11

y intersect z= 8

x intersect z= 7

(4+a)+ (11-a)+ (7-a)+ (8-a)+ (2+a)+ (2+a)+ a= 39

34+a =39

a= 5

no.of teachers who teaches all & fine art only

= a + (2+a)

= 5+7

= 12

Answer:

Step-by-step explanation:

Given: MN ≅ MA

          ME ≅ MR

Prove: ∠E ≅ ∠R

From the given diagram,

YN ≅ YA

EY ≅ RY

<EMA = <RMN (right angle property)

EA = EY + YA (addition property of a line)

NR = YN + RY (addition property of a line)

EA ≅ NR (congruent property)

ΔEMA ≅ ΔRMN (Side-Side-Side, SSS, congruence property)

<MNR ≅ MAE (angle property of congruent triangles)

Therefore,

<E ≅ <R (angle property of congruent triangles)

Answer:

Option B

Step-by-step explanation:

The margin of error describes how many percentage points the results will differ from the real population value, thus 'the margin of error for a 95% confidence interval is given as plus or minus 7 milligrams per deciliter of blood (mg/dl)' can be interpreted as 'The study used a method that gives a results within 7 mg/dl of the truth about the population in 95% of all samples.'

Answer:

The bass fish was the better catch

Step-by-step explanation:

From the question we are told that

     The  population mean for trout is  [tex]\mu_1 = 12 \ in[/tex]

     The  standard deviation is  [tex]\sigma_1 = 2.75 \ in[/tex]

      The  population mean for  base  is  [tex]\mu _2 = 4 \ lb[/tex]

      The standard deviation is  [tex]\sigma_2 = 0.8 \ lb[/tex]

      The number of  trout caught   [tex]x_1 = 18[/tex]

     The number of  bass caught  [tex]x_2 = 6[/tex]

Generally z-value(standardized value ) for the of number  trout caught  is mathematically represented as

        [tex]z_1 = \frac{x_1 - \mu_1}{\sigma_1 }[/tex]

substituting value

       [tex]z_1 = \frac{18 - 12}{2.75 }[/tex]

       [tex]z_1 = 2.18[/tex]

Generally z-value(standardized value ) for the of number  bass caught  is mathematically represented as

        [tex]z_2 = \frac{x_2 - \mu_2}{\sigma_2 }[/tex]

substituting value

       [tex]z_2 = \frac{6 - 4}{0.8 }[/tex]

       [tex]z_2 = 2.5[/tex]

From our calculation we see that  [tex]z_2 > z_1[/tex]

The  fish that was the better catch is the bass fish

Answer:

0.081

Step-by-step explanation:

To solve this question, we would use the z score formula

z score = (x-μ)/σ, where

x is the raw score = 36.32cm

μ is the population mean = 34.5 cm

σ is the population standard deviation = 1.3cm

z score = (36.32cm - 34.5cm)/1.3cm

z = 1.4

Using the normal distribution to find the z score for 1.4

P(z = 1.4) = 0.91924

Therefore, the probability that a boy has a head circumference greater than 36.32cm at birth is

P(x>36.32) = 1 - P(z = 1.4)

= 1 - 0.91924

= 0.080757

Approximately ≈ 0.081

Answer:

15

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

30 hcchxfifififififfud7dd7d

Ans   k = 4

Step-by-step explanation:

Here g(x) =[tex]\frac{-1}{3}x + 1[/tex] and

        f(x) = [tex]\frac{-1}{3} x -3[/tex]

Now,  g(x) = f(x) + k

    or,      [tex]\frac{-1}{3}x + 1[/tex]  =  [tex]\frac{-1}{3} x -3 + k[/tex]

    or,      1 + 3 = k

    So,  k = 4   Answer.

Answer:

proper because the numerator is lower than the denominator

Answer:

  see below

Step-by-step explanation:

The rotated location of D' is (-2, 1). The "arrow" points to the left. The attached figure is the best I could do with your distorted image.

You have to rotate the figure 90 counterclockwise about the origin.

Answer:

Cost=x25+200

Step-by-step explanation:

The amount of people is unknown but each person the cost will be $25 for refreshments per each passenger; the limo cost $200 once you figure out how many people will go to prom x will be, EXAMPLE: x=6 times $25 plus $200 which will give you the cost.

Answer: the numbers are 3 and -3

Step-by-step explanation:

let the unknown number be x

The first UNKNOWN NUMBER = X

The second unknown number is = 6 + x

Their product = -9

(X)(6 + X) = -9

6x +[tex]x^{2}[/tex]=-9

[tex]x^{2}[/tex] +6x +9=0

we multiply the coefficient of x which is 1 with 9

now, we look for two numbers that when multiplied will give us 9 and when added will give 6 and that is 3 and 3

[tex]x^{2}[/tex] +3x+3x +9 = 0

x(x+3) +3(x+3) = 0

(x +3 ) = 0

or (x +3)=0

x +3 =0

x=0 -3

x =-3

x +3=0

x =0-3

x =-3

since the numbers are the same ,we pick one

therefore,the first number =x =-3

the second number is 6 + x=6 + (-3)

6-3=3

Answer:

B.77.4%

Step-by-step explanation:

Mean wage (μ) = $4.50

Standard deviation (σ) = $0.50

For nay given salary X, the z-score is given by:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

For X = $3.75, the z-score is:

[tex]z=\frac{3.75-4.50}{0.50}\\z=-1.5[/tex]

For X = $5.00, the z-score is:

[tex]z=\frac{5.00-4.50}{0.50}\\z=1[/tex]

A z-score of -1.5 corresponds to the 6.68th percentile, while a score of 1 corresponds to the 84.13th percentile. Therefore, the percentage of workers getting paid between $3.75 and $5.00 an hour is:

[tex]P=84.13-6.68\\P=77.45\%[/tex]

The answer is alternative B.77.4%

Not the greatest picture; I think it's trying to be a house, an A frame with a rectangular base.

This is a prism with a side 3 equilateral triangle at the end and a length of 6.

The area of the triangle is

[tex]\Delta = \dfrac{\sqrt{3}}{4} s^2[/tex]

The volume is area times length,

[tex]V = L \Delta = \dfrac{\sqrt{3}}{4} s^2 L[/tex]

[tex]V = \dfrac{\sqrt{3}}{4} (3^2) 6 = \dfrac{27}{2} \sqrt{3}[/tex]

Answer: (27/2) √3

Answer:

the answer is

[tex]3 \sqrt{2} + 2 \sqrt{3} [/tex]

Step-by-step explanation:

the explanation is given in the image.

Answer:

[tex]\huge\boxed{\dfrac{\sqrt6}{\sqrt3-\sqrt2}=3\sqrt2+2\sqrt3}[/tex]

Step-by-step explanation:

[tex]\dfrac{\sqrt6}{\sqrt3-\sqrt2}\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\\\\\dfrac{\sqrt6}{\sqrt3-\sqrt2}\cdot\dfrac{\sqrt3+\sqrt2}{\sqrt3+\sqrt2}=\dfrac{\sqrt6(\sqrt3+\sqrt2)}{(\sqrt3-\sqrt2)(\sqrt3+\sqrt2)}=\dfrac{(\sqrt6)(\sqrt3)+(\sqrt6)(\sqrt2)}{(\sqrt3)^2-(\sqrt2)^2}[/tex]

[tex]\text{use}\ \sqrt{a}\cdot\sqrt{b}=\sqrt{ab}\ \text{and}\ (\sqrt{a})^2=a[/tex]

[tex]=\dfrac{\sqrt{(6)(3)}+\sqrt{(6)(2)}}{3-2}=\dfrac{\sqrt{18}+\sqrt{12}}{1}=\sqrt{9\cdot2}+\sqrt{4\cdot3}\\\\=\sqrt9\cdot\sqrt2+\sqrt4\cdot\sqrt3=3\sqrt2+2\sqrt3[/tex]

Answer:

12100

Step-by-step explanation:

If the number B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 from 1985 to 2007 where t = 0 correspond to year 1985

In order to determine the amount of federally insured banks that were there in 1990, we will first calculate the year range from initial time 1985 till 1990

The amount of time during this period is 5years. Substituting t = 5 into the modeled equation will give;

B ( t ) = − 329.4 t + 13747

B(5) = -329.4(5) + 13747

B(5) = -1647+13747

B(5) = 12100

This shows that there will be 12100 federally insured banks are there in the year 1990.

Answer:

1:3

Step-by-step explanation:

3/3=1

9/3=6

Answer:

Option A is the correct option.

Step-by-step explanation:

Given,

Number of pears = 3

Number of apples = 9

Find : Ratio of the number of pears to the number of apples on the fruit salad

Now,

[tex] \frac{pear}{apples} [/tex]

Plug the values

[tex] = \frac{3}{9} [/tex]

Divide the numerator and denominator by 3

[tex] = \frac{3 \div 3}{9 \div 3} [/tex]

Divide the numbers

[tex] = \frac{1}{3} [/tex]

It can be written as :

1 : 3

Hope this helps..

Best regards!!!

Answer:

[tex] x = 2 [/tex]

Step-by-step explanation:

Given a right-angled triangle as shown above,

Included angle = 60°

Opposite side length = 3

Adjacent side length = x

To find x, we would use the following trigonometric ratio as shown below:

[tex] tan(60) = \frac{3}{x} [/tex]

multiply both sides by x

[tex] x*tan(60) = \frac{3}{x}*x [/tex]

[tex] x*tan(60) = 3 [/tex]

Divide both sides by tan(60)

[tex] \frac{x*tan(60)}{tan(60} = \frac{3}{tan(60} [/tex]

[tex] x = \frac{3}{tan(60} [/tex]

[tex] x = 1.73 [/tex]

[tex] x = 2 [/tex] (approximated to whole number)

Answer:

Option A is correct

Step-by-step explanation:

From the question we are told that

  The  Null Hypothesis  is  [tex]H_o : p = 0.45[/tex]

   The alternative hypothesis [tex]H_a : p > 0.45[/tex]

   The  level of significance is  [tex]\alpha = 0.05[/tex]

    The  p-value is  [tex]p-value = 0.025[/tex]

Now looking at the given data we see that the the p-value is less than [tex]\alpha[/tex]

Generally when this occurs in a hypothesis test we reject the null hypothesis which mean that the result which we obtain is statistically significant.

Hence the alternative hypothesis is correct, which means that,

  There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%. which is option A

Answer:

  C. g(-13) = 20

Step-by-step explanation:

Let's check the offered statements:

  A. g(0) = 2 . . . . . . doesn't match g(0) = -2

  B. g(7) = -1 . . . . . . 7 is not in the domain of g

  C. g(-13) = 20 . . . could be true

  D. g(-4) = -11 . . . . -11 is not in the range of g

Answer:

Correct is A

Step-by-step explanation:

Correct is A , notice that when you perform synthetic division you get that the reminder is 50, please refer to the image I attach to see it.

for labor. Joni paid $85 less per hour for labor. explanation:

The correct comparison of the cost of labor between Shannon and Joni is that Shannon paid $7 more per hour for labor.

It refers to the total amount of the expenditure done on a product in manufacturing or procuring.

It refers to the expenditure done on procuring labor for the work.

In our situation Shannon paid total $339.50 in which the cost of the parts is $112 and 3.5 hours of labor. So,

labor cost Shannon Paid=339.50-112

=$227.50

labor cost per hour=227.50/3.5

=$6.5 per hour

Joni paid total $455 in which the cost of spare parts is $310 and rest is labor

labor cost paid by Joni=455-310

=$145

labor cost per hour=145/2.5

=$58 per hour

So by doing comparing we found that Shannon had paid $6 per hour extra for labor.

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Answer:

5 + 12i

Step-by-step explanation:

(3 + 2i)^2 = (3 + 2i)(3 + 2i) = 9 + 6i + 6i + 4i^2 = 9 + 12i - 4 = 5 + 12i

Answer:

5 + 2i

Step-by-step explanation:

since [tex]\sqrt{-1} = i[/tex]

Use the perfect square formula ( a + b )^2

= 3^2 + 2 · 3 · 2i + (2i)^2

= 5 + 2i

or,

[tex]5+2\sqrt{-1}[/tex]

Answer:

Orthocentre (intersection of altitudes) is at (37/10, 19/5)

Step-by-step explanation:

Given three vertices of a triangle

A(-5, -2)

B(7, -5)

C(3, 1)

Solution A by geometry

Slope AB = (yb-ya) / (xb-xa) = (-5-(-2)) / (7-(-5)) = -3/12 = -1/4

Slope of line normal to AB, nab = -1/(-1/4) = 4

Altitude of AB = line through C normal to AB

(y-yc) = nab(x-xc)

y-1 = (4)(x-3)

y = 4x-11           .........................(1)

Slope BC = (yc-yb) / (xc-yb) = (1-(-5) / (3-7)= 6 / (-4) = -3/2

Slope of line normal to BC, nbc = -1 / (-3/2) = 2/3

Altitude of BC

(y-ya) = nbc(x-xa)

y-(-2) = (2/3)(x-(-5)

y = 2x/3 + 10/3 - 2

y = (2/3)(x+2)    ........................(2)

Orthocentre is at the intersection of (1) & (2)

Equate right-hand sides

4x-11 = (2/3)(x+2)

Cross multiply and simplify

12x-33 = 2x+4

10x = 37

x = 37/10  ...................(3)

substitute (3) in (2)

y = (2/3)(37/10+2)

y=(2/3)(57/10)

y = 19/5  ......................(4)

Therefore the orthocentre is at (37/10, 19/5)

Alternative Solution B using vectors

Let the position vectors of the vertices represented by

a = <-5, -2>

b = <7, -5>

c = <3, 1>

and the position vector of the orthocentre, to be found

d = <x,y>

the line perpendicular to BC through A

(a-d).(b-c) = 0                          "." is the dot product

expanding

<-5-x,-2-y>.<4,-6> = 0

simplifying

6y-4x-8 = 0 ...................(5)

Similarly, line perpendicular to CA through B

<b-d>.<c-a> = 0

<7-x,-5-y>.<8,3> = 0

Expand and simplify

-3y-8x+41 = 0 ..............(6)

Solve for x, (5) + 2(6)

-20x + 74 = 0

x = 37/10  .............(7)

Substitute (7) in (6)

-3y - 8(37/10) + 41 =0

3y = 114/10

y = 19/5  .............(8)

So orthocentre is at (37/10, 19/5)  as in part A.