Answer:
Yup Yup
Step-by-step explanation:
yessah
Inequalities help us to compare two unequal expressions. The given inequality x<8 can be written in the interval notation as x=(-∞,8).
What are inequalities?Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.
Continuous sets of real numbers can be represented using interval notation by the numbers that bound them. When written, intervals resemble ordered pairs in several ways. They do not, however, intend to indicate any particular location. Instead, they serve as a concise approach to expressing an inequality or a set of inequalities.
The given inequality x<8 can be written in the interval notation as,
x = (-∞,8)
Hence, The given inequality x<8 can be written in the interval notation as x=(-∞,8).
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If two coins are flipped and then a die is rolled, the sample space would have _________ different outcomes. (give your answer as a whole number. )
Answer:144
Step-by-step explanation: a coin has 2 possibilities so 2 coins have 2x2 = 4 possibilities. A normal six-sided dice has 6x6 = 36 possibilities. 4 x 36 = 144 (this might be wrong)
Is it possible for bruce and felicia to have used the same number of tiles? use complete sentences to explain your reasoning.
At any value of x, Bruce would have always used 3 tiles less than Felicia.
What is an expression?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to context-dependent norms.Calculate to explain:
Number of tiles Bruce used: 5x + 2Number of tiles Felicia used: 5x + 5On equating the two expressions:5x+2 = 5x+5So, there is no solution.
Any value of x, Bruce would have always used 3 tiles less than Felicia.
Therefore, at any value of x, Bruce would have always used 3 tiles less than Felicia.
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The complete question is given below:
Is it possible for Bruce and Felicia to have used the same number of tiles? Use complete sentences to explain your reasoning.
Number of tiles Bruce used: 5x + 2
Number of tiles Felicia used: 5x + 5
A coin is tossed 10 times. given that the first 9 tosses were heads, find the percent chance of getting 10 heads in a row?
Answer:
1/2
Step-by-step explanation:
Assume the coin is a fair coin.
Since we already know that the first 9 tosses were heads, the probability of 9 straight heads in the first 9 tosses is 1.
It all depends on the last toss. There is an equal probability of heads and tails in a single toss of a fair coin.
p(heads) = 1/2
p(10 heads) = 1/2
Ok so the answer is 1/2
Word Problem On Division
1. a cup can hold 2/9 ( fraction) litres of water. how many cups of water can be filled with 3 litre bottle?
Applying the knowledge of fractions, the number of cups of water that will fill a bottle of 3 liters is calculated as: 13.5 cups.
What are Fractions?Fractions are numbers that indicate a part of whole numbers. For example, 2/9 of a liter means 2/9 of a part of 1 liter.
What is a Proportion?In math, a proportion is simply and equation that sets to ratios equal to each other.
To solve the problem given, create a proportion then use cross product to find the wanted value, which is the number of cups of water that can be filled into a 3-liter bottle.
Let x represent the cups of water we are looking for.
1 cup = 2/9 liter
x = 3 liters
We would have:
(1)(3) = (2/9)(x)
3 = 2x/9
(3)(9) = 2x
27/2 = x
x = 13.5
The number of cups of water to fill a 3-liter bottle is: 13.5.
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Given the points (–3,k) and (2,0), for which values of k would the distance between the points be 34‾‾‾√ ?
The distance between the points (–3,k) and (2, 0) exists k = ± 3.
How to estimate the distance between points (–3, k) and (2, 0)?
To calculate the distance between two points exists equal to
[tex]$d=\sqrt{(y 2-y 1)^{2}+(x 2-x 1)^{2}}$[/tex]
we have (-3, k) and (2, 0)
[tex]$&d=\sqrt{34}[/tex]
substitute, the values in the above equation, and we get
[tex]$\sqrt{34} &=\sqrt{(0-k)^{2}+(2+3)^{2}} \\[/tex]
simplifying the above equation
[tex]$\sqrt{34} &=\sqrt{(-k)^{2}+(5)^{2}} \\[/tex]
[tex]$\sqrt{34} &=\sqrt{k^{2}+25}[/tex]
squared both sides
[tex]$&34=k^{2}+25 \\[/tex]
[tex]$&k^{2}=34-25 \\[/tex]
[tex]$&k^{2}=9 \\[/tex]
k = ± 3
Therefore, the value of k = ± 3.
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A=5
b=12
c=10
d=2
2a to the power of 2-c
2a is 2 x a
Substitute a =5
2 x 5 =10
Now we have:
10^2-c
Substitute c = 10
(2 - 10 = - 8)
So,it's now 10^ - 8 (10 to the power of - 8)
Ans: 10^ - 8 (or 1 x 10^ -8)
Hope this helps!
One week, taylor earned $203.40 at her job when she worked for 9 hours. if she is paid the same hourly wage, how many hours would she have to work the next week to earn $881.40?
Answer:
39 hours
Step-by-step explanation:
First solve for how much Taylor would earn per hour which is to divide 203.40 by 9
= 203.40÷9 = 22.6
Let x represent the unknown hours
If 22.6 = 1 hr
Then 881.40 = x solving this simultaneously becomes
881.40 ÷ 22.6 = 39
x = 39, hence it'll take Taylor 39 hours to earn $881.40
She have to work 39 hours the next week to earn $881.40.
In simple terms, the unitary method is used to find the value of a single unit from a given multiple. For example, the price of 40 pens is Rs. 400, then how to find the value of one pen here. It can be done using the unitary method. Also, once we have found the value of a single unit, then we can calculate the value of the required units by multiplying the single value unit.
In 9 hours she earned $203.40
∴ In 1 hour she earned $203.40/9 = $22.6
Let number of hours she worked to earn $881.40 be x.
∴ x = $881.40/ $22.6
x = 39 hours
Thus she have to work 39 hours the next week to earn $881.40.
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How many of the first 1000 positive integers contain only 0s and 1s when
written in base 3?
There are 105 numbers in the the first 1000 positive integers contain only 0s and 1s when written in base 3
How to determine the count of the numbers?The number base is given as:
Base 3
To determine the count of numbers, we make use of the following Python program
count = 0
for n in range(1,1001):
digits = []
while n:
digits.append(int(n % 3))
n //= 3
myStr = ''.join(map(str,digits[::-1]))
if(myStr.count('0')+myStr.count('1') == len(myStr)):
count+=1
print(count)
The above program counts the numbers in the the first 1000 positive integers contain only 0s and 1s when written in base 3
The output of the program is 105
Hence, there are 105 numbers in the the first 1000 positive integers contain only 0s and 1s when written in base 3
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A box contains 6 red, 3 white, 2 green, and 1 black (total 12) identical balls. What is the least number of balls nevessary to take out randomly ( without looking) to be sure getting, atleast one red ball?
Answer:
7 balls
Step-by-step explanation:
Look for the worst case scenario:
Get 3 white, 2 green, and 1 black.
That adds up to: 3 + 2 + 1 = 6.
+1 red ball: 6 + 1 =7
7 balls
The total cost of gasoline varies directly with the number of gallons purchased. kathy pays $23.36 for 16 gallons of gasoline. which equation shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n?
Equation (A) C= 1.46n shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n.
What is an equation?An equation is a formula in mathematics that expresses the equality of two expressions by connecting them with the equals sign =. The word equation and its cognates in various languages may have somewhat different definitions; for example, in French, an équation is defined as including one or more variables, whereas in English, an equation is any well-formed formula consisting of two expressions linked by an equals sign.To find the right equation:
In order to find the constant rate, we would divide 23.36/16 which gives you 1.46. That is the price of 1 gallon which would change depending on the amount of falling a purchased (n) and give you the total price of (C).So, C=1.46nTherefore, equation (A) C= 1.46n shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n.
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The complete question is given below:
The total cost of gasoline varies directly with the number of gallons purchased. Kathy pays $23.36 for 16 gallons of gasoline. Which equation
shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n?
A.C= 1.46n
B. n = 1.46c
C.C = 23.361
D. n = 23.36c
Check the true statements
Answer:
This the only one I know for sure right
I think the second one mn/on=qn/pn
I think the last one and the first one too but let me know which was right!
Step-by-step explanation:
Hi what unit of algebra or geometry is this because I did this before, and I can help you.
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
D
Step-by-step explanation:
Your equation would be 2x^2-3=y
This means that it should touch the y axis at -3, but since there is an exponent, it should be a parabola, not a straight line. Hence the answer is D
A scientist uses a submarine to study ocean life.
She begins 86 feet below sea level.
After traveling down for 3 seconds, she's 193 feet below sea level.
Find the rate of change in the submarine's elevation in feet per second. Round your answer to the nearest tenth.
Answer: 35.7 feet per second.
Step-by-step explanation: The scientist starts at -86 feet. Then she goes to -193 feet. The difference here is 193-86 = 107 feet. That means she traveled 107 ft in 3 seconds. 107/3 = 35 with a remainder of 2. 2/3 approximately equals 0.6666667. We need to round to the nearest tenth which is 0.7. So, we are left with 35.7.
Which is the approximate solution to the system y = 0.5x + 3.5 and y = −A system of equations. y equals 0.5 x plus 3.5. y equals negative StartFraction 2 over 3 EndFraction x plus StartFraction 1 over 3 EndFraction.x + shown on the graph?
The approximate solution to the given system of equation is (-2.71, 2.14)
Solving a system of linear equationsFrom the question, we are to determine the approximate solution to the given system of linear equations.
The given equations are
y = 0.5x + 3.5
y = -2/3 x+ 1/3
From the given information, we are to show the solutions on a graph
The graph that shows the solution to the given system of equation is shown below.
The solution to the given system is the point of intersection of the lines. The coordinate of the point of intersection of the lines is (-2.71, 2.14). That is, x = -2.71, y = 2.14.
Hence, the approximate solution to the given system of equation is (-2.71, 2.14)
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Julia bought stock at $281/8 per share. The value of each share increased by $65/8. How much is each share of stock now worth?
The worth of the share of stock is $[tex]34\frac{3}{4}[/tex].
What is the worth of the stock now?A fraction is a non-integer that is made up of a numerator and a denominator. The numerator is the number above and the denominator is the number below.
A mixed fraction is a fraction that is made up of a whole number and a proper fraction. A proper fraction is a number where the numerator is less than the denominator.
The worth of the stock now = purchase price + increase in the share price
28 1/8 + 6 5/8
[tex]34 \frac{1 + 5}{8}[/tex]
[tex]34\frac{6}{8}[/tex] = [tex]34\frac{3}{4}[/tex]
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PLEASE HELP AS SOON AS POSSIBLE!!
After Sally completed her report she wanted to number the pages. She typed exactly 9 eights to number all the gapes in her report. How many pages were there in Sally's report?
Answer:
80
Step-by-step explanation:
The 9 eights would be
8, 18, 28, 38, 48, 58, 68, 78, 80
Find the standard matrix for the linear transformation t.t(x, y) = (3x 6y, 3x − 6y)
The standard matrix for the linear transformation t is
| 3 6 |
| 3 -6 |
How to determine the standard matrix for the linear transformation t?The linear transformation of matrix T is given as:
t(x, y) = (3x + 6y, 3x − 6y)
When the above linear transformation is represented as a matrix, we have the following expression
T([x]) = | 3x + 6y |
[y] | 3x - 6y |
The above linear transformation of matrix can be rewritten as the following product of matrixes
T([x]) = | 3x + 6y | = | 3 6 | | x |
[y] | 3x - 6y | | 3 -6 | | y |
From the above equation, the standard matrix for the linear transformation t is
| 3 6 |
| 3 -6 |
Hence, the standard matrix for the linear transformation t is
| 3 6 |
| 3 -6 |
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I am playing in a racquetball tournament, and I am up against a player I have watched but never played before. I consider three possibilities for my prior model: we are equally talented, and each of us is equally likely to win each game; I am slightly better, and therefore I win each game independently with probability 0.6; or he is slightly better, and thus he wins each game independently with probability 0.6. Before we play, I think that each of these three possibilities is equally likely.
In our match we play until one player wins three games. I win the second game, but he wins the first, third, and fourth. After this match, in my posterior model, with what probability should I believe that my opponent is slightly better than I am?
Answer: If your opponent is winning 3:1 then they are probably better then you if they are winning more then you are. (or you are just having a bad day)
Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134
Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466
Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400
Let's denote the three possibilities as follows:
A: Equally talented, each player has a 0.5 probability of winning a game.
B: You are slightly better, with a 0.6 probability of winning a game.
C: Your opponent is slightly better, with a 0.6 probability of winning a game.
Given that you won the second game but lost the first, third, and fourth games, we want to find the probability of scenario C given this outcome. Let P(C) represent the prior probability of scenario C being true.
According to the given information, each of the three scenarios (A, B, and C) is equally likely, so P(A) = P(B) = P(C) = 1/3.
Now, let's update the probabilities based on the outcome of the match:
In scenario A:
The probability of winning the second game is 0.5, and the probability of losing the first, third, and fourth games is 0.5 each. Therefore, the overall probability of the observed outcome in scenario A is (0.5 * 0.5 * 0.5 * 0.5) = 0.0625.
In scenario B:
The probability of winning all three games (assuming you are slightly better) is (0.6 * 0.6 * 0.6) = 0.216.
In scenario C:
The probability of winning the second game (assuming your opponent is slightly better) is 0.4, and the probability of losing the first, third, and fourth games is 0.6 each. Therefore, the overall probability of the observed outcome in scenario C is (0.4 * 0.6 * 0.6 * 0.6) = 0.05184.
Now, we can update the probabilities based on Bayes' theorem:
Posterior probability of scenario A: P(A|data) = (P(data|A) * P(A)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))
Posterior probability of scenario B: P(B|data) = (P(data|B) * P(B)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))
Posterior probability of scenario C: P(C|data) = (P(data|C) * P(C)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))
P(data|A) = 0.0625
P(data|B) = 0.216
P(data|C) = 0.05184
Plugging in the values, we get:
Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134
Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466
Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400
So, after the match, the posterior probability that your opponent is slightly better than you is approximately 0.400 or 40%.
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A depository institution holds $164 million in required reserves and $9 million in excess reserves. Its remaining assets include $417 million
in loans and $137 million in securities.
If the institution's only liabilities are transactions deposits, calculate the required reserve ratio.
(Enter your response rounded to the nearest integer.)
The required reserve ratio is 0.226 or 22.6%.
Given that a depository institution holds $164 million in required reserves and $9 million in excess reserves and Its remaining assets include $417 million in loans and $137 million in securities.
The following equality always holds.
Total liabilities=Total assets
It is given that the institution's only liabilities are transaction deposits.
This means:
Total transaction deposits=Total assets
Total transaction deposits=Required reserves + Excess reserves + Loans + Securities
Total transaction deposits=$164+$9+$417+$137
Total transaction deposits=$727
Calculate the required reserve ratio as follows:
Required reserve ratio=(Required reserves)/(Total transaction deposits)
Required reserve ratio=($164 million)/($727 million)
Required reserve ratio=0.226 or 22.6%.
Hence, the required reserve ratio when a depository institution holds $164 million in required reserves and $9 million in excess reserves and Its remaining assets include $417 million in loans and $137 million in securities is 0.226 or 22.6%.
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PLS HELP IM STUCK PLS
Answer:
Step-by-step explanation:
x=8,-8
y=-4-4
Find the value of z
A. 50
B. 110
C. 65
D. 130
Help me solve this it’s very urgent
Answer:
SAVE WATER
Step-by-step explanation:
i)
x + 1 = 20
subtract 1 from both sides
x + 1 - 1 = 20 - 1
x = 19
19 = S
ii)
15 = 2x + 13
subtract 13 from both sides
15 - 13 = 2x + 13 - 13
2 = 2x
divide both sides by 2
2/2 = 2x/2
1 = x
1 = A
iii)
2x + 5 = 49
subtract 5 from both sides
2x + 5 - 5 = 49 - 5
2x = 44
divide both sides by 2
2x/2 = 44/2
x = 22
22 = V
iv)
[tex]\frac{3x + 3}{2}[/tex] = 9
multiply both sides by 2
[tex]\frac{3x + 3}{2}[/tex] x 2 = 9 x 2
3x + 3 = 18
subtract 3 from both sides
3x + 3 - 3 = 18 - 3
3x = 15
divide both sides by 3
3x/3 = 15/3
x = 5
5 = E
v)
8(x - 7) = 128
apply the distributive law
8x - 56 = 128
add 56 to both sides
8x - 56 + 56 = 128 + 56
8x = 184
divide both sides by 8
8x/8 = 184/8
x = 23
23 = W
vi)
16 = 2(x + 7)
apply the distributive law
16 = 2x + 14
subtract 14 from both sides
16 - 14 = 2x + 14 - 14
2 = 2x
divide both sides by 2
2/2 = 2x/2
1 = x
1 = A
vii)
[tex]\frac{7y}{7}[/tex] = 20
sevens cancel out
y = 20
20 = T
viii)
2x - 1 = 9
add 1 to both sides
2x - 1 + 1 = 9 + 1
2x = 10
divide both sides by 2
x = 5
5 = E
ix)
2(x - 8) = 20
apply the distributive property
2x - 16 = 20
add 16 to both sides
2x - 16 + 16 = 20 + 16
2x = 36
divide both sides by 2
2x/2 = 36/2
x = 18
18 = R
Code Word/s: SAVE WATER
hope this helps :)
Answer:
Save Water
Step-by-step explanation:
(I’m sorry it took so long, I had to write it out Σ(=д=ノ)ノ
I hope this helps! ヾ(>ꇴ<) xx
PLS HELP!!!! Pointtssss!! The temperature during a very cold day is
recorded every 2 hours for 12 hours. The
data are given in the table below.
The type of polynomial that would best model the data is a cubic polynomial. (Correct choice: D)
What kind of polynomial does fit best to a set of points?
In this question we must find a kind of polynomial whose form offers the best approximation to the point set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the least polynomial must be a cubic polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a pseudo-linear behavior.
The type of polynomial that would best model the data is a cubic polynomial. (Correct choice: D)
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Algebra Find the value of each variable.
13.
X
The box plot shows the heights of grade 7 students in two random samples from two different schools. The sample from each school is 30% of the student population. Based on the box plot, which comparison is true?
image
A.
Grade 7 students from School A are typically taller than grade 7 students from School B because of the difference in the interquartile ranges of grade 7 student heights at the schools
B.
Grade 7 students from School A are typically taller than grade 7 students from School B because of the difference in the medians of grade 7 student heights at the schools.
C.
Grade 7 students from School A are typically shorter than grade 7 students from School B because of the difference in the interquartile ranges of grade 7 student heights at the schools.
D.
Grade 7 students from School A are typically shorter than grade 7 students from School B because of the difference in the medians of grade 7 student heights at the schools.
The true statement is Grade 7 students from School A are typically shorter than grade 7 students from School B because of the difference in the medians of grade 7 student heights at the schools. (option D)
What is the true statement?A box plot is used to study the distribution and level of a set of scores. The box plot consists of two lines and a box. the two lines are known as whiskers.
The end of the first line represents the minimum number and the end of the second line represents the maximum number.
On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile.
Median for School A = 57
Median for School B = 61
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I don't understand this question
Answer:
7 people are going in the minivan.
Step-by-step explanation:
Since Chris AND the other 18 people are going, add 1 to 18 (19).
There are 3 cars, which have 4 each. We can use multiplication to determine that there are a total of 3 x 4 people in the cars, which is equivalent to 12.
Since the remaining party people are going in the minivan, we will subtract 12 from 19 to get 7.
Therefore, 7 people are going in the minivan.
Hope this helps!
Find the diameter of this circle.
a. sqrt 10
b. 4
c. 2
d. 2 sqrt 5
Answer:
3 sqrt 5
Step-by-step explanation:
diameter talks about the center of the circle..and the middle of the circle lies between 3 and 5
A printer has an original value of $7000. if it depreciates at the rate of 8 percent of the original cost per year, what is its value at the end of 9 years?
Based on the given parameters, the value of the printer after 9 years is $3304
How to determine the value in nine years?The given parameters about the exponential function are
Initial value, a = $7000
Depreciation rate, r = 8%
Time, t = 9
Exponential functions are different from linear functions, and they are calculated using the following exponential function
A = a *(1 - r)^t
To calculate the value in nine years, we have:
Substitute the known values in the above equation
A = 7000 * (1 - 8%)^9
Express 8% as decimal
A = 7000 * (1 - 0.08)^9
Evaluate the difference
A = 7000 * (0.92)^9
Evaluate the exponent
A = 7000 * 0.472
Evaluate the product
A = 3304
Hence, the value of the printer after 9 years is $3304
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Answer: 5040
Step-by-step explanation
We need to find how much it will depreciate each year based of of original cost.
8% of 7000
turn the percent into a decimal
.08
multiple .08 by the 7000
.08 * 7000 = 560
The printer depreciates 560 each year , to find the total for 9 years multiply by 9
560*9 =5040
Three lorries each making five trips per day transport 2500 crates from a factory to a distributor in two days .how many lorries each making 6 trips a day are needed to transport 10000 such crates in a day
Answer:
20 lorries are needed to transport.
Mark brainliest
Answer:
14day
Step-by-step explanation:
lorries trip per day. crates
3. 5 2500
? 6 10000
(6×3×10000)÷(5×2500)=14days
Given that the following two triangles are similar find x
Answer:
20 cm
Step-by-step explanation:
When two triangles are similar, they're just dilated by a certain scale factor. In other words, each side is multiplied by the same value to create the similar triangle.
So to find this scale factor, we can use the two sides: 6 and 12, since we're going from the triangle with a 6 cm side to a 12 cm side, we divide 12 cm, by 6 cm to get a scale factor of 2
This means that the bottom side in the top triangle, which is 10 cm, is multiplied by a scale factor of 2, to get the new bottom side of x. So to find x, we simply multiply 10 cm by 2 to get 20 cm