Answer:
Cevap b okey xx
Explanation:
Sinyorrr
Given two character strings s1 and s2. Write a Pthread program to find out the number of substrings, in string s1, that is exactly the same as s2
Answer:
Explanation:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#define MAX 1024
int total = 0 ;
int n1, n2;
char s1, s2;
FILE fp;
int readf(FILE fp)
{
if((fp=fopen("strings.txt", "r"))==NULL) {
printf("ERROR: can’t open string.txt!\n");
return 0;
}
s1=(char)malloc(sizeof(char)MAX);
if(s1==NULL) {
printf("ERROR: Out of memory!\n");
return 1;
}
s2=(char)malloc(sizeof(char)MAX);
if(s1==NULL) {
printf("ERROR: Out of memory!\n");
return 1;
}
/* read s1 s2 from the file */
s1=fgets(s1, MAX, fp);
s2=fgets(s2, MAX, fp);
n1=strlen(s1); /* length of s1 */
n2=strlen(s2)-1; /* length of s2 */
if(s1==NULL || s2==NULL || n1<n2) /* when error exit */
return 1;
}
int num_substring(void)
{
int i, j, k;
int count;
for(i=0; i<=(n1-n2); i++) {
count=0;
for(j=i, k=0; k<n2; j++, k++){ /* search for the next string of size of n2 */
if((s1+j)!=(s2+k)) {
break;
}
else
count++;
if(count==n2)
total++; /* find a substring in this step */
}
}
return total;
}
int main(int argc, char argv[])
{
int count;
readf(fp);
count=num_substring();
printf("The number of substrings is: %d\n", count);
return 1;
}
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have methods that return the following:
the total rainfall for the year
the average monthly rainfall
the month with the most rain
the month with the least rain
Demonstrate the class in a complete program.
Input Validation: Do not accept negative numbers for monthly rainfall figures.
import java.io.*;
import java.util.*;
public class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
months[n-1] = in.nextInt();
}
}
public double getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is" + total);
return total;
}
public double getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is" + average);
return average;
}
public double getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amout of rainfall was" + largest +
"inches in month" + (largeind + 1));
return largest;
}
public double getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amout of rainfall was" + smallest +
"inches in month " + (smallind + 1));
return smallest;
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
System.out.println("Total" + r.getTotal());
System.out.println("Smallest" + r.getSmallest());
System.out.println("Largest" + r.getLargest());
System.out.println("Average" + r.getAverage());
}
}
Answer:
Explanation:
The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.
import java.io.*;
import java.util.*;
class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
int answer = 0;
while (true) {
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
answer = in.nextInt();
if (answer > 0) {
months[n-1] = answer;
break;
}
}
}
}
public void getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is " + total);
}
public void getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is " + average);
}
public void getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amount of rainfall was " + largest +
" inches in month " + (largeind + 1));
}
public void getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amount of rainfall was " + smallest +
" inches in month " + (smallind + 1));
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
r.getTotal();
r.getSmallest();
r.getLargest();
r.getAverage();
}
}
you are installing two new hard drives into your network attached storage device your director asks that they be put into a raid solution that offers redundndancy over performance which would you use
Question options:
a. RAID 0
b. RAID 1
c. RAID 5
d. RAID 6
e. RAID 10
Answer:
d. RAID 6
Explanation:
RAID is Redundant Array of Inexpensive/Independent Disks. RAID combines low cost physical hard disk drives in one hard disk drive. RAID is used to achieve data redundancy(data backup but with synchronization) or improved performance or both.
To get what the director requires he would need to use RAID 6. RAID 6 is RAID level optimized to achieve data redundancy but with slow performance.
3. When using the ohmmeter function of a digital multimeter, the leads are placed in what position relative to the component being tested?
A. Series
B. Parallel
C. Control
D. Line
Answer:
B. Parallel
Explanation:
When using the ohmmeter function of a digital multimeter, the leads are placed parallel to the component being tested. The digital multimeter is placed parallel to the component because, current has to flow into the component so as to be able to measure its resistance. Without the flow of current in the component, the resistance could not be measured.
If the component were placed in series, there would be no way to close the circuit because, we need a closed circuit so as to measure the resistance and use the ohmmeter function of the digital multimeter.
Only a parallel connection would close the circuit.
So, B is the answer.
Preserving confidentiality, integrity, and availability is a restatement of the concern over interruption, interception, modification, and fabrication.
i. Briefly explain the 4 attacks: interruption, interception, modification, and fabrication.
ii. How do the first three security concepts relate to these four attacks
Answer and Explanation:
I and II answered
Interruption: interruption occurs when network is tampered with or communication between systems in a network is obstructed for illegitimate purposes.
Interception: interception occurs when data sent between systems is intercepted such that the message sent to another system is seen by an unauthorized user before it reaches destination. Interception violates confidentiality of a message.
Modification: modification occurs when data sent from a system to another system on the network is altered by an authorized user before it reaches it's destination. Modification attacks violate integrity, confidentiality and authenticity of a message.
Fabrication: fabrication occurs when an unauthorized user poses as a valid user and sends a fake message to a system in the network. Fabrication violates confidentiality, integrity and authenticity.
Computer data that is suitable for sound
Answer:
Answer:In this context sound data is stored and transmitted in an analog form. Since computers represent data in digital form, (as bits and bytes) the
Una persona decide comprar un número determinado de quintales de azúcar, ayúdele a presentar el precio de venta al público por libra, considerando un 25% de utilidad por cada quintal.
The computer that is used in scientific research is ........
Answer:
supercomputers are the computer that is used in scientific research.
Answer:
super computer is the right answer
Program to calculate series 10+9+8+...+n" in java with output
Answer:
import java.util.Scanner;
class Main {
public static int calcSeries(int n) {
int sum = 0;
for(int i=10; i>=n; i--) {
sum += i;
}
return sum;
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int n = 0;
do {
System.out.print("Enter n: ");
n = reader.nextInt();
if (n >= 10) {
System.out.println("Please enter a value lower than 10.");
}
} while (n >= 10);
reader.close();
System.out.printf("sum: %d\n", calcSeries(n));
}
}
Write a class Example() such that it has a method that gives the difference between the size of strings when the '-' (subtraction) symbol is used between the two objects of the class. Additionally, implement a method that returns True if object 1 is greater than object 2 and False otherwise when the (>) (greater than) symbol is used. For example: obj1
Answer:
Here the code is given as follows,
Explanation:
class Example:
def _init_(self, val):
self.val = val
def _gt_(self, other):
return self.val > other.val
def _sub_(self,other):
return abs(len(self.val) - len(other.val))
def main():
obj1 = Example('this is a string')
obj2 = Example('this is another one')
print(obj1 > obj2)
print(obj1 - obj2)
main()
Output:-
State three advantages associated with the use of diskettes in computers
Write a program in Cto define a structure Patient that has the following members
Answer:
Explanation:
The answer should be 1.16 or 61.1
Select the correct statement(s) regarding 4B5B encoding.
a. 4B5B is used to map four codeword bits into a five bit data word
b. 4B5B information bit rate is 80% of the total (information plus overhead) bit rate
c. 4B5B information bit rate is 20% of the total (information plus overhead) bit rate
d. all statements are correct
Answer:
b. 4B5B information bit rate is 80% of the total information plus overhead bit rate.
Explanation:
4B5B bit rate encoding means there is 80% of the bit rate which included all the information plus the overheads. There is 20% of lack in bit rate due to encoding code words which converts data into smaller bits.
how much is this worth in dollars
Answer:
This is worth 50 dollars.
Explanation:
١ - one
٢ - two
٣ - three
٤ - four
٥ - five
٦ - six
٧ - seven
٨ - eight
٩ - nine
٠ - zero
What you see above is the ten digits in Arabic.
Both 5 (٥) and 0 (٠) appear here, thus representing 50.
Write a program that reads in the size of the side of a square and then prints a hollow square of that size out of asterisks and
blanks. Your program should work for squares of all side sizes between 1 and 20. For example, if your program reads a size of 5, it
should print
Answer:
Explanation:
#include <iostream>
using std::cout;
using std::endl;
using std::cin;
int main()
{
int side, rowPosition, size;
cout << "Enter the square side: ";
cin >> side;
size = side;
while ( side > 0 ) {
rowPosition = size;
while ( rowPosition > 0 ) {
if ( size == side || side == 1 || rowPosition == 1 ||
rowPosition == size )
cout << '*';
else
cout << ' ';
--rowPosition;
}
cout << '\n';
--side;
}
cout << endl;
return 0;
}
In Interactive Charting, which chart type allows you to chart the current spread between a corporate bond and a benchmark government bond?
a. Price
b. Price Impact
c. Bond Spread
d. Yield Curve
Answer:
c. Bond Spread
Explanation:
An interactive chart is used to show all the details in the chart and the user can extend or shrink the details that is presented in the charts by using the slider control.
The bond spread in an interactive is a chart that is used to compare and chart the current spread between the corporate bond as well as the benchmark government bond.
In Interactive Charting, the chart type that give room for charting the current spread between a corporate bond and a benchmark government bond is C:Bond Spread.
An interactive charts serves as a chart that give room to the user to carry out zooming actions as well as hovering a marker to get a tooltip and avenue to choose variable.
One of the notable type of this chart is Bond Spread, with this chart type, it is possible to charting the current spread that exist between a corporate bond as well as benchmark government bond.
Therefore, option C is correct because it allows charting of the current spread between a corporate bond.
Learn note about interactive charts at:
https://brainly.com/question/7040405
The subroutines/function calls you need to call to pass an application message down to the transport layer is called the
Answer:
"TCP/IP library" is the appropriate answer.
Explanation:
A communications protocol that always connects to yet another system or device and guarantees transmissions were also correctly converted to digital signals or received, is termed as TCP/IP.Technology can also do a variety of things on its own and. However, when you speak among each other devices' maximum throttle emerges.View "The database tutorial for beginners" and discuss how database management systems are different from spreadsheets. Describe one experience you have had working with data.
Answer and Explanation:
A spreadsheet is an interactive computer application for the analysis and storage of data. The database is a collection of data and accessed from the computer system. This is the main difference between spreadsheets and databases. The spreadsheet is accessed by the user and the database is accessed by the user. The database can store more data than a spreadsheet. The spreadsheet is used for tasks and used in enterprises to store the data. Spreadsheet and database are two methods and the main difference is the computer application that helps to arrange, manage and calculate the data. The database is a collection of data and organized to access easily. Spreadsheet applications were the first spreadsheet on the mainframe. Database stores and manipulates the data easily. The database maintains the data and stores the records of teachers and courses. The spreadsheet is the computer application and analyzing the data in table form. The spreadsheet is a standard feature for productive suite and based on an accounting worksheet.
Giải thích mục đích của các thao tác open() và close().
Answer:
Which lan is it
Answer:
Đang học năm nhất trường TDT đúng k bạn :D
Explanation:
Coding 5 - Classes The Item class is defined for you. See the bottom of the file to see how we will run the code. Define a class ShoppingCart which supports the following functions: add_item(), get_total_price(), and print_summary(). Write code only where the three TODO's are. Below is the expected output: Added 2 Pizza(s) to Cart, at $13.12 each. Added 1 Soap(s) to Cart, at $2.25 each. Added 5 Cookie(s) to Cart, at $3.77 each.
Answer:
Explanation:
The following is written in Java. It creates the ShoppingCart class as requested and implements the requested methods. A test class has been added to the main method and the output is highlighted in red down below.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
ShoppingCart newCart = new ShoppingCart();
newCart.add_item();
newCart.add_item();
newCart.add_item();
newCart.print_summary();
}
}
class ShoppingCart {
Scanner in = new Scanner(System.in);
ArrayList<String> items = new ArrayList<>();
ArrayList<Integer> amount = new ArrayList<>();
ArrayList<Double> cost = new ArrayList<>();
public ShoppingCart() {
}
public void add_item() {
System.out.println("Enter Item:");
this.items.add(this.in.next());
System.out.println("Enter Item Amount:");
this.amount.add(this.in.nextInt());
System.out.println("Enter Cost Per Item:");
this.cost.add(this.in.nextDouble());
}
public void get_total_price() {
double total = 0;
for (double price: cost) {
total += price;
}
System.out.println("Total Cost: $" + total);
}
public void print_summary() {
for (int i = 0; i < items.size(); i++) {
System.out.println(amount.get(i) + " " + items.get(i) + " at " + cost.get(i) + " each.");
}
get_total_price();
}
}
Write a Python program square_root.py that asks a user for an integer n greater or equal to 1. The program should then print the square root of all the odd numbers between 1 and n (Including n if n is odd). Print the square roots rounded up with no more than two digits after the decimal point.
Answer:
import math
n = int(input("Enter n: "))
for number in range(1, n+1):
if number % 2 == 1:
print("{:.2f}".format(math.sqrt(number)), end=" ")
Explanation:
In order to calculate the square roots of the numbers, import math. Note that math.sqrt() calculates and gives the square root of the given number as a parameter
Ask the user to enter the n
Create a for loop that iterates from 1 to n+1 (Since n is included, you need to write n+1)
Inside the loop, check whether the number is odd or not using the if structure and modulo. If the number is odd, calculate its square root using the math.sqrt() and print the result with two digits after the decimal
Write a removeDuplicates() method for the LinkedList class we saw in lecture. The method will remove all duplicate elements from the LinkedList by removing the second and subsequent elements. If there is only one copy of an element, it is not removed. The list size should shrink accordingly based on the number of duplicates removed.
Answer:
removeDuplicates() function:-
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
Explanation:
Complete Code:-
//Create Linked List Class.
class LinkedList {
//Create head pointer.
static ListNode head;
//define structure of ListNode.
//it has int val(data) and pointer to ListNode i.e, next.
static class ListNode {
int val;
ListNode next;
//constructor to create and initialize a node.
ListNode(int d) {
val = d;
next = null;
}
}
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
//display() function prints linked list.
void display(ListNode node)
{
//run while loop till last node.
while (node != null)
{
//print node value of current node.
System.out.print(node.val + " ");
//move node pointer by one node.
node = node.next;
}
}
public static void main(String[] args) {
//Create object of Linked List class.
LinkedList list = new LinkedList();
//first we create nodes and connect them to form a linked list.
//Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.
//Create a Node having node data = 1 and assign head pointer to it.
//As head is listNode of static type. so, we call head pointer using class Name instead of object name.
LinkedList.head = new ListNode(1);
//Create a Node having node data = 2 and assign head.next to it.
LinkedList.head.next = new ListNode(2);
LinkedList.head.next.next = new ListNode(3);
LinkedList.head.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next = new ListNode(4);
LinkedList.head.next.next.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next.next.next = new ListNode(5);
LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);
//display linked list before Removing duplicates.
System.out.println("Linked List before removing duplicates : ");
list.display(head);
//call removeDuplicates() function to remove duplicates from linked list.
list.removeDuplicates();
System.out.println("")
//display linked list after Removing duplicates.
System.out.println("Linked List after removing duplicates : ");
list.display(head);
}
}
Output:-
A cashier distributes change using the maximum number of five-dollar bills, followed by one-dollar bills. Write a single statement that assigns num_ones with the number of distributed one-dollar bills given amount_to_change. Hint: Use %.
Sample output with input: 19
Change for $ 19
3 five dollar bill(s) and 4 one dollar bill(s)
1 amount_to_change = int(input())
2
3 num_fives amount_to_change // 5
4
5 Your solution goes here
6 I
7 print('Change for $, amount_to_change)
8 print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')
Answer:
Explanation:
The code that was provided in the question contained a couple of bugs. These bugs were fixed and the new code can be seen below as well as with the solution for the number of one-dollar bills included. The program was tested and the output can be seen in the attached image below highlighted in red.
amount_to_change = int(input())
num_fives = amount_to_change // 5
#Your solution goes here
num_ones = amount_to_change % 5
print('Change for $' + str(amount_to_change))
print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')
Suppose that you write a subclass of Insect named Ant. You add a new method named doSomething to the Ant class. You write a client class that instantiates an Ant object and invokes the doSomething method. Which of the following Ant declarations willnot permit this? (2 points)I. Insect a = new Ant ();II. Ant a = new Ant ();III. Ant a = new Insect ();1) I only2) II only3) III only4) I and II only5) I and III only
Answer:
5) I and III only
Explanation:
From the declarations listed both declarations I and III will not permit calling the doSomething() method. This is because in declaration I you are creating a superclass variable but initializing the subclass. In declaration III you are doing the opposite, which would work in Java but only if you cast the subclass to the superclass that you are initializing the variable with. Therefore, in these options the only viable one that will work without error will be II.
What are the LinkedIn automation tools you are using?
Answer:
Well, for me I personally use LinkedCamap to drive more LinkedIn connections, hundreds of leads, sales, and conversions automatically.
Some other LinkedIn automation tools are;
ExpandiMeet AlfredPhantombusterWeConnectLinkedIn HelperHope this helps!
Write three statements to print the first three elements of vector runTimes. Follow each with a newline. Ex: If runTimes = {800, 775, 790, 805, 808}, print: 800 775 790
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int main()//main method
{
int runTimes[] = {800, 775, 790, 805, 808};//defining array of integer
for(int x=0;x<3;x++)//defining for loop to print three element of array value
{
printf("%d\n",runTimes[x]);//print array value
}
return 0;
}
Output:
Please find the attached file.
Explanation:
In this code, an array integer "runTimes" is declared that holds the given array values, and in the next step, a for loop is declared.
Inside the loop, an integer variable x is declared that starts from 0 and ends when its value less than 3 in which we print the first three array element values.
Write a class called Student that has two private data members - the student's name and grade. It should have an init method that takes two values and uses them to initialize the data members. It should have a get_grade method.
Answer:
Explanation:
The following class is written in Python as it is the language that uses the init method. The class contains all of the data members as requested as well as the init and get_grade method. It also contains a setter method for both data variables and a get_name method as well. The code can also be seen in the attached image below.
class Student:
_name = ""
_grade = ""
def __init__(self, name, grade):
self._name = name
self._grade = grade
def set_name(self, name):
self._name = name
def set_grade(self, grade):
self._grade = grade
def get_name(self):
return self._name
def get_grade(self):
return self._grade
Write a program that reads a list of integers, and outputs those integers in reverse. The input begins with an integer indicating the number of integers that follow. For coding simplicity, follow each output integer by a comma, including the last one.Ex: If the input is:5 2 4 6 8 10the output is:10,8,6,4,2,To achieve the above, first read the integers into a vector. Then output the vector in reverse.
Answer:
The program in C++ is as follows:
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> intVect;
int n;
cin>>n;
int intInp;
for (int i = 0; i < n; i++) {
cin >> intInp;
intVect.push_back(intInp); }
for (int i = n-1; i >=0; i--) { cout << intVect[i] << " "; }
return 0;
}
Explanation:
This declares the vector
vector<int> intVect;
This declares n as integer; which represents the number of inputs
int n;
This gets input for n
cin>>n;
This declares intInp as integer; it is used to get input to the vector
int intInp;
This iterates from 0 to n-1
for (int i = 0; i < n; i++) {
This gets each input
cin >> intInp;
This passes the input to the vector
intVect.push_back(intInp); }
This iterates from n - 1 to 0; i.e. in reverse and printe the vector elements in reverse
for (int i = n-1; i >=0; i--) { cout << intVect[i] << " "; }
now now now now mowewweedeeee
Answer:
15
Inside the type declaration, you specify the maximum length the entry can be. For branch, it would be 15.
I can't seem to type the full "vc(15)" phrase because brainly won't let me.
Your dashboard should show the sum and average as two separate columns. If you use measure names as the column field, what should you use for the marks
Answer:
Hence the answer is a sum.
Explanation:
Here the statement shows that the dashboard should show the sum and average as two separate columns if we name measure names because the column field then for marks we'll use the sum. Since the sum displays the sum of the values of all the fields, which refers to the marks of the person.
Therefore the answer is a sum.
If we use measure names as the column field, we should use "the sum".
A set of cells that are support equipment on about a similar vertical line, is considered as a column.
Usually, the name of the user or a client represents a field column, while the total and sometimes even averaging columns in our dashboards or screen are different.When using a summation of total summary, perhaps the column field (title), as well as its amount and averaging marking, are indicated.The preceding reply is thus right.
Learn more:
https://brainly.com/question/17271202
