Write the rule that describes the first transformation?
RED —> BLUE

Answer:

The distance between the campsites was 70 miles.

Step-by-step explanation:

Since two groups were moving from one campsite to another, and the first group traveled the distance in 5 hours while the second group finished in 7 hours, to find the distance between the campsites if the first group was going 4mph faster than the second group, the following calculation must be performed:

X + 4 = 5

X = 7

4 x 7 = 28

(4 + 4) x 5 = 40

10 x 7 = 70

(10 + 4) x 5 = 70

Therefore, the distance between the campsites was 70 miles.

Answer Deleted

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Answer:

Charge for each bag = 0.65

Step-by-step explanation:

Let the cost of 1 bag be = x

Bags             Cost

750               375.00

 1                     x

[tex]\frac{750}{1} = \frac{375}{x}\\\\x \times 750 = 375 \times 1\\\\x = \frac{375}{750} = 0.50[/tex]

Therefore, the amount Jose paid for each bag = 0.50

He is going to sell each bag for 0.15 more than he paid,

that is , 0.50 + 0.15 = 0.65

Answer:

(5,4)

Step-by-step explanation:

The coordinates of a point are the x and y-values of a point. It is organized like (x,y). The x-value is written first and then the y-value. The x-value is the "run" or the horizontal value; so, the value of the axis on the bottom. The y-value is the "rise" or the vertical value. The axes are also labeled. For this graph, the x-value is 5 and the y-value is 4. The final answer is (5,4).

Answer: 13/7 or as a decimal 1.857142857

How did i get the answer:

Step 1: Simplify both sides of the equation.

so 1/2 of 10 is 5, 1/2 of 16 is 8

-3/5 of 15 is -9 and -3/5 of -35 is POSITIVE 21

all together should look like 5x+8+−13=−9x+21

(now we have to combine like terms)

8+ -13= -5

5x -5 = -9x+21

Step 2: Add 9x to both sides

5x + 9x= 14x

14x -5 = 21

Step 3: Add 5 to both sides.

21+5= 26

14x=26

Step 4: Divide both sides by 14.

26/14= 1.85714286 or 13/7

Given:

After deduction of 4 paisa in a Rupee a sum of Rs 720 is left.

To find:

The original amount.

Solution:

We know that,

1 Rs. = 100 paisa

After deduction of 4 paisa in a Rupee, we get

[tex]100-4=96[/tex]

It means Rs. 720 is the 96% of the original amount.

Let x be the original amount.

[tex]720=\dfrac{96}{100}x[/tex]

[tex]72000=96x[/tex]

[tex]\dfrac{72000}{96}=x[/tex]

[tex]750=x[/tex]

Therefore, the original amount is Rs. 750.

Answer:

1437.3 cm^3 is the volume of sphere whose radius is 7cm

Answer:

x=2.5

Step-by-step explanation:

2 (2+3y)÷2+3y=8

2+3y+3y=8

2+6y=8

6y=8-2

6y=6

y=1

x=2+3(1)÷2

x=5÷2

x=2.5

The values of x and y are 2.5,1

y = -7(-13)

=> y = -7 × (-13)

= y = 91

Answer:

[tex]\frac{3v}{a^{2}} = h[/tex]

Step-by-step explanation:

[tex]v = \frac{1}{3} a^{2} h[/tex]

[tex]3v = a^{2} h[/tex]

[tex]\frac{3v}{a^{2}} = h[/tex]

Answer:

Below.

Step-by-step explanation:

Sameer:-

Number of mango's = total weight / weight of 1 mango

= 5 kg / 500g

= 5000/500

= 10.

Number of apples: =  5000/250 = 20.

Total number of fruit = 30.

Anil :-

Number of guava = total weight / weight of 1 guava

= 7 kg / 800g

= 7000/800

= 9.

Number of banana: =  4000/625 = 6.

Total number of fruit = 15.

Sameer bought the most fruit,  15 more than Anil.

Note: in Anil's case I rounded the values to the nearest whole number.

Answer:

The program in Java is as follows:

import java.util.*;

public class PyTheorem{

   public static void main(String [] args){

       Random rNum = new Random();

       int a = rNum.nextInt(17) + 5;

       int b = rNum.nextInt(17) + 5;

       System.out.println("a: "+a);

       System.out.println("b: "+b);

       double hyp = Math.sqrt(Math.pow(a,2)+Math.pow(b,2));

       System.out.print("Hypotenuse: "+hyp);

   }}

Step-by-step explanation:

This generates random number for a

       int a = rNum.nextInt(17) + 5;

This generates random number for b

       int b = rNum.nextInt(17) + 5;

Print a

       System.out.println("a: "+a);

Print b

       System.out.println("b: "+b);

Calculate the hypotenuse

       double hyp = Math.sqrt(Math.pow(a,2)+Math.pow(b,2));

Print the calculated hypotenuse

       System.out.print("Hypotenuse: "+hyp);

Answer:

49+m

Step-by-step explanation:

37+12 = 49

49 + m is the total time Katherine takes.

Answer:

Step-by-step explanation:

19.

The numbers are m and n

Sum of m and n = m + n

Sum is multiplied by 91 = 91 x ( m + n )

20.

Let the number be = m

Six subtracted from the number = m - 6

41 times the difference = 41 x ( m - 6)

21.

Let the number be = r

Difference between 83 and 10 = 83 - 10 = 73

[tex]The \ number\ divided \ by\ the \ difference \ = \frac{r}{73}[/tex]

22.

Total of p and 23 = p + 12

[tex]Total \ divided \ by \ 18 = \frac{p + 12 }{18}[/tex]

23.

The product of c and 3  = 3c

Sum of 9 and 12 = 21

Product is more than Sum = 3c + 21

24.

Sum of y  and 10 = y + 10

Number x decreased by 5 = x - 5

[tex]Sum \ divided \ by \ difference = \frac{ y + 10 }{x - 5}[/tex]

Answer:

33km

Step-by-step explanation:

Let the distance traveled by bus be x, then distance traveled by train would be 2x

Therefore,

5 + x + 2x = 104

5 + 3x = 104

3x = 104 - 5

3x = 99

x = 33

Step-by-step explanation:

[tex](\sec A - \csc A)(1 + \cot A + \tan A)[/tex]

[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)[/tex]

[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)[/tex]

[tex]=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)[/tex]

[tex]=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)[/tex]

[tex]=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}[/tex]

[tex]=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}[/tex]

[tex]=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}[/tex]

[tex]=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}[/tex]

[tex]=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)[/tex]

[tex]=\sec^2A\csc A - \csc^2A\sec A[/tex]

Answer:

2

Step-by-step explanation:

Given [tex]-6-2x[/tex] where [tex]x=-4[/tex], substitute [tex]x=-4[/tex] to find the value of the given equation.

Substituting [tex]x=-4[/tex]:

[tex]-6-2(-4)[/tex]

Multiply [tex]-2\cdot -4[/tex]:

[tex]-6+8[/tex]

Combine like terms:

[tex]-6+8=\boxed{2}[/tex]

Therefore, the value of [tex]-6-2x[/tex] when [tex]x=-4[/tex] is [tex]\boxed{2}[/tex].

9514 1404 393

Explanation:

Your question covers a good bit of the material in an algebra course. The short answer is, "the same way you solve a numerical equation." The point of algebra is that literals can stand for numbers, and so be manipulated the same way numbers are.

Expressions are evaluated according to the Order of Operations. For equations involving a single variable, the equation specifies what operations are being performed on that variable. To find the vale of the variable (solve for that literal), you need to "undo" the operations that are performed on it. As with many problems that have layers, you work down through the layers from the outside in. Generally, that means working through the list of operations "backwards," undoing the last one first.

Simple example

  y = mx + b . . . . . . solve for x

In this equation, the operations performed on x are ...

In accordance with the above, the first thing we do is "undo" the addition of b. (Note that this could be a number or literal--or even a complicated expression--and the process would be exactly the same.) To "undo" addition, we add the opposite.

  y -b = mx +b -b   ⇒   y -b = mx

Next, we "undo" the multiplication by m. That is, we divide by m, or multiply by the reciprocal of m. Either is the same as the other.

  (y -b)(1/m) = (mx)(1/m)   ⇒   (y -b)/m = x

Now, we have solved this literal equation for x.

_____

Throughout this process you must adhere strictly to the properties of equality. That is, anything you do to one side of the equation must also be done to the other side.

The reason you study inverses and identity elements is so you understand that addition of an additive inverse produces the additive identity element:

  x + (-x) = 0

Similarly, multiplication by the multiplicative inverse (reciprocal) produces the multiplicative identity element.

  x · (1/x) = 1

When other operations are involved, such as raising to a power, trig functions, roots, logs, exponentiation, each of these has an associated inverse function that produces an identity:

  (x^a)^(1/a) = x^1 = x

  arcsin(sin(x)) = x

  (√x)^2 = x

  10^(log(x)) = x   or   log(10^x) = x

Some of these inverse functions have restricted domains, so care must be used when solving equations involving them.

When a variable of interest appears on both sides of the equal sign, then you must figure a way to rearrange the equation so the terms with the variable can be combined.

Example:

  ax + b = cx +d . . . . . solve for x

  ax -cx = d -b . . . . . . subtract (cx+b). (Of course, this is subtracted from both sides of the equation.)

  x(a -c) = d -b . . . . . combine x-terms

  x = (d -b)/(a -c) . . . . divide by the coefficient of x

Note that we had to divide the entire right-side expression by the x-coefficient, so had to enclose it in parentheses.

More Complicated Example:

A recent Brainly problem asked for the solution to ...

  T = 2π√(L/g) . . . . solve for L

Here, L is divided by g, a root taken, and that multiplied by 2π. Undoing these in reverse order, we first divide by 2π, square both sides to undo the root, then multiply by g to undo the division:

  [tex]T=2\pi\sqrt{\dfrac{L}{g}}\\\\\dfrac{T}{2\pi}=\sqrt{\dfrac{L}{g}}\\\\\left(\dfrac{T}{2\pi}\right)^2=\dfrac{L}{g}\\\\\boxed{L=g\left(\dfrac{T}{2\pi}\right)^2}[/tex]

The problem posted on Brainly had numbers where some of these variables are. That does not affect the solution method, except that sometimes numerical values can be combined where literal values cannot.

_____

Key Points

Answer:

-7

Step-by-step explanation:

if you multiply by 7 positive it wont work because u cant cancel 7x out and a fraction wont work because theres no fraction involved in this so ur answer is A

Answer:

（2,1）

Step-by-step explanation:

the graph intersects at 2 and 1

Explanation:

The range is the set of y outputs of a relation. So we just list the y coordinates of the points shown.

We could sort the values to get {-1, 4, 11, 13}, but order doesn't matter in a set. So this step is optional.

Answer:

True

Step-by-step explanation:

Required

Does dilation preserve angle measure?

When a point, side, line, or angle is dilated; the length of the line will be altered by the ratio or scale of dilation.

However, the measure of angle will remain the same.

Hence, the given statement is true.

Answer:

Joe must sell $ 24,330 to make $ 2,082.9 in commission.

Step-by-step explanation:

Since Joe works as a salesman at the baby retail store, and he receives a 5% commission on the first $10,000, 9% on the next $7,000, and 13% on any additional sales, to calculate how much Joe must sell to make $2082.9 in commission the following calculation must be performed:

10,000 x 0.05 = 500

7,000 x 0.09 = 630

2,082.90 - 500 - 630 = X

952.90 = X

0.13X = 952.90

X = 952.90 / 0.13

X = 7.330

10,000 + 7,000 + 7,330 = X

24,330 = X

Therefore, Joe must sell $ 24,330 to make $ 2,082.9 in commission.

Answer:

Our fourth number is 52.

Step-by-step explanation:

Let our first even number be x.

Then the second even number must be (x + 2), the third (x + 4), fourth (x + 6), and the fifth (x + 8).

They sum to 250. Hence:

[tex]x+(x+2)+(x+4)+(x+6)+(x+8)=250[/tex]

Solve for x. Combine like terms:

[tex]5x+20=250[/tex]

Subtract 20 from both sides:

[tex]5x=230[/tex]

And divide both sides by five. Hence:

[tex]x=46[/tex]

Thus, our sequence is 46, 48, 50, 52, and 54.

Hence, our fourth number is 52.

Answer: Tis 0

Step-by-step explanation:

Answer:

Option C

Step-by-step explanation:

Suppose that we have a given proposition p

We define the complement as:

"NOT p" or ¬p

So, if p is:

the dog is red

the complement is

the dog is NOT red.

The principal rule to work with this is:

if p is true, then ¬p is false

if p is false, then ¬p is true.

Here the proposition is:

p = "When 100 engines are shipped, all of them are free of defects."

When this is this is true, ¬p must be false.

when this is false, ¬p must be true.

Let's analyze the given options, first the incorrect ones:

A: "At most one of the engines is defective."

here if we have for example, two defective engines, then this proposition and the original proposition are false.

B: " All of the engines are defective."

Here if there is one defective engine, then this is false, and also is the original proposition.

D: "None of the engines are defective"

When the original proposition is true "When 100 engines are shipped, all of them are free of defects.", this proposition is also true (because none of the engines are defective)

Finally, the corrrect one

C "At least one of the engines is defective"

When the original proposition is true, there are no defective engines, so this is false.

While, if this is true, there is at least one defective engine, so the original proposition is false.

Then this is the correct option:

¬p = "At least one of the engines is defective"

Answer: 12

Step-by-step explanation:

The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.