a. The product of the reaction between [tex]H_{3}C[/tex]-C=CH₂ and [tex]Br_{2}[/tex] is 1,2-dibromo-2-methylpropane: [tex]H_{3}C[/tex]-C=CH₂ + [tex]Br_{2}[/tex] → BrCH₂ -CH(Br)-[tex]CH_{3}[/tex]
b. The product of the reaction between [tex]H_{3}C[/tex]-CH=CH-[tex]CH_{3}[/tex] and conc. [tex]H_{2}SO _{4}[/tex] is 2-methylpropene:
[tex]H_{3}C[/tex]-CH=CH-[tex]CH_{3}[/tex] + [tex]H_{2}SO _{4}[/tex] → [tex]H_{3}C[/tex]-C([tex]CH_{3}[/tex])=CH₂ + H₂O
c. The product of the reaction between [tex]KMnO_{4}[/tex] (aq) and any organic compound is typically a mixture of products, depending on the specific organic compound being reacted. Therefore, the structure of the product cannot be determined without additional information about the organic compound being reacted.
d. NR means that no reaction occurs.
What is product of the reaction ?
In chemistry, the product of a reaction refers to the substances that are formed as a result of a chemical reaction. These substances are formed by the rearrangement of atoms and molecules in the reactants. The products of a chemical reaction are typically represented by a chemical equation, which shows the reactants on the left side of the equation and the products on the right side of the equation. In many cases, the products of a chemical reaction have different properties than the reactants, and they can be used in a variety of applications in chemistry, biology, and other fields.
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A student mixes 100. mL of 0.25 M HCl(aq) with 200. mL of 0.50 M HClO4(aq) and then dilutes the mixture with distilled water to a total volume of 500. mL. The [H3O+] in the final solution is closest to
(A) 0.0025 M
(B) 0.12 M
(C) 0.25 M
(D) 0.75 M
Answer:
The answer is B: 0.0025 M
According to molar concentration and dilution concept, the [H₃O+] in the final solution is closest to 0.05 M.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.In case of 2 solutions concentrated and diluted it is calculated as, M₁V₁=M₂V₂ substitution gives M₂=0.25×100/500=0.05
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Please help me
Define acid.
Mention four products of destructive distillation of coal.
In a tabular, highlight two differences between diamond and graphite.
List four types of salt.
Outline two physical properties of a base.
why does glass containing an iced beverage feel cold
Answer:
Molecules in the skin are moving faster than molecules in the glass.
Explanation:
Put it in your own words.
Answer:
The energy from the ice transferred to the glass.
d. Addition of a catalyst
7) At 15 °C, a certain reaction is able to produce 0.80 moles of product per minute? At what rate might
the product be produced at 25 °C?
a. 0.80 moles per minute
b. 1.6 moles per minute
c. 0.40 moles per minute
d. 0.20 moles per minute
Addition of a catalyst, at 15 °C, a certain reaction is able to produce 0.80 moles of product per minute at 25 °C it will produce at a rate of 0.40 moles per minute. The correct option to this question is C.
Effect of temperatureAs the concentration of an enzyme rises, so does the rate of an enzyme-catalyzed reaction. An enzyme-catalyzed process moves more quickly at higher temperatures than it does at lower ones. The protein gets denatured at higher temperatures, which also noticeably slows down the rate of the reaction.With a reduced activation energy, a catalyst offers the reaction a different pathway. The rate will rise since there are more particles with activation energy today. The activation energy does not change as the temperature rises.The amount of energy that can be transformed into activation energy in a collision increases with temperature, which will speed up the reaction rate. The opposite would happen if the temperature dropped.For more information on catalyst kindly visit to
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1. Your teacher will show a video that demonstrates how aluminum metal reacts
with copper (II) chloride (CuCl₂). Answer the following questions about the
reaction you observed between aluminum and copper(II) chloride.
(a) Based on the observations you made during the video, write the balanced
molecular equation for the reaction between solid aluminum and a solution
of copper(II) chloride.
The balanced molecular equation for the reaction between solid aluminum and a solution of copper(II) chloride is: 2Al(s) + 3CuCl2(aq) → 3Cu(s) + 2AlCl3(aq).
What takes place when aluminium and copper II chloride interact?Aluminium and copper(II) chloride react very vigorously, causing the reaction mixture to become extremely hot as heat is produced, the aluminium foil to dissolve, a reddish brown solid to appear, and gas bubbles to be released.
What does place when aluminium foil is dipped in a copper II nitrate solution?The aluminium foil disintegrates, heat is released, the copper(II) ions' blue colour disappears, and a new, reddish-brown solid develops in the reaction mixture.
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. Mercury is the only metal which is a liquid at room temperature. The density of mercury is 13.6 g/cm3. What is the mass, in pounds, of 1.00 quart of mercury? [1 liter = 1.057 quart; 1 pound = 453.6 grams]
According to the question the 1.00 quart of mercury has a mass of 0.0283 lb.
What is mercury?Mercury is the smallest and innermost planet in the Solar System. It is a terrestrial planet with a thin atmosphere composed mostly of oxygen, sodium, and helium. It is one of four rocky planets on the inside of the Solar System, the other three being Venus, Earth and Mars. Mercury is named after the Roman deity Mercury, the messenger of the gods. It is a very dense planet due to its large iron core and its small size.
1 quart = 0.946 liters
1.00 quart of mercury has a mass of 13.6 g/cm³ x 0.946 liters = 12.8 g
To convert the mass of mercury from grams to pounds, divide 12.8 g by 453.6 g/lb.
12.8 g / 453.6 g/lb = 0.0283 lb
Therefore, 1.00 quart of mercury has a mass of 0.0283 lb.
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The equation below represents the dissociation of vinegar which is a weak acid. How can you tell that it is an acid and it is weak? Just from looking at the equation.
Because it is not very effective at transferring [tex]H^{+}[/tex] ions to water, vinegar is a weak acid. Less than 0.4% of the [tex]CH_{3}CO_{2}H[/tex]molecules in a 1 M solution interact with water to create [tex]H_{3}O^{+}[/tex]and [tex]CH_{3}CO_{2}^{-}[/tex] ions. More than 99.6% of the acetic acid molecules are still whole.
Weak acidsAcids that partially dissociate in solution are referred to as weak acids. To put it another way, a weak acid is any acid that is not a strong acid. A weak acid's strength is influenced by how much it dissociates; the more it dissociates, the stronger the acid.In comparison to weak acids, strong acids have a lower pH. 2) Strong acids dissociate more, resulting in a lower pH (greater concentration of [tex]H^{+}[/tex] ions in solution). 3) This can be verified by usingFor more information on weak acid kindly visit to
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4. If 7.37 liters of HCI reacts with Al, how many moles of hydrogen, H₂,can be produced?
As a result, aluminium (Al) and 7.37 litres of hydrochloric acid (HCl) can react to produce 225.46 moles of hydrogen gas (H2).
8.0 moles of Al interacting with HCl can produce how many moles of H2?As a result, when 8 moles of aluminium are entirely consumed during the process of dissolving it in HCl solution, 12 moles of hydrogen gas are created.
The chemical reaction between aluminium (Al) and hydrochloric acid (HCl) has the following balanced chemical equation:
[tex]3 H2 + 2 AlCl3 = 2 HCl + 2 Al[/tex]
According to the equation, 2 moles of HCl result in 3 moles of H2. In order to determine the amount of H2 generated, we must first determine how many moles of HCl are contained in 7.37 litres of acid.
The following formula can be used to determine the quantity of HCl:
Volume in litres times concentration in moles per litre equals moles.
Since the HCl concentration is not specified in the inquiry, we are unable to immediately calculate the moles. However, we may convert the volume in litres to the mass in grams using the density of HCl, and then use the molar mass of HCl to calculate the number of moles.
At standard circumstances (0 °C and 1 abm), HCl has a density of roughly 1.49 g/mL. As a result, 7.37 litres of HCl have the following mass:
Density equals mass, therefore 7.37 L times 1.49 g/mL equals 10.9763 kg.
Since HCl has a molar mass of about 36.46 g/mol, there are the following moles of HCl:
[tex]10.9763 kg / 36.46 g/mol = 300.61 mol is the formula for moles of HCl.[/tex]
Now, we can determine the number of moles of H2 created using the mole ratio from the balanced equation: moles of[tex]H2 = (moles of HCl / 2) x (3/2) = (300.61 mol / 2) x (3/2) = 225.46 mol[/tex]
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create dialogue between two people
A dialogue is a conversation between two or more people.
What is dialogue?A dialogue is a conversation between two or more people.
Here's an example of a dialogue between two people named John and Sarah:
John: Hi, Sarah. How are you doing today?
Sarah: Hey, John. I'm doing pretty well, thanks. How about you?
John: Not too bad. Hey, did you hear about the new restaurant that opened up on Main Street?
Sarah: No, I haven't. What's it called?
John: It's called La Cantina. I heard they have really good Mexican food.
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How does a Sulfur 2 ion differ from a neutral Sulfur atom?
O
Mass number
Atomic number
Number of electrons
Proton number
Answer:
o
Mass number
Atomic number
Number of electrons
Proton number
Explanation:
how many moles
if you have a bottle of sulfur hexafluoride 20.00 L and a density of 6.17 g/L
Answer:
Explanation:
Ρ=6.17g/L
m=20*6.17
m=123.4g
n=m/M
n=123.4 mol/138
n= 0.89mol
Students are planning to conduct some tests on two substances: candle wax and sulfur crystals
Which property of the wax and the sulfur should be investigated to provide evidence of the relative strengths of their intermolecular forces?
A. Mass
B. Color
C. Texture
D. Melting point
Melting point is the property of the wax and the sulfur should be investigated to provide evidence of the relative strengths of their intermolecular forces. Therefore, the correct option is option D.
What is intermolecular forces?The electrical forces of attraction and repulsion that act between atoms along with other types of nearby particles, such as atoms or ions, are examples of intermolecular forces (IMFs), also known as secondary forces. In comparison to intramolecular forces, which bind a molecule together, intermolecular forces are weak.
For instance, the forces between adjacent molecules are substantially weaker than the covalent bond, which involves sharing pairs of electrons between atoms. Both types of forces are crucial components of the force fields that molecular mechanics typically use. Melting point is the property of the wax and the sulfur should be investigated to provide evidence of the relative strengths of their intermolecular forces.
Therefore, the correct option is option D.
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Describe the orbital notation in detail. For example, 1s: up arrow down arrow; 2s up arrow down arrow; 2p three up arrows for potassium.
1s2 2s2 2p6 3s2 3p6 4s1
Orbital notation is a way of representing the electronic configuration of an atom, which describes the arrangement of electrons in its various energy levels or orbitals.
How is each orbital is represented by in the orbital notation?In this notation, each orbital is represented by a box or circle, and the electrons are represented by up or down arrows, which indicate their spin. The number and arrangement of boxes and arrows in the notation follow the rules of the Aufbau principle, the Pauli exclusion principle, and Hund's rule.
The Aufbau principle tells that electrons fill the least energy orbitals before filling higher energy orbitals. The first shell of an atom contains one s orbital, which can hold up to two electrons. The s orbital is represented by a single box or circle, and each electron is represented by an up or down arrow.
The electronic configuration for potassium (K) is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹. In orbital notation, this would be represented as 1s: up arrow, down arrow; 2s: up arrow, down arrow; 2p: up arrow, up arrow, up arrow; 3s: up arrow, down arrow; 3p: up arrow, up arrow, up arrow; 4s: up arrow.
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Sulfurous acid ( H2SO3) is a diprotic acid with a1=1.39×10−2 and a2=6.73×10−8.
Determine the pH of a 0.189M sulfurous acid ( H2SO3 ) solution.
A sulfuric acid solution with a concentration of 0.189M has a pH of roughly 0.778.
Sulfuric acid: Is it a diprotic acid?A diprotic acid is sulfuric acid, Sulfurous acid. The findings of an acid-base titration can be used to calculate the values of Ka1 and Ka2. To completely neutralise diprotic acids, two hydroxide ions are needed for each molecule. Sulfuric acid, a stronger acid than Hydrogen sulfide, with a pH of 1.5 in a solution of 0.100 mol dm³.
The chemical equation for sulfuric acid dissociation is as follows:
Sulfuric acid + Water ⇌ Hydronium ion + hydrosulfite anion
Write the expression for the acid dissociation constant (Ka1) for the first dissociation:
Ka1 = [Hydronium ion[hydrosulfite anion]/[Sulfuric acid]
Substitute the given value of Ka1 (1.39×10−2) and the initial concentration of Sulfuric acid (0.189 M) into the expression for Ka1 and solve for [hydronium ion]:
1.39×10−2 = [hydronium ion][Hydrogen sulfite]/0.189
[hydronium ion] = 0.167 M
pH = -log[hydronium ion]
pH = -log(0.167)
pH = 0.778
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Calculate the mole fraction of H₂SO₄ in a solution of 583 g of H₂SO₄ (98.079 g/mol) in 1.50 kg of water (18.0153 g/mol).
0.0666
0.0713
0.28
2.12
The mole fraction of H₂SO₄ in the given solution is 0.0666.
What is Solution?
A solution is a homogeneous mixture of two or more substances, where the substances are evenly distributed at the molecular or ionic level. In a solution, the solute is the substance that is dissolved, while the solvent is the substance that dissolves the solute. The properties of a solution are different from those of its individual components, and the composition of a solution can be varied within certain limits. Solutions can be classified as solid, liquid or gas solutions, depending on the state of the solvent and solute.
To calculate the mole fraction of H₂SO₄ in the given solution, we need to first calculate the moles of H₂SO₄ and water:
Moles of H₂SO₄ = Mass / Molar mass = 583 g / 98.079 g/mol = 5.945 mol
Moles of water = Mass / Molar mass = 1.50 kg / 18.0153 g/mol = 83.277 mol
The total moles of solute and solvent in the solution are:
Total moles = Moles of H₂SO₄ + Moles of water = 5.945 mol + 83.277 mol = 89.222 mol
The mole fraction of H₂SO₄ in the solution can be calculated as:
Mole fraction of H₂SO₄ = Moles of H₂SO₄ / Total moles
Mole fraction of H₂SO₄ = 5.945 mol / 89.222 mol = 0.0666
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The structural layers of the sun are shown in the cross-sectional diagram. An image of six concentric circles is shown. The six layers thus formed are of varying thickness. The layers in order from inside out are labeled, A, B, C, D, E, F. Which layer represents the corona? C D E F
The outermost of the six sun layers with the letters A, B, C, D, E, and F, layer F in the cross-sectional figure symbolises the corona.
Is the corona of the sun referred to as such?The Sun's atmosphere's outermost region is called the corona. The brilliant brightness of the Sun's surface often obscures the corona. Without employing specialised equipment, it is challenging to see. A total solar eclipse, however, makes the corona visible.
What takes place within the corona layer?The term "corona" refers to the topmost region of the Sun's atmosphere. It rises hundreds of kilometres above the Sun's surface and gradually changes into the solar wind, which travels across our solar system.
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If all the coefficients in the already balanced equation are multiplied by 2, will the equation still remain balanced and will the multiplication affect the equilibrium constant? If you answer yes to any part of the question, please explain in detail.
Yes, If all the coefficients in a balanced chemical equation are multiplied by 2, the equation will still remain balanced because the ratio of the reactants and products remain the same.
What are the coefficients?
For example, the balanced equation: [tex]2H_{2}[/tex] + [tex]O_{2}[/tex] -> [tex]2H_{2}O[/tex]
The coefficients of a chemical equation are the numbers written in front of the chemical formulas of reactants and products, indicating the relative amounts of each substance involved in the reaction. The coefficients are used to balance the chemical equation, ensuring that the law of conservation of mass is obeyed. The coefficients represent the smallest whole-number ratios of the substances in the reaction, and they provide important information about the stoichiometry of the reaction.
When all the coefficients are multiplied by 2, the equation becomes: [tex]4H_{2}[/tex] + [tex]2O_{2}[/tex] -> [tex]4H_{2}O[/tex]
The equation is still balanced because the ratio of hydrogen to oxygen to water molecules remains the same (4:2:4).
Multiplying the coefficients by a constant will not affect the equilibrium constant (Kc) as long as the reaction conditions remain constant. This is because the equilibrium constant is a ratio of the concentrations of products and reactants at equilibrium, and the ratio remains the same even if the coefficients of the balanced equation are multiplied by a constant. However, if the temperature, pressure or concentration of any reactants or products are changed, then the value of the equilibrium constant will change.
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In which case are the white balls the maximum distance, and the maximum angle apart?
The maximum distance between the two white balls is 2R, and the maximum angle between them is 180 degrees (or π radians).
How to solveMaximum distance between the balls:
The maximum distance between the two white balls will be achieved when they are placed at opposite ends of a diameter of the circular region.
In this case, the distance between them will be equal to the diameter of the circle, which is 2R.
Maximum angle between the balls:
To find the maximum angle between the two balls, imagine the center of the circle as the vertex of the angle, and the positions of the two balls as the endpoints of the angle's two sides.
Since the balls are located at opposite ends of a diameter, the angle formed will be a straight angle, which is 180 degrees (or π radians).
So, the maximum distance between the two white balls is 2R, and the maximum angle between them is 180 degrees (or π radians).
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Two white balls, A and B, are placed on a flat surface inside a circular region of radius R. What is the maximum distance and maximum angle between the balls that can be achieved
Determine the density of carbon dioxide gas at 100.0°C and 9.81 atm pressure?
(R = 0.08206 L • atm/K • mol) C(12.01), O(16.00)
The density of carbon dioxide gas at 100.0°C and 9.81 atm pressure is approximately 1.950 g/L.
How to determine the density of carbon dioxide?To determine the density of carbon dioxide gas at 100.0°C and 9.81 atm pressure, we can use the ideal gas law, which is given by:
PV = nRT where:
P = pressure of the gas (in atm)
V = volume of the gas (in liters)
n = number of moles of the gas
R = ideal gas constant (0.0821 L atm / (mol K))T = temperature of the gas (in Kelvin)
First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15 to it:
Temperature in Kelvin (T) = 100.0°C + 273.15T = 373.15 K
Next, we can rearrange the ideal gas law to solve for density, which is defined as mass per unit volume:
Density (d) = mass / volume
Since density is equal to mass divided by volume, we can rewrite the ideal gas law equation in terms of density: d = (m / V) = (P * M) / (RT) where:m = mass of the gas (in grams);M = molar mass of the gas (in g/mol).
We also need to convert the pressure from atm to Pascals (Pa) since SI units are used for density:
Pressure in Pascals (Pa) = Pressure in atm * 101325 (Pa/atm)
Given:Temperature (T) = 373.15 K
Pressure (P) = 9.81 atm * 101325 Pa/atm = 997647.05 Pa (rounded to 5 significant figures)
Molar mass of carbon dioxide (CO2) = 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen)
Plugging in the given values into the equation for density:
d = (P * M) / (RT)d = (997647.05 Pa * 44.01 g/mol) / (0.0821 L atm / (mol K) * 373.15 K)
Note that the units cancel out appropriately to give us the density in g/L, since mass is in grams and volume is in liters:d = 1.950 g/L
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CaCO3 + 2HCI =CaCl2 + H₂O + CO2
5. Calcium carbonate (CaCO3) combines with HCl to produce calcium chloride (CaCl₂),
water, and carbon dioxide gas (CO₂). How many grams of HCI are required to react with
6.35 mol CaCO3?
463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.
What is meant by molar mass?Mass of one mole of substance is referred to as the molar mass. The molar mass of a substance can be calculated by adding up the atomic masses of all the atoms in a molecule.
Balanced chemical equation for the reaction between calcium carbonate (CaCO₃) and hydrochloric acid (HCl) is: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
6.35 mol CaCO₃ * 2 mol HCl / 1 mol CaCO₃ = 12.7 mol HCl
Now, we use the molar mass of HCl (36.46 g/mol) to convert from moles to grams: 12.7 mol HCl * 36.46 g/mol = 463.5 g HCl
Therefore, 463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.
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Which statements best describe plasmas? Check all that apply.
• Plasmas have a definite volume.
• Plasmas can change shape.
• Plasmas contain ionized particles
• Plasmas are abundant on Earth.
• Plasmas are good insulators
The statement "Plasmas can change shape" and "Plasmas contain ionized particles" best describe plasmas.
What is plasmas?Plasma is a state of matter similar to solids, liquids, and gases. It is often called the fourth state of matter. Plasmas are created by ionizing a gas, which means that some or all of its atoms have been stripped of their electrons, leaving behind positively charged ions and negatively charged electrons. The resulting mixture of charged particles can conduct electricity and respond to electric and magnetic fields.
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Draw the full arrow pushing mechanism for the following reaction
In an arrow-pushing mechanism, a curved arrow is drawn from a region of high electron density to a region of low electron density.
What is an arrow-pushing mechanism in the reaction of organic compounds?An arrow-pushing mechanism is a way of representing the movement of electrons during a chemical reaction in organic chemistry. It uses curved arrows to show how electrons are shifted or transferred between atoms in a molecule.
For example, in a nucleophilic substitution reaction, a nucleophile attacks an electrophilic center, and the electrons from the nucleophile form a new bond with the electrophilic center. The movement of electrons is shown by the curved arrow.
Arrow-pushing mechanisms are also used to represent other types of reactions, such as acid-base reactions, addition reactions, elimination reactions, and rearrangement reactions.
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Phosphorus (P4) and oxygen react to produce diphosphorus pentoxide. How many grams of diphosphorus pentoxide are produced from the reaction of 38.76 grams of oxygen with excess phosphorus? Round your answer to the hundredths of a gram. Do not include units. Use the atomic masses in this PERIODIC TABLE. DO NOT ROUND THESE MASSES IN YOUR CALCULATION.
The mass of diphosphorus pentoxide produced is: 549.47 g
What is mass?
Mass is a measure of the amount of matter in an object. It is typically measured in units of grams (g) or kilograms (kg). Mass is a scalar quantity and is different from weight, which is the force exerted on an object due to gravity and depends on both the mass of the object and the acceleration due to gravity.
The balanced chemical equation for the reaction between phosphorus and oxygen to produce diphosphorus pentoxide is:
[tex]4P[/tex] + [tex]5O_{2}[/tex] → [tex]2P_{4}O_{10}[/tex]
To solve the problem, we need to first calculate the amount of phosphorus required to react with 38.76 grams of oxygen. Since phosphorus is in excess, the amount of diphosphorus pentoxide produced will be limited by the amount of oxygen.
The molar mass of oxygen is 15.999 g/mol. Therefore, the number of moles of oxygen in 38.76 grams is:
38.76 g / 15.999 g/mol = 2.422 mol
According to the balanced equation, 5 moles of oxygen react with 4 moles of phosphorus to produce 2 moles of diphosphorus pentoxide. Therefore, the number of moles of phosphorus required is:
4/5 × 2.422 mol = 1.9376 mol
The molar mass of diphosphorus pentoxide is 283.886 g/mol. Therefore, the mass of diphosphorus pentoxide produced is:
1.9376 mol × 283.886 g/mol = 549.47 g
Rounding to the hundredths of a gram, the answer is:
549.47 g → 549.47
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Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO2 through the solution. How much SO2 is required to treat 3.00 × 108 L of 4.50×10-2 mM Cr(VI)?
We need 2.59 × 10⁷ g or 25.9 metric tons of SO₂ to treat 3.00 × 10⁸ L of 4.50×10⁻² mM Cr(VI).
What is meant by aqueous solution?Solution in which the solvent is water (H₂O) is known as an aqueous solution.
Balanced equation for the reaction is: Cr₂O₇²⁻ + 3SO₂ + 2H₂O → 2CrO₄²⁻ + 3H₂SO₄
Cr₂O₇²⁻ = 2 × 52 + 7 × 16 = 252 g/mol
n(Cr₂O₇²⁻) = [Cr₂O₇²⁻] × V
n(Cr₂O₇²⁻) = (4.50 × 10² mM) × (3.00 × 10⁸ L) × (1 mM / 1000 mM)
n(Cr₂O₇²⁻) = 1.35 × 10⁵ mol
n(SO₂) = 3 × n(Cr₂O₇²⁻)
n(SO₂) = 3 × 1.35 × 10⁵ mol
n(SO₂) = 4.05 × 10⁵ mol
mass(SO₂) = n(SO₂) × MM(SO2)
mass(SO₂) = (4.05 × 10⁵ mol) × (64.06 g/mol)
mass(SO₂) = 2.59 × 10⁷ g
Therefore, we need 2.59 × 10⁷ g or 25.9 metric tons of SO₂ to treat 3.00 × 10⁸ L of 4.50×10⁻² mM Cr(VI).
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The temperature of a 2.0-liter sample of helium gas at STP is increased to 27C, and the pressure is decreased to 80 kPa. What is the new volume of the helium sample? Round your answer to the nearest tenth of a liter?
The new volume of the helium sample would be 2.4 L.
Volume of a gasAccording to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in kelvins.
At STP (standard temperature and pressure), which is defined as 0°C (273.15 K) and 101.325 kPa, the volume of 2.0 liters of helium gas contains one mole of helium atoms.
To find the new volume of the helium sample when the temperature is increased to 27°C (300.15 K) and the pressure is decreased to 80 kPa, we can use the following equation:
(P1V1)/T1 = (P2V2)/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
Plugging in the values, we get:
(101.325 kPa)(2.0 L)/(273.15 K) = (80 kPa)(V2)/(300.15 K)
Solving for V2, we get:
V2 = (101.325 kPa)(2.0 L)/(273.15 K) * (300.15 K)/(80 kPa) = 2.36 L
Therefore, the new volume of the helium sample is approximately 2.4 L (rounded to the nearest tenth).
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CaCO3 + 2HCI=CaCl2 + H₂O + CO₂
6. If 6.32 grams of CaCO3 reacts with HCl, how many liters of water, H₂O, are formed?
Water produced by 6.32 grams of [tex]CaCO_{3}[/tex] reacts with [tex]HCl[/tex] reaction is 0.11376 L as the density of water is 1.
How to calculate volume of water?[tex]CaCO_{3}[/tex]'s molar mass is equal to 100 g/mol (40 + 12 + 16 3 g/mol).
HCl's molar mass is (1 + 35.5) g/mol, or 36.5 g/mol.
Water's molecular weight is (12 + 16) g/mol, or 18 g/mol.
[tex]CaCO_{3}[/tex]initial mole number = (6.32g) / (100 g/mol) = 0.00632mol
Initial number of moles of HCl = (35.5 g/mol/36.8 g) = 1.04 mol
Mole ratio: [tex]CaCO_{3}:HCl:CaCl_{2}:H_{2}O[/tex]= 1: 2: 1: 1. [tex]CaCO_{3}:HCl:CaCl_{2}:H_{2}O[/tex]
If [tex]CaCO_{3}[/tex] fully reacts, [tex]HCl[/tex] is required at a rate of (0.00632mol) x 2 (equals 0.01264mol <1.04 mol).
[tex]HCl[/tex] is hence abundant. As a reactant, [tex]CaCO_{3}[/tex] is the limiting one.
Total number of [tex]CaCO_{3}[/tex] reactions: 0.00632moles
No. of moles of water created / No. of moles of [tex]CaCO_{3}[/tex] reacting / 0.00632mol
0.11376 g of [tex]H_{2}O[/tex]were generated from (0.00632 mol) by (18 g/mol).
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2. When dinitrogen pentoxide is heated, it decomposes to
nitrogen dioxide and oxygen. How many moles of nitrogen
dioxide can be formed from the decomposition of 1.25 g of
dinitrogen pentoxide?
0.02314 moles of NO₂ can be formed from the decomposition of 1.25 g of dinitrogen pentoxide.
The balanced equation for the decomposition of dinitrogen pentoxide is:
2 N₂O₅ → 4 NO₂ + O₂
The molar mass of N₂O₅ is 108.01 g/mol.
To determine the number of moles of N₂O₅ present in 1.25 g, we use the following calculation:
moles N₂O₅ = mass / molar mass
moles N₂O₅ = 1.25 g / 108.01 g/mol
moles N₂O₅ = 0.01157 mol
From the balanced equation, we can see that 2 moles of N₂O₅ decompose to form 4 moles of NO2. Therefore, the number of moles of NO2 produced can be calculated as:
moles NO₂ = (0.01157 mol N2O5) × (4 mol NO2 / 2 mol N2O5)
moles NO₂ = 0.02314 mol
Therefore, 0.02314 moles of NO₂ can be formed from the decomposition of 1.25 g of dinitrogen pentoxide.
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Help please! I'll award brainliest and extra points if you show your work too :)
a. This reaction is endothermic because energy is absorbed during the reaction.
b. ΔH = +187 kJ
What is the energy change of the reaction?c. The balanced chemical equation for the decomposition of calcium carbonate is:
CaCO3(s) → CO2(g) + CaO(s)
d. We can use the molar mass of calcium carbonate to convert 21.0 g of CaCO3 to moles:
21.0 g CaCO3 x (1 mol CaCO3 / 100.09 g CaCO3) = 0.210 mol CaCO3
From the balanced equation, we can see that the molar ratio of CaCO3 to ΔH is 1:1. Therefore, the energy absorbed can be calculated as:
0.210 mol CaCO3 x 187 kJ/mol = 39.3 kJ
Therefore, 39.3 kJ of energy is absorbed during the decomposition of 21.0 g of calcium carbonate.
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CHALLENGE The circles below represent of the large circle, and multiply it by 30. That Earth and the moon. Measure the diameter would be the correct distance from Earth to the moon at this scale. Draw the two circles in the space provided. Use the correct distance you found.● = Earth ●=moon
To draw the two circles, we would need to draw a smaller circle with a diameter of 2,532.5 miles (representing the moon) and a larger circle with a diameter of 75,974.4 miles (representing the Earth) that is 30 times larger than the smaller circle.
What is the explanation for the above response?If we assume that the larger circle represents the Earth, then the diameter of the Earth would be 30 times the diameter of the smaller circle representing the moon. Let's say that the diameter of the smaller circle is x. Then the diameter of the larger circle (Earth) would be 30 times x or 30x.
To find the correct distance from Earth to the moon at this scale, we need to know the actual distance from Earth to the moon, which is approximately 238,855 miles or 384,400 kilometers. If we divide this distance by the scale factor of 30, we get:
238,855 miles / 30 = 7,961.8 miles
Therefore, the diameter of the smaller circle (moon) would be approximately 7,961.8 miles / π = 2,532.5 miles (rounded to one decimal place). And the diameter of the larger circle (Earth) would be 30 times that or 75,974.4 miles
So, to draw the two circles, we would need to draw a smaller circle with a diameter of 2,532.5 miles (representing the moon) and a larger circle with a diameter of 75,974.4 miles (representing the Earth) that is 30 times larger than the smaller circle.
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15.0 moles of gas are in a 6.00 L tank at 20.3 ∘C . Calculate the difference in pressure between methane and an ideal gas under these conditions. The van der Waals constants for methane are a=2.300L2⋅atm/mol2 and b=0.0430 L/mol.
Under the given circumstances, the pressure difference between methane and an ideal gas is 58.5 atm.
What is an ideal gas?An ideal gas is a theoretical gas composed of a large number of small particles that have zero volume, do not interact with each other, and are in constant random motion. The behavior of an ideal gas is described by the ideal gas law, which relates the pressure, volume, temperature, and number of moles of the gas.
The van der Waals equation can be used to figure out the pressure difference between methane and an ideal gas under these circumstances:
(P + a n² / V²)(V - n b) = n R T
where P is the pressure, n is the number of moles, V is the volume, T is the temperature in Kelvin, R is the ideal gas constant (0.08206 L·atm/K·mol), a and b are the van der Waals constants for methane.
First, we can calculate the pressure of an ideal gas under these conditions using the ideal gas law:
P = n R T / V
P = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K) / (6.00 L)
P = 299.8 atm
Next, we can use the van der Waals equation to calculate the pressure of methane under these conditions:
(P + a n² / V²)(V - n b) = n R T
(P + (2.300 L²·atm/mol²) (15.0 mol)² / (6.00 L)²) ((6.00 L) - (15.0 mol) (0.0430 L/mol)) = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K)
Simplifying the equation gives:
P + 1.319 atm = 359.6 atm
P = 358.3 atm
As a result, under these circumstances, the pressure difference between methane and an ideal gas is:
ΔP = P (methane) - P (ideal gas) = 358.3 atm - 299.8 atm = 58.5 atm.
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