x²-7x+5 in the form (x-a)²-b​

Answer:

d.

Step-by-step explanation:

Here is an answer I found on the internet (kudos to investopedia.com)

If a Z-score is 0, it indicates that the data point's score is identical to the mean score.

In other words, it's saying that a z-score of zero has a standard deviation of zero.

Answer:

[tex]g(x) = \frac{-2}{x-1}+5\\\\[/tex]

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

[tex]g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5[/tex]

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation [tex]g(x) = \frac{-2}{x-1}+5\\\\[/tex] to the form [tex]g(x) = \frac{a}{x-h}+k\\\\[/tex]

We can see that

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

Answer:

Yes they ate Equivalent

Step-by-step explanation:

Given the expression

h(x) = - 3x – 1;j(x) = – 7x + 11 ; k(x) = 21.22 – 262 – 11

H(x)•j(x) = (-3x-1)(-7x+11)

H(x)•j(x) = (-3x)(-7x)-3x(11)-1(-7x)(-1)(11)

H(x)•j(x) = 21x²-33x+7x-11

H(x)•j(x) = 21x²-26x-11

This shows that H(x)•j(x) = k(x)

Answer:

Area of the given regular pentagon is 61.5 cm².

Step-by-step explanation:

Area of a regular polygon is given by,

Area = [tex]\frac{1}{2}aP[/tex]

Here, a = Apothem of the polygon

P = Perimeter of the polygon

Apothem of the regular pentagon given as 4.1 cm.

Side of the pentagon = 6 cm

Perimeter of the pentagon = 5(6)

                                             = 30 cm

Substituting these values in the formula,

Area = [tex]\frac{1}{2}(4.1)(30)[/tex]

        = 61.5 cm²

Therefore, area of the given regular pentagon is 61.5 cm².

Answer:

865 in the workforce should be interviewed to meet your requirements

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

A pilot survey reveals that 5 of the 50 sampled hold two or more jobs.

This means that [tex]\pi = \frac{5}{50} = 0.1[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

How many in the workforce should be interviewed to meet your requirements?

Margin of error of 2%, so n for which M = 0.02.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.02 = 1.96\sqrt{\frac{0.1*0.9}{n}}[/tex]

[tex]0.02\sqrt{n} = 1.96\sqrt{0.1*0.9}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.1*0.9}}{0.02}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96\sqrt{0.1*0.9}}{0.02})^2[/tex]

[tex]n = 864.4[/tex]

Rounding up:

865 in the workforce should be interviewed to meet your requirements

Answer:

it would be 1/4(60)

Step-by-step explanation:

30 percent of 61 is 18.3 and 1/4 of 60 is 15 which is closest to 18.3

Answer:

.0421

about 4.21%

Step-by-step explanation:

[tex]\frac{{8\choose3}}{{21\choose3}}=\frac{56}{1330}=.042105263[/tex]

Answer:

If rounded to the nearest 10 bacteria, then it would be 500 bacteria.

Step-by-step explanation:

First multiply 150 by two in order to get 300, that leaves 4 hours to figure out. From there you can figure out the rest by seeing that 4 is 2/3 of 6. I converted it into the decimal number .66. Multiply 300 by .66 to get 198 and then add it to 300 to get 498. Then just round it up to the nearest 10 bacteria which leaves you with the final answer of 500 bacteria.

Answer:

19.634954085

Step-by-step explanation:

Pipe Diameter = Height of the trench

Pipe Height = Width of the trench

V = Pi*r^2*L/ Pi*r^2*h

= 22/7 x (2.5/2)^2 x 4

= 19.634954085

B is the answer.

The triangles doesnt creates a SSS,SAS,SAA, scenario.

This triangle isn't ASA because the triangles share the same side but it have different angles that include the side.

9514 1404 393

Answer:

  2

Step-by-step explanation:

Solving the given equation for y, you have ...

  2x +4y = -64

  4y = -2x -64

  y = -1/2x -16

The coefficient of x is the slope of the given line: -1/2. The slope of the perpendicular line is the opposite reciprocal of this:

  -1/(-1/2) = 2

The slope of the perpendicular line is 2.

Answer:

(a)

[tex]Q_1 = 14[/tex]

[tex]Median = 15[/tex]

[tex]Q_3 = 20[/tex]

(b) [tex]IQR = 6[/tex]

Step-by-step explanation:

Given

[tex]14\ 14\ 15\ 26\ 13\ 16\ 21\ 20\ 15\ 13[/tex]

[tex]n = 10[/tex]

Solving (a): Median and the quartiles

Start by sorting the data

[tex]Sorted: 13\ 13\ 14\ 14\ 15\ 15\ 16\ 20\ 21\ 26[/tex]

The median position is:

[tex]Median = \frac{n + 1}{2}[/tex]

[tex]Median = \frac{10 + 1}{2} = \frac{11}{2} = 5.5th[/tex]

This implies that the median is the average of the 5th and the 6th data;

So;

[tex]Median = \frac{15+15}{2} = \frac{30}{2} = 15[/tex]

Split the dataset into two halves to get the quartiles

[tex]Lower: 13\ 13\ 14\ 14\ 15\[/tex]

[tex]Upper: 15\ 16\ 20\ 21\ 26[/tex]

The quartiles are the middle items of each half.

So:

[tex]Lower: 13\ 13\ 14\ 14\ 15\[/tex]

[tex]Q_1 = 14[/tex] ---- 14 is the middle item

[tex]Upper: 15\ 16\ 20\ 21\ 26[/tex]

[tex]Q_3 = 20[/tex] ---- 20 is the middle item

Solving (b): The interquartile range (IQR)

This is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR = 20 - 14[/tex]

[tex]IQR = 6[/tex]

Solving (c): Incomplete details

Answer:

5/9

Step-by-step explanation:

Let the total number of buttons is x.

Number of red buttons:

Number of red square buttons is 0.1x

Required probability:

Answer:

9

Step-by-step explanation:

Answer:

0.52 = 52% probability that an email is detected as spam.

Step-by-step explanation:

Probability that an email is detected as spam:

99% of 50%(are spam).

5% of 100 - 50 = 50%(false positives, that is, e-mails that are not spam but are detected as spams).

What is the probability that an email is detected as spam?

[tex]p = 0.99*0.5 + 0.05*0.5 = 0.52[/tex]

0.52 = 52% probability that an email is detected as spam.

9514 1404 393

Answer:

  x = 1, x = 7

Step-by-step explanation:

You can see from the graph that the x-intercepts of f(x) are ...

  0 = f(-3)

  0 = f(3)

To find the corresponding values of x for f(x-4), we can solve ...

  0 = f(x -4)

  x -4 = -3   ⇒   x = 1

  x -4 = 3   ⇒   x = 7

The x-intercepts of the function after translation 4 units right are ...

  x = 1, x = 7

__

Your sketch will be the same curve moved 4 units to the right. (Add 4 to every x-value shown.)

Answer:

7 sq unit

Step-by-step explanation:

Area of triagle ABC = Area of rectangle mnBp - Area of trangle AmC - Are of triangle CnB - Area of triangle ABp

Area of rectangle mnBp = 5x3 = 15 sq unit

Area of trangle AmC = 4x2 /2 = 4 sq unit

Are of triangle CnB = 5x1 /2 = 2.5 sq unit

Area of triangle ABp = 3x1 /2 = 1.5 sq unit

I believe you can work out thd answer from the above

Dada una ecuación de la forma

Tenemos que:

Sabemos que:

f(x)=1+6Sen(2x+π/3)

Y podemos reescribirla como:

f(x)=6Sen(2(x+π/6))+1

Siendo:

La imagen de una función trigonométrica de esta forma es:

y ∈ [-A+D,A+D]

y ∈ [-6+1, 6+1]

y ∈ [-5,7]

La gráfica se adjunta.

(3.1) … … …

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{2x-y}{x-2y}[/tex]

Multiply the right side by x/x :

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{2-\dfrac yx}{1-\dfrac{2y}x}[/tex]

Substitute y(x) = x v(x), so that dy/dx = x dv/dx + v :

[tex]x\dfrac{\mathrm dv}{\mathrm dx} + v = \dfrac{2-v}{1-2v}[/tex]

This DE is now separable. With some simplification, you get

[tex]x\dfrac{\mathrm dv}{\mathrm dx} = \dfrac{2-2v+2v^2}{1-2v}[/tex]

[tex]\dfrac{1-2v}{2-2v+2v^2}\,\mathrm dv = \dfrac{\mathrm dx}x[/tex]

Now you're ready to integrate both sides (on the left, the denominator makes for a smooth substitution), which gives

[tex]-\dfrac12\ln\left|2v^2-2v+2\right| = \ln|x| + C[/tex]

Solve for v, then for y (or leave the solution in implicit form):

[tex]\ln\left|2v^2-2v+2\right| = -2\ln|x| + C[/tex]

[tex]\ln(2) + \ln\left|v^2-v+1\right| = \ln\left(\dfrac1{x^2}\right) + C[/tex]

[tex]\ln\left|v^2-v+1\right| = \ln\left(\dfrac1{x^2}\right) + C[/tex]

[tex]v^2-v+1 = e^{\ln\left(1/x^2\right)+C}[/tex]

[tex]v^2-v+1 = \dfrac C{x^2}[/tex]

[tex]\boxed{\left(\dfrac yx\right)^2 - \dfrac yx+1 = \dfrac C{x^2}}[/tex]

(3.2) … … …

[tex]y' + \dfrac yx = \dfrac{y^{-3/4}}{x^4}[/tex]

It may help to recognize this as a Bernoulli equation. Multiply both sides by [tex]y^{\frac34}[/tex] :

[tex]y^{3/4}y' + \dfrac{y^{7/4}}x = \dfrac1{x^4}[/tex]

Substitute [tex]z(x)=y(x)^{\frac74}[/tex], so that [tex]z' = \frac74 y^{3/4}y'[/tex]. Then you get a linear equation in z, which I write here in standard form:

[tex]\dfrac47 z' + \dfrac zx = \dfrac1{x^4} \implies z' + \dfrac7{4x}z=\dfrac7{4x^4}[/tex]

Multiply both sides by an integrating factor, [tex]x^{\frac74}[/tex], which gives

[tex]x^{7/4}z'+\dfrac74 x^{3/4}z = \dfrac74 x^{-9/4}[/tex]

and lets us condense the left side into the derivative of a product,

[tex]\left(x^{7/4}z\right)' = \dfrac74 x^{-9/4}[/tex]

Integrate both sides:

[tex]x^{7/4}z=\dfrac74\left(-\dfrac45\right) x^{-5/4}+C[/tex]

[tex]z=-\dfrac75 x^{-3} + Cx^{-7/4}[/tex]

Solve in terms of y :

[tex]y^{4/7}=-\dfrac7{5x^3} + \dfrac C{x^{7/4}}[/tex]

[tex]\boxed{y=\left(\dfrac C{x^{7/4}} - \dfrac7{5x^3}\right)^{7/4}}[/tex]

(3.3) … … …

[tex](\cos(x) - 2xy)\,\mathrm dx + \left(e^y-x^2\right)\,\mathrm dy = 0[/tex]

This DE is exact, since

[tex]\dfrac{\partial(-2xy)}{\partial y} = -2x[/tex]

[tex]\dfrac{\partial\left(e^y-x^2\right)}{\partial x} = -2x[/tex]

are the same. Then the general solution is a function f(x, y) = C, such that

[tex]\dfrac{\partial f}{\partial x}=\cos(x)-2xy[/tex]

[tex]\dfrac{\partial f}{\partial y} = e^y-x^2[/tex]

Integrating both sides of the first equation with respect to x gives

[tex]f(x,y) = \sin(x) - x^2y + g(y)[/tex]

Differentiating this result with respect to y then gives

[tex]-x^2 + \dfrac{\mathrm dg}{\mathrm dy} = e^y - x^2[/tex]

[tex]\implies\dfrac{\mathrm dg}{\mathrm dy} = e^y \implies g(y) = e^y + C[/tex]

Then the general solution is

[tex]\sin(x) - x^2y + e^y = C[/tex]

Given that y (1) = 4, we find

[tex]C = \sin(1) - 4 + e^4[/tex]

so that the particular solution is

[tex]\boxed{\sin(x) - x^2y + e^y = \sin(1) - 4 + e^4}[/tex]

Answer:

Step-by-step explanation:

I assume that you mean y = x²/(x²+1), not y = x²/x²+1.

x²+1 = 0

x² = -1

x = ±√(-1) = ±i

deleted: deleted by user

Answer:

.3

Step-by-step explanation:

let x= P(f)

.65= .55+x-.2

P(F)=.3

Answer:

x = -3 +/- square root(22)

Step-by-step explanation:

x = -b +/- square root(b^2 - 4ac) / 2a

ax^2 + bx + c = 0

these are both the quadratic formula but one is solved for the x and another for 0

a= 1

b= 6

c = -13

x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)

x = -6 +/- sqrt( 36 + 52) / 2

x= -6 +/- sqrt (88) / 2

sqrt of 88 = 2 x sqrt (22)

divide 2 on each

x= -3 +/- sqrt (22)

Answer:

Step-by-step explanation:

Answer:

16 sq units

Step-by-step explanation:

Answer:

3/8.

Step-by-step explanation:

First convert days to hours:

2 days = 2 * 24 = 48 hours.

The greatest common factor of 18 and 48 = 6 so the required fraction is

18/48

= (18/6) / (48/6)

= 3/8.

Answer:

Step-by-step explanation:

The equation in slope-intercept form:  y = mx + b

y + 2 = -2(x - 5)

y + 2 = -2x + 10              {subtract 2 from both sides

y = -2x + 8

Answer:

144 people

Step-by-step explanation:

88% = 0.88

We multiply the total number with 0.88 to see how many people went in the water:

1200(0.88) = 1056

To find the number of those who did NOT go in the water, we subtract the product from the total number:

1200 - 1056 = 144

Answer:

144 people DID NOT go in the water

Step-by-step explanation:

We know that there at 1,200 ppl at the beach and 88% of them DID go into the water.

So the percent of people that DID NOT go into the water is 12%, because

100% - 88% = 12%

12% is the same as 0.12

Multiply 0.12 and 1,200 and you get: 144

Hope it helps (●'◡'●)