You are bowling for a spare. There is just one pin left, and you make a nice play. As the 5.1 kg ball approches at a velocity of 3.40 m/s north it hits the pin! The 1.5 kg pin is sent into motion and the bowling ball continues to roll at a velocity of 0.87 m/s north. What is the final velocity of the pin?

Answer:

Velocity V = 13 m/s

Explanation:

Given:

m = 1.2 kg

p = 15.6 kg·m/s

__________

V - ?

Momentum:

p = m·V

Velocity:

V =p /m  = 15.6 / 1.2 ≈ 13 m/s

The spectrum of a very distant galaxy shows features due to carbon, silicon, and sulfur. the presence of these elements in the spectrum tells astronomers that the galaxy must have had an entire generation of stars that was born, lived, and died.

Absorption lines, not emission lines, were discovered in investigations of the Sun's spectrum (dark lines against the brighter continuum). Until Gustav Kirchhoff revealed in 1859 that the same substance can either create emission lines (when a hot gas emits its own light) or absorption lines, the precise origin of these "Fraunhofer lines," as we now refer to them, was unknown for a long time (when a light from a brighter, and usually hotter, source is shone through it). With that finding, spectroscopy became a viable method for analyzing the chemical makeup of stars.

Chemical elements can be found in other things besides stars. We can search for the signatures of elements in any spectrum from any object. Nebula and supernova leftovers are among.

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According to Newton's law of motion, the direction of motion of an object depends on the direction of the applied force.

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force and it will move in the direction of the applied force.

The Newton's first law of motion is also called the law of inertia because it depends on the mass of the object. The more massive an object is, the more inertia the object will possess and vice versa.

Also, the Newton's second law of motion states that the force acting on an object is directly proportional to the product of mass and acceleration of the object.

Mathematically, Newton's second law of motion is given as;

F = ma

F = mv/t

Ft = mv

This law (Newton's second law of motion) is also states that the force applied on an object directly proportional to the rate of change of momentum of the object.

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The size of the shadow hangs on the distance of the source of light and on the angle at which the light rays drop on the object.

A person or object chunks more light when the sun is low in the sky. More brick light makes shadows longer. Less light is wad when the sun is high in the sky. This makes shadows shorter. The angle at which light hit an object affects the size and shape of its shadow. Shadows are longer when the light source is at a low angle (side on) and squat when the light source is at a higher angle (overhead). find design when investigating how shadows change size and how a shadow is formed understand the role of light-position

So we can conclude that The Sun's position in the sky influences the length of the shadow. When the Sun is low on the horizon, the shadows are long.

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Answer: 3/4 net decline
(three quarters)

Explanation:

Option A,C  It decrease the strength of the magnet and also decrease the number of coils in the solenoid.

A device called a solenoid is made up of a casing, a coil of wire, and a moving plunger (armature). A magnetic field develops around the coil when an electrical current is injected, drawing the plunger in. A solenoid, put more plainly, changes electrical energy into mechanical work.

Copper wire is twisted tightly in a coil that has several turns. The creation of a powerful magnetic field or flux occurs when an electrical current runs through this wire.

The coil is enclosed in a housing, which is often composed of steel or iron, which concentrates the magnetic field it produces.

The magnetic field's concentration, which provides the mechanical force needed to perform the action, draws the plunger to the stop.

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A decrease in velocity is referred to as deceleration. If car is moving at 30 m/s and stop in 50 m .The value of deceleration is 11.56 ms−2.

While acceleration is motion in which an object's speed varies every second, deceleration is motion that causes an object to slow down.

We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed. For instance, when we apply the brakes while driving, we benefit from the vehicle's ability to decelerate and slow down.

The Deceleration Formula is the final velocity minus the initial velocity, with a negative sign in the result because the velocity is decreasing, if starting velocity, final velocity, and time taken are given.

velocity of car = 30 m/s

car need to stop in 50m

Deceleration a = v^2 –  u^2 / 2s

                          = 0^2 - 50^2 / 2*30

                          = 11.56

Deceleration of the care = 11.56 ms−2

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For general projectile motion with no air resistance, the horizontal component of a projectile's acceleration is: E. is always zero.

Projectile motion can be defined as a form of motion which is experienced by a physical object that is projected near planet Earth's surface while moving along a parabolic (u-shaped curve) path, and under the influence of a gravitational force only.

Based on scientific research and records, we can infer and logically deduce that the initial horizontal velocity of an object undergoing a projectile motion is always equal to its final horizontal velocity.

Additionally, the horizontal component of the acceleration of a physical object that is undergoing a projectile motion is always equal to zero (0) meter per seconds square because it is experiencing a constant velocity.

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Complete Question:

For general projectile motion with no air resistance, the horizontal component of a projectile's acceleration

A. remains a non-zero constant

B. continuously decreases

C. continuously increases

D. first decreases and then increases

E. is always zero

If two vehicles approach an uncontrolled intersection at about the same time the driver of the vehicle on the left shall yield the right-of-way to the vehicle on the right.

A driver proceeding through an uncontrolled intersection must yield to a vehicle to their right, as that vehicle has the right of way even though the two vehicles arrived at the same time.

At an uncontrolled intersection, the Vehicle A driver must yield to traffic on its right and proceed with caution only when it is safe to do so. Therefore, they would be found 100% responsible.

Therefore when two vehicles approach an uncontrolled intersection on the same side then the vehicle on the left shall yield the right-of-way to the vehicle on the right.

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The final angular velocity of the merry-go-round is 8 rad/s.

The radius of the Merry-go-round is 1.5 m and it is spinning with a speed of 2rad/s the girl pushes on it for 5 revolutions which applies and acceleration of 3rad/s².

The final angular velocity of the merry-go-round can be given by the equation,

W'² - W² = 2AS

Where,

W' is the final angular velocity,

W is the initial angular velocity,

A is the angular acceleration,

S is the angular displacement which is 10 rad in this case.

Putting values,

W'² - (2)² = 2(10)(3)

W' = 8rad/s.

So, the final angular velocity is 8rad/s.

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Answer:

3 m/s^2

Explanation:

Acceleration = change in speed  /  change i time

                      = 15 m/s  / 5 s =  3 m/s^2

The rock's impact velocity with the river is - 98.1 m/s. At the time of impact, the  rock was traveling at a speed of 42.14 m/s.

G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity).

In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.

The rock was traveling at 42.14 m/s when it impacted the ocean.

Then V = -9.81 * 10 = -98.1.

There for,

The rock's impact velocity with the river is -98.1m/s .

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The magnitudes and directions of the velocities of the two marbles after the collision is: v1f is left and v2f is right.

The initial marble weighs m1 = 0.015 kg.

Second marble's mass is m2=0.045kg.

The first marble's initial velocity is v1i=0.40m/8 before to contact.

The second marble's initial velocity is v2i=0m/8 prior to impact.

After the impact, the first marble's final speed is v1f.

Following the collision, the initial marble's final velocity is v2f.

If the collision is elastic, the kinetic energy is preserved.

We'll write 1/2 m1 for KE = 1/2 mv2 (v1i)

2 + 1/2 m2(vi) (vi)

2 = 1/2 m1(v1f)2 + 1/2 m2 (v2f) (v2f)

2.

Using this equation, we can establish a new relationship between velocities and determine each marble's post-collision velocity:

v1f=(m1-m2)/(m1+m2)

v1\sv1f=(0.015kg-0.045kg)/(0.015kg+0.045kg)

0.40m/s\s=-0.20m/s

First marble is moving leftward at 0.20 m/s, as indicated by the negative sign.

Find the second marble's final velocity.

​v2f=2m1v1/(m1+m2)\s

v2f=2⋅0.015kg⋅0.40m/s/(0.015kg+0.045kg)\s

v2f=0.20

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Water's high specific heat capacity explains why why water bonds with other molecules.

The correct answer choice is option a.

Water has the ability to easily attract other molecules simply because of the fact its hydrogen and oxygen components is made up of positive and negative ions respectively.

Technically, the bonds in hydrogen possess a form of electrostatic force which makes it very possible for water to bond with other molecules with its high specific heat capacity.

So therefore, we can now confirm and deduce that from the simple note given above that the hydrogen bonds presence in water molecule makes it easy for water to combine with other molecules.

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The period of the  object undergoing simple harmonic motion   is

simple harmonic motion sometime shortened as SHM may be a sort of periodic movement where the restoring drive on the moving object is straightforwardly relative to the magnitude of the displacement of the object and acts towards the object's equilibrium position. It comes about in an oscillation that proceeds inconclusively, on the off chance that uninhibited by friction or any other dissemination of energy.

we are given the time taken to complete the distance covered between two  zero velocity  points apart from the distance of   41.6 cm which is  0.12 so the period  will be  = 2T = 2 * 0.12 = 0.24 s

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The magnitude of its acceleration is a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] )

The length of the vector is all there is to an acceleration's magnitude. To put it another way, writing the magnitude of acceleration indicates how quickly velocity varies. In the standard international (SI) system, the acceleration is measured in units of meters per second square.

Let T be the rope's tension, assuming it has no mass.

T =( 2[tex]W_{A}[/tex])a/g ------- 1

([tex]W_{B}[/tex]) - T = ([tex]W_{B}\\[/tex])a/g ------- 2

Add 1 and 2

[tex]W_{B}[/tex] =(a/g)( 2[tex]W_{A}[/tex]+ [tex]W_{B}[/tex])

a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] ).

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The efficiency of the machine is ξ= 50%.

Given - 20 joules and 30 joules are input and output work of the system respectively.

To find the efficiency of the system.

principle ;- Efficiency represents the capability of a system to do work .

Mathematically , efficiency has an equation that relates the input and output work and accurately provides the result.

Formula  -   ξ= οₙ/Iₙ x 100

οₙ = output work , Iₙ= input work

Calculations :-  ξ= { 10/20 }x 100

ξ= 50%

Result- The Efficiency of the machine is 50%.

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The  functional groups that are represented in this molecular structure are; a methyl group, a hydroxyl group, and a carboxyl group

We know that the functional group would be defined as that atom, or a group of atoms or even a bond that is the major point where a chemical reaction occurs among the members of a particular hom----ologous series. Note that the hom----ologous series is a family of compounds that differ from each other by chain length only.

Now we have to look at the compound and of course the attachments to the compound would tell us how many of the functional groups that we do have in the molecule and we can take a cursory look at the image attached for this detail.

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Using the concepts of angular displacement, we got that 0.241 rad/s is the angular velocity of track star which runs a 230 m race on a 230 m circular track in 26 s.

We know very well that angular velocity is given by change in angular displacement per unit time.

Here, we can see that a truck distance covered and length of circular track is same.

Perimeter of circular track is equal to the distance covered by the truck.

It means, truck rounds a full circle in 26 sec

So, the angle covered by truck is 360° or 2π radian.

Initially angle is 0 radian and final angle is 2π radian

Therefore, angular velocity =(θ[tex]_f_i_n_a_l[/tex] -θ[tex]_i_n_i_t_i_a_l[/tex])/time

                               => ω=(2π-0)/26

                               =>w=(2π/26)

                                =>w=(2×3.14)/26

                                =>ω=6.28/26

                                =>w=0.241 rad/sec.

Hence, when a track star runs a 230 m race on a 230 m circular track in 26 s, the angular velocity assuming a constant speed is 0.241 rad/sec.

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Distance x force equals work done. When this occurs, the amount of work done is measured in joules (J), the amount of force is recorded in newtons (N), and the distance travelled along the force's path is measured in meters (m).

The SI unit of labor is called a joule (J).

The following questions have the following answers:

1) In the picture below, F1 acts downward and F2 acts upward.

2) Moments on the LHS equal F1d1 and on the RHS, F2d2.

Moment in LHS= RHS F1d1= F2d2 F1= (20Kg 10)/200 N Consequently, 200 N0.8= F20.95 160= 0.95 F2 = 168.42 N

The net force has a magnitude of 168.42 N and is directed upward.

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(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s​.

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

t =  √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

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The correct expression for the acceleration magnitude {a}aa of the stunt woman from from the above given task is: m(a + g).

The correct option is b.

The complete image is attached.

It follows that one of the Newton law motion describes a system that in every action, there is equal and opposite reaction. In order words, no reaction will occur without an action.

That being said, the stunt woman from the above given task possesses a mass m which will ultimately be falling under acceleration due to gravity. This means that the acceleration, a by the process equals gravitational acceleration, g under standard conditions. It is on this premise that her acceleration magnitude {a}aa is given by m(a + g).

In conclusion, we now know from the detailed explanation and image above that the magnitude of the woman is m(a + g).

Complete question:

A stunt woman of mass m falls into a net during the filming of an action movie. She experiences a normal force magnitude {F_n}F

n

F, start subscript, n, end subscript while touching the net.

Which of the following statements is correct for the acceleration magnitude {a}aa of the stunt woman?

Consider upward as the positive direction

a. m(a - g).

b. m(a + g).

c. m(a + g + m)

d. None of the above.

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The acceleration due to gravity on the surface of planet Pluto is 0.62 m/s²

From the Newton's law of universal gravity, the acceleration due to gravity is given by:

g = GM / R²

Where

With the above formula, we can obtain the acceleration due to gravity. Details below

g = GM / R²

g = (6.67×10¯¹¹ × 1.2×10²²) / (1.14×10⁶)²

g = 0.62 m/s²

Thus, the acceleration due to gravity is 0.62 m/s²

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Yes it will affect the number of magnetic field lines travelling through the coil changes when the magnet is moved inside a coil of wire.

How is the first law of Faraday formulated?

The first and second laws of electrolysis by Faraday, which are as follows, govern the electrolysis process: The charge (mQ m Q) has a direct relationship with the mass of material liberated (or deposited).

According to Faraday, the variation in the number of field lines traversing the wire coil is what creates the induced electromagnetic field (EMF) in the loop. The rate of change in the number of magnetic field lines that pass through the loop, in particular, is what determines the induced emf. The term "magnetic flux" is similar to the term "electric flux," and it refers to the number of field lines that are passing through a surface.

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Saturn is undergoing an apparent retrograde movement period as the Earth moves closer to Saturn in its orbit and then both planets are located on the side of the Sun. Stars that are nearer to us will exhibit higher parallax, similar to how it occurs on Earth.

The star parallax of the Earth is quite modest, barely 0.03 seconds of arc. It would be difficult to see against the backdrop of stars, even with a good telescope.

The angle between the Earth's place at a single time of year and the Earth 6 months later, as determined from a nearby star, is known as the parallax angle. This angle is used by astronomers to calculate how far away that star is from Earth.

We may calculate the distance to a nearby planet using the method described before, s. Now, measuring from an observation point O, we determine the angle the planet occupies, which is. Therefore, P1P2=d, where d is the planet's diameter. As a result, we may use the parallax method to calculate the radius of a neighboring planet.

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1)The current flowing when:

(A) 75 m C pass a point in I min will be 1.25 *  [tex]10^{-3}[/tex] A

B) 0.5 GC pass a point in 2 hours will be  0.5 * [tex]10^{9}[/tex] C

C)  2.0 MC pass a point in 1000 hours will be 2 * [tex]10^{6}[/tex] C

The charge flow when the current flow is:

(A) 6.0 A for 5 min will be 1800 C

B) 250 mA for 4 hours will be 3600 C

C) 2.5 KA for 50 s will be 125 *  [tex]10^{3}[/tex] C

3A)  [tex]10^{9}[/tex] seconds will it take for pass 25 MC at a current of 25 mA

B) 4 seconds will it take for pass 48 C at a current of 12 A

C) 90 seconds will it take for pass 360 C at a current of 4.0 A

4) A) Potential difference  across the resistor will be  0.4 V

B) Total charge flow in 3 minutes will be  18 C

1 )

current = charge / time

A) 75 m C = 75 * [tex]10^{-3}[/tex] C

current = 75 * [tex]10^{-3}[/tex] C / 60 = 1.25 *  [tex]10^{-3}[/tex] A

B ) 0.5 GC = 0.5 * [tex]10^{9}[/tex] C

current =  0.5 * [tex]10^{9}[/tex] C  / 216000 = 0.0023 * [tex]10^{5}[/tex] =2.3 * [tex]10^{2}[/tex] A

C) 2.0 MC  = 2 * [tex]10^{6}[/tex] C

current =  2 * [tex]10^{6}[/tex]  / 36 * [tex]10^{5}[/tex] = 0.0556 * 10 A

2) charge = current * time

A) Q 1 = 6 * 300 = 1800 C

B) Q2 = 250 * [tex]10^{-3}[/tex] * 14400 = 3600 C

C) Q3 = 2.5 * [tex]10^{3}[/tex] C * 50 = 125 *  [tex]10^{3}[/tex] C

3 )

time = charge / current

A) T1 = 25 * [tex]10^{6}[/tex] / 25 * [tex]10^{-3}[/tex] = [tex]10^{9}[/tex] seconds

B) T2 = 48 / 12 = 4 seconds

C) T3 = 360 / 4 = 90 seconds

4)

a) V = IR ( using ohm's law )

       = 0.1 * 4 = 0.4 V

b) charge = current * time

                = 0.1 * 180 = 18 C

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The vertical height of the building is determined as 44.1 m.

The height of the building is calculated by applying the following kinematic equation as shown below.

h = vyt + ¹/₂gt²

where;

h = (v sinθ)t + ¹/₂gt²

where

The given parameters include the following;

h = (0 x sin25)(3)  +  ¹/₂(9.8)(3²)

h = 44.1 m

Thus, the height of the building is equal to the vertical distance travelled by the brick thrown at the given initial velocity.

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7 bright fringes lie between the first and second minima of the diffraction envelope.

Diffraction is defined because of the interference or bending of waves around the corners of an obstacle or via an aperture into the vicinity of the geometrical shadow of the impediment/aperture. The diffracting object or aperture correctly becomes a secondary source of the propagating wave.

Refraction is the alternate in direction of waves that takes place whilst waves journey from one medium to another. Refraction is always accompanied by means of a wavelength and speed alternate. Diffraction is the bending of waves around barriers and openings. the amount of diffraction increases with increasing wavelength.

Calculation:-

Here d = 15 a/2(since there are 15 bright fringes ).

Then for the first minimum which occurs at an angle1

then a sin? 1 =? (m=1)

For the second minimum which occurs at an angle= of 2

then a sin?2 = 2? (m=2)

then we calculate the values of m for which

1 < ?< ?2 for sin?1 < sin?< sin?2 ? < 2m?/15 <2?

that is 1<2m/15 <2

Hence, there are 7 bright fringes.

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Coaxial cable may experience unpleasant interference from electrical wires. Therefore, even if the cables are divided by wood or other building materials, keep coax wires at least 6 inches away from electrical cables.

A form of copper cable known as coaxial cable is designed to prevent signal interference by using a metal shield and other parts. It is generally utilized by cable TV providers to link their satellite antenna facilities to client residences and establishments.

The same coaxial cable network that delivers cable television and internet to your house is used for both services. First, your internet service provider sends a data signal to your modem via the coaxial cable, also known as coax, inside your home.

You will need a coaxial cable connected to your TV if you want to watch live TV through a provider like Free view or Free sat.

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