you are looking down at a loop and there is a magnet below the loop with the north pole facing you. as the magnet falls away from you, which way does the induced current flow in the loop?

Magnitude of the average emf induced in the loop is 0.20 mV.

The magnitude of average emf induced in the loop is calculated as follows are;

emf = NA(B₁ - B₂)/t

by using the formula of the induced emf we calclate the average emf.

A = area of the loop

N =number of turns

B1 = initial magnetic field

B2 = final magnetic field

t=time

A = πr² = π(0.04)²

= 5.027 x 10⁻³ m²

emf = (1)(5.027 x 10⁻³)(0.06 - 0.04)/0.5

emf = 2.01 x 10⁻⁴ V

emf = 0.201 mV

Thus,  magnitude of the average emf is induced in the loop = 0.20 mV.

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The normal force applied by the table onto the gingerbread man is 1.96 N.

The normal force is a type of force that is felt when a surface pushes against an object that is placed on that surface.

In other words, a normal force is a type of force directed opposite to the weight of an object. The normal force of an object is always directed upwards while the weight of the object is directed downwards.

According to Newton's third law of motion, the magnitude of the normal force of an object acting upwards is always equal to the weight of the object acting downwards.

The normal force applied by the table onto the gingerbread man is calculated as follows;

Fn = mg

where;

Fn = 0.2 kg  x  9.8 m/s²

Fn = 1.96 N

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In both cases, y and x components are solved and added. The resulting speed hypotenuse is then computed and its direction calculated.

Airplane:

Ф = 270 - 265 = 5°

Hypotenuse, h = 400 mph

y component = 400 Sin Ф = 400 Sin 5 = 36.61 mph

x component = 400 Cos Ф = 400 Cos 5 = 418.40 mph

Wind

Ф = 315 -210 = 60°

Hypotenuse, h = 30 mph

y component = 30 Sin 60 = 25.98 mph

x component = 30 Cos 60 = 15 mph

Total y = 36.61+25.98 = 62.59 mph

Total x = 418.40+15 = 433.40 mph

Resulting speed of airplane = Sqrt (y^2+x^2) = Sqrt (62.59^2+433.40^2) = 437.9 mph

Direction = 270 -[tan^-1 (y/x)] = 270 -[tan^-1(62.59/433.40)] = 261.78°

Therefore, the resulting speed is 437.9 mph in the direction of 261.78°

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Circuit you ultimately want to measure the power dissipation of the 2.0 is The sum of the voltage drops across each resistor is zero.

Apply the Kirchhoff’s Voltage law to the above two loops.

For Loop 1

2 - i1 + 2i2 - 4 - i1 = 0

i2 - i1 = 2

For loop 2

4  - 2i2 + i3 - 4 + i3 = 0

i3 = i2

The sum of the voltage drops across each resistor is zero. The sign of the higher potential is taken as positive and the sign of the lower potential is taken as negative.

The sum of the voltage drops across each resistor is zero. The sign of the higher potential is taken as positive and the sign of the lower potential is taken as negative.

The voltage drop in an electrical circuit is the reduction in electrical potential along the current's course. Voltage drops across conductors, contacts, and connectors are undesirable because they result in energy loss from the source's internal resistance, conductors, and contacts. The amount of power available to be transformed in that load to another useable form of energy is inversely correlated with the voltage drop across the electrical load.

For instance, an electric space heater might have a resistance of ten ohms, whereas the wires that power it might have a resistance of only two ohms, or about 2% of the circuit's total resistance. This indicates that 2% or more of the supplied voltage is wasted in the wire itself. Voltage drops could be too great.

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The momentum of the probe Pf  = + 5.1 x [tex]10^{7 }[/tex] kg m/s.

Find the attachment answer

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substitute an equivalent resultant force and a couple of moment acting at point A. Allow w1 to be 5.70 kN/m, w2 to be 4.10 kN/m, and a to be 3.85 m. the pair moment is 77.08 kN m, and the resulting force is FR=4.8125 kN.

The force delivered by the distributed loads is given as,

F₁=[tex]\frac{1}{2}[/tex] w₁a

  =[tex]\frac{1}{2}[/tex](5.70kN/m)(3.85m)

   =10.9725 kN

F₂=w₂a

   =(4.10 kN/m)(3.85m)

   =15.785 kN

The resultant force is given as,

[tex]F_{R}[/tex]= -F₁+F₂

    = -10.9725 kN+15.785 kN

    =4.8125kN

The resultant moment exerted on the beam is calculated  as,

M=-F₁(a/3)+F₂(a+(a/2))

M=-(10.9725 kN)(3.85m/3)+15.785 kN(3.85+(3.85/2))

   = -14.081 kN m+91.158 kN m

   =77.08 kN m

In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force (1687). Newton's first law states that a body at rest or traveling at a constant speed in a straight line will stay in that state unless a force is applied to it. According to the second law, when an external force acts on a body, the body accelerates (changes velocity) in the force's direction.

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Answer:

a=2 m/s²

Explanation:

v=u+at

25=15 +5a

5a=10

a=2 m/s²

Wavelength of 594.6 nm of visible light would have a minimum at the same location.

For constructive interference

d sinQ=ml=2x436nm=892nm

For destructive interference of the other light, we have

d sinQ=(m’+1/2)l

where,  d = distance between slits

            Q = angle formed

            m = order of bright fringe

            m' = order of dark fringe

            I = wavelength

When the two angle are equal, then

892nm=(m’+1/2)l

l=1784 nm for m’=0

l=613 nm for m’=1

l=368 nm for m’=2

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The gravitational torque on your arm in this position around the shoulder joint  is  mgL/2.

The force that can cause an object to rotate along an axis is measured as torque. An object acquires angular acceleration due to torque.

A vector quantity is a torque. The force acting on the axis determines the direction of the torque vector.

Let the mass of your arm = m.

Length of your arm = L.

If the hand has uniform mass, the position of its center of gravity during it is horizontal is = L/2.

Hence, the torque on your arm in this position around the shoulder joint be =

weight of your hand × the position of its center of gravity with respect to shoulder

= mgL/2

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The correct response is 1.428 velocity through orifice v2 = 2 gh v2 = 2 * 9.8 * 17 v = 18.254. initially

The amount of time it takes to get to the ground is initially

t=g 2 = 9.8 2100 =4.51s.

b) The horizontal distance before touching the ground, x=ut=204.5=90m c) The constant horizontal velocity over the frequency,

At "A," V x = 20 m/s, and V y = u+at= 0 + 9.8 4.5 = 44.1 m/s

Final velocity is equal to v r= (4.41) + (20) 2 =48.42 m/s tan, which is equal to x V y= 204.41 =2.205 =tan 1.428.

Water is inside a cylinder that is exposed to the atmosphere and is standing upright on a table. Although the side of the cylinder has three holes Speed of outflow at point D is equal to (2gD) length of time it takes to get there

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B. Zero, The work done on the object by the normal force of the surface is zero. work done is measured in joules (J) and force is measured in newtons (N).

The body is inclined at θ=30°,

s=10m, m=5kg

Work done by the object = FsCosθ

but the surface is a friction-less, this means coefficient of friction =0

F=μR

F=0*R

F=0

W=FScosθ

W=0*SCosθ

Work done =0

There is connection between work and energy, in a sense that when there is a net force doing work on an object, the object's kinetic energy will change by an amount equal to the work done.

If force is applied on a system and the it experiences a displacement then the work is said to be done on the system. If a system applies a force on something and causes displacement then the work is said to be done by the system.

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Answer:  3275.7 m

Explanation:

displacement in x direction:  11200 - 8400 = 2800

displacement in y direction:  1700

displacement A - B:

[tex]\sqrt{2800^{2} + 1700^{2} }[/tex] = 3275.7

If a flash of lightning, and hear the thunder 5.9 seconds later, the distance of the lightning strike is 1 mile.

A mile is longer than a kilometer. To find out whether a kilometer or a mile is longer, convert them to feet. One mile is 5,280 feet. One kilometer is 3,280.84 feet.

Most roads have speed limits between 25 and 60 mph, so you can expect to drive one mile in 1 to 2.5 minutes. Whatever you do, don't let the math get you off the road! And don't forget that it's important to properly insure your vehicle.

The 10,000 steps are about 5 miles or 1 hour and 40 minutes, depending on stride length and walking speed. But that doesn't mean you have to do it all in one walk.

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Answer: A. acceleration

Explanation: Acceleration is the term that is equal to velocity change per second. Acceleration refers to the rate at which an object's velocity changes over time. It measures how quickly an object's speed or direction changes. When an object speeds up, slows down, or changes direction, its velocity is changing, and this change per unit of time is known as acceleration.

To calculate acceleration, you divide the change in velocity by the time it takes for that change to occur. The unit of acceleration is meters per second squared (m/s²) in the metric system. For example, if an object's velocity changes from 10 m/s to 20 m/s in 2 seconds, the acceleration would be (20 m/s - 10 m/s) / 2 s = 5 m/s².

The maximum velocity attained by the mass is given by the equation v(max) is  0.80 m/s

Step 1: Calculate the spring constant

The frequency of a mass on a spring is given by the equation:

f = (1/2π)√(k/m)

where f is the frequency, k is the spring constant, and m is the mass.

Given:

f = 1.27 Hz

x = 2.0 cm = 0.02 m

Therefore:

k = (2πf)2m

k = (2π*1.27 Hz)2*0.02 m

k = 2.02 N/m

Step 2: Calculate the maximum velocity

The maximum velocity of an oscillating mass on a spring is given by the equation:

vmax = (2πfx)√(k/m)

where vmax is the maximum velocity, f is the frequency, x is the displacement, k is the spring constant, and m is the mass.

Given:

f = 1.27 Hz

x = 0.02 m

k = 2.02 N/m

Therefore:

vmax = (2π*1.27 Hz*0.02 m)√(2.02 N/m/0.02 m)

vmax = 0.80 m/s

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Proper order is 1) action potential reaches the synaptic knob, 2) voltage gated calcium channels open, 3) calcium enters the synaptic knob, 4) calcium trigger exocytosis of vesicles, 5) neurotransmitter diffusion across synaptic cleft 6) neurotransmitter binds to postsynaptic receptors.

The "pressure" that drives electricity is known as voltage. Higher voltages cause more electricity to flow to an electronic equipment. The voltage is measured in units called volts (V), and it is symbolized by this unit. The circuitry in electronic devices can be harmed by high voltages because they are made to function at specified voltages.

In contrast, a voltage that is too low can also lead to problems since it disables circuits and renders the devices that are constructed around them inoperable. In order to manage electronic devices properly and locate the root causes of troubles when they arise, one needs to have a basic understanding of voltage and how to resolve related problems.

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It is True since mass m is an inertial mass.

Mass at rest. This is mostly explained by Newton's law, the all-too-famous formula F = ma, which asserts that an object will accelerate proportionately to the force F applied to it, with the mass of the object serving as the constant of proportion. In very simple terms, you may calculate the inertial mass by applying a force of F Newtons to an object, measuring the acceleration in m/s2, and then multiplying that value by the acceleration to get the inertial mass m in kilograms. It's also intriguing to note that there is no physical distinction between inertial mass and gravitational mass. The values have been verified by numerous trials, and the results have consistently agreed with the margin of error for the experiments 

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Young's experiment is used to find the distance of n'th number dark fringe from the central fringe of screen.

(a)The distance on the screen from the center of the central maximum to the first minimum is 0.88 mm.

(b) The distance on the screen from the center of the central maximum to the point where the intensity has fallen to [tex]$\frac{I_0}{2}$[/tex] is [tex]$0.44 \mathrm{~mm}$[/tex].

What is young's experiment?

Young's experiment is used to find the distance of n'th number dark fringe from the central fringe of screen.

It can be find out with the following formula given as,

[tex]$$y_n=\frac{(2 n-1) D \lambda}{2 d}$$[/tex]

Here, [tex]$\lambda$[/tex] is the wavelength of the light and D is the distance of the screen to the slits.

- (a)The distance on the screen from the center of the central maximum to the first minimum-

Use the above formula for the first minimum as,

[tex]$$\begin{aligned}y_1 & =\frac{(2(1)-1) 0.7 \times 660 \times 10^{-9}}{2 \times 0.26 \times 10^{-3}} \\y_1 & =0.88 \mathrm{~mm}\end{aligned}$$[/tex]

Thus, the distance on the screen from the center of the central maximum to the first minimum is [tex]$0.88 \mathrm{~mm}$[/tex].

(b) The distance on the screen from the center of the central maximum to the point where the intensity has fallen to [tex]$\frac{I_0}{2}$[/tex] -

As the intensity has fallen to the [tex]$I_0 / 2$[/tex], thus the value of path difference will become equal to the [tex]$\pi / 2$[/tex].

The above formula for this path difference can be written as,

[tex]$$\begin{aligned}y & =\frac{(2 \times 1) D}{2 d} \times \frac{\lambda}{2 \pi} \times \frac{\pi}{2} \\y & =\frac{(0.7}{0.260 \times 10^{-3}} \times \frac{660 \times 10^{-9}}{2 \pi} \times \frac{\pi}{2} \\y & =0.44 \mathrm{~nm}\end{aligned}$$[/tex]

Thus, the distance on the screen from the center of the central maximum [tex]$0.44 \mathrm{~mm}$[/tex].

Hence,

- (a)The distance on the screen from the center of the central maximum to the first minimum is [tex]$0.88 \mathrm{~mm}$[/tex].

- (b) The distance on the screen from the center of the central maximum to the point where the intensity has fallen to [tex]$\frac{I_0}{2}$[/tex] is [tex]$\mathbf{0 . 4 4} \mathrm{mm}$[/tex].

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The minimum speed that the bucket must swing so that the bucket does not come crashing down at the top of its loop is v = [tex]\sqrt{rg}[/tex]

Fc = Fg

mac = mg

ac = g

ac = v^2/r

v^2/r = g

The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has magnitude but no direction as a unit of measurement.

Speed is the rate at which anything moves over a predetermined distance.

an object that moves quickly and with high speed, covering a lot of ground in a short time. A slow-moving object with a low speed, on the other hand, covers a comparatively short distance in the same amount of time. An item with zero speed is stationary.

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Net external force in the x- direction=--140.8 N

We are given that

F1= 78.4 N(right)

F2= 229.2 N(left)

F3= 345.9 N(upward)

F4=  248.9N (downward)

We have to find the net external force in the x- direction.

Net external force along x- direction=Fx=F1-F2

229.2-78.4=-140.8 N

Net external force along y- direction=Fy=F3-F4

=345.9-248.9

=97 N

Hence,  net external force in the x- direction=--140.8 N

Consider the scenario when a body is simultaneously being dragged down by its weight and lifted by a lifting force. The vector sum of the lifting force and the weight represents the net force applied on that object.

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The amount of energy that is required was found to be 4.184 J

define energy ?

In physics, energy (from Ancient Greek: v, enérgeia, "activity") is a quantitative quality that is transmitted to a body or a physical system and is observable in the execution of work as well as in the form of heat and light. The law of conservation of energy holds that energy can be transformed in form but cannot be generated or destroyed. The joule is the International System of Units (SI) unit of measurement for energy (J).

The kinetic energy of a moving object, the potential energy stored by an object (for example, due to its position in a field), the elastic energy stored in a solid object, chemical energy associated with chemical reactions, radiant energy carried by electromagnetic radiation, and internal energy contained within a thermodynamic system are all examples of common forms of energy. All living creatures continually absorb and expel energy.

So, to do that, we'll set up our equation so that q equals 40.7, and then the specific heat of water is 4.184 joules per gramme, times degrees celsius, and since I'm keeping this in grammes, this is the correct value of c, and then our final temperature minus our initial temperature, so 70 degrees celsius minus negative 10 degrees celsius, and that gives us 40.7 times 4.184 times 80, which gives us the value of q

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A circular loop carrying a current is placed in a given magnetic field and if the magnetic moment of the loop is 0.75 am2, then the area of the coil is calculated as b) 1.5 m².

In electromagnetism, magnetic moment is the magnetic strength and orientation of a magnet  that produces a magnetic field. Examples of objects that have magnetic moments are loops of electric current, permanent magnets, elementary particles and others.

As we know that, M = NIA

Where;  M -- magnetic moment, I -- current and A -- area.

Given M= 0.75, I= 0.5

A= M/NI

= 0.75/0.5

Area of the coil=1.5 m².

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The electric flux through each gaussian was said to be q

what is electric flux ?

The electric flux is the amount of electric field that flows through a covered surface. According to Gauss's law, which is given by the equation, the electric flux through a surface is proportional to the charge inside the surface.

Фe=∅E x dA

=Qin/∈

The electrical flux is determined by the charges inside the closed path. Any flux caused by charges outside of the closed surface is zero.

Concerning the enclosed surface,

step 1

∅a=-q/∈o

q1+q3=-q------1

∅b = 3q/∈o

q1+q2=3q------2

∅c = -2q/∈o

q3+q2= -2q-------3

step 2

q1=3q-q2

q1+q3=-q

3q-q2+q3=-q

q3=q2=-4q-------4

eq3+eq4

q3+q2=-2q + q3-q2=-4q

2q3=-6q

q3=3q

step 3

q1=-q-q3

=-q-(-3q)

=2q

use this value in eq 2

q2=3q-q1

=3q-2q

=q

the electric flux through each was said to be q

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Technician A is right. A pressure plate with a diaphragm requires less pedal effort to operate than one with a coil spring.

A diaphragm clutch is a type of car clutch that uses a diaphragm spring to engage and disengage the clutch.

The structure of this clutch is very similar to that of a single plate clutch, with the exception of using Belleville springs instead of coil springs in the diaphragm. Because there are no release levers and the spring has multi-lever functionality, this clutch has more advantages. The spring's pressure is constantly changing. It rises until the spring is flat, at which point it begins to descend. Unlike a coil spring-type clutch, the driver of this clutch does not need to apply as much pedal pressure to keep the clutch from engaging.

Thus clutch plate pushes the friction plate onto the flywheel. The diaphragm spring is located on the plate on one side of the pressure.

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The distance to the object creating the echo is 2,454.6 meters.

Assuming the submarine is in saltwater, the speed of sound in seawater is approximately 1,484 meters per second.

The distance to the object creating the echo can be calculated by multiplying the speed of sound by the time it took for the echo to return to the submarine:

Distance = Speed x Time

Distance = 1,484 m/s x 1.65 s

Distance = 2,454.6 meters

Therefore, the distance to the object creating the echo is 2,454.6 meters.

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The plantaris works by flexing the knee and ankle joints sporadically. about the foot's position, the central nervous system.

There are numerous ways in which the plantaris tendon might hurt. First, when the plantaris tendon is overworked or overloaded, it might experience tendonitis or tendinopathy. Second, it's hypothesized that the plantaris can chafe and compress on the Achilles tendon, injuring it.

Function. The plantaris functions to plantar flex the knee joint and ankle joint sporadically. The central nervous system may receive proprioceptive feedback information about the location of the foot from the plantaris muscle.

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The speed of water at the end of spillway is 58.5 (m/s)

Calculation:

According to the Bernoulli equation:

P/x + v^2/2 + gz = constant

The initial vertical height of 175 m

However, the atmospheric pressure and density are essentially the same at the peak and bottom of the falls. Therefore,

v^2/2 + gz = constant , so:

v_bottom^2/ 2 = v_top^2/2 + gz, or:

v_bottom = √(v_top^2 + 2gz) = √(v_top^2 + 2g*175)

If v_top ≈ 0, then:

v_bottom = √(2gz) = √(2*9.8*175) = 58.5  (m/s)

What is the flow rate of water?

The amount of water that might theoretically flow out of your kitchen faucet or bathtub each minute is measured by your water flow rate, sometimes referred to as the gallons per minute (GPM). the flow rate is affected by a number of variables, but the household size is the most important one.

Therefore,  the highest possible speed of the water at the end of the spillway is 58.5m/s

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When two bumper cars collide, the force exerted on each car causes a change in the momentum for each car. the total momentum for both cars is the same before and after the collision.

Momentum can be defined as the impulse gained by a moving object.

Since it is a product of mass and velocity the product would not change even if the mass and velocity of the object changes after the collision.

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The collision is elastic, the final velocities v1 and v2 of particles 1 and 2 (v₁, v₂) = [(v/3), (4v/3)] Or (v₁, v₂) = (v, 0)

In elastic collisions, the momentum and kinetic energy is usually conserved.

The momentum before collision = momentum after collision

And

Kinetic energy before collision = Kinetic energy after collision

Momentum of object 1 before collision = (2m)v = 2mv

Momentum of object 2 before collision = (m)(0) = 0

Momentum of object 1 after collision = (2m)(v₁) = 2mv₁

Momentum of object 2 after collision = (m)(v₂) = mv₂

So, we have

2mv = 2mv₁ + mv₂

2v = 2v₁ + v₂

v₂ = 2v - 2v₁ (eqn 1)

Kinetic energy of object 1 before collision = (1/2)(2m)(v²) = mv²

Kinetic energy of object 2 before collision = (1/2)(m)(0²) = 0

Kinetic energy of object 1 after collision = (1/2)(2m)(v₁²) = mv₁²

Kinetic energy of object 2 after collision = (1/2)(m)(v₁²) = (mv₂²/2)

So, we have,

mv² = mv₁² + (mv₂²/2)

v² = v₁² + (v₂²/2)

2v² = 2v₁² + v₂² (eqn 2)

Substitute (v₂ = 2v - 2v₁) from (eqn 1) into (eqn 2)

2v² = 2v₁² + (2v - 2v₁)²

2v² = 2v₁² + 4v² - 8vv₁ + 4v₁²

6v₁² - 8vv₁ + 2v² = 0

6v₁² - 6vv₁ - 2vv₁ + 2v² = 0

6v₁(v₁ - v) - 2v(v₁ - v) = 0

(6v₁ - 2v)(v₁ - v) = 0

6v₁ = 2v or v₁ = v

v₁ = (v/3) or v₁ = v

If v₁ = (v/3)

From (eqn 1)

v₂ = 2v - 2v₁

v₂ = 2v - 2(v/3)

v₂ = 2v - (2v/3)

v₂ = (4v/3)

If v₁ = v,

From eqn 1,

v₂ = 2v - 2v₁

v₂ = 2v - 2v = 0

(v₁, v₂) = [(v/3), (4v/3)]

Or

(v₁, v₂) = (v, 0)

The collision is elastic, what are the final velocities v1 and v2 of particles 1 and 2 (v₁, v₂) = [(v/3), (4v/3)] Or (v₁, v₂) = (v, 0)

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If the mass of both planets is doubled, and the distance between them is also doubled, then the forces between them is are twice as much.

In physics, a force is a power that can change the motion of an item. A force can purpose an object with mass to alternate its pace. Pressure also can be described intuitively as a push or a pull. A force has both value and path, making it a vector quantity.

Force is a push or a pull and it affects our daily lives because, without force, people might not be capable of opening and near stuff or lifting up their arms or legs.

Variety of Forces :

* Muscular Forces, muscular tissues feature to produce an ensuing force which is referred to as 'muscular force'.

* Frictional Forces, while an item modifications its national motion, 'frictional pressure' acts upon it.

* Carried out pressure.

* Tension force.

* Spring force.

* Gravitational pressure.

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