Using compound interest and a graphing calculator, it is found that it will take about 15 years for the loan to be paid off.
What is compound interest?The amount of money earned, in compound interest, after t years, is given by:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
In which:
A(t) is the amount of money after t years. P is the principal(the initial sum of money). r is the interest rate(as a decimal value). n is the number of times that interest is compounded per year.For this problem, the parameters are given as follows:
A(0) = 95000, r = 0.06, n = 12.
Hence the value of the loan after t years is:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
[tex]A(t) = 95000\left(1 + \frac{0.06}{12}\right)^{12t}[/tex]
[tex]A(t) = 95000(1.005)^{12t}[/tex]
You have monthly payments of $1,200, hence the amount paid after t years is:
P(t) = 12 x 1,200t = 14400t
Then we have to solve for:
A(t) = P(t)
[tex]14400t = 95000(1.005)^{12t}[/tex]
Which is solved in the graph below, meaning that it will take about 15 years for the loan to be paid off.
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What is the slope of a line that is perpendicular to the line whose equation is ax by=c?
Answer:
b/a
Step-by-step explanation:
Perpendicular lines have slopes that are opposite sign and reciprocals (flipped over).
In the equation
ax + by = c,
the slope of the line is
-a/b
If you haven't memorized this pattern yet, you can calculate it by solving ax+by=c for y.
by = -ax +c
y = -a/b x + c/b
The slope is -a/b
So a perpendicular line would be opposite sign and flipped, b/a
If the top ten nations were randomly selected to march, one after another, into the stadium at the closing ceremonies, in how many ways could the nations have marched in?
Step-by-step explanation:
1. Entrance of Head of State and IOC President
2. Playing of the national anthem
3. The parade of the athletes
4. The symbolic release of doves
5. Olympic Laurel Award
6. Official Speeches
7. Opening of the Games
8. Raising the Olympic flag and playing the Olympic Anthem
9. Athletes, judges and coaches’ oath
10. Lighting of the Olympic flame
11. The artistic programme
[tex]3y - 5x = 10[/tex]
Find the gradient of the linear relation
Isolate y
3y=5x+10y=5/3x+10/3Compare to slope intercept form y=mx+b
Slope=m=5/3
Answer:
[tex]\dfrac{5}{3}[/tex]
Step-by-step explanation:
To find the gradient (slope) of the given linear relation, use arithmetic operations to isolate y:
Given relation:
[tex]3y-5x=10[/tex]
Add 5x to both sides:
[tex]\implies 3y-5x+5x=10+5x[/tex]
[tex]\implies 3y=5x+10[/tex]
Divide both sides by 3:
[tex]\implies \dfrac{3y}{3}=\dfrac{5}{3}x+\dfrac{10}{3}[/tex]
[tex]\implies y=\dfrac{5}{3}x+\dfrac{10}{3}[/tex]
Slope-intercept form of a linear equation
[tex]y = mx+b[/tex]
where:
m is the slope (gradient)b is the y-interceptComparing the rewritten equation with the slope-intercept formula, the gradient (slope) of the given linear relation is ⁵/₃.
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A friend of mine believes that the average GPA at KSU is equal to 3.0. In order to test whether he/she is right, I collect some information from the data. Specifically, I use 100 KSU students to form a sample and find that their sample average GPA is equal to 3.3. In addition, suppose that I also know the population standard deviation of GPA at KSU is 1.5. I decide to use 0.05 as the level of significance for my hypothesis testing. Could you help me with Q1-Q10 below? Q1: What should be my null hypothesis? What should be my alternative hypothesis? Q2: Is this a lower-tailed, upper-tailed or two-tailed case? Q3: Show me how to calculate my test statistic.
Q4: If I use the critical value approach, explain how to derive my critical value(s). Q5: If I use the p-value approach, explain how to derive my p-value. Q6: If I use the confidence interval approach, show me how to derive the confidence interval. Q7: How to make my decision, if I use the critical value approach? Q8: How to make my decision, if I use the p-value approach? Q9: How to make my decision, if I use the confidence interval approach? Q10: Are the decisions in Q7, Q8, and Q9 the same?
The solution of the questions is given as
a)
The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)
b)
This is a case with two separate arguments. (This is a two-tailed case)
c)
Test Statistic is given by:
z= 2.00
d)
Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.
e)
, p-value = 0.0455
f)
CI= (3.006, 3.594)
g)
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
h)
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
i) Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.
j)
The choices you choose in Questions 7, 8, and 9 are identical.
What is the null hypothesis?a)
The null hypothesis states that mu equals 3.0. ( the average GPA at KSU is equal to 3.0) (Claim)
The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)
b)
This is a case with two separate arguments.
c)
Test Statistic is given by:
[tex]z=\frac{\barx-u^0}{σ/Vn}\\\\z=33 - 3.0/1.5/V100[/tex]
z= 2.00
d)
[tex]\alpha = 0.05[/tex]
Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.
e)
Z Score = 2.00
reading from table, p-value = 0.0455
f)
Confidence Interval:
[tex]CI= \barx \pm \frac{ZX\sigma }{\sqrt((n)}[/tex]
[tex]CI =3.3 \pm 1.96 x 1.5 / \sqrt{100}[/tex]
CI= (3.006, 3.594)
g)
The disparity is noteworthy given that the computed value of Z = 2.00 is higher than the crucial value of z = 1.96. Cast doubt on the null hypothesis.
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
h)
The difference may be considered statistically significant since the p-value of 0.0455 is lower than the alpha threshold of 0.05. Cast doubt on the null hypothesis.
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
i)
The difference is statistically significant since the value of 3.0 is not included in the confidence range (3.006 - 3.594). Cast doubt on the null hypothesis.
Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.
j)
The choices you choose in Questions 7, 8, and 9 are identical.
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What is the slop of the line?
Find the error with subject-verb agreement. select the incorrect verb and type it correctly. on the ledge there is three potted geraniums that desperately need water. however the hanging ferns in the living room are thriving.
Answer:
Step-by-step explanation:
ggggggg
Evaluate the following integral (Calculus 2) Please show step by step explanation!
Answer:
[tex]\displaystyle \int \dfrac{\ln x}{x^8}\:\:\text{d}x=-\dfrac{\ln x}{7x^7}- \dfrac{1}{49x^7}+\text{C}[/tex]
Step-by-step explanation:
Fundamental Theorem of Calculus
[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]
If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.
Given integral:
[tex]\displaystyle \int \dfrac{\ln x}{x^8}\:\:\text{d}x[/tex]
[tex]\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}[/tex]
[tex]\implies \displaystyle \int x^{-8}\ln x\:\:\text{d}x[/tex]
[tex]\boxed{\begin{minipage}{4.8 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}[/tex]
Using Integration by parts:
[tex]\textsf{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}[/tex]
[tex]\textsf{Let }\dfrac{\text{d}v}{\text{d}x}=x^{-8} \implies v=-\dfrac{1}{7}x^{-8+1}=-\dfrac{1}{7}x^{-7}=-\dfrac{1}{7x^7}[/tex]
Therefore:
[tex]\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x^{-8}\ln x\:\:\text{d}x & = -\dfrac{1}{7x^7}\ln x- \int -\dfrac{1}{7x^7} \cdot \dfrac{1}{x}\:\:\text{d}x\\\\& = -\dfrac{\ln x}{7x^7}+ \int \dfrac{1}{7x^8}\:\:\text{d}x\\\\& = -\dfrac{\ln x}{7x^7}+ \int \dfrac{1}{7}x^{-8}\:\:\text{d}x\\\\& = -\dfrac{\ln x}{7x^7}-\dfrac{1}{7 \cdot 7}x^{-8+1}+\text{C}\\\\& = -\dfrac{\ln x}{7x^7}- \dfrac{1}{49x^7}+\text{C}\end{aligned}[/tex]
[tex]\boxed{\begin{minipage}{4 cm}\underline{Differentiating $\ln x$}\\\\If $y=\ln x$, then $\dfrac{\text{d}y}{\text{d}x}=\dfrac{1}{x}$\\\end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}[/tex]
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Substitute [tex]y=\ln(x) \iff e^y = x[/tex] and [tex]dy=\frac{dx}x[/tex] to get
[tex]\displaystyle \int \frac{\ln(x)}{x^8} \, dx = \int ye^{-7y} \, dy[/tex]
Integrate by parts with
[tex]u = y \implies du = dy[/tex]
[tex]dv = e^{-7y} \, dy \implies v = -\dfrac17 e^{-7y}[/tex]
Then
[tex]\displaystyle \int u\,dv = uv - \int v\,du \\\\ \implies \int y e^{-7y} \, dy = -\dfrac17 ye^{-7y} + \frac17 \int e^{-7y} \, dy + C \\\\ ~~~~~~~~~~~~ = -\frac17 ye^{-7y} - \frac1{49} e^{-7y} + C \\\\ ~~~~~~~~~~~~ = \boxed{-\frac{\ln(x)}{7x^7} - \frac1{49x^7} + C}[/tex]
Please answer quickly!
19) The sum of the arithmetic series is - 397. (Correct choice: E)
33) The sum of the geometric series is 1700. (Correct choice: E)
How to determine the sum of a given series
19) Arithmetic series are sets of elements generated by a linear expression of the form:
aₙ = a₁ + (n - 1) · d (1)
Where:
aₙ - n-th term of the seriesa₁ - First term of the series n - Index of the n-th term of the series.d - Change between two consecutive elements of the series.If we know that a₁ = 27, n = 20 and d = - 5, then sum of the first 20 terms of the series is:
x = 27 + 22 + 17 + 12 + 7 + 2 + (- 3) + (- 8) + (- 13) + (- 18) + (- 23) + (- 28) + (- 33) + (- 38) + (- 43) + (- 48) + (- 53) + (- 58) + (- 63) + (- 68)
x = - 397
The sum of the arithmetic series is - 397. (Correct choice: E)
33) Geometric series are sets of elements generated by a exponential expression of the form:
aₙ = a₁ · rⁿ (2)
Where:
aₙ - n-th term of the seriesa₁ - First term of the seriesr - Ratio between two consecutive elements of the series.If we know that a₁ = 1458 and r = 1 / 3, then the sum of the first 6 terms of the geometric series is:
x = 1458 + 162 + 54 + 18 + 6 + 2
x = 1700
The sum of the geometric series is 1700. (Correct choice: E)
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Morgan is designing a rectangular quilt. The quilt will be 1 3/5 meters wide and will have an area of 6m 2 (To the power). How long is the quilt?
Answer:3 3/4 meters
Step-by-step explanation:
6/(1 3/5)=3.75 meters or 3 3/4 meters
JDIDJRJDJF PLS HELP IM STUCK
Step-by-step explanation:
we have
B = J + 2
as the number of laps Bill ran.
to get the number of laps Jill ran we need to transform this equation, so that we get
J = ...
or
... = J
J has to be on one side, and the rest on the other (just as it is with B = ...).
so,
B = J + 2
B - 2 = J
or
J = B - 2
hey ! we are finished already !
PLEASE HELP ME QUICKLY!! IM BEING TIMED
The sum of 2 numbers is 36. The first number is twice the second number. Find the second number
Answer: 24+12=36
Step-by-step explanation:
36= _+_
2x(2 times)
x
X+2x=36
3x=36
12
12+2(12)=36
12+24=36
Answer:
The value of the second number is 24 and the first no 12.Step-by-step explanation:
Greetings !From, the given word explanation try to create your own equation like
x + y = 36... (1) let the two numbers be x and y respectively.2x = y ....(2) let x be the first no and it's twice that of the second number.From, equation (1) solve for x
x + y = 36x = 36-y... (3)Substitute, equation (3) to equation (2).
2(36-y) =y72 - 2y =y72 = y + 2y.... solve for y72 = 3y.... divide both sides by 372/3 = y..y=24 ...simplifiedHow many lattice points (points with integer coordinates) are on the line segment whose endpoints are $(3,17)$ and $(48,281)
Any line through the points [tex](a,b)[/tex] and [tex](c,d)[/tex] has
[tex]\gcd(c-a,d-b)+1[/tex]
lattice points. In this case, the count is GCD(45, 264) + 1.
Using Euclid's algorithm, we have
264 = 5•45 + 39
45 = 1•39 + 6
39 = 6•6 + 3
6 = 2•3 + 0
so that GCD(45, 264) = 3. Then there are 3 + 1 = 4 lattice points.
is (n x (n +1)) / 2 the same as (n/2)(n+1)
Answer:
nope
Step-by-step explanation:
simplify the first equation
Answer:
yes
Step-by-step explanation:
The associative and commutative properties of multiplication allow you to rearrange the product to the form shown in the question.
Division by 2 is effectively multiplication by 1/2.
[tex](n\times(n+1))/2\qquad\text{given}\\\\=\dfrac{n(n+1)}{2}=\dfrac{n}{2}(n+1)\\\\=\boxed{(n/2)(n+1)}[/tex]
__
Additional comment
Evaluation of the expressions according to the order of operations will proceed differently for the two expressions.
For the first expression, evaluation steps are ...
add 1 to nmultiply the sum by ndivide the product by 2For the second expression, evaluation steps are ...
divide n by 2add 1 to nmultiply the results of these two operationsAs we said above, the properties of multiplication ensure the results are the same either way.
As a practical matter, for integer values of n, one of n and (n+1) will be even. It is usually convenient to divide the even number by 2. This means the evaluation might be ...
((n+1)/2)n . . . . for odd n(n+1)(n/2) . . . . for even nFor certain computer representations of the numbers, results may differ depending on the specific numbers and the order of evaluation.
Figure 222 is a scaled copy of Figure 111.
PLEASE HELP
Identify the side in Figure 222 that corresponds to side \overline{CD}
CD
start overline, C, D, end overline in Figure 111.
Choose 1 answer:
Choose 1 answer:
An observer (o) spots a plane (p) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and located directly above a tower (t). the observer also notices a bird (b) circling directly above her. if the distance from the plane(p) to the tower (t) is 7,000 feet, how far is the bird (b) from the plane (p)? round to the nearest whole number. two parallel lines bp and ot with a transversal running through p and o. dotted red line from p to t and from b to o. angle pot is 33 degrees. the length of p t is 7000. the length of bp is x. 3,815 feet 5,873 feet 8,343 feet 10,779 feet
The distance between the bird (B) and plane (P) exists at 10,779 feet.
How to estimate the distance between the bird (B) and plane (P)?
Given the figure attached,
PT = OB = 7000 ft
PB = OT = x feet
and angle of elevation (∠POT) = 30°
By applying the Tan rule in the triangle POT,
tan 33° = Opposite side/Adjacent side = PT/OT
tan 33° = 7000/x
x = 7000/tan33°
x = 10779 feet
The distance between the bird (B) and plane (P) exists at 10,779 feet.
Therefore, the correct answer is option D. 10779 feet.
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number 14 part 1 pls
Given
[tex]7 - px - x^2 = 16 - (q + x)^2[/tex]
expanding the right side gives
[tex]7 - px - x^2 = 16 - (q^2 + 2qx + x^2)[/tex]
[tex]7 - px - x^2 = 16 - q^2 - 2qx - x^2[/tex]
Two polynomials of equal degree are the same if their coefficients are identical. This means
[tex]\begin{cases}16 - q^2 = 7 \\ -2q = -p\end{cases}[/tex]
[tex]16 - q^2 = 7 \implies q^2 = 9 \implies q=\pm3[/tex]
[tex]-2q = -p \implies p = 2q = \pm6[/tex]
Both [tex]p[/tex] and [tex]q[/tex] are positive, so [tex]\boxed{p=6}[/tex] and [tex]\boxed{q=3}[/tex].
HALP AFAP PLSSS
Figure A is a scale image of figure B. what is the value of x?
Using proportions, it is found that the value of x is of 5.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
In this problem, since Figure A is a scale of Figure B, the side lengths are proportional, hence the following rule of three is established:
x/12.5 = 2/5
Applying cross multiplication:
5x = 25
x = 5.
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! What are modern numbers? and how are they used?
Modern numbers are the ten numerical digits used in constructing other numbers.
What are modern numbers?Modern numbers are also called Arabic numerals. They are the ten numerical digits:
0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
Uses of modern numbers;
They are used as symbols to write decimal numbers.They are used in writing numbers in other systems like the octal, and for writing identifiers such as computer symbols, trademarks, or license plates.They are used in constructing other numbers.Hence, modern numbers are the ten numerical digits used in constructing other numbers.
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If f(x + 1) = x + 2 then f(x - 1) is
Answer: [tex]\Large\boxed{f(x-1)=x}[/tex]
Step-by-step explanation:
Given function
f(x + 1) = x + 2
Isolate [ x + 1 ] on the right-hand side
f(x + 1) = x + 1 + 1
f(x + 1) = (x + 1) + 1
Substitute [ x + 1 ] with x
f(x) = x + 1
Substitute [ x ] with [ x - 1 ]
f(x - 1) = (x - 1) + 1
[tex]\Large\boxed{f(x-1)=x}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
These box plots show daily low temperatures for a sample of days in two
different towns.
Town A
Town B
10 15 20
H
5
ㅏ
20
30
30
40
55
55
05 10 15 20 25 30 35 40 45 50 55 60
Degrees (F)
The correct option regarding the data-sets represented by the box and whisker plots is:
B. The distribution for town A is positively skewed, but the distribution for town B is symmetric.
What does a box-and-whisker plot shows?A box and whisker plot shows three things:
The 25th percentile, which is the median of the bottom 50%.The median, which splits the entire data-set into two halfs, the bottom 50% and the upper 50%.The 75th percentile, which is the median of the upper 50%.For data-set A, we have that:
The 25th percentile is of 15.The median is of 20.The 75th percentile is of 30.Since 30 - 20 > 20 - 15, the distribution is positively skewed.
For data-set B, we have that:
The 25th percentile is of 20.The median is of 30.The 75th percentile is of 40.Since 40 - 30 = 30 - 20, the distribution is symmetric.
Hence the correct option is:
B. The distribution for town A is positively skewed, but the distribution for town B is symmetric.
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a) The line of y = 2x + 7 meets the y-axis at A.
write down the co-ordinates of A,
b) A line parralel to y = 2x + 7 passes through B(0,3)
Find the equation of this line.
(ii) C is the point on the line y = 2x + where x = 2
Find the the co-ordinates of the midpoint of BC
a) The coordinates of point A that meet the linear equation y = 2 · x + 7 are A(x, y) = (0, 7).
b) The equation of the line parallel to the line y = 2 · x + 7 is the line y = 2 · x + 3.
c) The coordinates of the midpoint of line segment BC is M(x, y) = (1, 7).
How to analyze linear equations
Herein we find three cases related to the linear equation y = 2 · x + 7. a) We need to determine the coordinates of point A, the y-coordinate can be determined by evaluating the function:
y = 2 · 0 + 7
y = 0 + 7
y = 7
The coordinates of point A that meet the linear equation y = 2 · x + 7 are A(x, y) = (0, 7).
b) Two lines are parallel to each other whether both have the same slope but different intercept. Then, the new line is of the form:
y = 2 · x + b
Now we proceed to find the intercept of the line:
b = y - 2 · x
b = 3 - 2 · 0
b = 3
The equation of the line parallel to the line y = 2 · x + 7 is the line y = 2 · x + 3.
c) The coordinates of point C is:
y = 2 · 2 + 7
y = 11
If we know that B(x, y) = (0, 3) and C(x, y) = (2, 11), then the coordinates of the midpoint of BC is:
M(x, y) = 0.5 · B(x, y) + 0.5 · C(x, y)
M(x, y) = 0.5 · (0, 3) + 0.5 · (2, 11)
M(x, y) = (1, 7)
The coordinates of the midpoint of line segment BC is M(x, y) = (1, 7).
RemarkThe statement presents typing mistakes and omissions, complete form is shown below:
a) The line of y = 2x + 7 meets the y-axis at A, where x = 0. Write down the co-ordinates of A.
b) A line parralel to y = 2x + 7 passes through B(x, y) = (0,3) Find the equation of this line.
c) C is the point on the line y = 2x + 7 where x = 2. Find the the co-ordinates of the midpoint of BC.
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each quadratic function with its respective graph. Graph Functions Graph of quadratic functions on a coordinate plane. Upward parabola vertex is at (2, 1) in quadrant 1. Left slope at (1, 2), (0, 5) enters quadrant 3. Right slope is at (3, 2), (4, 5) in quadrant 1. arrow Both Graph shows downward parabola plotted on a coordinate plane. The parabola has vertex at (minus 1, 4). The parabola has left slope at (minus 3, 0) and right slope at (1, 0). arrowBoth Graph shows upward parabola plotted on a coordinate plane. The parabola has vertex at (3, minus 4). The parabola has left slope at (1, 0) and right slope at (5, 0). arrowBoth
The correctly matched quadratic functions are given as follows:
Part A) The function of the First graph is f(x) = (x-3) (x + 1) Part B) The function of the Second graph is f(x) = -2 (x - 1) ( x + 3) Part C) The function of the Third graph is f(x) = 0.5(x - 6) (x + 2) What is a Quadratic Function?Quadratics are polynomial equations of the second degree, which means that they contain at least one squared term.
Quadratic equations are another name for it. The quadratic equation has the following general form: ax2 + bx + c = 0.
How do we correctly match the graphs?Recall that:
f(x) - a (x -c) (x - d)
where
a is the leading coefficientc and d are the roots or zeros of the function.Part A) First graph
We are given to know
The solutions or zeros of the first graph are
x=-1 and x=3
The parabola open up, so the leading coefficient a is positive, the function therefore, is equal to
f(x) = (x-3) (x + 1); Find the value of the coefficient a.The vertex is equal to the point (1, -4)
Substitute and solve for a
-4 = a(1-3)(1+1)
-4 = a(-2)(2)
a = 1
Hence, the function is equal to f(x) = (x-3) (x + 1)
Part B) Second Graph
We are also given to know that
The solutions or zeros of the first graph are
x=-3 and x=1
The parabola open down, so the leading coefficient a is negative
The function is equal to f(x) = a (x-1)(x+3)
Find the value of the coefficient a
The vertex is equal to the point (-1,8)
to solve for a, we must substitute:
8 = a(-1-1) (-1+3)
8 = a(-2)(2)
a = -2
Hence, the function is equal to: f(x) = -2 (x - 1) ( x + 3)
Part C)
We are given to know that the solutions or zeros of the first graph are
x=-2 and x=6
The parabola open up, so the leading coefficient a is positive
The function is equal to f(x) = a(x-6) (x+2).
Find the value of the coefficient a
The vertex is equal to the point (2,-8)
We substitute and solve for a:
-8 = a(2-6) (2+2)
-8 = a(-4)(4)
a = 0.5
Hence, the function is equal to f(x) = 0.5(x - 6) (x + 2)
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Find the quotient.
18.)97.2
Answer:
540
Step-by-step explanation:
540 =18% of 97.2
Done please
it's quotient it's a synthax error..
Most air travelers now use e-tickets. Electronic ticketing allows passengers to not worry about a paper ticket, and it costs the airline companies less to handle than paper ticketing. However, in recent times the airlines have received complaints from passengers regarding their e-tickets, particularly when connecting flights and a change of airlines were involved. To investigate the problem, an independent watchdog agency contacted a random sample of 20 airports and collected information on the number of complaints the airport had with e-tickets for the month of March. The information is reported below.
14 14 16 12 12 14 13 16 15 14
12 15 15 14 13 13 12 13 10 13
A) What assumption is necessary before conducting a test of hypothesis?
B) What is the decision rule?
Reject H0: ? ? 15 and accept H1: ? < 15 when the test statistic is
Less than or Greater than (pick one)
C) Compute the test statistic:
D) Reject or accept the null hypothesis?
The assumption that is necessary before conducting a test of hypothesis is that there is a significant amount of complaints for use of e-tickets.
How to illustrate the information?The assumption is that there is a significant amount of complaints for use of e-tickets.
H0: there is a significant amount of complaints for use of e-tickets.
H1: Number of complaints for use of e-tickets is not significant.
H1: parameter > value
Notice the inequality points to the right
Decision Rule: Reject H0 if test statistic > critical value
Decision Rule: Reject H0 if p -value = 0.05
The hypothetical mean is 15.00 and The actual mean is 13.50
The difference between these two values is -1.50.
The sample size is 20
Mean 13.50
SD 1.50
The test statistic will be -4.459.
Lastly z it's important to reject the null hypothesis since the test statistic is greater than the critical value of 1.7291.
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There is 1 pint of liquid in this container. if another pint were added, how much liquid would there be? a) 2 cups b) 1 pint c) 1 quart d) 2 gallons
Answer:
C: 1 Quart
Step-by-step explanation:
2 pints are the equivalent of 1 quart
Answer:1 Quart
Step-by-step explanation: Because 2 pints equals=1 quart
HELP Given the set of all odd integers from 1 to 81, what is the probability
of choosing a number that is a multiple of 9?
If you enter your answer as a decimal, round to the thousandths place.
Using it's concept, the probability of choosing a number that is a multiple of 9 is of 0.111.
What is a probability?A probability is given by the number of desired outcomes divided by the number of total outcomes.
From 1 to 81, there are 81 numbers, of which 81/9 = 9 are multiples of 9, hence, considering that 81 is the number of total outcomes and that 9 is the number of desired outcomes, the probability is given the following division:
p = 9/81 = 1/9 = 0.111.
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Use the wave equation to find the speed of a wave given by y(x,t) = (9. 13 mm) sin[(6. 65 m-1)x - (5. 52 s-1)t]
The speed of the wave is 0.83 m/s.
According to the statement
we have given that the equation and we have to find the speed of the wave.
So, For this purpose, we know that the
The given equation is y(x,t) = (9. 13 mm) sin [(6. 65 m^-1)x - (5. 52 s^-1)t]
Then we have to find the speed of the wave
So, Comparing y(x,t) = (9. 13 mm) sin[(6. 65 m-1)x - (5. 52 s-1)t]
to the general expression y(x,t)=y m sin(kx−ωt),
Because the general expression is y(x,t)=y m sin(kx−ωt)
we see that k= 6.65 m −1 and ω= 5.52 rad/s.
The speed of the wave is
v=ω/k=(5.52 rad/s)/(6.65 m )= 0.83 m/s
So, The speed of the wave is 0.83 m/s.
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If six cans of soda cost nine dollars, how much would it cost for 8 cans.
Answer:
Solution:
here,
6 cans cost = 9 dollars
1 can costs = 9÷6 dollars
= 1.5 dollars
Now,
8 cans cost = 8×1.5 dollars
= 12 dollars
The sum of 2 numbers is 73, and their difference is 11.
Find the numbers.
Answer: 42 and 31
Step-by-step explanation:
Let x be one number and y be the other.
We will write mathematical equations for these two numbers.
The sum of 2 numbers is 73.
x + y = 73
Their difference is 11.
x - y = 11
See attached for the graph.
The point of intersection is our solution.
Select the correct answer what are the solutions of this quadratic equation x^2+8x+3=0
Answer:
x= -4 + radical 13
Step-by-step explanation: