You discover that the head of a match contains 1.6x1024 atoms of sulfur S. How many moles of S does a match contain? (Show work please)

Explanation:

The temperature of the the fixed gas is451.938°C

Answer:

c

Explanation:

c

Double bond in ethene is made up of sigma and Pi bonds.

The covalent bond will be formed by the lateral overlap of the atomic orbitals is known as pi bond. For example, ethylene molecule contain 5 sigma bonding as well as 1 pi bonding in it. Pi bond formation will takes place by the parallel orientation of the two p orbitals in an adjacent atoms by proper sideways overlap. Thus in any molecule in which pi bond formation will takes place at all the atoms must be having in the same plane. Thus in pi bond carbon carbon double bond rotation is restricted due to the maximum overlap of the p orbitals. Example : Ethene molecule

Sigma bond (σ bond): A covalent bond will be formed by the overlap of atomic orbitals and/or hybrid orbitals along with the bond axis (i.e., along a line connected to the two bonded atoms). The sigma bond in the hydrogen molecule is formed by overlap of a pair of 1s orbitals, one from each hydrogen atom.

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The classification of each sample is pure element are shown in option A, C, and F, pure compound are shown in option D and I, mixture of an element and a compound are shown in option J, mixture of two elements are shown in option E and H, and mixture of two compounds are shown in option B and G.

Pure elements refer to substances that have one kind of atom. They have the same atomic number and one stable isotope as shown in the samples in option A, C, and F. A compound refers to a substance which is made up of two or more different chemical elements which are combined in a fixed ratio. A pure compound is composed of a particular set of molecules or ions that are chemically bonded as shown in the sample in option D and I.

Mixture comprises of two or more different elements and/or compounds which are physically intermingled. They can be separated into its components by physical means, and often retain many of the properties of its components. The mixture of an element and a compound are shown in option J, mixture of two elements are shown in option E and H, and mixture of two compounds are shown in option B and G.

Note: The question is incomplete. The complete question is attached.

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Answer:

What is the molar mass of CuCl₂? 134,4524 gr/mol

How many moles are in 79.8 grams of CuCl₂? 0,5935 moles of CuCl₂

Explanation:

Atomic weight of each element:

Cu = 63.546  *  1 = 63.546 gr/mol

Cl₂ = 35.4532 * 2 = 70,9064 gr/mol

The molar mass of CuCl₂ = 63.546 gr/mol + 70,9064 gr/mol

The molar mass of CuCl₂ = 134,4524 gr/mol

[tex]79.8\,grams\, \,of\, \,CuCl_2*\frac{1 mol\,CuCl_2}{134.4524\,grams\,\,of\,CuCl_2} \approx 0,5935\,\, mol \,of \,CuCl_2[/tex]

The standard enthalpy of formation of a compound is the enthalpy change associated with the reaction that generates 1 mole of that compound from its component elements under standard conditions.

The enthalpy change that takes place when 1 mole of a substance is created from its component elements in their standard states is known as the standard enthalpy of formation.

A pure element has a standard enthalpy of production of 0 in its normal state. The standard enthalpy change for any chemical reaction is equal to the sum of the standard enthalpies at which the products are formed less the sum of the standard enthalpies at which the reactants are formed.

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Answer:

below

Explanation:

2.7 g   per 100 ml is th same as 27 g per liter

Molar weight of Na Cl

   Na = 22.99  g/mole     Cl = 35.45 g/mole      Total= 58.44 g/mole

then 27 g is    27/ 58.44 = .462 moles per liter

                                                      which is .462 molar

Answer:

Lead is a post transition metal of variable valency

Explanation:

Lead has been placed in group 1st and 2nd because lead chloride is slightly soluble in water and therefore, lead is never completely precipitated by adding dilute HCl to a sample; the rest of the lead ions are precipitated with H2​S in acidic medium.

Sink- followed by a large amount of water Waste Bucket: Hydrochloric acid solution, Sodium hydroxide solution

Laboratory chemical waste can be disposed of in one of three ways: Non-hazardous waste should be disposed of in a sanitary sewer or garbage; sewer disposal should come after acid-base neutralization. Note:To be permitted, any other form of therapy must be incorporated within an experimental process.

There are several categories into which this garbage might be divided: dangerous, medical, biological, electrical, and lab. Reducing laboratory waste will provide a number of advantages, including monetary savings, lower disposal expenses, and increased lab safety.

The environment, the public's health, and the laboratory itself can all be harmed by improper laboratory waste disposal. The Laboratory: If it is discovered that a laboratory is unlawfully disposing of their hazardous waste, the EPA levies severe fines and penalties.

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Answer:

The equilibrium concentration of O2(g) in the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) can be determined by solving the equilibrium expression. The equilibrium constant is given as 800.4, and the concentration of SO2(g) and SO3(g) are 2.00 M and 10.0 M, respectively. Using the equilibrium expression, K = [SO3]2/[SO2]2[O2], the equilibrium concentration of O2(g) would be 0.016 M.

The number of moles can be used to calculate k, which is the concentration divided by the time, and m, which is the molarity.

The total of all the powers to which the concentration terms in the rate law are raised to describe the reaction's observed rate is known as the order of a reaction. The reaction exhibits zero-order kinetics if the reactant concentration rises.

The reaction's rate constant is represented by the symbol k.

The rate constant of a zero-order reaction is written as concentration/time, or m/s, where m is the molarity and s is one second.

∴ [tex]k = mol L^{-1} s^{-1}[/tex] is the unit of rate constant.

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Answer:

Parts per billion (ppb) is a unit of measurement used to express very low concentrations of a substance. It is equivalent to one part of a substance per billion parts of a whole, or one microgram per liter (μg/L) in the case of a liquid solution. For example, if a water sample contains 1 ppb of a certain chemical, it means that there is one microgram of that chemical per liter of water. It is often used in environmental monitoring to measure the levels of pollutants in air, water, and soil.

Explanation:

The partial pressure of water vapor is found to be 166 mmHg.

To calculate the partial pressure of water vapor above the solution, we need to use Raoult's law which states that the vapor pressure of a component in a solution is proportional to its mole fraction in the solution.

First, we need to calculate the mole fraction of water in the solution:

Moles of water = 121 g / 18.015 g/mol = 6.71 mol

Moles of methanol = 59.6 g / 32.04 g/mol = 1.86 mol

Total moles = 6.71 mol + 1.86 mol = 8.57 mol

Mole fraction of water = moles of water / total moles = 6.71 mol / 8.57 mol = 0.782

Mole fraction of methanol = moles of methanol / total moles = 1.86 mol / 8.57 mol = 0.218

Now, we can use Raoult's law to calculate the partial pressure of water vapor above the solution:

Partial pressure of water = mole fraction of water * vapor pressure of water at that temperature

= 0.782 * 212. mmHg

= 166.1 mmHg

Therefore, the partial pressure of water vapor above the solution is 166.1 mmHg.  The answer is rounded to three significant digits, which gives us 166 mmHg.

"

Complete question

At a certain temperature the vapor pressure of pure water is measured to be 212. mmHg. Suppose a solution is prepared by mixing 121. g of water and 59.6 g of methanol (CH3OH) Calculate the partial pressure of water vapor above this solution. Be sure your answer has the correct number of significant digits Note for advanced students: you may assume the solution is ideal mmHg

"

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The number of the molecules of water on the beach is 1.68 * 10^21 molecules.

We know that we can be able to obtain the Number of mass of the water molecules by the use of the equation that;

Density = mas/volume

Mass = Density * volume

Mass of the water = 0.05 g

Moles of the water molecules = Mass/ molar mass

= 0.05 g/18 g/mol

= 0.0028 moles

If 1 mole of the water would contain 6.02 * 10^23 molecules

0.0028 moles of the water molecules would contain 0.0028 moles *  6.02 * 10^23 molecules/1 moles

= 1.68 * 10^21 molecules

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The expression for Keq for the reaction is 0.25

The expression for Keq represents the relative concentrations of the products and reactants in a chemical reaction at a given temperature and pressure. To calculate Keq, one must first balance the chemical equation for the reaction and then determine the concentrations of all species involved in the reaction at equilibrium.

In this case, the balanced chemical equation for the reaction between 0.1 M AgNO3 and a saturated solution of PbCl2 is

AgNO3(aq) + PbCl2(aq) ⇌ AgCl(s) + Pb(NO3)2(aq)

At 25°C, the initial concentrations of AgNO3 and PbCl2 are 0.1 M and unknown, respectively. The reaction is performed by mixing 50 mL of 0.1 M AgNO3 with 50 mL of a saturated solution of PbCl2, so the final volume of the solution is 100 mL.

Once the reaction has reached equilibrium, the concentration of AgCl can be measured and the concentration of Pb(NO3)2 can be calculated using the stoichiometry of the balanced chemical equation. With these values, the expression for Keq can be calculated using the following formula:

Keq = [AgCl] [Pb(NO3)2] / [AgNO3] [PbCl2]

Where [AgCl], [Pb(NO3)2], [AgNO3], and [PbCl2] represent the concentrations of AgCl, Pb(NO3)2, AgNO3, and PbCl2 at equilibrium, respectively.

Given the concentration values, the expression for Keq can be calculated using the following formula:

Keq = [AgCl] [Pb(NO3)2] / [AgNO3] [PbCl2]

Plugging in the given values:

Keq = 0.05 M * 0.03 M / (0.1 M * 0.06 M)

= 0.25

Therefore, the expression for Keq for the reaction is 0.25.

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As 1  nanometer= 1×10[tex]^-9[/tex] m , thus 1.1×10[tex]^-10[/tex] m=1.1×10[tex]^-1[/tex] nm is the diameter of an atom.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

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A student was instructed to list four facts that may be inferred from the equation presented.

A mg, what is it?

A milligramme is 1,000 micrograms and one tenths of a gramme. Typically, a milligramme is denoted by the symbol mg. A microgram is one tenths of a milligramme one and millionth of a gramme. It is frequently shortened to mcg or ug.

A microgram is what?

Micrograms are a measurement unit (ug or mcg). One thousandth of a gramme is equal to one microgram. Micrograms are used in nutrition to measure the minuscule amounts of nutrients that we require. Micrograms may be used to determine the nutritional value of substances like folate and b - complex.

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The best answer that explain in terms of intermolecular forces why NH₃ has a higher boiling point than CH₄ is because of Because NH₃ can form hydrogen bonds, and CH₄cannnot. The correct answer is A.

Hydrogen bonding and London dispersion forces function as the intermolecular attractive forces in NH₃. Only London dispersion forces operate as intermolecular attractive forces in CH₄. When atoms are in the second period, hydrogen-bonding attractive forces are stronger than dispersion forces. As a result, NH₃ has a greater boiling point than CH₄ does.

Stronger than non-polar bonding are polar bonds. Methane is a non-polar molecule because all of its C-H bonds are non-polar. Therefore, the methane molecules are being affected by the weak Vander walls force. However, since N-H bonds in ammonia are polar, the ammonia molecules are connected to one another by hydrogen bonds, making ammonia a polar chemical. Methane therefore has a lower boiling point than ammonia.

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The number of grams required per pound of body weight, given the kg requirement, is 0.00385714 g per pound of body weigh.

To convert the dosage of 8.50 mg per kg of body weight to the number of grams per pound of body weight, you would first need to convert kg to lbs. 1 kg is equal to 2.20462 lbs. So, you would divide the dosage of 8.50 mg by 2.20462 to get the dosage in mg per pound of body weight.

= 8.50 mg / 2.20462

= 3.85714 mg/lb

To convert mg to g, we know that 1g = 1, 000mg. So we can divide 3.85714 mg/lb by 1000 to get the dosage in grams per pound

= 3.85714 mg/lb / 1000

= 0.00385714 g/lb

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Taking into account the definition of Avogadro's Number, 1.355×10²⁴ atoms of Li in 2.25 moles

Avogadro's number refers to the number of elementary entities (ie, atoms, electrons, ions, molecules) that exist in one mole of any substance. That is, it is the number of particles in 1 mole of any substance (The mole is the unit of the International System of Units that allows to express a quantity of substance and one mole is equal to the number of atoms in twelve grams of pure carbon-12.)

The known approximate value of Avogadro's number is 6.023×10²³ particles per mole.

It can be applied the following rule of three: considering the definition of Avogadro's number if 1 mole of Li contains 6.023×10²³ atoms, 2.25 moles of Li contains how many atoms?

amount of atoms of Li= (2.25 moles × 6.023×10²³ atoms)÷ 1 mole

amount of atoms of Li= 1.355×10²⁴ atoms

Finally, there are 1.355×10²⁴ atoms of Li.

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Al₂Cl₆ is an empirical formula

An empirical formula is a compound's chemical formula that only specifies the ratios of the elements it contains and not the precise number or arrangement of atoms.

Yes the given formula of Aluminum trichloride represented as Al₂Cl₆ is an empirical formula. An empirical formula represents the lowest whole number ratio of atoms in a molecular compound. In this case,

Al₂Cl₆ represents the simplest ratio of two aluminum atoms to six chlorine atoms.

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The given white substances can be divided into two groups based on their solubility.

Ionic compounds potassium iodide, sodium chloride, and calcium carbonate are all strong electrolytes that conduct electricity well when dissolved. They all dissolve readily in water.

Citric acid, sucrose, and phenyl salicylate are weak or non-electrolytes. Sucrose is more soluble in water than the other two substances are in ethanol.

The chemicals could also be divided into groups according to whether they dissolve in water producing hydrogen ions, hydroxide ions, or neither, according to whether they have high or low melting temperatures, according to whether they are optically active. Chemical classifications are extremely useful; they are applied as necessary.

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Zinc becomes superconducting at a temperature of approximately 31.75°C.

Superconductivity is a phenomenon where some materials exhibit zero electrical resistance and perfect diamagnetism (exclusion of magnetic fields) at low temperatures.

The temperature at which a material becomes superconducting is known as its critical temperature.

The conversion factor from millikelvin to Celsius is as follows:

1 mK = 1°C/273.15

The temperature at which zinc becomes superconducting in millikelvin is 8675 mK, so the temperature in degrees Celsius can be calculated as :

8675 mK * (1°C/273.15) = 31.75°C (rounded to 2 decimal places).

So, zinc becomes superconducting at a temperature of approximately 31.75°C.

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2.50 mL, 5.00 mL, and 7.50 mL of stock, each transferred into the volumetric flask and diluted to 10.00 mL. Option A

Step-by-Step approach:

The objective is to create a standard curve that represents the relationship between solution absorbance and dye concentration.

To create a standard curve, it is important to have a range of dilutions with different concentrations of the stock solution.

Option a) 2.50 mL, 5.00 mL, and 7.50 mL of stock, each transferred into the volumetric flask and diluted to 10.00 mL, provides a good range of dilutions.

This option allows for the creation of dilutions with different concentrations of the stock solution, which can then be plotted on the standard curve.

Option c) 3.00 mL and 5.00 mL of stock, each transferred into the volumetric flask and diluted to 10.00 mL, provides too limited of a range to create a useful standard curve.

Option b) 1.00 mL, 3.00 mL, 5.00 mL, and 7.00 mL of stock, each transferred into the volumetric flask and diluted to 10.00 mL, provides a good range of dilutions and is acceptable.

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The two major components making up at least 3% each of the human body are magnesium and nitrogen.

Magnesium makes up about 2.4% of the body, while nitrogen makes up about 3.2%. Oxygen, selenium, and cobalt make up smaller percentages of the body, with oxygen making up about 65%, selenium making up 0.19%, and cobalt making up 0.0012%.

Carbon usually forms four single covalent bonds, while hydrogen typically forms one single covalent bond. Therefore, the answer for carbon:hydrogen is 4:1.

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Histidine contains a amino group and a carboxylic acid group in its backbone and have an imidazole functional group in its side chain.

Histidine is classified as a semi essential amino acid needed in humans for growth and tissue repair. It plays a important role in immunity, gastric secretion. It is required for blood cell manufacture and protects tissues against damage caused by radiation and heavy metals. It is an alpha amino acid with an imidazole functional group. It forms complexes with many metal ions. It is a basic amino acid used to make up proteins in living things. Histidine plays important roles in the active site of enzymes such as serine proteases where it is a member of the catalytic triad. Excess of histidine converted to trans-urocanate by histidine ammonia lyase in liver and skin.

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Two correct answers which describe how water mixes in a thermohaline current are A. Cold water sinks under warmer water. And D. Saltier water sinks under less salty water.

Thermohaline Current is caused by variations in the seawater's surface density from pole to equator. Variations in temperature (thermal) and salinity (haline) affect the equator-to-pole surface. On Earth's climate, the thermohaline ocean currents have a significant impact on circulating heat across the planet.

In the thermohaline current, warmer, fresher water masses are less dense and float, while colder, saltier water masses are more dense and sink. Due to its higher density, this cold, salty water sinks.

So, it is obvious that the correct answers are:

A. Cold water sinks under warmer water.

D. Saltier water sinks under less salty water.

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If a solution has a pH of 7, this means that this is a solution of pure water. Therefore, the correct option is option C among all the given options.

pH is a numerical indicator of how acidic or basic aqueous or some other liquid solutions are. The phrase, which is frequently used during chemistry, biology, including agronomy, converts the hydrogen ion concentration, which typically ranges between 1 and 1014 gram-equivalents per liter, to numbers between 0 through 14.

The hydrogen ion concentration in pure water, which has a pH of 7, is 107 gram-equivalents per liter, making it neutrality (neither acidic nor alkaline). If a solution has a pH of 7, this means that this is a solution of pure water.

Therefore, the correct option is option C among all the given options.

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The structure of the monomer with empirical formula C4H6 and two double bonds can be represented as follows:

H2C=CH-CH=CH2

The degree of polymerization (DP) is defined as the number of monomer units in a polymer chain. If the polymer molecular weight is 108000, the DP can be calculated as follows:

DP = Molecular weight of polymer / Molecular weight of monomer

DP = 108000 / (12 + 6 + 14)

DP = 108000 / 32

DP = 3375

Therefore, the degree of polymerization of the polymer is 3375.

The electron configuration for each element is:

The electron configuration of an atom is the arrangement of electrons in its atomic orbitals. This arrangement is determined by the number of protons in the atom's nucleus and the energy levels of the electrons.

Electron configurations describe the distribution of electrons in the orbitals of an atom and are used to predict chemical properties and the behavior of atoms in a molecule. Electron configurations can be written in several ways, such as the condensed version, the noble gas core version, or the orbital filling version.

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According to the stoichiometry of the mentioned chemical equation 64.6 g of  glucose can be produced.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given chemical equation, there are total 256.6 g of reactants hence the same amount of products must be produced, thus mass of glucose= 256.6-192=64.6 g .

Thus, 64.6 g of  glucose can be produced in the given chemical equation.

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