With 65.2% of respondents opposing more than favoring or strongly opposing building new nuclear power plants.
(a) To find the sample size, we need to add up the number of respondents in each category across all six countries:
298 + 161 + 141 + 128 + 133 + 204 + 309 + 368 + 348 + 272 + 222 + 326 + 219 + 334 + 381 + 322 + 311 + 316 + 221 + 215 + 217 + 389 + 443 + 174 = 5005
So the sample size was 5005.
(b) We can use a chi-squared test of independence to determine whether attitudes toward building new nuclear power plants are independent of country. The null hypothesis is that the attitudes are not independent of country, and the alternative hypothesis is that they are independent.
Using a calculator or software, we can find the test statistic and p-value:
Test statistic: 154.95
p-value: 1.239e-28 (or approximately 0)
With a very small p-value, we reject the null hypothesis and conclude that attitudes toward building new nuclear power plants are not independent of country.
(c) To find the country with the most favorable attitude, we can add up the percentages of respondents who "strongly favor" and "favor more than oppose" for each country:
[tex]Great Britain: \frac{298}{976} = 30.5%[/tex]
[tex]France: \frac{529}{1367} = 38.7%[/tex]
[tex]Italy: \frac{489}{1248} = 39.2%[/tex]
[tex]Spain: \frac{400}{1042} = 38.4%[/tex]
[tex]Germany: \frac{355}{962} = 36.9%[/tex]
[tex]United States: \frac{530}{1335} = 39.7%[/tex]
So Italy has the most favorable attitude, with 39.2% of respondents strongly favoring or favoring more than opposing building new nuclear power plants.
To find the country with the least favorable attitude, we can add up the percentages of respondents who "oppose more than favor" and "strongly oppose" for each country:
[tex]Great Britain: \frac{527}{976} = 54.0%[/tex]
[tex]France: \frac{549}{1367} = 40.1%[/tex]
[tex]Italy: \frac{703}{1248} = 56.3%[/tex]
[tex]Spain: \frac{633}{1042} = 60.7%[/tex]
[tex]Germany: \frac{627}{962} = 65.2%[/tex]
[tex]United States: \frac{391}{1335} = 29.3%[/tex]
So Germany has the least favorable attitude, with 65.2% of respondents opposing more than favoring or strongly opposing building new nuclear power plants.
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Prove that 2^n > n^2 if n is an integer greater than 4
From the principal mathematical induction, the inequality, 2ⁿ > n², where n belongs to integers, is true for all integers greater than four, i.e., n > 4.
We have to prove the inequality 2ⁿ > n², for all integer greater than 4. For this we use mathematical induction method. The principle of mathematical induction is one of method used in mathematics to prove that a statement is true for all natural numbers.
Step 1 : first we consider case first for n= 5 , here 2⁵ = 32 and 5² = 25, so 2⁵ > 5²
Thus it is true for n = 5.
Step 2 : Now suppose it's true for some integer k such that n≤ k, that is 2ᵏ > k²--(1)
Step 3 : Now, we have to prove it's true for n = k + 1. So, 2ᵏ⁺¹ = 2ᵏ. 2
2ᵏ⁺¹ = 2ᵏ.2 > 2k² ( since, 2ᵏ > k² )
> 2k² = k² + k²
> k² + 2k + 1 ( since, k² > 2k + 1 ,k > 3)
> ( k +1)² = k² + 2k + 1
=> 2ᵏ⁺¹ > (k+1)²
So, we proved it for n = k + 1. Hence, this theorem is true for all n.
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Find mLMN.
5 cm
N
M
L
14.3 cm
Applying the formula for the length of an arc, the measure of angle LMN is approximately: 164°.
What is the Length of an Arc?The length of an arc (s) = ∅/360 × 2πr, where r is the radius of the circle.
Given the following from the image attached below, we have:
Reference angle (∅) = m<LMN
length of an arc (s) = 14.3 cm
Radius (r) = 5 cm
Plug in the values:
∅/360 × 2π × 5 = 14.3
∅/360 × 10π = 14.3
∅/360 = 14.3/10π
∅ = 14.3/10π × 360
∅ ≈ 164°
The measure of angle LMN ≈ 164°
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PHYSICS The distance an object falls afterffseconds is given by d= 161? (ignoring air resistance) To find the height of an object launched upward from ground level at a rate of 32 feet per secand, use the expression 32+ - 16+2 where fis the time in seconds. Factor the expression.
The time t in seconds at which the object hits the ground is: 2 seconds
How to solve quadratic expressions?Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
The distance d an object falls after t seconds is given by d = 16t²
To determine the height of an object launched upward from ground level at a rate of 32 feet per second, use the expression 32t - 16t², where t is the time in seconds.
Therefore, put h = 0 in the equation;
0 = 32t - 16t²
16t² = 32t
16t = 32
t = 2 seconds
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Identifying,simplifying, setting up, and solving proportions 1-4
1. Circling non-ratio.
c. 6d. 12.52. Circling ratios that are fully simplified.
a. 7/3b. 1/2c. 2/13d. 3/1e. 21/5f. 44/1g. 1/8h. 10/3i. 2/6 or 1/3Variables in a proportion:
3. a. x = 43. b. y = 154. a. x = 34. b. y = 2How to find variable in each proportion?3. Solve for the variable in each proportion.
a. 3/9 = x/12
To solve for x, cross-multiply and simplify:
3/9 = x/12
(3)(12) = (9)(x)
36 = 9x
x = 4
Therefore, the solution is x = 4.
b. 20/y = 4/3
To solve for y, cross-multiply and simplify:
20/y = 4/3
(4)(y) = (20)(3)
4y = 60
y = 15
Therefore, the solution is y = 15.
4. Solve for the variable in each proportion.
a. 2/14 = (x+1)/28
To solve for x, cross-multiply and simplify:
2/14 = (x+1)/28
(2)(28) = (14)(x+1)
56 = 14x + 14
42 = 14x
x = 3
Therefore, the solution is x = 3.
b. 3/(2y-3) = 6/y
To solve for y, cross-multiply and simplify:
3/(2y-3) = 6/y
(3)(y) = (6)(2y-3)
3y = 12y - 18
-9y = -18
y = 2
Therefore, the solution is y = 2.
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Find dy/dx for the following function, simplifying your answare as much as possible. (v) y = ttan x - phi kuadrat
The derivative of the function y = t*tan(x) - phi^2 with respect to x is dy/dx = t*sec^2(x).
Find the derivative dy/dx for the given function y = tan(x) - phi^2. Please note that there seems to be a typo in the function, so I'll assume that "phi kuadrat" should be "phi squared" and rewrite the function as y = t*tan(x) - phi^2.
To find the derivative dy/dx, we'll apply the rules of differentiation to each term separately:
1. Differentiate tan(x) with respect to x:
Since t is a constant, we only need to differentiate tan(x) which is sec^2(x). So, the derivative of t*tan(x) is t*sec^2(x).
2. Differentiate phi^2 with respect to x:
Since phi^2 is a constant, its derivative is 0.
Now, combine the derivatives of both terms:
dy/dx = t*sec^2(x) - 0
Simplify the answer:
dy/dx = t*sec^2(x)
So, the derivative of the function y = t*tan(x) - phi^2 with respect to x is dy/dx = t*sec^2(x).
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a bowl contains three red and four yellow marbles. you randomly select two marbles from the bowl. which of the following is a conditional probability? assume the second marble is drawn from the marbles remaining after the first draw.
The conditional probability in this scenario is the probability of drawing a yellow marble on the second draw, given that the first marble drawn was red.
To calculate this conditional probability, we can use Bayes' theorem, which states that the probability of an event (in this case, drawing a yellow marble on the second draw) given some prior knowledge (in this case, that the first marble drawn was red) is equal to the probability of both events occurring (drawing a red marble first and a yellow marble second) divided by the probability of the prior event (drawing a red marble first).
The probability of drawing a red marble first is 3/7 since there are three red marbles out of a total of seven marbles in the bowl. Once a red marble is drawn, there are six marbles remaining, of which three are yellow. Therefore, the probability of drawing a yellow marble second, given that the first marble was red, is 3/6 or 1/2.
Putting this together, we can calculate the conditional probability as follows:
P(Yellow on Second Draw | Red on First Draw) = P(Red on First Draw and Yellow on Second Draw) / P(Red on First Draw)
= (3/7) * (3/6) / (3/7)
= 1/2
Therefore, the conditional probability in this scenario is 1/2 or 50%. This means that there is a 50% chance of drawing a yellow marble on the second draw, given that the first marble drawn was red.
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1. Find any extrema or saddle points of f(x,y) = x^3 + 12xy - 3y^2 - 27x + 34 2. A company plans to manufacture closed rectangular boxes that have a volume of 16 ft? Without using Lagrange multipliers, find the dimensions that will minimize the cost if the material for the top and bottom costs twice as much as the material for the sides
The dimensions that minimize the cost subject to the volume constraint are [tex]L = 4 ft, W = 2 ft,[/tex] and [tex]H = 2 ft[/tex] using surface area.
Assuming that the cost of material is proportional to the surface area, we can write the cost function as:
[tex]C = k(2LW + 2LH + WH)[/tex]
where k is a constant of proportionality that depends on the cost of the material. We are given that the cost of the material for the top and bottom is twice the cost of the material for the sides, so we can take k = 3 for simplicity (since the cost of the material for the sides is then 1).
Using the volume constraint as before, we can eliminate one of the variables:
[tex]H = 16/LW[/tex]
When this is used as a cost function substitution,
[tex]C = 3(2LW + 2LH + WH) = 6LW + 96/L + 48/W[/tex]
To find the critical points of C, we need to find where the partial derivatives are zero:
[tex]dC/dL = 6W - 96/L^2 = 0[/tex]
[tex]dC/dW = 6L - 48/W^2 = 0[/tex]
When we simultaneously solve these equations, we obtain:
L = 4 ft
W = 2 ft
H = 2 ft
Therefore, the dimensions that minimize the cost subject to the volume constraint surface area are L = 4 ft, W = 2 ft, and H = 2 ft.
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Let and g be continuous functions on [0, 1], and suppose that f(0) <90) and (1) > g(1). Show that there is some c∈(0.1) such that f(c) = g(e).
We have shown that there exists some c in (0, 1) such that f(c) = g(c).
By the intermediate value theorem, since f and g are continuous on [0, 1], and f(0) < g(1), there exists some a in the interval [0, 1] such that f(a) = g(1).
Similarly, since f and g are continuous on [0, 1] and f(1) > g(1), there exists some b in the interval [0, 1] such that f(1) > g(b).
Now, consider the function h(x) = f(x) - g(x). Then h is continuous on [0, 1], and h(0) < 0 and h(1) > 0.
By the intermediate value theorem again, there exists some c in the interval (0, 1) such that h(c) = 0, which means that f(c) - g(c) = 0, or f(c) = g(c). Thus, we have shown that there exists some c in (0, 1) such that f(c) = g(c).
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Which of the points plotted is closer to (−4, 5), and what is the distance?
A graph with the x-axis starting at negative 10, with tick marks every one unit up to 10. The y-axis starts at negative 10, with tick marks every one unit up to 10. A point is plotted at negative 4, negative 5, at negative 4, 5 and at 5, 5.
Point (−4, −5), and it is 9 units away
Point (−4, −5), and it is 10 units away
Point (5, 5), and it is 9 units away
Point (5, 5), and it is 10 units away
The point that is closer to (-4,5) is (-4,-5), and the distance between the two points is 10 units.
We have a points plotted is closer to (−4, 5).
Using distance formula to calculate the distance between two points:
d =√((x2 - x1)² + (y²- y1)²)
d = √((-4 - (-4))² + (-5 - 5)²)
d = √(0² + (-10)²)
d = √100
d = 10
Thus, the distance between (-4,5) and (-4,-5) is 10 units.
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Let a be a root of some nonzero polynomial ao + a1x +... ·anx € F[x].Prove that a² is algebraic by finding a polynomial (coefficients should depend on a's) in F[x] that has a² as a root. Remark: This would be quite painful if instead of a2 we were given something like a5 - 3a² +1.
To prove that a² is algebraic, we need to find a polynomial in F[x] that has a² as a root. Let's start by considering the polynomial with coefficients depending on a's:
p(x) = (x - a²)
If we substitute x = a into this polynomial, we get:
p(a) = (a - a²) = a(1 - a)
Since a is a root of ao + a1x +... + anx^n, we know that:
ao + a1a +... + ana^n = 0
Multiplying both sides by a, we get:
a ao + a1a² +... + ana^{n+1} = 0
Substituting a(1 - a) for a², we get:
a ao + a1(a(1 - a)) +... + an(a(1 - a))^n = 0
Simplifying, we get:
a ao + a1a(1 - a) +... + ana^n(1 - a)^n = 0
Multiplying both sides by (1 - a)^n, we get:
a ao(1 - a)^n + a1a(1 - a)^{n+1} +... + ana^n(1 - a)^{2n} = 0
Now, let's group the terms by even powers of a and odd powers of a:
a^0(1 - a)^n ao + a^2(1 - a)^{n+1} a1 +... + a^{2n}(1 - a)^{2n} an = 0
This is a polynomial in F[x] with a² as a root. Therefore, we have proved that a² is algebraic.
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The 22 students in Mrs. Aire's class, each purchased balloons to decorate for a party in the gym. Each student paid $3.80. About how much money did the students spend?
Answer:
$83.60
Step-by-step explanation:
22 x $3.80 = $83.60
A mathematics student decides to use
355
an approximation to of
113
Calculate his percentage error in using
this value, giving your answer in
standard form.
In a case whereby A mathematics student decides to use an approximation of π of 355/113 his percentage error in using this value, can be expressed as
How can the percentage error be calculated?Percent error (percentage error) can be described as the difference that can be established between experimental as well as theoretical value, which is been divided by theoretical value then find the multiplication by 100
The error can be calculad as (355/113 - π) / π
=8.5*10^-5
The percentage error = 8.5*10^-5*100 = 8.5*10^-6
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Please answer this question for a quick 100 points
The weight of the candle after 5 hours of burning would be about 15.05 ounces.
If the burn rate is believed to be constant, we need to determine the average burn rate for the eight candles as the ratio of weight loss per hour.
Ounces lost over three hours =
0.5+0.6+0.5+0.7+0.7+0.5+0.5+0.6 = 4.6/8 = 0.575
Ounces lost per hour on average =
= 0.19
For 0 hours, the weight of each candle is 16 ounces.
Therefore, the equation can be =
w = 16 - 0.19h.
This model can be used to predict the weight of the candle when h, the number of hours of burning, is 5.
W = 16 - 0.19(5)
W = 16 - 0.95
W = 15.05
Hence the weight of the candle after 5 hours of burning would be about 15.05 ounces.
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row equivalent matrix method
4x-3y=11
3x+7y=-1
The market price of a t-shirt is $15.00. It is discounted at 10% off. What is the selling price of the t-shirt?
(Enter your answer following the model, i.e. $01.01)
Answer: $13.5
Step-by-step explanation:
1. 15 x 10 =150
2. 150/100=1.5
3. 15.00 - 1.50= 13.5
IM GIVING 40 POINTS!
There is a stack of 10 cards, each given a different number from 1 to 10. Suppose we select a card randomly from the stack, replace it, and then randomly select another card. What is the probability that the first card is an odd number and the second card is less than 4? Write your answer as a fraction in the simplest form
Answer:
There are 10 cards in the stack, and 5 of them are odd (1, 3, 5, 7, and 9). There are 3 cards (1, 2, and 3) that are less than 4. Since we are replacing the first card before selecting the second, the outcomes are independent and we can multiply the probabilities of each event.
The probability of selecting an odd card on the first draw is 5/10, or 1/2.
The probability of selecting a card less than 4 on the second draw is 3/10, since there are 3 cards that meet this condition out of a total of 10.
Therefore, the probability of selecting an odd card on the first draw and a card less than 4 on the second draw is:
(1/2) x (3/10) = 3/20
So the probability of selecting an odd card on the first draw and a card less than 4 on the second draw is 3/20.
Step-by-step explanation:
Answer:
3/20.
Step-by-step explanation:
To find the probability of two independent events happening together, we multiply their individual probabilities. The probability of the first card being an odd number is 5/10, because there are 5 odd numbers out of 10 cards. The probability of the second card being less than 4 is 3/10, because there are 3 cards (1, 2, and 3) that are less than 4 out of 10 cards. Therefore, the probability of the first card being an odd number and the second card being less than 4 is:
5/10 x 3/10 = 15/100
We can simplify this fraction by dividing both the numerator and denominator by 5:
15/100 = 3/20
So, the final answer is 3/20.
Received message. To find the probability of two independent events happening together, we multiply their individual probabilities. The probability of the first card being an odd number is 5/10, because there are 5 odd numbers out of 10 cards. The probability of the second card being less than 4 is 3/10, because there are 3 cards (1, 2, and 3) that are less than 4 out of 10 cards. Therefore, the probability of the first card being an odd number and the second card being less than 4 is: 5/10 x 3/10 = 15/100 We can simplify this fraction by dividing both the numerator and denominator by 5: 15/100 = 3/20 So, the final answer is 3/20.
Question 2 0/1 pt 100 99 Suppose y = anx" on an open interval I that contains the origin. Express the following as a simplified power series in 2 on I. n=0 (5+ – 4x)y" + (2x)y' + 3y M8 an +2 + 10 an +1 + an."
The expression can be expressed as a simplified power series in 2 on interval I as:
n=0 2^n*t^n [an+2 + 10an+1 + an]
To express the given expression as a simplified power series in 2 on interval I, we need to find the derivatives of y and substitute them into the expression.
First, we find the derivatives of y:
y' = an(nx^(n-1)) = nanx^(n-1)
y" = nan(n-1)x^(n-2)
Substituting y', y", and y into the given expression, we get:
(5 - 4x)(nan(n-1)x^(n-2)) + (2x)(nanx^(n-1)) + 3(anx^n)
= 5nan(n-1)x^n - 4nan(n-1)x^(n+1) + 2nanx^(n+1) + 3anx^n
Now we can express this as a power series in 2 by substituting x = 2t:
= 5nan(n-1)(2t)^n - 4nan(n-1)(2t)^(n+1) + 2nan(2t)^(n+1) + 3an(2t)^n
= 5nan(n-1)2^n*t^n - 8nan(n-1)2^(n+1)t^(n+1) + 2nan2^(n+1)t^(n+1) + 3an2^n*t^n
= 2^n*t^n [5nan(n-1) - 8nan(n-1)2t + 2nan(2t) + 3an]
= 2^n*t^n [an+2 + 10an+1 + an]
Therefore, the given expression can be expressed as a simplified power series in 2 on interval I as:
n=0 2^n*t^n [an+2 + 10an+1 + an]
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Explain why the graph is misleading
For all three points say the reason and explain what specifically is going on in the graph
The graph is misleading because the y values do not start from the origin
Explaining why the graph is misleadingThe graph represents the given parameter where
The x-axis represent the yearThe y-axis represent the sales per yearExamining the lengths of the bars with the values, we can see that
The y values do not start from the origin
This is because difference between the bars do not show the correct representation
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answer all questions
1.1 Find the domain of the following functions of: g(x) = root of {(x - 1)(2 – 2)}. 1.2 The size of an insect population at time t (measured in days) is given by p(t) = 3000 - 2000/(1+t^2). Determine the initial Determine the initial population P(0) and the population size after 4 days
1.1 To find the domain of the function g(x) = √((x - 1)(2 – 2)), first, we need to determine the values of x for which the function is defined.
Since the expression inside the square root is (x - 1)(2 – 2), we can see that (2 – 2) equals zero. Therefore, the expression inside the square root simplifies to (x - 1) * 0, which is always equal to 0. The square root of 0 is also 0, so the function g(x) is defined for all real values of x. Hence, the domain of the function g(x) is all real numbers.
1.2 The size of an insect population at time t (measured in days) is given by the function p(t) = 3000 - 2000/(1+t^2). To determine the initial population (P(0)), substitute t = 0 into the function:
P(0) = 3000 - 2000/(1 + 0^2) = 3000 - 2000/1 = 3000 - 2000 = 1000
So the initial population is 1000 insects.
Next, we need to find the population size after 4 days, which means we need to evaluate p(4):
P(4) = 3000 - 2000/(1 + 4^2) = 3000 - 2000/(1 + 16) = 3000 - 2000/17 ≈ 2882.35
After 4 days, the population size is approximately 2882.35 insects.
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The data in the table describes the preferred type of exercise of 9th graders.
Find the marginal relative frequency for students who prefer swimming as their preferred type of exercise.
39%
35%
19%
16%
Approximately 35% of students prefer swimming as their preferred type of exercise. So, correct option is B.
To find the marginal relative frequency for students who prefer swimming as their preferred type of exercise, we need to add up the percentage of boys and girls who prefer swimming.
The percentage of boys who prefer swimming is 16% and the percentage of girls who prefer swimming is 19%.
So, the total percentage of students who prefer swimming is:
16% + 19% = 35%
Therefore, the marginal relative frequency for students who prefer swimming as their preferred type of exercise is 35%.
So, correct option is B.
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Solve for length of segment b. 6 cm 4 cm 3 International Academy of Science. All Rights Reserved. Search b 18 cm b = [?] cm If two segments intersect inside or outside a circle: ab = cd Enter
The needed, following the property of intersecting chords, length of segment b is 2 cm,
To find the length of segment b, we need to use the property of intersecting chords inside or outside a circle, which states that the product of the two segments of each chord is equal.
Given that:
ab = 6 cm
cd = 4 cm
ac = 3 cm
bd = b cm (length of segment b, to be found)
The property states:
ab * bd = cd * ac
Substitute the given values:
6 cm * b cm = 4 cm * 3 cm
Now, solve for b:
6b = 12
Divide both sides by 6 to isolate variable b:
b = 12 / 6
b = 2 cm
So, the length of segment b is 2 cm.
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(Middle school work)
With regard to the clindrical designs, note that is advisable for Kevin to opt for the first design which requires about 108.35 square inches of plastic. The second design requires about 431.97 square so Kevin does not have enough plastic to make the second design.
How did we arrive at this?Here we used the surface area formula for cylinders.
Surface Area = 2πr² + 2πrh
R is the base and h is the height.
For First Design we have
Diameter (d) = 2r = 3
so r = 1.5
So Surface Area = 2π(1.5)² + 2π(1.5) (10)
SA First Cylinder = 108.35
Repeating the same step for the second cylinder we have:
SA 2ndCylinder = 431.97
Thus, the conclusion we have above is the correct one because:
108.35in² < 205in² > 431.97in²
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carl yastrzemski played for the boston red sox from 1961-1983 and is a hall of famer. his home run totals from his 23 year career are as follow: {11,19,14,15,20,16,44,23,40,40,15,12,19,15,14,21,28,17,21,15,7,16,10} find the mean, median,
Answer: 7, 10, 11, 12, 14, 14, 15, 15, 15, 15, 16, 16, 17, 19, 19, 20, 21, 21, 23, 28, 40, 40, 44
To find the mean of Carl Yastrzemski's home run totals, we need to add up all the values and then divide by the number of values.
11 + 19 + 14 + 15 + 20 + 16 + 44 + 23 + 40 + 40 + 15 + 12 + 19 + 15 + 14 + 21 + 28 + 17 + 21 + 15 + 7 + 16 + 10 = 391
There are 23 values in the data set, so we divide by 23:
Mean = 391/23 = 17
Therefore, the mean number of home runs that Carl Yastrzemski hit per season during his career was 17.
To find the median, we need to arrange the values in order from smallest to largest:
7, 10, 11, 12, 14, 14, 15, 15, 15, 16, 16, 17, 19, 19, 20, 21, 21, 23, 28, 40, 40, 44
There are an odd number of values, so the median is the middle value. In this case, the middle value is 16.
Therefore, the median number of home runs that Carl Yastrzemski hit per season during his career was 16.
In summary, the mean number of home runs per season was 17 and the median number of home runs per season was 16. The mean and median are both measures of central tendency, but they represent slightly different things. The mean is the average value and takes into account all the values in the data set. The median is the middle value and is less affected by extreme values. Both measures can be useful in understanding a data set, depending on what information you are looking for.
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Evaluate the integral by interpreting it in terms of areas. 4/−3 (1 − x) dx
Answer:
[tex] \frac{2}{3} square \: units[/tex]
‼️WILL MARK BRAINLIEST‼️
The probabilities are given as follows:
a. P(number greater than 10) = 1/6.
b. P(number less than 5) = 1/3.
c. The solid is fair, as each side of the dice has the same probability of coming up.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
The total number of outcomes for this problem is given as follows:
12.
2 of the numbers are greater than 10, which are 11 and 12, hence the probability is given as follows:
p = 2/12
p = 1/6.
4 of the numbers, which are 1, 2, 3 and 4, are less than 5, hence the probability is given as follows:
p = 4/12
p = 1/3.
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a tower that is 126 feet tall casts a shadow 139 feet long. find the angle of elevation of the sun to the nearest degree
The value of the angle of elevation of the sun is,
⇒ 40 degree
We have to given that;
A tower that is 126 feet tall casts a shadow 139 feet long.
Hence, We get;
The value of the angle of elevation of the sun is,
⇒ tan θ = Opposite / Adjacent
⇒ tan θ = 126/139
⇒ tan θ = 0.8513
⇒ θ = 40 degree
Thus, The value of the angle of elevation of the sun is,
⇒ 40 degree
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#4- Find the volume of the right prism. Round your answer to two decimal places, if necessary.
Thank you
I’m a bit confused. I know the formula is V=Bh
The base is the 2 rectangles on the side right? I just can’t find the height.
To find the volume of the right prism, we used the Pythagorean theorem to determine the height of the triangular base is 1.197 inches. We then used the formula V = Bh to calculate the volume, which was approximately 2.70 cubic inches.
To find the height of the prism, we need to use the information provided about the triangular base. Since the triangular base is equilateral with a dimension of 1.74 inches, the height of the triangle (and therefore, the height of the prism) can be found by using the Pythagorean theorem.
If we draw a line from the center of the base to the midpoint of one of the sides, we create a right triangle with hypotenuse 1.74 in (which is also the height of the triangle) and one leg equal to half the length of one of the sides of the triangle (since the base of the prism is a square with dimension 1.5 in).
Using the Pythagorean theorem, we can solve for the height of the triangle (and prism)
(1.74/2)² + (1.5/2)² = h²
0.8725 + 0.5625 = h²
h² = 1.435
h ≈ 1.197 inches
Now, we can use the formula V = Bh to find the volume of the prism
V = (1.5 x 1.5) x 1.197 ≈ 2.70 cubic inches
Therefore, the volume of the right prism is approximately 2.70 cubic inches.
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What is the number of possible outcomes for the tree diagram below?
Answer:
It's D. 6.I think i am right,you can choose letter D.If it's be false you can scold me ok?
find the measure of arc
Answer:
its D: 56Step-by-step explanation:
I knew this because i got this wright on my assignment
To pay for the trailer, the company took out a loan that requires Amazon Rafting to pay the bank a special payment of $8,700 in 5 years and also pay the bank regular payments of $4,100 each year forever. The interėst rate on the loan is 14. 3 percent per year and the first $4,100 yearly payment will be paid in one year from today. What was the price of the trailer?
The price of the trailer was $74,041.54.
Let's start by finding the present value of the perpetual annuity payments of $4,100 per year, using the formula:
PV = PMT / r
where:
PV is the present value
PMT is the payment per period
r is the interest rate per period
Since the payments are made annually and the interest rate is 14.3% per year, the interest rate per period is also 14.3%. Thus:
PV = $4,100 / 0.143 = $28,671.33
At a current interest rate of 14.3%, Amazon Rafting would need to invest this much in order to receive permanent $4,100 yearly payments.
Now, using the following calculation, we can determine the price of the caravan using the present value of the perpetuity and the future value of the special payment:
[tex]FV = PV * (1 + r)^n + SP[/tex]
where:
FV is the future value
PV is the present value of the perpetuity
r is the interest rate per period (14.3% per year)
n is the number of periods (5 years)
SP is the special payment of $8,700 over 5 years
Substituting the values we have:
[tex]FV = $28,671.33 * (1 + 0.143)^5 + $8,700[/tex]
FV = $28,671.33 * 1.8333 + $8,700
FV = $74,041.54
Therefore, the price of the trailer was $74,041.54.
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