You need a 75 % alcohol solution. On hand, you have a 260 mL of a 30% alcohol mixture. You also have 95 % alcohol mixture . How much of the 95% mixture will you need to add to obtain the desired solution? You will need mL of the 95% solution

Answer:

10, -7, -35, 5

Step-by-step explanation:

f(9) = -5(-9 + 7) = 10

0 = -5(x + 7)

0 = x + 7

x = -7

f(0) = -5(0 + 7) = -35

-60 = -5(x + 7)

12 = x + 7

x = 5

The statements that are true are angle MNL is complementary to angle KNL and angle GNM is supplementary to angle JNK. Option B and E

Ray NL creates two angles in the lower right quadrant.

The two angles created form a total of  90°, so the two angles formed are complementary. The relation is given as;

∠MNL + ∠KNL = ∠MNK = 90°

Hence ∠MNL and ∠KNL are complementary

∠GNM and ∠JNK are both right angles (and also vertical angles). They sum up to180°. They can be said to be supplementary.

∠GNM and ∠JNK are supplementary

Thus, the statements that are true are angle MNL is complementary to angle KNL and angle GNM is supplementary to angle JNK

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The adjusting entry to registering the Rent revenue shall be as pursues:

Unearned Rent Revenue Debit $6,000

Rent Revenue         Credit      $6,000

(being the adjustment made for Rent Revenue earned)

Adjusting entry to record the Rent Revenue are as follows:

It exists shown that on November 1, the company rented space to another tenant. A check in the amount of $9,000, symbolizing three months' rent in advance, stood obtained from the tenant on that date. The payment stood registered with a credit to the unearned rent revenue account.

Now on December 31, we must organize the adjusting access to record the Rent Revenue for the period (Nov. 1 to Dec. 31) which exists for two months. The Rent Revenue for two months shall be

9000 [tex]*[/tex] 2/3 = $6,000

Therefore the adjusting entry to registering the Rent revenue shall be as pursues:

Unearned Rent Revenue Debit $6,000

Rent Revenue         Credit      $6,000

(being the adjustment made for Rent Revenue earned)

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The complete question is:

On November 1, the company rented space to another tenant. A check for $9,000, representing three months' rent in advance, was received from the tenant on that date. The payment was recorded with a credit to the unearned rent revenue account. Complete the necessary adjusting entry for December 31 by selecting the account names and dollar amounts from the drop-down menus.

Answer:

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Oblique Asymptotes

R(x) will have oblique asymptote if it can be represented in the form

1 / (Q)x

Answer: yes, as long as you haven't used them. :)

Step-by-step explanation:

Answer:

[tex]512 ^{2} [/tex]

the area of the picture

Answer:

y = 33

Step-by-step explanation:

Angle y and 33 are alternate interior angles since the figure is a parallelogram and alternate interior angles are equal

y = 33

Answer:

y = 33°

Step-by-step explanation:

The diagonal of the parallelogram (a transversal) intersects two opposite and parallel sides of the parallelogram  

Then

The angles of measures y° and 33° are Alternate interior angles

Then

they are congruent.

In other words , y = 33°

If the probability of 1 is 0.5; 2 is 0.12; 3 is 0.12; 4 is 0.12; 5 is 0.12 then the graph is somewhat positively skewed and then becomes constant.

Given the probability of 1 is 0.5; 2 is 0.12; 3 is 0.12; 4 is 0.12; 5 is 0.12.

We are required to find whether the graph is constant,symmetric ,negatively skewed or positively skewed.

We can say that the graph is somewhat positively skewed and then it becomes constant.

Positively skewed graph is a graph in which more values exist at the left side of the graph means the tail is started in end.

Constant graph is a graph in which all the values are equal to each other.

In our case except the probability of 1 all the values are 0.12 and the probability of 1 is 0.5.

Hence if the probability of 1 is 0.5; 2 is 0.12; 3 is 0.12; 4 is 0.12; 5 is 0.12 then  the graph is somewhat positively skewed and then constant.

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Answer:

constant

Step-by-step explanation:

Answer:

Step-by-step explanation:

d

The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.

According to the question,

The standard form of the equation whose graph is the line through (1, -2) and (-5, 6). Now first to find slope of the equation using below formula,

Slope of the equation (m)= (change in y axis) / (change in x axis)

= (6- (-2))/(-5 - 1)

= 8/-6

=-(4/3)

Slope of the equation (m) = -4/3. whose graph is the line through (1, -2) and (-5, 6).Formula to find Standard form of the equation is y = mx + c.

-2 = -(4/3) 1 + c

c = -2 +(4/3)

c = -2/3

The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2. y = -(4/3)x -(2/3).

⇒  3y = -4x -2.

Hence, the standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.

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Answer:

0.6 km/hr

Step-by-step explanation:

Speed downstream: 13/5= 2.6 km/hr

Speed upstream: 7/5= 1.4 km/hr

Therefore, Velocity of current is: 1/2 (2.6-1.4) km/hr = 1/2(1.2) km/hr

Answer:

25.2

Step-by-step explanation:

I'll assume you wrote:

[tex]f(x) = 4e^{x-2} - 4[/tex]

So when x = 4:

[tex]4e^{4-2} - 4 = 4e^2 - 4[/tex] ≅ [tex]4\cdot 7.3 - 4 = 25.2[/tex]

Step-by-step explanation:

pls make did make sense, darling!!

The plot of [tex]\sqrt{25-x^2}[/tex] is that of the top half of a circle with radius 5. The interval [-5, 0] captures the left half of this semicircle.

Adding 5 to this shifts the plot up by 5 units. The area under this curve is then the combined area of a square with side length 5 and the area of a quarter circle with radius 5.

So we have

[tex]\displaystyle \int_{-5}^0 5 + \sqrt{25-x^2} \, dx = 5^2 + \frac\pi4\cdot5^2 = \boxed{25 + \frac{25\pi}4}[/tex]

Answer:

[tex]y=\left|\dfrac{1}{2}x-\dfrac{5}{2}\right|+3[/tex]

Step-by-step explanation:

Given equation:

[tex]y=\left|\dfrac{1}{2}x-2\right|+3[/tex]                            

Translation

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

When translating a graph to the right, subtract the number of units from the x variable.

Translating the given graph one unit to the right:

[tex]f(x-1) \implies y=\left|\dfrac{1}{2}(x-1)-2\right|+3[/tex]

Simplifying:

[tex]\implies y=\left|\dfrac{1}{2}(x-1)-2\right|+3[/tex]

[tex]\implies y=\left|\dfrac{1}{2}x-\dfrac{1}{2}-2\right|+3[/tex]

[tex]\implies y=\left|\dfrac{1}{2}x-\dfrac{5}{2}\right|+3[/tex]

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Answer:

Step-by-step explanation:

If two triangles are similar, their corresponding sides will be k times greater or smaller, where k is the scale factor.

We have two corresponding sides given, 6 and 24 or 6k. Using this info, find the value of k:

The other sides of the larger triangle are:

The perimeter is the sum of sides:

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex]\qquad❖ \: \sf \:2x + 6 + 5x + 90 = 180[/tex]

[ by linear pair ]

[tex]\qquad❖ \: \sf \:7x + 6 = 180 - 90[/tex]

[tex]\qquad❖ \: \sf \:7x + 6 = 90[/tex]

[tex]\qquad❖ \: \sf \:7x = 90 - 6[/tex]

[tex]\qquad❖ \: \sf \:7x = 84[/tex]

[tex]\qquad❖ \: \sf \:x = 84 \div 7[/tex]

[tex]\qquad❖ \: \sf \:x = 12[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

[tex]\qquad❖ \: \sf \:x = 12 \degree[/tex]

The amount received net of expenses is $397865 and the percentage of the sale price was 10%.

Given that Bourassas decides to sell a house for $ 440,000. You will be charged a real estate fee of 8% of the sale price, property insurance of 1.4% of the sale price, and an escrow fee of $ 775.

The declared retail price is $ 440,000.

Real estate commission = 8% of the sale price

Real Estate Fee = (8/100) × 440000

Real Estate Fee = 8 × 4400

Real Estate Fee = $ 35,200

Security insurance costs of the title = 1.4% of the sale price

Cost of title insurance = (1.4 / 100) × 440 000

Cost of title insurance = 1.4 × 4400

Title Insurance Cost = $ 6160

The escrow fee assigned is $ 775.

(a) In determining the amount received after deducting the sale price of the property commission, title insurance and escrow fees, we receive

Amount received after fees = sale price - real estate commission - title insurance - escrow fees

Amount received after fees = 440000-35200-6160-775

The amount received after fees = $397865

(b) To find the percentage of sale price, add together all the terms real estate commission, title insurance and escrow fees and divide by the sale price we get

Percentage of selling price=((35200+6160+775)/440000)×100

Percentage of sale price = (42135/440000) × 100

Percentage of sale price = 9.57

Percentage of sale price = 10% (rounded down)

Hence Bourassas decides to sell a house for $440,000, then the amount Bourassas will receive after expenses is $397,865 and the percentage of the sale price of expenses is 10%.

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Because the parabola intercepts the x-axis only once, we conclude that the discriminant is 0.

For a quadratic equation:

y = a*x^2 + b*x + c

The discriminant is:

D = b^2 - 4ac

In the graph we can see that the parabola intercepts the x-axis in its vertex, then the parabola has only one real zero, then we conclude that the discriminant is equal to zero.

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Answer:

  34

Step-by-step explanation:

You want the value of |m² +n²| for m = -5 and n = 3.

Put the values where the variables are in the expression and do the arithmetic.

  |m² +n²| = |(-5)² +3²| = |25 +9| = |34| = 34

The value of the expression is 34.

__

Additional comment

Here, the absolute value bars don't do anything, because the value between them is positive. If it were negative, they would remove the minus sign.

<95141404393>

Answer:

no solutions

Step-by-step explanation:

Explanation:

There are 25 choices for president. Then we have 25-1 = 24 choices for the secretary, and 24-1 = 23 choices for treasurer. This countdown (25,24,23) is because any given person cannot serve in more than one position.

Multiply out those values: 25*24*23 = 13800

Side note: you could use the nPr permutation formula as an alternative path. Plug in n = 25 and r = 3.

πx

Step-by-step explanation:

well pi is defined as the ratio of a circle's circumference to its diameter so just πx

Answer:

C ≈ 14.18

Step-by-step explanation:

Question Given:

A circle has an area of 16mm². Find it's circumference.

Formula:

C = 2√πA

Solve:

C = 2√πA

C = 2√(3.14 × 16)

C = 2√50.24

C = 14.1760361173

C ≈ 14.18

Hence, Circumference is approximately 14.18.

~Kavinsky

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Area of Circle :

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

Now, it's given that area of circle is : 16 mm²

Let's calculate Radius ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} = 16[/tex]

[tex] \qquad \sf  \dashrightarrow \: {r}^{2} = \cfrac{16}{ \pi} [/tex]

[tex]\qquad \sf  \dashrightarrow \: r = \sqrt{ \cfrac{16}{ \pi} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: r = { \cfrac{4}{ \sqrt{ \pi} } }[/tex]

Now,

[tex]\qquad \sf  \dashrightarrow \: circumference = 2\pi r[/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 2 \pi \cfrac{4}{ \sqrt{ \pi} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 8 \sqrt{ \pi} [/tex]

[ for approximate value take pi = 3.14 ]

[tex]\qquad \sf  \dashrightarrow \: c = 8 \sqrt{3.14} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c \approx 8 \times 1.77[/tex]

[tex]\qquad \sf  \dashrightarrow \: c \approx 14.18 \: \: mm[/tex]

Answer:

in case you don't understand feel free to ask bye.