You redo the primitive yo yo experiment (Figure 1), but instead of holding the free end of the string stationary, you move your hand vertically so that the tension in the string equals 2M /3. What is the vertical acceleration of the yo yo's cena of mass? Does it accelerate upward or downward? Express your answer to three significant figures and include the appropriate units. Enter positive value of the acceleration is directed upward and negative value if the acceleration is directed downward. "! A ? + 0 Units dere Value Submit Request Answer Part 6 What is the angular acceleration of the yo-yo around its axis? Express your answer in terms of Rand acceleration due to gravity g. A ROO? Submit Request Answer

According to newton's law of gravitation, the gravitational force(F)  is directly proportional to the product mass of the moon(Mm) and the mass of the planet (Mp) and it is inversely proportional to the square of the separation between them.

Fg ∝ (Mp)(Mm) →(1)

Fg ∝ 1/d²→(2)

Combining equation (1) and (2),

Fg ∝ (Mp)(Mm)/d²

Fg =  G(Mp)(Mm)/d²

This is an equation that describes the relation between mass of moon (Mm) and mass of planet (Mp) and separation(d) between them.

To support the claim in favuor of this equation we use this equation to obtain the value of acceleration due to gravity on earth.

Let m be the mass of an object on earth then Fg between earth (Mp) and mass of an object is obtained by:

Fg =  G(Mp)(m)/R², where R= Radius of earth

This force is equal to the weight of an object i.e.,

g= G(Mp)/R²

Putting the values of G, Mp and R , we get, g=9.81 m/s²

which is the value we obtained on earth for acceleration due to gravity.

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If a second electron is placed close to a proton, the force that would be exerted on the first electron It doubles.

A clear connotation is attached to the term "force." The terms "push" and "pull" are perfectly acceptable at this level to describe forces. Another item applies a force to the first. Both living things and non-living objects can be considered to be parts of a force.

The terms "contact forces" and "non-forces" refer to different kinds of forces. Forces include, among others, nuclear force, gravitational force, frictional force, magnetic force, electrostatic force, and spring force.

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The largest speed this projectile can have without causing the cable to break60.22 m/s.

The horizontal speed of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.

Calculation:-

Mass of the wood, M = 10 kg

Mass of the projectile, m = 0.8 kg

Length of the wire, l = 1.90 m

Maximum tension in the string, T = 500 N

The net force on the string is

F = T - (M+m)g

(M+m)v^2/l = 500 N -10.9 kg *9.8 m/s^2

v = 4.42 m/s

Let the initial velocity of the projectile be vi

By the law of conservation of momentum principle, we have

mvi = (M+m) v

0.8 kg *vi = 10.9 kg *4.42 m/s^2

vi =60.22 m/s

so, the largest speed, the projectile can have is 60.22 m/s

Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.

Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.

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Disclaimer:- your question is incomplete, please see below for the complete question.

A 20.0 kg wood ball hangs from a 1.30 m -long wire. The maximum tension the wire can withstand without breaking is 600 N . A 0.900 kg projectile traveling horizontally hits and embeds itself in the wood ball. What is the largest speed this projectile can have without causing the cable to break?

Original Work:

m = 20 kg wood ball + .9 kg projectile = 20.9 kg

Ft max = 600 N

1.3 m radius

F = mAr = Ft - Fg

m(v^2)/r = Ft - Fg

v = sqrt((r(Ft - Fg))/m)

v = sqrt((1.3m(600N - (20.9 kg)(9.81)))/20.9 kg)

v = 4.96 m/s

The opposing reaction absorbs energy from a process that releases energy in one direction.

A chemical reaction happens when one or more chemicals are changed into one or more other chemicals.

Every chemical reaction involves the transfer of energy in some way.

Exothermic reactions and endothermic reactions are the two different categories of chemical reactions.

An endothermic reaction requires an energy input to continue, whereas an exothermic reaction releases heat (i.e., energy).

In conclusion, if a reaction in releases energy, a reaction in opposite direction absorb energy

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(a) The most probable energy loss is on the order of 20 eV. N.B., energy loss spectra for fast charged particles are very similar in the range of 10 - 70 eV.

(b) Two types of energy loss predominate in fluid flow through a pipe network; major losses, and minor losses.  Major losses are associated with frictional energy loss that is caused by the viscous effects of the medium and roughness of the pipe wall.  Minor losses, on the other hand, are due to pipe fittings, changes in the flow direction, and changes in the flow area.  Due to the complexity of the piping system and the number of fittings that are used, the head loss coefficient (K) is empirically derived as a quick means of calculating the minor head losses.

The term "minor losses", used in many textbooks for head loss across fittings, can be misleading since these losses can be a large fraction of the total loss in a pipe system. In fact, in a pipe system with many fittings and valves, the minor losses can be greater than the major (friction) losses.

Thus, an accurate K value for all fittings and valves in a pipe system is necessary to predict the actual head loss across the pipe system. K values assist engineers in totaling all of the minor losses by multiplying the sum of the K values by the velocity head to quickly determine the total head loss due to all fittings.  

Knowing the K value for each fitting enables engineers to use the proper fitting when designing an efficient piping system that can minimize the head loss and maximize the flow rate.

Therefore, the loss of flow in the piping system occurs due to the fitting done by engineers.

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The piston in Fig. 3.16 is hit with a hammer and the gas initially at T and P is compressed by dV, after which it settles down the statement that is not true is The work done is less than -PdV .

The reversible extra than irreversible beacuse the important thing function why the irreversible is smaller than the reversible is the significance of the outside strain towards which the irreversible paintings is executed towards.

Particles flow from more positive to less positive chemical potential as Particles have a tendency to transport from better chemical capability to decrease chemical capability due to the fact this reduces the loose energy. In this way, chemical capability is a generalization of "potentials" in physics which include gravitational capability.

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The image distance with focal length of 25 cm is 37.50 cm. The magnification is 2.50.

What is focal length?

The focal length is the measure of the converging and diverging capacity of the system which is inverse of the optical power.

The image distance with focal length of 25 cm can be calculated as,

1 / f = 1 / d1 + 1 / d0

d1 = d0f / d0 - f = 15 x 25 / 15 - 25 = -37.50 cm.

The magnification can be calculated by,

M = f / f - d = 25 / 25 - 15 = 2.50

Therefore, the image distance is -37.50 cm and the magnification is 2.50 when the focal length is 25 cm.

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A raindrop of mass 3.29 × 10⁻⁵ kg falls vertically at constant speed under the influence of gravity and air resistance as it falls 140 m, the work done on the raindrop by the gravitational force is 45.1 mj .

In the question we have ,

Mass = 3.29 × 10⁻⁵ kg

Height = 140 m

Due to the effects of gravity and air , it falls vertically at a constant speed. We need to find the work that gravity gives the raindrops.

W = mgh

Here we know,

g = 9.8 m/s

Therefore,

W = 3.29 × 10 ⁻⁵ kg × 9.8 m/s × 140 m

W = 0.0451388 j

Hence, we get

W = 45.1 mj

Hence, the work done is 45.1 mj

Newton's law of universal gravitation states that all particles generally attract all other particles in the universe with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

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Answer:

C.

Explanation:

The magnetic force on the electron would be directed to the east.

What is magnetic force?
One of four basic forces of nature, the electromagnetic force, results in the magnetic force, which is brought about by the motion of charges. When two charge-containing objects move in the same direction, a magnetic attraction pulls them together. Similar to this, there is a repulsive force between charged objects moving in opposite directions.

We discovered how moving charge envelops itself with a magnetic field in our article on magnetic fields. The magnetic force in this context is a force that results from interacting magnetic fields.

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Q1 > Q2 > Q3 ranks the charge Q stored on the capacitors after they are fully charged voltage.

V=Q/R

voltage=v

charge=q

resistance=r

so the order will be Q1 > Q2 > Q3

The difference in electric potential per unit charge between two points in an electric field is referred to as voltage. The letters "V" or "E" are used to represent voltage in calculations and other mathematical contexts. The force that propels electrons across the circuit is produced by the voltage or potential difference.

A larger flow of electrons will cross the circuit with increased voltage and force. Without a difference in voltage or potential, electrons would randomly move through a vacuum. Another name for voltage is electric tension. For example, low tension, high tension, and super tension cables' respective voltage handling capacities are referred to as 1, 11, and 33 kV.

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the total distance traveled is three at T equaling three times the period.

Any position as a function of time can be described as simple harmonic motion using the following two components: The distance between the motion's centre and either extremity is known as amplitude. Period: The time required for a motion to complete one full cycle.

The object moves in a simple harmonic motion with an amplitude of X and a period of T when it is knocked out of balance. As the object moves through equilibrium, its top speed happens. The time T decreases as the spring stiffness increases.

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7.5 hr time will it take the trains to be 1,050 miles distance apart

f(x) = 80x

g(x) = 60x

h(x) = 140x

1,050  = 140x

x=1,050/ 140 = 7.5 hr

Distance is the length between two points or things, and it is directionless. Since distance is a scalar property, it only takes into account the total magnitude and ignores the start and finish locations. Being a scalar attribute, distance can only be positive or zero; it cannot be the opposite.

Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most common unit of measurement for distance (mm). When calculating distance, the letter D is frequently used to denote the distance traveled.

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The weight (in pounds) of a 1 kg bag of sugar is 2.203 pounds.

What is weight?

Weight of any given object can be defined as the force acting on the given object due to gravity which is a vector quantity. It can be calculated by multiplying acceleration due to gravity with the given mass of the object. The weight of an object can be different on the earth an on the surface of the moon.

The weight of 1 kg sugar can be calculated as,

W = gm

where W is the weight, g is the acceleration due to gravity and m is the mass

W = 9.8 m/s^2 x 1 kg = 9.8 N

To convert weight in N to weight in pound, divide the weight by 4.45,

9.8 / 4.45= 2.203 pounds.

Therefore the weight in pounds of a 1 kg sugar bag is 2.203 pounds.

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An isolated ground receptacle separates the supply grounding conductor from other grounded devices and materials.

An isolаted ground receptаcle hаs а grounding terminаl thаt hаs no contаct with the receptаcle mounting strаp or yoke. When instаlled аgаinst а grounded metаl box, the receptаcle mounting strаp is grounded. The receptаcle’s isolаted ground terminаl is then connected to аn аdditionаl insulаted grounding conductor thаt is instаlled аs а sepаrаte grounding pаth for the reduction of electricаl noise on the sensitive electronic equipment plugged into the receptаcle.

The isolаted ground receptаcle in the pаtient cаre spаce but outside the pаtient cаre vicinity (left) must be supplied by а metаl rаcewаy or cаble system thаt quаlifies аs аn equipment grounding conductor. The box must be grounded by а green insulаted wire type equipment ground аnd the isolаted ground receptаcle terminаl requires а green insulаted equipment grounding conductor with one or more yellow stripes.

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More bilateral transfer occurs from the preferred limb to the non-preferred limb than the opposite occurs.

Your given name, which is also known as the first name, is the name your parents gave you when you were born. Typically, middle names are given as initials rather than full names, and this is true for the initial as well.

On the last page, there is a mark that reads "I." Pen and ink are used for physical documentation. The initial is unique to the person using it, not unlike a signature in that it is not a generic symbol. To show that you have read the page and accepted its terms, please add a small personalization.

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Beta decay process is occurring when an unstable nucleus releases radiation in the form of an electron particle .

Radioactive decay is a process that involves the emission or release of a particle or energy as one atom changes its form into another . Radioactive decay can be alpha decay which involves emission of helium ions from the nucleus of an unstable atom . Beta decay is accompanied by the release of an electron and  transformation of a proton into a neutron in the nucleus .Beta decay can be further classified into three processes - electron emission , positron emission and electron capture .

Beta decay process is occurring when an unstable nucleus releases radiation in the form of an electron particle .

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The quickly moving particles experience insignificant attraction forces for one another, therefore gases do indeed expand to fill the volume and form of their container.

The attraction forces is an attraction that draws the body to it. In nature, there are many alluring forces at work. Among these are gravitational force, magnetic force, electric force, and electrostatic force. When a gases is heated, the particles' kinetic energy rises, which causes the gases to expand. When a gas is heated, the container's volume needs to be raised in order to maintain the pressure.

Because the quickly moving particles encounter low attraction forces for one another, gases expand to fill the volume and shape of their container.

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We learn about a star from a life track on an h-r diagram, when it will die where it is located, what surface temperature and luminosity it will have at each stage of its life, how long ago it was born.

The Hertzsprung–Russell diagram, abbreviated as H–R diagram, HR diagram or HRD, is a scatter plot of stars showing the relationship between the stars' absolute magnitudes or luminosities versus their stellar classifications or effective temperatures. The diagram was created independently in 1911 by Ejnar Hertzsprung and by Henry Norris Russell in 1913, and represented a major step towards an understanding of stellar evolution.

There are several forms of the Hertzsprung–Russell diagram, and the nomenclature is not very well defined. All forms share the same general layout: stars of greater luminosity are toward the top of the diagram, and stars with higher surface temperature are toward the left side of the diagram.

The original diagram displayed the spectral type of stars on the horizontal axis and the absolute visual magnitude on the vertical axis. The spectral type is not a numerical quantity, but the sequence of spectral types is a monotonic series that reflects the stellar surface temperature.

Modern observational versions of the chart replace spectral type by a color index (in diagrams made in the middle of the 20th Century, most often the B-V color) of the stars. This type of diagram is what is often called an observational Hertzsprung–Russell diagram, or specifically a color–magnitude diagram (CMD), and it is often used by observers.

In cases where the stars are known to be at identical distances such as within a star cluster, a color–magnitude diagram is often used to describe the stars of the cluster with a plot in which the vertical axis is the apparent magnitude of the stars. For cluster members, by assumption there is a single additive constant difference between their apparent and absolute magnitudes, called the distance modulus, for all of that cluster of stars.

Early studies of nearby open clusters (like the Hyades and Pleiades) by Hertzsprung and Rosenberg produced the first CMDs, a few years before Russell's influential synthesis of the diagram collecting data for all stars for which absolute magnitudes could be determined.

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As we move from left to right the metalic properties decreases and non-metalic property increases hence reactivity of the elements decreases.

It happens because there are more valence shells and less interaction between valence electrons and the nucleus. Consequently, the propensity to take electrons from other atoms declines. Atoms get more electronegative as they move through a period.

The ability to lose electrons increases generally with atom size. The capacity to lose electrons increases with increasing shielding. The most active metal is to the left and down because metallic character grows down the table and diminishes across it.

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Northeasters often bring heavy snowfall.

A Nor’easter is a hurricane alongside the East Coast of North America, so known due to the fact the winds over the coastal vicinity are usually from the northeast. these storms may occur at any time of yr but are most frequent and most violent between September and April. some widely recognized Nor’easters consist of the notorious snowfall of 1888, the “Ash Wednesday” hurricane of March 1962, the new England blizzard of February 1978, the March 1993 “Superstorm” and the current Boston snowstorms of January and February 2015.

Those storms progress commonly northeastward and typically achieve maximum intensity near New England and the Maritime Provinces of Canada. They nearly always convey precipitation in the form of heavy rain or snow, as well as winds of gale pressure, rough seas, and, every now and then, coastal flooding to the affected regions.

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EMF induced in loop is - 0.011304 volt.

Given,

radius of the loop , r = 17 cm

= 17 cm (1[tex]0^-^2[/tex]m/ 1cm)

= 0.17 m

area of the loop ,  A  = π[tex]r^2[/tex]

= (3.14)(0.17[tex])^2[/tex]

= 0.045216 [tex]m^2[/tex]

resitance of loop ,   R= 7.5 Ω

(a)

Between t= 0 sec and t= 1sec,

B/dt = 0.5 T/2 s = 0.25T/s

Hence , emf is induced in the loop during the following

time intervals is ,

V = A dB/dt

= (0.045216 [tex]m^2[/tex] )(0.25 T/s)

= 0.011304 volt

(b)

since ,

Between t= 2 sec and t= 4sec,

dB/dt =  0 T / 2 s =  0 T/s

Hence , emf is induced in the loop during the following

time intervals is ,

V = A dB/dt

= (0.045216 [tex]m^2[/tex] )(0  T/s)

= 0  volt

(c)

Between t= 4 sec and t= 6 sec,

dB/dt = ( - 0.5 T/ 2 s ) =  - 0.25 T/s

Hence , emf is induced in the loop during the following

time intervals is ,

V = A dB/dt

= (0.045216 [tex]m^2[/tex] )(- 0.25 T/s)

=  - 0.011304 volt

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The angular speed when in the straight position is 6.61rad/sec

We know that angular speed is defined as change of angular displacement in per unit time

Angular speed have proper relation with linear speed.

If she is making rotation around any circular track of radius R, then the total distance travelled by her will be 4πR.

In 1 rotation she travelled =perimeter of circle=2πR

Therefore, in 2 rotations =2×2πR=4πR

Means,4πR distance is travelled in 1.9sec

Threfore,2πR distance is travelled in =(1.9×2πR)/4πR=1.9/2=0.95sec

Now, total angular displacement in straight position is=2π  

So, applying the formula, we get angular speed(ω)=2π/0.95

=>ω=(2×3.14)/0.95

=>ω=6.28/0.95

=>ω=6.61rad/sec.

Hence, angular speed is 6.61rad/sec..

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Answer:

2.3 mL has only 2 significant figures.

An accurate solution can have only 2 significant figures (density = 2.0)

Increasing the wavelength of the light increases the spacing between different fringes since the spacing between different fringes is wavelength dependent.

The spacings among different fringes decreases as the space between the slits increases because it is dependent on L. Growing the wavelength of the light will increase the spacing among unique fringes for the reason that spacing between exclusive fringes is wavelength based.

The distinction in distance traveled through the 2 waves is one complete wavelength, that is, the direction distinction is 1 λ. when the path difference is one complete wavelength, a crest meets a crest and optimistic interference happens.

They unfold aside the intense spots spread aside. So in different words, if I had been to transport these distances and the slits nearer together, you will see these vibrant spots get farther and farther faraway from each other on the screen.

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A. The hang time of the ball is 5.52 seconds

B. The horizontal displacement of the ball is 149.04 m

A. How do I determine the hang time?

We'll begin by obtaining the time require for the ball to reach the maximum height. This can be obtained as follow:

v = u - gt (Since the ball is going against gravity)

0 = 27 - (9.8 × t)

0 = 27 - 9.8t

-9.8t = 0 - 27

-9.8t = -27

Divide both sides by -9.8

t = -27 / -9.8

t = 2.76 s

Now, we shall determine the hang time. This is shown below:

T = 2t

T = 2 × 2.76

T = 5.52 s

Thus, the hang time is 5.52 seconds

B. How do I determine the horizonat displacement?

The horizontal displacement of the ball can be obtained as follow:

Horizontal displacement = initial velocity × hang time

Horizontal displacement = 27 × 5.52

Horizontal displacement = 149.04 m

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81 joule is the kinetic energy of the golf ball.

K.E= mv²/2

K.E=0.045×60×60÷2

K.E=81 joule

Kinetic energy is a particular kind of power that is present in moving particles or objects. An object gains kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. Kinetic energy is a property of motion that depends on the mass and speed of an object or particle. Motion is any combination of vibration, axis rotation, translation, and movement (along a path from one location to another). A body's translational kinetic energy, which is determined by multiplying its mass, m, by the square of its speed, v, is equal to 1/2mv2.

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The main distinction between enthalpy and entropy, which exists despite the fact that they are both components of a thermodynamic system, is that enthalpy is represented as the total amount of heat content while entropy is the level of disorder.

SO₂ (g) + 2H₂S (g) ⇄ 3S(s) + 2H₂O (g)

The standard ΔG and ΔH of the products less the standard ΔG and ΔH of the reactants may be used to calculate the ΔG and ΔH of the reaction. So, the reaction's ΔG is:

ΔGr = 3ΔG S(s) + 2ΔG H₂O (g) - ( ΔG SO₂ (g) + 2ΔG H₂S (g))

ΔGr = 3×0 kJ/mol + 2×-228,6 kJ/mol - (-300,4 kJ/mol + 2×-33,01 kJ/mol)

ΔGr = -90,78 kJ/mol

In the same way, ΔHr is:

ΔHr = ΔH S(s) + 2ΔH H₂O (g) - ( ΔH SO₂ (g) + 2ΔH H₂S (g))

ΔHr = 3×0 kJ/mol + 2×-241,8 kJ/mol - (-296,9 kJ/mol + 2×-20,17 kJ/mol)

ΔHr = -146,36 kJ/mol

A ΔH < 0  indicates that heat is being produced by the process. According to Le Chatelier's principle, which states that changes in a system's temperature, pressure, volume, or concentration will result in predictable and opposing changes in the system, raising the temperature will result in the production of less product, while lowering the temperature will result in the production of more product.

As 2 moles of gas produce 5 moles of gas if the pressure decreases the system will try to produce more gas opposing the change, and again if the pressure increases the system will try to produce less gas.

complete Question :

using relative enthalpy and entropy values, determine how the process is affected after each of the following temperature or pressure changes? consider that a more effective reaction produces more product or more product in a shorter amount of time.

Reaction: SO₂ (g) + 2H₂S (g) ↔ 3S(s) + 2H₂O (g)Substance | ΔG kJ/mol | ΔH kJ/molH₂O(g) | -228.6 | -241.8H₂O(l) | -237.1 | -285.8SO₂(g) | -300.4 | -296.9SO₃(g) | -370.4 | -395.2H₂S(g) | -33.01 | -20.17S(s) | 0 | 0Categorize into: "More Effective" ~ "Less Effective" ~ "Equally Effective"

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A 2200 pF capacitor is charged to 130 V and then quickly connected to an inductor. The frequency of oscillation is observed to be 10 kHz. The inductance produced is 4.54 H.

The angular frequency of the oscillations in the LC circuit is given by:

        ω  = 1/[tex]\sqrt{LC}[/tex]

where,  ω= angular frequency

             L=inductance

             C=capacitance

Given,

C=2200 pF

= [tex]2.2 \times 10^{-9}[/tex] F

ω =10 kHz

= [tex]10 \times 10^{3}[/tex] Hz

= [tex]10^{4}[/tex] Hz

We have to find L(inductance).

Using the above equation, we get L=1/C × ω^2

Now putting the given values we get,

L=1/[tex]2.2 \times 10^{-9} \times 10^{4} \times 10^{4}[/tex]

 =1/[tex]2.2 \times 10^{-1}[/tex]

 =4.54 H(henry) [SI unit of inductance is henry]

So for given values the inductance in the circuit is 4.54 H(henry).

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The balloon will go upward with acceleration of 3.1 m/s².

The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force. Upthrust is another name for this upward thrust. A body submerged partially or completely in a fluid appears to lose weight, or to be lighter, due to the buoyant force.

Given that

Mass of the balloon = 80 g = 0.080 kg.

Volume of the balloon = 0.3 m³.

So, weight of the balloon =  0.080 × 9.8 N = 0.784 N.

Buoyant force acting on the balloon = 0.3 × 0.35 × 9.8 N = 1.029 N.

Hence, net upward force acting on the balloon is =   1.029 N -  0.784 N =  0.248 N.

So, upward acceleration of the balloon = 0.248/0.080 m/s² = 3.1 m/s².

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