The average acceleration vector of the ball is - 9.78 m/s².
When you throw a ball upward with an initial speed, it will go up until reaching its highest peak then it will go down. So the ball doing non-uniform motion. The formula for non-uniform motion including initial speed, and final speed with time is
v = u+at
u = initial speed (m/s) = 4.5 m/sv = final speed (m/s) = - 4.5 m/s (because it's going down)t = elapsed time (s) = 0.92 sa = acceleration (m/s²)v-u = at
[tex]a = \frac{v - u}{t}[/tex]
[tex]a = \frac{- 4.5 - 4.5}{0.92}[/tex]
[tex]a = \frac{- 9.0}{0.92}[/tex]
a = 9.78 m/s²
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A diver runs horizontally off the end of a 3.0-m-high diving board with an initial speed of 1.8 m/s. Find her y positions at the times t = 0.25 s , t = 0.50 s , and t = 0.75 s .
(a) At time, t = 0.25 s, the y position of the driver is 0.31 m.
(b) At time, t = 0.50 s, the y position of the driver is 1.2 m
(c) At time, t = 0.75 s, the y position of the driver is 2.76 m
What is the position of the driver?The position of the driver at the various time is determined by applying the following kinematic equation.
y = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the drivert is the time of motion of the drivery is the vertical position of the driver at various timet is the time of motionSince the driver runs horizontally, the initial vertical velocity = 0
y = 0 + ¹/₂gt²
y = ¹/₂gt²
at time, t = 0.25 s, the y position of the driver is calculated as;
y = ¹/₂gt²
y = ¹/₂(9.8)(0.25)²
y = 0.31 m
at time, t = 0.5 s, the y position of the driver is calculated as;
y = ¹/₂gt²
y = ¹/₂(9.8)(0.5)²
y = 1.2 m
at time, t = 0.75 s, the y position of the driver is calculated as;
y = ¹/₂gt²
y = ¹/₂(9.8)(0.75)²
y = 2.76 m
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I need help with question 1
Answer:
V = 140 km/h
Explanation:
Velocity is the change in position over time.
We can use the equation V = Δx / t
Note that V is the average velocity.
We are given Δx and t. Lets solve for V.
[tex]V=\frac{540}{4}[/tex]
[tex]V=140[/tex]
[tex]\frac{km}{hour}[/tex]
V = 140 km/h
How is the 12 volt potential difference of the car battery shared between the six heating
elements?
Answer:
To say we have a 12.0-V battery implies that its terminals have a 12.0-V likely contrast. At the point when such a battery moves charge, it puts the charge through an expected distinction of 12.0 V, and the charge is given an adjustment of potential energy equivalent to Δ U = q Δ V .
six cells
There are six cells to a 12 volt lead corrosive battery. A battery cell's greatest capacity to convey current (amps).
A 12 V lead-stockpiling battery comprises of six cells, each delivering roughly 2 V. The genuine standard cell potential is acquired from the standard decrease possibilities. In light of the positive and negative charges on the battery terminals, an electric potential contrast exists between them.A 6 cell lithium particle pack has an ostensible voltage of 21.6V to 22.2V and a most extreme charge voltage of 25.2 volts
Explanation:
One volt is the likely contrast between two focuses in an electric circuit when 1 joule of work is finished to move charge of 1 coulomb from one highlight other.A completely energized 12 volt battery ought to peruse at 12.6 volts on the multimeter. In the event that the perusing is lower than this, you'll need to accuse your battery of either a battery charger or by taking your vehicle for a drive.A 12 volt 105 AH battery can supply (under wonderful circumstances and to 100 percent release) 12 x 105, or 1260 Watt-hours (1.26 kWh).between 5 to 8 hoursThe short response is that a 200-watt sunlight based charger that creates 1 amp of current takes between 5 to 8 hours to charge a 12-volt vehicle battery totally.A 100Ah 12 volt profound cycle lead-corrosive battery can run a 100W ceaseless DC load for 6 hours whenever released to half as suggested. A 100Ah 12 volt lead-corrosive profound cycle battery could run a 100W evaluated AC food-blender for 7 hours with half Profundity of Release.Voltage contrast among An and B, VAB=(I1+I2)6=(2−1)6=6 volts.the systems shown are in equilibrium. if the spring scales are calibrated in newtons, what do they read?
Newton's first law states that an object at rest will remain at rest, and an object in motion won't change its velocity while the equilibrium condition is met.
When a system is in equilibrium then?When Newton's first law is true, the thing is in its equilibrium condition. When all external forces acting on an object (including moments) are balanced, that object is said to be in equilibrium in the reference coordinate system. This indicates that all external forces and moments acting on this item have a net effect of zero. When an object is at rest or moving with a constant speed in a reference coordinate system, respectively, they are said to be in static equilibrium and dynamic equilibrium.The inertial force produced by the velocity change can be measured by multiplying the mass with the translational acceleration or the mass moment of inertia with the angular acceleration.To Learn more About Newton's first law refer to :
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how do permanent dipoles compare to dispersion forces and temporary dipoles in terms of formation and strength?
Permanent dipoles are created by the interaction of permanent charges, which are charges that do not lose their charge when they are separated, as opposed to temporary dipoles, which form when two unlike poles come into contact and then separate.
Permanent dipoles are strong; they can be formed even when there is no electrical current present. The strength of a permanent dipole depends on its size and intensity, but it's typically much stronger than a temporary dipole.
Dispersion forces are weaker than both permanent dipoles and temporary dipoles. They can be generated by any two objects whose surfaces have different charges, regardless of whether there is an electrical current present or not.
The strength of dispersion forces depends on the size and intensity of the charged object, but it's typically much weaker than a permanent or temporary dipole.
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suppose i produce radio waves with an antenna that have a peak electric field amplitude e and peak magnetic field amplitude b. if i were to double the amplitude of the electric field (i.e. double e) what is the new value for b?
The formula for the relationship between the electric and magnetic fields is:
E = cB
As the amplitude of the electric field is precisely proportional to the magnetic field, the magnetic field will also double in size when the amplitude of the electric field doubles.
Radio waves typically operate at frequencies between 300 gigahertz and below, where the longest wavelengths of the electromagnetic spectrum are found. At 300 GHz, the corresponding wavelength is 1 mm; nevertheless, at 30 Hz, it is 10,000 kilometers.
A magnetic field, a vector field that affects an electric charge, an electric current, and magnetic materials magnetically. In a magnetic field, a moving charge experiences an external force that is perpendicular to the magnetic field and has its own velocity.
The maximum electric and magnetic field strength is known as the amplitude in electromagnetic waves. The wave amplitude determines the energy of the wave. Similar to how waves themselves move, the energy density also follows the electric and magnetic fields.
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A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mark while practicing for a race.
A linear track beings at 0 meters and has a total distance of 100 meters, then she will go 55 meters. Hence, option D is correct.
What is speed?The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has quantity but no orientation as a unit of measurement.
Let A represent Juliet's position. O is the starting point with OA = 10, AB = 45, and OP = 100 as its coordinates.
The location of Juliet following running 45 meters will therefore be 55 m, as may be seen from simple math. In the figure, it is OB.
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Your question is not complete, your question probably be :
A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mar
while practicing for a race.
After running 45 meters, how far is she from the beginning of the track?
10 meters
35 meters
45 meters
55 meters
why do you think it was initially difficult for astronomers to entertain the possibility that the spectra of quasars are highly red shifted
In the 1960s, it was proposed that quasars could be compact objects ejected quickly from the cores of adjacent regular galaxies.
Why did it take so long for astronomers to comprehend quasar spectra?Nobody anticipated that an object that resembles a star could have its spectral lines so drastically redshifted.
It's a concept that makes sense when you consider that as light's wavelength is extended, the spectral lines appear to have "shifted" toward the red portion of the spectrum.
Sound waves experience a similar effect when a source moves in relation to an observer.
As a result of the emission lines being "red shifted," astronomers initially had trouble distinguishing them in quasar spectra at optical wavelengths.
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suppose that the quarterback takes 0.30 ss to return to the ground after throwing the ball. how far ddd will he move horizontally, assuming his speed is constant?
The quarterback is located 0.3v above ground. The fundamental element of every projectile's body that is moving is its horizontal velocity (vx).
What is horizontal velocity?The fundamental element of every projectile's body that is moving is its horizontal velocity (vx). In any projectile motion, it is typically utilized to know the velocity value at which the particle travels along the horizontal direction. It's even thought of as the body's starting point for movement.
Let's say the projectile-moving particle reaches the highest point of its horizontal path. In that case, the horizontal velocity will typically be zero since the force of gravity will cause it to fall vertically downward as soon as it reaches the peak point. Vertical velocity has no impact on this horizontal velocity when it is at its highest point.
Let the horizontal velocity of the object = v
X = vt
X = 0.3v
Thus, The quarterback is located 0.3v above ground.
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What wavelength is the maximum absorbance observed in the spectrum displayed in figure 10. 11? report your answer using 3 significant figures.
The spectrum shown has a maximum absorption of 278.4 nm.
The absorbance between 400 and 650 nm is measured, often at intervals of 25 nm, to identify the wavelength of maximum absorption. To identify the wavelength of greatest absorption, the data can be analyzed or graphed.
The useful absorbance range for the majority of spectrometers and colorimeters is between 0.1 and 1. Values of absorbance more than or equal to 1.0 are excessive. Your solution is overly concentrated if the absorbance readings you are getting are 1.0 or higher.
Maximum Absorbance refers to an area with the highest absorbance level. We can infer from the graph that the absorbance is at its highest at wavelength 278.45 nm.
Therefore, maximal absorbance occurs at 278.4 nm wavelength.
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a car with a mass of 1,020.0 kg accelerates from 0 to 94.0 km/h in 10.0 s. the driver applies the brakes when the car is moving at 94.0 km/h, and the car comes to rest after traveling 38.0 m. what is the net force (in n) on the car during its deceleration? (assume the car is traveling in the positive direction. indicate the direction with the sign of your answer.)
The net force on the car during its deceleration = 9139.2 N
What is deceleration?Deceleration is actually inversely related to acceleration. We know that acceleration is the rate at which an object is speeding up, and deceleration is the rate at which an object is slowing down. For example, when you brake while driving, deceleration is used to slow the vehicle.
Given, m= 1020 kg
u= 0 m/s
V = 94 km/h or 26.1 m/s
t = 10 s
For deceleration
u = 26.1 m/s
v = 0
S = 38 m
by equation of motion ;
v² = u² + 2as
0 = 26.1² + 38a
a = - 8.96 m/s²
Net force during deceleration:
F= m*a
F= 1020 × 8.96
F = 9139.2 N
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a solenoid is wound with a single layer of insulated copper wire (of diameter 1.0 mm) and is 14.6 cm in diameter and 1.4 m long. how many turns are on the solenoid? assume that adjacent wires touch and that the insulation thickness is negligible.
How many turns are on the solenoid? The number of turns on solenoid are 1.400 turns
To find how many turns on solenoid can be calculated as follows:
Given data,
[tex]d[/tex] (diameter of copper wire) = 1mm = 1×[tex]10^{-3}[/tex]m
[tex]D[/tex] (diameter of solenoid) = 14.6cm = 0.146m
[tex]l[/tex] (length of solenoid) = 1.4m
Next, to determine how many turns on solenoid, we can use the formula below:
[tex]N=\frac{l}{d}[/tex]
[tex]N=\frac{1.4}{0.001}[/tex]
[tex]N=1.400[/tex] turns
Therefore, the number of turns on solenoid are 1.400 turns
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Can a spectrophotometer be used to measure the absorption of a particular wavelength of light that is not visible to the human eye?.
Yes, a spectrophotometer could be used to measure the absorption of a particular wavelength of light that is not visible to a normal human eye.
Although we cannot directly observe the absorption of this light, it is quantifiable. A spectrophotometer, which measures the absorption of light at certain wavelengths (whether visible or not) by a solution, may be used to compute the concentration. The popular and accessible technique of spectrophotometry may be used to determine the concentration of compounds in a solution or the degree of light absorption.
When a light beam is focused through the sample, each component either absorbs or transmits light of a certain wavelength. They are combined with quantifiable and visible colored byproducts. Another is that, as observed by a spectrophotometer, colorless substances generally absorb light from the region of the spectrum that is imperceptible to the human eye.
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the tide that results from a lunar wave is larger than the solar wave. group of answer choices true false
The given statement is true. A lunar eclipse happens when the Moon passes into the shadow of the Earth. A solar eclipse happens when the Moon passes between Earth and the Sun.
What is lunar wave and solar wave?A lunar eclipse happens when the Moon passes into the shadow of the Earth. This is only possible when the Sun, Earth, and Moon are precisely or extremely closely aligned with Earth between the other two, which can happen only on a full moon night when the Moon is close to either lunar node.
A solar eclipse happens when the Moon passes between Earth and the Sun, completely or partially blocking Earth's view of the Sun. A new moon corresponds with such an alignment, showing that the Moon is closest to the plane of the Earth's orbit. The Moon completely obscures the disk of the Sun during a total eclipse.
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The given statement is true. A lunar eclipse happens when the Moon passes into the shadow of the Earth. A solar eclipse happens when the Moon passes between Earth and the Sun.
What is lunar wave and solar wave?When the Moon enters the shadow of the Earth, an eclipse occurs. This can only occur on a full moon night when the Moon is close to either lunar node, when the Sun, Earth, and Moon are precisely or extremely closely aligned with Earth between the other two.When the Moon passes in front of Earth and the Sun, covering Earth's view of the Sun entirely or in part, a solar eclipse occurs. Such an alignment is accompanied by a new moon, demonstrating that the Moon is closest to the plane of the Earth's orbit. A total eclipse occurs when the Moon totally blocks out the Sun's disk.To learn more about Lunar and solar eclipse refer to:
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What is the process that causes harmful materials to seep into the ground and move through rock and soil and contaminate ground water?.
he weight of a body is 50N. how much force is needed to move it vertically upward with 5ms-2 acceleration
5.5 Newton force is needed to move it vertically upward with 5ms-2 acceleration
m=5.1 kg
a= 5m/s²
F=ma
F=5.1×5
F=5.5 N
Every action that attempts to maintain, modify, or change the motion of a body is referred to as a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).
According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight route in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changing velocity) in the direction of the force.
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consider a monochromatic electromagnetic plane wave propagating in the z direction. at a particular point in space, the magnitude of the electric field has an instantaneous value of 442 v/m in the positive x-direction. what is the instantaneous magnitude of the poynting vector at the same
The instantaneous magnitude of the poynting vector will be 518.48.
To calculated magnitude of the poynting vector, we require to use the formula of poynting vector
S = E*B/u
since B = E/c
so , S = E^2 /uc
where , E is the electric field and B is the magnetic field ,
S is the poynting vector magnitude and c is the speed of light.
Putting the values, we get
S = (442x442) /uc
S = 195364 / uc
uc = 4πx[tex]10^{-7}[/tex] x 3 x [tex]10^{8}[/tex]
uc = 376.8
Now, S = 195364/376.8
S = 518.48
Hence The instantaneous magnitude of the poynting is 518.48.
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for a double slit experiment, what is the smallest separation (in nm) between two slits that will produce a second-order maximum for 652 nm visible light?
The smallest separation in terms of nm between two slits that will produce a second-order maximum for 652 nm visible light is 1.30 um
Since the relationship between wavelength and angle for minima and maxima in Young's double slit experiment is:
For constructive interference
d sinθ = n
for Destructive interference
d sinθ = (n+1/2)λ, where λ is the wavelength, n is the order of maxima and minima, Since here n = 2
So the separation, λ = 652 nm , and θ = 90
so, d sin90 = 2*652*10⁻⁹
=> d= 2*652*10⁻⁹/ sin90
= 1.30 X10⁻⁶
= 1.30 цm
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discuss the statistical nature of the clausius statement of the second law that energy cannot go spontaneously from a colder to a hotter body. under what conditions is the statement applicable? in what sense is this statement incorrect?
It is true that clausius statement of the second law states that energy cannot go spontaneously from a colder to a hotter body.
What is second law of thermodynamics and what is clausius statement of the second law of thermodynamics?Second law of thermodynamics is the law stating that heat and energy are interconvertible and is transferred from one form to another.Clausius statement of the second law of thermodynamics states the same but it also states that energy and heat cannot be transferred from colder to hotter body.It simply justifies that heat cannot be transferred from hot reservoir to cold reservoir at any cost.The condition under which the clausius statement is true is that the entropy change should be greater or equal to zero.Hence if entropy change is zero or greater than zero then clausius statement is truly justified.To know more about thermodynamics visit:
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a 873-kg (1930-lb) dragster, starting from rest, attains a speed of 26.3 m/s (58.9 mph) in 0.59 s. find the average acceleration of the dragster during this time interval. what is the magnitude of the anverage net force on the dragster durng this time?
The average acceleration of the dragster during this time interval is 44.57 m/s² and the average net force on the dragster during this time is 38915N.
The initial speed U of the dragster is zero while the final speed V of the dragster is 26.3m/s. The director runs for a total of time t of 0.59 seconds.
According to the equation of motion,
V = U+at
Putting values,
26.3 = 0.59a
a = 44.57 m/s².
So, the acceleration of the dragster is 44.57 m/s².
The force on the director is given by,
F = ma
m mass of the dragster and a is the acceleration of the dragster.
F = 873×44.57
F = 38915N.
So, the net average force on the dragster during this time is 38915 Newton.
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a dockworker loading crates on a ship finds that a 29-kg crate, initially at rest on a horizontal surface, requires a 71-n horizontal force to set it in motion. however, after the crate is in motion, a horizontal force of 50 n is required to keep it moving with a constant speed. find the coefficients of static and kinetic friction between crate and floor.
The coefficients of static and kinetic friction between crate and floor are
0.25 and 0.176 respectively.
When a body is at rest and if a force is applied to move it, then it would require the force which is equal to the static friction force, if
fs is the static frictional force and the us is the static friction coefficient and Fn is the normal force
[tex]f_{s}[/tex] = us*Fn
Fn = mg
putting the appropriate values, we get
= 71/(29*9.8) = 71/284.2
= 0.2498 = 0.25
Now, similarly when body is in motion, kinetic frictional force is applied, so we can write
[tex]f_{k}[/tex] = uk*Fn
so putting the appropriate values, we get
= 50/mg = 50/284.2 = 0.1759
= 0.176
Hence the value of coefficient of static friction is 0.25 and the value of coefficient of kinetic friction is 0.176.
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. a car going around a curve of radius r at a speed v experiences a centripetal acceleration ac. what is its acceleration if it goes around a curve of radius 3r at a speed of 2v?
The acceleration of the car that goes around a curve of radius 3r at a speed of 2v is 4 / 3 ( ac )
ac = v² / r
ac = Centripetal acceleration
v = Linear / tangential velocity
r = Radius of curve
This the acceleration of the car that goes around a curve of radius r and velocity v.
For a car that goes around a curve of radius 3r at a speed of 2v,
ac' = ( 2v )² / 3r
ac' = 4v² / 3r
ac' = 4 / 3 ( ac )
Therefore, the acceleration of the car that goes around a curve of radius 3r at a speed of 2v is 4 / 3 ( ac )
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If an object accelerates from rest to its final vermouth in 12.3 s what is the final velocity if it traveled 200m
the final velocity is 10.50 m/s.
calculation:
time t= 12.3 s
distance s= 200u=0
equations are, v² = u² + 2as,
s = ut + ½at²
200= 0*12.3 + 1/2*a*
a=2.77
v² = u² + 2as,
v²= 0 + 2*2.77*200
v=10.50 m/s
What is the speed in units?A particle or object's movement with respect to time is expressed vectorially as velocity. The meter per second (m/s), usually referred to as speed, is the accepted unit of velocity magnitude.
In physics, what does "velocity" mean?An object's position and speed are mostly determined by its velocity. It calculates the distance an object travels in a specific length of time. The distance an object travels in a given amount of time is its velocity.
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two ice skater, one is 60kg, the other 40kg. when the 60kg man pushes the 40kg woman with 120 n force, what will be the acceleation for the 40kg and 60 kg person respectively?.please enter only the number, no unit!
The acceleration for the 40kg and 60 kg person will be 3 m / s² and - 2 m / s² respectively if the 60kg man pushes the 40kg woman with 120 N force.
F = m a
F = Force
m = Mass
a = Acceleration
For 40 kg woman,
m = 40 kg
F = 120 N
a = F / m
a = 120 / 40
a = 3 m / s²
For 60 kg man,
According to Newton's third law of motion, for every action there will be an equal and opposite reaction. So the 40 kg woman will push back with a force of - 120 N.
a = - 120 / 60
a = - 2 m / s²
The negative sign indicates negative direction.
Therefore, the acceleration for the 40kg and 60 kg person will be 3 m / s² and - 2 m / s² respectively
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what is a strength of a magnetic field for a current loop with 5 a current and diameter of 1.0 m from an electric wire?
0.80tesla is a strength of a magnetic field.
how strong is the magnetic field, exactly?At a distance r from the wire, a current I flowing through a long, straight wire generates a magnetic field with intensity H=I/2r. In other words, the field's strength is inversely proportional to the distance from the wire.
How is field strength determined?Newtons per coulomb (N/C) or volts per meter (V/m) are the SI units for measuring electric field strength. E = F/q, where F is the force felt by a very small test charge q placed in a field E in a vacuum, gives the force felt by the charge.
given,
I = 5A , r = 1.0m
H=I/2πr
H = 5 / 2*3.14*1.0
H = 0.80tesla
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a block of mass m starts from rest and slides down a frictionless semi-circular track from a height h as shown below. when it reaches the lowest point of the track, it inelastically collides with a stationary piece of putty also having mass 2m . the block and the putty stick together and continue to slide. what is the maximum height that the block-putty system could reach?
The maximum height of that block-putty system is h/4.
Whtat is inelastic collision?
A collision in which a portion of the kinetic energy of the colliding particles is converted into another type of energy.
What is velocity?
The primary determinant of an object's position and rate of motion is its velocity. It can be explained as the distance an object travels in one unit of time. The object's displacement in a given amount of time is called velocity.
The velocity of block just before hitting the putty (by energy conservation)
K.Ei+P.Ei=K.Ef+P.Ef
⇒0+mgh=21mv2
⇒v=[tex]\sqrt{2}[/tex]gh
Let the common velocity of both block and putty be v'
At collision momentum balance:
mv=mv′+mv′
⇒[tex]\sqrt{2}[/tex]gh=2v′
⇒v′=[tex]\sqrt{g/h}[/tex]
Again applying energy conservation (both block and putty at max height)
K.Ei+P.Ei=K.Ef+P.Ef
⇒1/2 2mv²=2mgh′
⇒1/2 gh/2=gh′
⇒h′=h/4
Therefore, the maximum height is h/4.
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What are at least two ways that you can get your catapult to increase the horizontal distance of an object launched from it?
Answer:Use Bungee Cord Power. Use the tension of bungee cords as opposed to springs to power your catapult.
Shoot From the Best Angle. Create an arm break that stops the arm at a 45-degree angle from the floor.
Explanation:
two 16.0 $kg$ ice sleds are placed a short distance apart, one directly behind the other, as shown in the figure. a 3.11 $kg$ cat, initially standing on sled 1, jumps across to sled 2 and then jumps back to sled 1. both jumps are made at a horizontal speed of 2.00 $m/s$ relative to the ice. what is the final speed of sled 2? (assume the ice is frictionless.)
The final speed of sled 2 = 0.77 m/s
What is impulse?Impulse is the integral of the force (F) over the time interval (t) for which the force acts. Since force is a vector quantity, momentum is also a vector quantity. Momentum applied to an object produces a vector change equivalent to its linear momentum, and the resulting direction is also changed.
For the given case:
After first jump speed of sled 1 is = u₁
Since there is no external force acting on the sled-cat system there'll be no change in momentum.
u₁ × 16 + 2 × 3.11 = 0
u₁ = -0.38 m/s
Now, for sled 2
2 × 3.11 = (3.11 + 16)u₂
u₂ = 0.32 m/s
After the second jump:
-2 × 3.11 + 16 × v₂ = 0.32 × (16 + 3.11)
v₂ = 0.77 m/s
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Approximately how much kinetic energy does an object have from its motion if its mass is 150-kg and it is moving at a speed of 5. 0 meters per second?.
Answer:
1875 J
Explanation:
kinetic energy= [tex]\frac{1}{2}[/tex]×mass×velocity²
K.E=[tex]\frac{1}{2}[/tex]mv²
K.E=[tex]\frac{1}{2}[/tex]×150×5.0²
K.E= 1875 J
in an emergency stop to avoid an accident, a shoulder strap seat belt holds a 60 kg passenger firmly in place. if the car were initially traveling at 90 km/h and came to a stop in 5.5 s along a straight, level road, what was the average force applied to the passenger by the seat belt?
Answer:
272.727N
Explanation:
Force is equal to the product of mass and acceleration. We know the mass of the person (60kg), so we just need to find how much they are decelerating when coming to a stop.
We do this using the motion equation v=u+at, where v is the final velocity, u is initial velocity, a is acceleration, and t is time. Noting 90km/hr=25m/s, we get:
0=25+5.5a
a=-4.5454545m/s^2
Force = mass * acceleration = 60 * 4.545 = 272.727N
