you throw a ball upward with an initial speed of 4.5 m/s. when it returns to your hand 0.92 s later, it has the same speed in the downward direction (assuming air resistance can be ig- nored). what was the average acceleration vector of the ball?

(a) At time, t = 0.25 s, the y position of the driver is 0.31 m.

(b) At time, t = 0.50 s, the y position of the driver is 1.2 m

(c) At time, t = 0.75 s, the y position of the driver is 2.76 m

The position of the driver at the various time is determined by applying the following kinematic equation.

y = vt + ¹/₂gt²

where;

Since the driver runs horizontally, the initial vertical velocity = 0

y = 0 + ¹/₂gt²

y = ¹/₂gt²

at time, t = 0.25 s, the y position of the driver is calculated as;

y = ¹/₂gt²

y = ¹/₂(9.8)(0.25)²

y = 0.31 m

at time, t = 0.5 s, the y position of the driver is calculated as;

y = ¹/₂gt²

y = ¹/₂(9.8)(0.5)²

y = 1.2 m

at time, t = 0.75 s, the y position of the driver is calculated as;

y = ¹/₂gt²

y = ¹/₂(9.8)(0.75)²

y = 2.76 m

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Answer:

272.727N

Explanation:

Force is equal to the product of mass and acceleration. We know the mass of the person (60kg), so we just need to find how much they are decelerating when coming to a stop.

We do this using the motion equation v=u+at, where v is the final velocity, u is initial velocity, a is acceleration, and t is time. Noting 90km/hr=25m/s, we get:

0=25+5.5a

a=-4.5454545m/s^2

Force = mass * acceleration = 60 * 4.545 = 272.727N

Answer:

V = 140 km/h

Explanation:

Velocity is the change in position over time.

We can use the equation V = Δx / t

Note that V is the average velocity.

We are given Δx and t. Lets solve for V.

[tex]V=\frac{540}{4}[/tex]

[tex]V=140[/tex]

[tex]\frac{km}{hour}[/tex]

V = 140 km/h

the final velocity is 10.50 m/s.

calculation:

time t= 12.3 s

distance s= 200u=0

equations are,  v² = u² + 2as,

s = ut + ½at²

200= 0*12.3 + 1/2*a*

a=2.77

v² = u² + 2as,

v²= 0 + 2*2.77*200

v=10.50 m/s

A particle or object's movement with respect to time is expressed vectorially as velocity. The meter per second (m/s), usually referred to as speed, is the accepted unit of velocity magnitude.

An object's position and speed are mostly determined by its velocity. It calculates the distance an object travels in a specific length of time. The distance an object travels in a given amount of time is its velocity.

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In the 1960s, it was proposed that quasars could be compact objects ejected quickly from the cores of adjacent regular galaxies.

Nobody anticipated that an object that resembles a star could have its spectral lines so drastically redshifted.

It's a concept that makes sense when you consider that as light's wavelength is extended, the spectral lines appear to have "shifted" toward the red portion of the spectrum.

Sound waves experience a similar effect when a source moves in relation to an observer.

As a result of the emission lines being "red shifted," astronomers initially had trouble distinguishing them in quasar spectra at optical wavelengths.

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It is true that clausius statement of the second law states that energy cannot go spontaneously from a colder to a hotter body.

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The net force on the car during its deceleration =  9139.2 N

Deceleration is actually inversely related to acceleration. We know that acceleration is the rate at which an object is speeding up, and deceleration is the rate at which an object is slowing down. For example, when you brake while driving, deceleration is used to slow the vehicle.

Given, m= 1020 kg

u= 0 m/s

V = 94 km/h or 26.1 m/s

t = 10 s

For deceleration

u = 26.1 m/s

v = 0

S = 38 m

by equation of motion ;

v² = u² + 2as

0 = 26.1² + 38a

a = - 8.96 m/s²

Net force during deceleration:

F= m*a

F= 1020 × 8.96

F = 9139.2 N

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The acceleration for the 40kg and 60 kg person will be 3 m / s² and - 2 m / s² respectively if the 60kg man pushes the 40kg woman with 120 N force.

F = m a

F = Force

m = Mass

a = Acceleration

For 40 kg woman,

m = 40 kg

F = 120 N

a = F / m

a = 120 / 40

a = 3 m / s²

For 60 kg man,

According to Newton's third law of motion, for every action there will be an equal and opposite reaction. So the 40 kg woman will push back with a force of - 120 N.

a = - 120 / 60

a = - 2 m / s²

The negative sign indicates negative direction.

Therefore, the acceleration for the 40kg and 60 kg person will be 3 m / s² and - 2 m / s² respectively

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How many turns are on the solenoid? The number of turns on solenoid are 1.400 turns

To find how many turns on solenoid can be calculated as follows:

Given data,

[tex]d[/tex] (diameter of copper wire) = 1mm = 1×[tex]10^{-3}[/tex]m

[tex]D[/tex] (diameter of solenoid) = 14.6cm = 0.146m

[tex]l[/tex] (length of solenoid) = 1.4m

Next, to determine how many turns on solenoid, we can use the formula below:

[tex]N=\frac{l}{d}[/tex]

[tex]N=\frac{1.4}{0.001}[/tex]

[tex]N=1.400[/tex] turns

Therefore, the number of turns on solenoid are 1.400 turns

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The final speed of sled 2 = 0.77 m/s

Impulse is the integral of the force (F) over the time interval (t) for which the force acts. Since force is a vector quantity, momentum is also a vector quantity. Momentum applied to an object produces a vector change equivalent to its linear momentum, and the resulting direction is also changed.

For the given case:

After first jump speed of sled 1 is = u₁

Since there is no external force acting on the sled-cat system there'll be no change in momentum.

u₁ × 16 + 2 × 3.11 = 0

u₁ = -0.38 m/s

Now, for sled 2

2 × 3.11 = (3.11 + 16)u₂

u₂ = 0.32 m/s

After the second jump:

-2 × 3.11 + 16 × v₂ = 0.32 × (16 + 3.11)

v₂ = 0.77 m/s

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The coefficients of static and kinetic friction between crate and floor are

0.25 and 0.176 respectively.

When a body is at rest and if a force is applied to move it, then it would require the force which is equal to the static friction force, if

fs is the static frictional force and the us is the static friction coefficient and Fn is the normal force

[tex]f_{s}[/tex] = us*Fn

Fn = mg

putting the appropriate values, we get

=  71/(29*9.8) = 71/284.2

= 0.2498 = 0.25

Now, similarly when body is in motion, kinetic frictional force is applied, so we can write

[tex]f_{k}[/tex] = uk*Fn

so putting the appropriate values, we get

= 50/mg = 50/284.2 = 0.1759

= 0.176

Hence the value of coefficient of static friction is 0.25 and the value of coefficient of kinetic friction is 0.176.

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The average acceleration of the dragster during this time interval is 44.57 m/s² and the average net force on the dragster during this time is 38915N.

The initial speed U of the dragster is zero while the final speed V of the dragster is 26.3m/s. The director runs for a total of time t of 0.59 seconds.

According to the equation of motion,

V = U+at

Putting values,

26.3 = 0.59a

a = 44.57 m/s².

So, the acceleration of the dragster is 44.57 m/s².

The force on the director is given by,

F = ma

m mass of the dragster and a is the acceleration of the dragster.

F = 873×44.57

F = 38915N.

So, the net average force on the dragster during this time is 38915 Newton.

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The smallest separation in terms of nm between two slits that will produce a second-order maximum for 652 nm visible light is  1.30 um

Since the relationship between wavelength and angle for  minima and maxima  in Young's double slit experiment is:

For constructive interference

d sinθ = n

for  Destructive interference

d sinθ = (n+1/2)λ, where  λ is the wavelength, n  is the order of maxima and minima, Since here n = 2

So the separation, λ =  652 nm , and  θ = 90

so, d sin90 = 2*652*10⁻⁹

=> d=  2*652*10⁻⁹/ sin90  

     =  1.30 X10⁻⁶

    = 1.30 цm

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The formula for the relationship between the electric and magnetic fields is:

E = cB

As the amplitude of the electric field is precisely proportional to the magnetic field, the magnetic field will also double in size when the amplitude of the electric field doubles.

Radio waves typically operate at frequencies between 300 gigahertz and below, where the longest wavelengths of the electromagnetic spectrum are found. At 300 GHz, the corresponding wavelength is 1 mm; nevertheless, at 30 Hz, it is 10,000 kilometers.

A magnetic field, a vector field that affects an electric charge, an electric current, and magnetic materials magnetically. In a magnetic field, a moving charge experiences an external force that is perpendicular to the magnetic field and has its own velocity.

The maximum electric and magnetic field strength is known as the amplitude in electromagnetic waves. The wave amplitude determines the energy of the wave. Similar to how waves themselves move, the energy density also follows the electric and magnetic fields.

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Newton's first law states that an object at rest will remain at rest, and an object in motion won't change its velocity while the equilibrium condition is met.

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The maximum height of that block-putty system is h/4.

Whtat is inelastic collision?

A collision in which a portion of the kinetic energy of the colliding particles is converted into another type of energy.

What is velocity?

The primary determinant of an object's position and rate of motion is its velocity. It can be explained as the distance an object travels in one unit of time. The object's displacement in a given amount of time is called velocity.

The velocity of block just before hitting the putty (by energy conservation)

K.Ei+P.Ei=K.Ef+P.Ef

⇒0+mgh=21mv2

⇒v=[tex]\sqrt{2}[/tex]gh

Let the common velocity of both block and putty be v'

At collision momentum balance:

mv=mv′+mv′

⇒[tex]\sqrt{2}[/tex]gh=2v′

⇒v′=[tex]\sqrt{g/h}[/tex]

Again applying energy conservation (both block and putty at max height)

K.Ei+P.Ei=K.Ef+P.Ef

⇒1/2 2mv²=2mgh′

⇒1/2 gh/2=gh′

⇒h′=h/4

Therefore, the maximum height is h/4.

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Answer:Use Bungee Cord Power. Use the tension of bungee cords as opposed to springs to power your catapult.

Shoot From the Best Angle. Create an arm break that stops the arm at a 45-degree angle from the floor.

Explanation:

Answer:

1875 J

Explanation:

kinetic energy= [tex]\frac{1}{2}[/tex]×mass×velocity²

K.E=[tex]\frac{1}{2}[/tex]mv²

K.E=[tex]\frac{1}{2}[/tex]×150×5.0²

K.E= 1875 J

0.80tesla is a strength of a magnetic field.

At a distance r from the wire, a current I flowing through a long, straight wire generates a magnetic field with intensity H=I/2r. In other words, the field's strength is inversely proportional to the distance from the wire.

Newtons per coulomb (N/C) or volts per meter (V/m) are the SI units for measuring electric field strength. E = F/q, where F is the force felt by a very small test charge q placed in a field E in a vacuum, gives the force felt by the charge.

given,

I = 5A , r = 1.0m

H=I/2πr

H = 5 / 2*3.14*1.0

H = 0.80tesla

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5.5 Newton force is needed to move it vertically upward with 5ms-2 acceleration

​

m=5.1 kg

a= 5m/s²

F=ma

F=5.1×5

F=5.5 N

Every action that attempts to maintain, modify, or change the motion of a body is referred to as a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).

According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight route in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changing velocity) in the direction of the force.

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Permanent dipoles are created by the interaction of permanent charges, which are charges that do not lose their charge when they are separated, as opposed to temporary dipoles, which form when two unlike poles come into contact and then separate.

Permanent dipoles are strong; they can be formed even when there is no electrical current present. The strength of a permanent dipole depends on its size and intensity, but it's typically much stronger than a temporary dipole.

Dispersion forces are weaker than both permanent dipoles and temporary dipoles. They can be generated by any two objects whose surfaces have different charges, regardless of whether there is an electrical current present or not.

The strength of dispersion forces depends on the size and intensity of the charged object, but it's typically much weaker than a permanent or temporary dipole.

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The acceleration of the car that goes around a curve of radius 3r at a speed of 2v is 4 / 3 ( ac )

ac = v² / r

ac = Centripetal acceleration

v = Linear / tangential velocity

r = Radius of curve

This the acceleration of the car that goes around a curve of radius r and velocity v.

For a car that goes around a curve of radius 3r at a speed of 2v,

ac' = ( 2v )² / 3r

ac' = 4v² / 3r

ac' = 4 / 3 ( ac )

Therefore, the acceleration of the car that goes around a curve of radius 3r at a speed of 2v is 4 / 3 ( ac )

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The instantaneous magnitude of the poynting vector will be 518.48.

To calculated magnitude of the poynting vector, we require to use the formula of poynting vector

S = E*B/u

since B = E/c

so , S = E^2 /uc

where , E is the electric field and B is the magnetic field ,

S is the poynting vector magnitude and c is the speed of light.

Putting the values, we get

S = (442x442) /uc

S =  195364 / uc

uc = 4πx[tex]10^{-7}[/tex] x 3 x [tex]10^{8}[/tex]

uc = 376.8

Now, S = 195364/376.8

S = 518.48

Hence The instantaneous magnitude of the poynting is 518.48.

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Yes, a spectrophotometer could be used to measure the absorption of a particular wavelength of light that is not visible to a normal human eye.

Although we cannot directly observe the absorption of this light, it is quantifiable. A spectrophotometer, which measures the absorption of light at certain wavelengths (whether visible or not) by a solution, may be used to compute the concentration. The popular and accessible technique of spectrophotometry may be used to determine the concentration of compounds in a solution or the degree of light absorption.

 When a light beam is focused through the sample, each component either absorbs or transmits light of a certain wavelength. They are combined with quantifiable and visible colored byproducts. Another is that, as observed by a spectrophotometer, colorless substances generally absorb light from the region of the spectrum that is imperceptible to the human eye.

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The quarterback is located 0.3v above ground. The fundamental element of every projectile's body that is moving is its horizontal velocity (vx).

The fundamental element of every projectile's body that is moving is its horizontal velocity (vx). In any projectile motion, it is typically utilized to know the velocity value at which the particle travels along the horizontal direction. It's even thought of as the body's starting point for movement.

Let's say the projectile-moving particle reaches the highest point of its horizontal path. In that case, the horizontal velocity will typically be zero since the force of gravity will cause it to fall vertically downward as soon as it reaches the peak point. Vertical velocity has no impact on this horizontal velocity when it is at its highest point.

Let the horizontal velocity of the object = v

X = vt

X = 0.3v

Thus, The quarterback is located 0.3v above ground.

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The given statement is true. A lunar eclipse happens when the Moon passes into the shadow of the Earth. A solar eclipse happens when the Moon passes between Earth and the Sun.

A lunar eclipse happens when the Moon passes into the shadow of the Earth. This is only possible when the Sun, Earth, and Moon are precisely or extremely closely aligned with Earth between the other two, which can happen only on a full moon night when the Moon is close to either lunar node.

A solar eclipse happens when the Moon passes between Earth and the Sun, completely or partially blocking Earth's view of the Sun. A new moon corresponds with such an alignment, showing that the Moon is closest to the plane of the Earth's orbit. The Moon completely obscures the disk of the Sun during a total eclipse.

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The given statement is true. A lunar eclipse happens when the Moon passes into the shadow of the Earth. A solar eclipse happens when the Moon passes between Earth and the Sun.

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The spectrum shown has a maximum absorption of 278.4 nm.

The absorbance between 400 and 650 nm is measured, often at intervals of 25 nm, to identify the wavelength of maximum absorption. To identify the wavelength of greatest absorption, the data can be analyzed or graphed.

The useful absorbance range for the majority of spectrometers and colorimeters is between 0.1 and 1. Values of absorbance more than or equal to 1.0 are excessive. Your solution is overly concentrated if the absorbance readings you are getting are 1.0 or higher.

Maximum Absorbance refers to an area with the highest absorbance level. We can infer from the graph that the absorbance is at its highest at wavelength 278.45 nm.

Therefore, maximal absorbance occurs at 278.4 nm wavelength.

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Answer:

To say we have a 12.0-V battery implies that its terminals have a 12.0-V likely contrast. At the point when such a battery moves charge, it puts the charge through an expected distinction of 12.0 V, and the charge is given an adjustment of potential energy equivalent to Δ U = q Δ V .

six cells

There are six cells to a 12 volt lead corrosive battery. A battery cell's greatest capacity to convey current (amps).

A 6 cell lithium particle pack has an ostensible voltage of 21.6V to 22.2V and a most extreme charge voltage of 25.2 volts

Explanation:

A linear track beings at 0 meters and has a total distance of 100 meters, then she will go 55 meters. Hence, option D is correct.

The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has quantity but no orientation as a unit of measurement.

Let A represent Juliet's position. O is the starting point with OA = 10, AB = 45, and OP = 100 as its coordinates.

The location of Juliet following running 45 meters will therefore be 55 m, as may be seen from simple math. In the figure, it is OB.

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Your question is not complete, your question probably be :

A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mar

while practicing for a race.

After running 45 meters, how far is she from the beginning of the track?

10 meters

35 meters

45 meters

55 meters