The Perimeter of CED AC is 34 in. AB is 26 in. BD is 28 in. P is 57 in.
Explain about the parallelogram?A parallelogram is the name given to a quadrilateral in geometry. In a parallelogram, the opposing sides are parallel and of equal length. The rhombus, rectangle, and square are just a few shapes that are parallelograms.
Having two sets of parallel sides makes a quadrilateral a parallelogram. A parallelogram has opposite sides that are the same length and angles that are the same size. Additionally, the internal angles on the same transverse side are supplementary. 360 degrees are equal to the total of all internal angles.
Two parallel pairs of sides make up a parallelogram, a quadrilateral. Four right angles form a parallelogram called a rectangle. Rhombus: An equal-length parallelogram with four sides.
The diagonals of a parallelogram bisect each other AC = 2 CE
Substitute AC= 34 into AC = 2 CE 34 = 2CE
Calculate 34 = 2 CE CE = 17
The diagonals of a parallelogram bisect each other BD = 2DE
Substitute BD= 28 into BD = 2DE 28 = 2DE
Calculate 28 = 2 DE DE = 14
Opposite sides of parallelogram are congruent AB = CD
Substitute AB = 26 into AB = CD CD = 26
Perimeter of a triangle PΔCDE = CE + CD + DE
Substitute CE = 17 DE = 14 CD = 26 PΔCDE = CE + CD + DE
PΔCDE = 17+ 26 + 14
PΔCDE = 57
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Subtract.
Your answer should be a polynomial in standard form.
(6a³ + 7a²) - (5a³ + 9a² + a) =
Step-by-step explanation:
=6a^3+7a^2-5a^3-9a^2-a
=a^3-2a^2-a this is the final answer.
.
Radioactive Strontium The half-life of strontium-90 is 28 years. How long will it take a 50- mg sample to decay to a mass of 32 mg?
The time taken is obtained as 3 years.
What is the time taken?We know that radioactivity has to do with the fact that a substances does disintegrate gradually over a period of time.
Let us recall the formula;
N/No = (1/2)^t/t1/2
N = The mass of radioactive atoms at time t
No = The mass of radioactive atoms initially present
t = time taken
t/12 = half life of the radioactive nucleus
Then;
32/50 = (1/2)^t/28
0.64 = (1/2)^t/28
log 0.64 = t/28 log0.5
t/28 = log(0.64/0.5)
t = 28 * log(0.64/0.5)
t = 3 years
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Graph the line with slope 1 passing through the point (-2 , -5)
Graph the line.
The equation of the line is y = x -3. The graph of the line is attached below.
What is a line?
A line is an object in geometry that is indefinitely long and has neither breadth nor depth nor curvature. Since lines can exist in two, three, or higher dimensional environments, they are one-dimensional things. The term "line" can also be used to describe a line segment in daily life that contains two locations that serve as its ends.
Given that the slope of the line is 1.
Assume that the equation of the line is y = mx +c, where m is the slope of the line and c is y-intercepts.
Putting m = 1 in y = mx +c:
y = 1 × x +c
y = x +c
Since the line passes through the point (-2, -5), thus the point satisfies the given equation of line.
Putting x = -2 and y = -5 in y = x +c
-5 = -2 + c
c = -3
The equation of line is y = x - 3.
The points on the line are
(-2, -5), (0, -3), (3, 0).
Plot the points and join them:
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Please help me I’ll mark your answer brainly
The measure of angle B is x, while the measure of angle A is 2·x. The 70° measure of angle C and the angle sum property of the interior angles of a triangle indicates that angle B is [tex]36.\overline 6^{\circ}[/tex] and angle A is [tex]73.\overline 3^{\circ}[/tex]
What are the interior angles of a triangle?The interior angles of a triangle are the angles formed by the sides sides of the triangle.
The question can be solved by making use of the known properties of a triangle.
The angle sum property of the interior angles in a triangle gives;
The sum of the interior angles of a triangle is 180°
Therefore; x + 2·x + 70 = 180
3·x = 180° - 70° = 110°
[tex]x = \dfrac{110^{\circ}}{3} = 36\frac{2}{3} ^{\circ}[/tex]
The measure of angle A is 2·x
Which gives;
[tex]A = 2 \times 36\frac{2}{3} ^{\circ} = 73\frac{1}{3} ^{\circ} = 73.\overline 3^{\circ}[/tex]
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what is (x+5)……………
……….:…………
Answer:
x+5
Step-by-step explanation:
there are no like terms
What is/are the effects when you perform the following transformations on your figure?
a. Reflections –
b. Translations –
c. Rotations –
d. Dilations –
Answer:
A. REFLECTION
Please guys do some research i know you're not that stu p id-_-
Which of the following are less than -0.625
Answer: The answer is A
Step-by-step explanation:
-5/8 is literally equal to -0.625 meaning this asnwer is equal not less
-0.5 is Greater than -0.625 because -0.6 is much larger
-8/5 is -1.6 which is Less than -0.625
Find the value of x .. assume that segments that appear to be tangent are tangent .
We got x = 16.54 by using Pythagorean theorem .
What is the Pythagorean theorem in plain English?
According to Pythagoras's Theorem, the square of the hypotenuse side in a right-angled triangle is equal to the sum of the squares of the other two sides. Perpendicular, Base, and Hypotenuse are the names of this triangle's three sides.angle of semicircle is always be 90° .
18² = 7.1² + x²
324 = 50.41 + x²
x² = 324 - 50.41
= 273.59
x = √ 273.59
x = 16.54
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How many times greater is 5.96 × 10^4 then 2.98 × 10^3?
A. 20
B. 500
C. 50
D. 200
The number 5.96 × 10⁴ is 20 times greater than 2.98 × 10³ , the correct option is (a) .
In the question ,
it is given that
the number is 5.96 × 10⁴ ,
we have to find that how many times greater is 5.96 × 10⁴ then 2.98 × 10³ .
to find that the number is how many times greater ,
we divide 5.96 × 10⁴ by 2.98 × 10³ .
So , on dividing the numbers we get
= ( 5.96 × 10⁴ ) / ( 2.98 × 10³ )
= 5.96/2.98 × 10⁴⁻³
= 2 × 10¹
= 20 times
Therefore , The number 5.96 × 10⁴ is 20 times greater than 2.98 × 10³ .
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Simon uses 121 one-inch tiles to make his square mosaic. What is the length of one side of his mosaic?
10 = 6/5 W
Solve the missing variable, W
[tex]\framebox{w=$\dfrac{25}{3}$}[/tex]
Flip the equation:
[tex]\frac{6}{5} w=10[/tex]
Multiply both sides by [tex]\frac{5}{6}[/tex]:
[tex](\frac{5}{6} )\times(\frac{6}{5} w)=(\frac{5}{6} )\times(10)[/tex]
[tex]w=\frac{25}{3}[/tex]
What is the y-intercept of the graph shown?
Responses
b=2b
b=−2b
b=−3b
b=3b
The y-intercept of the graph as shown is 2.
How to find the y-intercept of a line?The equation of a line can be represented as follows:
y = mx + b
where
m = slopeb = y-interceptThe y-intercept is the point where the graph intersects the y-axis. In other words, it is the value of y when x = 0 .
Therefore, let's trace the value of y when x = 0 on the graph.
Hence, when x = 0, y = 2
Therefore,
b = y-intercept = 2
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Answer:b=2b
b=−2b
b=−3b
b=3b
Step-by-step explanation: because I tought myself i know
Two integers are separated by 24 units on a number line. The sum of the integers is -12 and the quotient is -3. What are the two integers?
Answer:
6 and - 18
Step-by-step explanation:
let the 2 integers be a and b , then
a + b = - 12 → (1)
[tex]\frac{a}{b}[/tex] = - 3 → (2)
multiply both sides by b ( b ≠ 0 )
a = - 3b
substitute a = - 3b into (1)
- 3b + b = - 12
- 2b = - 12 ( divide both sides by - 2 )
b = 6
substitute b = 6 into (1) and solve for a
a + 6 = - 12 ( subtract 6 from both sides )
a = - 18
the two integers are - 18 and 6
Triangle PQR is isosceles, Q being the right angle. If the hypotenuse is 38.47cm, find: i. Lengths of sides PQ and QR. ii. The size of angle QPR
The size of angle QPR is 45° and the length of sides PQ and QR are both 27.20cm
What are Isosceles triangle?An isosceles triangle is a triangle that has at least two sides of equal length. Sometimes it is specified as having exactly two sides of equal length, and sometimes as having at least two sides of equal angle,
since ∆PQR is a right angle isosceles triangle then, if angle Q is 90^°, QPR = PRQ=x( angles of an isosceles triangle).
Therefore 90+x+x= 180°
2x= 90
x= 45°
To find line PQ and QR, we use trigonometry ratio
cos 45°= adj/hyp
I/√2= QR/38.47
QR= 38.47/√2
= 27.20cm
QR= PQ= 27.20
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126=2×3×3×k
Solve for k
[tex]{ \huge{ \boxed{ \red{ \sf{x = 7}}}}}[/tex]
Step-by-step explanation:-
[tex]{ \sf{126 = 2 \times 3 \times 3 \times k}}[/tex]
[tex]{ \sf{126 = 6 \times 3 \times k}}[/tex]
[tex]{ \sf{126 = 18 \times k}}[/tex]
[tex]{ \sf{126 = 18k}}[/tex]
Divide both the sides by 18 in order to find the value of k. Then,
[tex]{ \sf{ \frac{126}{18} = \frac{18}{18} k}}[/tex]
[tex]{ \boxed{ \boxed{ \purple{ \sf{x = 7}}}}}[/tex]
marie bought 1/2 gallon of milk which she finished after 6 days if she drank the same amounteach day how many gallons a day did she drink
She drinks 1/12 gallons of milk each day
How to determine how many gallons a day did she drink?From the question, we have the following parameters that can be used in our computation:
Size of milk = 1/2 gallons
Number of days = 6 days
These parameters can be represented as
(x, y) = (6, 1/2)
The number of gallons a day she drinks can then be represented as the slope/unit rate and the unit rate is then calculated as
unit rate = (y₂ - y₁)/(x₂ - x₁)
Where
(x, y) = (0, 0) and (6, 1/2)
Substitute the known values in the above equation
So, we have the following equation
Slope = (1/2 - 0)/(6 - 0)
Evaluate the quotient
Slope = 1/12
Hence, the number of gallons she drinks a day is 1/12
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The animals at a safari park include camels,
kangaroos and meerkats.
There are 12 more kangaroos than there are
camels.
There are 3 times as many meerkats as there
are camels.
There are the same number of kangaroos as
there are meerkats.
How many camels are there at the safari park?
Number of camels are there at the safari park are 6 unit.
The animals at a safari park include camels, kangaroos and meerkats.
Let kangaroos are represented as K and Camels are represented as C and Meerkats are represented as M.
There are 12 more kangaroos than there are camels which means
K = C + 12.
There are 3 times as many meerkats as there are camels which means
M = 3C.
There are the same number of kangaroos as there are meerkats which means
K = M
If K = M
therefore,
3C = C + 12
2C = 12 ,
C = 6 unit.
So, K = 6 + 12 = 18
Or M = 18
Therefore number of camels, kangaroos and meerkats at the safari park are 6 , 18 and 18 respectively.
Number of camels are there at the safari park are 6 unit.
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What is the image point of (2,0)(2,0) after the transformation D_{\frac{1}{2}}\circ R_{270^{\circ}}D
2
1
∘R
270
∘
The image of point (2,0) after the transformation involving the dilation and the rotation is given as follows:
(0, -1).
What are the transformations applied to the point?The first transformation applied to the point is a dilation, which multiplies the coordinates of the point by the scale factor.
The point has these following coordinates:
(2,0).
The scale factor of the dilation is:
k = 1/2 = 0.5.
Then each coordinate of the point is multiplied by 0.5, hence:
2 x 0.5 = 1.0 x 0.5 = 0.Hence the coordinates are:
(1,0).
The rule for a rotation of 270º clockwise around the origin is:
(x,y) -> (y,-x).
Then:
x = 1, -x = -1.y = 0.Thus the coordinates of the image are given as follows:
(0, -1).
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Can anyone please help me I would really appreciate it a lot
Using the geometric mean theorem,
[tex]\frac{y}{14.4}=\frac{14.4}{19.2} \\ \\ y=10.8[/tex]
Using Pythagoras on triangle [tex]ABD[/tex],
[tex]x=\sqrt{14.4^2+10.8^2}=18[/tex]
Triangles [tex]ABD[/tex] and [ted]CBD[/tex] are similar because corresponding angles are congruent and pairs of corresponding sides have proportional lengths.
To determine this, use the complementary angles.
If P= (2, 7) and Q= (2, -3), which could be the coordinates of R if triangle PQR is isosceles?
If P= (2, 7) and Q= (2, -3), then for triangle to be isosceles coordinate of R must be 2
Let coordinates
P = (2, 7) and Q = (2, -3)
PR = QR
(X-2)^2 +(Y-7)^2 = (X-2)^2 + {Y-(-3)}^2
(Y-7) = {Y - (-3)}^2. or y - 7 = ±(Y
or Y^2 - 14Y + 49 = Y^2 + 6Y + 9
20Y = 40
Y=2
coordinates of R if triangle PQR is isosceles ;
Hence any point R on the line Y = 2 will make PQR a isosceles triangle
with PR = QR.
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a) Find the circumference of a circle whose radius is 4 inches. Round to the nearest tenth.
b) Find the length of if mACB = 60º and the radius of the circle is 4 inches. Round to the nearest tenth.
Complete your work in the space provided.
The circumference of the circle is 25.1 inches.
The length of the arc ACB is 4.2 inches.
How to find circumference of a circle?The circumference of a circle is the perimeter of the circle.
Therefore,
circumference of a circle = 2πr
where
r = radiusHence,
circumference of a circle = 2 × 3.14 × 4
circumference of a circle = 8 × 3.14
circumference of a circle = 25.1 inches
The length of the arc ACB can be found as follows:
length of arc = ∅/ 360 × 2πr
length of the arc = 60 / 360 × 2 × 3.14 × 4
length of the arc = 60 / 360 × 25.12
length of the arc = 1507.2 / 360
length of the arc = 4.18666666667
length of the arc = 4.2 inches
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A rotating light is located 17 feet from a wall. The light completes one rotation every 2 seconds. Find the rate at which the light projected onto the wall is moving along the wall when the light's angle is 20 degrees from perpendicular to the wall.
When the the light's angle is 20° from perpendicular to the wall, and the light is rotating at an angular speed of one rotation in 2 seconds the rate the light projected onto the wall is moving is approximately 60.48 feet/s
What is angular speed?Angular speed, ω, is the angle, θ, in radians rotated by a rotating object per second. The unit of angular speed is radians per second, rad/s.
Mathematically;
[tex]\omega = \dfrac{\Delta \theta}{\Delta t}[/tex]
Where;
Δt = The time the object rotates through an angle of Δθ
The distance of the light from the wall, x = 17 feet
Time it takes the light to complete one rotation = 2 seconds
Angle the light makes with the perpendicular wall = 20°
[tex]tan(\theta) = \dfrac{y}{x}[/tex]
The distance the light has moved along the wall, y = x × tan(θ)
Therefore;
The y = 17 × tan(θ)
The angular velocity of the light, ω = θ/t
Therefore, θ = ω × t = ω·t
Which gives; y = 17 × tan(ω·t)
[tex]\omega = \dfrac{2\cdot \pi}{2}\ rad/s = \pi \ rad/s[/tex]
Therefore; x = 17 × tan(·t)
[tex]\dfrac{dy}{dt} = \dfrac{d}{dt} \left(17\times tan(\omega\cdot t)\right) = 17\cdot \omega\cdot sec^2(\omega \cdot t)[/tex]
ω = π rad/s (constant)
ω·t = θ
Therefore;
[tex]\dfrac{dy}{dt}= 17\cdot \omega\cdot sec^2(\theta)[/tex]
Rate the light is moving along the wall, dy/dt when θ = 20°, is therefore;
[tex]\dfrac{dy}{dt}= 17\times \pi\cdot sec^2(20^{\circ}) \approx 60.48[/tex]
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what percent is 25 of 100
if we take 25 to be the 100%, what is 100 off of it in percentage?
[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 25 & 100\\ 100& x \end{array} \implies \cfrac{25}{100}~~=~~\cfrac{100}{x} \\\\\\ \cfrac{1}{4}=\cfrac{100}{x}\implies x=400[/tex]
Answer:
25
Step-by-step explanation:
25/100=.25x100=25
Natalie has a budget of $15,000 dollars to spend on tracking devices to study bison. A radio tracker costs $650 and a GPS tracker costs $1400. Natalie wants to buy at least 9 radio trackers and more than 3 GPS trackers. The following system of inequalities represents this situation, where x is the number of radio trackers and y is the number of GPS trackers. x ≥ 9 y > 3 650x + 1400y ≤ 15000
The inequality as per the question is x ≥ 9 and y > 3 and the diagram according to this is attached below.
What is an equality?Inequalities are mathematical expressions where neither side is equal. In inequality, as opposed to equations, we compare the two values. Less than (or less than and equal to), larger than (or greater or equal to), or not similar to signs are used in place of the equal sign in between.
As per the given information in the question.,
x ≥ 9 and,
y > 3
The equation is,
650 x + 1400 y ≤ 1
[tex]\frac{x/15000}{650}+\frac{y/15000}{1400} \leq 1[/tex]
x/23.07 + y/10.71 ≤ 1
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If V is the midpoint of WY, VY=29-4x, and WY=5x+19, find WV.
The value of WV is 9x - 10
What is line segment?A line segment can be defined as the part of a straight line which is bound by two distinct end points, and is known to be made up of every point on the line that between its endpoints.
From the information given, we can say that WY is a line with V as its midpoint with segments WV and VY.
We have;
VY=29-4x WY=5x+19This is represented as;
WV + VY = WY
Then;
WV = WY - VY
substitute the values
WV = 5x + 19 - (29 - 4x)
expand the bracket
WV = 5x + 19 - 29 + 4x
collect like terms
WV = 9x - 10
Hence, the value is 9x - 10
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A cell phone plan costs $100 to start. Then there is a $25 charge each month. What is the total cost (start-up fee and monthly charge) to use the cell phone plan for 1 month? 6 months? Be sure to show your work. What is the total cost for months? Enter your first and last name below and then click start. If this is your second attempt, be sure to put a "2" after your name so I know it is your second attempt. Graph the cost of the cell phone plan over a period of two years, using months as the units of time. Be sure to label your axes and scale them by labeling each gridline with a number.
The $100 start-up fee and $25 monthly rental gives;
The cost of using the phone for 1 month = $125
The cost of using the phone for 6 months = $250
The cons of using the phone for n months = $(100 + 25·n)
Please find attached the graph of the cellphone plan over a period of two years (24 months)
What is a graph of a function?A graph is a visual representation of the variation of one variable of a function with respect to other variables of the function.
The start-up fee of the cell phone plan = $100
The amount charged each month = $25
First part;
The total cost for the start-up fee and monthly rental for 1 month = $100 + $25
The total cost for 1 month = $125
The total cost for 6 months = $100 + 6 × $25 = $250
The total cost for n months = 100 + n × 25 = $(100 + 25·n)
Please find the graph of the total cost to the number of months created with MS Excel
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No one bothers to help, plsssssssssss!!!!!!!!!!!!!!!!!!!!!!!
slope-related question image pasted below!!!
Answer:
I'm not sure if its right but I got
6/9
Step-by-step explanation:
What I did was:
I took the 2 points:
(-4,4) and (5,-2)
Then did rise over run
Which left me with 6/9
Which of the following (x,y) coordinates are solutions to the inequality 2x+5y<1?
The solution to the inequality given as 2x+5y<1 has the coordinates of (-10, 4)
How to determine the coordinates of the solution of the inequality?From the question, we have the following inequality that can be used in our computation:
2x+5y<1
Solving further, we need to collect the like terms
Since there are no like terms in the expression, it remains unchanged
So, the inequality becomes
2x + 5y < 1
Subtract 5y from both sides of the inequality
This gives
2x < 1 - 5y
Divide both sides by 2
The expression becomes
x < 1/2 - 5/2y
Evaluate
x < 0.5 - 2.5y
At this point, we assume any value for y and then solve for x
Assume that the value of y is 4
So, we have the following representation
x < 0.5 - 2.5 * 4
Evaluate the products
x < -9.5
This means that x is less than -9.5 when y is 4
-10 is less than -9.5
So, we have
x = -10 and y = 4
Express as ordered pairs (i.e. coordinates)
(x, y) = (-10, 4)
Hence, the coordinates of the solution is (-10, 4)
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What is the sum of −12, 5, and −10?
(A) −27
(B) −17
(C) 17
(D) 27
Mia is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 15 meters from the building. The angle of elevation from her eyes to the roof ((point AA)) is 18^{\circ}
∘
, and the angle of elevation from her eyes to the top of the antenna ((point BB)) is 53^{\circ}
∘
. If her eyes are 1.75 meters from the ground, find the height of the antenna ((the distance from point AA to point BB)). Round your answer to the nearest tenth of a meter if necessary.
Considering the angle of elevations, the distance from point AA to point BB which is the height of the antenna is 5.34 meters
How to find the distance between the pointsinformation given in the question
Mia stands at a horizontal distance of 15 meters from the building
The angle of elevation from her eyes to the roof ((point AA)) is 18
the angle of elevation from her eyes to the top of the antenna ((point BB)) is 53^
her eyes are 1.75 meters from the ground
The direction of movements describes a right angle triangle of
opposite = height of antenna + height of the building
adjacent = 15 meters
The distance from point AA to point BB and the height of the antenna is worked using SOH CAH TOA
Sin = opposite / hypotenuse - SOH
Cos = adjacent / hypotenuse - CAH
Tan = opposite / adjacent - TOA
The the height of the antenna is calculated using tan, TOA let the angle be x
tan x = Opposite / Adjacent
using 53 gives the height of the antenna + height of the building, while using 18 gives height of the building only
tan 53 = opposite / 15
opposite = 15 * tan 53 = 19.906 meters
opposite = 15 * tan 18 = 14.266 meters
Height of the antenna
= 19.606 - 14.266
= 5.34 meters
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