19.
a. Given the formula A= (1/2)bh , solve for b.
Only answer if you know the question please

the answer for table f is 216 and the answer for table e is 10 for the first column and 8 for the second

Answer:

Domain is {xER} (This means that x is all real numbers)

Range is [tex]f(x) \leq 6[/tex] (This means that x is less than or equal to 6)

Step-by-step explanation:

The radian measure of the angle at the center of the circle is approximately 1.6623 radians.

We are given that the radius of the circle is 77.0 cm and the length of the intercepted arc is 128 cm. We need to find the radian measure of the angle at the center of the circle.

To solve this problem, we use the formula relating the angle at the center of a circle, the radius of the circle, and the arc length intercepted by the angle.

The formula is given byθ = s/rwhereθ = angle at the center of the circle in radians s = arc length intercepted by the angle r = radius of the circle Substituting the given values, we getθ = 128/77.0 = 1.6623 radians (rounded to four decimal places)

Therefore, the radian measure of the angle at the center of the circle is approximately 1.6623 radians.

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Answer: square root of 29

Step-by-step explanation:

Given the question :

Distance between (4, 7) and (2, 2)

Distance between two points is given by:

Distance = sqrt[(X2 - X1)² + (Y2 - Y1)²]

X1 = 4 ; Y1 = 7 ; X2 = 2 ; Y2 = 2

Distance = sqrt[(2 - 4)² + (2 - 7)²]

Distance = sqrt[(-2² + - 5²)]

= sqrt(4 + 25)

= sqrt(29)

Answer:

as in pic below

Step-by-step explanation:

At year 2, you will have approximately $25,915.13 in your bank account, assuming an initial investment with a 5% interest rate compounded annually. The correct answer is (a).


To find out how much money you will have in your bank account at year 2, we can use the compound interest formula:
A = P(1 + r/n)^(nt)
Where:
A = Final amount (in this case, $30,000)
P = Principal amount (initial investment)
R = Annual interest rate (5% or 0.05)
N = Number of times interest is compounded per year (assumed to be once per year)
T = Number of years (in this case, 3)
Let’s solve for P, the principal amount at year 0:
30,000 = P(1 + 0.05/1)^(1*3)
30,000 = P(1.05)^3
Dividing both sides of the equation by (1.05)^3:
P = 30,000 / (1.05)^3
P ≈ 25,915.13
Therefore, at year 2, you will have approximately $25,915.13 in your bank account.
The correct answer is (a) $25,915.13.

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Answer:

A

Step-by-step explanation:

y = 12x + 8

The correct equation represents the relationship between y, the total cost of the popcorn and movie tickets, and x, the number of movie tickets that are purchased is,

⇒ y = 12x + 8

Now,

Let p be the price of one bucket of popcorn and t be the price of one ticket.

Since, The total cost for a bucket of popcorn and 4 movie tickets is, $56

⇒ p + 4t = 56  .. (1)

And, the total cost for the same size bucket of popcorn and 6 movie tickets is $80.

⇒ p + 6t = 80   ..(2)

Now, Equation (1) - Equation (2),

-2 t = - 24

⇒ t = 12

By substituting this value in equation (1),

We get,

p + 48 = 56

⇒ p = 8

Thus, the price of one bucket of popcorn = $8

And, the price of one ticket = $12

Thus, The total price (y) of one bucket of popcorn and x tickets is,

y = 8 + 12 x

y = 12x + 8

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Answer:

The answer would be 1 + 14x + -7y

Brainlist???

Given y = g(x) therefore,

y = -4.

Since there's no x. That means x = 0.

Therefore the value of x is 0

Answer:

It depends on what the question and or equation is that you are using if i knew why you where trying to solve for x I could tell you.

Step-by-step explanation:

Answer:

22

Step-by-step explanation:

2+2+9+9

22

Answer:

Charlie's lemonade is stronger

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Answer:

38.18%

Step-by-step explanation:

Experimental probability is probability that is determined on the basis of the results of repeated experiments.

Experimental Probability = The number of times a result happens / The number of times the experiment is carried out *100%

In this problem, The number of times a result happens is the number of times Pedro sees heads, which is 21. The number of time the experiment is carried out is 55.

So the result is 55/21 *100% = 38.181818... * 100%= 38.18%

Hope you learn with joy and high grades !

Referring to Table 3.1, if the government imposes a price of $3, a shortage will result.

To determine the outcome when the government imposes a price of $3, we need to compare the quantity demanded and quantity supplied at this price level.
According to Table 3.1, at a price of $3, the quantity demanded is 30 units, while the quantity supplied is 40 units. The quantity demanded (30 units) is less than the quantity supplied (40 units), resulting in a situation known as a shortage.
A shortage occurs when the quantity demanded exceeds the quantity supplied at a given price. In this case, a shortage of 10 units occurs because consumers are willing to buy more than what producers are offering at the price of $3.
To summarize, if the government imposes a price of $3 based on Table 3.1, a shortage will result. This means that the quantity demanded exceeds the quantity supplied at the given price, indicating that consumers are unable to purchase all the units they desire.

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 the complete question is:

Table 3.1
Quantity Demanded.
Price per Unit
Quantity supplied
10
$5
50
20
30
$4
$3
40
30
40
50
$2
$1
20
10
Refer to Table 3.1. If the government imposes a price of $3.
a shortage will result.
Market is in equilibrium.
the price will fall to $1 because producers will be forced to incur losses.
a surplus will result.

Answer: 1/16

Step-by-step explanation:

Each number in the series is half of the previous number. The negatives alternate with the positives. So they must be multipling by -1/2.

-1/8(-1/2) = 1/16

After that would be

1/16(-1/2) = -1/32

Hope this helps. (And maybe worth Brainliest)

Answer:  7/2

Step-by-step explanation:

[tex]\lim_{x \to \frac{1}{2}} \dfrac{8x-3}{2x-1}-\dfrac{4x^2+1}{4x^2-1}[/tex]

Multiply the left fraction by 2x+1 so both fractions have the same denominator.

[tex]\lim_{x \to \frac{1}{2}} \dfrac{8x-3}{2x-1}\bigg(\dfrac{2x+1}{2x+1}\bigg)-\dfrac{4x^2+1}{4x^2-1}\\\\\\\lim_{x \to \frac{1}{2}} \dfrac{12x^2+2x-4}{4x^2-1}\\\\\\\lim_{x \to \frac{1}{2}} \dfrac{2(3x+2)(2x-1)}{(2x+1)(2x-1)}\\\\\\\lim_{x \to \frac{1}{2}} \dfrac{2(3x+2)}{2x+1}[/tex]

Directly input x = 1/2        [tex]\dfrac{2[3(\frac{1}{2})+2]}{2(\frac{1}{2})+1}\quad =\dfrac{7}{2}[/tex]

A(X) is a subspace of V if and only if v; Oy for a₂, a₃,..., an and a₁ + a₂ + ... + an = 1. This relationship highlights the connection between the subspace A(X) and the coefficients in the linear combinations of vectors in X.

Let X = {V₁, V₂,..., Vn} be a subset of a vector space V over F. The set A(X) is the set of all linear combinations of vectors in X, expressed as a₁V₁ + a₂V₂ + ... + anVn, where a₁, a₂,..., an ∈ F.

First, assume that A(X) is a subspace of V. This means A(X) satisfies the subspace criteria of closure under addition and scalar multiplication. For any vectors v and w in A(X) and any scalar c ∈ F, we have cv ∈ A(X) and v + w ∈ A(X). By expressing v and w as linear combinations of vectors in X, we can observe that the coefficients of the linear combinations can be added or multiplied by a scalar without violating the subspace criteria. Therefore, we can conclude that there exist coefficients a₁, a₂,..., an such that v = a₁V₁ + a₂V₂ + ... + anVn and w = a₁'V₁ + a₂'V₂ + ... + an'Vn, where a₁ + a₁' + ... + an + an' = 1.

Conversely, assume that v; Oy for a₂, a₃,..., an and a₁ + a₂ + ... + an = 1. We need to prove that A(X) satisfies the subspace criteria. For any vectors v and w in A(X) and any scalar c ∈ F, we can express v and w as linear combinations of vectors in X with coefficients a₁, a₂,..., an. By performing the operations of addition and scalar multiplication, we can see that the resulting linear combinations still satisfy the conditions v; Oy and a₁ + a₂ + ... + an = 1. Therefore, A(X) is closed under addition and scalar multiplication.

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An nth-degree polynomial function with real coefficients that satisfies the given conditions, where n = 3 and the zeros are -2 and 9 + 21, and the function value f(1) = 204, is f(x) = (x + 2)(x - (9 + 21))(x - 1).

To find the polynomial function that satisfies the given conditions, we start by considering the zeros. Since the zeros are given as -2 and 9 + 21, we can write the factors for the polynomial as (x + 2) and (x - (9 + 21)).

Next, we consider the function value f(1) = 204. This means that when x = 1, the function should evaluate to 204. To satisfy this condition, we include the factor (x - 1) in our polynomial.

Combining these factors, we have the polynomial function f(x) = (x + 2)(x - (9 + 21))(x - 1).

To verify the real zeros and the given function value, we can use a graphing utility. By graphing the function, we can observe the x-intercepts, which represent the zeros, and check if the function evaluates to 204 when x = 1.

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Answer:

40 km

Step-by-step explanation:

Divide the distance by the scale

12/3 = 4

Multiply that number by the 10 km

4 x 10 = 40

- x - y - z = - 8 ------- (1)

- 4x + 4y + 5z = 7 -------- (2)

2x + 2z = 4 --------- (3)

From (3): x + z = 2

                     x = 2 - z --------- (4)

Substitute (4) into (1),

- x - y - z = - 8

- (2-z) - y - z = - 8

- 2 + z - y - z = -8

- 2 - y = - 8

2 + y = 8

Therefore, y = 6

Substitute y = 6 and (4) into (2),

- 4x + 4y + 5z = 7

- 4(2 - z) + 4(6) + 5z = 7

- 8 + 4z + 24 + 5z = 7

9z + 16 = 7

9z = - 9

Therefore, z = - 9

Substitute z = - 9 into (4),

x = 2 - z

x = 2 - (-9)

x = 2 + 9

Therefore x = 11

Solution:

x = 11

y = 6

z = -9

Answer:

x = 126°

x - 30 = 96°

Step-by-step explanation:

The sum of angles in a 5 sided polygon is 540°.

Hence all these angles would = 540

x + x + (x - 30) + (x - 30) + (x - 30) = 540

Collect like terms

5x - 90 = 540

Rearrange

5x = 540 + 90

5x = 630

x = 126

x - 30 = 96

Answer:
The amount of Radium-226 remaining after 2000 years is approximately 209.08 mg.

Step-by-step explanation:

We can use the formula for exponential decay to solve this problem. The formula is:

N = N0 * (1/2)^(t/T)

where N is the amount of substance remaining after time t, N0 is the initial amount of substance, T is the half-life of the substance, and t is the time elapsed.

In this case, we are given that the half-life of Radium-226 is 1590 years, and that we start with an initial amount of 500 mg. We want to find the amount remaining after 2000 years.

Substituting the given values into the formula, we get:

N = 500 * (1/2)^(2000/1590)

Evaluating the expression, we get:

N ≈ 209.08

So the amount of Radium-226 remaining after 2000 years is approximately 209.08 mg.

Answer:

Developing and improving communication skills will help ensure that messages are sent and received properly. Analyze the effects of effective communication. Effective communication involves the sender having the desired effect on the receiver of the message.

Step-by-step explanation:

I just did it and got it it right

Hope this helps!

       God Bless You! <3

Answer:

(3/4) x (3/2) =  1 1/8 cups is you Answer.

This is the same as saying 6 cubic cm

====================================================

Work Shown:

d = density = 4 g/cm^3

m = mass = 24 g

v = volume = unknown

--------------

d = m/v

4 = 24/v

4v = 24 .... multiply both sides by v

v = 24/4 .... divide both sides by 4

v = 6 cm^3